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  • How to had operation with character/items on binary with concrete operations on C++?

    - by Piperoman
    I have the next problem. A item can had a lot of states: NORMAL = 0000000 DRY = 0000001 HOT = 0000010 BURNING = 0000100 WET = 0001000 COLD = 0010000 FROZEN = 0100000 POISONED= 1000000 A item can had some states at same time but not all of them Is impossible to be dry and wet at same time. If you COLD a WET item, it turns into FROZEN. If you HOT a WET item, it turns into NORMAL A item can be BURNING and POISON Etc. I have try to set binary flags to states, and use AND to set operation to combine different states, checking before if is possible or not to do it, or change to another status. Exist a concrete patron to solve this problem efficiently without had a interminable switch that check every states with everynew states? It is relative easy to check 2 different states, but if exist a third state it is not trivial to do.

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  • Is this a pattern? Proxy/delegation of interface to existing concrete implementation

    - by Ian Newson
    I occasionally write code like this when I want to replace small parts of an existing implementation: public interface IFoo { void Bar(); } public class Foo : IFoo { public void Bar() { } } public class ProxyFoo : IFoo { private IFoo _Implementation; public ProxyFoo(IFoo implementation) { this._Implementation = implementation; } #region IFoo Members public void Bar() { this._Implementation.Bar(); } #endregion } This is a much smaller example than the real life cases in which I've used this pattern, but if implementing an existing interface or abstract class would require lots of code, most of which is already written, but I need to change a small part of the behaviour, then I will use this pattern. Is this a pattern or an anti pattern? If so, does it have a name and are there any well known pros and cons to this approach? Is there a better way to achieve the same result? Rewriting the interfaces and/or the concrete implementation is not normally an option as it will be provided by a third party library.

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  • Decision Tree code golf

    - by Chris Jester-Young
    In Google Code Jam 2009, Round 1B, there is a problem called Decision Tree that lent itself to rather creative solutions. Post your shortest solution; I'll update the Accepted Answer to the current shortest entry on a semi-frequent basis, assuming you didn't just create a new language just to solve this problem. :-P Current rankings: 107 Perl 121 PostScript (binary) 136 Ruby 154 Arc 160 PostScript (ASCII85) 170 PostScript 192 Python 199 Common Lisp 214 LilyPond 222 JavaScript 273 Scheme 280 R 312 Haskell 314 PHP 339 m4 346 C 406 Fortran 462 Java 476 Java (well, kind of) 718 OCaml 759 F# 1741 sed C++ not qualified for now

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  • Finding the maximum number of child nodes in a tree

    - by Jiminizer
    First, I should make it clear that this is required for an academic project. I am trying to find the maximum number of child nodes for any node in a tree, using Common Lisp. My current code is shown below - I'm not 100% on the logic of it, but I feel it should work, however it isn't giving me the required result. (defun breadth (list y) (setf l y) (mapcar #'(lambda (element) (when (listp element) (when (> (breadth element (length element)) l) (setf l (breadth element (length element))) ))) list) l) (defun max-breadth(list) (breadth list (length list)) ) As an example, running (max-breadth '(a ( (b (c d)) e) (f g (h i) j))) should return 4. Does anyone have any ideas where I'm going wrong? I suspect it's related to the second conditional, but I'm not sure.

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  • Subsume external library into source tree with Autotools.

    - by troutwine
    I am developing a new project, using Autotools for my build infrastructure. I would like to subsume external dependencies into my source tree. These dependencies are using Autotools, as well. How can I configure my project's build scripts to build and link against subsumed dependencies? Though Duret-Lutz's tutorial is excellent, this situation is only briefly addressed in a few slides. I found his explanation deeply confusing. By adding the directory name of subsumed dependencies to the toplevel Makefile.am's SUBDIRS the dependency is being configured and built. It is possible to manually set include paths through CFLAGS, but how do I link against libtool .la files?

