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  • Which one of the following is NOT a pitfall of inheritance?

    - by Difficult PEOPLE
    Which one of the following is NOT a pitfall of inheritance? Base-derive classes should be totally separate and do not have an is-a relationship. Base-derive classes should have been aggregate classes instead. Inheritance may be inverted, example: Truck<-Vehicle should be Vehicle<-Truck. Incompatible class hierarchies may be connected because of multiple inheritance. Aggregation should have been used instead. Functionality is transferred from a base class to a derived one. In my opinion, NOT a pitfall of inheritance meas can use inheritance. 1 seems do without inheritance 2 aggregate substitute Base-derive I don't know So, I think 5 is the answer.

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  • What is the answer to this homework about maps and collections? [closed]

    - by Bishan
    Maps collection is referred to an dictionary because of the way it works. Each entry into a maps collection involves a pair of objects. In a maps collection, an object associates the key which determines where the object is stored in the map. The key object in the maps collection can be duplicated. A stack which has Last In First Out storage mechanism can be considered as a maps collection. I think #1,#2,#3 and #5 are Correct in above, but I have doubt with #5. Am I correct?

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  • (This is for a project, so yes it is homework) How would I finish this java code?

    - by user2924318
    The task is to create arrays using user input (which I was able to do), then for the second part, use a separate method to sort the array in ascending order then output it. I have gotten it to do everything I need except I don't know how I would get it to sort. The directions say to use a while loop from 0 to the length to find the minimum value then swap that with the 1st, but I don't know how to do this. This is what I have so far: public static void main(String[] args) { Scanner in = new Scanner(System.in); int storage = getNumDigits(in); if(storage == 0){ System.out.print("No digits to store? OK, goodbye!"); System.exit(0); } int []a = new int [storage]; a = getDigits(a, in); displayDigits(a); selectionSort(a); } private static int getNumDigits(Scanner inScanner) { System.out.print("Please enter the number of digits to be stored: "); int stored = inScanner.nextInt(); while(stored < 0){ System.out.println("ERROR! You must enter a non-negative number of digits!"); System.out.println(); System.out.print("Please enter the number of digits to be stored: "); stored = inScanner.nextInt(); } return stored; } private static int[] getDigits(int[] digits, Scanner inScanner) { int length = digits.length; int count = 0; int toBeStored = 0; while(count < length){ System.out.print("Enter integer " +count +": "); toBeStored = inScanner.nextInt(); digits[count] = toBeStored; count++; } return digits; } private static void displayDigits(int[] digits) { int len = digits.length; System.out.println(); System.out.println("Array before sorting:"); System.out.println("Number of digits in array: " +len); System.out.print("Digits in array: "); for(int cnt = 0; cnt < len-1; cnt++){ System.out.print(digits[cnt] + ", "); } System.out.println(digits[len-1]); } private static void selectionSort(int[] digits) { int l = digits.length; System.out.println(); System.out.println("Array after sorting:"); System.out.println("Number of digits in array: " +l); System.out.print("Digits in array: "); int index = 0; int value = digits[0]; int indVal = digits[index]; while(index < l){ indVal = digits[index]; if(indVal <= value){ indVal = value; digits[index] = value; index++; } else if(value < indVal){ index++; } System.out.print(value); //This is where I don't know what to do. } }

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  • list in loop, Nonetype errors

    - by user2926755
    Here is my Code def printList(stringlist): empty = [] if stringlist is None: print empty else: print stringlist def add (stringlist, string): string = [] if string is None else string if stringlist is not None: stringlist.insert(0, string) else: stringlist.append(1) it somehow appears "AttributeError: 'NoneType' object has no attribute 'append'" I was originally looking for the code to be run like this: >>> myList = None >>> printList(myList) [] >>> for word in ['laundry','homework','cooking','cleaning']: myList = add(myList, word) printList(myList) [laundry] [homework, laundry] [cooking, homework, laundry] [cleaning, cooking, homework, laundry]

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  • Accelerated C++, problem 5-6 (copying values from inside a vector to the front)

