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  • How do I parse youtube xml for a specific entry?

    - by sharataka
    I am trying to return the duration of the video but am having trouble. #YOUTUBE FEED #download the file: file = urllib2.urlopen('http://gdata.youtube.com/feeds/api/videos/2s0vk2wEMtA') #convert to string: data = file.read() #close file because we dont need it anymore: file.close() #entire feed root = etree.fromstring(data) for entry in root: for item in entry: print item When I print item, I see as the last element: Element '{http://gdata.youtube.com/schemas/2007}duration' at 0x10c4fb7d0 But I don't know how to get the value from this. Any advice?

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  • wxPython formatting questions

    - by Kevin
    I have an app I was working on to learn more about wxPython( I have been primarily been a scripter ). I forgot about it now I am opening it back up. It's a screen scraper, and I have it working almost the way I want it, going to build a regex parser to strip out the links in every scrape that I don't need. The questions I have are this. In it current state, if I check more than one site, it goes out and scrapes, and returns it in separate windows, the for:each section in the Clicked function. I want to put them in a frame, in the window, altogether. I also want to know if I can take the list they are read into and send it to a checklist, so someone could check off separate items, I want to build a save function and keep certain ones. In regards to a save function, I want to keep saved checks, are there calls to the widgets to save their states? I know it's a lot, but thanks for the help.

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  • Find all A^x in a given range

    - by Austin Henley
    I need to find all monomials in the form AX that when evaluated falls within a range from m to n. It is safe to say that the base A is greater than 1, the power X is greater than 2, and only integers need to be used. For example, in the range 50 to 100, the solutions would be: 2^6 3^4 4^3 My first attempt to solve this was to brute force all combinations of A and X that make "sense." However this becomes too slow when used for very large numbers in a big range since these solutions are used in part of much more intensive processing. Here is the code: def monoSearch(min, max): base = 2 power = 3 while 1: while base**power < max: if base**power > min: print "Found " + repr(base) + "^" + repr(power) + " = " + repr(base**power) power = power + 1 base = base + 1 power = 3 if base**power > max: break I could remove one base**power by saving the value in a temporary variable but I don't think that would make a drastic effect. I also wondered if using logarithms would be better or if there was a closed form expression for this. I am open to any optimizations or alternatives to finding the solutions.

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  • Defining the hash of an object as the sum of hashes of its members

    - by Space_C0wb0y
    I have a class that represents undirected edges in a graph. Every edge has two members vertex1 and vertex2 representing the vertices it connects. The problem is, that an edge can be specified two directions. My idea was now to define the hash of an edge as the sum of the hashes of its vertices. This way, the direction plays no role anymore, the hash would be the same. Are there any pitfalls with that?

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  • Elegant way to add functionallity to previously defined functions

    - by Bastiaan
    How to combine two functions together I have a class controlling some hardware: class Heater() def set_power(self,dutycycle, period) ... def turn_on(self) ... def turn_off(self) And a class that connects to a database and handles all data logging fuctionallity for an experiment: class DataLogger() def __init__(self) # Record measurements and controls in a database def start(self,t) # Starts a new thread to aqcuire and reccord measuements every t secconds Now, in my program recipe.py I want to do something like: log = DataLogger() @DataLogger_decorator H1 = Heater() log.start(60) H1.set_power(10,100) H1.turn_on() sleep(10) H1.turn_off() etc Where all actions on H1 are recorded by the datalogger. I can change any of the classes involved, just looking for an elegant way to do this. Ideally the hardware functions remain separated from the database and DataLogger functions. And ideally the DataLogger is reusable for other controls and measurements.

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  • How do I assign functions in a dictionary?

    - by Ziv
    hi, I'm having a problem with a simple program I wrote, I want to perform a certain function according to the users input. I've already used a dictionary as a replacement for a switch to do assignment but when I try to assign functions to the dictionary it doesn't execute them... The code: def PrintValuesArea(): ## do this def PrintValuesLength(): ## do that def PrintValuesTime(): ## do third PrintTables={"a":PrintValuesArea,"l":PrintValuesLength,"t":PrintValuesTime} PrintTables.get(ans.lower()) ## ans is the user input what did I do wrong? It looks the same as all the examples I've seen....

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  • Object for storing strings geted from prints

    - by evg
    class MyWriter: def __init__(self, stdout): self.stdout = stdout self.dumps = [] def write(self, text): self.stdout.write(smart_unicode(text).encode('cp1251')) self.dumps.append(text) def close(self): self.stdout.close() writer = MyWriter(sys.stdout) save = sys.stdout sys.stdout = writer I use self.dumps list to store geted data from prints. Is it exists more convinient object for storing string lines in memory? ideally i want dump it to one big string. I can get it like this "\n".join(self.dumps) from code above. Mb it's better to just concat strings - self.dumps += text ?

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  • How to merge or copy anonymous session data into user data when user logs in?

    - by benhoyt
    This is a general question, or perhaps a request for pointers to other open source projects to look at: I'm wondering how people merge an anonymous user's session data into the authenticated user data when a user logs in. For example, someone is browsing around your websites saving various items as favourites. He's not logged in, so they're saved to an anonymous user's data. Then he logs in, and we need to merge all that data into their (possibly existing) user data. Is this done different ways in an ad-hoc fashion for different applications? Or are there some best practices or other projects people can direct me to?

