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  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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  • Looping through array in PHP to post several multipart form-data

    - by Léon Pelletier
    I'm trying in an asp web application to code a function that would loop through a list of files in a multiple upload form and send them one by one. Is this something that can be done in ASP? Because I've read some posts about how to attach several files together, but saw nothing about looping through the files. I can easily imagine it in C# via HttpWebRequest or with socket, but in php, I guess there are already function designed to handle it? // This is false/pseudo-code :) for (int index = 0; index < number_of_files; index++) { postfile(file[index]); } And in each iteration, it should send a multipart form-data POST. postfile(TheFileInfos) should make a POST like it: POST /afs.aspx?fn=upload HTTP/1.1 [Header stuff] Content-Type: multipart/form-data; boundary=----------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 [Header stuff] ------------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 Content-Disposition: form-data; name="Filename" myimage1.png ------------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 Content-Disposition: form-data; name="fileid" 58e21ede4ead43a5201206101806420000007667212251 ------------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 Content-Disposition: form-data; name="Filedata"; filename="myimage1.png" Content-Type: application/octet-stream [Octet Stream] [Edit] I'll try it: <html> <head> <title>Untitled Document</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> </head> <body> <form name="form1" enctype="multipart/form-data" method="post" action="processFiles.php"> <p> <? // start of dynamic form $uploadNeed = $_POST['uploadNeed']; for($x=0;$x<$uploadNeed;$x++){ ?> <input name="uploadFile<? echo $x;?>" type="file" id="uploadFile<? echo $x;?>"> </p> <? // end of for loop } ?> <p><input name="uploadNeed" type="hidden" value="<? echo $uploadNeed;?>"> <input type="submit" name="Submit" value="Submit"> </p> </form> </body> </html>

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • Adding Insert Row in tableView

    - by user333624
    Hello everyone, I have a tableView that loads its data directly from a Core Data table with a NSFetchedResultsController. I'm not using an intermediate NSMutableArray to store the objects from the fetch results; I basically implemented inside my UITableViewController the protocol method numberOfRowsInSection and it returns the numberOfObjects inside a NSFetchedResultsSectionInfo. id <NSFetchedResultsSectionInfo> sectionInfo = [[fetchedResultsController sections] objectAtIndex:section]; and then I configure the cell content by implementing configureCell:atIndexPath and retrieving object info from the fetchedResultController but right now I have a generic configuration for any object (to avoid complications) cell.textLabel.text = @"categoria"; I also have a NavigationBar with a custom edit button at the right that loads my own selector called customSetEditing. What I'm trying to accomplish is to load an "Insert Cell" at the beginning of the tableView so when I tap it, it creates a new record. This last part is easy to implement the problem is that I dont's seem to be able to load the insert row or any row when I tap on the navigation bar edit button. this is the code for my customSetEditing: - (void) customSetEditing { [super setEditing:YES animated:YES]; [self.tableView setEditing:YES animated:YES]; [[self tableView] beginUpdates]; //[[self tableView] beginUpdates]; UIBarButtonItem *customDoneButtonItem = [[UIBarButtonItem alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemDone target:self action:@selector(customDone)]; [self.navigationItem.rightBarButtonItem release]; self.navigationItem.rightBarButtonItem = customDoneButtonItem; //[categoriasArray insertObject:[NSNull null] atIndex:0]; NSMutableArray *indexPaths = [[NSMutableArray alloc] initWithObjects:[NSIndexPath indexPathForRow:0 inSection:0],nil ]; [self.tableView insertRowsAtIndexPaths:indexPaths withRowAnimation:UITableViewRowAnimationTop]; //[indexPaths release]; [self.tableView reloadData];} Before adding the:[self.tableView reloadData]; I was getting an out of bounds error plus a program crash and although the program is not crashing it is not loading anything. I have seen many examples of similar situations in stackoverflow (by the way is an excellent forum with very helpful and nice people) none of the examples seems to work for me. Any ideas?

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  • Wordpress plugin $post

    - by Jordan Pagaduan
    I have already get how to insert in the database. My only problem is to get the value of text box to insert in the database. Here is my code: function dbAdd() { global $wpdb; $new_title = $_POST['new_title']; $new_author = $_POST['new_author']; $new_url = $_POST['new_url']; if($wpdb->insert('wp_podcast_data', array( 'mp3_id' => '', 'title' => '$new_title', 'creator' => '$new_author', 'url' => '$new_url') )) { echo"<h1>Save Successfully!</h1>"; }else { echo mysql_error(); } } ---------------------------------------------------------- function player_manager_index() { if($_SERVER['REQUEST_METHOD']=='POST') { dbAdd(); } ?> <h3>Podcast Player Manager (This Plug is not yet finish)</h3><br /> <p>Note: This Player Manager needs the URL of mp3 file that you want to include in your podcast player.</p> <form method="post" action=""> <label for="new_title" style="display:block; padding-top: 5px; cursor: default;">Title</label><input type="text" id="new_title" name="new_title" size="50" /> <label for="new_author" style="display:block; padding-top: 5px; cursor: default;">Author</label><input type="text" id="new_author" name="new_author" size="50" /> <label for="new_url" style="display:block; padding-top: 5px; cursor: default;">URL</label><input type="text" id="new_url" name="new_url" size="50" /> <div><input type="submit" value="Add New" style="margin-left: 20px; margin-top: 15px;" /></div> </form> Please Help me. I'm newbie in wordpress. Thank you so much.

