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  • How I can compile this C++ code that fails with "'::main' must return 'int'"? [migrated]

    - by krisu
    I have tried to find a solution that make batch file start flashing on taskbar and only good solution was this post on Stack Overflow. But I can't compile the code with WinGW or anything else to EXE, only getting this error: hello.cpp:6:32: error: '::main' must return 'int' Right now, I'm using TDM-GCC to compile code, because it's bit better... Can somebody give me code that actually works or even better compile it to EXE already? P.S. Even more better if somebody could compile this Delphi code, because I can't find any software that's free.

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  • Custom internal search engine [migrated]

    - by nobody
    I am building a social network, and I need a simple internal search engine that will display a list of all website users starting with the ones that have the specific keyword in their username. So here is what i need: a search engine that will take a keyword. the search engine will open a new page with a list of all website users, displaying first the users that have the specific keyword in their username. display your username in the placeholder. So, here is what I have so far: <div class="logobox r"> <form method="post" action="../sity/search.php"> <!--will redirect you to a new page with a list of all website users.--> <input type="text" class="logo" name="searchUser" placeholder="<?php echo $comObj->getSession('username')?>"> <!--will take a keyword as a imput, and will display your username in the placeholder--> <button type="submit" class="sity" value="sity">sity</button> </form> </div> And here is the searchUser function: function searchUser($keyword) { $commObj = new common; $sql = "SELECT `id`,`username`, `profile_pic` FROM ".$this->tables['user']." WHERE `username` LIKE '%".$keyword."%' AND `id` <> ".$commObj->getSession('userid'); $result = $this->selectAll($sql); unset($this->rsa); return $result; } The problem is that when you click on the search box, instead of letting you to enter a keyword, the page will logout you from the website. I still can't figure out why. Here is the link to the website: www.sity.net Any suggestion will be highly appreciated. Thanks

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  • Can't connect to Wireless

    - by SimplyRed37
    Good day all! I hope you are doing good. I have performed a WUBI installation of 12.04 on my HP G62 laptop, which has an Atheros AR9285 wireless chipset. Everything works fine with my wired network connection. However, wireless is unable to connect to my wifi network. I enter the WPA2 key and then it attemps to connect, but eventually comes back, asking for the WPA2 key again, as if it was not good. All of the other laptops in the household are able to connect, using the same key (I configured them all, so I am 500% sure of the WPA2 key). Any idea as to what could be causing this? I can definitely post the output of CLI commands like "rfkill list" or "sudo lshw -class network", or "ifconfig". I have installed Ubuntu a few time but I am definitely still a newbie, but I am definitely computer savyy. Looking forward to suggestions . Thanks in advance !!! Dan...

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  • Firefox Address Bar Search Returns Web Server Running?

    - by Stix
    When I type "trends" in Firefox 25.0 address bar, it returns what looks like a web server running on my PC, although I am not running a web server. I don't have the score to post the screen shot, but specifically it says: It works! This is the default web page for this server. The web server software is running but no content has been added, yet. Why would this display, instead of the normal behavior of the search engine? I'm using Windows 7 with the Anaconda Python distribution installed, but there is no Python interpreter fired up.

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  • Memory Speeds: 1x4GB or 2x2GB? [closed]

    - by Dasutin
    When it comes to speeds what is faster having one 4GB module in your system or having two 2GB modules. I'm not taking in the fact that the system could have dual channel capabilities. Also what about a server environment? Would it be better to have one large, high density module or break it up into several modules for speed and price? I heard an engineer at my office having a discussion with an employee. He said that its better in all situations to have one large capacity modules instead of breaking it up. It would be cheaper and perform faster. He also said it would take longer for the computer to access what it needed if there were more modules instead of having just one. His explanation didn't seem right to me and I thought I would post this question here to see what other people thought.

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  • NET USE LPT2: printer_port

    - by tpierzina
    This I understand: net use P: \\SOME_COMPUTER\SOME_SHARE net use P: \\1.2.3.4\SOME_SHARE (the second argument is a logical share on the given computer) This, I do NOT understand: net use LPT2: IP_1.2.3.4 (where IP_1.2.3.4 is the name of a "port" assigned to a printer; the IP is a valid and responding device, but the full string "IP_1.2.3.4" is not) Can anyone tell me, is there ever a syntax of NET USE that could operate on a printer port like that? I can't get it to work, can't find anything via Google, and am practically in tears. [Sorry if this is cheating, this is basically a re-post of http://stackoverflow.com/questions/1884235/old-school-windows-2000-printing-or-when-is-a-port-name-a-computer but with the scope narrowed just to the main issue at hand.

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  • How do I sell Oracle? It all starts with the database

    - by swiesner
    Partner sales reps often ask me how they start a conversation with their customers around Oracle. The first question should be, "are you running an Oracle database?" Much of what we do at Oracle is intended to optimize our customers' investments in the Oracle database. Many of our acquisitions, new features in existing products, new applications, are often designed to improve the experience of the 400,000 Oracle database customers worldwide. Once you find an Oracle database customer, the next set of questions are much easier, but depend on your expertise: License Management, Upsell, and Services. Let's start with License Management: Have there been any changes to your infrastructure since you purchased the database licenses? Have you upgraded the servers on which the Oracle database is running? Have the number of users or employees increased since the last license purchase? Yes to any of these questions will lead to investigating correct licensing. The goal is to provide a "soft" license review. Oracle generally does not require any license keys to install our software, so we need to help our customers with compliance. Correct licensing is essential to managing costs, and can provide a great way to efficiently manage IT spend. You might want to contact your local Oracle Channel Manager or VAD for licensing assistance. Or, review the Software Investment Guide. Naturally, these questions can lead to upsell opportunities. If your customer has invested in Oracle technology to manage their data, that data is essential to running their business. We'll take a look at those upsell questions in a later blog post.

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  • In Ubuntu, my apps no longer have the system menu bar (not the panels!)

