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  • Java how to replace 2 or more spaces with single space in string and delete leading spaces only

    - by Nessa
    Looking for quick, simple way in Java to change this string " hello there " to something that looks like this "hello there" where I replace all those multiple spaces with a single space, except I also want the one or more spaces at the beginning of string to be gone. Something like this gets me partly there String mytext = " hello there "; mytext = mytext.replaceAll("( )+", " "); but not quite.

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  • How to compute palindrome from a stream of characters in sub-linear space/time?

    - by wrick
    I don't even know if a solution exists or not. Here is the problem in detail. You are a program that is accepting an infinitely long stream of characters (for simplicity you can assume characters are either 1 or 0). At any point, I can stop the stream (let's say after N characters were passed through) and ask you if the string received so far is a palindrome or not. How can you do this using less sub-linear space and/or time.

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  • Parsing Tabular cell data with space where there is td tag.

    - by Harikrishna
    I am parsing html tabular information with the help of the html agility pack. Now First I am finding the rows in that table like var rows = table.Descendants("tr"); then I find the cell data for each row like foreach(var row in rows) { string rowInnerText = row.InnerText; } That gives me the cell data.But with no spaces between them like NameAdressPhone No but I want the innertext like Name Address Phone No means where there is td tag I want to keep there one space between different column cell.

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  • Can i get the particular disk space(like C: ) using Jav program..?

    - by Venkats
    I used SystemEnvironment class in java for getting system information. In that i can get only RAM size, i can't get the specific disk space like c: and D: code is, com.sun.management.OperatingSystemMXBean mxbean = (com.sun.management.OperatingSystemMXBean)ManagementFactory.getOperatingSystemMXBean(); System.out.println("Total RAM:"+mxbean.getTotalSwapSpaceSize()/(1024*1024*1024)+""+"GB"); Can i get this using in java program?

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  • Re-sizing disk partition linux/vm

    - by Tiffany Walker
    I VM Player running a linux guest and I was wanting to know how do I expand the disk? In the VM player I gave more disk space but I am not sure how to mount/expand/connect the new disk space to the system. My old disk space was 14GB [root@localhost ~]# df -h / Filesystem Size Used Avail Use% Mounted on /dev/mapper/VolGroup-lv_root 14G 4.5G 8.2G 36% / Then I expanded it and now I see sda2 which is the new space? [root@localhost ~]# fdisk -l Disk /dev/sda: 128.8 GB, 128849018880 bytes 255 heads, 63 sectors/track, 15665 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000cd44d Device Boot Start End Blocks Id System /dev/sda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 64 2611 20458496 8e Linux LVM Disk /dev/mapper/VolGroup-lv_root: 14.5 GB, 14537457664 bytes 255 heads, 63 sectors/track, 1767 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/VolGroup-lv_swap: 6408 MB, 6408896512 bytes 255 heads, 63 sectors/track, 779 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Do I need to mount the new space first? resize2fs -p /dev/mapper/VolGroup-lv_root 108849018880 resize2fs 1.41.12 (17-May-2010) The containing partition (or device) is only 3549184 (4k) blocks. You requested a new size of 1474836480 blocks. resize2fs -p /dev/mapper/VolGroup-lv_root 128849018880 resize2fs 1.41.12 (17-May-2010) resize2fs: Invalid new size: 128849018880 [root@localhost ~]# lvextend -L+90GB /dev/mapper/VolGroup-lv_root Extending logical volume lv_root to 103.54 GiB Insufficient free space: 23040 extents needed, but only 0 available [root@localhost ~]# lvextend -L90GB /dev/mapper/VolGroup-lv_root Extending logical volume lv_root to 90.00 GiB Insufficient free space: 19574 extents needed, but only 0 available EDIT: So after trying pvcreate/vgextend nothing has so far worked. I'm guessing the new disk space added from VM Player is not showing up? pvscan PV /dev/sda2 VG VolGroup lvm2 [19.51 GiB / 0 free] Total: 1 [19.51 GiB] / in use: 1 [19.51 GiB] / in no VG: 0 [0 ]

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  • Why would a SQL query JOIN on the same table twice with the same condition?