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  • How to compare two lists with duplicated items in one list?

    - by eladc
    I need to compare list_a against many others. my problem starts when there's a duplicated item in the other lists (two k's in other_b). my goal is to filter out all the lists with the same items (up to three matching items). list_a = ['j','k','a','7'] other_b = ['k', 'j', 'k', 'q'] other_c = ['k','k','9','k'] >>>filter(lambda x: not x in list_a,other_b) ['q'] I need a way that would return ['k', 'q'], because 'k' appears only once in list_a. comparing list_a and other_c with set() isn't good for my purpose since it will return only one element: k. while I need ['k','9','k'] I hope I was clear enough. Thank you

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  • command line arg?

    - by kaushik
    This is a module named XYZ. def func(x) ..... ..... if __name__=="__main__": print func(sys.argv[1]) Now I have imported this module in another code and want to use the func. How can i use it? import XYZ After this, where to give the argument, and syntax on how to call it, please?

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  • does webapp has 'elseif' or 'elif' in template tags..

    - by zjm1126
    my code is : Hello!~~~ {% if user %} <p>Logged in as {{ user.first_name }} {{ user.last_name }}.</p> {% elif openid_user%} <p>Hello, {{openid_user.nickname}}! Do you want to <a href="{{openid_logout_url}}">Log out?</p> {% else %} <p><a href="/login?redirect={{ current_url }}">google Log in</a>.</p> <p><a href="/twitter">twitter Log in</a>.</p> <p><a href="/facebook">facebook Log in</a>.</p> <p><a href="{{openid_login_url}}">openid Log in</a>.</p> <iframe src="/_openid/login?continue=/"></iframe> {% endif %} the error is : TemplateSyntaxError: Invalid block tag: 'elif' does not webapp has a 'else if ' ? thanks

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  • list in loop, Nonetype errors

    - by user2926755
    Here is my Code def printList(stringlist): empty = [] if stringlist is None: print empty else: print stringlist def add (stringlist, string): string = [] if string is None else string if stringlist is not None: stringlist.insert(0, string) else: stringlist.append(1) it somehow appears "AttributeError: 'NoneType' object has no attribute 'append'" I was originally looking for the code to be run like this: >>> myList = None >>> printList(myList) [] >>> for word in ['laundry','homework','cooking','cleaning']: myList = add(myList, word) printList(myList) [laundry] [homework, laundry] [cooking, homework, laundry] [cleaning, cooking, homework, laundry]

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  • Sqlalchemy: Many to Many relationship error

    - by 1001010101
    Dear everyone, I am following the Many to many relationship described on http://www.sqlalchemy.org/docs/mappers.html#many-to-many #This is actually a VIEW tb_mapping_uGroups_uProducts = Table( 'mapping_uGroups_uProducts', metadata, Column('upID', Integer, ForeignKey('uProductsInfo.upID')), Column('ugID', Integer, ForeignKey('uGroupsInfo.ugID')) ) tb_uProducts = Table( 'uProductsInfo', metadata, Column('upID', Integer, primary_key=True) ) mapper( UnifiedProduct, tb_uProducts) tb_uGroupsInfo = Table( 'uGroupsInfo', metadata, Column('ugID', Integer, primary_key=True) ) mapper( UnifiedGroup, tb_uGroupsInfo, properties={ 'unifiedProducts': relation(UnifiedProduct, secondary=tb_mapping_uGroups_uProducts, backref="unifiedGroups") }) where the relationship between uProduct and uGroup are N:M. When I run the following sess.query(UnifiedProduct).join(UnifiedGroup).distinct()[:10] I am getting the error: sqlalchemy.exc.ArgumentError: Can't find any foreign key relationships between 'uProductsInfo' and 'uGroupsInfo' What am I doing wrong?

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  • delete common dictionaries in list based on a value

    - by pythoonatic
    How would I delete all corresponding dictionaries in a list of dictionaries based on one of the dictionaries having a character in it. data = [ { 'x' : 'a', 'y' : '1' }, { 'x' : 'a', 'y' : '1/1' }, { 'x' : 'a', 'y' : '2' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, ] For example, how would I delete all of the x = a due to one of the y in the x=a having a / in it? Based on the example data above, here is where I would like to get to: cleaneddata = [ { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, ]

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  • nested list comprehension using intermediate result

    - by KentH
    I am trying to grok the output of a function which doesn't have the courtesy of setting a result code. I can tell it failed by the "error:" string which is mixed into the stderr stream, often in the middle of a different conversion status message. I have the following list comprehension which works, but scans for the "error:" string twice. Since it is only rescanning the actual error lines, it works fine, but it annoys me I can't figure out how to use a single scan. Here's the working code: errors = [e[e.find('error:'):] for e in err.splitlines() if 'error:' in e] The obvious (and wrong) way to simplify is to save the "find" result errors = [e[i:] for i in e.find('error:') if i != -1 for e in err.splitlines()] However, I get "UnboundLocalError: local variable 'e' referenced before assignment". Blindly reversing the 'for's in the comprehension also fails. How is this done? THanks. Kent

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