    - by user25522
    So, I booted up my box today after the weekend, and my apps no longer have the System Menu Bar at the top. It kinda sucks 'cause that's an easy way to maximize windows. How do I get it back? And I'm not talking about the panels at the top/bottom of the screen. This is what my terminal looks like. It's really missing the bar at the top. I have no rep so can't post pics, but here's a link to the image

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  • How to Edit or Add a New Row in jqGrid

    - by Paul
    My jqGrid that does a great job of pulling data from my database, but I'm having trouble understanding how the Add New Row functionality works. Right now, I'm able to edit inline data, but I'm not able to create a new row using the Modal Box. I'm missing that extra logic that says, "If this is a new row, post this to the server side URL" instead of modifying existing data. (Right now, hitting Submit only clears the form and reloads the grid data.) The documentation states that Add New Row is: jQuery("#editgrid").jqGrid('editGridRow',"new",{height:280,reloadAfterSubmit:false}); but I'm not sure how to use that correctly. I've spent alot of time studying the Demos, but they seem to all use an external button to fire the new row command, rather than using the Modal Form, which I want to do. My complete code is here: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>jqGrid</title> <link rel="stylesheet" type="text/css" media="screen" href="../css/ui-lightness/jquery-ui-1.7.2.custom.css" /> <link rel="stylesheet" type="text/css" media="screen" href="../css/ui.jqgrid.css" /> <script src="jquery-1.3.2.min.js" type="text/javascript"></script> <script src="../js/i18n/grid.locale-en.js" type="text/javascript"></script> <script src="jquery.jqGrid.min.js" type="text/javascript"></script> </head> <body> <h2>My Grid Data</h2> <table id="list" class="scroll"></table> <div id="pager" class="scroll c1"></div> <script type="text/javascript"> var lastSelectedId; jQuery('#list').jqGrid({ url:'grid.php', datatype: 'json', mtype: 'POST', colNames:['ID','Name', 'Price', 'Promotion'], colModel:[ {name:'product_id',index:'product_id', width:25,editable:false}, {name:'name',index:'name', width:50,editable:true, edittype:'text',editoptions:{size:30,maxlength:50}}, {name:'price',index:'price', width:50, align:'right',formatter:'currency', editable:true}, {name:'on_promotion',index:'on_promotion', width:50, formatter:'checkbox',editable:true, edittype:'checkbox'}], rowNum:10, rowList:[5,10,20,30], pager: $('#pager'), sortname: 'product_id', viewrecords: true, sortorder: "desc", caption:"Database", width:500, height:150, onSelectRow: function(id){ if(id && id!==lastSelectedId){ $('#list').restoreRow(lastSelectedId); $('#list').editRow(id,true,null,onSaveSuccess); lastSelectedId=id; }}, editurl:'grid.php?action=save'}) .jqGrid('navGrid','#pager', {refreshicon: 'ui-icon-refresh',view:true}, {height:280,reloadAfterSubmit:true}, {height:280,reloadAfterSubmit:true}, {reloadAfterSubmit:true}) .jqGrid('editGridRow',"new",{height:280,reloadAfterSubmit:false}); function onSaveSuccess(xhr) {response = xhr.responseText; if(response == 1) return true; return false;} </script></body></html> If it makes it easier, I'd be willing to scrap the inline editing functionality and do editing and posting via modal boxes. Any help would be greatly appreciated.

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  • WPF TabControl - how to preserve control state within tab items (MVVM pattern)

    - by Tim Coulter
    I am a newcomer to WPF, attempting to build a project that follows the recommendations of Josh Smith's excellent article describing The Model-View-ViewModel Design Pattern. Using Josh's sample code as a base, I have created a simple application that contains a number of "workspaces", each represented by a tab in a TabControl. In my application, a workspace is a document editor that allows a hierarchical document to be manipulated via a TreeView control. Although I have succeeded in opening multiple workspaces and viewing their document content in the bound TreeView control, I find that the TreeView "forgets" its state when switching between tabs. For example, if the TreeView in Tab1 is partially expanded, it will be shown as fully collapsed after switching to Tab2 and returning to Tab1. This behaviour appears to apply to all aspects of control state for all controls. After some experimentation, I have realized that I can preserve state within a TabItem by explicitly binding each control state property to a dedicated property on the underlying ViewModel. However, this seems like a lot of additional work, when I simply want all my controls to remember their state when switching between workspaces. I assume I am missing something simple, but I am not sure where to look for the answer. Any guidance would be much appreciated. Thanks, Tim Update: As requested, I will attempt to post some code that demonstrates this problem. However, since the data that underlies the TreeView is complex, I will post a simplified example that exhibits the same symtoms. Here is the XAML from the main window: <TabControl IsSynchronizedWithCurrentItem="True" ItemsSource="{Binding Path=Docs}"> <TabControl.ItemTemplate> <DataTemplate> <ContentPresenter Content="{Binding Path=Name}" /> </DataTemplate> </TabControl.ItemTemplate> <TabControl.ContentTemplate> <DataTemplate> <view:DocumentView /> </DataTemplate> </TabControl.ContentTemplate> </TabControl> The above XAML correctly binds to an ObservableCollection of DocumentViewModel, whereby each member is presented via a DocumentView. For the simplicity of this example, I have removed the TreeView (mentioned above) from the DocumentView and replaced it with a TabControl containing 3 fixed tabs: <TabControl> <TabItem Header="A" /> <TabItem Header="B" /> <TabItem Header="C" /> </TabControl> In this scenario, there is no binding between the DocumentView and the DocumentViewModel. When the code is run, the inner TabControl is unable to remember its selection when the outer TabControl is switched. However, if I explicitly bind the inner TabControl's SelectedIndex property ... <TabControl SelectedIndex="{Binding Path=SelectedDocumentIndex}"> <TabItem Header="A" /> <TabItem Header="B" /> <TabItem Header="C" /> </TabControl> ... to a corresponding dummy property on the DocumentViewModel ... public int SelecteDocumentIndex { get; set; } ... the inner tab is able to remember its selection. I understand that I can effectively solve my problem by applying this technique to every visual property of every control, but I am hoping there is a more elegant solution.

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  • SSRS ReportViewer 2010 Iframe IE Problem

    - by Phil
    Hello all, My problem relates to trying to include an SSRS (SQL Server) Report inside my MVC application. I've settled on the hybrid solution of having a WebForm with the ReportViewer Control in and then on my MVC View pages having an iframe reference this WebForm page. The tricky part is that the iframe needs to be dynamically populated with the report rather than using src due to posting parameters to the WebForm. It works perfectly in Firefox and Chrome, however IE throws a "Sys is Undefined" javascript error. Using src on the iframe works in IE, but I can't find a way to post parameters (don't want to use something like /Report.aspx?param1=test due to the possible length). Its a ASP.NET MVC 2 project, .NET 4, Visual Studio 2010 on Windows 7 x74 if its any help. So here is the code (I could provide the VS2010 project files if anyone wants them) In my webform: <%@ Page Language="C#" AutoEventWireup="true" CodeBehind="Report.aspx.cs" Inherits="SSRSMVC.Views.Home.Report" %> <%@ Register Assembly="Microsoft.ReportViewer.WebForms, Version=10.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" Namespace="Microsoft.Reporting.WebForms" TagPrefix="rsweb" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <body> <form id="RSForm" runat="server"> <asp:ScriptManager ID="ScriptManager" runat="server" EnablePartialRendering="true" ScriptMode="Release"> </asp:ScriptManager> <asp:UpdatePanel ID="ReportViewerUP" runat="server"> <ContentTemplate> <rsweb:ReportViewer ID="ReportViewer" runat="server" Width="100%" Height="380px" ProcessingMode="Local" InteractivityPostBackMode="AlwaysAsynchronous" AsyncRendering="true"> <LocalReport ReportPath="Models\\TestReport.rdlc"> </LocalReport> </rsweb:ReportViewer> </ContentTemplate> </asp:UpdatePanel> </form> </body> </html> And Codebehind: using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using Microsoft.Reporting.WebForms; namespace SSRSMVC.Views.Home { public partial class Report : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) { string test = Request.Params["val1"]; ReportViewer.LocalReport.DataSources.Add(new ReportDataSource("DataSet1", new SSRSMVC.Models.DataProvider().GetData())); } } } } And lastly my View page, <script type="text/javascript"> $(window).load(function () { $.post('/Report.aspx', { val1: "Hello World" }, function (data) { var rv_frame = document.getElementById('Frame1'); rv_frame = (rv_frame.contentWindow) ? rv_frame.contentWindow : (rv_frame.contentDocument.document) ? rv_frame.contentDocument.document : rv_frame.contentDocument; rv_frame.document.open(); rv_frame.document.write(data); rv_frame.document.close(); }); }); </script>

