Search Results

Search found 6375 results on 255 pages for 'colon syntax'.

Page 42/255 | < Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >

  • Syntax for combining joins in mysql

    - by UltraVi01
    I seem to remember reading somewhere that there is a way to combine LEFT JOIN statements into a more simple query. I have the following query and was hoping someone could kindly take a look at it. SET @userId = 8; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug, user u, profile p LEFT JOIN user_block ub ON @userId = ub.blocked_id LEFT JOIN user_block ub2 ON @userId = ub2.blocker_id LEFT JOIN user_user uu ON @userId = uu.user_id LEFT JOIN friend_request fr ON @userId = fr.user_id WHERE ug.user_id = u.id AND u.profile_id = p.id AND (ub.blocker_id IS NULL OR ub.blocker_id != ug.user_id) AND (ub2.blocked_id IS NULL OR ub2.blocked_id != ug.user_id) AND (uu.user_friends_id IS NULL OR uu.user_friends_id != ug.user_id) AND (fr.to_user_id IS NULL OR (fr.to_user_id != ug.user_id)) AND ug.user_id!=@userId AND p.suggestible AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4

    Read the article

  • C# string syntax error

    - by Mesa
    I'm reading in data from a file and trying to write only the word immediately before 'back' in red text. For some reason it is displaying the word and then the word again backwords. Please help. Thank you. private void Form1_Load(object sender, EventArgs e) { Regex r = new Regex(" "); StreamReader sr = new StreamReader("KeyLogger.txt"); string[] tokens = r.Split(sr.ReadToEnd()); int index = 0; for(int i = 0; i <= tokens.Length; i++) { if (tokens[i].Equals("back")) { //richTextBox1.Text+="TRUE"; richTextBox1.SelectionColor = Color.Red; string myText; if (tokens[i - 1].Equals("back")) myText = ""; else myText = tokens[i - 1]; richTextBox1.SelectedText = myText; richTextBox1.Text += myText; } else { //richTextBox1.Text += "NOOOO"; } //index++; //richTextBox1.Text += index; } }

    Read the article

  • Why does Javascript's OR return a value other than true/false?

    - by Fletcher Moore
    I saw this construction in order to get the browser viewport width: function () { return window.innerWidth || document.documentElement.clientWidth || document.body.clientWidth; } I understand the browser quirks involved. What I don't understand is why || returns the value. So I tried this alert(undefined || 0 || 3); and sure enough, it alerts 3. I find this bizarre, because I expect true or false. Could anyone explain what's going on?

    Read the article

  • undefined C/C++ symbol as operator

    - by uray
    I notice that the character/symbol '`' and '@' is not used as an operator in C/C++, does anyone know the reason or historically why its so? if its really not used, is it safe to define those symbols as another operator/statement using #define?

    Read the article

  • syntax for binding multiple variables within text

    - by danke
    When binding multiple variables value1 value2 value3 in the same text field, do I do this: text="{some text value1 other text value2 and other text value3}" or text="some text {value1} other text {value2} and other text {value3}" I noticed both work, but which is the right way to do it and will work all the time.

    Read the article

  • Why do some people prefer "T const&" over "const T&"?

    - by Michael Aaron Safyan
    So, I realize that const T& and T const& are identical and both mean a reference to a const T. In both cases, the reference is also constant (references cannot be reassigned, unlike pointers). I've observed, in my somewhat limited experience, that most C++ programmers use const T&, but I have come across a few people who use T const&. Is this just a personal preference? Why is one chosen over the other?

    Read the article

  • Simple question about C++ constant syntax

    - by WilliamLou
    Here is some code copied from Thinking in C++ Vol1 Chapter 10. #include <iostream> using namespace std; int x = 100; class WithStatic { static int x; static int y; public: void print() const { cout << "WithStatic::x = " << x << endl; cout << "WithStatic::y = " << y << endl; } }; what's the meaning of const for the function print()? Thanks!

    Read the article

  • Why do I get a "warning: no newline at end of file" ?

    - by user198729
    The file is a helloworld.cpp: #include <iostream> using namespace std; int main() { if(true) cout << "!!!Hello World!!!" << endl; // prints !!!Hello World!!! return 0; } But when I build it,get a warning: g++ -Wall -O2 -c -o hw.o hw.cpp hw.cpp:8:2: warning: no newline at end of file g++ -o myprog hw.o If I add a newline at the end,the warning will go. Why is that newline at end of file recommended in a cpp source file?

    Read the article

  • Need help for this syntax: "#define LEDs (char *) 0x0003010"

    - by Noge
    I'm doing programming of a softcore processor, Nios II from Altera, below is the code in one of the tutorial, I manage to get the code working by testing it on the hardware (DE2 board), however, I could not understand the code. #define Switches (volatile char *) 0x0003000 #define LEDs (char *) 0x0003010 void main() { while (1) *LEDs = *Switches; } What I know about #define is that, it is either used to define a constant, or a macro, but why in the above code, there are casting like, (char *) 0x0003010, in #define? why the 2 constants, Switches and LEDs act like a variable instead of a constant? Thanks in advance !

    Read the article

  • TextMate: Conditional formatting?

