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  • How to get JSON code into MYSQL database?

    - by the_boy_za
    I've created this form with a jQuery autocomplete function. The selected brand from the autocomplete list needs to get sent to a PHP file using $.ajax function. My code doesn't seem to work but i can't find the error. I don't know why the data isn't getting inserted into MYSQL database. Here is my code: JQUERY: $(document).ready(function() { $("#autocomplete").autocomplete({ minLength: 2 }); $("#autocomplete").autocomplete({ source: ["Adidas", "Airforce", "Alpha Industries", "Asics", "Bikkemberg", "Birkenstock", "Bjorn Borg", "Brunotti", "Calvin Klein", "Cars Jeans", "Chanel", "Chasin", "Diesel", "Dior", "DKNY", "Dolce & Gabbana"] }); $("#add-brand").click(function() { var merk = $("#autocomplete").val(); $("#selected-brands").append(" <a class=\"deletemerk\" href=\"#\">" + merk + "</a>"); //Add your parameters here var param = JSON.stringify({ Brand: merk }); $.ajax({ type: "POST", async: true, url: "scripttohandlejson.php", contentType: "application/json", data: param, dataType: "json", success: function (good){ //handle success alert(good) }, failure: function (bad){ //handle any errors alert(bad) } }); return false; }); }); PHP FILE: scripttohandlejson.php <?PHP $getcontent = json_decode($json, true); $getcontent->{'Brand'}; $vraag ="INSERT INTO kijken (merk) VALUES ='$getcontent' "; $voerin = mysql_query($vraag) or die("couldnt put into db"); <?

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  • Need some help with a MySQL subquery count

    - by Ferdy
    I'm running into my own limits of MySQL query skills, so I hope some SQL guru can help out on this one. The situation is as follow: I have images that can be tagged. As you might expect this is stored in three tables: Image Tag Tag_map (maps images to tags) I have a SQL query that calculates the related tags based on a tag id. The query basically checks what other tags were used for images for images using that tag. Example: Image1 tagged as "Bear" Image2 tagged as "Bear" and "Canada" If I throw "Bear" (or its tag id) at the query, it will return "Canada". This works fine. Here's the query: SELECT tag.name, tag.id, COUNT(tag_map.id) as cnt FROM tag_map,tag WHERE tag_map.tag_id = tag.id AND tag.id != '185' AND tag_map.image_id IN (SELECT tag_map.image_id FROM tag_map INNER JOIN tag ON tag_map.tag_id = tag.id WHERE tag.id = '185') GROUP BY tag_map.id LIMIT 0,100 The part I'm stuck with is the count. For each related tag returned, I want to know how many images are in that tag. Currently it always returns 1, even if there are for example 3. I've tried counting different columns all resulting in the same output, so I guess there is a flaw in my thinking.

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  • Special characters stripped by mySQL/PHP JSON

    - by Will Gill
    Hi, I have a simple PHP script to extract data from a mySQL database and encode it as JSON. The problem is that special characters (for example German ä or ß characters) are stripped from the JSON response. Everything after the first special character for any single field is just stripped. The fields are set to utf8_bin, and in phpMyAdmin the characters display correctly. The PHP script looks like this: <?php header("Content-type: application/json; charset=utf-8"); $con = mysql_connect('database', 'username', 'password'); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("sql01_5789willgil", $con); $sql="SELECT * FROM weightevent"; $result = mysql_query($sql); $row = mysql_fetch_array($result); $events = array(); while($row = mysql_fetch_array($result)) { $eventid = $row['eventid']; $userid = $row['userid']; $weight = $row['weight']; $sins = $row['sins']; $gooddeeds = $row['gooddeeds']; $date = $row['date']; $event = array("eventid"=>$eventid, "userid"=>$userid, "weight"=>$weight, "sins"=>$sins, "gooddeeds"=>$gooddeeds, "date"=>$date); array_push($events, $event); } $myJSON = json_encode($events); echo $myJSON; mysql_close($con); ?> Sample output: [{"eventid":"2","userid":"1","weight":"70.1","sins":"Weihnachtspl","gooddeeds":"situps! lots and lots of situps!","date":"2011-01-02"},{"eventid":"3","userid":"2","weight":"69.9","sins":"A second helping of pasta...","gooddeeds":"I ate lots of salad","date":"2011-01-01"}] -- in the first record the value for field 'sins' should be "Weihnachtsplätzchen". thanks very much!

