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• Code producing System.NullReferenceException error for Membership.GetUser(). This is VB.Net (ASP.Net 4)

  - by Derrek

  I have a Default.aspx page that is not static. I have added functionality with datalist and sqldatasources. When a user logins he/she will see items like saved workouts, saved equipment, total replys, etc... This is based on getting the currently logged in user UserID. Quite simply this works great when the user is logged in. However, I do not want to force a user to login to view the Default page because it does have functionality on it that does not require login. When a user is not logged in of course I receive the [System.NullReferenceException] error. I understand the error well but I do not know how to code to fix it. That is where I need help. I will admit I am more designer than developer. However, I do know the exception error I am receivving is caused by me not setting a value in my code when a user is not logged in. I do not know how to do that and have for a week made unsuccessful attempts at writing the code. Both sets of code below compile for VB.Net/ASP.Net 4/Visual Studio 2010 without errors. However, I still get the System.NullReferenceException error if not logged in. I know it can be done but I do not know the right syntax. If you can help please insert you code in mine or write it out. JUST TELLING ME WHERE TO GO TO FIND AN ANSWER WON'T HELP. I HAVE DONE THAT FOR 7 STRAIGHT DAYS. I APPRECIATE OUR HELP. Partial Class _Default Inherits System.Web.UI.Page Protected Sub SqlDataSource4_Selecting(ByVal sender As Object, ByVal e As SqlDataSourceCommandEventArgs) Handles SqlDataSource4.Selecting Dim MemUser As MembershipUser MemUser = Membership.GetUser() If Not MemUser Is DBNull.Value Then UserID.Text = MemUser.ProviderUserKey.ToString() e.Command.Parameters("@UserId").Value = MemUser.ProviderUserKey.ToString() End If End Sub -------------------------------------ORIGINAL CODE------------------------------- Partial Class _Default Inherits System.Web.UI.Page Protected Sub SqlDataSource4_Selecting(ByVal sender As Object, ByVal e As SqlDataSourceCommandEventArgs) Handles SqlDataSource4.Selecting Dim MemUser As MembershipUser MemUser = Membership.GetUser() UserID.Text = MemUser.ProviderUserKey.ToString() e.Command.Parameters("@UserId").Value = MemUser.ProviderUserKey.ToString() End Sub

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• HABTM selection seemingly ignores joinTable

  - by TheCapn

  I'm attempting to do a HABTM relationship between a Users table and Groups table. The problem is, that I when I issue this call: $this->User->Group->find('list'); The query that is issued is: SELECT [Group].[id] AS [Group__id], [Group].[name] AS [Group__name] FROM [groups] AS [Group] WHERE 1 = 1 I can only assume at this point that I have defined my relationship wrong as I would expect behavior to use the groups_users table that is defined on the database as per convention. My relationships: class User extends AppModel { var $name = 'User'; //...snip... var $hasAndBelongsToMany = array( 'Group' => array( 'className' => 'Group', 'foreignKey' => 'user_id', 'associationForeignKey' => 'group_id', 'joinTable' => 'groups_users', 'unique' => true, ) ); //...snip... } class Group extends AppModel { var $name = 'Group'; var $hasAndBelongsToMany = array ( 'User' => array( 'className' => 'User', 'foreignKey' => 'group_id', 'associationForeignKey' => 'user_id', 'joinTable' => 'groups_users', 'unique' => true, )); } Is my understanding of HABTM wrong? How would I implement this Many to Many relationship where I can use CakePHP to query the groups_users table such that a list of groups the currently authenticated user is associated with is returned?

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• In Rails 3, how does one render HTML within a JSON response?

  - by ylg

  I'm porting an application from Merb 1.1 / 1.8.7 to Rails 3 (beta) / 1.9.1 that uses JSON responses containing HTML fragments, e.g., a JSON container specifying an update, on a user record, and the updated user row looks like . In Merb, since whatever a controller method returns is given to the client, one can put together a Hash, assign a rendered partial to one of the keys and return hash.to_json (though that certainly may not be the best way.) In Rails, it seems that to get data back to the client one must use render and render can only be called once, so rendering the hash to json won't work because of the partial render. From reading around, it seems one could put that data into a JSON .erb view file, with <%= render partial % in and render that. Is there a Rails-way of solving this problem (return JSON containing one or more HTML fragments) other than that? In Merb: only_provides :json ... self.status = 204 # or appropriate if not async return { 'action' => 'update', 'type' => 'user', 'id' => @user.id, 'html' => partial('user_row', format: :html, user: @user) }.to_json In Rails?

