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  • Changing style sheets depending on useragent

    - by John Vasiliou
    <script language="Javascript"> var deviceIphone = "iPhone"; var deviceIpod = "iPod"; //Initialize our user agent string to lower case. var uagent = navigator.userAgent.toLowerCase(); //************************** // Detects if the current device is an iPhone. function DetectiPhone() { if (uagent.search(deviceIphone) > -1) {document.write('<link rel="stylesheet" type="text/css" href="ui/mobile/css/site.css">'); } etc... Above is the start of my code. I am trying to change the CSS file depending on what platform the user is using. I currently use media="screen ... " but it doesn't work with the amount of platforms I'm trying to use. I need something a lot more detailed/complex that is why I'm turning to useragents. Any ideas why the css file doesn't change on my iPhone using the above code? Better yet, any ideas on another way to change style sheets depending on the users platform/screen resolution?

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  • rb plugin the hot key not working

    - by Bunny Rabbit
    def activate(self,shell): self.shell = shell self.action = gtk.Action ('foo','bar','baz',None) self.activate_id = self.action.connect ('activate', self.call_bk_fn,self.shell) self.action_group = gtk.ActionGroup ('hot_key_action_group') self.action_group.add_action_with_accel (self.action, "<control>E") uim = shell.get_ui_manager () uim.insert_action_group (self.action_group, 0) uim.ensure_update () def call_bk_fn(self,shell): print('hello world') i am using the above code in a plugin for rhythmbox ,and here i am trying to register the key ctr+e so that the call_bk_fn gets called whenever the key combination is pressed , but its not working why is that so ?

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  • Python/Django: log to console under runserver, log to file under Apache

    - by Justin Grant
    How can I send trace messages to the console (like print) when I'm running my Django app under manage.py runserver, but have those messages sent to a log file when I'm running the app under Apache? I reviewed Django logging and although I was impressed with its flexibility and configurability for advanced uses, I'm still stumped with how to handle my simple use-case. My apologies for not being able to find the answer elsewhere-- this is a newbie question I know.

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  • array with sessions, only prints one letter

    - by jolabero
    On login: $result = mysql_query("SELECT `id`, `username`, `email` FROM `users` WHERE `username` = '$username' AND `password` = '$passwd'"); $userdata = array('id','username','email'); $_SESSION['user'] = mysql_result($result, 0, $userdata); And when i want to print the users username echo $_SESSION['user']['username'] it only prints the first letter :/ whats wrong`?

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  • Creating an instance within the Class itself

    - by didxga
    What's going on when the assignment statement executed at Line 4, does compiler ignore the new operator and keep the foo variable being null or something else happen to handle this awkward moment? public class Foo { // creating an instance before its constructor has been invoked, suppose the "initializing" // gets printed in constructor as a result of the next line, of course it will not print it private Foo foo = new Foo();//Line 4 public Foo() { System.out.println("initializing"); } }

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  • how to do this problem?

    - by Sachin Tendulkar
    Write an iterative program that finds the largest number of McNuggets that cannot be bought in exact quantity. Your program should print the answer in the following format (where the correct number is provided in place of n): "Largest number of McNuggets that cannot be bought in exact quantity: n"

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  • Write failed, errno 0

    - by EpsilonVector
    I have a client server situation in which I receive data using read(socket, char_buf, BUF_SIZE) and then try to write it into a log file using write(filefd, char_buf, strlen(char_buf)) Strangely enough this fails (write returns -1), and yet the errno is set to 0, and I can print the message, AND the log file descriptor works (I write to it before and after this command). What's going on?? (Working on Linux kernel 2.4 (homework))

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  • Best Ways to send message or data to fax machine

    - by CitadelCSAlum
    I currently am working on a web application that needs to collect data from a form and will take the information and put it in a report format and sent it to a fax machine and print it out. What is the easiest way to do this. I would like it to act similar to collecting informastion off of a form and then sending an email, but I would like to send it to a fax instead. Thanks!

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  • C# - Printing the Form

    - by Jon
    I am using the code from MS to print a form however it looks like the form needs to be visible with a Show/ShowDialog() to work. I am trying to use the code for a form that I don't want to show. Any ideas?