    - by Darel
    Hello, I'm working through the exercises in Accelerated C++ and I'm stuck on question 5-6. Here's the problem description: (somewhat abbreviated, I've removed extraneous info.) 5-6. Write the extract_fails function so that it copies the records for the passing students to the beginning of students, and then uses the resize function to remove the extra elements from the end of students. (students is a vector of student structures. student structures contain an individual student's name and grades.) More specifically, I'm having trouble getting the vector.insert function to properly copy the passing student structures to the start of the vector students. Here's the extract_fails function as I have it so far (note it doesn't resize the vector yet, as directed by the problem description; that should be trivial once I get past my current issue.) // Extract the students who failed from the "students" vector. void extract_fails(vector<Student_info>& students) { typedef vector<Student_info>::size_type str_sz; typedef vector<Student_info>::iterator iter; iter it = students.begin(); str_sz i = 0, count = 0; while (it != students.end()) { // fgrade tests wether or not the student failed if (!fgrade(*it)) { // if student passed, copy to front of vector students.insert(students.begin(), it, it); // tracks of the number of passing students(so we can properly resize the array) count++; } cout << it->name << endl; // output to verify that each student is iterated to it++; } } The code compiles and runs, but the students vector isn't adding any student structures to its front. My program's output displays that the students vector is unchanged. Here's my complete source code, followed by a sample input file (I redirect input from the console by typing " < grades" after the compiled program name at the command prompt.) #include <iostream> #include <string> #include <algorithm> // to get the declaration of `sort' #include <stdexcept> // to get the declaration of `domain_error' #include <vector> // to get the declaration of `vector' //driver program for grade partitioning examples using std::cin; using std::cout; using std::endl; using std::string; using std::domain_error; using std::sort; using std::vector; using std::max; using std::istream; struct Student_info { std::string name; double midterm, final; std::vector<double> homework; }; bool compare(const Student_info&, const Student_info&); std::istream& read(std::istream&, Student_info&); std::istream& read_hw(std::istream&, std::vector<double>&); double median(std::vector<double>); double grade(double, double, double); double grade(double, double, const std::vector<double>&); double grade(const Student_info&); bool fgrade(const Student_info&); void extract_fails(vector<Student_info>& v); int main() { vector<Student_info> vs; Student_info s; string::size_type maxlen = 0; while (read(cin, s)) { maxlen = max(maxlen, s.name.size()); vs.push_back(s); } sort(vs.begin(), vs.end(), compare); extract_fails(vs); // display the new, modified vector - it should be larger than // the input vector, due to some student structures being // added to the front of the vector. cout << "count: " << vs.size() << endl << endl; vector<Student_info>::iterator it = vs.begin(); while (it != vs.end()) cout << it++->name << endl; return 0; } // Extract the students who failed from the "students" vector. void extract_fails(vector<Student_info>& students) { typedef vector<Student_info>::size_type str_sz; typedef vector<Student_info>::iterator iter; iter it = students.begin(); str_sz i = 0, count = 0; while (it != students.end()) { // fgrade tests wether or not the student failed if (!fgrade(*it)) { // if student passed, copy to front of vector students.insert(students.begin(), it, it); // tracks of the number of passing students(so we can properly resize the array) count++; } cout << it->name << endl; // output to verify that each student is iterated to it++; } } bool compare(const Student_info& x, const Student_info& y) { return x.name < y.name; } istream& read(istream& is, Student_info& s) { // read and store the student's name and midterm and final exam grades is >> s.name >> s.midterm >> s.final; read_hw(is, s.homework); // read and store all the student's homework grades return is; } // read homework grades from an input stream into a `vector<double>' istream& read_hw(istream& in, vector<double>& hw) { if (in) { // get rid of previous contents hw.clear(); // read homework grades double x; while (in >> x) hw.push_back(x); // clear the stream so that input will work for the next student in.clear(); } return in; } // compute the median of a `vector<double>' // note that calling this function copies the entire argument `vector' double median(vector<double> vec) { typedef vector<double>::size_type vec_sz; vec_sz size = vec.size(); if (size == 0) throw domain_error("median of an empty vector"); sort(vec.begin(), vec.end()); vec_sz mid = size/2; return size % 2 == 0 ? (vec[mid] + vec[mid-1]) / 2 : vec[mid]; } // compute a student's overall grade from midterm and final exam grades and homework grade double grade(double midterm, double final, double homework) { return 0.2 * midterm + 0.4 * final + 0.4 * homework; } // compute a student's overall grade from midterm and final exam grades // and vector of homework grades. // this function does not copy its argument, because `median' does so for us. double grade(double midterm, double final, const vector<double>& hw) { if (hw.size() == 0) throw domain_error("student has done no homework"); return grade(midterm, final, median(hw)); } double grade(const Student_info& s) { return grade(s.midterm, s.final, s.homework); } // predicate to determine whether a student failed bool fgrade(const Student_info& s) { return grade(s) < 60; } Sample input file: Moo 100 100 100 100 100 100 100 100 Fail1 45 55 65 80 90 70 65 60 Moore 75 85 77 59 0 85 75 89 Norman 57 78 73 66 78 70 88 89 Olson 89 86 70 90 55 73 80 84 Peerson 47 70 82 73 50 87 73 71 Baker 67 72 73 40 0 78 55 70 Davis 77 70 82 65 70 77 83 81 Edwards 77 72 73 80 90 93 75 90 Fail2 55 55 65 50 55 60 65 60 Thanks to anyone who takes the time to look at this!

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  • CodePlex Daily Summary for Saturday, March 13, 2010

