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  • problem using fprintf

    - by shiran bar
    I'm trying to print to a text file numerous variables yet it doesn't work. I checked and verified that i write it in the correct syntax. I also checked the return value and it's positive therefore i know it did write to the file, however when i open the file it's empty. I would be happy for some help. This is the code: I initiate DynsaleDayPtr in the main: FILE* DynsaleDayPtr = CreateTextFiles("sale_day.txt"); Create function: FILE* CreateTextFiles (char* fileName) { FILE* saleFilePtr=NULL; if((saleFilePtr=fopen(fileName,"a+"))==NULL) printf("File couldn't be opened\n"); return saleFilePtr; } The call to the function TextAddSale is done from a function that is called in the main: TextAddSale(DynSaleDayPtr,dynNumOfRecords); Bool TextAddSale (FILE* DynsaleDayPtr, int* dynNumOfRecords) { char id[6]; char name [50]; char priceChar[20]; char* tmp = NULL; int price=-1; DynamicRecord * newRec=NULL; scanf("%s%s%s",id,name,priceChar); newRec = (DynamicRecord *)malloc(sizeof(DynamicRecord)); if (newRec == NULL) return False; tmp = (char*)malloc(strlen(name)+1); if (tmp == NULL) { free (newRec); return False; } strcpy(tmp,name); newRec->productName = tmp; strcpy(newRec->productId, id); newRec->productPrice=atoi (priceChar); if (fprintf(DynsaleDayPtr,"%d %s %s %d", strlen(newRec->productName), newRec->productId, newRec->productName, newRec->productPrice)>0) { *dynNumOfRecords=(*dynNumOfRecords)+1; return True; } } thanks!

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  • C++ Problem resolution - is it the best way to simulate a "tuple"?

    - by fbin
    Hi everyone! I've got the following problem: "Write a template function vectorMAXMIN() that will accept a vector and a number indicating the size of the vector and will return the max and the min values of the vector"... So i think in it... Create a class vector to avoid the "size" passing value and control the insertions and can get from this the max and min values... ( dunno if it's a good idea ) The problem is "how to return a tuple?" When i read the problem, i thought in a tuple to return "max, min values" is it correct? The code: #include <iostream> template < typename T > class _tuple { public: T _Max; T _Min; }; template < typename T > class _vector { public: _vector( int cnt = 0); ~_vector(); _tuple< T > get_tuple( void ); void insert( const T ); private: T *ptr; int cnt; int MAX; }; template < typename T > _vector< T >::_vector( int N ) { ptr = new T [N] ; MAX = N; cnt = 0; } template < typename T > _tuple<T> _vector< T >::get_tuple( void ) { _tuple< T > _mytuple; _mytuple._Max = ptr[0]; _mytuple._Min = ptr[0]; for( int i = 1; i < cnt; i++) { if( _mytuple._Max > ptr[i] ) _mytuple._Max = ptr[i]; if( _mytuple._Min < ptr[i] ) _mytuple._Min = ptr[i]; } return _mytuple; } template < typename T > void _vector< T >::insert( const T element) { if( cnt == MAX ) std::cerr << "Error: Out of range!" << std::endl; else { ptr[cnt] = element; cnt++; } } template < typename T > _vector< T >::~_vector() { delete [] ptr; } int main() { _vector< int > v; _tuple < int > t; v.insert(2); v.insert(1); v.insert(5); v.insert(0); v.insert(4); t = v.get_tuple(); std::cout << "MAX:" << t._Max; std::cout << " MIN:" << t._Min; return 0; }

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  • Help with string equality in Java

    - by annayena
    The following function accepts 2 strings, the 2nd (not 1st) possibly containing *'s (asterisks). An * is a replacement for a string (empty, 1 char or more), it can appear appear (only in s2) once, twice, more or not at all, it cannot be adjacent to another * (ab**c), no need to check that. public static boolean samePattern(String s1, String s2) It returns true if strings are of the same pattern. It must be recursive, not use any loops, static or global variables. Also it's prohibited to use the method equals in the String class. Can use local variables and method overloading. Can use only these methods: charAt(i), substring(i), substring(i, j), length(). Examples: 1: TheExamIsEasy; 2: "The*xamIs*y" ---> true 1: TheExamIsEasy; 2: "Th*mIsEasy*" ---> true 1: TheExamIsEasy; 2: "*" ---> true 1: TheExamIsEasy; 2: "TheExamIsEasy" ---> true 1: TheExamIsEasy; 2: "The*IsHard" ---> FALSE I am stucked on this question for many hours now! I need the solution in Java please kindly help me.

