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  • SugarCRM installation frozen

    - by Tom S.
    Hi there. I'm trying to install SugarCRM version 5.5.1. on a webhost. Everything goes nice until the step when the installation begins. The output is this one: Creating Sugar configuration file (config.php) Creating Sugar application tables, audit tables and relationship metadata ............. And never moves on! I check the database and can see that there are tables missing. The install.log file doesnt have any errors, and the last line in the file is: 2010-04-27 22:17:03...creating Relationship Meta for Bug It seems the installation stopped here, but i cant get why! Iv searched in the foruns, etc, but cant get it... Anyone had this issue? Any clues about whats happening? Thanks a lot

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  • Codeigniter active record select, left join, count

    - by sea_1987
    Hi There, I have a form that shows results from a database query, these results can have many other assets ajoined to them and I wanting to find a way of showing how many assets each elemement has. For example my table is of areas of england an other table has where the users live I current have this code, $this->db->select('*'); $this->db->from('places'); $this->db->join('users, places.place_id = user.place_id, left'); $this->db->get(); The issue I am having is getting the query to return the place name and the number of users living in that place, it is possible?

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • A rails migration that specifies the distance between two months..?

    - by Trip
    I would like to make two drop downs. a start time, and an end time. Specifically, I only need months. I would like to, for example, choose January, and then March, and then have the database read that it is the these two months plus February. Is there any out of the box migration that could work? I'm guessing.. script/generate migration AddMonthsToClass beginDate:datetime #through endDate:datetime I apologize ahead of time if my question sounds retarded! Sorry! :D

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  • A little bit of Ajax goes a long way

    - by Holland
    ..except when you're having problems. My problem is this: I have a hierarchical list of categories stored in a database which I wish to output in a dropdown list. The hierarchy comes into place when the subcategories are to be displayed, which are dependent on a parent id (which equals out to the first seven or so main categories listed). My thoughts are relatively simple: when the user clicks the dynamically allocated list of main categories, they are clicking on an option tag. For each option tag, an id (i.e., the parent) is listed in the value attribute, as well as an argument which is sent to a Javascript function which then uses AJAX to get the data via PHP and sends it to my 'javascript.php' file. The file then does magic, and populates the subcategory list, which is dependent on the main category selected. I believe I have the idea down, it's just that I'm implementing the solution improperly, for some reason. Here's what I have so far: from javascript.php <script type="text/javascript" src=<?=JPATH_BASE.DS.'includes'.DS.'jquery.js';?>> var ajax = { ajax.sendAjaxData = function(method, url, dataTitle, ajaxData) { $.ajax({ type: 'post', url: "C:/wamp/www/patention/components/com_adsmanagar/views/edit/tmpl/javascript.php", data: { 'data' : ajaxData }, success: function(result){ // we have the response alert("Your request was successful." + result); }, error: function(e){ alert('Error: ' + e); } }); } ajax.printSubCategoriesOnClick = function(parent) { alert("hello world!"); ajax.sendAjaxData('post', 'javascript.php', 'data' parent); <?php $categories = $this->formData->getCategories($_POST['data']); ?> ajax.printSubCategories(<?=$categories;?>); } ajax.printSubCategories = function(categories) { var select = document.getElementById("subcategories"); for (var i = 0; i < categories.length; i++) { var opt = document.createElement("option"); opt.text = categories['name']; opt.value = categories['id']; } } } </script> the function used to populate the form data function populateCategories($parent, FormData $formData) { $categories = $formData->getCategories($parent); echo "<pre>"; print_r($categories); echo "</pre>"; foreach($categories as $section => $row){ ?> <option value=<?=$row['id'];?> onclick="ajax.printSubCategoriesOnClick(<?=$row['id']?>)"> <? echo $row['name']; ?> </option> <?php } } The problem is that when I try to do a print_r on my $_POST variable, nothing shows up. I also receive an "undefined index" error (which refers to the key I set for the data type). I'm thinking that for some reason, the data is being sent to my form.php file, or my default.php file which includes both the form.php and javascript.php files via a function. Is there something specific that I'm missing here? Just looking up basic AJAX syntax (via jQuery) hasn't helped out, unfortunately.

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  • What is wrong with this WHERE clause?

    - by Victor
    Is there a reason why this query doesn't work? The following query will work if I just exclude the WHERE clause. I need to know what is wrong with it. I know the given values of $key exists in the table, so why doesn't this work? $q = "SELECT * WHERE t1.project=$key FROM project_technologies AS t1 JOIN languages AS t2 ON t1.language = t2.key"; Table's have the following fields: project_technologies - key - project - language languages - key - name

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  • How do I put array into columns

    - by mathew
    $db = mysql_connect("", "", "") or die("Could not connect."); mysql_select_db("",$db)or die(mysql_error()); $sql = "SELECT * FROM table where 1"; $pager = new pager($sql,'page',6); while($row = mysql_fetch_array($pager->result)) { echo $row['persons']."<br>"; } mysql_close($db); above code output : Mathew Thomas John Stewart Watson Kelvin What I need is it should split inot multiple columns say: Mathew Stewart Thomas Watson John Kelvin HOw do I do this??