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  • mysql image disable print download

    - by Vish
    Hi, We use a Flex AIR client and a WAMP server. Tiff images are stored in MySQL. Currently, I can download the image from AIR client and it prompts for a download dialog. Things are fine till this point. We got a new requirement. Requirement is that only some users can print the image which gets downloaded. For other users, they should not be able to print the tiff image. Wondering how to accomplish this. One idea, not sure if its efficient, is to convert the image requested to pdf at the server side, disable print option there(hope there are API's available) and send back the pdf. Please let me know btter ideas. Also, is there a way to prevent file download dialog from popping up everytime the file is requested for download? Can we just get the file stream to the client and manipulate it to open with a particular viewer or write it to pdf... Please help.

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  • What is the best way to handle the Connections to MySql from c#

    - by srk
    I am working on a c# application which connects to MySql server. There are about 20 functions which will connect to database. This application will be deployed in 200 over machines. I am using the below code to connect to my database which is identical for all the functions. The problem is, i can some connections were not closed and still alive when deployed in 200 over machines. Connection String : <add key="Con_Admin" value="server=test-dbserver; database=test_admindb; uid=admin; password=1Password; Use Procedure Bodies=false;" /> Declaration of the connection string Globally in application [Global.cs] : public static MySqlConnection myConn_Instructor = new MySqlConnection(ConfigurationSettings.AppSettings["Con_Admin"]); Function to query database : public static DataSet CheckLogin_Instructor(string UserName, string Password) { DataSet dsValue = new DataSet(); //MySqlConnection myConn = new MySqlConnection(ConfigurationSettings.AppSettings["Con_Admin"]); try { string Query = "SELECT accounts.str_nric AS Nric, accounts.str_password AS `Password`," + " FROM accounts " + " WHERE accounts.str_nric = '" + UserName + "' AND accounts.str_password = '" + Password + "\'"; MySqlCommand cmd = new MySqlCommand(Query, Global.myConn_Instructor); MySqlDataAdapter da = new MySqlDataAdapter(); if (Global.myConn_Instructor.State == ConnectionState.Closed) { Global.myConn_Instructor.Open(); } cmd.ExecuteScalar(); da.SelectCommand = cmd; da.Fill(dsValue); Global.myConn_Instructor.Close(); } catch (Exception ex) { Global.myConn_Instructor.Close(); ExceptionHandler.writeToLogFile(System.Environment.NewLine + "Target : " + ex.TargetSite.ToString() + System.Environment.NewLine + "Message : " + ex.Message.ToString() + System.Environment.NewLine + "Stack : " + ex.StackTrace.ToString()); } return dsValue; }

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  • php oop and mysql

    - by gloris
    I need to get data, to check and send to db. Programming with PHP OOP. Could you tell me if my class structure is good and how dislpay all data?. Thanks <?php class Database{ private $DBhost = 'localhost'; private $DBuser = 'root'; private $DBpass = 'root'; private $DBname = 'blog'; public function connect(){ //Connect to mysql db } public function select($rows){ //select data from db } public function insert($rows){ //Insert data to db } public function delete($rows){ //Delete data from db } } class CheckData{ public $number1; public $number2; public function __construct(){ $this->number1 = $_POST['number1']; $this->number2 = $_POST['number2']; } function ISempty(){ if(!empty($this->$number1)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number1); } else{ echo "Empty1"; } if(!empty($this->$number2)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number2); } else{ echo "Empty2"; } } } class DisplayData{ //How print all data? function DisplayNumber(){ $data = new Database(); $data->select(); } } $check = new CheckData(); $check->ISempty(); $display = new DisplayData() $display->DisplayNumber(); ?>

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  • MySQL to PostreSQL and Named Scope

