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• PHP/SQL/Wordpress: Group a user list by alphabet

  - by rayne

  I want to create a (fairly big) Wordpress user index with the users categorized alphabetically, like this: A Amy Adam B Bernard Bianca and so on. I've created a custom Wordpress query which works fine for this, except for one problem: It also displays "empty" letters, letters where there aren't any users whose name begins with that letter. I'd be glad if you could help me fix this code so that it only displays the letter if there's actually a user with a name of that letter :) I've tried my luck by checking how many results there are for that letter, but somehow that's not working. (FYI, I use the user photo plugin and only want to show users in the list who have an approved picture, hence the stuff in the SQL query). <?php $alphabet = range('A', 'Z'); foreach ($alphabet as $letter) { $user_count = $wpdb->get_results("SELECT COUNT(*) FROM wp_users WHERE display_name LIKE '".$letter."%' ORDER BY display_name ASC"); if ($user_count > 0) { $user_row = $wpdb->get_results("SELECT wp_users.user_login, wp_users.display_name FROM wp_users, wp_usermeta WHERE wp_users.display_name LIKE '".$letter."%' AND wp_usermeta.meta_key = 'userphoto_approvalstatus' AND wp_usermeta.meta_value = '2' AND wp_usermeta.user_id = wp_users.ID ORDER BY wp_users.display_name ASC"); echo '<li class="letter">'.$letter.''; echo '<ul>'; foreach ($user_row as $user) { echo '<li><a href="/author/'.$user->user_login.'">'.$user->display_name.'</a></li>'; } echo '</ul></li>'; } } ?> Thanks in advance!

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• Could you help me write a proper query in rails for accessing the following information?

  - by aditi-syal

  @workname = [] @recos = [] @bas = [] if current_user.recommendations.size != 0 current_user.recommendations.each do |r| if r.work_type == 'J' @job = Job.find_by_id(r.work_id) @workname.push "#{@job.title} at #{@job.company.name}" else @qualification = Qualification.find_by_id(r.work_id) @workname.push "Student at #{@qualification.school_name}" end @recommender = User.find_by_id(r.recommender_id) if r.recommender_work_type == 'J' @job = Job.find_by_id(r.recommender_work_id) @recos.push "#{@recommender.first_name} #{@recommender.last_name}" @bas.push "#{r.basis.gsub("You","#{@job.title} at #{@job.company.name}")}" else @qualification = Qualification.find_by_id(r.recommender_work_id) @recos.push "#{@recommender.first_name} #{@recommender.last_name} as " @bas.push "#{r.basis.gsub("You","Student at #{@qualification.school_name}")}" end end end

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• Architectural advice on connecting multiple diverse sites into a single community.

  - by Aleksandar

  Hi SO, I've been given a task to connect multiple sites of the same client into a single network. So i would like to hear an architectural advice on connecting these sites into a single community. These sites include: 1. Invision Power Board Forum (the most important site) 2. 3 custom made cms-s (changes to code allowable) 3. 1 drupal site 4. 3-4 wordpress blogs Requirements are as follows: 1. Connecting all users of all sites into a single administrable entity. With permissions changing ability, users banning etc. 2. Later on, based on this implementation I have to implement "facebook like" chat, which will be available to all users regardless of place of login. I have few ideas on my mind on how to go with this, but would like to hear some people with more experience and expertize than my self. Cheers!

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• Pagination links broken - php/jquery

  - by ClarkSKent

  Hey, I'm still trying to get my pagination links to load properly dynamically. But I can't seem to find a solution to this one problem. vote down star Hi everyone, I am still trying to figure out how to fix my pagination script to work properly. the problem I am having is when I click any of the pagination number links to go the next page, the new content does not load. literally nothing happens and when looking at the console in Firebug, nothing is sent or loaded. I have on the main page 3 links to filter the content and display it. When any of these links are clicked the results are loaded and displayed along with the associated pagination numbers for that specific content. I believe the problem is coming from the sql query in generate_pagination.php (seen below). When I hard code the sql category part it works, but is not dynamic at all. This is why I'm calling $ids=$_GET['ids']; and trying to put that into the category section but then the numbers don't display at all. If I echo out the $ids variable and click on a filter it does display the correct name/id, so I don't know why this doesn't work Here is the main page so you can see how I am including and starting the function(I'm new to php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="page'.$i.'">'.$i.'</li>'; } ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Here is the generate pagination where the problem seems to occur: <?php $ids=$_GET['ids']; include_once('config.php'); $per_page = 3; //Calculating no of pages $sql = "SELECT COUNT(*) FROM explore WHERE category='$ids'"; $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); ?> I thought I might as well post the jquery script if someone wants to see: $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = $(this).attr("id").replace("page",""); $("#content").load("pagination_data.php?page=" + pageNum, function(){ $(this).attr('data-page', pageNum); Hide_Load(); }); }); }); If any could assist me on solving this problem that would be great, thanks.