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  • Pointers in C with binary file

    - by darkie15
    Hi All, I am reading the contents of the file using fread into an char array. But I am not sure why it is not getting printed in the output. Here is the code: void getInfo(FILE* inputFile) { char chunk[4]; int liIndex; for (liIndex = 0 ; liIndex < 4 ; liIndex++) { fread(chunk, sizeof(char), 4, inputFile); } printf("\n chunk %s", chunk); } Output prints nothing at all. Where am I going wrong? Regards , darkie

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  • Rotating bits of any integer in C

    - by Tim
    Pass a integer 2 to this function and then return a integer which is 4 x = 2; x = rotateInt('L', x, 1); (left shift the bits by 1) Example: 00000010 - rotate left by 1 - 00000100 but if I pass this: x = rotateInt('R', x, 3); it will return 64, 01000000 Here is the code, can someone correct the error... thanks int rotateInt(char direction, unsigned int x, int y) { unsigned int mask = 0; int num = 0, result = 0; int i; for(i = 0; i < y; i++) { if(direction == 'R') { if((x & 1) == 1) x = (x ^ 129); else x = x >> 1; } else if(direction == 'L') { if((x & 128) == 1) x = (x ^ 129); else x = x << 1; } } result = (result ^ x); return result; }

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  • Main purpose of this task is to calculate volumes and surface areas of three dimensional geometric shapes like, cylinders, cones.

    - by Csc_Girl_Geek
    In Java Language Design your classes as below introducing: an Interface named “GeometricShapes” an abstract class named “ThreeDShapes” two child classes of ThreeDShapes: Cylinders and Cones. One test class names “TestShapes” Get the output for volumes and surface areas of cylinders and cones along with respective values of their appropriate input variables. Try to use toString() method and array. Your classes should be designed with methods that are required for Object-Oriented programming. So Far I Have: package Assignment2; public interface GeometricShapes { public void render(); public int[] getPosition(); public void setPosition(int x, int y); } package Assignment2; public abstract class ThreeDShapes implements GeometricShapes { public int[] position; public int[] size; public ThreeDShapes() { } public int[] getPosition() { return position; } public void setPosition(int x, int y) { position[0] = x; position[1] = y; } } package Assignment2; public class Cylinders extends ThreeDShapes { public Cylinder() { } public void render() { } } I don't think this is right and I do not know how to fix it. :( Please help.

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  • array multiplication task

    - by toby
    I am tying to get around how you will multiply the values in 2 arrays (as an input) to get an output. The problem I have is the how to increment the loops to achieve the task shown below #include <iostream> using namespace std; main () { int* filter1, *signal,fsize1=0,fsize2=0,i=0; cout<<" enter size of filter and signal"<<endl; cin>> fsize1 >> fsize2; filter1= new int [fsize1]; signal= new int [fsize2]; cout<<" enter filter values"<<endl; for (i=0;i<fsize1;i++) cin>>filter1[i]; cout<<" enter signal values"<<endl; for (i=0;i<fsize2;i++) cin>>signal[i]; /* the two arrays should be filled by users but use the arrays below for test int array1[6]={2,4,6,7,8,9}; int array2[3]={1,2,3}; The output array should be array3[9]={1*2,(1*4+2*2),(1*6+2*4+3*2),........,(1*9+2*8+3*7),(2*9+3*8),3*9} */ return 0; } This is part of a bigger task concerning filter of a sampled signal but it is this multiplication that i cant get done.

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  • Why does this program stop running?

    - by designloper
    Hi everyone....I am developing a card making system...nothing fancy. Right got this far but program now stops running with no error when running after the first card sample i.e. " Enter 'OK' if this card is OK, otherwise enter an alternative border character: + ". Any suggestions Java Masters? //Ask user for input //makes use of print line method System.out.println("Enter name: "); //took the variables //called the object of the scanner 'cardOrder' //and use the Scanner objects method '.nextLine' //to read the next line of the input firstName = cardOrder.nextLine(); mInitial = cardOrder.nextLine(); lastName = cardOrder.nextLine(); //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); //test if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } else if(b == optionA) { //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n+ +" + "\n+" + " " + firstName + mInitial + lastName + " +" + "\n+ +\n" + firstName + mInitial + lastName +"++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: OK "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } } else if (c == optionA) {//Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } }

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  • 1-DimArray Counting same elements (0,1)