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• help me to parse JSON value using JSONTouch

  - by EquinoX

  I have the following json: http://www.adityaherlambang.me/webservice.php?user=2&num=10&format=json I would like to get all the name in this data by the following code, but it gives an error. How can I fix it? NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; NSDictionary *results = [responseString JSONValue]; NSDictionary *users = [results objectForKey:@"users"] objectForKey:@"user"]; for (NSDictionary *user in users){ //NSLog(@"key:%@, value:%@", user, [user objectForKey:user]); NSString *title = [users objectForKey:@"NAME"]; NSLog(@"%@", title); } Error: 2011-01-29 00:18:50.386 NeighborMe[7763:207] -[__NSArrayM objectForKey:]: unrecognized selector sent to instance 0xb618840 2011-01-29 00:18:50.388 NeighborMe[7763:207] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[__NSArrayM objectForKey:]: unrecognized selector sent to instance 0xb618840' *** Call stack at first throw: ( 0 CoreFoundation 0x027d9b99 __exceptionPreprocess + 185 1 libobjc.A.dylib 0x0292940e objc_exception_throw + 47 2 CoreFoundation 0x027db6ab -[NSObject(NSObject) doesNotRecognizeSelector:] + 187 3 CoreFoundation 0x0274b2b6 ___forwarding___ + 966 4 CoreFoundation 0x0274ae72 _CF_forwarding_prep_0 + 50 5 NeighborMe 0x0000bd75 -[NeighborListViewController connectionDidFinishLoading:] + 226 6 Foundation 0x0007cb96 -[NSURLConnection(NSURLConnectionReallyInternal) sendDidFinishLoading] + 108 7 Foundation 0x0007caef _NSURLConnectionDidFinishLoading + 133 8 CFNetwork 0x02d8d72f _ZN19URLConnectionClient23_clientDidFinishLoadingEPNS_26ClientConnectionEventQueueE + 285 9 CFNetwork 0x02e58fcf _ZN19URLConnectionClient26ClientConnectionEventQueue33processAllEventsAndConsumePayloadEP20XConnectionEventInfoI12XClientEvent18XClientEventParamsEl + 389 10 CFNetwork 0x02e5944b _ZN19URLConnectionClient26ClientConnectionEventQueue33processAllEventsAndConsumePayloadEP20XConnectionEventInfoI12XClientEvent18XClientEventParamsEl + 1537 11 CFNetwork 0x02d82968 _ZN19URLConnectionClient13processEventsEv + 100 12 CFNetwork 0x02d827e5 _ZN17MultiplexerSource7performEv + 251 13 CoreFoundation 0x027bafaf __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 15 14 CoreFoundation 0x0271939b __CFRunLoopDoSources0 + 571 15 CoreFoundation 0x02718896 __CFRunLoopRun + 470 16 CoreFoundation 0x02718350 CFRunLoopRunSpecific + 208 17 CoreFoundation 0x02718271 CFRunLoopRunInMode + 97 18 GraphicsServices 0x030b800c GSEventRunModal + 217 19 GraphicsServices 0x030b80d1 GSEventRun + 115 20 UIKit 0x002e9af2 UIApplicationMain + 1160 21 NeighborMe 0x00001c34 main + 102 22 NeighborMe 0x00001bc5 start + 53 23 ??? 0x00000001 0x0 + 1 ) terminate called after throwing an instance of 'NSException' I really just wanted to be able to iterate through the names

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• Rails - Create if record doesn't exist or else update.....Whats Best way to do this?

  - by ChrisWesAllen

  Hi, I have a create statement for some models but its creating a record within a join table regardless if the record exist. Here is what my code looks like. @user = User.find(current_user) @event = Event.find(params[:id]) for interest in @event.interests @user.choices.create(:interest => interest, :score => 4) end The problem is it creates records no matter what. I would like it to create a record if it doesnt exist, if a record does exist I would just to it to take the attribute of the found record and add or subtract 1. So, I've been looking around and I see something called find_or_create_by. My question is what happens if it finds? Preferably if it finds,I would like to take the current :score attribute and +1. SO is it possible to find or create by id? I'm not sure what attribute I would find by since the model I'm looking at is a join model which only had id foreign keys and the score attribute. I tried @user.choices.find_or_create_by_user(:user => @user.id, :interest => interest, :score => 4) but got "undefined method `find_by_user'".....ANy ideas or help?