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  • How can i put my form value in javascript array

    - by Lucas van den Abbeele
    I want to make a script where i can put my form in the javascript array invoer[] and display the total It constantly stops working and i searched a lot, i really can't find the right way :D This is my javascript code var strijk = ['broek', 'hemd', 'tshirt', 'lakens', 'korte broek', 'babykledij']; var minuten = [5, 10, 5, 6, 3, 3]; function invoerstrijk() { document.write("<form action='' method='get' name='strijkform'>"); for (var a = 0; a < minuten.length; a++) { document.write(strijk[a] + "<input id='" + strijk[a] + "' name ='" + strijk[a] + "' type='text' />" + "<BR>"); } document.write("<button onclick='opgeven()'>opgeven</button>"); document.write("</form>"); } function opgeven() { var invoer = []; for (var a = 0; a < minuten.length; a++) { invoer[a] = document.getElementByI(strijk[a]).value; } var totaal; for (var a = 0; a < minuten.length; a++) { totaal += parseint(invoer[a]) * parseint(minuten[a]); } document.write("<input name=" + strijk[a] + " type='text' value=" + invoer[a] + " readonly />"); if (invoer != []) { document.write("totaal aantal minuten" + totaal); } else { document.write("geen invoer"); } } my html looks likes this <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <script type="text/javascript" > //my javasccript </script> <button id="B1" onclick="invoerstrijk()" >Nieuwe strijk</button> </body> </html>

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  • MVC | Linq Update Query | Help!

    - by 109221793
    Hi guys, I'm making modifications to a C# MVC application that I've inherited. I have a database, and for simplicity I'll just focus on the two tables I'm working with for this linq query. Item ItemID Int PK ItemName RepairSelection (Yes or No) RepairID Int FK Repair RepairID Int PK RepairCategory SubmissionDate DateSentForRepair Ok, so ItemID is pretty much the identifier, and the View to display the Repair details goes like this (snippet): <%= Html.LabelFor(x => x.ItemID)%> <%= Html.DisplayFor(x => x.ItemID)%><br /> <%= Html.LabelFor(x => x.Repair.RepairCategory)%> <%= Html.DisplayFor(x => x.Repair.RepairCategory, "FormTextShort")%><br /> <%= Html.LabelFor(x => x.Repair.SubmissionDate)%> <%= Html.DisplayFor(x => x.Repair.SubmissionDate)%><br /> <%= Html.LabelFor(x => x.Repair.DateSentForRepair)%> <%= Html.DisplayFor(x => x.Repair.DateSentForRepair)%><br /> <%= Html.ActionLink("Edit Repair Details", "Edit", new { ItemID= Model.ItemID})%> Here is the GET Edit action: public ActionResult Edit(Int64? itemId) { ModelContainer ctn = new ModelContainer(); var item = from i in ctn.Items where i.ItemID == itemId select i; return View(item.First()); } This is also fine, the GET Edit view displays the right details. Where I'm stuck is the linq query to update the Repair table. I have tried it so many ways today that my head is just fried (new to Linq as you may have guessed). My latest try is here (which I know is way off so go easy ;-) ): [HttpPost] public ActionResult Edit(Int64 itemId, Repair repair, Item item, FormCollection formValues) { if (formValues["cancelButton"] != null) { return RedirectToAction("View", new { ItemID = itemId }); } ModelContainer ctn = new ModelContainer(); Repair existingData = ctn.Repair.First(a => a.RepairId == item.RepairID && item.ItemID == itemId); existingData.SentForConversion = DateTime.Parse(formValues["SentForConversion"]); ctn.SaveChanges(); return RedirectToAction("View", new { ItemID = itemId }); } For the above attempt I get a Sequence Contains No Elements error. Any help or pointers would be appreciated. Thanks guys.

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  • [NHibernate and ASP.NET MVC] How can I implement a robust session-per-request pattern in my project,

    - by Guillaume Gervais
    I'm currently building an ASP.NET MVC project, with NHibernate as its persistance layer. For now, some functionnalities have been implemented, but only use local NHibernate sessions: each method that accessed the database (read or write) needs to instanciate its own NHibernate session, with the "using()" directive. The problem is that I want to leverage NHibernate's Lazy-Loading capabilities to improve the performance of my project. This implies an open NHibernate session per request until the view is rendered. Furthermore, simultaneous request must be supported (multiple Sessions at the same time). How can I achieve that as cleanly as possible? I searched the Web a little bit and learned about the session-per-request pattern. Most of the implementations I saw used some sort of Http* (HttpContext, etc.) object to store the session. Also, using the Application_BeginRequest/Application_EndRequest functions is complicated, since they get fired for each HTTP request (aspx files, css files, js files, etc.), when I only want to instanciate a session once per request. The concern that I have is that I don't want my views or controllers to have access to NHibernate sessions (or, more generally, NHibernate namespaces and code). That means that I do not want to handle sessions at the controller level nor the view one. I have a few options in mind. Which one seems the best ? Use interceptors (like in GRAILS) that get triggered before and after the controller action. These would open and close sessions/transactions. Is it possible in the ASP.NET MVC world? Use the CurrentSessionContext Singleton provided by NHibernate in a Web context. Using this page as an example, I think this is quite promising, but that still requires filters at the controller level. Use the HttpContext.Current.Items to store the request session. This, coupled with a few lines of code in Global.asax.cs, can easily provide me with a session on the request level. However, it means that dependencies will be injected between NHibernate and my views (HttpContext). Thank you very much!