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  • Question About MP4(AAC) Binary Tree

    - by DeanMc
    I'm in the very early stages of working on a tag editor for mp4 files and more specifically iTunes AAC ones. After doing some snooping around it seems that the file's structure is not as complicated as I first thought and is built in a sort of tree like the following 4 Bytes [Atom Length] 4 Bytes [Atom Name] X Bytes [Atom Data] An atom's data is as large as the length and can contain either Data(information) or another atom. What I am trying to work out is how one determines if the data is information or an actual atom. Any insight would be much appreciated.

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  • Sorting tree with a materialized path?

    - by Ovid
    I have a tree structure in a table and it uses materialized paths to allow me to find children quickly. However, I also need to sort the results depth-first, as one would expect with threaded forum replies. id | parent_id | matpath | created ----+-----------+---------+---------------------------- 2 | 1 | 1 | 2010-05-08 15:18:37.987544 3 | 1 | 1 | 2010-05-08 17:38:14.125377 4 | 1 | 1 | 2010-05-08 17:38:57.26743 5 | 1 | 1 | 2010-05-08 17:43:28.211708 7 | 1 | 1 | 2010-05-08 18:18:11.849735 6 | 2 | 1.2 | 2010-05-08 17:50:43.288759 9 | 5 | 1.5 | 2010-05-09 14:02:43.818646 8 | 6 | 1.2.6 | 2010-05-09 14:01:17.632695 So the final results should actually be sorted like this: id | parent_id | matpath | created ----+-----------+---------+---------------------------- 2 | 1 | 1 | 2010-05-08 15:18:37.987544 6 | 2 | 1.2 | 2010-05-08 17:50:43.288759 8 | 6 | 1.2.6 | 2010-05-09 14:01:17.632695 3 | 1 | 1 | 2010-05-08 17:38:14.125377 4 | 1 | 1 | 2010-05-08 17:38:57.26743 5 | 1 | 1 | 2010-05-08 17:43:28.211708 9 | 5 | 1.5 | 2010-05-09 14:02:43.818646 7 | 1 | 1 | 2010-05-08 18:18:11.849735 How would I work that out? Can I do that in straight SQL (this is PostgreSQL 8.4) or should additional information be added to this table?

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  • Adjacency List Tree Using Recursive WITH (Postgres 8.4) instead of Nested Set

    - by Koobz
    I'm looking for a Django tree library and doing my best to avoid Nested Sets (they're a nightmare to maintain). The cons of the adjacency list model have always been an inability to fetch descendants without resorting to multiple queries. The WITH clause in Postgres seems like a solid solution to this problem. Has anyone seen any performance reports regarding WITH vs. Nested Set? I assume the Nested set will still be faster but as long as they're in the same complexity class, I could swallow a 2x performance discrepancy. Django-Treebeard interests me. Does anyone know if they've implemented the WITH clause when running under Postgres? Has anyone here made the switch away from Nested Sets in light of the WITH clause?

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  • easiest way to convert virtualbox snapshots to tree view

