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  • problem with setcookie

    - by Simon
    there is one think, i can't understand anyway:((( when i try to set cookie(it is on line 28 in login.php), browser returns me an error!!! Cannot modify header information - headers already sent by (output started at C:\xampp2\htdocs\video\index.php:9) in C:\xampp2\htdocs\video\login.php on line 28 but on line 9 in index php, i haven't any header!!! there is a tag!!! i cant understand it!!! can somebody tall me why it returns me such error?

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  • WordPress: Display Single Post

    - by Jeremy Person
    I am trying to display a WordPress post on the homepage of a site. It is reporting the following error: Parse error: syntax error, unexpected '=' in /home/####/####/####/####/wp-content/themes/oceanswaves/home.php on line 105 <?php query_posts(‘p=143'); if(have_posts()) : the_post(); ?> <?php the_content(); ?> <?php endif; ?> Thank you

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  • facebook app using fbml displays nothing

    - by fusion
    i've made an app in php and html and trying to integrate it with fb. the app on my website is using jquery, but knowing that fbml doesn't support jquery, i've tried to instead use fbjqry. this doesn't work either. i'm not sure where i'm going wrong. /////////////// index.php: <?php // Copyright 2007 Facebook Corp. All Rights Reserved. require_once 'config_fb.php'; //***** Greet the currently logged-in user! echo "<p>Hello, <fb:name uid=\"$user_id\" useyou=\"false\" />!</p>"; include 'quote.html'; ?> ///////////////// quote.html: <!DOCTYPE html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <link rel="stylesheet" type="text/css" href="css/jquote.css" /> <!--<script type="text/javascript" src="scripts/jquery-1.4.2.js"></script>--> <script type="text/javascript" src="fbjqry/utility.js"></script> <script type="text/javascript" src="fbjqry/fjqry.js"></script> <script type="text/javascript"> // On page load, fill the box with content. $(document).ready(function() { $("#quoteContainer").load("quote.php"); }); var auto_refresh = setInterval( function () { $('#quoteContainer').load('quote.php'); }, 5000); // refresh every 10000 milliseconds </script> </head> <div id="wrapper"> <div class="header">&nbsp;Quote of the Day</div> <div id="quoteContainer"> </div> </div> </html> //// from the above file it should take quotes from quote.php and display it, but it doesn't display anything. it seems as though it isn't reading from the quote.php file. is the command of fbjqry different from jquery? if i use iframes instead of fbml, everything loads correctly except that i'd like tab/profile box for this app, which iframes doesn't have.

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  • session management: problem displaying username in the header

    - by aeonsleo
    hi, I am working on a simple login and logout module for my website without any security. I am using wamp on a windows xp machine. I am creating session when a user submits the login informaton it redirects to a process.php file which creates the session variables and starts session. Now if the login is successful user is redirected to the welcome page which includes a header file(which displays the header involving signin logout help options) The problem is the header is not changing the signin link to logout as the user logs successfully. The below code is from process.php which initiates a login. $username = $_POST['username']; $password = $_POST['password']; //echo "{$username}:{$password}"; $connection = mysql_connect("localhost","root",""); if(!$connection) { die("Database Connection Failed".mysql_error()); } $db_select = mysql_select_db("tester",$connection); if(!$db_select) { die("Database Selection Failed".mysql_error()); } $result = mysql_query("SELECT * FROM user",$connection); if(!$result) { die("Database Selection Failed".mysql_error()); } $q = "SELECT * FROM user " ."WHERE Name='".$username."' AND Password='".$password. "' "; // Run query $r = mysql_query($q); if ( $obj = @mysql_fetch_object($r) ) { session_start(); // Login good, create session variables $_SESSION["valid_id"] = session_id(); $_SESSION["valid_user"] = $_POST["username"]; $_SESSION["valid_time"] = time(); Header('Location: welcome.php'); The following code is from header.php which is included in welcome.php </div> <div id = "userdetail"> <?php if(isset($_SESSION["valid_user"])) { echo($_SESSION["valid_user"]." " ); echo("<a href=logout.php>Logout</a>"); } else { echo("<a href = login.php>Sign In</a>"); } ?> | Help | Search <input type = "text" name = "searchbox" value = "" /> </div> </div>

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  • Rewritecond multiple RewriteRule