    - by Nebs
    I want to be able to color lines differently based on the starting character. eg.: - This is line 1 - This is line 2 x This is line 3 - This is line 4 x This is line 5 So lines 1,2,4 (starting with '-') should be blue while lines 3,5 (starting with 'x') should be red. Is this possible? How would you do it? Thanks.

    Read the article

  • rails multiple outer joins syntax

    - by Craig McGuff
    I have the following models user has_many :leave_balances leave_balance belongs_to :user belongs_to :leave_type leave_type has_many :leave_balances I want to output a table format showing user names and their balance by leave type. Not every user can have every balance i.e. outer joins required. I'd like to see something like this: Employee Annual Leave Sick Leave Bob 10 Fred 9 Sara 12 15 I am unsure how to get this out as a single statement? I am thinking something like User.joins(:leave_balances).joins(:leave_type)

    Read the article

  • What's wrong with my logic (Java syntax)

    - by soda
    I'm trying to make a simple program that picks a random number and takes input from the user. The program should tell the user if the guess was hot (-/+ 5 units) or cold, but I never reach the else condition. Here's the section of code: public static void giveHint (int guess) { int min = guess - 5; int max = guess + 5; if ((guess > min) && (guess < max)) { System.out.println("Hot.."); } else { System.out.println("Cold.."); } }

    Read the article

  • Ruby - model.rb:20: syntax error, unexpected keyword_end, expecting $end

    - by Yasir Adnan
    I don't understand what's wrong with my code. model.rb require 'Gemfile' DataMapper.setup(:default, 'mysql://root:password@localhost/rengine') Class User include DataMapper::Resource property :id, Serial # An auto-increment integer key property :email, String, format: :email_address property :username, String, required: true property :password, String , length: 10..255, required: true property :created_at, DateTime property :updated_at, DateTime #User can have mutiple posts has n, :posts end Class Post include DataMapper::Resource property :id, Serial # An auto-increment integer key property :title, String, required: true property :body, Text, required: true property :created_at, DateTime property :updated_at, DateTime #Posts belongs to a USer belongs_to :user end DataMapper.auto_upgrade! I didn't able to figure out. What's problem is here??

    Read the article

  • JQuery Syntax Problem?

    - by Michael Smith
    I am using JQuery to insert divs into a page but i cant seem to get the quotation marks correctly setup. For example the code below works fine: var newDiv_1 = '<div id="event_1"><b>Hello World 01</b></div>'; $('#mon_Events').append(newDiv_1); But when i try to use variable in place of the normal text, i doesnt seem to work: var eventname = 1; var newDiv_1 = '<div id="event_' . eventName . '"><b>Hello World 01</b></div>'; $('#mon_Events').append(newDiv_1); How do i use variable inside this statement?

    Read the article

  • Perl - getting a value from a hash where the key has a dot

    - by imerez
    I have a hash in Perl which has been dumped into from some legacy code the name of the key has now changed from simply reqHdrs to reqHdrs.bla $rec->{reqHdrs.bla} My problem is now I cant seem to access this field from the hash any ideas? The following is my error Download Script Output: Bareword "reqHdrs" not allowed while "strict subs" in use

    Read the article

  • error C2146: syntax error : missing ';' before identifier 'g_App'

    - by numerical25
    I wish c++, was a little more specific on the messages they give. The following error is being thrown in the document below main.h #ifndef main_h #define main_h //includes #include <windows.h> #include <commctrl.h> #include <d3d9.h> #include <fstream> #include "capplication.h" //constants #define TITLE "D3D Tut 01: Create Window" #define WINDOW_X 350 #define WINDOW_Y 320 //Button ID's #define ID_START 1 #define ID_CANCEL 2 //globals extern CApplication g_App; //function prototypes LRESULT CALLBACK WindowProcedure(HWND,UINT,WPARAM,LPARAM); #endif The only header file that could possible throw this error is the capplication.h. given below capplication.h #ifndef capplication_h #define capplication_h #include"main.h" class CApplication { public: CApplication(void); ~CApplication(void); void InitWindow(void); void SaveSettings(void); void LoadSettings(void); void KillWindow(void); inline bool GetWindowStatus(void) { return m_bRunningWindow; } inline HWND GetWindowHandle(void) { return m_hWindow; } inline void SetWindowStatus(bool bRunningWindow) { m_bRunningWindow = bRunningWindow; } private: bool m_bRunningWindow; HWND m_hWindow, m_hBtnStart, m_hBtnCancel, m_hLblResolution, m_hCbResolution, m_hLblBackBuffer, m_hCbBackBuffer, m_hLblDepthStencil, m_hCbDepthStencil, m_hLblVertexProcessing, m_hCbVertexProcessing, m_hLblMultiSampling, m_hCbMultiSampling, m_hLblAnisotropy, m_hCbAnisotropy; DWORD m_dwWidth, m_dwHeight, m_dwVertexProcessing, m_dwAnisotropy; D3DFORMAT m_ColorFormat, m_DepthStencilFormat; D3DMULTISAMPLE_TYPE m_MultiSampling; }; #endif Besides that, the only suspicious thing I see is fstream given in the first code. I did have it as fstream.h But VC++ was not recognizing it so I was told to remove the h and I did. now I am down to this error. and I have no clue what it could be. Possibly something obvious

    Read the article

< Previous Page | 38 39 40 41 42 43 44 45 46 47 48 49  | Next Page >