    CodePlex Daily Summary for Saturday, March 13, 2010New Projects[Experiment] vczh DBUI: EXPERIMENT. Auto UI adaptor for a specified data base[SAMPLE PROJECT] Branch and Patch with GIT: I'll paste more here later...BlogPress: This web application provides a content management system. Coot: Facebook Photos Screensaver.DotNetNuke® JDMenu: dnnJDMenu makes it easy to use the open source JDMenu component in your DotNetNuke skin.DotNetNuke® RadRotator: dnnRadRotator makes it easy to add telerik RadRotator functionality to your site or custom module. Licensing permits anyone to use the components ...DotNetNuke® RadTabStrip: DNNRadTabStrip makes it easy to add telerik RadTabStrip functionality to your module or skin. Licensing permits anyone to use the components (incl...DotNetNuke® RadTreeView: DNNRadTreeView makes it easy to add telerik RadTreeView functionality to your module or skin. Licensing permits anyone to use the components (incl...DotNetNuke® Skin Garden: A DotNetNuke Design Challenge skin package submitted to the "Out of the box" category by Mark Allan of DnnGarden. Concise and semantic HTML 5 stru...ElmasFC: Elmas Facebook CheckerFront Callback Protocol: Front Callback Protocol make it easier for developers to create a network application in the .Net Language. It provide the flexibility of using TCP...Glass UI: A Windows Forms Control Library built specifically for Aero Glass. This will consist of existing controls, modified to render on glass, as well as ...Guitarist Tools: Some tools for guitarists.HomeUX: HomeUX is home control software featuring a Silverlight-based touch screen user interface.Homework Helper: Homework Helper help students to train simpler homework like "What's the name of the capital of France?" - Question - Answear based. It's made i...IGNOU Mini Project Allocation: A mini project allocation system.Images Compiler: Images Compiler is pretty small wpf application for users who want to resize, rename, disable colors... for too much images in very short time. It...InstitutionManagementSystem: Institution Management System prototypeManagedCv: ManagedCv is the library for C#/VB/ to use the OpenCV librarymanagement joint ownership: Application pour la gestion des actions réalisées au sein d’une copropriété. Application for management actions within a joint ownershipMapWindow6: MapWindow 6.0 is an open source geographic information system (GIS) and library of geospatial software development tools for .NET, written in C#. T...Morris Auto: Morris Auto is a social application build templateMouse control with finger detection: The aim of this project is to design an application for recognition of the movement of a finger through a webcam and then control the mouse. The pr...ORAYLIS BI.Quality: ORAYLIS BI.Quality makes it easier to develop BI Solutions in an agile environment. It adapts Unit Tests to BI Development. Propositional Framework: Different sales propositions are presented to the user using data collected from marketing intelligence, browser history or user behaviour as they ...ServStop: ServStop is a .NET application that makes it easy to stop several system services at once. Now you don't have to change startup types or stop them ...shatkotha web portal: source code of web portal shatkothaSurvey and Registration tools: Two Silverlight tools for add Survey and Registration in your websiteTable Storage Backup & Restore for Windows Azure: Allows various backup & restore options for Windows Azure Table Storage accounts: - Backup from one storage account to another - Backup a storag...Topsy Lib: This project provides wrapper methods to call Topsy's web services from C#.twNowplaying: twNowplaying is a small and handy utility that allows you to tweet your currently playing track from Spotify to Twitter. Followed by the #twNowplay...XOM: XOM: Xml Object Mapper Automatically populate your objects with data from XML via an XML map. Never do this again: if(e.GetElementsByTagName("us...YS Utils: The library contains set of useful classes which may solve common tasks for different applications.ZabViewer: CS ProjectNew ReleasesAppFabric Caching Admin Tool: AppFabric Caching Admin Tool (0.8): System Requirements:.NET 4.0 RC AppFabric Caching Beta2 Test On:Win 7 (64x)ASP.Net Routing Configuration: mal.Web.Routing v0.9.2.0: mal.Web.Routing v0.9.2.0DotNetNuke IM Module of Facebook Like Messenger: DNN IM Module of Facebook Like Messenger: Empower DNN Website with a 1-to-1 Chat Solution named Free Facebook Messenger Style Web Chat Bar of 123 Web Messenger. 1. If you need to use the c...DotNetNuke® Form and List (formerly User Defined Table): 05.01.02: Form and List 05.01.02 (Release Candidate 2)5.1.2 will be the next stabilzation release. Major Highlights fixed Cancel action in a form, it don't ...DotNetNuke® JDMenu: DNN jdMenu 1.0.0: dnnJDMenu makes it easy to use the open source JDMenu component in your DotNetNuke skin. Many thanks to Jonathan Sharp of Outwest Media for creati...DotNetNuke® RadTabStrip: DNNRadTabstrip 1.0.0: DNNRadTabStrip makes it easy to add telerik RadTabStrip functionality to your module or skin. Licensing permits anyone to use the components (inclu...DotNetNuke® RadTreeView: DNNRadTreeView 1.0.0: DNNRadTreeView makes it easy to create skins which use the Telerik RadTreeview functionality. Licensing permits anyone (including designers) to use...DotNetNuke® Skin Garden: Garden Package 1.0.0: A DotNetNuke Design Challenge skin package submitted to the "Out of the box" category by Mark Allan of DnnGarden. Concise and semantic HTML 5 struc...ElmasFC: Elmas FC: This porgram is checking your facebook account automaticly.Free DotNetNuke IM of 123 Web Messenger -- Web-based Friend List: Free Download DNN IM Module and Source Code: 123 Web Messenger offers free DotNetNuke Instant Messaging to help you embed a IM Software into DNN Website by integrating 123 Web Messenger with D...Free Silverlight & WPF Chart Control - Visifire: Visifire SL and WPF Charts 3.0.4 Released: Hi, Today we have released the final version of Visifire v3.0.4 which contains the following major features: * Zooming * Step Line chart ...Home Access Plus+: v3.1.0.0: Version 3.1.0.0 Release Problem with this release, get Version 3.1.1.1 Change Log: Fixed ampersand issue Added Unzip Features Added Help Desk ...Home Access Plus+: v3.1.1.1: Version 3.1.1.1 Release Change Log: Fixed the Help Desk File Changes: ~/App_Data/Tickets.xml ~/bin/CHS Extranet.dll ~/bin/CHS Extranet.pdbHomework Helper: Homework Helper 1.0: The first release of Homework Helper. It got basic functionality. Check the Documentation or press F1 while using the program.Homework Helper: Homework Helper v1.0: This is the latest version of Homework Helper. Just a few updates since the latest one (a couple of minutes ago). Now it saves your settings! Instr...IBCSharp: IBCSharp 1.02: What IBCSharp 1.02.zip unzips to: http://i39.tinypic.com/28hz8m1.png Note: The above solution has MSTest, Typemock Isolator, and Microsoft CHESS c...InfoService: InfoService v1.5 RC 1: InfoService Release Canidate Please note this is a RC. It should be stable, but i can't guarantee that! So use it on your own risk. Please read Pl...IntX: IntX 0.9.3.3: Fixed issue #7100IronRuby: 1.0 RC3: The IronRuby team is pleased to announce version 1.0 RC3! As IronRuby approaches the final 1.0, these RCs will contain crucial bug fixes and enhanc...MAISGestão: LayerDiagram (pdf): This is the final version of the layer diagramMapWindow6: MapWindow 6.0 msi (March 12): After some significant trouble with svn, this site represents a test of using Mercurial for our version control. Hopefully the choice of this new ...MSBuild Mercurial Tasks: 0.2.0 Beta: This release realises the Scenario 2 and provides two MSBuild tasks: HgCommit and HgPush. This task allows to create a new changeset in the current...NLog - Advanced .NET Logging: NLog 2.0 preview 1: This is very experimental first build of NLog from 2.0 branch is available for download. It’s not alpha, beta or even gamma, just a preview of upco...Open NFe: Fonte DANFE v1.9.5: Código-fonte para a versão 1.9.5 do DANFEOpiConsole (XNA): OpiConsole 0.3: OpiConsole 0.3 OpiConsole includes: * PC & Xbox support. * Default commands (cvar, quit etc.) * Ability to add custom commands. *...ORAYLIS BI.Quality: Release 1.0.0: Release 1.0.0Pcap.Net: Pcap.Net 0.5.0 (38141): Pcap.Net - March 2010 Release Pcap.Net is a .NET wrapper for WinPcap written in C++/CLI and C#. It Features almost all WinPcap features and include...PhysX.Net: PhysX.Net 0.12.0.0 Beta 1: This is beta release of 0.12.0.0 for people to test and provide feedback on. It targets 2.8.3.21 of PhysXPólya: Pólya 2010 03 13 alpha: Pólya is a collection of generic data structures; as generic as C#/.Net allows them to be. In this first release the focus has been on some fundam...Prolog.NET: Prolog.NET 1.0 Beta 1.3: Installer includes: primary Prolog.NET assembly Prolog.NET Workbench Prolog.NET Scheduler sample application PrologTest console applicatio...Propositional Framework: USP: The initial code drop was based on the Autocomplete demo and the neural network approach used by Jeff Heaton (@ http://www.heatonresearch.com/) - e...Protocol Transition with BizTalk: Source: Stable buildRoTwee: RoTwee (7.1.0.0): Now picture of your friend is shown in RoTwee. Place mouse cursor to the tweet !ServStop: 0.5.0.0: Initial Release Contents of ServStop0500.zip ServStop.exe 0.5.0.0 Initial Release. 32,768 bytes. Other files None. Source code available on "...SkeinLibManaged: Release 1.0.0.0 (Beta): This is the compiled DLL with XML documentation, so there should be plenty of context sensitive help and Intellisense. This is the Release version...sPWadmin: pwAdmin v0.9a: Added: LiveChat Plugin Shows the latest 150 chat messages from "/Your PW Server/logservice/logs/world2.chat" Refresh chat every 5 seconds Allow...sPWadmin: pwAdmin v0.9b: Some minor fixes to style, layout & different browser support Merged the forms in server configuration tab to a single form that can now save mul...Topsy Lib: Initial release: Initial Debug and Release versions.twNowplaying: twNowplaying: Press the Twitter icon to get started, don't forget to submit bugs to the issue tracker. What's new This release has some minor UI fixes.twNowplaying: twNowplaying Alpha 1.0: Press the Twitter icon to get started, don't forget to submit bugs to the issue tracker. Thank you , and enjoy! =)VCC: Latest build, v2.1.30312.0: Automatic drop of latest buildWPF Dialogs: Version 0.1.3: The FolderBrowseDialog / FolderBrowseDialog - Deutsch was improved and extended.XOM: XOM 0.1A: Just a release of the code I have so far. In order to get your objects to work, you need to create an XML file to define your objects. Here is a ...Xpress - ASP.NET MVC 个人博客程序: xpress2.1.1.0312.beta: 最新beta版，注意：此版本和2.1.0不兼容 更改内容： 将主题文件发放在 Views 文件夹下 主题文件支持强类型Model 主题资源文件放在Resouces目录下YS Utils: V 1.0.0.0: This is first release. The YSUtils library contains first set of classes. ZIP files contains documentation.Most Popular ProjectsMetaSharpWBFS ManagerRawrAJAX Control ToolkitMicrosoft SQL Server Product Samples: DatabaseSilverlight ToolkitWindows Presentation Foundation (WPF)ASP.NET Ajax LibraryASP.NETMicrosoft SQL Server Community & SamplesMost Active ProjectsRawrN2 CMSBlogEngine.NETFasterflect - A Fast and Simple Reflection APIpatterns & practices – Enterprise LibraryFarseer Physics EngineSharePoint Team-MailerCaliburn: An Application Framework for WPF and SilverlightCalcium: A modular application toolset leveraging PrismjQuery Library for SharePoint Web Services