    - by swamprunner7
    How can i rewrite these: RewriteCond %{HTTP_HOST} ^(www\.)?([0-9a-zA-Z\-_]+)\.test\.com$ [NC] RewriteRule ^$ /feeds.php?act=user&login=%2 [L] RewriteCond %{HTTP_HOST} ^(www\.)?([0-9a-zA-Z\-_]+)\.test\.com$ [NC] RewriteRule ^(faves)$ /feeds.php?act=faves&login=%2 [L] to something like: RewriteCond %{HTTP_HOST} ^(www\.)?([0-9a-zA-Z\-_]+)\.test\.com$ [NC] RewriteRule ^$ /feeds.php?act=user&login=%2 [L] RewriteRule ^(faves)$ /feeds.php?act=faves&login=%2 [L] Is it posible to apply RewriteCond for multiple rules?

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  • Drupal site requires a higher memory limit after migration? Why?

    - by oalo
    Hello. We have a website which had a previous memory limit of 12 MB (12 MB in php.ini, and 16 MB in settings.php) and worked previously. After moving to a new server it started giving memory limit errors and displaying half-blank screen. We increaded the limit in both files (php.ini and settings.php) and now it works, but I dont understand how is it possible that now it needs a considerably larger amount of memory (it used to work with 12 MB, now it cont work with less than 20 MB).

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  • PHPUnit Command Line Include Path

    - by thatidiotguy
    So I have a project structure like so: MyProject/ src/ //subfolders and source code ..... tests/ package/ MyTest.php I am trying to run the unit tests in MyTest.php with PHPUnit but it has a use statement for PHP classes located in the src folder. So I tried to use the include-path directive for PHPUnit like so: (I am in the directory with MyTest.php) phpunit --include-path ~/workspace/MyProject/src/ MyTest Unfortunately execution is halting at the first use statement. What gives?

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  • Getting a file pointer from file descriptor

    - by Naga Kiran
    In PHP 5.2.3, "fdopen" was used to read/write to a file descriptor that's opened by another application. fdopen(<fileDescriptorId>,"rw"); //It worked fine with PHP 5.2.3 After upgrading PHP to 5.3.2, it's throwing "undefined reference to 'fdopen' function". Please suggest whats the replacement for this in PHP 5.3.2 or any workaround.

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  • Reading an XML file and store data to mysql database.

    - by Jack Brown
    Hi I need the following php script to do a currency conversion using a different XML file. Its a script from white-hat design http://www.white-hat-web-design.co.uk/articles/php-currency-conversion.php The script needs to be amended to do the following: 1, The php script downloads every 24 hours an xml file from rss.timegenie.com/foreign_exchange_rates_forex rss.timegenie.com/forex.xml rss.timegenie.com/forex2.xml 2, It then stores the xml file data/contents to a mysql database file ie currency and rate. Any advice would be appreciated.

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  • Can't use method return value in write context--how to fix for include_once?

    - by Bill Paetzke
    I'm getting this error in CodeIgniter when trying to load the email library: Can't use method return value in write context It's happening on line 827 of Loader.php in [codeigniter root]/system/libraries/Loader.php include_once($filepath); where $filepath equals "/var/www/system/libraries/Email.php" I called it like this in another php file: $this->load->library('email'); where $this is the CodeIgniter instance. According to the CodeIgniter email doc page, I'm doing it right. But it's not working...

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  • ZF Autoloader to load ancestor and requested class

    - by Pekka
    I am integrating Zend Framework into an existing application. I want to switch the application over to Zend's autoloading mechanism to replace dozens of include() statements. I have a specific requirement for the autoloading mechanism, though. Allow me to elaborate. The existing application uses a core library (independent from ZF), for example: /Core/Library/authentication.php /Core/Library/translation.php /Core/Library/messages.php this core library is to remain untouched at all times and serves a number of applications. The library contains classes like class ancestor_authentication { ... } class ancestor_translation { ... } class ancestor_messages { ... } in the application, there is also a Library directory: /App/Library/authentication.php /App/Library/translation.php /App/Library/messages.php these includes extend the ancestor classes and are the ones that actually get instantiated in the application. class authentication extends ancestor_authentication { } class translation extends ancestor_translation { } class messages extends ancestor_messages { } usually, these class definitions are empty. They simply extend their ancestors and provide the class name to instantiate. $authentication = new authentication(); The purpose of this solution is to be able to easily customize aspects of the application without having to patch the core libraries. Now, the autoloader I need would have to be aware of this structure. When an object of the class authentication is requested, the autoloader would have to: 1. load /Core/Library/authentication.php 2. load /App/Library/authentication.php My current approach would be creating a custom function, and binding that to Zend_Loader_Autoloader for a specific namespace prefix. Is there already a way to do this in Zend that I am overlooking? The accepted answer in this question kind of implies there is, but that may be just a bad choice of wording. Are there extensions to the Zend Autoloader that do this? Can you - I am new to ZF - think of an elegant way, conforming with the spirit of the framework, of extending the Autoloader with this functionality? I'm not necessary looking for a ready-made implementation, some pointers (This should be an extension to the xyz method that you would call like this...) would already be enough.