    - by Chris
    Hello, I have a 1-dim array that fills up a table of 40 random elements (all the values are either 0 or 1). So i wanne "count" the largest row of the values net to each otherto each other.. Meaning for example : 111100101 = the longest row would be 1111 (= 4 elements of the same kind closest to each other). So 011100 would result in the longest row being 3 elements (3 x 1). My problem i have no idea how to check upon the "next element" and check if its a 0 or 1. Like the first would be 1111 (count 4) but the next would be a 0 value = meaning i have to stop counting. My idea was placing this value (4) in a other array (example: 111100101) , and place the value of the 1's back on zero. And start the process all over again. To find the largest value i have made a other method that checks up the biggest value in the array that keeps track of the count of 0's 1's, this is not the problem. But i cannot find a way to fill the array tabelLdr up. (having all the values of the group of elements of the same kind (being 0 or 1). In the code below i have 2 if's and offcourse it will never go into the second if (to check if the next value in the array is != then its current state (being 0 or 1) Best Regards. public void BerekenDeelrij(byte[] tabel, byte[] tabelLdr) { byte LdrNul = 0, Ldréén = 0; //byte teller = 0; for (byte i = 0; i < tabel.Length; i++) { if (tabel[i] == 0) { LdrNul++; //this 2nd if cleary does not work, but i have no idea how to implend this sort of idea in my program. if (tabel[i] == 1) //if value != 0 then the total value gets put in the second array tabelLdr, { tabelLdr[i] = LdrNul; LdrNul = 0; } } if (tabel[i] == 1) { Ldréén++; if (tabel[i] == 0) { tabelLdr[i] = Ldréén; Ldréén = 0; } } }/*for*/ }

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  • find nth digit in C

    - by kokkch
    i spend more than a day to solve this and i can't. I have a function name int get_nth_digit (int x, int pos); which takes as entering the number given by the user(x) and a number that represents the position in which the user wishes to return the item. How can do this with C program? can you help me pls???? thx

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  • priority queue implementation

    - by davit-datuashvili
    i have implemented priority queue and i am interested if it is correct public class priqueue { private int n,maxsize; int x[]; void swap(int i,int j){ int t=x[i]; x[i]=x[j]; x[j]=t; } public priqueue(int m){ maxsize=m; x=new int [maxsize+1]; n=0; } void insert(int t){ int i,p; x[++n]=t; for (i=n;i>1 && x[p=i/2] >x[i];i=p) swap(p,i); } public int extramin(){ int i,c; int t=x[1]; x[1]=x[n--]; for (i=1;(c=2*i)<=n;i=c){ if (c+1<=n && x[c+1]<x[c]) c++; if (x[i]<=x[c]) break; swap(c,i); } return t; } public void display(){ for (int j=0;j<x.length;j++){ System.out.println(x[j]); } } } public class priorityqueue { public static void main(String[] args) { priqueue pr=new priqueue(12); pr.insert(20); pr.insert(12); pr.insert(22); pr.insert(15); pr.insert(35); pr.insert(17); pr.insert(40); pr.insert(51); pr.insert(26); pr.insert(19); pr.insert(29); pr.insert(23); pr.extramin(); pr.display(); } } //result: 0 12 15 17 20 19 22 40 51 26 35 29 23

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  • Java Sorting "queue" list based on DateTime and Z Position (part of school project)

    - by Kuchinawa
    For a school project i have a list of 50k containers that arrive on a boat. These containers need to be sorted in a list in such a way that the earliest departure DateTimes are at the top and the containers above those above them. This list then gets used for a crane that picks them up in order. I started out with 2 Collection.sort() methods: 1st one to get them in the right XYZ order Collections.sort(containers, new Comparator<ContainerData>() { @Override public int compare(ContainerData contData1, ContainerData contData2) { return positionSort(contData1.getLocation(),contData2.getLocation()); } }); Then another one to reorder the dates while keeping the position in mind: Collections.sort(containers, new Comparator<ContainerData>() { @Override public int compare(ContainerData contData1, ContainerData contData2) { int c = contData1.getLeaveDateTimeFrom().compareTo(contData2.getLeaveDateTimeFrom()); int p = positionSort2(contData1.getLocation(), contData2.getLocation()); if(p != 0) c = p; return c; } }); But i never got this method to work.. What i got working now is rather quick and dirty and takes a long time to process (50seconds for all 50k): First a sort on DateTime: Collections.sort(containers, new Comparator<ContainerData>() { @Override public int compare(ContainerData contData1, ContainerData contData2) { return contData1.getLeaveDateTimeFrom().compareTo(contData2.getLeaveDateTimeFrom()); } }); Then a correction function that bumps top containers up: containers = stackCorrection(containers); private static List<ContainerData> stackCorrection(List<ContainerData> sortedContainerList) { for(int i = 0; i < sortedContainerList.size(); i++) { ContainerData current = sortedContainerList.get(i); // 5 = Max Stack (0 index) if(current.getLocation().getZ() < 5) { //Loop through possible containers above current for(int j = 5; j > current.getLocation().getZ(); --j) { //Search for container above for(int k = i + 1; k < sortedContainerList.size(); ++k) if(sortedContainerList.get(k).getLocation().getX() == current.getLocation().getX()) { if(sortedContainerList.get(k).getLocation().getY() == current.getLocation().getY()) { if(sortedContainerList.get(k).getLocation().getZ() == j) { //Found -> move container above current sortedContainerList.add(i, sortedContainerList.remove(k)); k = sortedContainerList.size(); i++; } } } } } } return sortedContainerList; } I would like to implement this in a better/faster way. So any hints are appreciated. :)