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  • Help With Database Layout

    - by three3
    Hello everyone, I am working on a site similar to Craigslist where users can make postings and sell items in different cities. One difference between my site and Craigslist will be you will be able to search by zip code instead of having all of the cities listed on the page. I already have the ZIP Code database that has all of the city, state, latitude, longitude, and zip code info for each city. Okay, so to dive into what I need done and what I need help with: 1.) Although I have the ZIP Code database, it is not setup perfectly for my use. (I downloaded it off of the internet for free from http://zips.sourceforge.net/) 2.) I need help setting up my database structure (Ex: How many different tables should I use and how should I link them) I will be using PHP and MySQL. These our my thoughts so far on how the database can be setup: (I am not sure if this will work though.) Scenario: Someone goes to the homepage and it will tell them, "Please enter your ZIP Code.". If they enter "17241" for example, this ZIP Code is for a city named Newville located in Pennsylvania. The query would look like this with the current database setup: SELECT city FROM zip_codes WHERE zip = 17241; The result of the query would be "Newville". The problem I see here now is when they want to post something in the Newville section of the site, I will have to have an entire table setup just for the Newville city postings. There are over 42,000 cities which means I would have to have over 42,000 tables (one for each city) so that would be insane to have to do it that way. One way I was thinking of doing it was to add a column to the ZIP Code database called "city_id" which would be a unique number assigned to each city. So for example, the city Newville would have a city_id of 83. So now if someone comes and post a listing in the city Newville I would only need one other table. That one other table would be setup like this: CREATE TABLE postings ( posting_id INT NOT NULL AUTO_INCREMENT, for_sale LONGTEXT NULL, for_sale_date DATETIME NULL, for_sale_city_id INT NULL, jobs LONGTEXT NULL, jobs_date DATETIME NULL, jobs_city_id INT NULL, PRIMARY KEY(posting_id) ); (The for_sale and job_ column names are categories of the types of postings users will be able to list under. There will be many more categories than just those two but this is just for example.) So now when when someone comes to the website and they are looking for something to buy and not sell, they can enter their ZIP Code, 17241, for example, and this is the query that will run: SELECT city, city_id FROM zip_codes WHERE zip = 17241; //Result: Newville 83 (Please note that I will be using PHP to store the ZIP Code the user enters in SESSIONS and Cookies to remember them throughout the site) Now it will tell them, "Please choose your category.". If they choose the category "Items For Sale" then this is the query to run and sort the results: SELECT posting_id, for_sale, for_sale_date FROM postings WHERE for_sale_city_id = $_SESSION['zip_code']; Will this work? So now my question to everyone is will this work? I am pretty sure it will but I do not want to set this thing up and realize I overlooked something and have to start from all over from scratch. Any opinions and ideas are welcomed and I will listen to anyone who has some thoughts. I really appreciate the help in advance :D

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  • Small performance test on a web service

    - by vtortola
    Hi, I'm trying to develop a small application that test how many requests per second can my service support but I think I'm doing something wrong. The service is in an early development stage, but I'd like to have this test handy in order to check in time to time I'm not doing something that decrease the performance. The problem is that I cannot get the web server or the database server go to the 100% of CPU. I'm using three different computers, in one is the web server (WinSrv Standard 2008 x64 IIS7), in other the database (Win 2K - SQL Server 2005) and the last is my computer (Win7 x64 ultimate), where I'll run the test. The computers are connected through a 100 ethernet switch. The request POST is 9 bytes and the response will be 842 bytes. The test launches several threads, and each thread has a "while" loop, in each loop it creates a WebRequest object, performs a call, increment a common counter and waits between 1 and 5 millisencods, then it do it again: static Int32 counter = 0; static void Main(string[] args) { ServicePointManager.DefaultConnectionLimit = 250; Console.WriteLine("Ready. Press any key..."); Console.ReadKey(); Console.WriteLine("Running..."); String localhost = "localhost"; String linuxmono = "192.168.1.74"; String server= "192.168.1.5:8080"; DateTime start = DateTime.Now; Random r = new Random(DateTime.Now.Millisecond); for (int i = 0; i < 50; i++) { new Thread(new ParameterizedThreadStart(Test)).Start(server); Thread.Sleep(r.Next(1, 3)); } Thread.Sleep(2000); while (true) { Console.WriteLine("Request per second :" + counter/DateTime.Now.Subtract(start).TotalSeconds ); Thread.Sleep(3000); } } public static void Test(Object ip) { Guid guid = Guid.NewGuid(); Random r = new Random(DateTime.Now.Millisecond); while (true) { String test = "<lalala/>"; WebRequest req = WebRequest.Create("http://" + (String)ip + "/WebApp/"+guid.ToString()+"/Data/Tables=whatever"); req.Method = "POST"; req.ContentType = "application/xml"; req.Credentials = new NetworkCredential("aaa", "aaa","domain"); Byte[] array = Encoding.UTF8.GetBytes(test); req.ContentLength = array.Length; using (Stream reqStream = req.GetRequestStream()) { reqStream.Write(array, 0, array.Length); reqStream.Close(); } using (Stream responseStream = req.GetResponse().GetResponseStream()) { String response = new StreamReader(responseStream).ReadToEnd(); if (response.Length != 842) Console.Write(" EEEE "); } Interlocked.Increment(ref counter); Thread.Sleep(r.Next(1,5)); } } If I run the test neither of the computers do an excesive CPU usage. Let's say I get a X requests per second, if I run the console application two times at the same moment, I get X/2 request per second in each one... but still the web server is on 30% of CPU, the database server on 25%... I've tried to remove the thread.sleep in the loop, but it doesn't make a big difference. I'd like to put the machines to the maximun, to check how may requests per second they can provide. I guessed that I could do it in this way... but apparently I'm missing something here... What is the problem? Kind regards.

