Search Results

Search found 24400 results on 976 pages for 'print screen'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 461/976 | < Previous Page | 457 458 459 460 461 462 463 464 465 466 467 468  | Next Page >

  • Problem with setting text into a uneditable JTextField

    - by The Z
    I have a tabbed pane with a couple of uneditable JTextFields which I want to fill in with information from a database. However, when I set the text in the text fields to anything, it doesn't show up when I run the program. When I get the text and print it out, it does show. What could be the problem here?

    Read the article

  • ImageViews sometimes not displaying in FrameLayout activity

    - by Ken
    The top level layout in my activity is a framelayout. I have completed, debugged and tested this app and it works exactly like it should in all respects on my g1 and on various emulators. But on 3.7-inch displays running 2.1+, some imageviews packed in a linearlayout are periodically not visible. I know that they are there because you can touch and drag them with effect in the app. So I assume somehow they have gotten under the SurfaceView that is the main component of the app. This is apparently so even though the SurfaceView is declared in the xml prior to the LinearLayout. However, the ImageViews IN the LinearLayout are added programmatically towards the end of onCreate(). Framelayout stacks everything that is added to it, one on top of the other--the only way you will see more than one child of a frame layout is if they are smaller than the screen and are placed apart from eachother. Oddly, sometimes the imageviews ARE visible--it is random. Anyway, I've been trying to combat this with framelayout.bringChildToFront(View v) on the linearlayout without success. I wonder if anyone has any insight into how the behavior could be random like that, and how I should code these imageviews to keep this from happening, and why the problem appears only to occur on 3.7 vs 3.2 inch screens (as it happens, the two 3.2-inch screens were both htc, so vendor might be factor too). [edit] Actually, I've determined that this is a 2.2 issue, not a screen size (or even vendor) issue. Can't ensure that ImageViews added to a framelayout with a SurfaceView in it will appear on top of the surfaceview. I ran some tests in the respective onDraw() methods and the imageviews are 'visible' (0), and nothing does anything to the alpha of the drawables, which are there as well at ondraw(). [/edit] Any insight would be welcomed. Ken T.

    Read the article

  • Is it good practice to name variables differently when defining more than one function?

    - by John
    For example, in this simple function where fun1 takes as input two numbers, adds them together and passes them to function 2 for printing the output. var1_in is local to each function, so is it OK to use the name var1_in in both functions, or is it better practice to call them different things? fun1 <- function (var1_in, var2_in) { var3 = var1_in + var2_in fun2(var3) } fun2 <- function (var1_in) { var4 = var1_in print(var4) }

    Read the article

  • iOS - Passing variable to view controller

    - by gj15987
    I have a view with a view controller and when I show this view on screen, I want to be able to pass variables to it from the calling class, so that I can set the values of labels etc. First, I just tried creating a property for one of the labels, and calling that from the calling class. For example: SetTeamsViewController *vc = [[SetTeamsViewController alloc] init]; vc.myLabel.text = self.teamCount; [self presentModalViewController:vc animated:YES]; [vc release]; However, this didn't work. So I tried creating a convenience initializer. SetTeamsViewController *vc = [[SetTeamsViewController alloc] initWithTeamCount:self.teamCount]; And then in the SetTeamsViewController I had - (id)initWithTeamCount:(int)teamCount { self = [super initWithNibName:nil bundle:nil]; if (self) { // Custom initialization self.teamCountLabel.text = [NSString stringWithFormat:@"%d",teamCount]; } return self; } However, this didn't work either. It's just loading whatever value I've given the label in the nib file. I've littered the code with NSLog()s and it is passing the correct variable values around, it's just not setting the label. Any help would be greatly appreciated. EDIT: I've just tried setting an instance variable in my designated initializer, and then setting the label in viewDidLoad and that works! Is this the best way to do this? Also, when dismissing this modal view controller, I update the text of a button in the view of the calling ViewController too. However, if I press this button again (to show the modal view again) whilst the other view is animating on screen, the button temporarily has it's original value again (from the nib). Does anyone know why this is?

