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  • Why won't the following PDO transaction won't work in PHP?

    - by jfizz
    I am using PHP version 5.4.4, and a MySQL database using InnoDB. I had been using PDO for awhile without utilizing transactions, and everything was working flawlessly. Then, I decided to try to implement transactions, and I keep getting Internal Server Error 500. The following code worked for me (doesn't contain transactions). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } Then I attempted to utilize transactions with the following code (which doesn't work). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->beginTransaction(); $dbh->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); $dbh->commit(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } When I run the previous code, I get an Internal Server Error 500. Any help would be greatly appreciated! Thanks!

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  • How can I join 3 tables with mysql & php?

    - by steven
    check out the page [url]http://www.mujak.com/test/test3.php[/url] It pulls the users Post,username,xbc/xlk tags etc which is perfect... BUT since I am pulling information from a MyBB bulletin board system, its quite different. When replying, people are are allowed to change the "Thread Subject" by simplying replying and changing it. I dont want it to SHOW the changed subject title, just the original title of all posts in that thread. By default it repies with "RE:thread title". They can easily edit this and it will show up in the "Subject" cell & people wont know which thread it was posted in because they changed their thread to when replying to the post. So I just want to keep the orginial thread title when they are replying. Make sense~?? Tables:mybb_users Fields:uid,username Tables:mybb_userfields Fields:ufid Tables:mybb_posts Fields:pid,tid,replyto,subject,ufid,username,uid,message Tables:mybb_threads Fields:tid,fid,subject,uid,username,lastpost,lastposter,lastposteruid I haev tried multiple queries with no success: $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_userfields.ufid ) WHERE mybb_posts.fid=42"); $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_posts.uid ) WHERE mybb_threads.fid=42"); $result = mysql_query(" SELECT * FROM mybb_posts LEFT JOIN (mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid ) WHERE mybb_posts.fid=42");

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  • php weird bug where an array is not an array !

    - by iko
    I've been going mad trying to figure out why an array would not be an array in php. For a reason I can't understand I have a bug in a smarty class. The code is this : $compiled_tags = array(); for ($i = 0, $for_max = count($template_tags); $i < $for_max; $i++) { $this->_current_line_no += substr_count($text_blocks[$i], "\n"); // I tried array push instead to see // bug is here array_push($compiled_tags,$this->_compile_tag($template_tags[$i])); //$compiled_tags[] = $this->_compile_tag($template_tags[$i]); $this->_current_line_no += substr_count($template_tags[$i], "\n"); } the error message is Warning: array_push() expects parameter 1 to be array, integer given in .... OR before with [] Warning: Cannot use a scalar value as an array in .... I trying a var_debug on $compiled_tags and as soon I enter the for loop is not an array anymore but an integer. I tried renaming the variable, but same problem. I'm sure is something simple that I missed but I can't figure it out. Any help is (as always) welcomed !

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  • What is a good RPC model for building a AJAX web app using PHP & JS?

    - by user366152
    I'm new to writing AJAX applications. I plan on using jQuery on the client side while PHP on the server side. I want to use something like XML-RPC to simplify my effort in calling server-side code. Ideally, I wouldn't care whether the transport layer uses XML or JSON or a format more optimized for the wire. If I was writing a console app I'd use some tool to generate function stubs which I would then implement on the RPC server while the client would natively call into those stubs. This provides a clean separation. Is there something similar available in the AJAX world? While on this topic, how would I proceed with session management? I would want it to be as transparent as possible. For example, if I try to hit an RPC end-point which needs a valid session, it should reject the request if the client doesn't pass a valid session cookie. This would really ease my application development. I'd then have to simply handle the frontend using native JS functions. While on the backend, I can simply implement the RPC functions. BTW I dont wish to use Google Web Toolkit. My app wont be extremely heavy on AJAX.

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  • Where is a small, simple CMS that has no Front End done in PHP?