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  • KSoap2 Android not valid SOAP

    - by Rogier21
    Hello all, I am trying to post to my own test soap server (C#) with Android in combination with KSOAP2. Now I have the specifications from the SOAP server, it expects: POST /SharingpointCheckBarcode.asmx HTTP/1.1 Host: awc.test.trin-it.nl Content-Type: text/xml; charset=utf-8 Content-Length: length SOAPAction: "http://tempuri.org/checkBarcode" <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Header> <AuthHeader xmlns="http://tempuri.org/"> <username>string</username> <password>string</password> </AuthHeader> </soap:Header> <soap:Body> <checkBarcode xmlns="http://tempuri.org/"> <barcode>string</barcode> </checkBarcode> </soap:Body> </soap:Envelope> But what Android KSOAP2 sends out: <?xml version="1.0" encoding="utf-8"?> <v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/"> <v:Header /> <v:Body> <checkBarcode xmlns="http://tempuri.org" id="o0" c:root="1"> <username i:type="d:string">test</username> <password i:type="d:string">test</password> <barcode i:type="d:string">2620813000301</barcode> </checkBarcode> </v:Body> </v:Envelope> With this code: try { SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); request.addProperty("username", "test"); request.addProperty("password", "test"); request.addProperty("barcode", "2620813000301"); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet = true; envelope.encodingStyle = "test"; envelope.setOutputSoapObject(request); AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport (URL); androidHttpTransport.debug = true; androidHttpTransport.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"utf-8\"?>"); androidHttpTransport.call(SOAP_ACTION, envelope); Log.d("MyAPP", "----------------- " + androidHttpTransport.requestDump +"\r\n\r\n" + androidHttpTransport.responseDump); ((TextView)findViewById(R.id.lblStatus)).setText(androidHttpTransport.requestDump +"\r\n\r\n" + androidHttpTransport.responseDump); } catch(Exception E) { ((TextView)findViewById(R.id.lblStatus)).setText("ERROR:" + E.getClass().getName() + ": " + E.getMessage()); } The response I get back from the server is that there are no results found, so not an error, but when I test it with another App or PHP, it with the same data, it says it's OK. I think it's because of the

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  • AuthSub token from Google/YouTube API is always returned as invalid

    - by Miriam Raphael Roberts
    Anyone out there have experience with the YouTube/Google API? I am trying to login to Google/Youtube using clientLogin, retrieve an AuthSub token, exchange it for a multi-session token and then use it in our upload form. Just a note that we are not going to have other users logging into our (secure) website, this is for our use only (no multi-users). We just want a way to upload videos to our YT account via our own website without having to login/upload to YouTube. Ultimately, everything is dependent on the first step. My AuthSub token is always being returned as invalid (Error '403'). All the steps I used are below with username/password changed. Anyone have an insight on why my AuthSub is always invalid? I am spending an enormous amount of time trying to get this to work. STEP 1: Getting the authsub token from Youtube/Google POST /youtube/accounts/ClientLogin HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Content-Length: 86 Email=MyGoogleUsername&Passwd=MyGooglePasswd&accountType=GOOGLE&service=youtube&source=Test RESPONSE RECEIVED: Auth=AIwbFAR99f3iACfkT-5PXCB-1tN4vlyP_1CiNZ8JOn6P-......yv4d4zeGRemNm4il1e-M6czgfDXAR0w9fQ YouTubeUser=MyYouTubeUsername CURL COMMAND USED: /usr/bin/curl -S -v --location https://www.google.com/youtube/accounts/ClientLogin --data Email=MyGoogleUsername&Passwd=MyGooglePasswd&accountType=GOOGLE&service=youtube&source=Test --header Content-Type:application/x-www-form-urlencoded STEP 2: Exchanging the AuthSub token for a multi-use token GET /accounts/AuthSubSessionToken HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Authorization: AuthSub token="AIwbFASiRR3XDKs......p5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" Response received: 403 Invalid AuthSub token. curl command used: /usr/bin/curl -S -v --location https://www.google.com/accounts/AuthSubSessionToken --header Content-Type:application/x-www-form-urlencoded -H Authorization: AuthSub token="AIwbFAQR_4xG2g.....vp3BQZW5XEMyIj_wFozHSTEQ-BQRfYuIY-1CyqLeQ" STEP 3: Checking to see if the token is good/valid GET /accounts/AuthSubTokenInfo HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Authorization: AuthSub token="AIwbFASiRR3XDKsNkaIoPaujN5RQhKs3u.....A_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" Received response: 403 Invalid AuthSub token. curl command used: /usr/bin/curl -S -v --location https://www.google.com/accounts/AuthSubTokenInfo --header Content-Type:application/x-www-form-urlencoded -H Authorization: AuthSub token="AIwbFAQR_4xG2gHoAKDsNdFqdZdwWjGeNquOLpvp3BQZW5XEMyIj_wFozHSTEQ-BQRfYuIY-1CyqLeQ" STEP 4: Trying to get the upload token using the authsub token POST /action/GetUploadToken HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: gdata.youtube.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/atom+xml Authorization: AuthSub token="AIwbFASiRR3XDKsNkaIoPaujN5RQhp5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" X-Gdata-Key:key="AI39si5EQyo-TZPFAnmGjxJGFKpxd_7a6hEERh_3......R82AShoQ" Content-Length:0 GData-Version:2 Recevied Response: 401 Token invalid - Invalid AuthSub token. Curl command used: /usr/bin/curl -S -v --location http://gdata.youtube.com/action/GetUploadToken -H Content-Type:application/atom+xml -H Authorization: AuthSub token="AIwbFASiRR3XDKs....sYDp5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" -H X-Gdata-Key:key="AI39si5EQyo-TZPFAnmGjxJGF......Kpxd6dN2J1oHFQYTj_7a6hEERh_3E48R82AShoQ" -H Content-Length:0 -H GData-Version:2

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  • ASP.NET MVC jquery.UI dialog - How to validate the dialog's input on server and return error?

