Search Results

Search found 24214 results on 969 pages for 'login screen'.

Page 484/969 | < Previous Page | 480 481 482 483 484 485 486 487 488 489 490 491  | Next Page >

  • Need to cast to an object without knowing what type the object is

    - by jle
    I am trying to dynamically load my authentication server type based on a setting. I am hung up on how to cast to a type when I don't know the type. Type t = Type.GetType(WebConfigurationManager.AppSettings.Get("AuthenticationSvcImpl")); IAuthenticationService authCli = Activator.CreateInstance(t); return authCli.AuthenticateUser(login); I know there is Convert.ChangeType(), but that just converts to an object...

    Read the article

  • svn unix permissions

    - by Eqbal
    I am trying to set up an svn repository on a linux server. What permissions do I need to set so users within a group are able to checkout/update/add to the repository using their unix login/password over ssh on TotoiseSVN? I tried setting 770 and it does not seem to work.

    Read the article

  • How to navigate to another html page?

    - by newbie
    In my application there's a usual login page sending username and password to the server script, where it needs to be authenticated, and in case of an authentic user, the server should redirect to a page student.html. This is my code var ports = 3000; var portt = 3001; var express = require('express'); var student = require('express')(); var teacher = require('express')(); var server_s = require('http').createServer(student); var server_t = require('http').createServer(teacher); var ios = require('socket.io').listen(server_s); var iot = require('socket.io').listen(server_t); var path = require('path'); server_s.listen(ports); server_t.listen(portt); student.use(express.static(path.join(__dirname, 'public'))); student.get('/', function(req,res){ res.sendfile(__dirname + '/login.html'); }); teacher.use(express.static(path.join(__dirname, 'public'))); teacher.get('/', function(req,res){ res.sendfile(__dirname + '/mytry.html'); }); ios.sockets.on('connection', function(socket){ var username, password; socket.on('check',function(data){ username = data[0]; password = data[1]; //************* Database connection and query ************* var mysql = require('mysql'); var connection = mysql.createConnection({ host : 'localhost', user : 'user', password: '*******', database: 'my_db' }); connection.connect(); var qstring = 'SELECT s_id FROM login_student WHERE username='+username+'AND password='+password; connection.query(qstring, function(err, rows, fields) { if (err) { console.log('ERROR: ' + err); socket.emit('login_failure','DB error'); return; } console.log('The solution is: ', rows[0].solution); if (rows>0) //***** Here i want redirection to another page ****** else socket.emit('login_failure','Invalid Username or password'); }); connection.end(); }); }); iot.sockets.on('connection', function(socket){ ; }); }); Can anyone suggest what should I do?

    Read the article

  • ImageViews sometimes not displaying in FrameLayout activity

    - by Ken
    The top level layout in my activity is a framelayout. I have completed, debugged and tested this app and it works exactly like it should in all respects on my g1 and on various emulators. But on 3.7-inch displays running 2.1+, some imageviews packed in a linearlayout are periodically not visible. I know that they are there because you can touch and drag them with effect in the app. So I assume somehow they have gotten under the SurfaceView that is the main component of the app. This is apparently so even though the SurfaceView is declared in the xml prior to the LinearLayout. However, the ImageViews IN the LinearLayout are added programmatically towards the end of onCreate(). Framelayout stacks everything that is added to it, one on top of the other--the only way you will see more than one child of a frame layout is if they are smaller than the screen and are placed apart from eachother. Oddly, sometimes the imageviews ARE visible--it is random. Anyway, I've been trying to combat this with framelayout.bringChildToFront(View v) on the linearlayout without success. I wonder if anyone has any insight into how the behavior could be random like that, and how I should code these imageviews to keep this from happening, and why the problem appears only to occur on 3.7 vs 3.2 inch screens (as it happens, the two 3.2-inch screens were both htc, so vendor might be factor too). [edit] Actually, I've determined that this is a 2.2 issue, not a screen size (or even vendor) issue. Can't ensure that ImageViews added to a framelayout with a SurfaceView in it will appear on top of the surfaceview. I ran some tests in the respective onDraw() methods and the imageviews are 'visible' (0), and nothing does anything to the alpha of the drawables, which are there as well at ondraw(). [/edit] Any insight would be welcomed. Ken T.