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  • Trying to run multiple HTTP requests in parallel, but being limited by Windows (registry)

    - by Nailuj
    I'm developing an application (winforms C# .NET 4.0) where I access a lookup functionality from a 3rd party through a simple HTTP request. I call an url with a parameter, and in return I get a small string with the result of the lookup. Simple enough. The challenge is however, that I have to do lots of these lookups (a couple of thousands), and I would like to limit the time needed. Therefore I would like to run requests in parallel (say 10-20). I use a ThreadPool to do this, and the short version of my code looks like this: public void startAsyncLookup(Action<LookupResult> returnLookupResult) { this.returnLookupResult = returnLookupResult; foreach (string number in numbersToLookup) { ThreadPool.QueueUserWorkItem(lookupNumber, number); } } public void lookupNumber(Object threadContext) { string numberToLookup = (string)threadContext; string url = @"http://some.url.com/?number=" + numberToLookup; WebClient webClient = new WebClient(); Stream responseData = webClient.OpenRead(url); LookupResult lookupResult = parseLookupResult(responseData); returnLookupResult(lookupResult); } I fill up numbersToLookup (a List<String>) from another place, call startAsyncLookup and provide it with a call-back function returnLookupResult to return each result. This works, but I found that I'm not getting the throughput I want. Initially I thought it might be the 3rd party having a poor system on their end, but I excluded this by trying to run the same code from two different machines at the same time. Each of the two took as long as one did alone, so I could rule out that one. A colleague then tipped me that this might be a limitation in Windows. I googled a bit, and found amongst others this post saying that by default Windows limits the number of simultaneous request to the same web server to 4 for HTTP 1.0 and to 2 for HTTP 1.1 (for HTTP 1.1 this is actually according to the specification (RFC2068)). The same post referred to above also provided a way to increase these limits. By adding two registry values to [HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Internet Settings] (MaxConnectionsPerServer and MaxConnectionsPer1_0Server), I could control this myself. So, I tried this (sat both to 20), restarted my computer, and tried to run my program again. Sadly though, it didn't seem to help any. I also kept an eye on the Resource Monitor (see screen shot) while running my batch lookup, and I noticed that my application (the one with the title blacked out) still only was using two TCP connections. So, the question is, why isn't this working? Is the post I linked to using the wrong registry values? Is this perhaps not possible to "hack" in Windows any longer (I'm on Windows 7)? Any ideas would be highly appreciated :) And just in case anyone should wonder, I have also tried with different settings for MaxThreads on ThreadPool (everyting from 10 to 100), and this didn't seem to affect my throughput at all, so the problem shouldn't be there either.

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  • jQuery - Form input return confirm to delete

    - by bruno
    hello guys. I struggled a lot before posting here :) now, I want to replace my default javascript confirmation for deleting a file. I saw a lot of examples here, but no example with form input. Now I have his form: <form action="delete.php" method="post"> <input type="hidden" name="id" value="<{$pid}>" /> <input type="hidden" name="picture" value="<{$lang_del_pic}>" /> <input type="image" src="<{xoImgUrl}>img/del-icon.gif" width="16" height="16" align="bottom" border="0" alt="Delete media" name="pictured" value="<{$lang_del_pic}>" onclick="javascript: return confirm('<{$lang_confirm_del}>');" /> </form> Now, I did everything, I have this div: <div id="dialog-confirm" title="Empty the recycle bin?"> <p><span class="ui-icon ui-icon-alert" style="float:left; margin:0 7px 20px 0;"></span>These items will be permanently deleted and cannot be recovered. Are you sure?</p> </div> this javascript: <script type="text/javascript"> $(document).ready(function() { $("#dialog").dialog({ autoOpen: false, modal: true }); }); $(".confirmLink").click(function(e) { e.preventDefault(); var targetUrl = $(this).attr("href"); $("#dialog").dialog({ buttons : { "Confirm" : function() { window.location.href = targetUrl; }, "Cancel" : function() { $(this).dialog("close"); } } }); $("#dialog").dialog("open"); }); </script> and this new form: <form name="dialog-confirm" id="dialog-confirm" method="post"> <input type="hidden" name="id" value="<{$pid}>" /> <input type="hidden" name="picture" value="<{$lang_del_pic}>" /> <input type="image" src="<{xoImgUrl}>img/del-icon.gif" width="16" height="16" align="bottom" border="0" alt="Delete media" name="pictured" value="" id="opener" /> </form> On press, I call successfuly the jQuery modal diolog, and everything works, but somehow, when I press 'delete all' the script tells me - "the script is called without the necessary parameters" Now I guess I am failig to send the pic ID to be deleted with the jQuery, .. but do not know how to fix it. Any ideas ?