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• CodeIgniter Unable to Access Error Message Error

  - by 01010011

  Hi, I've created this registration form for registering new users to a website using CodeIgniter. My problem is, whenever I enter a username that already exists in my database, instead of giving me my error message which explains this to the user, it instead gives me this error message: Unable to access an error message corresponding to your field name Here are snippets of the code from my controller. Any assistance will be appreciated: function register() $this->load->library('form_validation'); $this->form_validation->set_rules('username', 'Username','trim|required|alpha_numeric|min_length[6]|xss_clean|strtolower|callback_username_not_exists); ... } function username_not_exists($username) { $this->form_validation->set_message('username','That %s already exists.'); if($this->User_model->check_exists_username($username)) { return false; } else { return true; }

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• executing perl code stored in a database?

  - by TheGNUGuy

  Hey everyone, Is it possible to save some perl code in a database then retrieve it using a select statement and then execute that perl code? I have tried using the eval() function but that doesn't seem to work. Here is what I'm trying right now and it doesn't seem to work: my $temp = $qryResults[0]; print $temp."\n"; eval{"$temp"}; the output is $con->Disconnect();exit; Thanks for the help!

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• Function for putting all database to an array

  - by jasmine

  I have written a function to print database to an array like this Array( ID=>1, PARENTID =>1, TITLE => LIPSUM, TEXT =>LIPSUM ) My function is: function dbToArray($db) { $allArrays =array(); $query = mysql_query("SELECT * FROM $db"); $dbRow = mysql_fetch_array($query); for ($i=0; $i<count($dbRow) ; $i++) { $allArrays[$i] = $dbRow; } $txt .='<pre>'; $txt .= print_r($allArrays); $txt .= '</pre>'; return $txt; } Anything wrong in my function. Any help is appreciated about my problem. Thanks in advance

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• T-SQL - Left Outer Joins - Filters in the where clause versus the on clause.

  - by Greg Potter

  I am trying to compare two tables to find rows in each table that is not in the other. Table 1 has a groupby column to create 2 sets of data within table one. groupby number ----------- ----------- 1 1 1 2 2 1 2 2 2 4 Table 2 has only one column. number ----------- 1 3 4 So Table 1 has the values 1,2,4 in group 2 and Table 2 has the values 1,3,4. I expect the following result when joining for Group 2: `Table 1 LEFT OUTER Join Table 2` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL `Table 2 LEFT OUTER Join Table 1` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 The only way I can get this to work is if I put a where clause for the first join: PRINT 'Table 1 LEFT OUTER Join Table 2, with WHERE clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL and a filter in the ON for the second: PRINT 'Table 2 LEFT OUTER Join Table 1, with ON clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Can anyone come up with a way of not using the filter in the on clause but in the where clause? The context of this is I have a staging area in a database and I want to identify new records and records that have been deleted. The groupby field is the equivalent of a batchid for an extract and I am comparing the latest extract in a temp table to a the batch from yesterday stored in a partioneds table, which also has all the previously extracted batches as well. Code to create table 1 and 2: create table table1 (number int, groupby int) create table table2 (number int) insert into table1 (number, groupby) values (1, 1) insert into table1 (number, groupby) values (2, 1) insert into table1 (number, groupby) values (1, 2) insert into table2 (number) values (1) insert into table1 (number, groupby) values (2, 2) insert into table2 (number) values (3) insert into table1 (number, groupby) values (4, 2) insert into table2 (number) values (4) EDIT: A bit more context - depending on where I put the filter I different results. As stated above the where clause gives me the correct result in one state and the ON in the other. I am looking for a consistent way of doing this. Where - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL On - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number AND table1.groupby = 2 --****************************** WHERE table2.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 1 1 NULL 2 2 NULL 1 2 NULL Where (table 2 this time) - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 On - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number --****************************** WHERE table1.number IS NULL AND table1.groupby = 2 Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- (0) rows returned

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• Place Query Results into Array then Implode?