    Read the article

  • iOS - Passing variable to view controller

    - by gj15987
    I have a view with a view controller and when I show this view on screen, I want to be able to pass variables to it from the calling class, so that I can set the values of labels etc. First, I just tried creating a property for one of the labels, and calling that from the calling class. For example: SetTeamsViewController *vc = [[SetTeamsViewController alloc] init]; vc.myLabel.text = self.teamCount; [self presentModalViewController:vc animated:YES]; [vc release]; However, this didn't work. So I tried creating a convenience initializer. SetTeamsViewController *vc = [[SetTeamsViewController alloc] initWithTeamCount:self.teamCount]; And then in the SetTeamsViewController I had - (id)initWithTeamCount:(int)teamCount { self = [super initWithNibName:nil bundle:nil]; if (self) { // Custom initialization self.teamCountLabel.text = [NSString stringWithFormat:@"%d",teamCount]; } return self; } However, this didn't work either. It's just loading whatever value I've given the label in the nib file. I've littered the code with NSLog()s and it is passing the correct variable values around, it's just not setting the label. Any help would be greatly appreciated. EDIT: I've just tried setting an instance variable in my designated initializer, and then setting the label in viewDidLoad and that works! Is this the best way to do this? Also, when dismissing this modal view controller, I update the text of a button in the view of the calling ViewController too. However, if I press this button again (to show the modal view again) whilst the other view is animating on screen, the button temporarily has it's original value again (from the nib). Does anyone know why this is?

    Read the article

  • How to parse responses from a Django server in android?

    - by primal
    Hi, In the Android application I am building, I want to be able to communicate with a local server developed in Django. (Basically a login page and a home page populated with posts and images from users) So do I need to use XML Parsers for the parsing the response from a Django server or is it possible for the server to respond with strings which can be directly used? Also what about images? Regards, Primal

    Read the article

  • iphone :- i have one webservice in that Authentication require

    - by Heart PAL
    hello, i have one webservice given by my client ... problem is this webservise require Authentication...without username and password no one get data from this url...so how can i do authentication this webservice . this is same like u r gling to login to facebook or twitter then first we enter username and password for authenticate . how can i do this same. i have username and password for this webservise can i pass this static data in code ?

    Read the article

  • How to query data from a password protected https website

    - by Addie
    I'd like my application to query a csv file from a secure website. I have no experience with web programming so I'd appreciate detailed instructions. Currently I have the user login to the site, manually query the csv, and have my application load the file locally. I'd like to automate this by having the user enter his login information, authenticating him on the website, and querying the data. The application is written in C# .NET. The url of the site is: https://www2.emidas.com/default.asp. I've tested the following code already and am able to access the file once the user has already authenticated himself and created a manual query. System.Net.WebClient Client = new WebClient(); Stream strm = Client.OpenRead("https://www3.emidas.com/users/<username>/file.csv"); Here is the request sent to the site for authentication. I've angle bracketed the real userid and password. POST /pwdVal.asp HTTP/1.1 Accept: image/jpeg, application/x-ms-application, image/gif, application/xaml+xml, image/pjpeg, application/x-ms-xbap, application/vnd.ms-excel, application/vnd.ms-powerpoint, application/msword, application/x-shockwave-flash, */* User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; Tablet PC 2.0; OfficeLiveConnector.1.4; OfficeLivePatch.1.3; .NET4.0C; .NET4.0E) Content-Type: application/x-www-form-urlencoded Accept-Encoding: gzip, deflate Cookie: ASPSESSIONID<unsure if this data contained password info so removed>; ClientId=<username> Host: www3.emidas.com Content-Length: 36 Connection: Keep-Alive Cache-Control: no-cache Accept-Language: en-US client_id=<username>&password=<password>

    Read the article

  • psql: FATAL: Ident authentication failed for user "postgres"

    - by morpheous
    I have installed PostgreSQL and pgAdminIII on my Ubuntu Karmic box. I am able to use pgAdminIII successfully (i.e. connect/log on), however when I try to login to the server using the same username/pwd on the command line (using psql), I get the error: psql: FATAL: Ident authentication failed for user "postgres" Does anyone now how to resolve this issue?

    Read the article

  • How can I use wildcard urls with Code Igniter?

    - by tarnfeld
    I am building a system that has urls like app.com/login and app.com/dothing but it will also have app.com/xOldP. The web application is build using the latest version of Code Igniter and I was wondering if there was a way to add a check in, that if the url is a controller then do that and finish, but if not, do something else (which will check the url and if its not real 404, which I can do). I was wondering how annoying this would be :/ Some sample code or links would be great!

    Read the article

  • anonymous ASP.net form with SSL

    - by user307852
    Hi I want to create contact form with SSL I have anonymous webapplication and won't be any login usecase, so whole webapplication must work via http:// but when user go to contact form, it must work via https:// I know how to do the redirect to https:// programatically, I've been searching how to configure SSL on IIS but it seems to not be the case?? I don't wont whole webappliation to work via https, only my contact form - how to do that and how o onfigure that? The data from my form will be passed to database, but it is not important here.