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  • Assign value to HTML textbox from JSP

    - by prakash_d22
    Hello I am creating a web page to add some information about given product.I need to enter id,name,description and image as information.I need the id to be auto generated.I am using jsp and database as access.I am fetching the count(*)+1 value from database and assigning to my html text box but its showing as null.can i get some help? Code: <body> <%@page import="java.sql.*"%> <%! String no; %> <% try{ Class.forName("sun.jdbc.odbc.JdbcOdbcDriver"); Connection con = DriverManager.getConnection("jdbc:odbc:pd"); ResultSet rs = null; Statement st = con.createStatement(); String sql = ("select count(*)+1 from products"); st.executeUpdate(sql); while (rs.next()) { no=rs.getString("count(*)+1"); } rs.close(); st.close(); con.close(); } catch(Exception e){} %> <Form name='Form1' action="productcode.jsp" method="post"> <table width="1024" border="0"> <tr> <td width="10">&nbsp;</td> <td width="126">Add Product: </td> <td width="277">&nbsp;</td> <td width="583">&nbsp;</td> </tr> <tr> <td>&nbsp;</td> <td>Product Id:</td> <td><label> <input type="text" name="id" value="<%= no%>"/> </label></td> <td>&nbsp;</td> .... and so on

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  • Code Golf: Countdown Number Game

    - by Noldorin
    Challenge Here is the task, inspired by the well-known British TV game show Countdown. The challenge should be pretty clear even without any knowledge of the game, but feel free to ask for clarifications. And if you fancy seeing a clip of this game in action, check out this YouTube clip. It features the wonderful late Richard Whitely in 1997. You are given 6 numbers, chosen at random from the set {1, 2, 3, 4, 5, 6, 8, 9, 10, 25, 50, 75, 100}, and a random target number between 100 and 999. The aim is to make use the six given numbers and the four common arithmetic operations (addition, subtraction, multiplication, division; all over the rational numbers) to generate the target - or as close as possible either side. Each number may only be used once at most, while each arithmetic operator may be used any number of times (including zero.) Note that it does not matter how many numbers are used. Write a function that takes the target number and set of 6 numbers (can be represented as list/collection/array/sequence) and returns the solution in any standard numerical notation (e.g. infix, prefix, postfix). The function must always return the closest-possible result to the target, and must run in at most 1 minute on a standard PC. Note that in the case where more than one solution exists, any single solution is sufficient. Examples: {50, 100, 4, 2, 2, 4}, target 203 e.g. 100 * 2 + 2 + (4 / 4) e.g. (100 + 50) * 4 * 2 / (4 + 2) {25, 4, 9, 2, 3, 10}, target 465 e.g. (25 + 10 - 4) * (9 * 2 - 3) {9, 8, 10, 5, 9, 7), target 241 e.g. ((10 + 9) * 9 * 7) + 8) / 5 Rules Other than mentioned in the problem statement, there are no further restrictions. You may write the function in any standard language (standard I/O is not necessary). The aim as always is to solve the task with the smallest number of characters of code. Saying that, I may not simply accept the answer with the shortest code. I'll also be looking at elegance of the code and time complexity of the algorithm! My Solution I'm attempting an F# solution when I find the free time - will post it here when I have something! Format Please post all answers in the following format for the purpose of easy comparison: Language Number of characters: ??? Fully obfuscated function: (code here) Clear (ideally commented) function: (code here) Any notes on the algorithm/clever shortcuts it takes.

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • how to upload a audio file using REST webservice in Google App Engine for Java

    - by sathya
    Am using google app engine with eclipse IDE and trying to upload a audio file. I used the File Upload in Google App Engine For Java and can able to upload the file successfully. Now am planning to use REST web service for it. I had analyzed in developers.google but i failed. Can anyone suggest me how to implement REST Web services in google app engine using Eclipse. The code google provided is shown below, // file Upload.java public class Upload extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException { Map<String, BlobKey> blobs = blobstoreService.getUploadedBlobs(req); BlobKey blobKey = blobs.get("myFile"); if (blobKey == null) { res.sendRedirect("/"); } else { res.sendRedirect("/serve?blob-key=" + blobKey.getKeyString()); }}} // file Serve.java public class Serve extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doGet(HttpServletRequest req, HttpServletResponse res) throws IOException { BlobKey blobKey = new BlobKey(req.getParameter("blob-key")); blobstoreService.serve(blobKey, res); }} // file index.jsp <%@ page import="com.google.appengine.api.blobstore.BlobstoreServiceFactory" %> <%@ page import="com.google.appengine.api.blobstore.BlobstoreService" %> <% BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); %> <form action="<%= blobstoreService.createUploadUrl("/upload") %>" method="post" enctype="multipart/form-data"> <input type="file" name="myFile"> <input type="submit" value="Submit"> </form> // web.xml <servlet> <servlet-name>Upload</servlet-name> <servlet-class>Upload</servlet-class> </servlet> <servlet> <servlet-name>Serve</servlet-name> <servlet-class>Serve</servlet-class> </servlet> <servlet-mapping> <servlet-name>Upload</servlet-name> <url-pattern>/upload</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Serve</servlet-name> <url-pattern>/serve</url-pattern> </servlet-mapping> Now how to provide a rest web service for the above code. Kindly suggest me an idea.

