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• ForEach with EditorFor

  - by hermiod

  I have got an Entity model which contains a collection of Message objects which are of the type Message which has several properties, including content, MessageID, from, and to. I have created an EditorTemplate for type Message, however, I cannot get it to display the contents of the Messages collection. There are no errors, but nothing is output. Please note that the view code is from an EditorTemplate for the parent Talkback class. Can you have an EditorTemplate calling another EditorTemplate for a child collection? Both the Talkback and Message class are generated by Entity framework from an existing database. View code: <% foreach (TalkbackEntityTest.Message msg in Model.Messages) { Html.EditorFor(x=> msg, "Message"); } %> This is my template code. It is the standard auto-generated view code with some minor changes. <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<TalkbackEntityTest.Message>" %> <%: Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div class="editor-label"> <%: Html.LabelFor(model => model.MessageID) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.MessageID) %> <%: Html.ValidationMessageFor(model => model.MessageID) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.acad_period) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.acad_period) %> <%: Html.ValidationMessageFor(model => model.acad_period) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.talkback_id) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.talkback_id) %> <%: Html.ValidationMessageFor(model => model.talkback_id) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.From) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.From) %> <%: Html.ValidationMessageFor(model => model.From) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.To) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.To) %> <%: Html.ValidationMessageFor(model => model.To) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.SentDatetime) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.SentDatetime, String.Format("{0:g}", Model.SentDatetime)) %> <%: Html.ValidationMessageFor(model => model.SentDatetime) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.content) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.content) %> <%: Html.ValidationMessageFor(model => model.content) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.MessageTypeID) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.MessageTypeID) %> <%: Html.ValidationMessageFor(model => model.MessageTypeID) %> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> There is definitely content in the Message collection as, if I remove EditorFor and put in response.write on the content property of the Message class, I get the content field for 3 Message objects on the page, which is exactly as expected.

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• In MVC , DAO should be called from Controller or Model

  - by tito

  I have seen various arguments against the DAO being called from the Controller class directly and also the DAO from the Model class.Infact I personally feel that if we are following the MVC pattern , the controller should not coupled with the DAO , but the Model class should invoke the DAO from within and controller should invoke the model class.Why because , we can decouple the model class apart from a webapplication and expose the functionalities for various ways like for a REST service to use our model class. If we write the DAO invocation in the controller , it would not be possible for a REST service to reuse the functionality right ? I have summarized both the approaches below. Approach #1 public class CustomerController extends HttpServlet { proctected void doPost(....) { Customer customer = new Customer("xxxxx","23",1); new CustomerDAO().save(customer); } } Approach #2 public class CustomerController extends HttpServlet { proctected void doPost(....) { Customer customer = new Customer("xxxxx","23",1); customer.save(customer); } } public class Customer { ........... private void save(Customer customer){ new CustomerDAO().save(customer); } } Note- Here is what a definition of Model is : Model: The model manages the behavior and data of the application domain, responds to requests for information about its state (usually from the view), and responds to instructions to change state (usually from the controller). In event-driven systems, the model notifies observers (usually views) when the information changes so that they can react. I would need an expert opinion on this because I find many using #1 or #2 , So which one is it ?

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• Why is my django bulk database population so slow and frequently failing?

  - by bryn

  I decided I'd like to use django's model system rather than coding raw SQL to interface with my database, but I am having a problem that surely is avoidable. My models.py contains: class Student(models.Model): student_id = models.IntegerField(unique = True) form = models.CharField(max_length = 10) preferred = models.CharField(max_length = 70) surname = models.CharField(max_length = 70) and I'm populating it by looping through a list as follows: from models import Student for id, frm, pref, sname in large_list_of_data: s = Student(student_id = id, form = frm, preferred = pref, surname = sname) s.save() I don't really want to be saving this to the database each time but I don't know another way to get django to not forget about it (I'd rather add all the rows and then do a single commit). There are two problems with the code as it stands. It's slow -- about 20 students get updated each second. It doesn't even make it through large_list_of_data, instead throwing a DatabaseError saying "unable to open database file". (Possibly because I'm using sqlite3.) My question is: How can I stop these two things from happening? I'm guessing that the root of both problems is that I've got the s.save() but I don't see a way of easily batching the students up and then saving them in one commit to the database.