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• Where to create/keep secret files for license information/trials on Windows/Mac OS X/Linux?

  - by BastiBense

  I'm writing a commercial product which uses a simple registration mechanism and allows the user to use the application for a demo period before purchasing. My application must somewhere store the registration information (if entered) and/or the date of the first launch to calculate if the user is still within the demo/trail period. While I'm pretty much finished with the registration mechanism itself, I now have to find a good way to store the registration information on the user's disk. The most obvious idea would be to store the trial period in the preferences file, but since user tend to delete/tinker with those from time to time, it might be a good idea to keep the registration information in a separate, more hidden file. So here's my question: What is the best place/strategy to keep and create such hidden files on Windows, Mac OS X and Linux? Here is what came to my mind so far: Linux/Mac OS X Most Unix-like systems are rather locked down when it comes to places a user can write files to. In most cases this is only the /tmp directory and the user's home directory. I guess the easiest here is probably to create a file with a dot-prefix to make it less visible, then give it a name that won't make it obvious that it's associated with my application. Windows Probably much like Linux/Mac OS X - more recent Windows versions become more restrictive when it comes to file system permissions. Anyway, I'd like to hear your ideas and thoughs. Even better if you have already implemented something similar in the past. Thanks! Update For me the places for such files is more relevant than the discussion of the question if this way for copy protection is good or bad.

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• Help - use PHP-broswer, or proxy or get_page_contents or include page, or something else ??

  - by userlite

  Hi, I am trying to develop a web application for which I need to capture a specific user-driven event (such as mouse dblclick) occurring on a different-website page loaded through my website. What I want to do is : User visits my website - hosted by me. There, user types in any website URL (e.g.: http://www.example.com) That URL page gets loaded as is. When user double-clicks mouse over any link or image from that page, a popup/side-panel is displayed with content related to that particular image or link. I can do this with a combination of PHP get_page_contents or include-page, and javascript dblclick. However, when user clicks on any link or submits a form, the control goes to that other website, where I cannot show the side-panel. I might be able to handle the links by proxifying them when user clicks on any of them. How do I handle forms submission and other stuff ? I can use a full-featured proxy, but that will be too heavy just for the purpose of capturing the event. My question is that is there a way to write some kind of light PHP script that sits on my website - that loads other websites contents as is, but lets me capture the mouse-dblclick event to show related-content in the side panel . I have already searched the internet, but could not find anything. Any help is really appreciated. Thanks.

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• best way to avoid sql injection

  - by aauser

  I got similar domain model 1) User. Every user got many cities. @OneToMany(targetEntity=adv.domain.City.class...) 2) City. Every city got many districts @OneToMany(targetEntity=adv.domain.Distinct.class) 3) Distintc My goal is to delete distinct when user press delete button in browser. After that controller get id of distinct and pass it to bussiness layer. Where method DistinctService.deleteDistinct(Long distinctId) should delegate deliting to DAO layer. So my question is where to put security restrictions and what is the best way to accomplish it. I want to be sure that i delete distinct of the real user, that is the real owner of city, and city is the real owner of distinct. So nobody exept the owner can't delete ditinct using simple url like localhost/deleteDistinct/5. I can get user from httpSession in my controller and pass it to bussiness layer. After that i can get all cities of this user and itrate over them to be sure, that of the citie.id == distinct.city_id and then delete distinct. But it's rather ridiculous in my opinion. Also i can write sql query like this ... delete from t_distinct where t_distinct.city_id in (select t_city.id from t_city left join t_user on t_user.id = t_city.owner_id where t_user.id = ?) and t_distinct.id = ? So what is the best practice to add restrictions like this. I'm using Hibernate, Spring, Spring MVC by the way.. Thank you

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• C++: Help with cin difference between Linux and Windows

  - by Krashman5k

  I have a Win32 console program that I wrote and it works fine. The program takes input from the user and performs some calculations and displays the output - standard stuff. For fun, I am trying to get the program to work on my Fedora box but I am running into an issue with clearing cin when the user inputs something that does not match my variable type. Here is the code in question: void CParameter::setPrincipal() { double principal = 0.0; cout << endl << "Please enter the loan principal: "; cin >> principal; while(principal <= 0) { if (cin.fail()) { cin.clear(); cin.ignore(INT_MAX, '\n'); } else { cout << endl << "Plese enter a number greater than zero. Please try again." << endl; cin >> principal; } } m_Parameter = principal; } This code works in Windows. For example, if the user tries to enter a char data type (versus double) then the program informs the user of the error, resets cin, and allows the user another opportunity to enter a valid value. When I move this code to Fedora, it compiles fine. When I run the program and enter an invalid data type, the while loop never breaks to allow the user to change the input. My questions are; how do I clear cin when invalid data is inputted in the Fedora environment? Also, how should I write this code so it will work in both environments (Windows & Linux)? Thanks in advance for your help!