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  • why resubmit after refresh php page

    - by user2719452
    why resubmit after refresh php page? try it, go to: http://qass.im/message-envelope/ and upload any image now try click F5, after refresh page "resubmit" Why? I don't want resubmit after refresh page What is the solution? See this is my form code: <form id="uploadedfile" name="uploadedfile" enctype="multipart/form-data" action="upload.php" method="POST"> <input name="uploadedfile" type="file" /> <input type="submit" value="upload" /> </form> See this is php code upload.php file: <?php $allowedExts = array("gif", "jpeg", "jpg", "png", "zip", "pdf", "docx", "rar", "txt", "doc"); $temp = explode(".", $_FILES["uploadedfile"]["name"]); $extension = end($temp); $newname = $extension.'_'.substr(str_shuffle(str_repeat("0123456789abcdefghijklmnopqrstuvwxyz", 7)), 4, 7); $imglink = 'attachment/attachment_file_'; $uploaded = $imglink .$newname.'.'.$extension; if ((($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpg") || ($_FILES["uploadedfile"]["type"] == "image/pjpeg") || ($_FILES["uploadedfile"]["type"] == "image/x-png") || ($_FILES["uploadedfile"]["type"] == "image/gif") || ($_FILES["uploadedfile"]["type"] == "image/png") || ($_FILES["uploadedfile"]["type"] == "application/msword") || ($_FILES["uploadedfile"]["type"] == "text/plain") || ($_FILES["uploadedfile"]["type"] == "application/vnd.openxmlformats-officedocument.wordprocessingml.document") || ($_FILES["uploadedfile"]["type"] == "application/pdf") || ($_FILES["uploadedfile"]["type"] == "application/x-rar-compressed") || ($_FILES["uploadedfile"]["type"] == "application/x-zip-compressed") || ($_FILES["uploadedfile"]["type"] == "application/zip") || ($_FILES["uploadedfile"]["type"] == "multipart/x-zip") || ($_FILES["uploadedfile"]["type"] == "application/x-compressed") || ($_FILES["uploadedfile"]["type"] == "application/octet-stream")) && ($_FILES["uploadedfile"]["size"] < 5242880) // Max size is 5MB && in_array($extension, $allowedExts)) { move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], $uploaded ); echo '<a target="_blank" href="'.$uploaded.'">click</a>'; // If has been uploaded file echo '<h3>'.$uploaded.'</h3>'; } if($_FILES["uploadedfile"]["error"] > 0){ echo '<h3>Please choose file to upload it!</h3>'; // If you don't choose file } elseif(!in_array($extension, $allowedExts)){ echo '<h3>This extension is not allowed!</h3>'; // If you choose file not allowed } elseif($_FILES["uploadedfile"]["size"] > 5242880){ echo "Big size!"; // If you choose big file } ?> if you have solution, please edit my php code and paste your solution code! Thanks.

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  • I am unsure of how to access a persistence entity from a JSP page?

    - by pharma_joe
    Hi, I am just learning Java EE, I have created a Persistence entity for a User object, which is stored in the database. I am now trying to create a JSP page that will allow a client to enter a new User object into the System. I am unsure of how the JSP page interacts with the User facade, the tutorials are confusing me a little. This is the code for the facade: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Add User to System</title> </head> <body> <h2>Add User</h2> <h3>Please fill out the details to add a user to the system</h3> <form action=""> <label>Email:</label> <input type="text" name="email"><br /> <label>Password:</label> <input type="password" name="name"><br /> <label>Name:</label> <input type="text" name="name"><br /> <label>Address:</label> <input type="text" name="address"><br /> <label>Type:</label> <select name="type"> <option>Administrator</option> <option>Member</option> </select><br /> <input type="submit" value="Add" name="add"/> <input type="reset" value="clear" /> </form> </body> This is the code I have to add a new User object within the User facade class: @Stateless public class CinemaUserFacade { @PersistenceContext(unitName = "MonashCinema-warPU") private EntityManager em; public void create(CinemaUser cinemaUser) { em.persist(cinemaUser); } I am finding it a little difficult to get my head around the whole MVC thing, getting there but would appreciate it if someone could turn the light on for me!

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  • Crystal Reports : How to add an external assembly class?

    - by Sunil
    I am using VS2010, CrystalReport13 & MVC3. My problem is unable to add an external assembly in Crystal Report using "Database Expert" Option. I have a class named WeeklyReportModel in an external assembly. In my web project, data retrieving from DB as IEnumerable collection of WeeklyReportModel. I tried ProjectData - .NetObjects in Crystal Report for adding the WeeklyReportModel. But this external assembly is not showing under ".NetObjects". Then I tried other option as Create New Connection - ADO.Net – Make New Connection and pointed this External Assembly. It has been added under Ado.Net node, but while expanding displays as "...no items found..." Totally frustrated. Please help. External Assembly Class: namespace SMS.Domain { public class WeeklyReportModel { public int StoreId { get; set; } public string StoreName{ get; set; } public decimal Saturday { get; set; } public decimal Sunday { get; set; } public decimal Monday { get; set; } public decimal Tuesday { get; set; } public decimal Wednesday { get; set; } public decimal Thurday { get; set; } public decimal Friday { get; set; } public decimal Average { get; set; } public string DateRange { get; set; } } } In Controller-action[Data retrieving as Collection Of WeeklyReportModel] namespace SMS.UI.Controllers { public class ReportController : Controller { public ActionResult StoreWeeklyReport(string id) { DateTime weekStart, weekClose; string[] dateArray = id.Split('_'); weekStart = Convert.ToDateTime(dateArray[0].ToString()); weekClose = Convert.ToDateTime(dateArray[1].ToString()); SMS.Infrastructure.Report.AuditReport weeklyReport = new SMS.Infrastructure.Report.AuditReport(); IEnumerable<SMS.Domain.WeeklyReportModel> weeklyRpt = weeklyReport.ReportByStore().WeeklyReport(weekStart, weekClose); Session["WeeklyData"] = weeklyRpt; Response.Redirect("~/Reports/Weekly/StoreWeekly.aspx"); return View(); } } } Thanks in advance.

