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  • Default permission for newly-created files/folders using ACLs not respected by commands like "unzip"

    - by Ngoc Pham
    I am having trouble with setting up a system for multiple users accessing the same set of files. I've read tuts and docs around and played with ACLs but haven't succeeded yet. MY SCENARIO: Have multiple users, for example, user1 and user2, which is belong to a group called sharedusers. They must have all WRITE permission to a same set of files and directories, say underlying in /userdata/sharing/. I have the folder's group set to sharedusers and SGID to have all newly created files/dirs inside set to same group. ubuntu@home:/userdata$ ll drwxr-sr-x 2 ubuntu sharedusers 4096 Nov 24 03:51 sharing/ I set ACLs for this directory so I can have permission of sub dirs/files inheritted from its parents. ubuntu@home:/userdata$ setfacl -m group:sharedusers:rwx sharing/ ubuntu@home:/userdata$ setfacl -d -m group:sharedusers:rwx sharing/ Here's what I've got: ubuntu@home:/userdata$ getfacl sharing/ # file: sharing/ # owner: ubuntu # group: sharedusers # flags: -s- user::rwx group::r-x group:sharedusers:rwx mask::rwx other::r-x default:user::rwx default:group::r-x default:group:sharedusers:rwx default:mask::rwx default:other::r-x Seems okay as when I create new folder with new files inside and the permission is correct. ubuntu@home:/userdata/sharing$ mkdir a && cd a ubuntu@home:/userdata/sharing/a$ touch a_test ubuntu@home:/userdata/sharing/a$ getfacl a_test # file: a_test # owner: ubuntu # group: sharedusers user::rw- group::r-x #effective:r-- group:sharedusers:rwx #effective:rw- mask::rw- other::r-- As you can see, the sharedusers group has effective permission rw-. HOWEVER, if I have a zip file, and use unzip -q command to unzip the file inside the folder sharing, the extracted folders don't have group write permisison. Therefore, the users from group sharedusers cannot modify files under those extracted folders. ubuntu@home:/userdata/sharing$ unzip -q Joomla_3.0.2-Stable-Full_Package.zip ubuntu@home:/userdata/sharing$ ll drwxrwsr-x+ 2 ubuntu sharedusers 4096 Nov 24 04:00 a/ drwxr-xr-x+ 10 ubuntu sharedusers 4096 Nov 7 01:52 administrator/ drwxr-xr-x+ 13 ubuntu sharedusers 4096 Nov 7 01:52 components/ You an spot the difference in permissions between folder a (created before) and folder administrator extracted by unzip. And the ACLs of a files inside administrator: ubuntu@home:/userdata/sharing$ getfacl administrator/index.php # file: administrator/index.php # owner: ubuntu # group: ubuntu user::rw- group::r-x #effective:r-- group:sharedusers:rwx #effective:r-- mask::r-- other::r-- It also has ubuntu group, not sharedusers group as expected. Could someone please explain the problem and give me advice? Thank you in advance!

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  • How to protect files/folders from being copied/moved/deleted/cut on windows

    - by Sean Lee
    I need to share data on an external drive that will be handed over to someone else, and I would like to achieve the following: (1) protect all the files and folders from being copied/moved/deleted/cut on windows system (2) files are browsable and media playable, but it stays inside the drive (3) the same behavior if drive is plugged on linux system, or not accessible at all is fine too. How can I do these without using paid software?

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  • Scan HTML for unused assets i folders

    - by Byran
    I have a aging website I'm managing and I'd like to remove all unused external files (.css, .jpg, .js, etc.) that are currently in various folders all over the site. Is there a tool out there that can help me identify and/or remove these for me?

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  • Zipping folder with absolute path without keeping tree of folders

    - by Preston
    I am attempting to use the zip -r command to zip a folder which includes two files. I need to pass the absolute path of the folder with two files (/path/to/my/files/), which is causing all of the folders to be zipped with it, where as I only need the last folder (files/) and its contents to be zipped, so that when the file is unzipped, there is only one folder and the two files within it. How can I modify the command to be able to pass the absolute paths in the arguments while keeping only the last folder?

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  • How to perform "shell" icon embedding in Visual Studio 2010?

    - by JustABill
    As far as I can tell, there have been (at least?) three types of icon embedding. There's the original style used by shell32.dll and friends, .Net's embedding, and the new type that WPF uses. I'm looking for how to perform the first one, as I want to have a few other icons available as resources for a jumplist, which can only accept that style. However, I can't figure out how to embed in this style, only the other two. How do I do this? All the results I find on google, etc are for adding icons to ResX files or similar. I am using C#, if it matters.

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  • How do I escape a string for a shell command in nodejs (V8 Javascript engine)?

    - by Maciek
    In nodejs, the only way to execute external commands is via sys.exec(cmd). I'd like to call an external command and give it data via stdin. In nodejs there does yet not appear to be a way to open a command and then push data to it (only to exec and receive its standard+error outputs), so it appears the only way I've got to do this right now is via a single string command such as: var dangerStr = "bad stuff here"; sys.exec("echo '" + dangerStr + "' | somecommand"); Most answers to questions like this have focused on either regex which doesn't work for me in nodejs (which uses Google's V8 Javascript engine) or native features from other languages like Python. I'd like to escape dangerStr so that it's safe to compose an exec string like the one above. If it helps, dangerStr will contain JSON data.

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  • How do I arbitrarily reorder lines in a text file using a Unix shell?

    - by Tim Bellis
    I've got a text file with an arbitrary number of lines, e.g.: one line some other line an additional line one more here I'd like to write a script to reorder those lines based on a given order. e.g. An input of 2 1 3 4 would swap the first and second lines. An input of 3 1 2 4 would put the 3rd line first, the 1st line second, the 2nd line third and keep the 4th line fourth. I could hack something together, but I'm wondering if there's an elegant solution? I can use either bash or ksh.

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  • Propagaging Apache rules Automatically for all folders Beneath Root [closed]

    - by Sam
    Hi folks, my webroot folder /httpdocs folder contains a .htaccess file The first lines look like this: RewriteEngine on RewriteBase / AddDefaultCharset UTF-8 Options +FollowSymLinks -Indexes -ExecCGI # DirectoryIndex index.php /index.php # ServerSignature Off Now, I want all settings that I have set it to, to be propagated automatically to other folders as well. How can I do that? Thanks very much for suggestions.

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  • How can I do a 'where' clause in Linux shell?

    - by Hoa
    I have a CSV file and I would like to filter all the lines where the 19th column has two or more characters. I know the individual pieces but can't figure out how to glue them together. First I have to cat the file. The following prints the 19th column awk -F "," '{print $19}' file.txt awk also has length and ifs And I know it all has to be glued together using pipes. I'm just getting stuck at the exact syntax since I have not done much bash programming before.

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  • protect ftp folders and

    - by sasori
    I have multiple people accessing my ftp server and i want to protect some folders inside this ftp server with a password. So the people that are inside the ftp server only can acces the protected the folder with a password. can someone tell me how to do that please ?

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  • Why doesn't "cd" work in a bash shell script?

    - by askgelal
    I'm trying to write a small script to change the current directory to my project directory: #!/bin/bash cd /home/askgelal/projects/java I saved this file as proj, changed the chmod, copied it to /usr/bin. When I call it by: proj, it does nothing. What am I doing wrong?

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