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  • First record does not show in pagination script

    - by whitstone86
    This is my pagination script which extracts info for my TV guide project that I am working on. Currently I've been experimenting with different PHP/MySQL before it becomes a production site. This is my current script: <?php /*********************************** * PhpMyCoder Paginator * * Created By PhpMyCoder * * 2010 PhpMyCoder * * ------------------------------- * * You may use this code as long * * as this notice stays intact and * * the proper credit is given to * * the author. * ***********************************/ // set the default timezone to use. Available since PHP 5.1 putenv("TZ=US/Eastern") ?> <head> <title> Pagination Test - Created By PhpMyCoder</title> <style type="text/css"> #nav { font: normal 13px/14px Arial, Helvetica, sans-serif; margin: 2px 0; } #nav a { background: #EEE; border: 1px solid #DDD; color: #000080; padding: 1px 7px; text-decoration: none; } #nav strong { background: #000080; border: 1px solid #DDD; color: #FFF; font-weight: normal; padding: 1px 7px; } #nav span { background: #FFF; border: 1px solid #DDD; color: #999; padding: 1px 7px; } </style> </head> <?php //Require the file that contains the required classes include("pmcPagination.php"); //PhpMyCoder Paginator $paginator = new pmcPagination(20, "page"); //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, airdate, expiration, episode, setreminder FROM lagunabeach where expiration >= now() order by airdate, 3 ASC LIMIT 0, 100;"); //You can also add reuslts to paginate here mysql_data_seek($queryresult,0) ; while($row = mysql_fetch_array($result)) { $paginator->add(new paginationData($row['programme'], $row['channel'], $row['airdate'], $row['expiration'], $row['episode'], $row['setreminder'])); } ?> <?php //Show the paginated results $paginator->paginate (); ?><? include("pca-footer1.php"); ?> <?php //Show the navigation $paginator->navigation(); ?> Despite me having two records for the programmes airing today, it only shows records from the second one onwards - the programme that airs at 8:35pm UK time GMT does not show, but the later 11:25pm UK time GMT one does show. How should I fix this? Above is my code if that is of any use! Thanks

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  • Using ImageMagick to create an image from a PDF...efficiently

    - by bigsweater
    I'm using ImageMagick to create a tiny JPG thumbnail image of an already-uploaded PDF. The code works fine. It's a WordPress widget, though this isn't necessarily WordPress specific. I'm unfamiliar with ImageMagick, so I was hoping somebody could tell me if this looks terrible or isn't following some best practices of some sort, or if I'm risking crashing the server. My questions, specifically, are: Is that image cached, or does the server have to re-generate the image every time somebody views the page? If it isn't cached, what's the best way to make sure the server doesn't have to regenerate the thumbnail? I tried to create a separate folder (/thumbs) for ImageMagick to put all the images in, instead of cluttering up the WP upload folders with images of PDFs. It kept throwing a permission error, despite 777 permissions on the folder in my testing environment. Why? Do the source/destination directories have to be the same? Am I doing anything incorrectly/inefficiently here that needs to be improved? The whole widget is on Pastebin: http://pastebin.com/WnSTEDm7 Relevant code: <?php if ( $url ) { $pdf = $url; $info = pathinfo($pdf); $filename = basename($pdf,'.'.$info['extension']); $uploads = wp_upload_dir(); $file_path = str_replace( $uploads['baseurl'], $uploads['basedir'], $url ); $dest_path = str_replace( '.pdf', '.jpg', $file_path ); $dest_url = str_replace( '.pdf', '.jpg', $pdf ); exec("convert \"{$file_path}[0]\" -colorspace RGB -geometry 60 $dest_path"); ?> <div class="entry"> <div class="widgetImg"> <p><a href="<?php echo $url; ?>" title="<?php echo $filename; ?>"><?php echo "<img src='".$dest_url."' alt='".$filename."' class='blueBorder' />"; ?></a></p> </div> <div class="widgetText"> <?php echo wpautop( $desc ); ?> <p><a class="downloadLink" href="<?php echo $url; ?>" title="<?php echo $filename; ?>">Download</a></p> </div> </div> <?php } ?> As you can see, the widget grabs whatever PDF is attached to the current page being viewed, creates an image of the first page of the PDF, stores it, then links to it in HTML. Thanks for any and all help!