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• Skip subdirectory in python import

  - by jstaab

  Ok, so I'm trying to change this: app/ - lib.py - models.py - blah.py Into this: app/ - __init__.py - lib.py - models/ - __init__.py - user.py - account.py - banana.py - blah.py And still be able to import my models using from app.models import User rather than having to change it to from app.models.user import User all over the place. Basically, I want everything to treat the package as a single module, but be able to navigate the code in separate files for development ease. The reason I can't do something like add for file in __all__: from file import * into init.py is I have circular references between the model files. A fix I don't want is to import those models from within the functions that use them. But that's super ugly. Let me give you an example: user.py ... from app.models import Banana ... banana.py ... from app.models import User ... I wrote a quick pre-processing script that grabs all the files, re-writes them to put imports at the top, and puts it into models.py, but that's hardly an improvement, since now my stack traces don't show the line number I actually need to change. Any ideas? I always though init was probably magical but now that I dig into it, I can't find anything that lets me provide myself this really simple convenience.

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• What is a good solution to log the deletion of a row in MySQL?

  - by hobodave

  Background I am currently logging deletion of rows from my tickets table at the application level. When a user deletes a ticket the following SQL is executed: INSERT INTO alert_log (user_id, priority, priorityName, timestamp, message) VALUES (9, 4, 'WARN', NOW(), "TICKET: David A. deleted ticket #6 from Foo"); Please do not offer schema suggestions for the alert_log table. Fields: user_id - User id of the logged in user performing the deletion priority - Always 4 priorityName - Always 'WARN' timestamp - Always NOW() message - Format: "[NAMESPACE]: [FullName] deleted ticket #[TicketId] from [CompanyName]" NAMESPACE - Always TICKET FullName - Full name of user identified by user_id above TicketId - Primary key ID of the ticket being deleted CompanyName - Ticket has a Company via tickets.company_id Situation/Questions Obviously this solution does not work if a ticket is deleted manually from the mysql command line client. However, now I need to. The issues I'm having are as follows: Should I use a PROCEDURE, FUNCTION, or TRIGGER? -- Analysis: TRIGGER - I don't think this will work because I can't pass parameters to it, and it would trigger when my application deleted the row too. PROCEDURE or FUNCTION - Not sure. Should I return the number of deleted rows? If so, that would require a FUNCTION right? How should I account for the absence of a logged in user? -- Possibilities: Using either a PROC or FUNC, require the invoker to pass in a valid user_id Require the user to pass in a string with the name Use the CURRENT_USER - meh Hard code the FullName to just be "Database Administrator" Could the name be an optional parameter? I'm rather green when it comes to sprocs. Assuming I went with the PROC/FUNC approach, is it possible to outright restrict regular DELETE calls to this table, yet still allow users to call this PROC/FUNC to do the deletion for them? Ideally the solution is usable by my application as well, so that my code is DRY.

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• rails route question

  - by badnaam

  I am trying to build a search functionality which at a high level works like this. 1 - I have a Search model, controller with a search_set action and search views/partial to render the search. 2 - At the home page a serach form is loaded with an empty search object or a search object initialized with session[:search] (which contains user search preferences, zip code, proximity, sort order, per page etc). This form has a post(:put) action to search_set. 3 - When a registered user performs a set the params of the search form are collected and a search record is saved against that user. If a unregistered user performs a search then the search set action simply stores the params in the session[:search]. In either case, the search is executed with the given params and the results are displayed. At this point the url of in the location bar is something like.. http://localhost:3000/searches/search_set?stype=1 At this point if the user simply hits enter on the location bar, I get an error that says "No action responded to show" I am guessing because the URL contains search_set which uses a put method and even though I have a search_show (:get) action (which simply reruns the search in the session or saved in the database) does not get called. How can I handle this situation where I can route a user hitting enter into the location bar to a get method? If this does not explain the problem , please let me know I can share more details/code etc. Thanks!

