Search Results

Search found 41660 results on 1667 pages for 'mike two'.

Page 49/1667 | < Previous Page | 45 46 47 48 49 50 51 52 53 54 55 56  | Next Page >

  • visual c# 2010 communicating between two projects

    - by cake is a joke
    I am trying to create a windows form project, and use speech recognition for the Kinect with the Kinect to Windows SDK. I have the form application project (p1) and the Kinect speech project (p2) which is a command prompt. I made it a command prompt because it was the easiest way to do things. Anyway, I have read and found two things about this. 1)I found out how to run two projects at the same time in the same solution. 2) I also found out how to add references to get classes from each project to the other. So, how would I get variables from each project? Just by using project references, or something? P2 can recognize speech and save it to variables, if that counts for anything.

    Read the article

  • compare two characters based on subset

    - by schultem
    I have a simple dataframe with two columns: df <- data.frame(x = c(1,1,2,2,3), y = c(rep(1:2,2),1), target = c('a','a','a','b','a')) I would like to compare the strings in the target column (find out whether they are equal or not, i.e., TRUE or FALSE) within every level of x (same number for x). First I would like to compare lines 1 and 2, then 3 and 4 ... My problem is that I am missing some comparisons, for example, line 5 has only one case instead of two - so it should turn out to be FALSE. Variable y indicates the first and second case within x. I played around with ddply doing something like: ddply(df, .(x), summarise, ifelse(as.character(df[df$y == '1',]$target), as.character(df[df$y == '2',]$target),0,1)) which is ugly ... and does not work ... Any insights how I could achieve this comparison? Thanks

    Read the article

  • Compare two date whit jquery

    - by Mercer
    Hello, i have two String fields who represent Date in my page and i would to compare this two fields to know if my first date < second date <tr> <td align="right">First Date: </td> <td align="left"> <html:text name="addPublicationForm" styleId="firstDate" property="firstDate" maxlength="10"/></td> </tr> <tr> <td align="right">Second Date: </td> <td align="left"> <html:text name="addPublicationForm" styleId="secondDate" property="secondDate" maxlength="10"/></td>

    Read the article

  • Criteria: search for two different entity classes...

    - by RoCMe
    Hi! I have a "super entity" SuperEntity and three entities ChildEntity1, ..., ChildEntity3 which extends the super class. It's easy to search for all entities in the database, i.e. we could use session.createCriteria(SuperEntity.class); It's no problem to search for one specific entity type, too, just replace the SuperEntity with any of the children to look for entities of that type. But I have a problem when allowing 'multiple choice' for the types. I.e., it could be neccessary to search all entities of type 1 and 2, but not of type 3. A first idea was to create two independent queries and join the results in a final list - but that would destroy the paging which uses offset and limit functionality of the database... Is there a possibility in Criteria to join two different queries in one single result list? Kind regards, RoCMe

    Read the article

  • Two way replication

    - by Nidzaaaa
    I have a little problem... I have this case: -2 server instances -2 Databases -1 Table (5 columns) From server 1 I created publication to replicate all columns of table I have in 1. DB From server 2 I created subscription to pull all columns from table which is in server 1 DB But now, I need to publicate one columns of same table from server 2 to server 1 and also it has to be in same DB... I tried with using logic and creating publication for server 2 and subscription on server 1 but there is error appearing "You have selected the Publisher as a Subscriber and entered a subscription database that is the same as the publishing database. Select another subscription database." I hope someone understood my problem and have an answer for me, thanks in advance... p.s. Ask for more info if you need ...

    Read the article

  • extract two parts of a string using regex in php

    - by Jubair
    Ok so I have this string: &lt;img src=images/imagename.gif alt='descriptive text here'&gt; and I am trying to split it up into the following two strings (array of two strings, what ever, just broken up). imagename.gif descriptive text here Note yes, its' actually the & lt; and not < same with the closing on the string. I know regex is the answer, but not the best at regext to know to pull it off in php.

    Read the article

  • Join two list comparing their elements properties

    - by 100r
    public class Person() { int ID; string Name; DateTime ChangeDate } var list1 = new List<Person> { new Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" }, new Person { ID= 2, Name = "John", ChangeDate= "2011-10-22" }, new Person { ID= 3, Name = "Mike", ChangeDate= "2011-10-23" }, new Person { ID= 4, Name = "Dave", ChangeDate= "2011-10-24" } }; var list2 = new List<Person> { new Person { ID= 1, Name = "Pete", ChangeDate= "2011-10-21" }, new Person { ID= 2, Name = "Johny", ChangeDate= "2011-10-20" }, new Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" }, new Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" } }; As output I would like to have list1 + list2 = Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" }, Person { ID= 2, Name = "John", ChangeDate= "2011-10-22" }, Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" }, Person { ID= 4, Name = "Dave", ChangeDate= "2011-10-24" } Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" } And the Algorithm is like this. Join two list. If elements of lists have same ID, compare them by ChangeDate and take the ond with bigger date. If ChangeDate are equeal take any of them but not both. Maybe its easier to concat both lists and than to filter them with lambda. I tried, but always came out with some ugly code :/ Anyone have any idea?

    Read the article

  • Why are textures always square powers of two? What if they aren't?

