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  • search form in php via ajax

    - by fusion
    i've a search form wherein the database query has been coded in php and the html file calls this php file via ajax to display the results in the search form. the problem is, i would like the result to be displayed in the same form as search.html; yet while the ajax works, it goes to search.php to display the results. search.html: <!DOCTYPE html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <script src="scripts/search_ajax.js" type="text/javascript"></script> </head> <body> <form id="submitForm" method="post"> <div class="wrapper"> <div class="field"> <input name="search" id="search" /> </div><br /> <input id="button1" type="submit" value="Submit" class="submit" onclick="run_query();" /><br /> </div> <div id="searchContainer"> </div> </form> </body> </html> if i add action="search.php" to the form tag, it displays the result but on search.php. i'd like it to display on the same form [i.e search.html, and not search.php] if i just add the javascript function [as done above], it displays nothing on search.html

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  • [grails] setting cookies when render type is "contentType: text/json"

    - by Robin Jamieson
    Is it possible to set cookies on response when the return render type is set as json? I can set cookies on the response object when returning with a standard render type and later on, I'm able to get it back on the subsequent request. However, if I were to set the cookies while rendering the return values as json, I can't seem to get back the cookie on the next request object. What's happening here? These two actions work as expected with 'basicForm' performing a regular form post to the action, 'withRegularSubmit', when the user clicks submit. // first action set the cookie and second action yields the originally set cookie def regularAction = { // using cookie plugin response.setCookie("username-regular", "regularCookieUser123",604800); return render(view: "basicForm"); } // called by form post def withRegularSubmit = { def myCookie = request.getCookie("username-regular"); // returns the value 'regularCookieUser123' return render(view: "resultView"); } When I switch to setting the cookie just before returning from the response with json, I don't get the cookie back with the post. The request starts by getting an html document that contains a form and when doc load event is fired, the following request is invoked via javascript with jQuery like this: var someUrl = "http://localhost/jsonAction"; $.get(someUrl, function(jsonData) { // do some work with javascript} The controller work: // this action is called initially and returns an html doc with a form. def loadJsonForm = { return render(view: "jsonForm"); } // called via javascript when the document load event is fired def jsonAction = { response.setCookie("username-json", "jsonCookieUser456",604800); // using cookie plugin return render(contentType:'text/json') { 'pair'('myKey': "someValue") }; } // called by form post def withJsonSubmit = { def myCookie = request.getCookie("username-json"); // got null value, expecting: jsonCookieUser456 return render(view: "resultView"); } The data is returned to the server as a result of the user pressing the 'submit' button and not through a script. Prior to the submit of both 'withRegularSubmit' and 'withJsonSubmit', I see the cookies stored in the browser (Firefox) so I know they reached the client.

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  • asp.net mvc ajax helper/post additional data w/o jquery.

    - by Jopache
    I would like to use the ajax helper to create ajax requests that send additional, dynamic data with the post (for example, get the last element with class = blogCommentDateTime and send the value of that last one to the controller which will return only blog comments after it). I have successfully done so with the help of jQuery Form plugin like so: $(document).ready(function () { $("#addCommentForm").submit(function () { var lastCommentDate = $(".CommentDateHidden:last").val(); var lastCommentData = { lastCommentDateTicks: lastCommentDate }; var formSubmitParams = { data: lastCommentData, success: AddCommentResponseHandler } $("#addCommentForm").ajaxSubmit(formSubmitParams); return false; }); This form was created with html.beginform() method. I am wondering if there is an easy way to do this using the ajax.beginform() helper? When I try to use the same code but replace html.beginform() with ajax.beginform(), when i try to submit the form, I am issuing 2 posts (which is understandable, one being taken care of by the helper, the other one by me with the JS above. I can't create 2 requests, so this option is out) I tried getting rid of the return false and changing ajaxSubmit() to ajaxForm() so that it would only "prepare" the form, and this leads in only one post, but it does not include the extra parameter that I defined, so this is worthless as well. I then tried keeping the ajaxForm() but calling that whenever the submit button on the form gets clicked rather than when the form gets submitted (I guess this is almost the same thing) and that results in 2 posts also. The biggest reason I am asking this question is that I have run in to some issues with the javascript above and using mvc validation provided by the mvc framework (which i will set up another question for) and would like to know this so I can dive further in to my validation issue.