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• How to use the values from session variables in jsp pages that got saved using @Scope("session") in the mvc controllers

  - by droidsites

  Doing a web site using spring mvc. I added a SignupController to handle all the sign up related requests. Once user signup I am adding that to a session using @Scope("session"). Below is the SignupController code, SignupController.java @Controller @Scope("session") public class SignupController { @Autowired SignupServiceInter signUpService; private static final Logger logger = Logger.getLogger(SignupController.class); private String sessionUser; @RequestMapping("/SignupService") public ModelAndView signUp(@RequestParam("userid") String userId, @RequestParam("password") String password,@RequestParam("mailid") String emailId){ logger.debug(" userId:"+userId+"::Password::"+password+"::"); String signupResult; try { signUpService.registerUser(userId, password,emailId); sessionUser = userId; //adding the sign up user to the session return new ModelAndView("userHomePage","loginResult","Success"); //Navigate to user Home page if everything goes right } catch (UserExistsException e) { signupResult = e.toString(); return new ModelAndView("signUp","loginResult", signupResult); //Navigate to signUp page back if user does not exist } } } I am using "sessionUser" variable to store the signed up User Id. My understanding is that when I use @Scope("session") for the controller all the instance variables will added to HttpSession. So by that understanding I tried to access this "SessionUser" in userHomePage.jsp as, userHomepage.jsp Welcome to <%=session.getAttribute("sessionUser")%> But it throws null. So my question is how to use the values from session variables in jsp pages that got saved using @Scope("session") in the mvc controllers. Note: My work around is that pass that signed User Id to jsp page through ModelAndView, but it seems passing the value like these among the pages takes me back to managing state among pages using QueryStrings days.

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• Why are some classes created on the fly and others aren't in CakePHP 1.2.7?

  - by JoseMarmolejos

  I have the following model classes: class User extends AppModel { var $name= 'User'; var $belongsTo=array('SellerType' => array('className' => 'SellerType'), 'State' => array('className' => 'State'), 'Country' => array('className' => 'Country'), 'AdvertMethod' => array('className' => 'AdvertMethod'), 'UserType' => array('className' => 'UserType')); var $hasMany = array('UserQuery' => array('className' => 'UserQuery'));} And: class UserQuery extends AppModel { var $name = 'UserQuery'; var $belongsTo = array('User', 'ResidenceType', 'HomeType');} Everything works fine with the user class and all its associations, but the UserQuery class is being completely ignored by the orm (table name user_queries and the generated queries do cast it as UserQuery. Another weird thing is that if I delete the code inside the User class I get an error, but if I do the same for the UserQuery class I get no errors. So my question is why does cakephp generate a class on the fly for the UserQuery and ignores my class, and why doesn't it generate a class on the fly for the User as well ?

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• How to get a specific attribute from an object list?

  - by anarhikos

  I've an array keeping a list of Group objects. I want to set this list to the DropDownChoice component. However I want to show the end user only the name attribute of Group objects, and then get the selected values' id attribute to add database. What to do? private List<Group> groupTypes; DatabaseApp db = new DatabaseApp(); groupTypes = db.getGroups(); groupDropDownChoice = new DropDownChoice("type", groupTypes); ... ... addUserForm.add(new Button("submit"){ @Override public void onSubmit(){ Group group = (Group) groupDropDownChoice.getModelObject(); ... ... db.addUser(group.getId(), den, name, login, email, password1); DatabaseApp.java public List<Group> getGroups() throws SQLException{ List<Group> groups = new ArrayList<Group>(); try { String query = "SELECT * FROM [GROUP]"; Statement statement = db.createStatement(); ResultSet result = statement.executeQuery(query); while(result.next()){ int id = result.getInt("ID"); String name = result.getString("NAME"); groups.add(new Group(id, name)); } result.close(); } catch (SQLException ex) { throw new SQLException(ex.getMessage()); } return groups; }

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• Rails active record association problem

  - by Harm de Wit

  Hello, I'm new at active record association in rails so i don't know how to solve the following problem: I have a tables called 'meetings' and 'users'. I have correctly associated these two together by making a table 'participants' and set the following association statements: class Meeting < ActiveRecord::Base has_many :participants, :dependent => :destroy has_many :users, :through => :participants and class Participant < ActiveRecord::Base belongs_to :meeting belongs_to :user and the last model class User < ActiveRecord::Base has_many :participants, :dependent => :destroy At this point all is going well and i can access the user values of attending participants of a specific meeting by calling @meeting.users in the normal meetingshow.html.erb view. Now i want to make connections between these participants. Therefore i made a model called 'connections' and created the columns of 'meeting_id', 'user_id' and 'connected_user_id'. So these connections are kinda like friendships within a certain meeting. My question is: How can i set the model associations so i can easily control these connections? I would like to see a solution where i could use @meeting.users.each do |user| user.connections.each do |c| <do something> end end I tried this by changing the model of meetings to this: class Meeting < ActiveRecord::Base has_many :participants, :dependent => :destroy has_many :users, :through => :participants has_many :connections, :dependent => :destroy has_many :participating_user_connections, :through => :connections, :source => :user Please, does anyone have a solution/tip how to solve this the rails way?