    - by Scott Leis
    I'm working on changes to a SQL Server v8 database developed by someone else, and have found something that seems (based on my limited SQL knowledge) strange and pointless. One of the views has a query that does a LEFT OUTER JOIN twice on the same table with the same condition. Is there any reason for doing this? The query is below. See the second- and third-last lines that both join the "te_SDE_Survey" table on the "SDE_ID" field. Also note these lines set two different aliases for the table, and both aliases are used in the SELECT part of the query. SELECT vs.SLMS_Code, vs.Retail_Date, vs.TagNo, vs.Rego, vs.Model, vs.Company, vs.AccountType, viqdp.SDE_ID, bd.Debit_Date, isu.Survey_Date, CASE WHEN isu.Q6 IS NOT NULL THEN isu.Q6 ELSE CASE WHEN returned_surveys.survey_date IS NULL THEN CASE WHEN (viqdp.expiryDate < getdate() AND cs.sup1 IS NULL AND cs.sup2 IS NULL AND cs.sup3 IS NULL AND cs.sup5 IS NULL AND cs.sup8 IS NULL AND cs.sup9 IS NULL) THEN 'E' WHEN (viqdp.expiryDate < getdate() AND cs.sup1 = 'F' AND cs.sup2 = 'F' AND cs.sup3 = 'F' AND cs.sup5 = 'F' AND cs.sup8 = 'F' AND cs.sup9 = 'F') THEN 'E' WHEN cs.sup1 = 'T' THEN 'S' WHEN cs.sup2 = 'T' AND (cs.sup8 = 'F' AND cs.sup9 = 'F') THEN 'D' WHEN cs.sup3 = 'T' AND (cs.sup8 = 'F' AND cs.sup9 = 'F') THEN 'D' WHEN cs.sup5 = 'T' AND (cs.sup8 = 'F' AND cs.sup9 = 'F') THEN 'D' WHEN cs.sup8 = 'T' AND (cs.sup2 = 'F' AND cs.sup3 = 'F' AND cs.sup5 = 'F') THEN 'E' WHEN cs.sup9 = 'T' AND (cs.sup2 = 'F' AND cs.sup3 = 'F' AND cs.sup5 = 'F') THEN 'E' WHEN (cs.sup8 = 'T' OR cs.sup9 = 'T') AND (cs.sup2 = 'T' OR cs.sup3 = 'T' OR cs.sup5 = 'T') THEN 'S' END WHEN (tey.survey_expire_method = 'pre2008') THEN CASE WHEN (datediff(month, viqdp.generate_date, returned_surveys.survey_date) 1) THEN 'E' END WHEN (tey.survey_expire_method = 'expiryDateColumn') THEN CASE WHEN (returned_surveys.survey_date viqdp.expiryDate) THEN 'E' END END END AS score_or_exclusion_status, CASE WHEN (bd.explanation IS NULL) THEN '' ELSE bd.explanation END AS explanation, tey.te_Year FROM dbo.te_Vehicle_Sale vs INNER JOIN dbo.te_Year tey ON vs.Retail_Date = tey.Start_Date AND vs.Retail_Date <= tey.End_Date LEFT OUTER JOIN dbo.Bad_Data bd ON vs.TagNo = bd.TagNo LEFT OUTER JOIN dbo.te_Vehicle_SDESurvey viqdp ON vs.TagNo = viqdp.TagNo LEFT OUTER JOIN dbo.te_SDE_Survey isu ON viqdp.SDE_ID = isu.SDE_ID LEFT OUTER JOIN dbo.te_SDE_Survey returned_surveys ON viqdp.SDE_ID = returned_surveys.SDE_ID LEFT OUTER JOIN dbo.te_SDE_Contact_Suppression cs ON viqdp.SDE_ID = cs.SDE_ID

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  • SELECT Statement without duplicate rows on the multiple join tables

    - by theBo
    I have 4 tables built with JOINS and I would like to SELECT DISTINCT rows on the setsTbl.s_id so they always show regardless if there's relational data against them or not!. This is what I have at present which displays the data but doesn't display all of but not the entire distinct row! SELECT setsTbl.s_id, setsTbl.setName, userProfilesTbl.no + ' ' + userProfilesTbl.surname AS Name, trainingTbl.t_date, userAssessmentTbl.o_id FROM userProfilesTbl LEFT OUTER JOIN userAssessmentTbl ON userProfilesTbl.UserId = userAssessmentTbl.UserId FULL OUTER JOIN trainingTbl ON userAssessmentTbl.tt_id = trainingTbl.tt_id RIGHT OUTER JOIN setsTbl ON trainingTbl.s_id = setsTbl.s_id WHERE (userProfilesTbl.st_id=@st_id AND userProfilesTbl.sh_id=@sh_id) AND (DATEPART(yyyy,t_date) = @y_date ) OR (userAssessmentTbl.o_id IS NULL) ORDER BY setName ASC, t_date ASC With this statement I get some of the rows (the ones with data against them) but as stated the s_id field does not return distinct. This following inner select statement works in part when used in SQL Query analyzer and returns pretty much the data i require s_id setName Name o_id ----- ----- ----- ------ 1 100 Barnes 2 2 100 Beardsley 3 3 101 Aldridge 1 4 102 Molby 2 5 102 Whelan 3 but not when used outside of that environment. select * from ( SELECT userProfilesTbl.serviceNo + ' ' + userProfilesTbl.surname AS Name, userProfilesTbl.st_id, userProfilesTbl.sh_id, userAssessmentTbl.o_id, setsTbl.s_id, setsTbl.setName, row_number() over ( partition by setsTbl.s_id order by setsTbl.s_id ) r FROM userProfilesTbl LEFT OUTER JOIN userAssessmentTbl ON userProfilesTbl.UserId = userAssessmentTbl.UserId FULL OUTER JOIN trainingTbl ON userAssessmentTbl.tt_id = trainingTbl.tt_id RIGHT OUTER JOIN setsTbl ON trainingTbl.s_id = setsTbl.s_id ) x where x.r = 1 Not receiving any errors just not displaying the data?

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