    Read the article

  • Javascript/JQuery if statement

    - by Samuurai
    This is probably pretty simple, but I can't figure out how to do it: I have this code: $.post("/admin/contract", { 'mark_paid' : true, 'id' : id }, In pseudo code, how can I do this: $.post("/admin/contract", { 'mark_paid' : true, 'id' : id, if(is_set(dont_email)) {print 'dont_email' : true} },

    Read the article

  • Counting vowels

    - by user74283
    Can anyone please tell me what is wrong with this script. I am a python newb but i cant seem to figure out what might be causing it not to function. def find_vowels(sentence): """ >>> find_vowels(test) e """ count = 0 vowels = "aeiuoAEIOU" for letter in sentence: if letter in vowels: count += 1 print count if __name__ == '__main__': import doctest doctest.testmod()

    Read the article

  • Is it possible to create an Android Service that listens for hardware key presses?

    - by VoteBrian
    I'd like to run an Android background service that will act as a keylistener from the home screen or when the phone is asleep. Is this possible? From semi-related examples online, I put together the following service, but get the error, "onKeyDown is undefined for the type Service". Does this mean it can't be done without rewriting Launcher, or is there something obvious I'm missing? public class ServiceName extends Service { @Override public void onCreate() { //Stuff } public IBinder onBind(Intent intent) { //Stuff return null; } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if(event.getAction() == KeyEvent.ACTION_DOWN) { switch(keyCode) { case KeyEvent.KEYCODE_A: //Stuff return true; case KeyEvent.KEYCODE_B: //Stuff return true; //etc. } } return super.onKeyDown(keyCode, event); } } I realize Android defaults to the search bar when you type from the home screen, but this really is just for a very particular use. I don't really expect anyone but me to want this. I just think it'd be nice, for example, to use the camera button to wake the phone.

    Read the article

  • I want to trace logs using a Macro multi parameter always null. problem c++ windows

    - by sxingfeng
    I am using the following way to cout a function's time: #define TIME_COST(message, ...)\ char szMessageBuffer[2048] = {0};\ va_list ArgList;\ va_start(ArgList, message);\ vsprintf_s(szMessageBuffer, 2048, message, ArgList);\ va_end(ArgList); \ string strMessage(szMessageBuffer);\ CQLogTimer t(strMessage); // CQLogTimer is a self destructor,which will cout life time of its own and print szMessageBuffer. However when I use the macro this : void fun { TIME_COST("hello->%s", filePath); XXXXXX } The message generated always is hello-(null) Can Any one help? Many thanks!

    Read the article

  • how to create class alert using lcdui package in blackberry

    - by Baby
    Advance Thanks.i am new to blackberry developement.i try the following code for creating alert using lcdui package.but nothing will coming when i am running Plz help me. package alertpack; import javax.microedition.lcdui.Alert; import javax.microedition.lcdui.AlertType; import javax.microedition.lcdui.Command; import javax.microedition.lcdui.CommandListener; import javax.microedition.lcdui.Display; import javax.microedition.lcdui.Displayable; import javax.microedition.lcdui.Form; import javax.microedition.lcdui.Screen; import javax.microedition.midlet.MIDlet; import javax.microedition.midlet.MIDletStateChangeException; import net.rim.device.api.ui.Color; import net.rim.device.api.ui.Graphics; public class alertclass extends MIDlet implements CommandListener { private Display display; private Alert alert; private Form form = new Form("Throw Exception"); private Command exit = new Command("Exit", Command.SCREEN, 1); //public static void main(String[] args) //{ //} private boolean exitFlag = false; public alertclass(){ display = Display.getDisplay(this); form.addCommand(exit); form.setCommandListener(this); } protected void destroyApp(boolean unconditional) throws MIDletStateChangeException { // TODO Auto-generated method stub if (unconditional == false) { throw new MIDletStateChangeException(); } } protected void pauseApp() { // TODO Auto-generated method stub } protected void startApp() throws MIDletStateChangeException { // TODO Auto-generated method stub display.setCurrent(form); } public void commandAction(Command c, Displayable d) { // TODO Auto-generated method stub if (c == exit) { try { if (exitFlag == false) { alert = new Alert("Busy", "Please try again.", null, AlertType.WARNING); alert.setTimeout(Alert.FOREVER); display.setCurrent(alert, form); destroyApp(false); } else { destroyApp(true); notifyDestroyed(); } } catch (Exception exception) { exitFlag = true; } } } }

    Read the article

  • Perl: Printing without a newline

    - by synapz
    I have a computationally expensive task in perl, and would like to inform the user that computation is ongoing by printing out a period after each portion of the computation is completed. Unfortunately, until I print a "\n", none of my periods are printed. How can I address this?