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• How to map this class in NHibernate (not FluentNHibernate)?

  - by JMSA

  Suppose I have a database like this: This is set up to give role-wise menu permissions. Please note that, User-table has no direct relationship with Permission-table. Then how should I map this class against the database-tables? class User { public int ID { get; set; } public string Name { get; set; } public string Username { get; set; } public string Password { get; set; } public bool? IsActive { get; set; } public IList<Role> RoleItems { get; set; } public IList<Permission> PermissionItems { get; set; } public IList<string> MenuItemKeys { get; set; } } This means, (1) Every user has some Roles. (2) Every user has some Permissions (depending on to Roles). (3) Every user has some permitted MenuItemKeys (according to Permissions). How should my User.hbm.xml look like?

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• How to convert object to string list?

  - by user1381501

  I want to get two values by using linq select query and try to convert object to string list. I am trying to convert list to list. The code as below. I got the error when I convert object to string list : return returnvalue = (List)userlist; public List<string> GetUserList(string username) { List<User> UserList = new List<User>(); List<string> returnvalue=new List<string>(); try { string returnstring = string.Empty; DataTable dt = null; dt = Library.Helper.FindUser(username, 200); foreach (DataRow dr in dt.Rows) { User user = new User(); spuser.id = dr["ID"].ToString(); spuser.name = dr["Name"].ToString(); UserList.Adduser } } catch (Exception ex) { } List<SharePointMentoinUser> userlist = UserList.Select(a => new User { name = (string)a.name, id = (string)a.id }).ToList(); **return returnvalue = (List<string>)userlist;** }

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• How to terminate a request in JSP (not the "return;")

  - by Genom

  I am programming a website with JSP. There are pages where user must be logged in to see it. If they are not logged in, they should see a login form. I have seen in a php code that you can make a .jsp page (single file), which checkes, whether the user is logged in or not. If not it will show the login form. If the user is logged in, nothing will be done. So in order to do that I use this structure in my JSPs: Headers, menus, etc. etc... normal stuff which would be shown such as body, footer to a logged in user. This structure is very easy to apply to all webpages. So I don't have to apply checking algorithm to each webpage! I can simply add this "" and the page is secure! So my problem is that if the user is not logged in, then only the log in form should be shown and the footer. So code should bypass the body. Therefore structured my checklogin.jsp so: If user is not logged in show the login form and footer and terminate request. The problem is that I don't know how to terminate the request... If I use "return;" then only the checklogin.jsp stops but server continues to process parent page! Therefore page has 2 footers! (1 from parent page and 1 from checklogin.jsp). How can I avoid this? (There is exit(); in php for this by the way!) Thanks for any suggestions!

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• WIN32 API question - Looking for answer asap

  - by Lalit_M

  We have developed a ASP.NET web application and has implemented a custom authentication solution using active directory as the credentials store. Our front end application uses a normal login form to capture the user name and password and leverages the Win32 LogonUser method to authenticate the user’s credentials. When we are calling the LogonUser method, we are using the LOGON32_LOGON_NETWORK as the logon type. The issue we have found is that user profile folders are being created under the C:\Users folder of the web server. The folder seems to be created when a new user who has never logged on before is logging in for the first time. As the number of new users logging into the application grows, disk space is shrinking due to the large number of new user folders getting created. Has anyone seen this behavior with the Win32 LogonUser method? Does anyone know how to disable this behavior? I have tried LOGON32_LOGON_BATCH but it was giving an error 1385 in authentication user. I need either of the solution 1) Is there any way to stop the folder generation. 2) What parameter I need to pass this to work? Thanks

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• login script in php using session variables

