Function syntax puzzler in scalaz
- by oxbow_lakes
Following watching Nick Partidge's presentation on deriving scalaz, I got to looking at this example, which is just awesome:
import scalaz._
import Scalaz._
def even(x: Int) : Validation[NonEmptyList[String], Int]
= if (x % 2 ==0) x.success else "not even: %d".format(x).wrapNel.fail
println( even(3) <|*|> even(5) ) //prints: Failure(NonEmptyList(not even: 3, not even: 5))
I was trying to understand what the <|*|> method was doing, here is the source code:
def <|*|>[B](b: M[B])(implicit t: Functor[M], a: Apply[M]): M[(A, B)]
= <**>(b, (_: A, _: B))
OK, that is fairly confusing (!) - but it references the <**> method, which is declared thus:
def <**>[B, C](b: M[B], z: (A, B) => C)(implicit t: Functor[M], a: Apply[M]): M[C]
= a(t.fmap(value, z.curried), b)
So I have a few questions:
How come the method appears to take a monad of one type parameter (M[B]) but can get passed a Validation (which has two type paremeters)?
How does the syntax (_: A, _: B) define the function (A, B) => C which the 2nd method expects? It doesn't even define an output via =>