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  • Why do some questions get closed for no reason? [closed]

    - by IVlad
    Recently there was a question asking about generating all subsets of a set using a stack and a queue, which was closed (and now deleted it seems) as not a real question for no good reason, since it didn't fit into any of these conditions: It's difficult to tell what is being asked here. No, it was clear what was being asked. This question is ambiguous, vague, incomplete, or rhetorical and cannot be reasonably answered in its current form. Not ambiguous, not vague, not incomplete, definitely not rhetorical and could easily be answered if one knew the solution. Now, the exact same thing has happened with this question: http://stackoverflow.com/questions/2791982/a-shortest-path-problem-with-superheroes-and-intergalactic-journeys/2793746#2793746 I am interested in hearing a logical argument for why that question is either ambiguous, vague, incomplete, rhetorical or cannot reasonably be answered in its current form. It seems that (the same bunch of) people like to close questions that they think are homework questions, especially when they think people want to be served the solution on a platter, which is also not the case: Any suggestions or ideas of how this problem might be solved would be most welcomed. Most of the time the people asking these questions are very reasonable and appreciate even the most vague idea, yet their question is closed. Let's go further and assume that it IS a homework problem. So what? When I registered here I didn't see any rule that said not to post homework problems, nor do I see such a rule now. What is wrong with posting homework problems that makes people hunt them down with a passion to close them without even reading the entire question body? This site is full of questions asked by people who get paid to know the things they are asking, yet their questions are considered fine. How is solving someone's homework problem worse? In some places (like where I live), computer science is a mandatory high school subject, and not everyone is interested in it. How is helping at least those people worse than doing someone's JOB? Not answering homework questions is fine and it's everyone's choice, but I consider closing them to be an act of power abuse, selfishness, and an insult to the fellow community members who are also interested in a solution or want feedback on their proposed solution. So my questions are: - Why do questions like the above get closed for reasons that do not apply? Why do you close them? Why don't you? - Why doesn't a vote to reopen a question reopen it automatically? Needing 5 votes for a reopen takes too long, and it's not fair because one reopen vote basically cancels out a close vote, making it 4 close votes (or 5 to 1, which is the same as only 4 people wanting to close the question), which isn't enough to close the question. I think a question should only be closed when CloseVotes - ReopenVotes >= 5. I'm hoping this will stay up, but I realize it probably won't. In either case, I think this is worth saying and discussing, since it IS community-related.