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  • Implementing database redundancy with sharded tables

    - by ensnare
    We're looking to implement load balancing by horizontally sharding our tables across a cluster of servers. What are some options to implement live redundancy should a server fail? Would it be effective to do (2) INSERTS instead of one ... one to the target shard, and another to a secondary shard which could be accessed should the primary shard not respond? Or is there a better way? Thanks.

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  • Another rookie question; How to implement Count() here?

    - by Camran
    I have this query: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id ORDER BY modify_date DESC I need to implement a count here, to just count all rows in combination with the JOINS you see. How should I do this? SELECT COUNT(mt.*, fordon.* etc) FROM ? // This method wont work Thanks

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  • How do I show a user's credit based on their session

    - by Jamie
    Hi all - I'm developing a simple LAMP app where users can credit their account using Paypal. I suspect this is a simple issue, but have spent quite a while experimenting to no avail and would appreciate any thoughts: System has a user management system working fine using sessions, but I can't get it to display the current user's credit. But I've been trying things along the lines of: $result = mysql_query(" SELECT * FROM users INNER JOIN account ON account.UserID=account.UserID ORDER BY account.accountID"); while($_SESSION['Username'] = $row['Username'] ) { echo $row['Username']; echo $row['Credit']; } I suspect the while statement is invalid, but I want it to echo username and credit where the current session username = the username stored in the database. Thanks so much for taking a look - very much appreciated.

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  • Help with SQL query (add 5% to users with conditions)

    - by Mestika
    Hi everyone, I’m having some difficulties with a query which purpose is to give users with more than one thread (called CS) in current year a 5% point “raise”. My relational schema looks like this: Thread = (threadid, threadname, threadLocation) threadoffering = (threadid, season, year, user) user = (name, points) Then, what I need is to check: WHERE thread.threadid = threadoffering.threadid AND where threadoffering.year AND threadoffering.season = currentDate AND where threadoffering.User 1 GIVE 5 % raise TO user.points I hope it is explained thoroughly but otherwise here it is in short text: Give a 5 % “point raise” to all users who has more than 1 thread in threadLocation CS in the current year and season (always dynamic, so for example now is year = 2010 and season is = spring). I am looking forward to your answer Sincerely, Emil

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  • PDO::PARAM for type decimal?

    - by dmontain
    I have 2 database fields `decval` decimal(5,2) `intval` int(3) I have 2 pdo queries that update them. The one that updates the int works ok $update_intval->bindParam(':intval', $intval, PDO::PARAM_INT); but I can't update the decimal field. I've tried the 3 ways below, but nothing works $update_decval->bindParam(':decval', $decval, PDO::PARAM_STR); $update_decval->bindParam(':decval', $decval, PDO::PARAM_INT); $update_decval->bindParam(':decval', $decval); It seems the problem is with the database type decimal? Is there a PDO::PARAM for a field of type decimal? If not, what do I use as a workaround?

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  • Relational database question with php.

    - by Oliver Bayes-Shelton
    Hi, Not really a coding question more a little help with my idea of a Relational database. If I have 3 tables in a SQL database. In my php script I basically query the companies which are in industry "a" and then insert a row into a separate table with their details such as companyId , companyName etc is that a type of Relational database ? I have explained it in a simple way so we don't get confused what I am trying to say.

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  • XML flat file vs. relational database backend

    - by donpal
    Most projects now need some form of a database. When someone says database, I usually think relational databases, but I still hear about flat file XML databases. What parameters do you take into consideration when deciding between a "real" database and a flat-file XML database. When should one be used over the other, and under what circumstances should I never consider using a flat file (or vice versa a relational) database?

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  • Relational database queestion with php.

    - by Oliver Bayes-Shelton
    Hi, Not really a coding question more a little help with my idea of a Relational database. If I have 3 tables in a SQL database. In my php script I basically query the companies which are in industry "a" and then insert a row into a seperate table with their details such as companyId , companyName etc is that a type of Relational database ? I have explained it in a simple way so we don't get confused what I am trying to say.

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  • Select query 2-3 times faster than view

    - by Richard Knop
    This query run alone: SELECT -- lots of columns FROM (((((((((((`table1` `t1` LEFT JOIN `table2` `t2` ON(( `t2`.`userid` = `t1`.`userid` ))) LEFT JOIN `table3` `t3` ON(( `t1`.`orderid` = `t3`.`orderid` ))) LEFT JOIN `table4` `t4` ON(( `t4`.`orderitemlicenseid` = `t3`.`orderitemlicenseid` ))) LEFT JOIN `table5` `t5` ON(( `t1`.`orderid` = `t5`.`orderid` ))) LEFT JOIN `table6` `t6` ON(( `t5`.`transactionid` = `t6`.`transactionid` ))) LEFT JOIN `table7` `t7` ON(( `t7`.`transactionid` = `t5`.`transactionid` ))) LEFT JOIN `table8` `t8` ON(( `t8`.`voucherid` = `t7`.`voucherid` ))) LEFT JOIN `table9` `t9` ON(( `t8`.`voucherid` = `t9`.`voucherid` ))) LEFT JOIN `table10` `t10` ON(( ( `t10`.`vouchergroupid` = `t9`.`vouchergroupid` ) AND ( `t2`.`territoryid` = `t10`.`territoryid` ) ))) LEFT JOIN `table11` `t11` ON(( `t11`.`voucherid` = `t8`.`voucherid` ))) LEFT JOIN `table12` `t12` ON(( `t12`.`orderid` = `t1`.`orderid` ))) GROUP BY `t5`.`transactionid` Takes about 2.5 seconds to finish. When I save it to a view and run it as: SELECT * FROM viewName; It takes 7 seconds to finish. What is the reason and how can I make the view faster?

