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  • Preview for create/edit content doesn't work

    - by Snazzy
    Hi! I'm configuring a DRUPAL site web (that it was previously created) and I'm testing the diferent options. When I create a new content or edit a old content and change anything and then I click on 'Preview' doesn't appear the recent changes (just appear the old values), I have to save it before. NOTE: I do the accions as ROOT (it not a privilege problem). Anyone knows what is happened?

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  • how to pass an array from a asp.net mvc controller action back to javascript using jquery / ajax

    - by oo
    Here is my jQuery code: $.get('/Home/GetList', function(data) { debugger; $('#myMultiSelect').val(values); }); Here is my controller code: public ActionResult GetList(int id) { int[] bodyParts = _repository.GetList(id); //how do i return this as an array back to javascript ?? } if I have the GetList function return an array of integers, how do I return this to the jQuery function?

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  • polymorphism alternative for MySQL stored procedures

    - by zombiegx
    I'm porting some stored procedures from Informix to MySQL, but I have two stored procedures on Informix that have same name and different parameters. In MySQL, I can't create two SP with the same name, and also can't create a SP with default values in parameters. so, do someone out there know any hackery or black magic that may help me solve this problem? thanks.

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    How to make the use of hidden variables as array for consecutive submission of data so that they can be used to display the records list. I have a form with 4 text fields and a file upload field.. as i submit he form it should get appended to the list which needs to be displayed below the form, such that these values are NOT stored in the DB.. So in this case how can i use the post array to collect the data and display in the list below?

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  • Parallel computation of the median of a large array

    - by recipriversexclusion
    I got asked this question once and still haven't been able to figure it out: You have an array of N integers, where N is large, say, a billion. You want to calculate the median value of this array. Assume you have m+1 machines (m workers, one master) to distribute the job to. How would you go about doing this? Since the median is a nonlinear operator, you can't just find the median in each machine and then take the median of those values.

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  • Set the volume of an android application

    - by klaus-johan
    Hi, In order for the user to control the volume , my android application has a menu consisting of a slider that provides int values from 0 to 10 , when dragged. After I obtain a value , I must set the volume to the corresponding value chosen by the user , and well , this is the part that I don't know to implement and I 'd like to find about it.

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  • String literals and escape characters in postgresql

    - by rjohnston
    Attempting to insert an escape character into a table results in a warning. For example: create table EscapeTest (text varchar(50)); insert into EscapeTest (text) values ('This is the first part \n And this is the second'); Produces the warning: WARNING: nonstandard use of escape in a string literal (Using PSQL 8.2) Anyone know how to get around this?

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  • JQuery input elements

    - by codeasp
    I need to get all input elements within a div and then attach event handlers, so that whenever values change it updates a hidden field. Children elements within the div might already contain event handlers, if so the attach should chain it. Any help is much appreciated.

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  • replace function in dml statements in oracle 8i

    - by maheshasoni
    Can we use Replace function in a update statement ? If yes then How? I have a column 'enrollno' having values like '800-00001' to '800-01800'. I want to replace inital '800-' to '800' in all 1800 records. (Output should be '8000001' to '80001800') Is it possible through replace function or any other option is there in ORACLE8i ? MaheshA...

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  • A problem with compare item value

    - by Tony
    Hi, I have defined my class: public class Host { public string Name; } then a strongly-typed dictionary: Dictionary<string, Host> HostsTable; then I try to compare a value: if (HostsTable.Values.Where(s => s.Name == "myhostname") != null) { doSomething } and the problem is, nothing is found, even I'm sure the item is on the list. What I'm doing wrong ?

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  • apex button to call a page in another application

    - by jaykio77
    I have a workspace with which I have 5 applications based on same schema. Now I want to have a main page from where I could call main pages of all these applications. I used this syntax to call home page in another application but to no avail f?p=4000:4150:&APP_SESSION. Where 4000:4150 are the values for the application and the page I want to display. Please let me know where am I making mistake.

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  • Textbox not updating in UI screen

    - by subash
    i have a page consisting of devexpress gridview control with 4 columns and 4 asp.net text boxes. on selecting a row in gridview ,it should update the 4 textboxes with the values of the row selected. so i was assigning the value of the rows of the grid to the text box in the custom callback event of the grid and also the value gets assigned to the all textboxes's text property but it doesn't updates the textbox value in the UI screen.

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  • in ruby, how do you make this nested hash work?

    - by David
    this one creates an error: @settings = { :tab1 => { :name => { :required => true }, :description } } need to change :descrpition to :description = {}, but i don't have any values for :description so i want it to remain as is (without the empty = {}) Would you show me the best way to handle this kind of situation? thanks in advance

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  • Need help with 2 MySql Queries. Join vs Subqueries.

    - by BugBusterX
    I have 2 tables: user: id, name message: sender_id, receiver_id, message, read_at, created_at There are 2 results I need to retrieve and I'm trying to find the best solution. I have included queries that I'm using in the very end. I need to retrieve a list of users, and also with each user have information available whether there are any unread messages from each user (them as sender, me as receiver) and whether or not there are any read messages between us ( they send I'm receiver or I send they are receivers) I need Same as above, but only those members where there has been any messaging between us, sorted by unread first, then by last message received. Can you advise please? Should this be done with joins or subqueries? In first case I do not need the count, I just need to know whether or not there is at least one unread message. I'm posting code and my current queries, please have a look when you get a chance: BTW, everything is the way I want in fist query. My concern is: In second query I would like to order by messages.created_at, but I dont think I can do that with grouping? And also I dont know if this approach is the most optimized and fast. CREATE TABLE `user` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `user` VALUES (1,'User 1'),(2,'User 2'),(3,'User 3'),(4,'User 4'),(5,'User 5'); CREATE TABLE `message` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `sender_id` bigint(20) DEFAULT NULL, `receiver_id` bigint(20) DEFAULT NULL, `message` text, `read_at` datetime DEFAULT NULL, `created_at` datetime NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `message` VALUES (1,3,1,'Messge',NULL,'2010-10-10 10:10:10'),(2,1,4,'Hey','2010-10-10 10:10:12','2010-10-10 10:10:11'),(3,4,1,'Hello','2010-10-10 10:10:19','2010-10-10 10:10:15'),(4,1,4,'Again','2010-10-10 10:10:25','2010-10-10 10:10:21'),(5,3,1,'Hiii',NULL,'2010-10-10 10:10:21'); SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) GROUP BY u.id SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) where m.id IS NOT NULL GROUP BY u.id

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