    Read the article

  • How to rebuild Safari Web Clip functionality in PHP

    - by Mayko
    Hi there, is there a way to rebuild Mac OSX Snow Leopard's Dashboard Widget 'Web Clip' on a PHP website? Something like a crawler or scraper. I thought about using file_get_contents to getting the page content into the page, but how do I select a section on the external page? And does this work with session/login content as well? I'm happy for any kind of suggestions! Cheers

    Read the article

  • AFNetworking PostPath php Parameters are null

    - by Alejandro Escobar
    I am trying to send a username and password from an iOS app using AFNetworking framework to a php script. The iOS app continues to receive status code 401 which I defined to be "not enough parameters". I have tried returning the "username" from the php script to the iOS app and receive . Based on what I've been investigating so far, it seems as though: 1) The php script is not decoding the POST parameters properly 2) The iOS app is not sending the POST parameters properly The following is the iOS function - (IBAction)startLoginProcess:(id)sender { NSString *usernameField = usernameTextField.text; NSString *passwordField = passwordTextField.text; NSDictionary *parameters = [NSDictionary dictionaryWithObjectsAndKeys:usernameField, @"username", passwordField, @"password", nil]; NSURL *url = [NSURL URLWithString:@"http://localhost/~alejandroe1790/edella_admin/"]; AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:url]; [httpClient defaultValueForHeader:@"Accept"]; [httpClient setParameterEncoding:AFJSONParameterEncoding]; [httpClient postPath:@"login.php" parameters:parameters success:^(AFHTTPRequestOperation *operation, id response) { NSLog(@"operation hasAcceptableStatusCode: %d", [operation.response statusCode]); } failure:^(AFHTTPRequestOperation *operation, NSError *error) { NSLog(@"Error with request"); NSLog(@"%@",[error localizedDescription]); }]; } The following is the php script function checkLogin() { // Check for required parameters if (isset($_POST["username"]) && isset($_POST["password"])) { //Put parameters into local variables $username = $_POST["username"]; $password = $_POST["password"]; $stmt = $this->db->prepare("SELECT Password FROM Admin WHERE Username=?"); $stmt->bind_param('s', $username); $stmt->execute(); $stmt->bind_result($resultpassword); while ($stmt->fetch()) { break; } $stmt->close(); // Username or password invalid if ($password == $resultpassword) { sendResponse(100, 'Login successful'); return true; } else { sendResponse(400, 'Invalid Username or Password'); return false; } } sendResponse(401, 'Not enough parameters'); return false; } I feel like I may be missing something. Any assistance would be great.

    Read the article

  • Is it possible to create an Android Service that listens for hardware key presses?

    - by VoteBrian
    I'd like to run an Android background service that will act as a keylistener from the home screen or when the phone is asleep. Is this possible? From semi-related examples online, I put together the following service, but get the error, "onKeyDown is undefined for the type Service". Does this mean it can't be done without rewriting Launcher, or is there something obvious I'm missing? public class ServiceName extends Service { @Override public void onCreate() { //Stuff } public IBinder onBind(Intent intent) { //Stuff return null; } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if(event.getAction() == KeyEvent.ACTION_DOWN) { switch(keyCode) { case KeyEvent.KEYCODE_A: //Stuff return true; case KeyEvent.KEYCODE_B: //Stuff return true; //etc. } } return super.onKeyDown(keyCode, event); } } I realize Android defaults to the search bar when you type from the home screen, but this really is just for a very particular use. I don't really expect anyone but me to want this. I just think it'd be nice, for example, to use the camera button to wake the phone.

    Read the article

  • Authorization error in facebook aplication

    - by bhaskaragr29
    require_login($required_permissions = 'email,photo_upload'); $auth= $facebook-do_get_session($_GET['auth_token']); $facebook-set_user($s['uid'], $s['session_key'], $s['expires'], $s['secret']) ? when ever i tries to login into my app it just refreshed and refresh with wih different auth_tokens. please help

    Read the article

  • Is there any restriction in generating the maximum number of keys for google maps

    - by Aruna
    Hi , I have generated a Google map key by login as a [email protected] . Is there any restriction in generating the number of keys for each user. Since we have 2 different domains and i need to generate key for that too. Actually i am not sure about of how many keys the person who used this id has created.. And is there any way to find of how many keys had already been created for the same account previously???

