i've a search form in which i'm trying to implement pagination - getting the data through ajax. everything works out fine initially, except when i go to the next page or any of the links on the pagination. it gives me a page not found error. can anyone please point out what is wrong with my code?
search.html
<div class="search_wrapper">
<input type="text" name="query" id="query" class="txt_search" onkeyup="submitPage('http://website/name/search.php', 'txtHint', '1');" />
<input type="button" name="button" class="button_search" onclick="submitPage('http://website/name/search.php', 'txtHint', '1');" />
<p>
<div id="txtHint"></div>
</p>
</div>
search ajax.js:
function submitPage(url, target_id, page) {
// Retrieve element handles, and populate request parameters.
var target = document.getElementById(target_id);
if(typeof page == 'undefined') {
page = 1; }
// Set up an AJAX object. Typically, an FBML response is desired.
document.getElementById(target_id).setInnerXHTML('<span id="caric"><center><img src="http://website/name/images/ajax-loader.gif" /></center></span>');
var ajax = new Ajax();
ajax.responseType = Ajax.FBML;
ajax.requireLogin = true;
ajax.ondone = function(data) {
// When the FBML response is returned, populate the data into the target element.
document.getElementById('caric').setStyle('
display','none');
if (target) target.setInnerFBML(data);
}
ajax.onerror = function() {
var msgdialog = new Dialog();
msgdialog.showMessage('Error', 'An error has occurred while trying to load.');
return false;
}
var params = {
'query' : document.getElementById('query').getValue()
};
ajax.post(url, params, page);
}
search.php:
$search_result = "";
if (isset($_POST["query"]))
$search_result = trim($_POST["query"]);
if(isset($_GET['page']))
$page = $_GET['page'];
else
$page = 1;
.....
$self = $_SERVER['PHP_SELF'];
$limit = 2; //Number of results per page
$numpages=ceil($totalrows/$limit);
$query = $query." ORDER BY idQuotes LIMIT " . ($page-1)*$limit . ",$limit";
$result = mysql_query($query, $conn)
or die('Error:' .mysql_error());
?>
<div class="search_caption">Search Results</div>
<div class="search_div">
<table>
. . .
display results
</table>
</div>
<hr>
<div class="searchmain">
<?php
//Create and print the Navigation bar
$nav="";
$next = $page+1;
$prev = $page-1;
if($page > 1) {
$nav .= "<a onclick=\"submitPage('','','$prev'); return false;\" href=\"$self?page=" . $prev . "&q=" .urlencode($search_result) . "\">< Prev</a>";
$first = "<a onclick=\"submitPage('','','1'); return false;\" href=\"$self?page=1&q=" .urlencode($search_result) . "\"> << </a>" ;
}
else {
$nav .= " ";
$first = " ";
}
for($i = 1 ; $i <= $numpages ; $i++) {
if($i == $page) {
$nav .= "<span class=\"no_link\">$i</span>";
}else{
$nav .= "<a onclick=\"submitPage('','',$i); return false;\" href=\"$self?page=" . $i . "&q=" .urlencode($search_result) . "\">$i</a>";
}
}
if($page < $numpages) {
$nav .= "<a onclick=\"submitPage('','','$next'); return false;\" href=\"$self?page=" . $next . "&q=" .urlencode($search_result) . "\">Next ></a>";
$last = "<a onclick=\"submitPage('','','$numpages'); return false;\" href=\"$self?page=$numpages&q=" .urlencode($search_result) . "\"> >> </a>";
}
else {
$nav .= " ";
$last = " ";
}
echo $first . $nav . $last;
?>
</div>
this is the link which displays on the next page:
http://apps.facebook.com/website-folder/search.php?page=2&q=good&_fb_fromhash=[some obscure number]