  - by jason

  Basically I pull an Id from table1, use that id to find a site id in table2, then need to use the site ids in an array, implode, and query table3 for site names. I cannot implode the array correctly first I got an error, then used a while loop. With the while loop the output simply says: Array $mysqli = mysqli_connect("server", "login", "pass", "db"); $sql = "SELECT MarketID FROM marketdates WHERE Date = '2010-04-04 00:00:00' AND VenueID = '2'"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); $dates_id = mysqli_fetch_assoc ( $result ); $comma_separated = implode(",", $dates_id); echo $comma_separated; //This Returns 79, which is correct. $sql = "SELECT SIteID FROM bookings WHERE BSH_ID = '1' AND MarketID = '$comma_separated'"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); // This is where my problems start $SIteID = array(); while ($newArray = mysqli_fetch_array($result, MYSQLI_ASSOC)) { $SIteID[] = $newArray[SIteID]; } $locationList = implode(",",$SIteID); ?> Basically what I need to do is correctly move the query results to an array that I can implode and use in a 3rd query to pull names from table3.

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• how to evaluate query by DMBS?

  - by Kevinniceguy

  How do we evaluate the below database query by DBMS? the query is something like : SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo = CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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• jQuery / jqGrids / Submitting form data troubles...

  - by Kelso

  Ive been messing with jqgrids alot of the last couple days, and I have nearly everything the way I want it from the display, tabs with different grids, etc. Im wanting to make use of Modal for adding and editing elements on my grid. My problem that Im running into is this. I have my editurl:"editsu.php" set, if that file is renamed, on edit, i get a 404 in the modal.. great! However, with that file in place, nothing at all seems to happen. I even put a die("testing"); line at the top, so it sees the file, it just doesnt do anything with it. Below is the content. ........ the index page jQuery("#landings").jqGrid({ url:'server.php?tid=1', datatype: "json", colNames:['ID','Tower','Sector', 'Client', 'VLAN','IP','DLink','ULink','Service','Lines','Freq','Radio','Serial','Mac'], colModel:[ {name:'id', index:'id', width : 50, align: 'center', sortable:true,editable:true,editoptions:{size:10}}, {name:'tower', index:'tower', width : 85, align: 'center', sortable:true,editable:false,editoptions:{readonly:true,size:30}}, {name:'sector', index:'sector', width : 50, align: 'center',sortable:true,editable:true,editoptions:{readonly:true,size:20}}, {name:'customer',index:'customer', width : 175, align: 'left', editable:true,editoptions:{readonly:true,size:35}}, {name:'vlan', index:'vlan', width : 35, align: 'left',editable:true,editoptions:{size:10}}, {name:'suip', index:'suip', width : 65, align: 'left',editable:true,editoptions:{size:20}}, {name:'datadl',index:'datadl', width:55, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from datatypes"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'dataul', index:'dataul', width : 55, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from datatypes"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'servicetype', index:'servicetype', width : 85, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from servicetype"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'voicelines', index:'voicelines', width : 35, align: 'center',editable:true,editoptions:{size:30}}, {name:'freqname', index:'freqname', width : 35, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from freqband"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'radioname', index:'radioname', width : 120, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from radiotype"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'serial', index:'serial', width : 100, align: 'right',editable:true,editoptions:{size:20}}, {name:'mac', index:'mac', width : 120, align: 'right',editable:true,editoptions:{size:20}} ], rowNum:20, rowList:[30,50,70], pager: '#pagerl', sortname: 'sid', mtype: "GET", viewrecords: true, sortorder: "asc", altRows: true, caption:"Landings", editurl:"editsu.php", height:420 }); jQuery("#landings").jqGrid('navGrid','#pagerl',{edit:true,add:true,del:false,search:false},{height:400,reloadAfterSubmit:false},{height:400,reloadAfterSubmit:false},{reloadAfterSubmit:false},{}); now for the editsu.php file.. $operation = $_REQUEST['oper']; if ($operation == "edit") { qquery("UPDATE customers SET vlan = '".$_POST['vlan']."', datadl = '".$_POST['datadl']."', dataul = '".$_POST['dataul']."', servicetype = '".$_POST['servicetype']."', voicelines = '".$_POST['voicelines']."', freqname = '".$_POST['freqname']."', radioname = '".$_POST['radioname']."', serial = '".$_POST['serial']."', mac = '".$_POST['mac']."' WHERE id = '".$_POST['id']."'") or die(mysql_error()); } Im just having a hard time troubleshooting this to figure out where its getting hung up at. My next question after this would be to see if its possible to make it so when you click "add", that it auto inserts a row into the db with a couple variable predtermined and then bring up the modal window, but ill work on the first problem first. thanks!