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  • DataGridTemplateColumn for individual control-column vs DataGridTextColumn

    - by msfanboy
    Hello, what is the difference, both works: DataGridTemplateColumn versus DataGridTextColumn <DataGridTemplateColumn Header="Homework"> <DataGridTemplateColumn.CellTemplate> <DataTemplate> <RichTextBox > <FlowDocument> <Paragraph> <Run Text="{Binding Homework}"/> </Paragraph> </FlowDocument> </RichTextBox> </DataTemplate> </DataGridTemplateColumn.CellTemplate> </DataGridTemplateColumn> <DataGridTextColumn Header="Homework"> <DataGridTextColumn.CellTemplate> <DataTemplate> <RichTextBox > <FlowDocument> <Paragraph> <Run Text="{Binding Homework}"/> </Paragraph> </FlowDocument> </RichTextBox> </DataTemplate> </DataGridTextColumn.CellTemplate> </DataGridTextColumn >

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  • Vimrc: how to reuse code and definitions for differnt file types?

    - by sixtyfootersdude
    I have defined my own file types using vim. For example I have: .classNotes .reportJotNotes .homework These file types are defined in .vim files: ~/.vim/syntax/homework.vim ~/.vim/syntax/reportJotNotes.vim ~/.vim/syntax/homework.vim Many of these things have several of the same code in them. Ie they all have this for titles: syn region JakeTitle start=+=== + end=+===+ oneline highlight JakeTitle ctermbg=black ctermfg=Yellow syn region JakeMasterTitle start=+==== + end=+====+ oneline highlight JakeMasterTitle cterm=bold term=bold ctermbg=black ctermfg=LightBlue Instead of having this in all three .vim files I would rather have it in one file and then in each file could source it. How can I do this?

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  • "Index of ..." directory's files listing

    - by Tony
    On my courses we've got homework on site in folders such as: http://example.com/files/tasks1-edc34rtgfds http://example.com/files/tasks2-0bg454fgerg http://example.com/files/tasks3-h1dlkjiojo8 ... Each tasksi-xxxxxxxxxxx is a folder with 11 random characters at the end. And when you view the above URLs in browser you can see Index of /tasksi-xxxxxxxxx with all the files in that folder. When you view http://example.com/files/ you can see only empty html with words "Hello, world". The problem is that you can't look into the next task without knowledge of its URL. So for example we've got the URLs for tasks1 and tasks2, and we can't guess what tasks3 URL will be (as we need to know the 11 random characters at the end) How can I get the list of all directories? (Is there a way to type something like http://example.com/files/task1-aflafjal343/..? or another way?) I want to see all upcoming homework tasks.

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  • hi question about mathematics

    - by davit-datuashvili
    hi i have one question i know site mathoverflow.com and have posted question but unfortunately no one give me answer if i post here can anybody help me? it is not homework because i know somebody will say it is homework what u have tried but this is not so i dont know how solve please if it is possible i will post here ok?

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  • Looking for advice on how to do some bit-twiddling [closed]

    - by davit-datuashvili
    hi everybody fisrt of all this is not homework and now question is like this suppose i have array int a[]=new int[]{0xBCDA,0xABFE,0xBCAD,0xEFCA,0xFFCA} i know that there is always some hexadecimal number which occurs in all number or in this case A is repeat in array everywhere so my aim is print only repeat number and other numbers should be zero so my new array should be like this 0x000A, 0xA000,0x00A0 0x000A,0x000A any idea please help me? p.s please nobody say that this is homework

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  • question about heapsearch order

    - by davit-datuashvili
    ia have meet following problem suppose we have sorted array of size 2^k-1 where k is given number we should copy this array into heapsearch array b the elements in odd positions of a go in order into last half of the positions of b positions congruent to 2 modul0 4 go into b's secodn quarter and so on this is not homework and please nobody tag it as homework it is from programming pearls please any ideas

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  • please help me to solve problem

    - by davit-datuashvili
    hi everybody fisrt of all this is not homework and now question is like this suppose i have array int a[]=new int[]{0xBCDA,0xABFE,0xBCAD,0xEFCA,0xFFCA} i know that there is always some hexadecimal number which occurs in all number or in this case A is repeat in array everywhere so my aim is print only repeat number and other numbers should be zero so my new array should be like this 0x000A, 0xA000,0x00A0 0x000A,0x000A any idea please help me? p.s please nobody say that this is homework

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  • Trying to run my code and compiler seems to just close after it executes [migrated]