  - by kracekumar

  ? username: '; } else { $user=$_POST['user']; $query="select name from login where name='$user'"; $result=mysql_query($query) or die(mysql_error()); $rows=mysql_num_rows($result)or die(mysql_error()); session_start(); //echo "results"; $username=mysql_fetch_array($result) or die(mysql_error()); $fields=mysql_num_fields($result) or die(mysql_error()); echo "username:$username[0]"; $_SESSION['username']=$username[0]; $sesion_username=$_SESSION['username']; //echo "rows:$rows"." "."fields:$fields"; echo""."username:$sesion_username"; } ? i wanted to create a site where user can login and upload their details depending on their user name have stored their details in a database,the problem i am facing is two people 'a' and 'b' login one after other session_variable $_SESSION['username'] will have 'b's' username ,so i can't display 'a's' details now. . . . what i want to achieve is when a user logins in i want to store his name and other details in session variable and navigate him according and display his details

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• Access database Need to prevent from approving overlapping OT.Second Try with modified request Not a programmer [on hold]

  - by user2512764

  Employees Signups on company Website for advance overtime line. Access table already has overtime signups which does not require user to add the time but it requires only to add location as approved. Since this table has field Employee name, Date, start time and End time and location, All the fields has the data except for location. In the data base I have created a form based on this table. Since the table already have most of the information User only has to add location in the form field in order to approve overtime. Once user approves an overtime line for example: User approves overtime for employee name 'John' which starts on 7/1/2013 at 0400-0800, location is successfully added. When user tries to add location for John again which might has the start time for 7/1/2013 at 0600=0900. Again we are not entering Start time, End time and date it is already in the table. we are only entering location as approval. Soon user enters the location for John in the form field, since there is a conflict with previously overtime line which has already been approved. program needs to check employee name, date and time in previously approved (Added location) overtime line and The location in current record needs to be deleted and go to next record. I hope I have explained it in understandable format. Thank You,

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• jQuery validation plugin: valid() does not work with remote validation ?

  - by a-dilla

  I got started by following this awesome tutorial, but wanted to do the validation on on keyup and place my errors somewhere else. The remote validation shows its own error message at the appropriate times, making me think I had it working. But if I ask specifically if a field with remote validation is valid, it says no, actually, its not. In application.js I have this... $("#new_user").validate({ rules: { "user[login]": {required: true, minlength: 3, remote: "/live_validations/check_login"}, }, messages: { "user[login]": {required: " ", minlength: " ", remote: " "}, } }); $("#user_login").keyup(function(){ if($(this).valid()){ $(this).siblings(".feedback").html("0"); }else{ $(this).siblings(".feedback").html("1"); } }) And then this in the rails app... def check_login @user = User.find_by_login(params[:user][:login]) respond_to do |format| format.json { render :json => @user ? "false" : "true" } end end I think that my problem might have everything to do with this ticket over at jQuery, and tried to implement that code, but, being new to jQuery, it's all a bit over my head. When I say bit, I mean way way. Any ideas to fix it, or a new way to look at it, would be a big help.

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• Invalid SSH key error in juju when using it with MAAS

  - by Captain T

  This is the output of juju from a clean install with 2 nodes all running 12.04 juju bootstrap - finishes with no errors and allocates the machine to the user but still no joy after juju environment-destroy and rebuild with different users and different nodes. root@cloudcontrol:/storage# juju -v status 2012-06-07 11:19:47,602 DEBUG Initializing juju status runtime 2012-06-07 11:19:47,621 INFO Connecting to environment... 2012-06-07 11:19:47,905 DEBUG Connecting to environment using node-386077143930... 2012-06-07 11:19:47,906 DEBUG Spawning SSH process with remote_user="ubuntu" remote_host="node-386077143930" remote_port="2181" local_port="57004". The authenticity of host 'node-386077143930 (10.5.5.113)' can't be established. ECDSA key fingerprint is 31:94:89:62:69:83:24:23:5f:02:70:53:93:54:b1:c5. Are you sure you want to continue connecting (yes/no)? yes 2012-06-07 11:19:52,102 ERROR Invalid SSH key 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@658: Client environment:zookeeper.version=zookeeper C client 3.3.5 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@662: Client environment:host.name=cloudcontrol 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@669: Client environment:os.name=Linux 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@670: Client environment:os.arch=3.2.0-23-generic 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@671: Client environment:os.version=#36-Ubuntu SMP Tue Apr 10 20:39:51 UTC 2012 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@679: Client environment:user.name=sysadmin 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@687: Client environment:user.home=/root 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@699: Client environment:user.dir=/storage 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@zookeeper_init@727: Initiating client connection, host=localhost:57004 sessionTimeout=10000 watcher=0x7feb11afc6b0 sessionId=0 sessionPasswd=<null> context=0x2dc7d20 flags=0 2012-06-07 11:19:52,429:18541(0x7feb0e856700):ZOO_ERROR@handle_socket_error_msg@1579: Socket [127.0.0.1:57004] zk retcode=-4, errno=111(Connection refused): server refused to accept the client 2012-06-07 11:19:55,765:18541(0x7feb0e856700):ZOO_ERROR@handle_socket_error_msg@1579: Socket [127.0.0.1:57004] zk retcode=-4, errno=111(Connection refused): server refused to accept the client I have tried numerous ways of creating the keys with ssh-keygen -t rsa -b 2048, ssh-keygen -t rsa, ssh-keygen, and i have tried adding those to MAAS web config page, but always get the same result. I have added the appropriate public key afterwards to the ~/.ssh/authorized_keys I can also ssh to the node, but as I have not been asked to give it a user name or password or set up any sort of account, I cannot manually ssh into the node. The setup of the node is all handled by maas server. It seems like a simple error of looking at the wrong key or looking in the wrong places, only other suggestions I can find are to destroy the environment and rebuild (but that didn't work umpteen times now) or leave it to build the instance once the node has powered up, but I have left for a few hours, and left overnight to build with no luck.