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  • jquery ajax form success callback not being called

    - by Michael Merchant
    I'm trying to upload a file using "AJAX", process data in the file and then return some of that data to the UI so I can dynamically update the screen. I'm using the JQuery Ajax Form Plugin, jquery.form.js found at http://jquery.malsup.com/form/ for the javascript and using Django on the back end. The form is being submitted and the processing on the back end is going through without a problem, but when a response is received from the server, my Firefox browser prompts me to download/open a file of type "application/json". The file has the json content that I've been trying to send to the browser. I don't believe this is an issue with how I'm sending the json as I have a modularized json_wrapper() function that I'm using in multiple places in this same application. Here is what my form looks after Django templates are applied: <form method="POST" enctype="multipart/form-data" action="/test_suites/active/upload_results/805/"> <p> <label for="id_resultfile">Upload File:</label> <input type="file" id="id_resultfile" name="resultfile"> </p> </form> You won't see any submit buttons because I'm calling submit with a button else where and am using ajaxSubmit() from the jquery.form.js plugin. Here is the controlling javascript code: function upload_results($dialog_box){ $form = $dialog_box.find("form"); var options = { type: "POST", success: function(data){ alert("Hello!!"); }, dataType: "json", error: function(){ console.log("errors"); }, beforeSubmit: function(formData, jqForm, options){ console.log(formData, jqForm, options); }, } $form.submit(function(){ $(this).ajaxSubmit(options); return false; }); $form.ajaxSubmit(options); } As you can see, I've gotten desperate to see the success callback function work and simply have an alert message created on success. However, we never reach that call. Also, the error function is not called and the beforeSubmit function is executed. The file that I get back has the following contents: {"count": 18, "failed": 0, "completed": 18, "success": true, "trasaction_id": "SQEID0.231"} I use 'success' here to denote whether or not the server was able to run the post command adequately. If it failed the result would look something like: {"success": false, "message":"<error_message>"} Your time and help is greatly appreciated. I've spent a few days on this now and would love to move on.

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  • Wordpress Search Results in Order

    - by Brad Houston
    One of my clients websites, www.kevinsplants.co.uk is not showing the search results in alphabetical order, how do I go about ordering the results in alphabetical order? We are using the Shopp plugin and I believe its that plugin that is generating the results! Cheers, Brad case "orderby-list": if (isset($Shopp->Category->controls)) return false; if (isset($Shopp->Category->smart)) return false; $menuoptions = Category::sortoptions(); $title = ""; $string = ""; $default = $Shopp->Settings->get('default_product_order'); if (empty($default)) $default = "title"; if (isset($options['default'])) $default = $options['default']; if (isset($options['title'])) $title = $options['title']; if (value_is_true($options['dropdown'])) { if (isset($Shopp->Cart->data->Category['orderby'])) $default = $Shopp->Cart->data->Category['orderby']; $string .= $title; $string .= '<form action="'.esc_url($_SERVER['REQUEST_URI']).'" method="get" id="shopp-'.$Shopp->Category->slug.'-orderby-menu">'; if (!SHOPP_PERMALINKS) { foreach ($_GET as $key => $value) if ($key != 'shopp_orderby') $string .= '<input type="hidden" name="'.$key.'" value="'.$value.'" />'; } $string .= '<select name="shopp_orderby" class="shopp-orderby-menu">'; $string .= menuoptions($menuoptions,$default,true); $string .= '</select>'; $string .= '</form>'; $string .= '<script type="text/javascript">'; $string .= "jQuery('#shopp-".$Shopp->Category->slug."-orderby-menu select.shopp-orderby-menu').change(function () { this.form.submit(); });"; $string .= '</script>'; } else { if (strpos($_SERVER['REQUEST_URI'],"?") !== false) list($link,$query) = explode("\?",$_SERVER['REQUEST_URI']); $query = $_GET; unset($query['shopp_orderby']); $query = http_build_query($query); if (!empty($query)) $query .= '&'; foreach($menuoptions as $value => $option) { $label = $option; $href = esc_url($link.'?'.$query.'shopp_orderby='.$value); $string .= '<li><a href="'.$href.'">'.$label.'</a></li>'; } } return $string; break;

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  • PHP & MySQL - saving and looping problems.

    - by R.I.P.coalMINERS
    I'm new to PHP and MySQL I want a user to be able to store multiple names and there meanings in a MySQL database tables named names using PHP I will dynamically create form fields with JQuery every time a user clicks on a link so a user can enter 1 to 1,000,000 different names and there meanings which will be stored in a table called names. Since I asked my last question I figured out how to store my values from my form using the for loop but every time I loop my values when I add one or more dynamic fields the second form field named meaning will not save the value entered also my dynamic form fields keep looping doubling, tripling and so on the entered values into the database it all depends on how many form fields are added dynamically. I was wondering how can I fix these problems? On a side note I replaced the query with echo's to see the values that are being entered. Here is the PHP code. <?php if(isset($_POST['submit'])) { $mysqli = mysqli_connect("localhost", "root", "", "site"); $dbc = mysqli_query($mysqli,"SELECT * FROM names WHERE userID='$userID'"); $name = $_POST['name']; $meaning = $_POST['meaning']; if(isset($name['0']) && mysqli_num_rows($dbc) == 0 && trim($name['0'])!=='' && trim($meaning['0'])!=='') { for($n = 0; $n < count($name); $n++) { for($m = 0; $m < count($meaning); $m++) { echo $name[$n] . '<br />'; echo $meaning[$m] . '<br /><br />'; break; } } } } ?> And here is the HTML code. <form method="post" action="index.php"> <ul> <li><label for="name">Name: </label><input type="text" name="name[]" id="name" /></li> <li><label for="meaning">Meaning: </label><input type="text" name="meaning[]" id="meaning" /></li> <li><input type="submit" name="submit" value="Save" /></li> </ul> </form> If needed I will place the JQuery code.