    - by Shane
    I am trying to run a program and the compiler seems to just crash right after it executes ... i have no build errors so i am wondering what the hell is going on ... I am a bit of a novice so all help would be appreciated =). I don't know if you might have time to scan through the code but this is what i have got : using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace ConsoleApplication1 { public class Student { string Fname, Lname, Program ; int Sid ; // Inputting information for students public void InputStudentInfo () { Console.WriteLine ("Please enter your first name") ; Fname = Console.ReadLine() ; Console.WriteLine ("Please enter you last name") ; Lname = Console.ReadLine() ; Console.WriteLine ("Please enter you student ID#") ; Sid = int.Parse(Console.ReadLine()) ; Console.WriteLine ("Enter the Program that you are completeing") ; Program = Console.ReadLine() ; } // Printing information for students public void PrintStudentInfo () { Console.Write (" Your name is " + Fname) ; Console.Write(" " + Lname); Console.WriteLine (" Your student identification number is " + Sid) ; Console.WriteLine (" The program you are registered for is " + Program) ; } /* public void MenuInterface() { Console.WriteLine (" 1. Input Student information" ) ; Console.WriteLine (" 2. Input Course information" ) ; Console.WriteLine (" 3. Input Grade information" ) ; Console.WriteLine (" 4. Print Course information" ) ; Console.WriteLine (" 5. Print Student information" ) ; Console.WriteLine (" 6. Print Grade information" ) ; Console.WriteLine (" 7. Print Student information including Course they are registered in and the grade obtained for that course" ) ; Console.WriteLine (" 8. Print grade info of the course in which student has achieved the highest grade" ) ; Console.WriteLine (" 0. Exit") ; Console.WriteLine (" Please select a choice from 0-8") ; accode = Console.ReadLine(); } */ } public class Course { string course1, course2, course3 ; int Stuid ; // Inputting Course Information public void InputCourseInfo () { Console.WriteLine (" Please re-enter your identification number") ; Stuid = int.Parse(Console.ReadLine()) ; Console.WriteLine (" Enter the name of your first course") ; course1 = Console.ReadLine() ; Console.WriteLine (" Enter the name of your second course") ; course2 = Console.ReadLine() ; Console.WriteLine (" Enter the name of your third course") ; course3 = Console.ReadLine() ; } // Printing Course Information public void PrintCourseInfo () { Console.WriteLine (" Your ID # is " + Stuid) ; Console.Write (" The Courses you selected are " + course1) ; Console.Write("," + course2); Console.Write(" and " + course3); } } public class Grade : Course { int Studentid ; int [] hwgrade ; int [] cwgrade ; int [] midegrade ; int [] finalegrade ; int [] totalgrade ; string coursename ; public Grade ( string cname , int Studentident , int [] homework , int [] classwork , int [] midexam , int [] finalexam) { coursename = cname ; Studentid = Studentident ; hwgrade = homework ; cwgrade = classwork ; midegrade = midexam ; finalegrade = finalexam ; } public string coname { get { return coursename ; } set { coursename = value ; } } public int Studentidenty { get { return Studentid ; } set { Studentid = value ; } } public void InputGradeInfo() { Console.WriteLine (" Please enter your Student ID" ) ; grade.Studentidenty = Console.ReadLine() ; for ( int i = 0; i < 3; i++) { Console.Writeline (" Please enter the Course name" ) ; grade.coname[i] = Console.Readline() ; Console.Writeline (" Please enter your homework grade") ; grade.hwgrade[i] = int.parse(Console.Readline()) ; // ..... } } public void CalcTotalGrade() { for (int i = 0; i < 3; i++) { grade.courseper[i] = (grade.hwgrade[i] + grade.cwgrade[i]) / 2; grade.finalper[i] = (grade.midexam[i] + grade.finalegrade[i]) / 2; grade.totalgrade[i] = (grade.courseper[i] + finalper[i]) / 2; } } public void PrintGradeInfo() { for ( int i = 0; i < 3; i++) { Console.Writeline (" Your homework grade is" + grade.hwgrade[i]) ; // ..... } } static void Main(string[] args) { int accode ; Student student = new Student() ; Course course = new Course() ; Grade grade = new Grade() ; do { Console.WriteLine(" 1. Input Student information"); Console.WriteLine(" 2. Input Course information"); Console.WriteLine(" 3. Input Grade information"); Console.WriteLine(" 4. Print Course information"); Console.WriteLine(" 5. Print Student information"); Console.WriteLine(" 6. Print Grade information"); Console.WriteLine(" 7. Print Student information including Course they are registered in and the grade obtained for that course"); Console.WriteLine(" 8. Print grade info of the course in which student has achieved the highest grade"); Console.WriteLine(" 0. Exit"); Console.WriteLine(" Please select a choice from 0-8"); accode = Console.ReadLine(); switch (accode) { case 1: student.InputStudentInfo(); break; case 2: course.InputCourseInfo(); break; case 3: grade.InputGradeInfo(); break; case 4: course.PrintCourseInfo(); break; case 5: student.PRintStudentInfo(); break; case 6: grade.PrintGradeInfo(); break; case 0: Console.WriteLine(" You have chosen to exit the program have a good day. =)"); break; } } while (accode != 0); Console.ReadKey(); } } }

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  • Algorithm to use for shop floor layout?

    - by jkohlhepp
    I ran into a classroom problem yesterday (business oriented class, not computer science) and I found it interesting from an algorithmic perspective. The problem goes something like this: Assume there is a shop floor with N different rooms, and you have N different departments that need to go in those rooms. The departments and the rooms are all the same size, so any department could go in any room. There is a known travel distance from each room to each other room. There is also a known amount of trips necessary from one department to another (trips are counted the same regardless which room they originate from, so a trip from A to B is equivalent to a trip from B to A). Given those inputs, determine a layout of departments into rooms which minimizes travel time. What is the best way to approach this problem algorithmically? Is there already a particular algorithm or class of algorithms designed to solve this type of problem? Does this type of problem have a name in computer science? I am not looking for you to design an algorithm to solve this, although feel free to do so if you would like. I'm wondering if this is a problem space that has already been well defined and studied algorithmically and if so get some links to research further. I can see a lot of different data structures and algorithms that might apply to this and I'm curious which approach would be "best". And don't worry, you are not doing my homework for me. This is not a homework problem per se, as this is a business course and we were simply discussing the concepts and not trying to solve the problem algorithmically.