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• Should you do validation checks that go outside the possiblility of normal user activity?

  - by Scarface

  Hey guys I have been thinking about form security a lot lately. I have been told time and time again to check if form input is a number if you are expecting a number or escape it in case (unless you use proper mysqli formatting) to avoid injection. 1.After the safety checks are done, should I do additional logic checks? For example, if the user is sending a friend request to them-self for example even if my user interface will not show the form if the user is looking at their own page.

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• Successful SQL Injection despite PHP Magic Quotes

  - by Crimson

  I have always read that Magic Quotes do not stop SQL Injections at all but I am not able to understand why not! As an example, let's say we have the following query: SELECT * FROM tablename WHERE email='$x'; Now, if the user input makes $x=' OR 1=1 --, the query would be: SELECT * FROM tablename WHERE email='\' OR 1=1 --'; The backslash will be added by Magic Quotes with no damage done whatsoever! Is there a way that I am not seeing where the user can bypass the Magic Quote insertions here?

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• Push different views from a table.

  - by Tanner

  Hello All, Ive been following a tutorial to implement a search bar ( http://www.iphonesdkarticles.com/2009/01/uitableview-searching-table-view.html ) However I cant seem to push different views. Here is what my didsSelectRowAtIndexPath looks like. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { NSString *selectedCountry = nil; if(searching) selectedCountry = [copyListOfItems objectAtIndex:indexPath.row]; else { NSDictionary *dictionary = [listOfItems objectAtIndex:indexPath.section]; NSArray *array = [dictionary objectForKey:@"Countries"]; selectedCountry = [array objectAtIndex:indexPath.row]; } //Initialize the detail view controller and display it. if ([[listOfItems objectAtIndex:indexPath.row] isEqual:@"neon"]){ Neon *abo = [[Neon alloc] initWithNibName:@"Neon" bundle:nil]; //dvController.selectedCountry = selectedCountry; [self.navigationController pushViewController:abo animated:YES]; [abo release]; } } And here is the debuger message when I click on neon: 2010-05-09 08:47:27.516 iTeachU[3821:307] * Terminating app due to uncaught exception 'NSRangeException', reason: ' -[NSMutableArray objectAtIndex:]: index 60 beyond bounds [0 .. 0]' ** Call stack at first throw: terminate called after throwing an instance of 'NSException' Program received signal: “SIGABRT”. If anyone has a way to push views based on the cells text it would be greatly appreciated. Thanks

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• excel import query error

  - by pmms

  mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $result=mysql_query("select * from jos_users INTO OUTFILE 'users.csv' FIELDS ESCAPED BY '""' TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\n' "); header("Content-type: text/plain"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Content-Transfer-Encoding: binary"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; in the above code in query string i.e string in side mysql_quey we are getting following error Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in C:\wamp\www\samples\mysql_excel\exel_outfile.php on line 8 in query string '\n' charter is not identifying as string thats why above error getting

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• Best practices to store CreditCard information into DataBase

  - by Garis Suero

  In my country the online payments are not an old thing, the first time i saw a web application taking payments directly to a local bank account was last year. So, Im a newbie coding web payment system. My question is, what are the best practices to store creditcard information into the database... I have many ideas: encrypting the creditcard, database security restriction, etc. What have you done?

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• Is it dangerous to keep an admin page to administer your database?

  - by Scarface

  Hey guys I have an admin page that checks if you are admin before submitting any queries, and contains a header to the index page if you are not admin, but I am worried about protecting the page. I am concerned someone may be able to destroy my database with it. Does anyone have any recommendation into protecting a page like this, if not, should I just manually admin my database through phpmyadmin and delete the page all together?