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  • jQueryUI Modal confirmation dialog on form submission

    - by DavidYell
    I am trying to get a modal confirmation dialog working when a user submits a form. My approach, I thought logically, would be to catch the form submission. My code is as follows, $('#multi-dialog-confirm').dialog({ autoOpen: false, height: 200, modal: true, resizable: false, buttons: { 'Confirm': function(){ //$(this).dialog('close'); return true; }, 'Cancel': function(){ $(this).dialog('close'); return false; } } }); $('#completeform').submit(function(e){ e.preventDefault(); var n = $('#completeform input:checked').length; if(n == 0){ alert("Please check the item and mark as complete"); return false; }else{ var q = $('#completeform #qty').html(); if(q > 1){ $('#multi-dialog-confirm').dialog('open'); } } //return false; }); So I'm setting up my dialog first. This is because I'm pretty certain that the scope of the dialog needs to be at the same level as the function which calls it. However, the issue is that when you click 'Confirm' nothing happens. The submit action does not continue. I've tried $('#completeform').submit(); also, which doesn't seem to work. I have tried removing the .preventDefault() to ensure that the form submission isn't completely cancelled, but it doesn't seem to make a difference between that and returning false. Not checking the box, show and alert fine. Might change to dialog at some point ;), clicking 'Cancel' closes the dialog and remains on the page, but the elusive 'Confirm' buttons seems to not continue with the form submission event. If anyone can help, I'd happily share my lunch with you! ;)

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  • How to send array by post method

    - by GanChinHock.com
    Following is my sample form. <form METHOD="post" METHOD="post" ACTION="index.php" METHOD="post" METHOD="post" METHOD="post"> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="submit" NAME="submit" VALUE="Submit" /> </form> Basically I have 10 inputs of array. Assume my domain is http://domain.com and the file above is index.php. I am trying to fill the form automatically by using the following method. http://domain.com/index.php?array[]=John&array[]=Kelly ... & array[]=Steven Unfortunately, it is not working. :(

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  • Multiple forms using Rails & jQuery & AJAX

    - by biggie8199
    I have multiple coupons on a page and I'm trying to get comments to work on each coupon. So for each coupon i have a comments form. Im using jQuery + Ajax to accomplish this. Here's what my code looks like. Coupon Page <p>Comments:</p> <% form_for(@comment) do |f| %> <%= f.label :body %><br /><%= f.text_field :body, :size => "24" %> <%= f.hidden_field :coupon_id, :value => coupon.id %> <%= f.submit "Save" %> <% end %> Application.js jQuery.ajaxSetup({ 'beforeSend': function(xhr) {xhr.setRequestHeader("Accept", "text/javascript")} }) jQuery.fn.submitWithAjax = function() { this.submit(function() { $.post(this.action, $(this).serialize(), null, "script"); return false; }) return this; }; $(document).ready(function() { $("#new_comment").submitWithAjax(); }) I tried changing the jQuery selector to a class $(".new_comment").submitWithAjax(); Thinking that would work, now all the submit buttons work, however it posts only the first form on the page. What can I change to make it so ajax submits the correct form and not the first one?

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  • How to insert an element between the two elements dynamically?

    - by Harish
    I am using a table, in which there are buttons, on button click i want the new TR element to be inserted between the two TR or at the end of the TR... my code goes here <table> <tbody> <tr> <td> <input type="submit" value="Add" onclick="addFunction()" /> </td> </tr> <tr> <td> <input type="submit" value="Add" onclick="addFunction()" /> </td> </tr> <tr> <td> <input type="submit" value="Add" onclick="addFunction()" /> </td> </tr> </tbody> </table> i want to insert new TR element next to the element which has triggered the event... NOTE: i am not using any javascript library, just plain javascript

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  • pagination and url encoding help