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• Custom model binder for model inner property

  - by Andrej Kaurin

  My model is like this public class MyModel { string ID {get;set;} string Title {get;set;} MyOtherModel Meta {get;set;} } How to define custom model binder for type (MyOtherModel) so when default binder binds MyModel it calls custom model binder for 'Meta' property. I registered it in App start like: ModelBinders.Binders[typeof(MyOtherModel)] = new MyCustomBinder(); but this doesn't work. Any idea or any good article with more infor regarding to model binders?

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• Actor model to replace the threading model?

  - by prosseek

  I read a chapter in a book (Seven languages in Seven Weeks by Bruce A. Tate) about Matz (Inventor of Ruby) saying that 'I would remove the thread and add actors, or some other more advanced concurrency features'. Why and how an actor model can be an advanced concurrency model that replaces the threading? What other models are the 'advanced concurrency model'?

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• How to determine the maximum integer the model can handle?

  - by John Mee

  "What is the biggest integer the model field that this application instance can handle?" We have sys.maxint, but I'm looking for the database+model instance. We have the IntegerField, the SmallIntegerField, the PositiveSmallIntegerField, and a couple of others beside. They could all vary between each other and each database type. I found the "IntegerRangeField" custom field example here on stackoverflow. Might have to use that, and guess the lowest common denominator? Or rethink the design I suppose. Is there an easy way to work out the biggest integer an IntegerField, or its variants, can cope with?

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• Display a boolean model field in a django form as a radio button rather than the default Checkbox.

  - by Lakshman Prasad

  This is how I went about, to display a Boolean model field in the form as Radio buttons Yes and No. choices = ( (1,'Yes'), (0,'No'), ) class EmailEditForm(forms.ModelForm): #Display radio buttons instead of checkboxes to_send_form = forms.ChoiceField(choices=choices,widget=forms.RadioSelect) class Meta: model = EmailParticipant fields = ('to_send_email','to_send_form') def clean(self): """ A workaround as the cleaned_data seems to contain u'1' and u'0'. There may be a better way. """ self.cleaned_data['to_send_form'] = int(self.cleaned_data['to_send_form']) return self.cleaned_data As you can see in the code above, I need a clean method that converts input string to an integer, which may be unnecessary. Is there a better and/or djangoic way to do this. If so, how? And no, using BooleanField seems to cause a lot more problems. Using that seemed obvious to me; but it isn't. Why is it so.

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• How to make a Django model fields calculated at runtime?

  - by Anatoly Rr

  I have a model: class Person (models.Model): name = models.CharField () birthday = models.DateField () age = models.IntegerField () I want to make age field to behave like a property: def get_age (self): return (datetime.datetime.now() - self.birthday).days // 365 age = property (get_age) but at the same time I need age to be a true field, so I can find it in Person._meta.fields, and assign attributes to it: age.help_text = "Age of the person", etc. Obviously I cannot just override Person.save() method to calculate and store age in the database, because it inevitably will become wrong later (in fact, it shouldn't be stored in the database at all). Actually, I don't need to have setters now, but a nice solution must have setting feature. Is it possible in Django, or probably there is a more pythonic and djangoic approach to my problem?

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• How do I memoize expensive calculations on Django model objects?

  - by David Eyk

  I have several TextField columns on my UserProfile object which contain JSON objects. I've also defined a setter/getter property for each column which encapsulates the logic for serializing and deserializing the JSON into python datastructures. The nature of this data ensures that it will be accessed many times by view and template logic within a single Request. To save on deserialization costs, I would like to memoize the python datastructures on read, invalidating on direct write to the property or save signal from the model object. Where/How do I store the memo? I'm nervous about using instance variables, as I don't understand the magic behind how any particular UserProfile is instantiated by a query. Is __init__ safe to use, or do I need to check the existence of the memo attribute via hasattr() at each read? Here's an example of my current implementation: class UserProfile(Model): text_json = models.TextField(default=text_defaults) @property def text(self): if not hasattr(self, "text_memo"): self.text_memo = None self.text_memo = self.text_memo or simplejson.loads(self.text_json) return self.text_memo @text.setter def text(self, value=None): self.text_memo = None self.text_json = simplejson.dumps(value)

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• How do I flag only one of the formsets in django admin ?