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  • How to differenciate the data when doing a UNION on 2 SELECTS ?

    - by wiooz
    If I have the following two tables : Employes Bob Gina John Customers Sandra Pete Mom I will do a UNION for having : Everyone Bob Gina John Sandra Pete Mom The question is : In my result, how can I creat a dumn column of differenciate the data from my tables ? Everyone Bob (Emp) Gina (Emp) John (Emp Sandra (Cus) Pete (Cus) Mom (Cus) I want to know from with table the entry is from withouth adding a new column in the database... SELECT Employes.name FROM Employes UNION SELECT Customers.name FROM Customers;

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  • What scalability problems have you solved using a NoSQL data store?

    - by knorv
    NoSQL refers to non-relational data stores that break with the history of relational databases and ACID guarantees. Popular open source NoSQL data stores include: Cassandra (tabular, written in Java, used by Facebook, Twitter, Digg, Rackspace, Mahalo and Reddit) CouchDB (document, written in Erlang, used by Engine Yard and BBC) Dynomite (key-value, written in C++, used by Powerset) HBase (key-value, written in Java, used by Bing) Hypertable (tabular, written in C++, used by Baidu) Kai (key-value, written in Erlang) MemcacheDB (key-value, written in C, used by Reddit) MongoDB (document, written in C++, used by Sourceforge, Github, Electronic Arts and NY Times) Neo4j (graph, written in Java, used by Swedish Universities) Project Voldemort (key-value, written in Java, used by LinkedIn) Redis (key-value, written in C, used by Engine Yard, Github and Craigslist) Riak (key-value, written in Erlang, used by Comcast and Mochi Media) Ringo (key-value, written in Erlang, used by Nokia) Scalaris (key-value, written in Erlang, used by OnScale) ThruDB (document, written in C++, used by JunkDepot.com) Tokyo Cabinet/Tokyo Tyrant (key-value, written in C, used by Mixi.jp (Japanese social networking site)) I'd like to know about specific problems you - the SO reader - have solved using data stores and what NoSQL data store you used. Questions: What scalability problems have you used NoSQL data stores to solve? What NoSQL data store did you use? What database did you use before switching to a NoSQL data store? I'm looking for first-hand experiences, so please do not answer unless you have that.

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  • Table design issues - should I create separate fields or store as a blob

    - by Ali
    Hi guys I'm working on my web based ordering system and we would like to maintain a kind of task history for each of our orders. A hsitory in the sense that we would like to maintain a log of who did what on an order like lets say an order has been entered - we would like to know if the order was acknowledged for an example. Or lets say somebody followed up on the order - etc. Consider that there are numerous situations like this for each order would it be wise to create a schema on the lines of: Orders ID - title - description - date - is_ack - is_follow - ack_by ..... That accounts to a lot of fields - on teh other hand I could have one LongText field called 'history' and fill it with a serialised object holding all the information. However in the latter case I can't run a query to lets say retrieve all orders that have not been acknowledged and stuff like that. With time requirements woudl change and I would be required to modify it to allow for more detailed tracking and that is why I need to set up a way which would be feasible to scale upon yet I don't want to be restricted on the SQL side too much.

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  • Opencart Installation and Display Errors

    - by jpoles1
    Hello, I need a bit of help installing a copy of Opencart onto my Godaddy hosting. I have had one major problem and that was, after during and after the install, none of the styles or images where appearing. I was able to completely fix the admin panel, but I am now running into problems with the frontend. I was able to fix the styles by editing a couple lines in the index.php file: define('HTTP_SERVER', 'http://' . $_SERVER['HTTP_HOST'] .'/opencart/'); define('HTTP_IMAGE', 'http://jpoles1.com/image/'); Now the problem is that unless you are on the base url http://jpoles1.com/opencart/, none of the database functionality works. For example the brands dropdown on the left will only be populated on the root page. Am I going about this problem the wrong way? What should I do to fix this problem? -- Thanks, Jordan

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  • How to upgrade self-hosted wordpress and installed plugins of live site to latest availalbe versions

    - by jitendra
    I have to upgrade a running wordpress site's wordpress CMS and some installed plugins.and some plugins which i want to upgrade has been modified before to achieve something. http://is.gd/b5j9h How to upgrade Wordpress to latest without loosing anything, any post, comments? What precautions should i take? How should i take backup of all things? Should i take backup of database also? How to upgraded modified plugins without loosing functionality?

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