    - by Sufyan
    <?php $name=$_POST['name']; ?> <form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="text" name="name"> <input type="submit" value="GO" name="submit"> </form> <?php include ('db.php'); if(isset($_POST['submit'])) { mysql_query ("INSERT INTO example (name) VALUES('$name')") or die(mysql_error()); } if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) { $startrow = 0; } else { $startrow = (int)$_GET['startrow']; } $query = "SELECT * FROM example ORDER BY id DESC LIMIT $startrow, 20"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo "<li>"; echo $row['name'] ." "." <a href= 'like.php?quote=" . urlencode( $row['name'] ) . "'>Click Here</a>"; echo "</li>"; } echo '<a href="'.$_SERVER['PHP_SELF'].'?startrow='.($startrow+10).'">Next</a>'; ?> I want to make my page links hidden , how can i make then hidden so that a user cant edit it. 2nd question, currently i am showing total 10 records on each page and then a next page button , but the next button is keep showing even when there is no more records...! how to remove a next page button when records ended. ?? line number 28 is the link to pages which can be easyily editable by any user, i wnat to make them secure (using ID) and line 35 is n'next' page link , this link should not be appear when number of records ended

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  • Problems updating a textBox ASP.NET

    - by Roger Filipe
    Hello, I'm starting in asp.net and am having some problems that I do not understand. The problem is this, I am building a site for news. Every news has a title and body. I have a page where I can insert news, this page uses a textbox for each of the fields (title and body), after clicking the submit button everything goes ok and saves the values in the database. And o have another page where I can read the news, I use labels for each of the camps, these labels are defined in the Page_Load. Now I'm having problems on the page where I can edit the news. I am loading two textboxes (title and body) in the Page_Load, so far so good, but then when I change the text and I click the submit button, it ignores the changes that I made in the text and saves the text loaded in Page_Load. This code doesn't show any database connection but you can understand what i'm talking about. protected void Page_Load(object sender, EventArgs e) { textboxTitle.Text = "This is the title of the news"; textboxBody.Text = "This is the body of the news "; } I load the page, make the changes in the text , and then click submit. protected void btnSubmit_Click(object sender, EventArgs e) { String title = textboxTitle.Text; String body = textboxBody.Text; Response.Write("Title: " + title + " || "); Response.Write("Body: " + body ); } Nothing happens, the text in the textboxes is always the one I loaded in the page_load, how do I update the Text in the textboxes?

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  • Xcode "Build and Archive" from command line

    - by Dan Fabulich
    Xcode 3.2 provides an awesome new feature under the Build menu, "Build and Archive" which generates an .ipa file suitable for Ad Hoc distribution. You can also open the Organizer, go to "Archived Applications," and "Submit Application to iTunesConnect." Is there a way to use "Build and Archive" from the command line (as part of a build script)? I'd assume that xcodebuild would be involved somehow, but the man page doesn't seem to say anything about this. UPDATE Michael Grinich requested clarification; here's what exactly you can't do with command-line builds, features you can ONLY do with Xcode's Organizer after you "Build and Archive." You can click "Share Application..." to share your IPA with beta testers. As Guillaume points out below, due to some Xcode magic, this IPA file does not require a separately distributed .mobileprovision file that beta testers need to install; that's magical. No command-line script can do it. For example, Arrix's script (submitted May 1) does not meet that requirement. More importantly, after you've beta tested a build, you can click "Submit Application to iTunes Connect" to submit that EXACT same build to Apple, the very binary you tested, without rebuilding it. That's impossible from the command line, because signing the app is part of the build process; you can sign bits for Ad Hoc beta testing OR you can sign them for submission to the App Store, but not both. No IPA built on the command-line can be beta tested on phones and then submitted directly to Apple. I'd love for someone to come along and prove me wrong: both of these features work great in the Xcode GUI and cannot be replicated from the command line.

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  • struts2: problem in assigning a variable value to checkbox

    - by vivmal
    Hi All, I am working on struts2. In my jsp page I want to assign the value of a string variable to a checkbox (when it is checked by user). I tried it many times like - <% String code = "decompose"; %> 1) <tr><td> <s:checkbox name="codeCkBox" fieldValue="%{‘code’}" onclick="submit()"/> </td></tr> 2) <tr><td> <s:checkbox name="codeCkBox" value="%{‘code’}" onclick="submit()"/> </td></tr> 3) <tr><td> <s:set name="setCkBoxValue" value="%{‘code’}"/> <s:checkbox name="codeCkBox" fieldValue="# setCkBoxValue" onclick="submit()"/> </td></tr> But everytime when I tried to get this value by checkbox name it returns variable name i.e “code”. Looking for a solution. Thanks in advance.