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  • Generate navigation from a multi-dimensional array

    - by rg88
    The question: How do I generate navigation, allowing for applying different classes to different sub-items, from a multi-dimensional array? Here is how I was doing it before I had any need for multi-level navigation: Home Pics About and was generated by calling nav(): function nav(){ $links = array( "Home" => "home.php", "Pics" => "pics.php", "About" => "about.php" ); $base = basename($_SERVER['PHP_SELF']); foreach($nav as $k => $v){ echo buildLinks($k, $v, $base); } } Here is buildLinks(): function buildLinks($name, $page, $selected){ if($selected == $page){ $theLink = "<li class=\"selected\"><a href=\"$page\">$name</a></li>\n"; } else { $thelink = "<li><a href=\"$page\">$name</a></li>\n"; } return $thelink; } My question, again: how would I achieve the following nav (and notice that the visible sub navigation elements are only present when on that specific page): Home something1 something2 Pics About and... Home Pics people places About What I've tried From looking at it it would seem that some iterator in the SPL would be a good fit for this but I'm not sure how to approach this. I have played around with RecursiveIteratorIterator but I'm not sure how to apply a different style to only the sub menu items and also how to only show these items if you are on the correct page. I built this array to test with but don't know how to work with the submenu1 items individually: $nav = array( array( "Home" => "home.php", "submenu1" => array( "something1"=>"something1.php", "something2" => "something2.php") ), array("Pics" => "pics.php"), array("About" => "about.php") ); The following will print out the lot in order but how do I apply, say a class name to the submenu1 items or only show them when the person is on, say, the "Home" page? $iterator = new RecursiveIteratorIterator(new RecursiveArrayIterator($nav)); foreach($iterator as $key=>$value) { echo $key.' -- '.$value.'<br />'; }

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  • When using the Auth component with CakePHP, I keep ketting this error. Why?

    - by Josh Brown
    Warning (2): Cannot modify header information - headers already sent by (output started at /Applications/MAMP/htdocs/iframeworking/iframe/app/models/frame.php:7) [COREcake/libs/controller/controller.php, line 647] here is the code from frame.php: <?php class Frame extends AppModel { var $name = 'Frame'; var $belongsTo = array('User' => array('className' => 'User', 'dependent' => true)); } ?>

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  • how to facebook shoutbox open , with clicked friendname

    - by Surendra Singh
    Hey everyone i need source code for shotbox open with clicked friend name like facebook i tried it but ... it is opening with only one friend name .... i want it will open with the name of friend whom name or image is clicked My code is something like this <tr data-name="<?php echo $online_user_name; ?>"> <td> <div <?php echo $online_user_id; ?>"> <img src="../../social_users/<?php echo $online_user_gender; ?>/<?php echo $online_user_Email; ?>/Profile/<?php echo $online_user_pic; ?>" height="30" width="30" style="border-radius: 20px; border: 2px solid #fff;" onclick="shoutbox_open();"> </div> </td> <td style="color:#ffffff;"> <div <?php echo $online_user_id; ?> style="text-transform:capitalize; text-decoration:none; color:#6A7480;" onclick="shoutbox_open();"> <?php echo $online_user_name; ?> </div> &nbsp; </td> <td> <img src="background_file/background_icons/online_symbol.png" /> </td> </tr> <div id="shout_box"> <div id="header" > <span> <?php echo $online_user_name; ?> </span> <div id="close_btn" onclick="shoutbox_close();"> &nbsp; </div> </div> <div id="toggle_chat"> <div id="message_box"> </div> <div id="user_info"> <input name="shout_username" id="shout_username" type="text" placeholder="Your Name" value="" maxlength="15" /> <input name="shout_message" id="shout_message" type="text" placeholder="Type Message Hit Enter" maxlength="100" /> </div> </div> </div>

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  • Using jQuery to store basic text string in mySQL base?