    - by Rick
    I am using jQuery1.4.2, ASP.NET MVC 2 and jQuery.UI-1.8. I am creating a data input dialog which works OK when all the data is valid, but I want to validate the input data on the server and return an error to the dialog describing the error and I am not quite sure how to do that and keep the dialog open. The dialog is opened when a link is clicked. The solution may be to try to bypass more of the MVC framework's default binding that handles the submit button clicks and creates the expected ProfilePermission object and calls the Controller's AddPermission POST Action method, but I was hoping there may be an easier way without have to write more jquery/javascript code to handle the button clicks and pass the data to the server. My script code looks like $("#dialog").dialog({ modal: true, position: ['center', 180], width: 500, height: 130, autoOpen: false }); $(".addPermissionDialog").click(function (event) { event.preventDefault(); $("#dialog").dialog('open'); return false; }); My View <div id="dialog" title="Add Permission"> <%: Html.ValidationSummary("") %> <% using (Html.BeginForm("AddPermission", "Profile")) { %> <%: Html.Hidden("PersonId") %> <%: Html.Hidden("ProfileId") %> <div class="editor-label"> <label for="PersonName">User Name:</label> <%: Html.TextBox("PersonName")%> <label for="PermissionType">Permission:</label> <select name="PermissionTypeId" id="PermissionTypeId" > <option value="2">Edit</option> <option value="3">View</option> </select> </div> <br /> <p> <input type="submit" name="saveButton" value="Add Permission" /> <input type="submit" id="cancelButton" name="cancelButton" value="Cancel" /> <script type="text/javascript"> document.getElementById("cancelButton").disableValidation = true; </script> </p> <% } %> </div> <br /> <p> <%: Html.ActionLink("Add Permission", "AddPermission", new { profileId = Model.First().ProfileId }, new { @class = "addPermissionDialog" })%> </p> My Controller action [AcceptVerbs("Post")] [HandleError] public ActionResult AddPermission(string cancelButton, ProfilePermission profilePermission) { ViewData["Controller"] = controllerName; ViewData["CurrentCategory"] = "AddPermission"; ViewData["ProfileId"] = profilePermission.ProfileId; PermissionTypes permission = repository.GetAccessRights(profilePermission.ProfileId); if (permission == PermissionTypes.View || permission == PermissionTypes.None) { ViewData["Message"] = "You do not have access rights (Edit or Owner permissions) to this profile"; return View("Error"); } // If cancel return to previous page if (cancelButton != null) { return RedirectToAction("ManagePermissions", new { profileId = profilePermission.ProfileId }); } if (ModelState.IsValid) { repository.SavePermission(profilePermission); return RedirectToAction("ManagePermissions", new { profileId = profilePermission.ProfileId }); } // IF YOU GET HERE THERE WAS AN ERROR return PartialView(profilePermission); // The desire is to redisplay the dialog with error message }

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  • Uploading images from Flex to Rails using Paperclip

    - by 23tux
    Hi everyone, I'm looking for a way to upload images that were created in my flex app to rails. I've tried to use paperclip, but it don't seem to work. I've got this tutorial here: http://blog.alexonrails.net/?p=218 The problem is, that they are using a FileReference to browse for files on the clients computer. They call the .upload(...) function and send the data to the upload controller. But I'm using a URLLoader to upload a image, that is modified in my Flex-App. First, here is the code from the tutorial: private function selectHandler(event:Event):void { var vars:URLVariables = new URLVariables(); var request:URLRequest = new URLRequest(uri); request.method = URLRequestMethod.POST; vars.description = "My Description"; request.data = vars; var uploadDataFieldName:String = 'filemanager[file]'; fileReference.upload(request, uploadDataFieldName); } I don't know how to set that var uploadDataFieldName:String = 'filemanager[file]'; in a URLLoader. I've got the image data compressed as a JPEG in a ByteArray. It looks like this: public function savePicture():void { var filename:String = "blubblub.jpg"; var vars:URLVariables = new URLVariables(); vars.position = layoutView.currentPicPosition; vars.url = filename; vars.user_id = 1; vars.comic_id = 1; vars.file_content_type = "image/jpeg"; vars.file_file_name = filename; var rawBytes:ByteArray = new JPGEncoder(75).encode(bitmapdata); vars.picture = rawBytes; var request:URLRequest = new URLRequest(Data.SERVER_ADDR + "pictures/upload"); request.method = URLRequestMethod.POST; request.data = vars; var loader:URLLoader = new URLLoader(request); loader.addEventListener(Event.COMPLETE, savePictureHandler); loader.addEventListener(IOErrorEvent.IO_ERROR, errorHandlerUpload); loader.load(request); } If I set the var.picture URLVariable to the bytearray, then I get the error, that the upload is nil. Here is the Rails part: Picture-Model: require 'paperclip' class Picture < ActiveRecord::Base # relations from picture belongs_to :comic belongs_to :user has_many :picture_bubbles has_many :bubbles, :through => :picture_bubbles # attached file for picture upload -> with paperclip plugin has_attached_file :file, :path => "public/system/pictures/:basename.:extension" end and the picture controller with the upload function: class PicturesController < ApplicationController protect_from_forgery :except => :upload def upload @picture = Picture.new(params[:picture]) @picture.position = params[:position] @picture.comic_id = params[:comic_id] @picture.url = params[:url] @picture.user_id = params[:user_id] if @picture.save render(:nothing => true, :status => 200) else render(:nothing => true, :status => 500) end end end Does anyone know how to solve this problem? thx, tux

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  • ASP.NET MVC : AJAX ActionLink - Persist Data

    - by Mio
    Hi guys, I'm really new at this and I was searching the web for an answer to my question and I couldn't find it, so here I am posting my question :) I'm trying to create a new record in my table Facility. For my goreign keys I'm displaying the choices in tables instead of a dropdowns. When the user clicks on the select link which is an Ajax.ActionLink(), I wanna retrieve the right record from the DB and set the foreign key of my object Facility to the one slected and replace the Div by a new Partial View. The problem is when I try to submit the form, the Facility object doesnt seem to have the foreign key that I've just set in my ajax fuction in my controller. And if the user has enter some data in the other fields of the create form, I don't them to lose what they already entered. Here's my code. Model only contains a Facility. public ActionResult Create() { Model.Facility = new Facility(); return View(Model); } This is part of my Create View <div id="FacilityTypePartialView"> <% Html.RenderPartial("FacilityType"); %> </div> This is my Partial View FacilityType <% if (Model.IsNewFacility()) { %> <p> Id: <%= Html.Encode(Model.Facility.FacilityType.FId)%> </p> <p> Type: <%= Html.Encode(Model.Facility.FacilityType.FType)%> </p> <p> Description: <%= Html.Encode(Model.Facility.FacilityType.FDescription) %> </p> <% } %> <p> <%= Html.ActionLink("Manage Facility Type", "Index","FacilityType") %> </p> <table id="FacilityTypesList"> <tr> <th> Select </th> <th> FId </th> <th> FType </th> <th> FDescription </th> </tr> <% foreach (var item in Model.GetFacilityTypes()) { %> <tr> <td> <%=Ajax.ActionLink("Select", "FacilityTypeSelect", new { id = item.FId}, new AjaxOptions { UpdateTargetId = "FacilityTypePartialView" })%> </td> <td> <%= Html.Encode(item.FId) %> </td> <td> <%= Html.Encode(item.FType) %> </td> <td> <%= Html.Encode(item.FDescription) %> </td> </tr> <% } %> </table> Here's y Ajax Funcion public PartialViewResult FacilityTypeSelect(int id) { Facility facility = new Facility(); facility.FacilityType = _repository.GetFacilityType(id); Model.Facility = facility; if (this.Request.IsAjaxRequest() == false) { return PartialView("FacilityType/FacilityType", Model); } else { return PartialView("FacilityType/FacilityTypeSelected", Model); } } Finally, my Post method [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create( Facility facility) { Model.Facility = facility; if (ModelState.IsValid) { try { _repository.AddEntity(facility); _repository.Save(); return RedirectToAction("Details", new { id = facility.Id }); } catch { } } return View("Create", Model); } My Faciliy object coming from the View have the Facility.FacilityType set to nothing.