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  • Fix a 404: missing parameters error from a GET request to CherryPy

    - by norabora
    I'm making a webpage using CherryPy for the server-side, HTML, CSS and jQuery on the client-side. I'm also using a mySQL database. I have a working form for users to sign up to the site - create a username and password. I use jQuery to send an AJAX POST request to the CherryPy which queries the database to see if that username exists. If the username exists, alert the user, if it doesn't, add it to the database and alert success. $.post('submit', postdata, function(data) { alert(data); }); Successful jQuery POST. I want to change the form so that instead of checking that the username exists on submit, a GET request is made as on the blur event from the username input. The function gets called, and it goes to the CherryPy, but then I get an error that says: HTTPError: (404, 'Missing parameters: username'). $.get('checkUsername', getdata, function(data) { alert(data); }); Unsuccessful jQuery GET. The CherryPy: @cherrypy.expose def submit(self, **params): cherrypy.response.headers['Content-Type'] = 'application/json' e = sqlalchemy.create_engine('mysql://mysql:pw@localhost/6470') c = e.connect() com1 = "SELECT * FROM `users` WHERE `username` = '" + params["username"] + "'" b = c.execute(com1).fetchall() if not len(b) > 0: com2 = "INSERT INTO `6470`.`users` (`username` ,`password` ,`website` ,`key`) VALUES ('" com2 += params["username"] + "', MD5( '" + params["password"] + "'), '', NULL);" a = c.execute(com2) c.close() return simplejson.dumps("Success!") #login user and send them to home page c.close() return simplejson.dumps("This username is not available.") @cherrypy.expose def checkUsername(self, username): cherrypy.response.headers['Content-Type'] = 'application/json' e = sqlalchemy.create_engine('mysql://mysql:pw@localhost/6470') c = e.connect() command = "SELECT * FROM `users` WHERE `username` = '" + username + "'" a = c.execute(command).fetchall(); c.close() sys.stdout.write(str(a)) return simplejson.dumps("") I can't see any differences between the two so I don't know why the GET request is giving me a problem. Any insight into what I might be doing wrong would be helpful. If you have ideas about the jQuery, CherryPy, config files, anything, I'd really appreciate it.

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  • Is CakePhp 'standards compliant' when generating HTML, Forms, etc?

    - by dtj
    So I've been reading a lot of "Designing with Web Standards" and really enjoying it. I'm a big CakePhp user, and as I look at the source for various form elements that Cake creates with its FormHelper, I see all sorts of extraneous In the book, he promotes semantic HTML, and writing your markup as simple / generic as possible. So my question is, am I better writing my own HTML in these situations? I really want to work in compliance with XHTML and CSS standards, and it seems I'd spend just as much time (if not more) cleaning up Cakes HTML, when I could just write my own thoughts? p.s. Here's an example in an out of the box form that CakePhp generates using the FormHelper <form id="CompanyAddForm" method="post" action="/omni_cake/companies/add" accept-charset="utf-8"><div style="display:none;"><input type="hidden" name="_method" value="POST" /></div> <div class="input text required"><label for="CompanyName">Name</label><input name="data[Company][name]" type="text" maxlength="50" id="CompanyName" /></div> <div class="input text required"><label for="CompanyWebsite">Website</label><input name="data[Company][website]" type="text" maxlength="50" id="CompanyWebsite" /></div> <div class="input textarea"><label for="CompanyNotes">Notes</label><textarea name="data[Company][notes]" cols="30" rows="6" id="CompanyNotes" ></textarea></div> <div class="submit"><input type="submit" value="Submit" /></div></form>