    Read the article

  • how to create class alert using lcdui package in blackberry

    - by Baby
    Advance Thanks.i am new to blackberry developement.i try the following code for creating alert using lcdui package.but nothing will coming when i am running Plz help me. package alertpack; import javax.microedition.lcdui.Alert; import javax.microedition.lcdui.AlertType; import javax.microedition.lcdui.Command; import javax.microedition.lcdui.CommandListener; import javax.microedition.lcdui.Display; import javax.microedition.lcdui.Displayable; import javax.microedition.lcdui.Form; import javax.microedition.lcdui.Screen; import javax.microedition.midlet.MIDlet; import javax.microedition.midlet.MIDletStateChangeException; import net.rim.device.api.ui.Color; import net.rim.device.api.ui.Graphics; public class alertclass extends MIDlet implements CommandListener { private Display display; private Alert alert; private Form form = new Form("Throw Exception"); private Command exit = new Command("Exit", Command.SCREEN, 1); //public static void main(String[] args) //{ //} private boolean exitFlag = false; public alertclass(){ display = Display.getDisplay(this); form.addCommand(exit); form.setCommandListener(this); } protected void destroyApp(boolean unconditional) throws MIDletStateChangeException { // TODO Auto-generated method stub if (unconditional == false) { throw new MIDletStateChangeException(); } } protected void pauseApp() { // TODO Auto-generated method stub } protected void startApp() throws MIDletStateChangeException { // TODO Auto-generated method stub display.setCurrent(form); } public void commandAction(Command c, Displayable d) { // TODO Auto-generated method stub if (c == exit) { try { if (exitFlag == false) { alert = new Alert("Busy", "Please try again.", null, AlertType.WARNING); alert.setTimeout(Alert.FOREVER); display.setCurrent(alert, form); destroyApp(false); } else { destroyApp(true); notifyDestroyed(); } } catch (Exception exception) { exitFlag = true; } } } }

    Read the article

  • Linux Directory Access Problem: Permission Denied """In Root"""

    - by RBA
    Hi, When login through root on HP-tru Unix server, I am trying to access a directory, it is saying "Permission Denied".. Also, an sh file is also not able to execute through same root access.. I have checked the permission of the directory as well as for sh file through ls-ltr.. It is also fine.. Root System rwx-rwx-rwx-- What could be the possible cause, and how to correct it.. Thanks.

    Read the article

  • How can i find a file in system from flex

    - by praveen
    Hi, I am loading data from one sample.xml file using http service. the xml file will generated by jsp and it is saving in one proper location like(d:/programfiles/some.xml).now when I first time login to application i need to check whether that xml file is present or not. How can I check? Please help me in this it will very help full for me.

    Read the article

  • Asp.net: Implementing Auto-Logout functionality

    - by renegadeMind
    Hi, I have to implement auto-logout functionality in one of my projects and i just cant figure out where to start looking for ideas but SO. What i need is for the application to redirect the user to the login page if the user session has expired. Please tell me as to what should be my approach to tackle this requirement. Problem Statement: If the user leaves the system for more than n minutes in any given log-in instance, the system should automatically log them off.

    Read the article

  • figuring out which field to look for a value in with SQL and perl

    - by Micah
    I'm not too good with SQL and I know there's probably a much more efficient way to accomplish what I'm doing here, so any help would be much appreciated. Thanks in advance for your input! I'm writing a short program for the local school high school. At this school, juniors and seniors who have driver's licenses and cars can opt to drive to school rather than ride the bus. Each driver is assigned exactly one space, and their DLN is used as the primary key of the driver's table. Makes, models, and colors of cars are stored in a separate cars table, related to the drivers table by the License plate number field. My idea is to have a single search box on the main GUI of the program where the school secretary can type in who/what she's looking for and pull up a list of results. Thing is, she could be typing a license plate number, a car color, make, and model, someone driver's name, some student driver's DLN, or a space number. As the programmer, I don't know what exactly she's looking for, so a couple of options come to mind for me to build to be certain I check everywhere for a match: 1) preform a couple of SELECT * FROM [tablename] SQL statements, one per table and cram the results into arrays in my program, then search across the arrays one element at a time with regex, looking for a matched pattern similar to the search term, and if I find one, add the entire record that had a match in it to a results array to display on screen at the end of the search. 2) take whatever she's looking for into the program as a scaler and prepare multiple select statements around it, such as SELECT * FROM DRIVERS WHERE DLN = $Search_Variable SELECT * FROM DRIVERS WHERE First_Name = $Search_Variable SELECT * FROM CARS WHERE LICENSE = $Search_Variable and so on for each attribute of each table, sticking the results into a results array to show on screen when the search is done. Is there a cleaner way to go about this lookup without having to make her specify exactly what she's looking for? Possibly some kind of SQL statement I've never seen before?

    Read the article

  • How do I get only two form fields to show instead of all 5 on initial page load? CSS

    - by marcamillion
    Here is the implementation: http://jsfiddle.net/AdQfB/2/ If you notice, when you click 'Login' or 'Register' before entering anything, you should see a few fields disappear and re-appear respectively. I would like for this page to display the view of just the two fields on the first load (rather than the current 5 it shows on first load), then when the user clicks the 'register' link, it shows the other 3 - for a total of 5. How do I do that? Thanks

    Read the article

< Previous Page | 480 481 482 483 484 485 486 487 488 489 490 491  | Next Page >