    - by Lowgain
    I've got a named scope for one of my models that works fine. The code is: named_scope :inbox_threads, lambda { |user| { :include => [:deletion_flags, :recipiences], :conditions => ["recipiences.user_id = ? AND deletion_flags.user_id IS NULL", user.id], :group => "msg_threads.id" }} This works fine on my local copy of the app with a MySQL database, but when I push my app to Heroku (which only uses PostgreSQL), I get the following error: ActiveRecord::StatementInvalid (PGError: ERROR: column "msg_threads.subject" must appear in the GROUP BY clause or be used in an aggregate function: SELECT "msg_threads"."id" AS t0_r0, "msg_threads"."subject" AS t0_r1, "msg_threads"."originator_id" AS t0_r2, "msg_thr eads"."created_at" AS t0_r3, "msg_threads"."updated_at" AS t0_r4, "msg_threads"."url_key" AS t0_r5, "deletion_flags"."id" AS t1_r0, "deletion_flags"."user_id" AS t1_r1, "deletion_flags"."msg_thread_id" AS t1_r2, "deletion_flags"."confirmed" AS t1_r3, "deletion_flags"."created_at" AS t1_r4, "deletion_flags"."updated_at" AS t1_r5, "recipiences"."id" AS t2_r0, "recipiences"."user_id" AS t2_r1, "recipiences"."msg_thread_id" AS t2_r2, "recipiences"."created_at" AS t2_r3, "recipien ces"."updated_at" AS t2_r4 FROM "msg_threads" LEFT OUTER JOIN "deletion_flags" ON deletion_flags.msg_thread_id = msg_threads.id LEFT OUTER JOIN "recipiences" ON recipiences.msg_thread_id = msg_threads.id WHERE (recipiences.user_id = 1 AND deletion_flags.user_id IS NULL) GROUP BY msg_threads.id) I'm not as familiar with the working of Postgres, so what would I need to add here to get this working? Thanks!

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  • supplied argument is not a valid MySQL result

    - by jasmine
    I have written a function: function selectWithPaging($where){ $pg = (int) (!isset($_GET["pg"]) ? 1 : $_GET["pg"]); $pg = ($pg == 0 ? 1 : $pg); $perpage = 10;//limit in each page $startpoint = ($pg * $perpage) - $perpage; $result = mysql_query("SELECT * FROM $where ORDER BY id ASC LIMIT $startpoint,$perpage"); return $result; } but when inserting in this function : function categories() { selectWithPaging('category') $text .='<h2 class="mainH">Categories</h2>'; $text .= '<table><tr class="cn"><td>ID</td><td class="name">Category</td> <td>Durum</td>'; while ($row = mysql_fetch_array($result)) { $home = $row['home']; $publish = $row['published']; $ID = $row['id']; $src = '<img src="'.ADMIN_IMG.'homec.png">'; ------------- } there is this error: supplied argument is not a valid MySQL result What is wrong in my first function? Thanks in advance

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  • Disabling Text field with Javascript when value in drop down box is from mysql

    - by SteveJ313
    Hi I have a simple script in HTML, using a dropdown menu. When the value 1 is selected, the user can write in the text field, if value 2 is selected, it disables the text field. However, i changed the values of the dropdown menu, so that one value was from a mysql table(using PHP) and the other remained 'option value='1''. Yet now neither text field is disabled. Below is the code. `<script type="text/javascript"> function findselected() { if (document.form.selmenu.value == <?php echo $id; ?>) { document.form.txtField.disabled=true; // return false; // not sure this line is needed } else { document.form.txtField.disabled=false; // return false; // not sure this line is needed } } ` And the PHP section if(mysql_num_rows($SQL) == 1) { echo "<select name='selmenu' onChange='findselected()'>"; echo "<label>TCA_Subject</label>"; while ($row=mysql_fetch_array($SQL)) { echo "<option value='$id'>$thing</option>"; echo "<option value='2'>Choice 2</option>"; } } echo "<option value=$userid>'Choice 1'</option>"; ?> <option value='2'>Choice 2</option>"; </select> I have tried taking the second option value out of the loop, putting it into html, editing the variable in the javascript function. There is not a fault with the PHP as it is retrieving the right results and displaying it, yet the text field doesnt become disabled. Does anyone know of a possible solution? Thanks