  - by azuer88

  I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). My first solution was to override the validation of the formset but did understand how to do this. (is_correct is displayed as checkbox, and I'd display an error that only one is_correct should be selected.)

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• How to define one-to-many connection between a same model through another model

  - by Mekajiki

  I want to define one-to-many relationship as follows; User has one introducer User has many newcomers(who is introduced by the user) Use "Introduction" model instead of adding a column to users table. My table and model definition is as follows; DB Scheme: create_table "introductions", force: true do |t| t.integer "introducer_id" t.integer "newcomer_id" t.datetime "created_at" t.datetime "updated_at" User model: class User < ActiveRecord::Base has_many :introductions, foreign_key: :introducer_id has_many :newcomers, through: :introductions, source: :newcomer belongs_to :introduction, foreign_key: :newcomer_id belongs_to :introducer end Introduction model: class Introduction < ActiveRecord::Base belongs_to :introducer, class_name: 'User' belongs_to :newcomer, class_name: 'User' end This works fine: user1.newcomers.push user2 but, user2.introducer # => nil How can I define belongs_to relationship correctly?

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• MVC Rendered Partial, how to get partial/view model in main model post to controller

  - by user1475788

  I have a text file and when users upload the file, the controller action method parses that file using state machine and uses a generic list to store some values. I pass this back to the view in the form of an IEnumerable. Within my main view, based on this ienumerable list I render a partail view to iterate items and display labels and a textarea. Users could add their input in the text area. When the users hit the save button this ienumrable list from the partial view rendered is null. so please advice any solutions. here is my main view @model RunLog.Domain.Entities.RunLogEntry @{ ViewBag.Title = "Create"; Layout = "~/Views/Shared/_Layout.cshtml"; } @using (Html.BeginForm("Create", "RunLogEntry", FormMethod.Post, new { enctype = "multipart/form-data" })) { <div id="inputTestExceptions" style="display: none;"> <table class="grid" style="width: 450px; margin: 3px 3px 3px 3px;"> <thead> <tr> <th> Exception String </th> <th> Comment </th> </tr> </thead> <tbody> @if (Model.TestExceptions != null) { foreach (var p in Model.TestExceptions) { Html.RenderPartial("RunLogTestExceptionSummary", p); } } </tbody> </table> </div> } partial view as follows: @model RunLog.Domain.Entities.RunLogEntryTestExceptionDisplay <tr> <td> @Model.TestException@ </td> <td>@Html.TextAreaFor(Model.Comment, new { style = "width: 200px; height: 80px;" }) </td> </tr> Controller action [HttpPost] public ActionResult Create(RunLogEntry runLogEntry, String ServiceRequest, string Hour, string Minute, string AMPM, string submit, IEnumerable<HttpPostedFileBase> file, String AssayPerformanceIssues1, IEnumerable<RunLogEntryTestExceptionDisplay> models) { } The problem is test exceptions which contains exception string and comment is comming back null.

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• How to preprocess a Django model field value before return?

  - by Satoru.Logic

  Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

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• Using a join model to relate a model to itself

  - by Gabe Hollombe

  I have two models: User MentoringRelationship MentoringRelationship is a join model that has a mentor_id column and a mentee_id column (both of these reference user_ids from the users table). How can I specify a relation called 'mentees' on the User class that will return all of the users mentored by this user, using the MentoringRelationships join table? What relations do we need to declare in the User model and in the MentoringRelationship model?

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• MVVM- View Model-View Model Communications

  - by user275561

  How do I go about having two view models communicate with one another using MVVM Light. I know how to use the messenger class and register etc.. Here is my Scenario A Settings View ---> a Settings View Model . . . A MainPage View ---> A MainPage ViewModel If something changes in the Settings View it will Message back to the Settings View Model. So then I want the Settings View Model to communicate to the MainPage View Model about what changed. THe MainPage ViewModel will then tell the View.

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• Is Django's manage.py syncdb or South used to create the test database?