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• Sql query problem

  - by LiveEn

  I have the below sql query that will update the the values from a form to the database $sql="update leads set category='$Category',type='$stype',contactName='$ContactName',email='$Email',phone='$Phone',altphone='$PhoneAlt',mobile='$Mobile',fax='$Fax',address='$Address',city='$City',country='$Country',DateEdited='$today',printed='$Printed',remarks='$Remarks' where id='$id'"; $result=mysql_query($sql) or die(mysql_error()); echo '<h1>Successfully Updated!!.</h1>'; when i submit I dont get any errors and the success message is displayed but the database isnt updated . When i echo the $sql, all the values are set properly. and when i ech the $result i get the value 1. can someone please tell me what am i doing wrong here??

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• Compilation of latex file

  - by Tim

  Hi, I am compiling a latex file on a server and download from there the generated dvi, ps and pdf files to view them. The latex file by \includegraphics includes some figure files which are not on my local machine. I found that dvi file generated by latex command does not show the figures after dowloaded to my local, but ps file generated by dvips -Ppdf have the figures, and pdf file generated by either ps2pdf or pdflatex seem not have the figures again. Is it because the figures are not actually embeded as part of the dvi and pdf files by those compilation commands? How to actually embed figures so we can only export the document files to other machines? are the case for tables in separated tex files included into main tex file by /input and the case for style files included by \usepackage similar to the above case for figure files included by \includegraphics ? Thanks and regards!

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• php - disconnecting and connecting to multiple databases

  - by Phil Jackson

  Hi, I want to be able to switch from the current db to multiple dbs though a loop: $query = mysql_query("SELECT * FROM `linkedin` ORDER BY id", $CON ) or die( mysql_error() ); if( mysql_num_rows( $query ) != 0 ) { $last_update = time() / 60; while( $rows = mysql_fetch_array( $query ) ) { $contacts_db = "NNJN_" . $rows['email']; // switch to the contacts db mysql_select_db( $contacts_db, $CON ); $query = mysql_query("SELECT * FROM `linkedin` WHERE token = '" . TOKEN . "'", $CON ) or die( mysql_error() ); if( mysql_num_rows( $query ) != 0 ) { mysql_query("UPDATE `linkedin` SET last_update = '{$last_update}' WHERE token = '" . TOKEN . "'", $CON ) or die( mysql_error() ); }else{ mysql_query("INSERT INTO `linkedin` (email, token, username, online, away, last_update) VALUES ('" . EMAIL . "', '" . TOKEN . "', '" . USERNAME . "', 'true', 'false', '$last_update')", $CON ) or die( mysql_error() ); } } mysql_free_result( $query ); } // switch back to your own mysql_select_db( USER_DB, $CON ); It does insert and update details from the other databases but it also inserts and edits data from the current users database which I dont want. Any ideas?

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• Nested While Loop for mysql_fetch_array not working as I expected

  - by Ayush Saraf

  I m trying to make feed system for my website, in which i have got i data from the database using mysql_fetch_array system and created a while loop for mysql_fetch_array and inside tht loop i have repeated the same thing again another while loop, but the problem is that the nested while loop only execute once and dont repeat the rows.... here is the code i have used some function and OOP but u will get wht is the point! i thought of an alternative but not yet tried vaz i wanna the way out this way only i.e. using a for loopo insted of while loop that mite wrk... public function get_feeds_from_my_friends(){ global $Friends; global $User; $friend_list = $Friends->create_friend_list_ids(); $sql = "SELECT feeds.id, feeds.user_id, feeds.post, feeds.date FROM feeds WHERE feeds.user_id IN (". $friend_list. ") ORDER BY feeds.id DESC"; $result = mysql_query($sql); while ($rows = mysql_fetch_array($result)) { $id = $rows['user_id']; $dp = $User->user_detail_by_id($id, "dp"); $user_name = $User->full_name_by_id($id); $post_id = $rows['id']; $final_result = "<div class=\"sharedItem\">"; $final_result .= "<div class=\"item\">"; $final_result .= "<div class=\"imageHolder\"><img src=\"". $dp ."\" class=\"profilePicture\" /></div>"; $final_result .= "<div class=\"txtHolder\">"; $final_result .= "<div class=\"username\"> " . $user_name . "</div>"; $final_result .= "<div class=\"userfeed\"> " . $rows['post'] . "</div>"; $final_result .= "<div class=\"details\">" . $rows['date'] . "</div>"; $final_result .= "</div></div>"; $final_result .= $this->get_comments_for_feed($post_id); $final_result .= "</div>"; echo $final_result; } } public function get_comments_for_feed($feed_id){ global $User; $sql = "SELECT feeds.comments FROM feeds WHERE feeds.id = " . $feed_id . " LIMIT 1"; $result = mysql_query($sql); $result = mysql_fetch_array($result); $result = $result['comments']; $comment_list = get_array_string_from_feild($result); $sql = "SELECT comment_feed.user_id, comment_feed.comment, comment_feed.date FROM comment_feed "; $sql .= "WHERE comment_feed.id IN(" . $comment_list . ") ORDER BY comment_feed.date DESC"; $result = mysql_query($sql); if(empty($result)){ return "";} else { while ($rows = mysql_fetch_array($result)) { $id = $rows['user_id']; $dp = $User->user_detail_by_id($id, "dp"); $user_name = $User->full_name_by_id($id); return "<div class=\"comments\"><div class=\"imageHolder\"><img src=\"". $dp ."\" class=\"profilePicture\" /></div> <div class=\"txtHolder\"> <div class=\"username\"> " . $user_name . "</div> <div class=\"userfeed\"> " . $rows['comment'] . "</div> <div class=\"details\">" . $rows['date'] . "</div> </div></div>"; } } }