    - by Kenny Bones
    Could someone point me in the right direction here? Basically, I've got this jQuery code snippet: $('.bggallery_images').click(function () { var newBG = "url('" + $(this).attr('src'); var fullpath = $(this).attr('src'); var filename = fullpath.replace('img/Bakgrunner/', ''); $('#wrapper').css('background-image', newBG); // Lagre til SQL $.ajax({ url: "save_to_db.php", // The url to your function to handle saving to the db data: filename, dataType: 'Text', type: 'POST', // Could also use GET if you prefer success: function (data) { // Just for testing purposes. alert('Background changed to: ' + data); } }); }); This is being run when I click a certain button. So it's actually within a click handler. If I understand this correctly, this snippet takes the source if the image I just clicked and strips it so I end up with only the filename. If I do an alert(filename), I get the filename only. So this is working ok. But then, it does an ajax call to a php file called "save_to_db.php" and sends data: filename. This is correct right? Then, it does a callback which does an alert + data. Does this seem correct so far? Cause my php file looks like this: <?php require("dbconnect2.php"); $uploadstring = $_POST['filename']; $sessionid = $_SESSION['id']; echo ($sessionid); mysql_query("UPDATE brukere SET brukerBakgrunn = '$uploadstring' WHERE brukerID=" .$_SESSION['id']); mysql_close(); ?> When I click the image, the jQuery snippet fires and I get the results of this php file as output for the alert box. I think that the variables somehow are empty. Because notice the echo($sessionid); which is a variable I've created just to test what the session ID is. And it returns nothing. What could be the issue here? Edit: I just tried to echo out the $uploadstring variable as well and it also returns nothing. It's like the jQuery snippet doesn't even pass the variable on to the php file?

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  • How is $sys_root bieng assigned a value?

    - by Babiker
    I have been learning php for sometime now. Besides reading books and doing tutorials i also like to sometimes read other programmers code. I have came across this: <?php // authentication. include_once($sys_root."/inc/authenticate_check.php"); I understand the use for $sys_root, but what i dont understand is, how is $sys_root bieng assigned a value. I have checked and made sure that $sys_root is not a special var of PHP's.

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  • Write Mysql tables to XML : Security Issue

    - by jasmine
    I want to make a news portal(php) with minimum mysql force. :create a cron, fetch data from mysql and write to a php file . (I dont know is it right way) But Can I use xml instead of php file? Write mysql data to xml. Is this a secure way? What is the best way? XML or php file? Thanks in advance

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  • how to know smtp server name of my ISP?

    - by Piyush
    I want to send a mail from localhost. I am using XAMPP to develop my php app.I found in google that I have to modify php.ini file, localhost must be replaced by server name of my ISP.Whats that??? [mail function] ; For Win32 only. ; http://php.net/smtp SMTP = localhost ; http://php.net/smtp-port smtp_port = 25

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  • error to connect soap server

    - by moustafa
    i am working on shopping cart project, i need globalpay integration . i got the sample code and run in my localhost it shows me error this. Warning: SoapClient::__construct() [function.SoapClient---construct]: SSL: fatal protocol error in C:\wamp\www\exampls\PHP Web Service Sample (Credit Card) 4.0.0\PHP Web Service Sample (Credit Card) 4.0.0\globalpay.inc.php on line 37 i enabled soap server in php.ini.

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  • chained selects with one table

    - by Owen
    I know I am going about this in an unusual way, every tut I've seen uses multiple tables, but due to the way the rest of my site works I would like to create a chained select which operates using a single table. My table structure is: ---------------------- |Catagory|SubCategory| |01|cat1 |subcat1 | |02|cat1 |subcat2 | |03|cat2 |subcat1 | |04|cat2 |subcat2 | ---------------------- The code I have so far looks like: <tr> <td class="shadow"><strong>Category:</strong> </td> <td class="shadow"> <select id="category" name="category" style="width:150px"> <option selected="selected" value="<?php echo $category ?>"><?php echo $category?></option> <?php include('connect.php'); $result1 = mysql_query("SELECT DISTINCT category FROM categories") or die(mysql_error()); while($row = mysql_fetch_array( $result1 )) { $category = $row['category']; echo "<option value='". $row['category'] ."'>". $row['category'] ."</option>"; } ?> </select> </td> </tr> <tr> <td class="shadow"><strong>Sub Category:</strong> </td> <td class="shadow"> <select id="sub_catgory" name="sub_category" style="width:150px;"> <option selected="selected" value="<?php echo $sub_category ?>"><?php echo $sub_category ?></option> <?php include('connect.php'); $result2 = mysql_query("SELECT sub_category FROM categories WHERE ") or die(mysql_error()); while($row = mysql_fetch_array ($result2 )){ echo "<option value='" . $row['sub_category'] . "'>". $row['sub_category']. "</option>"; } ?> </select> </td> </tr> On the second select I am not sure how to state the WHERE clause. I need it to display the subcategories which have the same category as selected in the first select. PART 2 how would I include AJAX in this to preload the data so i don't need to refresh the page. Could someone either help me finish what I've started here or point me to a good tutorial. thanks