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  • facebook iframe stream.Publish cannot close dialog or skip

    - by fooyee
    am pulling my hair over this :( spent 10 hrs but nothing came out I read this thread http://forum.developers.facebook.com/viewtopic.php?pid=198128 but it didn't help much. I'm running a local dev App Engine server ( localhost:8080 ) iframe app so I have a couple of problems. 1) on safari 4.0.4, the publish story dialog comes up nicely with all images/data/action_links. upon posting a story (or skipping), the dialog goes blank and wouldn't close. 2) I tested the same code on firefox 3.5.8, the dialog comes up with all images/data/action_links, but then the whole thing freezes. Clicking anywhere on the dialog doesn't help at all. If i'm patient enough and click "publish", I have to wait for abt 10 seconds before the dialog says "story is published". then it freezes. (clicking on skip doesn't make a difference). btw, there is no "button clicking effect" : ie: the buttons don't look like they "sink down" upon clicking. I checked the firefox memory using the command "top" on the terminal, it all seems okay, no spike in CPU processes ( i could open other firefox tabs and work on them) My futile attempts at solving the problems... 1) so i thought, hmm could this be because of local dev (localhost) problem? I uploaded the code to the production server, the same thing happens. 2) I tried an older firefox (3.1) and the same problem persisted ( the freezing ) 3) I noticed that i kind of used 2 different FB features ( Connect and XFBML). The Connect Feature I used in the PostStory function. The XFBML feature I used before the tag. So I thought, hmm ... I tried replacing the FB_RequireFeatures["Connect"] feature with FB_RequireFeatures["XFBML"]. nothing changed. I still can't close the story dialog. 4) Is there a possibility that I didn't connect to xd_receiver.htm properly? my xd_receiver.htm is stored in my folder /media/fbconnect in my app.yaml handler: - url: /fbconnect static_dir: media/fbconnect so i thought a connection has to be established with xd_receiver.htm. any way I can test that? here're all the codes: <script type="text/javascript"> //post story function function PostStory() { //init facebook FB_RequireFeatures(["Connect"], function() { FB.Facebook.init('my_app_key', "/fbconnect/xd_receiver.htm"); FB.ensureInit(function() { var message = 'the message'; var attachment = { 'name': 'a simple app to send gifts', 'href': 'http://apps.facebook.com/my_app_name', 'caption': '{*actor*} sent u something', 'description': 'some description', "media": [{ "type": "image", "src": "http://bit.ly/105QYr", "href": "http://bit.ly/105QYr"}] }; //action links can only be seen AFTER the feed is published var action_links = [{ 'text': 'Send him/her a gift back!', 'href': 'http://somelink.com'}]; FB.Connect.streamPublish(message, attachment, action_links, null, "Share the gift with your friends", callback, false, null); }); }); function callback(post_id, exception) { //alert('Wall Post Complete'); } } </script> just before the end of the /body tag, i have this: <script type="text/javascript"> function callFBInit() { FB_RequireFeatures( ["XFBML"], function(){ FB.Facebook.init("my_app_key", "/fbconnect/xd_receiver.htm"); } ); } callFBInit(); btw, my xd_receiver.htm contains: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns=? http://www.w3.org/1999/xhtml? > <head> <title>cross-domain receiver page</title> </head> <body> <script src=?http://static.ak.facebook.com/js/api_lib/v0.4/xdcommreceiver.debug.js? type=? text/javascript? ></script> </body> </html> hope you guys can help out. thx

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  • How to prevent jQuery FancyBox from closing immediately after submit?

    - by Dimitri
    Hi! I'm loading an inline registration form in a FancyBox from jQuery. However after submitting the form, the box immediately closes while there is some feedback that I want to show the user in the FancyBox itself. This feedback is generated on the server side and is printed in the FancyBox. How can I make the box only closing when their is no feedback anymore? I was thinking about using ajax to just refresh the FancyBox itself and not the whole page after refreshing. But I just can't figure out how this ajax $.ajax({type, cache, url, data, success}); works... Also it seems like there's no reaction from the 'submit bind' in the javascript. I hope someone can help me with this problem. I paste my code below. If any questions, plz ask.. Thx in advance! This is the javascript: <script type="text/javascript"> $(document).ready(function() { $("#various1").fancybox({ 'transitionIn' : 'none', 'transitionOut' : 'none', 'scrolling' : 'no', 'titleShow' : false, 'onClosed' : function() { $("#registration_error").hide(); } }); }); $("#registration_form").bind("submit", function() { if ($("#registration_error").val() != "Registration succeeded!") { $("#registration_error").show(); $.fancybox.resize(); return false; } $.fancybox.showActivity(); $.ajax({ type : "POST", cache : false, url : "/data/login.php", data : $(this).serializeArray(), success : function(data) { $.fancybox(data); } }); return false; }); This is the inline form that I show in the FancyBox: <div style="display: none;"> <div id="registration" style="width:227px;height:250px;overflow:auto;padding:7px;"> <?php echo "<p id=\"registration_error\">".$feed."</p>"; ?> <form id="registration_form" action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post"> <p> <label for="username">Username: </label> <input type="text" id="login_name" name="username" size="30" /> </p> <p> <label for="password">Password: </label> <input type="password" id="pass" name="pw" size="30" /> </p> <p> <label for="repeat_password">Repeat password: </label> <input type="password" id="rep_pass" name="rep_pw" size="30" /> </p> <p> <input type="submit" value="Register" name="register" id="reg" /> </p> <p> <em></em> </p> </form> </div> </div>

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  • NLP with greatly contrained input and abilities