    Read the article

  • Import? Initialize? what do to?

    - by Jeremy B
    I'm working on homework and I'm close but I am having an issue. I just learned how to work with packages in eclipse so I have a class that is importing another class from a package (I think I said that right) The main prompts the user to enter an integer between -100 and 100 and I am having an issue with validating it. I know the issue is where I'm importing I'm just unsure the direction I need to go to fix it. This is a section of my main code. (my issue starts with the last couple lines if you want to skip ahead) import myUtils.util.Console; public class ConsoleTestApp { public static void main(String args[]) { // create the Console object Console c = new Console(); // display a welcome message c.println("Welcome to the Console Tester application"); c.println(); // int c.println("Int Test"); int i = c.getIntWithinRange("Enter an integer between -100 and 100: ", -101, 101); c.println(); I have a class called Console that is located in another package that I believe I have properly imported. here is the code I am stuck on in my console class. public int getIntWithinRange(String prompt, int min, int max) { int i = 0; boolean isValid = false; while (isValid == false) { System.out.println(prompt); if (sc.hasNextInt()) { //if user chooses menu option less than 1 the program will print an error message i = sc.nextInt(); if (i < min) { System.out.println("Error! Please enter an int greater than -100"); } else if (i > max) { System.out.println("Error! Please enter an int less than 100"); } else isValid = true; } else System.out.println("Error! Invalid number value"); sc.nextLine(); } // return the int return i; } when I run this I keep getting my last print which is an invalid number value. am I not importing the code from the main method in the other console properly?

    Read the article

  • python - remove string from words in an array

    - by tekknolagi
    #!/usr/bin/python #this looks for words in dictionary that begin with 'in' and the suffix is a real word wordlist = [line.strip() for line in open('/usr/share/dict/words')] newlist = [] for word in wordlist: if word.startswith("in"): newlist.append(word) for word in newlist: word = word.split('in') print newlist how would I get the program to remove the string "in" from all the words that it starts with? right now it does not work

    Read the article

  • figuring out which field to look for a value in with SQL and perl

    - by Micah
    I'm not too good with SQL and I know there's probably a much more efficient way to accomplish what I'm doing here, so any help would be much appreciated. Thanks in advance for your input! I'm writing a short program for the local school high school. At this school, juniors and seniors who have driver's licenses and cars can opt to drive to school rather than ride the bus. Each driver is assigned exactly one space, and their DLN is used as the primary key of the driver's table. Makes, models, and colors of cars are stored in a separate cars table, related to the drivers table by the License plate number field. My idea is to have a single search box on the main GUI of the program where the school secretary can type in who/what she's looking for and pull up a list of results. Thing is, she could be typing a license plate number, a car color, make, and model, someone driver's name, some student driver's DLN, or a space number. As the programmer, I don't know what exactly she's looking for, so a couple of options come to mind for me to build to be certain I check everywhere for a match: 1) preform a couple of SELECT * FROM [tablename] SQL statements, one per table and cram the results into arrays in my program, then search across the arrays one element at a time with regex, looking for a matched pattern similar to the search term, and if I find one, add the entire record that had a match in it to a results array to display on screen at the end of the search. 2) take whatever she's looking for into the program as a scaler and prepare multiple select statements around it, such as SELECT * FROM DRIVERS WHERE DLN = $Search_Variable SELECT * FROM DRIVERS WHERE First_Name = $Search_Variable SELECT * FROM CARS WHERE LICENSE = $Search_Variable and so on for each attribute of each table, sticking the results into a results array to show on screen when the search is done. Is there a cleaner way to go about this lookup without having to make her specify exactly what she's looking for? Possibly some kind of SQL statement I've never seen before?

    Read the article

  • innerJoin query show error

    - by Chithri Ajay
    just i print the two table data so i am using inner join SELECT sd.GameName FROM LottoryTickets AS sd JOIN group AS p ON sd.Group = p.groupname WHERE p.groupname = 11 now i get #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'group AS p ON sd.Group = p.groupname WHERE p.groupname = 11 LIMIT 0, 30' at line 3 this response please guide me thanks for advance.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 457 458 459 460 461 462 463 464 465 466 467 468  | Next Page >