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  • PHP Saving information to MySQL but not using hard coded code

    - by Homer_J
    Hi guys, Thanks everyone for assisting me but know I'm well and truely stuck...hopefully someone can advise? My current code that saves to a MySQL database: $q1 = $_POST["q1"]; $q2 = $_POST["q2"]; $q3 = $_POST["q3"]; $q4 = $_POST["q4"]; $q5 = $_POST["q5"]; $q6 = $_POST["q6"]; $q7 = $_POST["q7"]; $q8 = $_POST["q8"]; $proc = mysqli_prepare($link, "INSERT INTO tresults_bh_main (respondent_id, ip, browser, q1, q2, q3, q4, q5, q6, q7, q8) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?);"); mysqli_stmt_bind_param($proc, "issiiiiiiii", $respondent_id, $ip, $browser, $q1, $q2, $q3, $q4, $q5, $q6, $q7, $q8); At the moment this is all hard coded and I need it to use variables: I have an array which stores the following information: $qs['questions'] - stores, for example q1, q2, q3, q4 etc - obviously these change both in terms of of numbers, ie. q10, q11, q12 and also the amount in the array - so there could be 4 q's or 10 q's stored in the array. What I struggling to get my head around is how I would set-up this hard coded page to work with my variables. If anyone can help, much appreciated. Homer.

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  • How to store a captured image into MySQL database using JavaScript

    - by R J.
    I am capturing image using canvas and i want to store a captured image in MySQL Database using Javascript. This is my code: <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, maximum-scale=1.0"> <style> body {width: 100%;} canvas {display: none;} </style> <title>Instant Camera - Remote</title> <script> var video, canvas, msg; var load = function () { video = document.getElementById('video'); canvas = document.getElementById('canvas'); msg = document.getElementById('error'); if( navigator.getUserMedia ) { video.onclick = function () { var context = canvas.getContext("2d"); context.drawImage(video, 0, 0, 240, 320); var image1 = canvas.toDataURL("image/png"); document.write('<img src="' + image1 + '" />'); }; } else { msg.innerHTML = "Native web camera not supported :("; } }; window.addEventListener('DOMContentLoaded', load, false); </script> </head> <body> <video id="video" width="240" height="320" autoplay> </video> <p id="error">Click on the video to send a snapshot to the receiving screen</p> <canvas id="canvas" width="240" height="320"> </canvas> </body> </html>

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  • Questions about shifting from mysql to PDO

    - by Scarface
    Hey guys I have recently decided to switch all my current plain mysql queries performed with php mysql_query to PDO style queries to improve performance, portability and security. I just have some quick questions for any experts in this database interaction tool Will it prevent injection if all statements are prepared? (I noticed on php.net it wrote 'however, if other portions of the query are being built up with unescaped input, SQL injection is still possible' I was not exactly sure what this meant). Does this just mean that if all variables are run through a prepare function it is safe, and if some are directly inserted then it is not? Currently I have a connection at the top of my page and queries performed during the rest of the page. I took a look at PDO in more detail and noticed that there is a try and catch procedure for every query involving a connection and the closing of that connection. Is there a straightforward way to connecting and then reusing that connection without having to put everything in a try or constantly repeat the procedure by connecting, querying and closing? Can anyone briefly explain in layman's terms what purpose a set_exception_handler serves? I appreciate any advice from any more experienced individuals.

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  • Warning: Illegal string offset 'new_file' - Magento Site

    - by Roy
    We just migrated our magento installation from one of the hosting company and this keeps popping up whenever I try to duplicate product. Something wrong with codebase...Can someone please help. The code at 130 is… $object->setData($mediaAttrCode, $newImages[$attrData]['new_file']); THanks Warning: Illegal string offset 'new_file' in /home/spotzee/webapps/yourchemistonline/app/code/core/Mage/Catalog/Model/Product/Attribute/Backend/Media.php on line 130

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  • Can't view order in magento