    - by user559469
    The keys are: small and simple PHP MySql no Front End By "no front end" I mean literally, I can control the look 100%. I just want a CMS on the "backend" to manage content (user login/security, upload images, udate articles, etc.) that will not dictate in anyway how the managed data is presented. Maybe it just keeps the info in a (MySql) database (which I can query and extract myself) or if it writes content, it is in super-clean xhtml fragments or even just xml I will parse myself? I have looked at Wordpress -- and don't like the code it generates, not to mention the sites look too "canned" (you can usually spot a WP site a mile a way.) Joomla and Drupal look more customizable, but they are bloated now in my opinion, and really I just want something lightweight and simple. For one-user mom-and-pop sites. (No tiered publishing/approval systems, and all that.) I envision plugging this CMS into existing websites/web apps where most of the site is made and managed by me, but a few choice areas are managed by the site owner.

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  • Can anyone explain this impossible bit of PHP logic?

    - by user268208
    I'm attempting to debug a simple PHP script. Essentially, there's a variable which is defined with: $variable = ($_GET['variable'] == 'true') ? TRUE : FALSE; Then, in the view file, the following code is meant to display a box if $variable == TRUE: <? if ($variable == true) { ?> <p class="box">You have imported a new plan.</p> <? } ?> Now, even when that $variable, as shown by var_dump($variable); == FALSE, that HTML is printed between the if { } tags. To me, this defies logic. I simply can't figure out this problem out. Furthermore, this code works fine on many PHP4 and PHP5 installations except for one particular server running PHP5.2. Any possible suggestions? Leads? I'm pulling out my hair trying to figure this one out. Thank you.

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  • How to get values from SQL query made by php?

    - by Ole Jak
    So I made a query like this global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); in my DB there are filds ID, UID, SID, TIME (all INT type exept time) So I am triing to print query relult into form <form> <select class="multiselect" multiple="multiple" name="SIDs"> <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); for ($count=1; $count <= $streams_count; $count++) { echo "<option value=\"{$count}\""; echo ">{$count}</option>"; } ?> </select> <br/> <input type="submit" value="Submit Form"/> </form> How to print out as "option" "values" SID's from my sql query?

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  • How to write data option in jQuery.ajax() function when it include in a mysql_query?

    - by cj333
    I modify a php comment system. I want add it after every article witch are query from database. this is the php part <?php ... while($result = mysql_fetch_array($resultset)) { $article_title = $result['article_title']; ... ?> <form id="postform" class="postform"> <input type="hidden" name="title" id="title" value="<?=$article_title;?>" /> <input type="text" name="content" id="content" /> <input type="button" value="Submit" class="Submit" /> </form> ... <?php } ?> this is the ajax part. $.ajax({ type: "POST", url: "ajax_post.php", data: {title:$('#title').val(), content:$('#content').val() ajax_post.php echo $title; echo $content; How to modify the ajax data part that each article's comment can send each data to the ajax_post.php? thanks a lot.

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  • PHP - How do you secure a unique variable name?

    - by 102319141763223461745
    This function cropit, which I shamelessly stole off the internet, crops a 90x60 area from an existing image. In this code, when I use the function for more than one item (image) the one will display on top of the other (they come to occupy the same output space). I think this is because the function has the same (static) name ($dest) for the destination of the image when it's created (imagecopy). I tried, as you can see to include a second argument to the cropit function which would serve as the "name" of the $dest variable, but it didn't work. In the interest of full disclosure I have 22 hours of PHP experience (incidentally the same number of hours since the last I slept) and I am not that smart to begin with. Even if there's something else at work here entirely, seems to me that generally it must be useful to have a way to secure that a variable is always given a unique name. function cropit($srcimg, $dest) { $im = imagecreatefromjpeg($srcimg); $img_width = imagesx($im); $img_height = imagesy($im); $width = 90; $height = 60; $tlx = floor($img_width / 2) - floor ($width / 2); $tly = floor($img_height / 2) - floor ($height / 2); if ($tlx < 0) { $tlx = 0; } if ($tly < 0) { $tly = 0; } if (($img_width - $tlx) < $width) { $width = $img_width - $tlx; } if (($img_height - $tly) < $height) { $height = $img_height - $tly; } $dest = imagecreatetruecolor ($width, $height); imagecopy($dest, $im, 0, 0, $tlx, $tly, $width, $height); imagejpeg($dest); imagedestroy($dest); } $img = "imagefolder\imageone.jpg"; $img2 = "imagefolder\imagetwo.jpg"; cropit($img, $i1); cropit($img2, $i2); ?