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  • EJB / JSF java.lang.ClassNotFoundException: com.ericsantanna.jobFC.dao.DAOFactoryRemote from [Module "com.sun.jsf-impl:main" from local module loader

    - by Eric Sant'Anna
    I'm in my first time using EJB and JSF, and I can't resolve this: 20:23:12,457 Grave [javax.enterprise.resource.webcontainer.jsf.application] (http-localhost-127.0.0.1-8081-2) com.ericsantanna.jobFC.dao.DAOFactoryRemote from [Module "com.sun.jsf-impl:main" from local module loader @439db2b2 (roots: C:\jboss-as-7.1.1.Final\modules)]: java.lang.ClassNotFoundException: com.ericsantanna.jobFC.dao.DAOFactoryRemote from [Module "com.sun.jsf-impl:main" from local module loader @439db2b2 (roots: C:\jboss-as-7.1.1.Final\modules)] I'm getting this when I do an action like a selectOneMenu or a commandButton click. DAOFactory.class @Singleton @Remote(DAOFactoryRemote.class) public class DAOFactory implements DAOFactoryRemote { private static final long serialVersionUID = 6030538139815885895L; @PersistenceContext private EntityManager entityManager; @EJB private JobDAORemote jobDAORemote; /** * Default constructor. */ public DAOFactory() { // TODO Auto-generated constructor stub } @Override public JobDAORemote getJobDAO() { JobDAO jobDAO = (JobDAO) jobDAORemote; jobDAO.setEntityManager(entityManager); return jobDAO; } JobDAO.class @Stateless @Remote(JobDAORemote.class) public class JobDAO implements JobDAORemote { private static final long serialVersionUID = -5483992924812255349L; private EntityManager entityManager; /** * Default constructor. */ public JobDAO() { // TODO Auto-generated constructor stub } @Override public void insert(Job t) { entityManager.persist(t); } @Override public Job findById(Class<Job> classe, Long id) { return entityManager.getReference(classe, id); } @Override public Job findByName(Class<Job> clazz, String name) { return entityManager .createQuery("SELECT job FROM " + clazz.getName() + " job WHERE job.nome = :nome" , Job.class) .setParameter("name", name) .getSingleResult(); } ... TriggerFormBean.class @ManagedBean @ViewScoped @Stateless public class TriggerFormBean implements Serializable { private static final long serialVersionUID = -3293560384606586480L; @EJB private DAOFactoryRemote daoFactory; @EJB private TriggerManagerRemote triggerManagerRemote; ... triggerForm.xhtml (a portion with problem) </p:layoutUnit> <p:layoutUnit id="eastConditionPanel" position="center" size="50%"> <p:panel header="Conditions to Release" style="width:97%;height:97%;"> <h:panelGrid columns="2" cellpadding="3"> <h:outputLabel value="Condition Name:" for="conditionName" /> <p:inputText id="conditionName" value="#{triggerFormBean.newCondition.name}" /> </h:panelGrid> <p:commandButton value="Add Condition" update="conditionsToReleaseList" id="addConditionToRelease" actionListener="#{triggerFormBean.addNewCondition}" /> <p:orderList id="conditionsToReleaseList" value="#{triggerFormBean.trigger.conditionsToRelease}" var="condition" controlsLocation="none" itemLabel="#{condition.name}" itemValue="#{condition}" iconOnly="true" style="width:97%;heigth:97%;"/> </p:panel> </p:layoutUnit> In TriggerFormBean.class if comments daoFactory we get the same exception with triggerManagerRemote, both annotated with @EJB. I'm don't understand the relationship between my DAOFactory and the "Module com.sun.jsf-impl:main"... Thanks.

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  • mysql_fetch_array() expects parameter 1 to be resource problem

    - by user225269
    I don't get it, I see no mistakes in this code but there is this error, please help: mysql_fetch_array() expects parameter 1 to be resource problem <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO=".$_GET['id']); ?> <?php while ($row = mysql_fetch_array($result)) { ?> <table class="a" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="get" action="updateact.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Update Students</td> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $_GET['id']; ?>"></td> </tr> <tr> <td width="30" height="35"><font size="2">*Year:</td> <td width="30"><input name="yr" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $row["YEAR"]; ?>"></td> <?php } ?> I'm just trying to load the data in the forms but I don't know why that error appears. What could possibly be the mistake in here?