    - by koko
    Hi, I've been setting up a fresh magento 1.4.0.1 install, working great so far. I did some test orders just to see. Everything works fine, but when I click on "view order" under "my orders", I get a bunch of error messages: There has been an error processing your request Notice: iconv_substr() [function.iconv-substr]: Unknown error (0) in /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php on line 98 Trace: #0 [internal function]: mageCoreErrorHandler(8, 'iconv_substr() ...', '/data/web/A1423...', 98, Array) #1 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php(98): iconv_substr('1', 0, 50, 'UTF-8') #2 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php(173): Mage_Core_Helper_String-substr('1', 0, 50) #3 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php(112): Mage_Core_Helper_String-str_split('1', 50) #4 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/sales/order/items/renderer/default.phtml(58): Mage_Core_Helper_String-splitInjection('1') #5 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #6 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #7 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #8 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #9 /data/web/A14237/htdocs/magento/app/code/core/Mage/Sales/Block/Items/Abstract.php(137): Mage_Core_Block_Abstract-toHtml() #10 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/sales/order/items.phtml(52): Mage_Sales_Block_Items_Abstract-getItemHtml(Object(Mage_Sales_Model_Order_Item)) #11 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #12 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #13 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #14 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #15 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(516): Mage_Core_Block_Abstract-toHtml() #16 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(467): Mage_Core_Block_Abstract-_getChildHtml('order_items', true) #17 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/sales/order/view.phtml(64): Mage_Core_Block_Abstract-getChildHtml('order_items') #18 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #19 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #20 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #21 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #22 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(516): Mage_Core_Block_Abstract-toHtml() #23 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(463): Mage_Core_Block_Abstract-_getChildHtml('sales.order.vie...', true) #24 /data/web/A14237/htdocs/magento/app/code/core/Mage/Page/Block/Html/Wrapper.php(52): Mage_Core_Block_Abstract-getChildHtml('', true, true) #25 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Page_Block_Html_Wrapper-_toHtml() #26 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Text/List.php(43): Mage_Core_Block_Abstract-toHtml() #27 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Text_List-_toHtml() #28 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(516): Mage_Core_Block_Abstract-toHtml() #29 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(467): Mage_Core_Block_Abstract-_getChildHtml('content', true) #30 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/page/2columns-left.phtml(48): Mage_Core_Block_Abstract-getChildHtml('content') #31 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #32 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #33 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #34 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #35 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Model/Layout.php(536): Mage_Core_Block_Abstract-toHtml() #36 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Action.php(389): Mage_Core_Model_Layout-getOutput() #37 /data/web/A14237/htdocs/magento/app/code/core/Mage/Sales/controllers/OrderController.php(100): Mage_Core_Controller_Varien_Action-renderLayout() #38 /data/web/A14237/htdocs/magento/app/code/core/Mage/Sales/controllers/OrderController.php(136): Mage_Sales_OrderController-_viewAction() #39 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Action.php(418): Mage_Sales_OrderController-viewAction() #40 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Router/Standard.php(254): Mage_Core_Controller_Varien_Action-dispatch('view') #41 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Front.php(177): Mage_Core_Controller_Varien_Router_Standard-match(Object(Mage_Core_Controller_Request_Http)) #42 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Model/App.php(304): Mage_Core_Controller_Varien_Front-dispatch() #43 /data/web/A14237/htdocs/magento/app/Mage.php(596): Mage_Core_Model_App-run(Array) #44 /data/web/A14237/htdocs/magento/index.php(78): Mage::run('', 'store') #45 {main} gtx, koko

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  • 500 - An error has occurred! DB function reports no errors when adding new article in Joomla!