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• PDO and SQL IN statements

  - by Sai

  Im using a sequel for search like this using PDOs $states = "'SC','SD'"; $sql = "select * from mytable where states in (:states)"; $params = array(':states'=>$states); and I use my function $result = $this->selectArrayAssoc($sql, $params); where my selectArrayAssoc function as following public function selectArrayAssoc($sql, $params = array()){ try{ $sth = $this->db->prepare($sql); $sth->execute($params); $result = $sth->setFetchMode(PDO::FETCH_ASSOC); return $sth->fetchAll(); }catch(PDOException $e){ print $e->getMessage(); //Log this to a file later when in production exit; } } it does not take the quoted variables, I think it is suppressing, in such cases how to deal with this.

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• Non Working Relationship

  - by Dominik K.

  Hello everyone, I got a problem with cake's model architecture. I got a Users-Model and a Metas-Model. Here are the model codes: Users: <?php class User extends AppModel { var $name = 'User'; var $validate = array( 'username' => array('notempty'), 'email' => array('email'), 'password' => array('notempty') ); var $displayField = 'username'; var $hasMany = array( 'Meta' => array( 'className' => 'Meta', 'foreignKey' => 'user_id' ) ); } ?> and the Metas Model: <?php class Meta extends AppModel { var $name = 'Meta'; //The Associations below have been created with all possible keys, those that are not needed can be removed var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id', 'required' => true ) ); } ?> So now the question is why do I not get the Meta data into the User array? Should I get it in the Auth object? Or where can I work with the meta data? hope you can help me! Have a nice Day! Dom

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• Using Active Objects and BLOBs

  - by Andrew L.

  I am in a group of people who are creating a Defect Tracking program as a project. We have been using Active Objects and have run into some issues. Currently maximum file size for the blob is approx. 2Mb but we want to be able to increase it up to 2Gb. We currently have been looking at many sites and have not been able to find out how to increase the size. We are currently storing the blob as an array of bytes. Our current error says, Packet for Query is too large? We don't know how to set the variable, and we don't know how to set it using AO. We are programming this in Java, too. We are wondering if anyone has a solution to this problem. Thanks for the Help.

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• Use SQL Result to Query second time and grab more results via php

  - by maxwell

  I am grabbing a list of school names from a database. When the user clicks on the school name, i want the code to fetch 2-3 other attributes related to the school name that the user has clicked on. My code for the single school name list: $query = mysql_query("Select schoolname, product, username, password from credentials c join products p on p.productid = c.productid join schools s on s.schoolid = c.schoolid join icons i on i.productid = p.productid order by s.schoolname"); echo '<ul>'; while($row = mysql_fetch_array($query)) { echo "<li> <a href='#'>" . $row['schoolname'] . "</a> </li>"; } echo ''; Current Output: School A School A School B School B School B School C School C Expected Output: School name displayed only once (distinct won't work because each school name has 2-3 product credentials School A School B School C Ability for User to click on a school. then the school names underneath will move down (toggle effect) and user can see product, username and password displayed for the school clicked (for example: user clicked on School A) School A productname1, username, password productname2, username, password School B School C

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