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  • Can't use my form

    - by Alexandr
    I have class with my form in folder /application/forms/Auth.php it looks like class Form_Auth extends Zend_Form { public function __construct() { $this->setName(); parent::__construct(); $username = new Zend_Form_Element_Text('username'); $password = new Zend_Form_Element_Password('password'); $mail = new Zend_Form_Element_Text('mail'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username,$password,$mail,$submit)); } } When i try create object $this->view->form = new Form_Auth(); is see exeption Application error Exception information: Message: Invalid name provided; must contain only valid variable characters and be non-empty Stack trace: D:\WWW\zends\application\Forms\Auth.php(8): Zend_Form-setName() d:\WWW\zends\application\controllers\RegistrationController.php(49): Form_Auth-__construct() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Action.php(513): RegistrationController-indexAction() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action-dispatch('indexAction') D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard-dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front-dispatch() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap-run() D:\WWW\zends\public\index.php(26): Zend_Application-run() {main} Request Parameters: array ( 'controller' = 'registration', 'action' = 'index', 'module' = 'default', ) the version zf is 1.10.3 what i do wrong ?

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  • how to send value to the from action page from database

    - by Mayank swami
    I am creating a faq panel for there can be multiple answers for question and i want to take the answer id .because i am storing comment by answer id the problem is that how to sent the $answer_id to the comment_submit_process.php and how to recognize the answer ? $selected_ques= mysql_prep($_GET['ques']); $query = "SELECT * FROM formanswer where question_id = {$selected_ques}"; $ans= mysql_query($query); if($ans){ while($answer = mysql_fetch_array($ans)) //here is the form <form id="add-comment" action="comment_submit_process.php" > <textarea class="comment-submit-textarea" cols="78" name="comment" style="height: 64px;"></textarea> <input type="submit" name="submitbutton" value="Add Comment" class="comment-submit-button" > <br> <?php $ans_id= $answer['id']; echo $ans_id; ?> <input type="hidden" name="ques" value="<?php echo $_GET['$ans_id'] ?>" /> <span class="counter ">enter at least 15 characters</span> <span class="form-error"></span> </form> <?php }} ?>

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  • Codeigniter: Library function--I'm stuck

    - by Kevin Brown
    I have a library function that sets up my forms, and submits data. They're long, and they work, so I'll spare you reading my code. :) I simply need a way for my functions to determine how to handle the data. Until now, the function did one thing: Submit a report for the current user. NOW, the client has requested that an administrator also be able to complete a form--this means that the form would be filled out, and it would CREATE a user at the same time, whereas the current function EDITS and is accessed by an EXISTING user. Do I need a separate function to do essentially the same thing? How do I make one function perform two tasks? One to update a user, and if there is no user, create one. Current controller: function survey() { $id = $this->session->userdata('id'); $data['member'] = $this->home_model->getUser($id); //Convert the db Object to a row array $data['manager'] = $data['member']->row(); $manager_id = $data['manager']->manager_id; $data['manager'] = $this->home_model->getUser($manager_id); $data['manager'] = $data['manager']->row(); $data['header'] = "Home"; $this->survey_form_processing->survey_form($this->_container,$data, $method); } Current Library: function survey_form($container) { //Lots of validation stuff $this->CI->validation->set_rules($rules); if ( $this->CI->validation->run() === FALSE ) { // Output any errors $this->CI->validation->output_errors(); } else { // Submit form $this->_submit(); } $this->CI->load->view($container,$data); The submit function is huge too. Basically says, "Update table with data where user_id=current user" I hope this wasn't too confusing. I'll create two functions if need be, but I'd like to keep redundancy down! }

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  • Access values of a group of select boxes in php from post

    - by 2Real
    Hi, I'm new to PHP, and I can't figure this out. I'm trying to figure out how to access the data of a group of select boxes I have defined in my HTML code. I tried grouping them as a class, but that doesn't seem to work... maybe I was doing it wrong. This is the following HTML code. <form action="" method="post"> <select class="foo"> <option> 1.....100</option> </select> <select class="foo"> <option> 1.... 500></option> </select> <input type="submit" value="Submit" name="submit"/> </form> I essentially want to group all my select boxes and access all the values in my PHP code. Thanks

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  • Jquery unidentified data return when post

    - by Nhat Tuan
    <?php //load.php $myid = $_POST['id']; if($myid == 1){ echo '1'; }else if($myid == 0){ echo '0'; } ?> <html> <input id="id" /> <div id="result"></div> <input type="button" id="submit" /> <script type="text/javascript"> $('#submit').click( function(){ var send = 'id=' + $('#id').val(); $.post('load.php', send, function(data){ if(data == 1){ $('#result').html('Success'); }else if(data == 0){ $('#result').html('Failure'); }else{ $('#result').html('Unknow'); } }); }); </script> </html> I test this script in some free host and it work but in my real host jquery unidentified data return and it alway show 'Unknow'. When i change if(data == '1') it show 'Unknow' too EX: input id = 1 click submit & data return is 'Unknow' Why ?? I think this error from host, because i test it in some free host and it work, but now in my real host i got this error, how i can fix it ?