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  • Routing error when trying to use same view for update and create flows (Rails 3)

    - by Jamis Charles
    My overall use case: I have a Listing model that has many images. The Listing detail page lists all the fields that can be updated inline (through ajax). I want to be able to use the same view for both update listing and create new listing. My listing controller looks as follows: def detail @listing = Listing.find(params[:id]) @image = Image.new #should this link somewhere else? respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end def create # create a new listing and save it immediately. Assign it to guest, with a status of "draft" @listing = Listing.new(:price_id => 1) # Default price id # save it to db # TODO add validation that it has to have a price ID, on record creation. So the view doesn't break. @listing.save @image = Image.new # redirect_to "/listings/detail/@listing.id" #this didn't work respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end The PROBLEM I'm using a partial that shows the same form for the create view and the detail view. This works perfectly except for one thing: When I pull up http://0.0.0.0:3000/listings/detail/7, it works perfectly. When I pull up http://0.0.0.0:3000/listings/new, I get the following error: Showing /Applications/MAMP/htdocs/rails_testing/feedbackd/app/views/listings/_edit_form.html.erb where line #100 raised: No route matches {:action="show", :controller="images"} Extracted source (around line #100): 97: <!-- Form for new images --> 98: <div class="span-20 append-bottom"> 99: <!-- <%# form_for :image, @image, :url => image_path, :html => { :multipart => true } do |f| %> --> 100: <%= form_for @image, :url => image_path, :html => { :multipart => true } do |f| %> 101: <%= f.text_field :description %><br /> 102: <%= f.file_field :photo %> 103: <%= submit_tag "Upload" %> What I think the issue is: When I upload a new image (I'm using Paperclip), it requires the listing_id to create the image record. Since the listing_id isn't passed in with listings/new it can't find the listing_id. How can I pass in the id? Via a redirect? What's the best way to solve this? Thank you.

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  • How can I run an android frame animation without it skewing?

    - by GameDev123
    I have a small state machine that runs a series of frame by frame animations in an ImageView, in a nested hierarchy of layouts. There is more than adequate space to display each frame of the animation. Each frame of the animation is cropped to fit the minimum amount of area, in order to save memory. If a frame only contains 50x50 worth of pixels then the png is 50x50. There is no transparent padding to keep them the same size. The ImageView is directly within a RelativeLayout, and is anchored to the bottom left with some padding. The general idea being that the character in the animation performs some action, which results in individual frames of the animation growing or shrinking. The issue is that individual frames of animation are skewed, and there does not appear to be any way of preventing this. If I set the source of the imageview directly to one of the frames of animation, it displays fine in the layout manager. I have tried this with Adjust View Bounds set to true, false, and undefined. I have tried using the background and the src attribute of imageview to set the animation drawable, I have tried every configuration of layout manager and setting minimum/maximum size that I can think of, and it still stretches the character on various frames depending on the size of the source png. In essence, all I want to do is say "I want this ImageView to anchor in the bottom left and then display any frame that happens to be in it without stretching or skewing it in any way aside from that which occurred when the frame png's were loaded." Seems simple, but I have yet to come across any way of doing it. Here is the layout of the imageview as of my last test, I had to remove bits of the XML to get it to display but nothing pertinent: RelativeLayout android:orientation="horizontal" android:layout_above="@+id/MenuOptions" android:layout_width="fill_parent" android:id="@+id/AnimationLayout" android:clipChildren="false" android:minHeight="180dp" android:layout_height="fill_parent" android:layout_below="@+id/GameBarLayout" ImageView android:id="@+id/animatedImg" android:layout_height="wrap_content" android:layout_width="wrap_content" android:visibility="visible" android:baselineAlignBottom="true" android:minHeight="180dp" android:minWidth="200dp" android:adjustViewBounds="true" android:layout_alignParentBottom="true" android:paddingLeft="30dp" android:paddingBottom="10dp" android:src="@drawable/idle01"/ImageView /RelativeLayout Here is how an animation is set up: animationDrawable = new AnimationDrawable(); animationDrawable.addFrame(res.getDrawable(R.drawable.idle01), 16); animationDrawable.addFrame(res.getDrawable(R.drawable.idle02), 16); animationDrawable.addFrame(res.getDrawable(R.drawable.idle03), 16);

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  • jQuery slider onChange auto submit form

    - by bikey77
    I'm using a jQuery slider as a price range selector in a form. I'd like to have the form submit automatically when one of the values has been changed. I used a couple of examples I found on SO but they didn't work with my code. <form action="itemlist.php" method="post" enctype="application/x-www-form-urlencoded" name="priceform" id="priceform" target="_self"> <div id="slider-holder"> Prices: From <span id="pricefromlabel">100 &#8364;</span> To <span id="pricetolabel">500 &#8364;</span> <input type="hidden" id="pricefrom" name="pricefrom" value="100" /> <input type="hidden" id="priceto" name="priceto" value="500" /> <div id="slider-range"></div> <input name="Search" type="submit" value="Search" /> </div> </form> This is the code that displays the values of the slider and updates 2 hidden form fields I use to store the prices in order to submit: <script> $(function() { $("#slider-range" ).slider({ range: true, min: 0, max: 1000, values: [ <?=$minprice?>, <?=$maxprice?> ], start: function (event, ui) { event.stopPropagation(); }, slide: function( event, ui ) { $( "#pricefrom" ).val(ui.values[0]); $( "#priceto" ).val(ui.values[1]); $( "#pricefromlabel" ).html(ui.values[0] + ' &euro;'); $( "#pricetolabel" ).html(ui.values[1] + ' &euro;'); } }); return false; }); </script> I've tried adding this code as well as an data-autosubmit="true" attribute to the div but no result. $(function() { $('[data-autosubmit="true"]').change(function() { parentForm = $(this).('#priceform'); clearTimeout(submitTimeout); submitTimeout = setTimeout(function() { parentForm.submit() }, 100); }); I've also tried adding a $.post() event to the slider but I'm not very good with jQuery so I'm probably doing it wrong. Any help will be appreciated.

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