    - by amir beygi
    HI all My virtual box snapshot view is like this Name: Snapshot 2 (UUID: cb45aef4-54d4-4c4e-ad3e-dd7cccb6103a) Name: s131 (UUID: 8ec30c82-7796-4e51-8161-979f1b95fb0f) Name: s131 (UUID: 42066f33-969b-41f3-a779-7f6e2c45ea2c) Name: s131 (UUID: d71b9bc5-b862-46b5-ae4d-f88d3dd9756d) Name: s131 (UUID: 681896a9-7e61-4b5a-90bc-cb1bd785c6fc) Name: s131 (UUID: d7bf8593-d218-442d-b23b-4ee16e74087d) Name: s131 (UUID: e8b16fd2-7add-4294-b908-34c4e6dc79dc) Name: s131 (UUID: 57c3f5d7-d4ed-4a62-a7b8-5594f819e08e) Name: Snapshot 3 (UUID: 4a684149-9dd6-4bb2-baf5-5f590e91a344) Name: Snapshot 4 (UUID: d4cbaa7c-ae78-41e0-9962-46c587a9c667) Name: Snapshot 5 (UUID: 81567b6e-eea9-49a6-b3b8-a07f0be337d8) * and i want to convert this text to a tree like this Name: Snapshot 2 (UUID: cb45aef4-54d4-4c4e-ad3e-dd7cccb6103a) +--Name: s131 (UUID: 8ec30c82-7796-4e51-8161-979f1b95fb0f) +--Name: s131 (UUID: 42066f33-969b-41f3-a779-7f6e2c45ea2c) +--Name: s131 (UUID: d71b9bc5-b862-46b5-ae4d-f88d3dd9756d) +--Name: s131 (UUID: 681896a9-7e61-4b5a-90bc-cb1bd785c6fc) | +--Name: s131 (UUID: d7bf8593-d218-442d-b23b-4ee16e74087d) | +--Name: s131 (UUID: e8b16fd2-7add-4294-b908-34c4e6dc79dc) | +--Name: s131 (UUID: 57c3f5d7-d4ed-4a62-a7b8-5594f819e08e) +--Name: Snapshot 3 (UUID: 4a684149-9dd6-4bb2-baf5-5f590e91a344) +--Name: Snapshot 4 (UUID: d4cbaa7c-ae78-41e0-9962-46c587a9c667) +--Name: Snapshot 5 (UUID: 81567b6e-eea9-49a6-b3b8-a07f0be337d8) * or even an array that contents line number and parent's line number. My environment is linux, programming language is C, and i got this results from this shell command VBoxManage snapshot s2000 showvminfo s|grep Name|grep UUID

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  • Experience/Articles about "decision tree" documentation?

    - by Philipp Keller
    I'm running an "defect fixing" group (developers do 2 weeks operations, then rotate). I want to build up a documentation "how to deal with problem x" - basically a decision tree: Is the problem in part x of the web site? Yes: Is the problem occurring in all browsers? Yes: ... No: ... No: ... The documentation should be written and extended by the people using it. Do you know of any book/article describing how that is best done, or is there a software (Mac OS X) that helps doing that?

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  • SQL Loop over a family tree

    - by simon831
    Using SQL server 2008. I have a family tree of animals stored in a table, and want to give some information on how 'genetically diverse' (or not) the offspring is. In SQL how can I produce sensible metrics to show how closely related the parents are? Perhaps some sort of percentage of shared blood, or a number of generations to go back before there is a shared ancestor? AnimalTable Id Name mumId dadId select * from AnimalTable child inner join AnimalTable mum on child.[mumId] = mum.[Id] inner join AnimalTable dad on child.[dadId] = dad.[Id] inner join AnimalTable mums_mum on mum.[mumId] = mums_mum.[Id] inner join AnimalTable mums_dad on mum.[dadId] = mums_dad.[Id] inner join AnimalTable dads_mum on dad.[mumId] = dads_mum.[Id] inner join AnimalTable dads_dad on dad.[dadId] = dads_dad.[Id]

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  • Subversion merging, tree merge

    - by krystan honour
    I need to merge changes from a branch back into trunk but want to continue work on the existing branch. I was going to use a re-integrate merge but realised this is not suitable as I will need to recreate my branch etc which for a variety of reasons is not desirable. What I really want to do is merge the current revisions in the branch down to head and then keep people working on their current working copies. So my question is , can tree merge be used to solve this or do I have to reintegrate and recreate.

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  • Algorithm to aggregate values from child tree nodes

    - by user222164
    I have objects in a tree structure, I would like to aggregate status information from children nodes and update parent node with aggregated status. Lets say node A has children B1, B2, and B1 has C1, C2, C3 as children. Each of the nodes have a status attribute. Now if C1, C2, C3 are all complete then I would like to mark B1 as completed. And if C4, C5,C6,C7 are complete make B2 as complete. When B1 and B2 are both complete mark A as complete. I can go through these nodes in brute force method and make updates, could someone suggest an efficient algorithm to do it. A { B1 { C1, C2, C3}, B2 { C4, C5, C6, C7} }

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  • Binary Search Tree node removal

    - by doc
    I've been trying to implement a delete function for a Binary Search Tree but haven't been able to get it to work in all cases. This is my latest attempt: if(t->get_left() == empty) *t = *t->get_left(); else if(t->get_right() == empty) *t = *t->get_right(); else if((t->get_left() != empty) && (t->get_right() != empty)) { Node* node = new Node(t->get_data(), t->get_parent(), t->get_colour(), t->get_left(), t->get_right()); *t = *node; } t is a node and empty is just a node with nothing in it. I'm just trying to swap the values but I'm getting a runtime error. Any ideas? Thanks

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  • Algorithms to find longest common prefix in a sliding window.