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  • how to create a linked list in java without using util package? [closed]

    - by aparna
    I do not want to use any of the elements of the UTIL package. I tried but I am not able to get to the next node. Can anyone please help me out? Thanks in advance. I have put up this much. public class Element { private String s; private Element next; } public Element(String s) { this.s = s; this.next = null; } public void setNext(Element e) { this.next = e; } public String getString() { return this.s; } public Element getNext() { return this.next; } public String toString() { return "[" + s + "] => "; } public void add(String s) { int index = 0; System.out.println("Adding at index: " + index); Element curr = new Element(s); Element e = this.data[index]; if (e == null) { this.data[index] = curr; return; } while(e.getNext() != null) { e = e.getNext(); } e.setNext(curr); } }

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  • "Teach" a computer how to do addition?

    - by ffar
    The problem is to learn computer to do addition. Computer have as input a knowladge of a numbers: he "knows" that after 1 goes 2, after 2 goes 3 and so on... Having that data computer can easyly get next number. Next, computer have knowlandge as input that x+0=x and x+(y+1)=(x+1)+y. This axioms let computer to do addition. For example, to add 5 and 3, computer makes following: 5+3 = 5+(2+1) = (5+1)+2 = 6+2 = 6+(1+1) = (6+1)+1 = 7+1 = 8. But this is too long to add numbers in such way. The problem is to develop program which can improve this way of addition using the rules of mathemetics and logic. The goal addition must executed in O(log(N)) time, not O(N) time, N is magnitude of added numbers. Have this program any science value? Is any program can do such things?

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  • Creating Java Dialogs

    - by mike_hornbeck
    What would be the easiest way for creating a dialog: - in one window I'm giving data for envelope addressing, also set font type from list of sizes - when clicked OK, in the same window or in next window I get preview of how the envelope would look like with the given names, and used selected font size It should look similarly to this : Should I use Jdialog ? Or will JOptionPane will be enough ? The next step will be to choose color of font and background so I must keep that in mind.

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  • What is wrong with the below statement(C#3.0 / Lambda)

    - by Newbie
    what is wrong in the below Enumerable.Range(0, objEntityCode.Count - 1).Select(i => { options.Attributes[i] = new EntityCodeKey { EntityCode = objEntityCode[i].EntityCodes , OrganizationCode = Constants.ORGANIZATION_CODE }; }) .ToArray(); Throwing error The type arguments for method 'System.Linq.Enumerable.Select(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly. But this works Enumerable.Range(0, objEntityCode.Count - 1).ToList().ForEach(i => { options.Attributes[i] = new EntityCodeKey { EntityCode = objEntityCode[i].EntityCodes , OrganizationCode = Constants.ORGANIZATION_CODE }; } ); Using C#3.0. Purpose: I am learning LINQ / LAMBDA and trying to do the same program in different way. Thanks.

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  • SQL query to get lowest 2 values of a counted query selection (using db2)?

    - by jNoob
    Hi, Imagine I already have a query that returns the following: Col1 | Col2 ------------ A | 2 B | 3 C | 3 D | 4 E | 8 ... Say I used something like this: select Col1, count ( * ) as Col2 \ from ... where ... order by Col2 \ group by Col1 \ So now, all I want to select are (Col1, Col2) such that it returns the selections (a, b) and (c, d) where (b >= all (Col2)) and (d >= ((all (Col2)) - a)). So for the above example, it would return {(A, 2), (B, 3), (C, 3)}. How do I go about doing this? Any help would be highly appreciated. Thanks.

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  • Good JDBC pattern

    - by Java Developer
    What is the good practice for database operation in Java application? Do you construct the DML syntax in the Java code and send the statements to DB engine for execution, or you just collect the parameters and then make a call to stored procedure with the parameters via java code? or neither because that's just not how to do it? can anyone give an example of a full database utility classes to do database operations in Java app? also what about the transaction manager? My assignment is to make database operation that is modular in Java. Thanks

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  • C# print 2D-array in order. Please help!

    - by user339067
    Hello, I got a 2-dimentional array containing boolean values written in C#. The cols and rows of the array are to be determined by the user upon creation of the array. I then want to print out the array and it´s containing values onto the console in order. For example like this, how is this done in C#? ROWS - COLS - VALUE 1 - A - True 1 - B - True 1 - C - True 1 - D - True 2 - A - True 2 - B - False 2 - C - False 2 - D - True

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