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  • SSAS Maestro Training in July 2012 #ssasmaestro #ssas

    - by Marco Russo (SQLBI)
    A few hours ago Chris Webb blogged about SSAS Maestro and I’d like to propagate the news, adding also some background info. SSAS Maestro is the premier certification on Analysis Services that selects the best experts in Analysis Services around the world. In 2011 Microsoft organized two rounds of training/exams for SSAS Maestros and up to now only 11 people from the first wave have been announced – around 10% of attendees of the course! In the next few days the new Maestros from the second round should be announced and this long process is caused by many factors that I’m going to explain. First, the course is just a step in the process. Before the course you receive a list of topics to study, including the slides of the course. During the course, students receive a lot of information that might not have been included in the slides and the best part of the course is class interaction. Students are expected to bring their experience to the table and comparing case studies, experiences and having long debates is an important part of the learning process. And it is also a part of the evaluation: good questions might be also more important than good answers! Finally, after the course, students have their homework and this may require one or two months to be completed. After that, a long (very long) evaluation process begins, taking into account homework, labs, participation… And for this reason the final evaluation may arrive months later after the course. We are going to improve and shorten this process with the next courses. The first wave of SSAS Maestro had been made by invitation only and now the program is opening, requiring a fee to participate in order to cover the cost of preparation, training and exam. The number of attendees will be limited and candidates will have to send their CV in order to be admitted to the course. Only experienced Analysis Services developers will be able to participate to this challenging program. So why you should do that? Well, only 10% of students passed the exam until now. So if you need 100% guarantee to pass the exam, you need to study a lot, before, during and after the course. But the course by itself is a precious opportunity to share experience, create networking and learn mission-critical enterprise-level best practices that it’s hard to find written on books. Oh, well, many existing white papers are a required reading *before* the course! The course is now 5 days long, and every day can be *very* long. We’ll have lectures and discussions in the morning and labs in the afternoon/evening. Plus some more lectures in one or two afternoons. A heavy part of the course is about performance optimization, capacity planning, monitoring. This edition will introduce also Tabular models, and don’t expect something you might find in the SSAS Tabular Workshop – only performance, scalability monitoring and optimization will be covered, knowing Analysis Services is a requirement just to be accepted! I and Chris Webb will be the teachers for this edition. The course is expensive. Applying for SSAS Maestro will cost around 7000€ plus taxes (reduced to 5000€ for students of a previous SSAS Maestro edition). And you will be locked in a training room for the large part of the week. So why you should do that? Well, as I said, this is a challenging course. You will not find the time to check your email – the content is just too much interesting to think you can be distracted by something else. Another good reason is that this course will take place in Italy. Well, the course will take place in the brand new Microsoft Innovation Campus, but in general we’ll be able to provide you hints to get great food and, if you are willing to attach one week-end to your trip, there are plenty of places to visit (and I’m not talking about the classic Rome-Florence-Venice) – you might really need to relax after such a week! Finally, the marking process after the course will be faster – we’d like to complete the evaluation within three months after the course, considering that 1-2 months might be required to complete the homework. If at this point you are not scared: registration will open in mid-April, but you can already write to [email protected] sending your CV/resume and a short description of your level of SSAS knowledge and experience. The selection process will start early and you may want to put your admission form on top of the FIFO queue!

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  • PanelGridLayout - A Layout Revolution

    - by Duncan Mills
    With the most recent 11.1.2 patchset (11.1.2.3) there has been a lot of excitement around ADF Essentials (and rightly so), however, in all the fuss I didn't want an even more significant change to get missed - yes you read that correctly, a more significant change! I'm talking about the new panelGridLayout component, I can confidently say that this one of the most revolutionary components that we've introduced in 11g, even though it sounds rather boring. To be totally accurate, panelGrid was introduced in 11.1.2.2 but without any presence in the component palette or other design time support, so it was largely missed unless you read the release notes. However in this latest patchset it's finally front and center. Its time to explore - we (really) need to talk about layout.  Let's face it,with ADF Faces rich client, layout is a rather arcane pursuit, once you are a layout master, all bow before you, but it's more of an art than a science, and it is often, in fact, way too difficult to achieve what should (apparently) be a pretty simple. Here's a great example, it's a homework assignment I set for folks I'm teaching this stuff to:  The requirements for this layout are: The header is 80px high, the footer is 30px. These are both fixed.  The first section of the header containing the logo is 180px wide The logo is centered within the top left hand corner of the header  The title text is start aligned in the center zone of the header and will wrap if the browser window is narrowed. It should be aligned in the center of the vertical space  The about link is anchored to the right hand side of the browser with a 20px gap and again is center aligned vertically. It will move as the browser window is reduced in width. The footer has a right aligned copyright statement, again middle aligned within a 30px high footer region and with a 20px buffer to the right hand edge. It will move as the browser window is reduced in width. All remaining space is given to a central zone, which, in this case contains a panelSplitter. Expect that at some point in time you'll need a separate messages line in the center of the footer.  In the homework assigment I set I also stipulate that no inlineStyles can be used to control alignment or margins and no use of other taglibs (e.g. JSF HTML or Trinidad HTML). So, if we take this purist approach, that basic page layout (in my stock solution) requires 3 panelStretchLayouts, 5 panelGroupLayouts and 4 spacers - not including the spacer I use for the logo and the contents of the central zone splitter - phew! The point is that even a seemingly simple layout needs a bit of thinking about, particulatly when you consider strechting and browser re-size behavior. In fact, this little sample actually teaches you much of what you need to know to become vaguely competant at layouts in the framework. The underlying result of "the way things are" is that most of us reach for panelStretchLayout before even finishing the first sip of coffee as we embark on a new page design. In fact most pages you will see in any moderately complex ADF page will basically be nested panelStretchLayouts and panelGroupLayouts, sometimes many, many levels deep. So this is a problem, we've known this for some time and now we have a good solution. (I should point out that the oft-used Trinidad trh tags are not a particularly good solution as you're tie-ing yourself to an HTML table based layout in that case with a host of attendent issues in resize and bi-di behavior, but I digress.) So, tadaaa, I give to you panelGridLayout. PanelGrid, as the name suggests takes a grid like (dare I say slightly gridbag-like) approach to layout, dividing your layout into rows and colums with margins, sizing, stretch behaviour, colspans and rowspans all rolled in, all without the use of inlineStyle. As such, it provides for a much more powerful and consise way of defining a layout such as the one above that is actually simpler and much more logical to design. The basic building blocks are the panelGridLayout itself, gridRow and gridCell. Your content sits inside the cells inside the rows, all helpfully allowing both streching, valign and halign definitions without the need to nest further panelGroupLayouts. So much simpler!  If I break down the homework example above my nested comglomorate of 12 containers and spacers can be condensed down into a single panelGrid with 3 rows and 5 cell definitions (39 lines of source reduced to 24 in the case of the sample). What's more, the actual runtime representation in the browser DOM is much, much simpler, and clean, with basically one DIV per cell (Note that just because the panelGridLayout semantics looks like an HTML table does not mean that it's rendered that way!) . Another hidden benefit is the runtime cost. Because we can use a single layout to achieve much more complex geometries the client side layout code inside the browser is having to work a lot less. This will be a real benefit if your application needs to run on lower powered clients such as netbooks or tablets. So, it's time, if you're on 11.1.2.2 or above, to smile warmly at your panelStretchLayouts, wrap the blanket around it's knees and wheel it off to the Sunset Retirement Home for a well deserved rest. There's a new kid on the block and it wants to be your friend. 