    - by nn
    Hi, I have written a Lempel Ziv compressor and decompressor. I am seeking to improve the time to search the dictionary for a phrase. I have considered K-M-P and Boyer-Moore, but I think an algorithm that adapts to changes in the dictionary would be faster. I've been reading that binary search trees (AVL or with splays) improve the performance of compression time considerably. What I fail to understand is how to bootstrap the binary search tree and insert/remove data. I'm not actually quite sure the significance of each node in the binary search. I am searching for phrases so will each character be considered a node? Also how and what is inserted/removed from the search tree as new data enters the dictionary and old data is removed? The binary search tree sounds like a good payoff since it can adapt to the dictionary, but I'm just not quite sure of how it's used.

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  • Finding height in Binary Search Tree

    - by mike
    Hey I was wondering if anybody could help me rework this method to find the height of a binary search tree. So far my code looks like this however the answer im getting is larger than the actual height by 1, but when I remove the +1 from my return statements its less than the actual height by 1? I'm still trying to wrap my head around recursion with these BST any help would be much appreciated. public int findHeight(){ if(this.isEmpty()){ return 0; } else{ TreeNode<T> node = root; return findHeight(node); } } private int findHeight(TreeNode<T> aNode){ int heightLeft = 0; int heightRight = 0; if(aNode.left!=null) heightLeft = findHeight(aNode.left); if(aNode.right!=null) heightRight = findHeight(aNode.right); if(heightLeft > heightRight){ return heightLeft+1; } else{ return heightRight+1; } }

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  • nHibernate: Query tree nodes where self or ancestor matches condition

    - by Famous Nerd
    I have see a lot of competing theories about hierarchical queries in fluent-nHibernate or even basic nHibernate and how they're a difficult beast. Does anyone have any knowledge of good resources on the subject. I find myself needing to do queries similar to: (using a file system analog) select folderObjects from folders where folder.Permissions includes :myPermissionLevel or [any of my ancestors] includes :myPermissionLevel This is a one to many tree, no node has multiple parents. I'm not sure how to describe this in nHibernate specific terms or, even sql-terms. I've seen the phrase "nested sets" mentioned, is this applicable? I'm not sure. Can anyone offer any advice on approaches to writing this sort of nHibernate query?

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  • Calculating depth and descendants of tree

    - by yuudachi
    Can you guys help me with the algorithm to do these things? I have preorder, inorder, and postorder implemented, and I am given the hint to traverse the tree with one of these orders. I am using dotty to label (or "visit") the nodes. Depth is the number of edges from the root to the bottom leaf, so everytime I move, I add +1 to the depth? Something like that? No idea about the algorithm for descendants. They are asking about the number of nodes a specific node has under itself. These are normal trees btw.

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  • SimpleXML adding html into Hash tree

    - by Miriam Raphael Roberts
    Question: I have an xml file that I am pulling from the web and parsing. One of the items in the xml is a 'content' value that has HTML. I am using SimpleXML/XMLin to parse the file like so: $xml= eval { $data-XMLin($xmldata, forcearray = 1, suppressempty= +'') }; When I use Dumper to dump the hash, I dsicovered that SimpleXML is parsing the HTML into the hash tree. 'content' => { 'div' => [ { 'xmlns' => 'http://www.w3.org/1999/xhtml', 'p' => [ { 'a' => [ { 'href' => 'http://miamiherald.typepad.com/.a/6a00d83451b26169e20133ec6f4491970b-pi', 'style' => 'FLOAT: left', 'img' => [ etc..... This is not what I want. I want to just grab content inside of this entry. How do I do this?