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  • Call to undefined function phpinclude_once()

    - by Alex Zylman
    I'm making a new php page and I get the error Fatal error: Call to undefined function phpinclude_once() in /home8/nuventio/public_html/marketing/pb2/dashboard.php on line 1 I'm not sure why I'm getting this error, I've done previous pages the same way as this with no problems. This is the line in question: <?php include_once("../utils.php"); ?> After that it just goes into regular HTML code. It works fine without that line.

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  • Problem carrying Session over to other pages

    - by AAA
    I am able to login a user, but while processing to the next page (memebers area) I can't display any user info let alone print the $_SESSION[email]. I am not sure what's up. Below is the login code and the testing members are page. Login page: session_start(); //also in a real app you would get the id dynamically $sql = "select `email`, `password` from `accounts` where `email` = '$_POST[email]'"; $query = mysql_query($sql) or die ("Error: ".mysql_error()); while ($row = mysql_fetch_array($query)){ $email = $row['email']; $secret = $row['password']; //we will echo these into the proper fields } mysql_free_result($query); // Process the POST variables $email = $_POST["email"]; //Variables $_SESSION["email"] = $_POST["email"]; $secret = $info['password']; //Checks if there is a login cookie if(isset($_COOKIE['ID_my_site'])) //if there is, it logs you in and directes you to the members page { $email = $_COOKIE['ID_my_site']; $pass = $_COOKIE['Key_my_site']; $check = mysql_query("SELECT email, password FROM accounts WHERE email = '$email'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if (@ $info['password'] != $pass) { } else { header("Location: home.php"); } } } //if the login form is submitted if (isset($_POST['submit'])) { // if form has been submitted // makes sure they filled it in if(!$_POST['email'] | !$_POST['password']) { die('You did not fill in a required field.'); } // checks it against the database if (!get_magic_quotes_gpc()) { $_POST['email'] = addslashes($_POST['email']); } $check = mysql_query("SELECT email,password FROM accounts WHERE email = '".$_POST['email']."'")or die(mysql_error()); //Gives error if user dosen't exist $check2 = mysql_num_rows($check); if ($check2 == 0) { die('That user does not exist in our database. <a href=add.php>Click Here to Register</a>'); } while($info = mysql_fetch_array( $check )) //gives error if the password is wrong if (@ $_POST['password'] != $info['password']) { die('Incorrect password, please try again'); } else { // if login is ok then we add a cookie $_POST['email'] = stripslashes($_POST['email']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['email'], $hour); setcookie(Key_my_site, $_POST['password'], $hour); //then redirect them to the members area header("Location: home.php"); } } } else { // if they are not logged in ?> <?php } ?> home.php session_start(); if(!isset($_SESSION['email'])) { header('Location: login_test3.php'); die('<a href="login_test3.php">Login first!</a>'); } //Variables $_SESSION["email"] = $email; print $_SESSION['name']; UPDATE Just realized the existing code gets in to the home.php file but will not echo anything. But as soon as you hit refresh the session is gone.

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  • mod_rewrite - Don't get a second rule work

    - by poru
    I want to have a url like this: domain.com/css/site.css?test=234 Rule: RewriteEngine On RewriteRule ^([a-z]+)/$ $1.php RewriteRule ^css/([a-zA-Z0-9]+).css?count=(.*)$ css.php?f=$1&test=$2 But I get every time a 404: Not found (site.css) If I have a rule like that it works, just without getting the $_GET-Variable: RewriteEngine On RewriteRule ^([a-z]+)/$ $1.php RewriteRule ^css/([a-zA-Z0-9]+).css$ css.php?f=$1

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