    - by Roland
    I have an article that I want to publish on my Joomla! site. Every time I click apply or save. I get error 500 - An error has occurred! DB function reports no errors. I have no idea why this error comes up, al I can think is that it's a server error. I'm using TinyMCE to type articles together with Joomla! 1.5.11. Updated: I turned on Maximum error reporting in Joomla! and in the article manager I tried to save the article and got these couple of errors. Please check screenshot I tried adding <?php ini_set('error_reporting', E_ALL); error_reporting(E_ALL); ini_set('log_errors',TRUE); ini_set('html_errors',TRUE); ini_set('display_errors',true); ?> at the top of the index.php pages for Joomla! but it does not show any errors. I checked the error logs on the server and also no errors come up. I managed to publish the article via phpMyAdmin but then something else happens. I try to access to article from the front end, by clicking on the link to the article, but only a blank page comes up. This is really weird, since the error log does not show any information. So I assume the error needs to be coming from Joomla! This happens if I add a print_r($_POST) before if (!$row->check()) { on /administrator/components/com_content/controller.php (around line 693) Array ( [title] => Test. [state] => 0 [alias] => test [frontpage] => 0 [sectionid] => 10 [catid] => 44 [details] => Array ( [created_by] => 62 [created_by_alias] => [access] => 0 [created] => 2008-10-25 13:31:21 [publish_up] => 2008-10-25 13:31:21 [publish_down] => Never ) [params] => Array ( [show_title] => [link_titles] => [show_intro] => [show_section] => [link_section] => [show_category] => [link_category] => [show_vote] => [show_author] => 1 [show_create_date] => 0 [show_modify_date] => 0 [show_pdf_icon] => [show_print_icon] => [show_email_icon] => [language] => [keyref] => [readmore] => ) [meta] => Array ( [description] => Test. [keywords] => Test [robots] => [author] => Test ) [id] => 58 [cid] => Array ( [0] => 58 ) [version] => 30 [mask] => 0 [option] => com_content [task] => apply [ac1e0853fb1b3f41730c0d52de89dab7] => 1 ) I had a bounty on this question, but the problem is still not resolved? link text Any help will be appreciated!! Here is a link to the article (text file with the source I got from TinyMCE) Article

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  • Putting data from local SQL database to remote SQL database without remote SQL access enabled (PHP)

    - by Shyam
    Hi, I have a local database, and all the tables are defined. Eventually I need to publish my data remotely, which I can do easily with PHPmyadmin. Problem however is that my remote host doesn't allow remote SQL connections at all, so writing a script that does a mysqldump and run it through a client (which would've been ideal) won't help me here. Since the schema won't change, but the data will, I need some kind of PHP client that works "reverse". My question is if such a client exists and what would be recommended to use (by experience). I just need an one way trip here, from my local database (Rails) to the remote database (supports PHP), preferable as simple and slick as possible. Thank you for your replies, comments and feedback!

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  • Sql Query - Limiting query results

    - by Gublooo
    I am quite certain we cannot use the LIMIT clause for what I want to do - so wanted to find if there are any other ways we can accomplish this. I have a table which captures which user visited which store. Every time a user visits a store, a row is inserted into this table. Some of the fields are shopping_id (primary key) store_id user_id Now what I want is - for a given set of stores, find the top 5 users who have visited the store max number of times. I can do this 1 store at a time as: select store_id,user_id,count(1) as visits from shopping where store_id = 60 group by user_id,store_id order by visits desc Limit 5 This will give me the 5 users who have visited store_id=60 the max times What I want to do is provide a list of 10 store_ids and for each store fetch the 5 users who have visited that store max times select store_id,user_id,count(1) as visits from shopping where store_id in (60,61,62,63,64,65,66) group by user_id,store_id order by visits desc Limit 5 This will not work as the Limit at the end will return only 5 rows rather than 5 rows for each store. Any ideas on how I can achieve this. I can always write a loop and pass 1 store at a time but wanted to know if there is a better way

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  • How do I join these queries?

    - by GregoryD
    query1: SELECT category.id, category.name, category.level, category.description, category.cat1, category.cat2, category.cat3, category.cat4, category.pri_color, category.sec_color, category.last_report AS report_id FROM category, reports_category_layout WHERE category.id = reports_category_layout.catID AND reports_category_layout.site_code = 'las' query2: SELECT DISTINCT category.id, COUNT(forum.id) AS posts, SUM(forum.view) AS views FROM category, forum WHERE category.id = forum.catID AND forum.approved = 'yes' AND forum.site_code = 'las' GROUP BY category.id query3: SELECT forum.catID, forum.title, forum.paragraph, forum.created, users.alias, forum.userID FROM forum, users, forum_cache WHERE forum.catID = forum_cache.catID AND forum.id = forum_cache.last_report AND users.id = forum.userID AND forum.approved = 'yes' Essentially, I am unsure about the syntax to join these properly. I have written a query that simply joins them, but in the case that the forum cache table contains an unapproved forum id, it will simply not return the entire row. what I really need is for query1 and query2 to be left joined on the category id, and for query 3 to be left outer joined on id = catID.