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• SharePoint 2010 Hosting :: Hiding SharePoint 2010 Ribbon From Anonymous Users

  - by mbridge

  The user interface improvements in SharePoint 2010 as a whole are truly amazing. Microsoft has brought this already impressive product leaps and bounds in terms of accessibility, standards, and usability. One thing you might be aware of is the new and quite useful “ribbon” control that appears by default at the top of every SharePoint 2010 master page. Here’s a sneak peek: You’ll see this ribbon not only in the 2010 web interface, but also throughout the entire family of Office products coming out this year. Even SharePoint Designer 2010 makes use of the ribbon in a very flexible and useful way. Hiding The Ribbon In SharePoint 2010, the ribbon is used almost exclusively for content creation and site administration. It doesn’t make much sense to show the ribbon on a public-facing internet site (in fact, it can really retract from your site’s design when it appears), so you’ll probably want to hide the ribbon when users aren’t logged in. Here’s how it works: <SharePoint:SPSecurityTrimmedControl PermissionsString="ManagePermissions" runat="server">     <div id="s4-ribbonrow" class="s4-pr s4-ribbonrowhidetitle">         <!-- Ribbon code appears here... -->     </div> </SharePoint:SPSecurityTrimmedControl> In your master page, find the SharePoint ribbon by looking for the line of code that begins with <div id=”s4-ribbonrow”>. Place the SPSecurityTrimmedControl code around your ribbon to conditionally hide it based on user permissions. In our example, we’ve hidden the ribbon from any user who doesn’t have the ManagePermissions ability, which is going to be almost any user short of a site administrator. Other Permission Levels You can specify different permission levels for the SPSecurityTrimmedControl, allowing you to configure exactly who can see the SharePoint 2010 ribbon. Basically, this control will hide anything inside of it when users don’t have the specified PermissionString. The available options include: 1. List Permissions - ManageLists - CancelCheckout - AddListItems - EditListItems - DeleteListItems - ViewListItems - ApproveItems - OpenItems - ViewVersionsDeleteVersions - CreateAlerts - ViewFormPages 2. Site Permissions - ManagePermissions - ViewUsageData - ManageSubwebs - ManageWeb - AddAndCustomizePages - ApplyThemeAndBorder - ApplyStyleSheets - CreateGroups - BrowseDirectories - CreateSSCSite - ViewPages - EnumeratePermissions - BrowseUserInfo - ManageAlerts - UseRemoteAPIs - UseClientIntegration - Open - EditMyUserInfo 3. Personal Permissions - ManagePersonalViews - AddDelPrivateWebParts - UpdatePersonalWebParts You can use this control to hide anything in your master page or on related page layouts, so be sure to keep it in mind when you’re trying to hide/show things conditionally based on user permission. The One Catch You may notice that the login control (or welcome control) is actually inside the ribbon by default in SharePoint 2010. You’ll probably want to pull this control out of the ribbon and place it elsewhere on your page. Just look for the line of code that looks like this: <wssuc:Welcome id="IdWelcome" runat="server" EnableViewState=”false”/> Move this code out of the ribbon and into another location within your master page. Save your changes, check in and approve all files, and anonymous users will never know your site is built on SharePoint 2010!

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