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  • PHP class extends not working why and is this how to correctly extend a class?

    - by Matthew
    Hi so I'm trying to understand how inherteince works in PHP using object oriented programming. The main class is Computer, the class that is inheriting is Mouse. I'm extedning the Computer class with the mouse class. I use __construct in each class, when I istinate the class I use the pc type first and if it has mouse after. For some reason computer returns null? why is this? class Computer { protected $type = 'null'; public function __construct($type) { $this->type = $type; } public function computertype() { $this->type = strtoupper($this->type); return $this->type; } } class Mouse extends Computer { protected $hasmouse = 'null'; public function __construct($hasmouse){ $this->hasmouse = $hasmouse; } public function computermouse() { if($this->hasmouse == 'Y') { return 'This Computer has a mouse'; } } } $pc = new Computer('PC', 'Y'); echo $pc->computertype; echo $pc->computermouse;

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  • object-oriented question

    - by user522962
    I am attempting to put all my database connections in 1 php file, rather than in each of my individual php pages. I have the following: //conn.php: <?php class conn { var $username = "name"; var $password = "password"; var $server = "localhost"; var $port = "3306"; var $databasename = "db"; var $tablename = "tablename"; var $connection; public function getConnected() { $this->connection = mysqli_connect( $this->server, $this->username, $this->password, $this->databasename, $this->port ); } } ?> // file.php: <?php require_once("conn.php"); class myClass{ public function con() { $conn = new conn(); $conn->getConnected(); } public function myF() { $stmt = mysqli_prepare($conn->connection, "SELECT * FROM $conn->tablename"); mysqli_stmt_execute($stmt); } } ?> I then call this as follows: $myNew = new myClass(); $myNew-con(); $myNew-myF(); When I call this, I get the following error: Undefined property: myClass::$connection What am I doing wrong?

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  • How to check successful copy() function execution in php?

    - by OM The Eternity
    How to check successful copy() function execution in php? I am using the following code: <? function full_copy( $source, $target ) { if ( is_dir( $source ) ) { @mkdir( $target ); $d = dir( $source ); while ( FALSE !== ( $entry = $d->read() ) ) { if ( $entry == '.' || $entry == '..' ) { continue; } $Entry = $source . '/' . $entry; if ( is_dir( $Entry ) ) { full_copy( $Entry, $target . '/' . $entry ); continue; } copy( $Entry, $target . '/' . $entry ); } $d->close(); }else { copy( $source, $target ); } } $source ='.'; $destination = '/html/parth/'; full_copy($source, $destination); ?> I do not get anything in my parth folder. Why? I am using Windows, Script is executed on fedora system (its my server)...

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  • ZF2 namespace and file system

    - by user1918648
    I have standard Application module in ZF2. It's configured by default, I didn't change anything. I just added some stuff: module/ Application/ src/ Application/ Entity/ Product/ **Product.php** Controller/ **IndexController.php** Product.php namespace Application\Entity; class Product { } IndexController.php namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } } and I get following error: Fatal error: Class 'Application\Entity\Product' not found in \module\Application\src\Application\Controller\IndexController.php on line 20 I use the same namespace, but it doesn't see it. Why? P.S: If I will change Product.php to be the following: namespace Application\Entity\Product; class Product { } then in the IndexController.php the following code will be working: namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } }

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  • Why does this sql statement keep saying it is a boolean and not a parameter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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  • Wordpress Widget - Adding URL to title