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  • selectLimit in JQgrid

    - by Leander
    Hallo, I have a problem. I'am trying to get some data from my database. But with a limit. So i use the selectLimit command. But when i load the grid my firebug gives the following error: "parsererror"?e:null},parse:function(d...d(a.fn.jqGrid,d);this.no_legacy_api|| When I go to the selectLimit in the jqgrid.php and print out what the function returns it normaly return an array with all 500 objects with the correct data. This is the code of the grid: <?php require_once ($_SERVER['DOCUMENT_ROOT'].'/includes_config/config.inc.php'); require_once ($_SERVER['DOCUMENT_ROOT'].'/portal/classes/core/database/class_Database_control.php'); $dtb = new clsDatabaseControl(); $dtb = $dtb->getDatabase(ConnectionString); $dtb->doConnect(); require_once (ClassRoot.'/3rd/jqgrid/jq-config.php'); require_once (ClassRoot.'/3rd/jqgrid/php/jqGrid.php'); require_once (ClassRoot.'/3rd/jqgrid/php/jqGridPdo.php'); //require_once (ClassRoot.'/modules/logging/class_logging_control.php'); // //$oLogginControl = new clsLoggingControl($dtb); //$sSQL = $oLogginControl->getAanmeldingenGrid(); $sSQL = "SELECT LogAanmeldID, LogAanmeldStamp, UserFirstName, UserLastName, LogAanmeldIP, LogAanmeldMethod, LogAanmeldHost, LogAanmeldAgent FROM log_aanmelden, user WHERE log_aanmelden.LogAanmeldUserID = user.UserID"; $conn = new PDO(DB_DSN,DB_USER,DB_PASSWORD); $conn->query("SET NAMES utf8"); $grid = new jqGridRender($conn); //$grid->SelectCommand = $sSQL; $grid->selectLimit($sSQL ,500,1); $grid->dataType = 'json'; $grid->setColModel(); $grid->setUrl('modules/module_logging/index.php?grid=2'); $grid->setGridOptions(array( "hoverrows"=>true, //"sortname"=>"naam", "height"=>450 )); // Enable toolbar searching $grid->toolbarfilter = true; $grid->setFilterOptions(array("stringResult"=>true)); $grid->navigator = true; $grid->setNavOptions('navigator', array("excel"=>true,"add"=>false,"edit"=>false,"del"=>false,"view"=>true, "refresh"=>false)); $custom = <<<CUSTOM $(document).ready(function() { gridParentWidth = $(window).width(); $('#grid').jqGrid('setGridWidth',gridParentWidth-10); }) $(window).resize(function() { gridParentWidth = $(window).width(); $('#grid').jqGrid('setGridWidth',gridParentWidth-10); }); function formatAddAdresboek(cellValue, options, rowObject) { var imageHtml = "<a href='?FFID=51000&TID=1&INS=3&contactID=" + cellValue + "' originalValue='" + cellValue + "'><img border='0' alt='Toevoegen aan Persoonlijk Adresboek' src='images/16X16/new_user.gif'/></a>"; imageHtml = imageHtml + " <a href='?FFID=51000&TID=2&INS=3&contactID=" + cellValue + "' originalValue='" + cellValue + "'><img border='0' alt='Toevoegen aan Praktijk Adresboek' src='images/16X16/new_usergroup.gif'/></a>"; return imageHtml; } function unformatAddAdresboek(cellValue, options, cellObject) { return $(cellObject.html()).attr("originalValue"); } CUSTOM; $grid->setJSCode($custom); // Enjoy $grid->renderGrid('#grid','#pager',true, null, null, true,true); $conn = null; ?> When I inspect the $_GET the answer is empty and in stead of a JSON tab there is an HTML tab. When i use the selectCommand in stead of the selectLimit it return all the data correct as an json object an parses it correcly in the grid but it doens't use the LIMIT, Because when i add the limit. PDO doens't work anymore. So how do I get the object from the selectLimit to the grid? Can someone please help me get the grid working?