    - by Mike F
    Hat in hand here. I'm a seasoned developer and I would be grateful for a bit of help. I don't have time to read or digest long intricate discussions on theoretical concepts around NLP (or go get my PHD). That said, I have read a few and it's a damn interesting field. The problem is I need real world solutions, for real world products, in real world time frames. The problem I'm having is right now I'm not sure what the right questions are to ask to get started implementing. I believe this is mostly related to vocabulary. I'll read somewhere, a blog post, a forum post, a whitepaper, and it says, I'm doing flooping with the blargy blarg method, and I go google flooping and blargy blarg, and I get references to more obscurity. It seemingly never ends. So, my question is multiphased. First, more generally, how do I become passingly educated on this quickly? Just in time educated. I only need to know what I need to know to take the next step. I've spent 20 years writing code. Explain quick. I'll get it. (I mean provide a reference to something that explains quickly of course). I'm happy to read the right book, but I don't want to read a book where I read the chapter introduction that explains what floopy floop is and then skip over the rest of the chapter with examples of floopy flooping (because now I get what it is). I also don't want to read a book that goes into too much detail with theoretical underpinnings or history. For example, the Jurafsky book seems like way more than I need: http://www.amazon.com/gp/product/0131873210. But I will read it if this is the right book to read. (It's also dang expensive!) I need the root node of the expedited learning tree here, if you will. Point me in the right direction and I'll be quite grateful. I'm expecting quite a lot of firehose drinking - I just need the right firehose. Second, what I need to do is take a single sentence, with a very reduced vocabulary, and get a grammar tree (sorry if this is the wrong terminology) that I can do something with. I know I could easily write this command line input style in c in a more conventional manner, but I need it to be way better than that. But I don't need a chatterbot either. What I'm doing needs to live in a constrained environment. I can't use Python (unfortunately). I can't ship with gigabytes of corpuses. I need any libraries I use to be in c/c++. If I have to write this myself, I will. Hopefully, it will be achievable considering the reduced problem set. Maybe, probably, that's just naive. If so, let me know. :-) Thanks in advance - Mike

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  • MVC 2 Ajax.Beginform passes returned Html to javascript function

    - by Joe
    Hi, I have a small partial Create Person form in a page above a table of results. I want to be able to post the form to the server, which I can do no problem with ajax.Beginform. <% using (Ajax.BeginForm("Create", new AjaxOptions { OnComplete = "ProcessResponse" })) {%> <fieldset> <legend>Fields</legend> <div class="editor-label"> <%=Html.LabelFor(model => model.FirstName)%> </div> <div class="editor-field"> <%=Html.TextBoxFor(model => model.FirstName)%> <%=Html.ValidationMessageFor(model => model.FirstName)%> </div> <div class="editor-label"> <%=Html.LabelFor(model => model.LastName)%> </div> <div class="editor-field"> <%=Html.TextBoxFor(model => model.LastName)%> <%=Html.ValidationMessageFor(model => model.LastName)%> </div> <p> <input type="submit" /> </p> </fieldset> <% } %> Then in my controller I want to be able to post back a partial which is just a table row if the create is successful and append it to the table, which I can do easily with jquery. $('#personTable tr:last').after(data); However, if server validation fails I want to pass back my partial create person form with the validation errors and replace the existing Create Person form. I have tried returning a Json array Controller: return Json(new { Success = true, Html= this.RenderViewToString("PersonSubform",person) }); Javascript: var json_data = response.get_response().get_object(); with a pass/fail flag and the partial rendered as a string using the solition below but that doesnt render the mvc validation controls when the form fails. SO RenderPartialToString So, is there any way I can hand my javascript the out of the box PartialView("PersonForm") as its returned from my ajax.form? Can I pass some addition info as a Json array so I can tell if its pass or fail and maybe add a message? UPDATE I can now pass the HTML of a PartialView to my javascript but I need to pass some additional data pairs like ServerValidation : true/false and ActionMessage : "you have just created a Person Bill". Ideally I would pass a Json array rather than hidden fields in my partial. function ProcessResponse(response) { var html = response.get_data(); $("#campaignSubform").html(html); } Many thanks in advance

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  • JMS messaging implementation

    - by Gandalf StormCrow
    I've been struggling with this "simple" task for more expirienced people, I'm stuck for 2 days now need help. I've changed things arround like zillion times now, finally I stumbled upon this spring JMS tutorial. What I want to do, Send a message and receive it. I've been also reading this book chapter 8 on messaging. It really nicely explains 2 type of messaging and there is nice example for publish-and-subscribe type but now example for point-to-point messaging( this is the one I need). I'm able to send message to the queue on my own, but don't have a clue how to receive thats why I tried with this spring tutorial here is what I've got so far : SENDER : package quartz.spring.com.example; import java.util.HashMap; import java.util.Map; import javax.jms.ConnectionFactory; import javax.jms.JMSException; import javax.jms.Message; import javax.jms.Queue; import javax.jms.Session; import org.springframework.jms.core.MessageCreator; import org.springframework.jms.core.JmsTemplate; import org.springframework.jms.core.JmsTemplate102; import org.springframework.jms.core.MessagePostProcessor; public class JmsQueueSender { private JmsTemplate jmsTemplate; private Queue queue; public void setConnectionFactory(ConnectionFactory cf) { this.jmsTemplate = new JmsTemplate102(cf, false); } public void setQueue(Queue queue) { this.queue = queue; } public void simpleSend() { this.jmsTemplate.send(this.queue, new MessageCreator() { public Message createMessage(Session session) throws JMSException { return session.createTextMessage("hello queue world"); } }); } public void sendWithConversion() { Map map = new HashMap(); map.put("Name", "Mark"); map.put("Age", new Integer(47)); jmsTemplate.convertAndSend("testQueue", map, new MessagePostProcessor() { public Message postProcessMessage(Message message) throws JMSException { message.setIntProperty("AccountID", 1234); message.setJMSCorrelationID("123-00001"); return message; } }); } } RECEIVER : package quartz.spring.com.example; import javax.jms.JMSException; import javax.jms.Message; import javax.jms.MessageListener; import javax.jms.TextMessage; public class ExampleListener implements MessageListener { public void onMessage(Message message) { if (message instanceof TextMessage) { try { System.out.println(((TextMessage) message).getText()); } catch (JMSException ex) { throw new RuntimeException(ex); } } else { throw new IllegalArgumentException("Message must be of type TextMessage"); } } } applicationcontext.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jee="http://www.springframework.org/schema/jee" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-2.0.xsd"> <bean id="sender" class="quartz.spring.com.example.JmsQueueSender" init-method="sendWithConversion" /> <bean id="receiver" class="quartz.spring.com.example.ExampleListener" init-method="onMessage" /> </beans> Didn't really know that learning curve for this is so long, I mean the idea is very simple: Send message to the destination queue Receive message from the destination queue To receive messages, you do the following(so does book say): 1 Locate a ConnectionFactory, typically using JNDI. 2 Use the ConnectionFactory to create a Connection. 3 Use the Connection to create a Session. 4 Locate a Destination, typically using JNDI. 5 Use the Session to create a MessageConsumer for that Destination. Once you’ve done this, methods on the MessageConsumer enable you to either query the Destination for messages or to register for message notification. Can somebody please direct me towards right direction, is there a tutorial which explains in details how to receive message from the queue?I have the working send message code, didn't post it here because this post is too long as it is.