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  • hy i dont get the check value in check box?

    - by udaya
    Hi I have a check box when check that check box the id corresponding to the check box is placed on a text box ... but when there is only single value in the database i cant get the check value why? here is my code <? if(isset($AcceptFriend)) {?> <form action="<?=site_url()?>friends/Accept_Friend" name="orderform" id="orderform" method="post" style="background:#CCCC99"> <input type="text" name="chId" id="chId" > <table border="0" height="50%" id="chkbox" width="50%" > <tr> <? foreach($AcceptFriend as $row) {?> <tr> <td>Name</td><td><?=$row['dFrindName'].'</br>';?></td> <td> <input type="checkbox" name="checkId" id="checkId" value="<? echo $row['dMemberId']; ?>" onClick="get_check_value()" ></td> </tr> <? }}?> </tr> <tr> <td width="10px"><input type="submit" name="submit" id="submit" class="buttn" value="AcceptFriend"></td></tr> </table> </form> This is the script i am using function get_check_value() { var c_value = ""; for (var i=0; i < document.orderform.checkId.length; i++) { if (document.orderform.checkId[i].checked) { c_value = c_value + document.orderform.checkId[i].value + "\n"; } } alert(c_value); document.getElementById('chId').value= c_value; }

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  • Input questions mysql php html

    - by Marcelo
    (Q1)Hi I'm using textbox in my project and I can't receive the values that are typed <textarea rows="5" cols="60"> Type your suggestion </textarea> <br> <input type="submit" name="sugestao" value="Submit" /> Sorry I don't know how to 'kill' html code, that's why < is missing. All I'm getting in the column of the database from this text box is "Submit", I'd like to receive whatever is written in the text area. How can I make the value equal whaterever is typed? (Q2) How can I make sure that I'll only store the same type(int,varchar,text) that I setted,declared in the database. For example: age(int), but if someone types "abc" in the input it will be stored in my database as the value 0 . How can I forbid this, and only save the age when it's just int and all the other fields(like name, email) are filled ?. And if is still possible warn the user that he is typing something wrong, don't need to say where. Sorry for any mistake in English and Thanks for the attention.

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  • How to send data after form has been validated using jQuery?

    - by Keith Donegan
    I have a simple email address sign up form as follows: <form action="" id="newsletterform" method="get"> <input type="text" name="email" class="required email" id="textnewsletter" /> <input type="submit" id="signup" /> </form> Here's what I want to be able to do: Validate the form to look for an empty string or a incorrectly filled out email address one the user clicks submit or hits enter. If one of the above happens (empty string etc), I would like to generate an error to let the user know. Then once the user fills out a correctly formed email address and hits submit (or enter) I want the form to send the email address to wherever I specify in the jQuery code and then generate a little "Thank you for signing up notice", all without reloading the browser. I have looked at too many tutorials and my eyes are pretty much aching at this stage, so please don't point me to any urls (I most likely have been there). If someone could provide a barebone outline of what to do It would be so much appreciated.

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  • Location of Embedly (JQuery-Preview) Results

    - by user749798
    Embedly/Jquery-Preview has been fantastic. However, I'm trying to change the location of the preview result, and having trouble. Right now, the result appears right below the input field...but I'd rather have it in a separate part of the page. Is there a way to do this? I've tried changing the location of the selector and loading divs, but that hasn't helped. It seems to ignore those divs and put it right below the submit button. Below is my code: <form accept-charset="UTF-8" action="private" class="new_comment" data-remote="true" id="new_comment" method="post"> <input class="photo_comm" id="comment_comment" name="comment[comment]" placeholder="add a comment or link..." size="30" type="text" /><span type="text" id="counter">1000</span> <input class="btn btn-primary btn-mini" data-disable-with="Submitting..." name="commit" type="submit" value="Post" /> </form> <!-- Placeholder that tells Preview where to put the loading icon--> <div class="loading"> <img src='http://embedly.github.com/jquery-preview/images/loading-rectangle.gif'> </div> <!-- Placeholder that tells Preview where to put the selector--> <div class="selector"></div> $('#comment_comment').preview({ key:'60f1dcdf3258476794784148a6eb65e7', // Sign up for a key: http://embed.ly/pricing selector : {type:'rich'}, preview : { submit : function(e, data){ e.preventDefault(); $.ajax({ dataType: 'script', url: this.form.attr('action'), type: 'POST', data: data }); }, }, autoplay : 0, maxwidth : 400, display : {display : 'rich'} });