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  • Newbie Python programmer tangling with Lists.

    - by Sergio Tapia
    Here's what I've got so far: # A. match_ends # Given a list of strings, return the count of the number of # strings where the string length is 2 or more and the first # and last chars of the string are the same. # Note: python does not have a ++ operator, but += works. def match_ends(words): counter = 0 for word in words: if len(word) >= 2 and word[0] == word[-1]: counter += counter return counter # +++your code here+++ return I'm following the Google Python Class, so this isn't homework, but me just learning and improving myself; so please no negative comments about 'not doing my homework'. :P What do you guys think I'm doing wrong here? Here's the result: match_ends X got: 0 expected: 3 X got: 0 expected: 2 X got: 0 expected: 1 I'm really loving Python, so I just know that I'll get better at it. :)

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  • How to generate all variations with repetitions of a string?

    - by Svenstaro
    I want to generate all variations with repetitions of a string in C++ and I'd highly prefer a non-recursive algorithm. I've come up with a recursive algorithm in the past but due to the complexity (r^n) I'd like to see an iterative approach. I'm quite surprised that I wasn't able to find a solution to this problem anywhere on the web or on StackOverflow. I've come up with a Python script that does what I want as well: import itertools variations = itertools.product('ab', repeat=4) for variations in variations: variation_string = "" for letter in variations: variation_string += letter print variation_string Output: aaaa aaab aaba aabb abaa abab abba abbb baaa baab baba babb bbaa bbab bbba bbbb Ideally I'd like a C++ program that can produce the exact output, taking the exact same parameters. This is for learning purposes, it isn't homework. I wish my homework was like that.

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  • How to test if an array contains a pair of numbers whose product is odd?

    - by John
    How can I write a function that takes an array of integers and returns true if their exists a pair of numbers whose product is odd? What are the properties of odd integers? And of course, how do you write this function in Java? Also, maybe a short explanation of how you went about formulating an algorithm for the actual implementation. Yes, this is a function out of a textbook. No, this is not homework—I'm just trying to learn, so please no "do your own homework comments."

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  • Freeglut ( OpenGL ) in C

    - by user1832149
    I would like to ask for you a little help in my homework. I'm learning at an university of Debrecen, and I would like to be a programmer, but I'm stuck with this homework. It's a OpenGL project in C. (freeglut) The next task is about: Window to viewport transformation. Draw graphs of functions, as shown below. The individual views (viewport) defines four different rectangles. Functions look like this picture: one window in 4 piece, and one pice of one function. The functions, respectively: f(x)=x2 g(x)=x3 h(x)=sin(x) i(x)=cos(x) Heres a pic what I need to make: How would I approach such a task?

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  • Internet Protocol Suite: Transition Control Protocol (TCP) vs. User Datagram Protocol (UDP)

    How do we communicate over the Internet?  How is data transferred from one machine to another? These types of act ivies can only be done by using one of two Internet protocols currently. The collection of Internet Protocol consists of the Transition Control Protocol (TCP) and the User Datagram Protocol (UDP).  Both protocols are used to send data between two network end points, however they both have very distinct ways of transporting data from one endpoint to another. If transmission speed and reliability is the primary concern when trying to transfer data between two network endpoints then TCP is the proper choice. When a device attempts to send data to another endpoint using TCP it creates a direct connection between both devices until the transmission has completed. The direct connection between both devices ensures the reliability of the transmission due to the fact that no intermediate devices are needed to transfer the data. Due to the fact that both devices have to continuously poll the connection until transmission has completed increases the resources needed to perform the transmission. An example of this type of direct communication can be seen when a teacher tells a students to do their homework. The teacher is talking directly to the students in order to communicate that the homework needs to be done.  Students can then ask questions about the assignment to ensure that they have received the proper instructions for the assignment. UDP is a less resource intensive approach to sending data between to network endpoints. When a device uses UDP to send data across a network, the data is broken up and repackaged with the destination address. The sending device then releases the data packages to the network, but cannot ensure when or if the receiving device will actually get the data.  The sending device depends on other devices on the network to forward the data packages to the destination devices in order to complete the transmission. As you can tell this type of transmission is less resource intensive because not connection polling is needed,  but should not be used for transmitting data with speed or reliability requirements. This is due to the fact that the sending device can not ensure that the transmission is received.  An example of this type of communication can be seen when a teacher tells a student that they would like to speak with their parents. The teacher is relying on the student to complete the transmission to the parents, and the teacher has no guarantee that the student will actually inform the parents about the request. Both TCP and UPD are invaluable when attempting to send data across a network, but depending on the situation one protocol may be better than the other. Before deciding on which protocol to use an evaluation for transmission speed, reliability, latency, and overhead must be completed in order to define the best protocol for the situation.  

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  • Surface of Revolution with 3D surface

    - by user5584
    I have to use this function to get a Surface of Revolution (homework). newVertex = (oldVertex.y, someFunc1(oldVertex.x, oldVertex.y), someFunc2(oldVertex.x, oldVertex.y)); As far as I know (FIXME) Surface of Revolution means rotations of a (2D)curve around an axis in 3D. But this vertex computing gives a 3D plane (FIXME again :D), so rotation of this isn't obvious. Am I misunderstanding something?

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