    - by Nick Canarelli
    I can't seem to figure out how to wrap the title of the widget in an tag. For example, I am trying to get it so that when you type the url in a text field, it is then placed in the tag so that it is a hyperlink on the website... class Example_Widget extends WP_Widget { /** * Widget setup. */ function Example_Widget() { /* Widget settings. */ $widget_ops = array( 'classname' => 'example', 'description' => __('A widget that displays company announcements.', 'example') ); /* Widget control settings. */ $control_ops = array( 'width' => 300, 'height' => 350, 'id_base' => 'example-widget' ); /* Create the widget. */ $this->WP_Widget( 'example-widget', __('Announcement Widget', 'example'), $widget_ops, $control_ops ); } /** * How to display the widget on the screen. */ function widget( $args, $instance ) { extract( $args ); /* Our variables from the widget settings. */ $title = apply_filters('widget_title', $instance['title'] ); $excerpt = $instance['excerpt']; $url = $instance['url']; /* Before widget (defined by themes). */ echo $before_widget; /* Display the widget title if one was input (before and after defined by themes). */ if ( $title ) echo $before_title . $title . $after_title; /* Display name from widget settings if one was input. */ if ( $excerpt ) printf( '<p style="font-family: arial; font-size: 12px; line-height: 16px;">' . __('%1$s.', 'example') . '</p>', $excerpt ); /* After widget (defined by themes). */ echo $after_widget; } /** * Update the widget settings. */ function update( $new_instance, $old_instance ) { $instance = $old_instance; /* Strip tags for title and name to remove HTML (important for text inputs). */ $instance['title'] = strip_tags( $new_instance['title'] ); $instance['excerpt'] = strip_tags( $new_instance['excerpt'] ); return $instance; } /** * Displays the widget settings controls on the widget panel. * Make use of the get_field_id() and get_field_name() function * when creating your form elements. This handles the confusing stuff. */ function form( $instance ) { /* Set up some default widget settings. */ $defaults = array( 'title' => __('Title Goes Here', 'example'), 'excerpt' => __('Excerpt goes here.'), ); $instance = wp_parse_args( (array) $instance, $defaults ); ?> <!-- Widget Title: Text Input --> <p> <label for="<?php echo $this->get_field_id( 'title' ); ?>"><?php _e('Title:', 'hybrid'); ?></label> <input id="<?php echo $this->get_field_id( 'title' ); ?>" name="<?php echo $this->get_field_name( 'title' ); ?>" value="<?php echo $instance['title']; ?>" style="width:100%;" /> </p> <!-- Your Name: Text Input --> <p> <label for="<?php echo $this->get_field_id( 'excerpt' ); ?>"><?php _e('Excerpt:', 'example'); ?></label> <input id="<?php echo $this->get_field_id( 'excerpt' ); ?>" name="<?php echo $this->get_field_name( 'excerpt' ); ?>" value="<?php echo $instance['excerpt']; ?>" style="width:100%;" /> </p> <?php } } ?> And here is the functions file code register_sidebar(array( 'name' => __( 'Announcements' ), 'description' => __( 'Display company announcements here.' ), 'before_widget' => '', 'after_widget' => '<hr style="margin-top: 4px; color: #f00; background-color: #585040; height: 1px; border: none; margin-bottom: 2px;"/>', 'before_title' => '<h2 style="font-size: 12px;">', 'after_title' => '</h2>' ));

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  • Building a Web Form in ASP.NET and PHP: a Comparison

    While there are important differences between PHP and ASP.NET both are used to build websites. Because of this both need to enable developers to build web forms among other tasks. This article compares building a web form in PHP with building the same form in ASP.NET to help those familiar with one set of tools to learn how to use the other set.... Download a Free Trial of Windows 7 Reduce Management Costs and Improve Productivity with Windows 7

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  • Using PHP Encryption for Login Authentication

    <b>Webreference:</b> "Following up on "Implementing One-way Encryption in PHP," my previous tutorial about using one-way encryption to build a secure online diary application, this article explores using PHP encryption for login authentication."

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  • Creating a Simple PHP Blog in Azure

    - by Josh Holmes
    In this post, I want to walk through creating a simple Azure application that will show a few pages, leverage Blob storage, Table storage and generally get you started doing PHP on Azure development. In short, we are going to write a very simple PHP Blog engine for Azure. To be very clear, this is not a pro blog engine and I don’t recommend using it in production. It’s a » read more.