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  • The post->success->data variable is empty..

    - by Asaf
    Hello, I tried sending some data like so: <form action="http://www.someurl.com/something.php" id="login"> <input type="textbox" id="UserName" value="user"> <input type="textbox" id="Password" value="password"> <input type="submit" value="submit"> </form> <div id="result"></div> <script type="text/javascript"> $('form#login').submit(function() { $.post($('form#login').attr('action'), $('form#login').serialize(), function(data) { $('#result').html(data+'222') }); return false; }); </script> Now, the value of #result div change to 222... that is: the post was successful but for some reason there is no data, and when I go directly to something.php and post manually, it does bring back data (am I mistaken or does the post(success(data)) variable returns the whole page returned after you post something? if so, how could it be?) Thank you very much for your help

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  • S.redirectTo leads always to a blank screen

    - by Jaime Ocampo
    I am now playing a little bit with lift (2.8.0), and all the features in LiftRules work as intended. But I haven't been able to use S.redirectTo at all. I always ends with a blank screen, no matter what. No error messages at all! As an example, I have the following form: ... <lift:logIn.logInForm form="post"> <p><login:name /></p> <p><login:password /></p> <p><login:submit /></p> </lift:logIn.logInForm> ... And the code is: object LogIn extends helper.LogHelper { ... def logInForm(in: NodeSeq): NodeSeq = { var name = "" var password = "" def login() = { logger.info("name: " + name) logger.info("password: " + password) if (name == "test1") S.redirectTo("/example") if (name == "test2") S.redirectTo("/example.html") if (name == "test3") S.redirectTo("example.html") S.redirectTo("/") } bind("login", in, "name" -> SHtml.text(name, name = _), "password" -> SHtml.password(password, password = _), "submit" -> SHtml.submit("Login", login)) } } The method 'login' is invoked, I can check that in the log information. But as I said, no matter which name I enter, I always end with a blank screen, although 'examples.html' is available when being accessed directly in the browser. How should I invoke S.redirectoTo in order to navigate to 'examples.html'? Also, why don't I receive an error message (I am logging at a debug level)? I think all the configuration in Boot is correct, since all LitRules examples (statelessRewrite, dispatch, viewDispatch, snippets) work fine.

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  • Drupal - Search box not working - custom theme template

    - by vr3690
    Hello, I am using a customised version of search-theme-from.tpl When I use the search box, I do get transferred to the search page. But the search does not actually take place. The search box on the search results page does work though. This is my search-them-form.tpl.php file (demo : <input type="text" name="search_theme_form_keys" id="edit-search-theme-form-keys" value="Search" title="Enter the terms you wish to search for" class="logininput" height="24px" onblur="restoreSearch(this)" onfocus="clearInput(this)" /> <input type="submit" name="op" id="edit-submit" value="" class="form-submit" style="display: none;" /> <input type="hidden" name="form_token" id="edit-search-theme-form-form-token" value="<?php print drupal_get_token('search_theme_form'); ?>" /> <input type="hidden" name="form_id" id="edit-search-theme-form" value="search_theme_form" /> There is also a javascript file involved. I guess it's use is pretty clear from the code: function trim(str) { return str.replace(/^\s+|\s+$/g, ''); } function clearInput(e) { e.value=""; // clear default text when clicked e.className="longininput_onfocus"; //change class } function restoreSearch(e) { if (trim(e.value) == '') { { e.value="Search"; // reset default text onBlur e.className="logininput"; //reset class } } } What can be the problem and how can I fix it?

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