  - by Thierry Lam

  With Django 1.1.1 and South 0.62, running a test from the CLI usually have the following output: Creating table some_model Installing index for my_app.SomeModel model . ----- Ran 1 test in 1s OK After upgrading to South 0.7, the output is invoking South's migration: Creating table some_model Installing index for my_app.SomeModel model Migrating... Running migrations for my_app: - Migrating forwards to 0001_initial > my_app:0001_initial - Loading initial data for my_app Migrated: - my_app . ----- Ran 1 test in 1s OK To create the test DB, has the test always used South migration in the past(before South 0.7) even if the output is not explicitly being shown?

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• Django many-to-many relationship to self with extra data, how do I select from a certain direction?

  - by Jake

  I have some hierarchical data where each Set can have many members and can belong to more than one Set(group) Here are the models: class Set(models.Model): ... groups = models.ManyToManyField('self', through='Membership', symmetrical=False) members = models.ManyToManyField('self', through='Membership', symmetrical=False) class Membership(models.Model): group = models.ForeignKey( Set, related_name='Members' ) member = models.ForeignKey( Set, related_name='Groups' ) order = models.IntegerField( default=-1 ) I want to know how to get all the members or all the groups for a Set instance. I think I can do it as follows, but it's not very logical, can anyone tell me what's going on and how I should be doing it? # This gives me a set of Sets # Which seems to be the groups this Set belongs to set_instance.set_set.all() # These give me a set of Memberships, not Sets set_instance.Members.all() set_instance.Groups.all() # These they both return a set of Sets # which seem to be the members of this one set_instance.members.all() set_instance.groups.all()

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• Showing custom model validation exceptions in the Django admin site.

  - by Guy Bowden

  I have a booking model that needs to check if the item being booked out is available. I would like to have the logic behind figuring out if the item is available centralised so that no matter where I save the instance this code validates that it can be saved. At the moment I have this code in a custom save function of my model class: def save(self): if self.is_available(): # my custom check availability function super(MyObj, self).save() else: # this is the bit I'm stuck with.. raise forms.ValidationError('Item already booked for those dates') This works fine - the error is raised if the item is unavailable, and my item is not saved. I can capture the exception from my front end form code, but what about the Django admin site? How can I get my exception to be displayed like any other validation error in the admin site?

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• What is the proper way to check the previous value of a field before saving an object? (Using Django

  - by anonymous coward

  I have a Django Model with updated_by and an approved_by fields, both are ForeignKey fields to the built-in (auth) User models. I am aware that with updated_by, it's easy enough to simply over-ride the .save() method on the Model, and shove the request.user in that field before saving. However, for approved_by, this field should only ever be filled in when a related field (date_approved) is first filled in. I'm somewhat certain that I can check this logically, and fill in the field if the previous value was empty. What is the proper way to check the previous value of a field before saving an object? I do not anticipate that date_approved will ever be changed or updated, nor should there be any reason to ever update the approved_by entry. UPDATE: Regarding forms/validation, I should have mentioned that none of the fields in question are seen by or editable by users of the site. If I have misunderstood, I'm sorry, but I'm not sure how forms and validation apply to my question.

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• Working with extra fields in an Inline form - save_model, save_formset, can't make sense of the diff

  - by magicrebirth

  Suppose I am in the usual situation where there're extra fields in the many2many relationship: class Person(models.Model): name = models.CharField(max_length=128) class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(Person, through='Membership') class Membership(models.Model): person = models.ForeignKey(Person) group = models.ForeignKey(Group) date_joined = models.DateField() invite_reason = models.CharField(max_length=64) # other models which are unrelated to the ones above.. class Trip(models.Model): placeVisited = models.ForeignKey(Place) visitor = models.ForeignKey(Person) pleasuretrip = models.Boolean() class Place(models.Model): name = models.CharField(max_length=128) I want to add some extra fields in the Membership form that gets displayed through the Inline. These fields basically are a shortcut to the instantiation of another model (Trip). Trip can have its own admin views, but these shortcuts are needed because when my project partners are entering 'Membership' data in the system they happen to have also the 'Trip' information handy (and also because some of the info in Membership can just be copied over to Trip etc. etc.). So all I want to have is two extra fields in the Membership Inline - placeVisited and pleasuretrip - which together with the Person instance will let me instantiate the Trip model in the background... I found out I can easily add extra fields to the inline view by defining my own form. But once the data have been entered, how and when to reference to them in order to perform the save operations I need to do? class MyForm(forms.ModelForm): place = forms.ModelChoiceField(required=False, queryset=Place.objects.all(), label="place",) pleasuretrip = forms.BooleanField(required=False, label="...") class MembershipInline(admin.TabularInline): model = Membership form = MyForm def save_model(self, request, obj, form, change): place = form.place pleasuretrip = form.pleasuretrip person = form.person .... # now I can create Trip instances with those data .... obj.save() class GroupAdmin(admin.ModelAdmin): model = Group .... inlines = (MembershipInline,) This doesn't seem to work... I'm also a bit puzzled by the save_formset method... maybe is that the one I should be using? Many thanks in advance for the help!!!!