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  • PHP blunders with random numbers

    <b>The H Open:</b> "Security expert Andreas Bogk warns that, despite recent PHP improvements, the session IDs of users who are logged into PHP applications remain guessable. Upon close examination, the alleged improvements display frightening weaknesses."

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  • Utilisation du tampon de sortie en PHP, par Julien Pauli

    Lors du déclenchement d'un affichage en PHP (echo, var_dump(), printf() ou toute autre fonction), la chaine à afficher ne part pas directement vers l'affichage. Elle est en réalité stockée dans différentes piles appelées "tampons", sur lesquelles l'utilisateur a un contrôle plus ou moins fin. Lorsque le dernier tampon tout en bas est vidé, l'affichage est alors envoyé à un endroit, en fonction de la SAPI utilisée. Cet article détaillera les différentes couches de tampon, leur utilisation et leur impact sur le code PHP.

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  • Freelance Jobs in PHP

    PHP is the most popular, widely used server site scripting language that is used for web development. You can find a lot of freelance projects in PHP.

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  • Rewrite in Mediawiki, remove index.php, htaccess

    - by tran cuong
    I've just installed Mediawiki on Apache and I want the url should be localhost/Main_Page/ localhost/Special:Recent_Changes ... instead of localhost/index.php/Main_Page/ localhost/index.php/Special:Recent_Changes I've tried many times and in many ways but it still doesn't work. Any suggest for a "exactly" what to do, step by step. MediaWiki docs didn't talk about .htaccess. It had only nginx and lighttpd.

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  • jQuery not refreshing tabs content in IE

    - by iddimu
    Hi all! I have a page that is using jQuery tabs. Within one of my tabs I have a div that contains a form (initially hidden) that I want to use to add content to the tab. What I have works perfectly in Chrome, Firefox, and Safari. But, in IE 7 the tab will not refresh. The post works and the data gets added to the database, but it simply will not show the new content after submitting it. I don't think it matters - but, just for information I am using the Codeigniter PHP framework as well. Here is my javascript: <script type="text/javascript"> $(document).ready(function(){ // initialize the addChild form as hidden until user requests it open $('#addChild').hide(); // open the form $('#openDialog').click( function(){ $('#addChild').slideToggle(); return false; }); // close the form $('#closeDialog').click( function(){ $('#addChild').slideToggle(); return false; }); // submit the form $('#frmAddChild').submit( function(){ $('#addChild').slideToggle(); $.ajax({ url: '/children/add', type: 'POST', data: $('#frmAddChild').serialize() //cache: false }); //reload the children tab $('#tabs').tabs('load',3); return false; }); }); </script> And, here is my PHP/HTML: <?php // initialize the elements of the form $frmAddChild = array( 'name' => 'frmAddChild', 'id' => 'frmAddChild', 'method' => 'post' ); $child_name = array( 'name' => 'child_name', 'id' => 'child_name', ); $child_dob = array( 'name' => 'child_dob', 'id' => 'child_dob' ); $btnOpenDialog = array( 'name' => 'openDialog', 'id' => 'openDialog', 'value' => 'true', 'content' => 'Add Child' ); $btnCloseDialog = array( 'name' => 'closeDialog', 'id' => 'closeDialog', 'value' => 'true', 'content' => 'Cancel' ); // button that shows the drop down to add echo form_button($btnOpenDialog); ?> <div id="addChild" title="Add Child"> <?php echo form_open('children/add/',$frmAddChild); ?> <table> <tr> <td> <?php echo form_label('Child\'s Name', 'child_name'); ?>: </td> <td> <?php echo form_input($child_name); ?> </td> </tr> <tr> <td> <?php echo form_label('Date of Birth','child_dob'); ?>: </td> <td> <?php echo form_input($child_dob); ?> </td> </tr> <tr> <td colspan="2" align="right"> <?php echo form_submit('submit', 'Add'); ?> <?php echo form_button($btnCloseDialog); ?> </td> </tr> </table> <?php echo form_close(); ?> </div> Does anyone have any ideas how I can get this working correctly in IE? Also, if anyone has any comments about how I have things structured, please let me know. I'm new to Codeigniter and I am by no means a javascript or jQuery expert. Thanks for your help!

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