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  • rubygem Twitter4R Issues

    - by Leonardo Dario Perna
    Hi everyone, I'm trying to get started with twitter4r but I'm having some issues: Why I can't load the gem in IRB? $ sudo gem install twitter4r Successfully installed twitter4r-0.3.2 1 gem installed Installing ri documentation for twitter4r-0.3.2... Installing RDoc documentation for twitter4r-0.3.2... $ irb require 'rubygems' = false require 'twitter4r' LoadError: no such file to load -- twitter4r from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from (irb):2 I've downloaded the http://files.rubyforge.vm.bytemark.co.uk/twitter4r/twitter4rails.post-0_2_4.zip app and it works only with twitter4r-0.2.4 and NOT with last version twitter4r-0.3.2: $ script/server ./script/../config/boot.rb:26:Warning: Gem::SourceIndex#search support for String patterns is deprecated, use #find_name = Booting Mongrel (use 'script/server webrick' to force WEBrick) = Rails application starting on http://0.0.0.0:3000 = Call with -d to detach = Ctrl-C to shutdown server ** Starting Mongrel listening at 0.0.0.0:3000 ** Starting Rails with development environment... Exiting /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require': no such file to load -- twitter/rails (MissingSourceFile) from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:495:in `require' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:342:in `new_constants_in' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:495:in `require' from /Users/leonardodarioperna/Projects/Kaaaki/marrakaaaki/ twitter4rails.post-0_2_4/config/environment.rb:64 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:495:in `require' ... 23 levels... from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/rails-1.2.3/lib/commands/server.rb:39 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from script/server:3 Last thing, in the /config/environment.rb I need to specify: RAILS_GEM_VERSION = '1.2.3' unless defined? RAILS_GEM_VERSION if I use my last rails version: RAILS_GEM_VERSION = '2.3.4' unless defined? RAILS_GEM_VERSION I get this error: $ script/server -p3002 = Booting Mongrel = Rails 2.3.4 application starting on http://0.0.0.0:3000 /Library/Ruby/Site/1.8/rubygems.rb:280:in `activate': can't activate activerecord (= 1.15.6, runtime) for [], already activated activerecord-2.3.4 for ["rails-2.3.4"] (Gem::LoadError) from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:35:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:156:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:521:in `new_constants_in' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:156:in `require' from /Library/Ruby/Gems/1.8/gems/twitter4r-0.2.4/lib/twitter/rails.rb: 6 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:156:in `require' ... 8 levels... from /Library/Ruby/Gems/1.8/gems/rails-2.3.4/lib/commands/server.rb: 84 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from script/server:3 And that's all :-) Thank you!

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  • wmd editor (jquery version) over ajax forms

    - by Davide Barison
    i'm trying wmd editor over ajax. here there is the bugged code wdm code is based on openlibrary fork on github it work very good without ajax. but when i try to display editor over ajax form it doesn't load. non ajax version produce this html: <div id="wmd-container"> <div id="wmd-button-bar"></div> <div id="wmd-button-bar-0" class="wmd-button-bar"><ul class="wmd-button-row"><li style="background-position: 0px 0px;" title="Strong &lt;strong&gt; Ctrl+B" class="wmd-button wmd-bold-button"></li><li style="background-position: -20px 0px;" title="Emphasis &lt;em&gt; Ctrl+I" class="wmd-button wmd-italic-button"></li><li class="wmd-spacer"></li><li style="background-position: -40px 0px;" title="Hyperlink &lt;a&gt; Ctrl+L" class="wmd-button wmd-link-button"></li><li style="background-position: -60px 0px;" title="Blockquote &lt;blockquote&gt; Ctrl+Q" class="wmd-button wmd-quote-button"></li><li style="background-position: -80px 0px;" title="Code Sample &lt;pre&gt;&lt;code&gt; Ctrl+K" class="wmd-button wmd-code-button"></li><li style="background-position: -100px 0px;" title="Image &lt;img&gt; Ctrl+G" class="wmd-button wmd-image-button"></li><li class="wmd-spacer"></li><li style="background-position: -120px 0px;" title="Numbered List &lt;ol&gt; Ctrl+O" class="wmd-button wmd-olist-button"></li><li style="background-position: -140px 0px;" title="Bulleted List &lt;ul&gt; Ctrl+U" class="wmd-button wmd-ulist-button"></li><li style="background-position: -160px 0px;" title="Heading &lt;h1&gt;/&lt;h2&gt; Ctrl+H" class="wmd-button wmd-heading-button"></li><li style="background-position: -180px 0px;" title="Horizontal Rule &lt;hr&gt; Ctrl+R" class="wmd-button wmd-hr-button"></li><li class="wmd-spacer"></li><li style="background-position: -200px -20px;" title="Undo - Ctrl+Z" class="wmd-button wmd-undo-button"></li><li style="background-position: -220px -20px;" title="Redo - Ctrl+Shift+Z" class="wmd-button wmd-redo-button"></li><li style="background-position: -240px 0px;" class="wmd-button wmd-help-button"><a title="WMD website" target="_blank" href="http://wmd-editor.com/"></a></li></ul></div><div id="wmd-button-bar-2" class="wmd-button-bar"></div><div id="wmd-button-bar-4" class="wmd-button-bar"></div><textarea id="wmd-input" class="resizable" name="post-text" cols="92" rows="15" tabindex="101"></textarea><div id="wmd-preview-4" class="wmd-preview"></div><div id="wmd-preview-2" class="wmd-preview"></div><div id="wmd-preview-0" class="wmd-preview"></div> </div> with ajax form: <div id="wmd-container"> <div id="wmd-button-bar"></div> <div id="wmd-button-bar-1" class="wmd-button-bar"></div><div id="wmd-button-bar-3" class="wmd-button-bar"></div><textarea id="wmd-input" class="resizable" name="post-text" cols="92" rows="15" tabindex="101"></textarea><div id="wmd-preview-3" class="wmd-preview"></div><div id="wmd-preview-1" class="wmd-preview"></div> </div> any help?

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