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• Is there a way to customize how the value for a custom Model Field is displayed in a template?

  - by Jordan Reiter

  I am storing dates as an integer field in the format YYYYMMDD, where month or day is optional. I have the following function for formatting the number: def flexibledateformat(value): import datetime, re try: value = str(int(value)) except: return None match = re.match(r'(\d{4})(\d\d)(\d\d)$',str(value)) if match: year_val, month_val, day_val = [int(v) for v in match.groups()] if day_val: return datetime.datetime.strftime(datetime.date(year_val,month_val,day_val),'%b %e, %Y') elif month_val: return datetime.datetime.strftime(datetime.date(year_val,month_val,1),'%B %Y') else: return str(year_val) Which results in the following outputs: >>> flexibledateformat(20100415) 'Apr 15, 2010' >>> flexibledateformat(20100400) 'April 2010' >>> flexibledateformat(20100000) '2010' So I'm wondering if there's a function I can add under the model field class that would automatically call flexibledateformat. So if there's a record r = DataRecord(name='foo',date=20100400) when processed in the form the value would be 20100400 but when output in a template using {{ r.date }} it shows up as "April 2010". Further clarification I do normally use datetime for storing date/time values. In this specific case, I need to record non-specific dates: "x happened in 2009", "y happened sometime in June 1996". The easiest way to do this while still preserving most of the functionality of a date field, including sorting and filtering, is by using an integer in the format of yyyymmdd. That is why I am using an IntegerField instead of a DateTimeField. This is what I would like to happen: I store what I call a "Flexible Date" in a FlexibleDateField as an integer with the format yyyymmdd. I render a form that includes a FlexibleDateField, and the value remains an integer so that functions necessary for validating it and rendering it in widgets work correctly. I call it in a template, as in {{ object.flexibledate }} and it is formatted according to the flexibledateformat rules: 20100416 - April 16, 2010; 20100400 - April 2010; 20100000 - 2010. This also applies when I'm not calling it directly, such as when it's used as a header in admin (http://example.org/admin/app_name/model_name/). I'm not aware if these specific things are possible.

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• Django Inline formset for editing multiple related records at once - the right way to go?

  - by Bert

  Hi, When using inline formsets, how does one do paging? I'm using django 1.1. The situation I'm in, is that the user needs to be able to edit the related objects quickly and easily (which is why I think I should be using an inline formset). However, there can be a more than a hundred objects to edit, which makes a pretty large formset, so paging would make sense. Is there a better way to be doing this? Thanks Bert

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• How do you set the sitemap priority for flatpages in django?

  - by mlissner

  I have a site with about 60,000 pages that are getting placed in the sitemap, and which have a priority of 0.3. These are all really long pages that are rich in keywords. I also have a few pages (like the about page), that need high priority, but which I've implemented with the django flatpages framework. Is it possible for pages created this way to have a higher priority in the sitemap?

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• django-haystack: how to access the spelling suggestions on the template ?

  - by pierre-guillaume-degans

  Hey, I'm trying django-haystack with Solr and HAYSTACK_INCLUDE_SPELLING = True. How do you access the spelling suggestions on the template (generated by the default SearchView) ? Thanks :-)

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• Why does django-sphinx only output 20 results? How can I get the rest?

  - by mlissner

  Doing a search using django-sphinx gives me results._sphinx that says there were 68 results, but when I iterate over them, I can only get at the first 20 of them. I'm SURE there's a way around this, and that this is by design, but it's officially stumping the heck out of me. Does anybody know how to get the complete queryset?

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