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  • GWT: Select a TreeItem with right click

    - by Ivan
    I'm capturing a right click event to show a context menu. What I haven't been able to figure out, is how to make the right click actually select the TreeItem, prior to showing of context menu. All help is appreciated. private Tree tree = new Tree() { @Override public void onBrowserEvent(Event event) { if (event.getTypeInt() == Event.ONCONTEXTMENU) { DOM.eventPreventDefault(event); showContextMenu(event); } super.onBrowserEvent(event); } @Override protected void setElement(Element elem) { super.setElement(elem); sinkEvents(Event.ONCONTEXTMENU); } };

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  • A RecursiveParentChildIterator -- like the RecursiveDirectoryIterator

    - by Stephen J. Fuhry
    There are tons of examples of using the RecursiveIterator to flatten a tree structure.. but what about using it to explode a tree structure? Is there an elegant way to use this, or some other SPL library to recursively build a tree (read: turn a flat array into array of arbitrary depth) given a table like this: SELECT id, parent_id, name FROM my_tree EDIT: You know how you can do this with Directories? $it = new RecursiveDirectoryIterator("/var/www/images"); foreach(new RecursiveIteratorIterator($it) as $file) { echo $file . PHP_EOL; } .. What if you could do something like this: $it = new RecursiveParentChildIterator($result_array); foreach(new RecursiveIteratorIterator($it) as $group) { echo $group->name . PHP_EOL; // this would contain all of the children of this group, recursively $children = $group->getChildren(); } :END EDIT

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  • Long IF tree with strings

    - by DalGr
    I have a C program which uses Lua for scripting. In order to keep readability and avoid importing several constants within the individual Lua states, I condense a large amount of functions within a simple call (such as "ObjectSet(id, "ANGLE", 45)"), by using an "action" string. To do this I have a large if tree comparing the action string to a list (such as "if(stringcompare(action, "ANGLE") ... else if (stringcompare(action, "X")... etc") This approach works well, and within the program it's not really slow, and is fairly quick to add a new action. But I kind of feel perfectionist. Is there a better way to do this in C? And having Lua in heavy use, maybe there is a way to use it for this purpose? (embedded "chunks" making a dictionary?) Although this part is mostly curiosity.

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  • How to find longest common substring using trees?

    - by user384706
    The longest common substring problem according to wiki can be solved using a suffix tree. From wiki: The longest common substrings of a set of strings can be found by building a generalised suffix tree for the strings, and then finding the deepest internal nodes which have leaf nodes from all the strings in the subtree below it I don't get this. Example: if I have: ABCDE and XABCZ then the suffix tree is (some branches from XABCZ omitted due to space): The longest common substring is ABC but it is not I can not see how the description of wiki helps here. ABC is not the deepest internal nodes with leaf nodes. Any help to understand how this works?

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  • Has anybody used the WB B-tree library?

    - by Chris B
    I stumbled across the WB on-disk B-tree library: http://people.csail.mit.edu/jaffer/WB It seems like it could be useful for my purposes (swapping data to disk during very large statistical calculations that do not fit in memory), but I was wondering how stable it is. Reading the manual, it seems worringly 'researchy' - there are sections labelled [NOT IMPLEMENTED] etc. But maybe the manual is just out-of-date. So, is this library useable? Am I better off looking at Tokyo Cabinet, MemcacheDB, etc.? By the way I am working in Java.

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  • how can I declare a value deep in an object tree using variable properties in javascript

    - by joshs
    I am trying to have a javascript object tree behave like a php associative array in the following way. var key1 = 'a'; var key2 = 'b'; var key3 = 'c'; var obj[key1][key2][key3] = 'd'; However, in javascript I believe you need to define each property/object pair individually, forming deeper leaves. Something like: var obj[key1] = {}; var obj[key1][key2] = {}; ... Is there a way to simplify or shorten this script? Thanks

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