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  • php form-input validation

    - by fusion
    i have a html page in which i enter data which then submits and inserts in a database on a php page. how would i validate in php that the data received is not a duplicate of the data in the database? any help appreciated.

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  • ODBC Connection String Problem

    - by Brett
    Hi there, I am having major trouble connecting to my database via ODBC. The db is local (but I have a mirror on a virtual machine), so I am trying to use the connectionstring: Dsn=MonetDB;host=TARBELL where TARBELL is the name of my computer. However, it doesn't connect. BUT, this string does: Dsn=MonetDB;host=localhost as does Dsn=MonetDB Can anyone explain this? I am at a complete loss. I have taken down my firewalls (at least until I get this figured out), so that can't be the problem. I eventually want to change the TARBELL to the mirrored virtual machine running another instance of the database. Many thanks, Brett

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  • phpexcel write excel and save ?

    - by boss
    code: <?php /** PHPExcel */ require_once '../Classes/PHPExcel.php'; /** PHPExcel_IOFactory */ require_once '../Classes/PHPExcel/IOFactory.php'; // Create new PHPExcel object $objPHPExcel = new PHPExcel(); // Set properties $objPHPExcel->getProperties()->setCreator("Maarten Balliauw") ->setLastModifiedBy("Maarten Balliauw") ->setTitle("Office 2007 XLSX Test Document") ->setSubject("Office 2007 XLSX Test Document") ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.") ->setKeywords("office 2007 openxml php") ->setCategory("Test result file"); $result = 'select * from table1'; for($i=0;$i<count($result);$i++){ $result1 = 'select * from table2 where table1_id = ' . $result[$i]['table1_id']; for ($j=0;$j<count($result1);$j++) { $objPHPExcel->setActiveSheetIndex(0)->setCellValue('A' . $j, $result1[$j]['name']); } // Set active sheet index to the first sheet, so Excel opens this as the first sheet $objPHPExcel->setActiveSheetIndex(0); // Save Excel 2007 file $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel2007'); $objWriter->save(str_replace('.php', '.xlsx', __FILE__)); // Echo done echo date('H:i:s') . " Done writing file.\r\n"; } ?> The above code executes and save n no of .xlsx files in the folder, but the problem im getting is biggest count(result1) in the for loop executing in all saved excel files. Please give me the solution.

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  • PHP PDO Related: Update SQL Statement not Updating the content of Database

    - by Rachel
    I am trying to implement update statement using prepared statement in php script but it appears that it is not update record in the database and am not sure why and so would appreciate if you can share some insights. Code $query = "UPDATE DatTable SET DF_PARTY_ID = :party_id, DF_PARTY_CODE = :party_code, DF_CONNECTION_ID = :connection_id WHERE DF_PARTY_ID = ':party_id'"; $stmt = $this->connection->prepare($query); $stmt->bindValue(':party_id', $data[0], PDO::PARAM_INT); $stmt->bindValue(':party_code', $data[1], PDO::PARAM_INT); $stmt->bindValue(':connection_id', $data[2], PDO::PARAM_INT); $stmt->execute(); Inspiring Solution leading to this approach. Any Suggestions ?

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  • Database design for summarized data

    - by holden
    I have a new table I'm going to add to a bunch of other summarized data, basically to take some of the load off by calculating weekly avgs. My question is whether I would be better off with one model over the other. One model with days of the week as a column with an additional column for price or another model as a series of fields for the DOW each taking a price. I'd like to know which would save me in speed and/or headaches? Or at least the trade off. IE. ID OBJECT_ID MON TUE WED THU FRI SAT SUN SOURCE OR ID OBJECT_ID DAYOFWEEK PRICE SOURCE

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  • Finding date between start date and end date

    - by Pankaj Khurana
    Hi, I want to check whether a date is between start date and end date. i have added a where class where datepaid between '2010-04-01' AND '2010-04-15' but the problem is that it excludes '2010-04-15'. It should include end date also how can i do this? Please help me on this Regards, pankaj

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