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  • Exception Handaling in google app engine

    - by Rahul99
    i am raising exception using if UserId == '' and Password == '': raise Exception.MyException , "wrong userId or password" but i want print the error message on same page class MyException(Exception): def __init__(self,msg): Exception.__init__(self,msg)

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  • [Python] Different work of the script in Windows and in FreeBSD

    - by www.yegorov-p.ru
    Hello. I'm writing some script, that works with web-servers. So, I have the following code: client = suds.client.Client(WSDLfile) client.service.Login('mylogin', 'mypass') print client.options.transport.cookiejar ####### sessnum = str(client.options.transport.cookiejar).split(' ')[1] client = suds.client.Client( WSDLfile, headers= { 'Set-Cookie' : sessnum } ) When running in FreeBSD, it returns <cookielib.CookieJar[<Cookie sessnum=9WAXQ25D37XY535F6SZ3GXKSCTZG8CVJ for .IP.IP.IP.IP/>]> but in Windows it returns <cookielib.CookieJar[]> How can I fix it?

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  • PRINTER SET UP IN EXCEL VISUAL BASIC

    - by Gina
    I am trying to assign a cell in excel for the user to type the printer name where they want the print out to go and then use that value in the Application.ActivePrinter = (use the cell value) Even though I have done the programming assigning a name to the cell and using it in a variable it is giving me an error. I have set my variable as string, text, object and variant already and it's not working. Do you know what code should I use to be able to do this?

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  • How to convert a string to variable name

    - by p1xelarchitect
    I'm loading several external JSON files and want to check if they have been successfully cached before the the next screen is displayed. My strategy is to check the name of the array to see if it an object. My code works perfectly when I check only a single array and hard code the array name into my function. My question is: how can i make this dynamic? not dynamic: (this works) $("document").ready(){ checkJSON("nav_items"); } function checkJSON(){ if(typeof nav_items == "object"){ // success... } } dynamic: (this doesn't work) $("document").ready(){ checkJSON("nav_items"); checkJSON("foo_items"); checkJSON("bar_items"); } function checkJSON(item){ if(typeof item == "object"){ // success... } } here is the a larger context of my code: var loadAttempts = 0; var reloadTimer = false; $("document").ready(){ checkJSON("nav_items"); } function checkJSON(item){ loadAttempts++; //if nav_items exists if(typeof nav_items == "object"){ //if a timer is running, kill it if(reloadTimer != false){ clearInterval(reloadTimer); reloadTimer = false; } console.log("found!!"); console.log(nav_items[1]); loadAttempts = 0; //reset // load next screen.... } //if nav_items does not yet exist, try 5 times, then give up! else { //set a timer if(reloadTimer == false){ reloadTimer = setInterval(function(){checkJSON(nav_items)},300); console.log(item + " not found. Attempts: " + loadAttempts ); } else { if(loadAttempts <= 5){ console.log(item + " not found. Attempts: " + loadAttempts ); } else { clearInterval(reloadTimer); reloadTimer = false; console.log("Giving up on " + item + "!!"); } } } }

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  • Haskell Tuple Size Limit

    - by SHiNKiROU
    Why I can't construct large tuples in Haskell? Why there's a tuple size limit? Prelude> (1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1) <interactive>:1:0: No instance for (Show (t, t1, t2, ... t23)) arising from a use of `print' at <interactive>:1:0-48 Possible fix: add an instance declaration for (Show (t, t1, t2, ... t23)) In a stmt of a 'do' expression: print it

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  • python: How to refer to specific item within a list of lists?

    - by user964689
    Python beginner here, I have a list of lists and want to refer to a specific part of that list. For example lol = [[1, 2, 4], [6, 7, 8], [9, 10, 14]] If I just want to print the first item in one of the lists, eg the 1, 6 or 9, how would I do that? I can only find ways to refer to each of the lists seperately eg lol[0] but not to then refer to an item within that list. Thank you in advance for your help! Cheers

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  • how do i call methods from another class in android?

    - by Phani Gargey
    I have two classes in question. Both extend Activity. Class A public void displayinfo() { setContentView(R.layout.dynamicinfo); //Add some buttons dynamically here //do some processing // move on to Class B } In Class B: I want to go back to Class A state in UI if BACK button is pressed. Class B //Register a listener for this button Backbutton.setOnClickListener(new OnClickListener() { public void onClick(View arg0) { Log.i("setOnClickListener", "Pressed Back Button "); Toast.makeText(mycontext, "Pressed Back Button", Toast.LENGTH_SHORT).show(); //HERE I want to go back class's function in UI as well as restoring the sttae for that screen. } how do I do that? I looked around some questions. they did not answer clearly what I am looking for.hence the posting. thanks.I think I was adding my own Back button on the Layout I created in the Class B's UI Screen --not using the regular "Back" button on the key board. May be that was the problem.

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