    - by Keavon
    Why are the resolution of textures in games always a power of two (128x128, 256x256, 512x512, 1024x1024, etc.)? Wouldn't it be smart to save on the game's file size and make the texture exactly fit the UV unwrapped model? What would happen if there was a texture that was not a power of two? Would it be incorrect to have a texture be something like 256x512, or 512x1024? Or would this cause the problems that non-power-of-two textures may cause?

    Read the article

  • Possible to set two values for two different nodes from user input in XForms?

    - by iHeartGreek
    Hi! I would like to set two values for two different nodes from user input in XForms. I am curious about how this is done, if at all possible. For example, if I have the following data model: <xf:instance id="criteria_data" xmlns=""> <criteria> <set> <root></root> <criterion></criterion> </set> </criteria> </xf:instance> <xf:instance id="choices" xmlns=""> <choices> <root label="The Choices">/AAA</root> <choice label="BBB">/@BBB</choice> </choices> </xf:instance> <xf:instance id="choices" xmlns=""> <choices> <root>/AAA</root> <choice label="BBB">/@BBB</choice> <choice label="CCC">/@CCC</choice> <choices> </xf:instance> <xf:bind id="data_criterion" nodeset="instance('criteria_data')/criteria/set/criterion"/> <xf:bind id="data_root" nodeset="instance('criteria_data')/criteria/set/root"/> <xf:bind id="choices_root" nodeset="instance('choices')/root"/> <xf:bind id="choices" nodeset="instance('choices')/choice"/> and my ui code looks like: <xf:select bind="data_criterion" appearance="full"> <xf:label>Your choices:</xf:label> <xf:itemset bind="choices"> <xf:label ref="@label"></xf:label> <xf:value ref="."></xf:value> </xf:itemset> </xf:select> But I essentially want it to be like this (though this is invalid and does not produce any xml at all): <xf:select appearance="full"> <xf:label>Your choices:</xf:label> <xf:itemset bind="choices"> <xf:label ref="@label"></xf:label> <xf:value bind="data_criterion" ref="."></xf:value> <xf:value bind="data_root" ref="instance('choices')/root"></xf:value> </xf:itemset> </xf:select> The XML output I want to achieve (if user checks "BBB"): <criteria> <set> <root>/AAA</root> <criterion>/@BBB</criterion> </set> </criteria> How can I achieve setting these two nodes for the one checkbox seletion? Hope that all made sense... Thanks! :)

    Read the article

  • Jquery / PhP / Joomla Select one of two comboboxes does not get updated

    - by bluesbrother
    I am making a Joomla component wich has 3 comboboxes/selects on the page. One with languages and 2 with subjects. If you change the language the other two get filled with the same data (the subjects in the selected language) the name of the selectbox are different but otherwise the same. I get an error for one of the subject boxes (hence the url gets red), but there is no logic in wich one will give an error. In Firebug i get the HTML back for the one without the other and this one gets updated but the other one gives nothing back. If i right click in firebug on the one that gave the error, and do "send again" it will load fine. Is their a timing problem? The change event of the language selectbox: jQuery('#cmbldcoi_ldlink_language').bind('change', function() { var cmbLangID = jQuery('#cmbldcoi_ldlink_language').val(); if (cmbLangID !=0) { getSubjectCmb_lang(cmbLangID, 'cmbldcoi_ldlink_subjects', '#ldlinksubjects'); } }); Function that requests the php file to create the html for the select: function getSubjectCmb_lang(langID, cmbName, DivWhereIn) { var xdate = new Date().getTime(); var url = 'index.php?option=com_ldadmin&view=ldadmin&format=raw&task=getcmbsubj_lang&langid=' + langID + '&cmbname=' + cmbName + '&'+ xdate; jQuery(DivWhereIn).load(url, function(){ }); } And in the php file there is a connection made to the database to ge the information to build the selectbox. I use a function for this that is okay because it makes al my selectboxes. The only place where there are problems with select boxes is on the pages that has 2 selects that need to change when a third one changed. My guess it is somewhere in the Jquery where this goes wrong. And i think it has to do with timing. But i am open for all sugestions. Thanx. UPDATE: No the ID and Name fields are different. They are named : cmbldcoi_child cmbldcoi_parent Here is my code: The change event for the first combobox which makes the other two change: jQuery('#cmbldcoi_language_chain_subj').bind('change', function(){ var langID = jQuery('#cmbldcoi_language_chain_subj').val(); if (langID != 0){ getSubjectCmb_lang(langID, 'cmbldcoi_child', '#div_cmbldcoi_child'); getSubjectCmb_lang(langID, 'cmbldcoi_parent', '#div_cmbldcoi_parent'); } }); } The function wicht calls the php file to get the info from the database: function getSubjectCmb_lang(langID, cmbName, DivWhereIn){ var xdate = new Date().getTime(); var url = 'index.php?option=com_ldadmin&view=ldadmin&format=raw&task=getcmbsubj_lang&langid=' + langID + '&cmbname=' + cmbName + '&'+ xdate; jQuery(DivWhereIn).load(url, function(){ }); } The PHP code function getcmbsubj_lang(){ $langid = JRequest::getVar('langid'); if ($langid > 0 ){ $langid = JRequest::getVar('langid'); }else{ $langid = 1; } $cmbName = JRequest::getVar('cmbname'); //$lang_sufx = self::get_#__sufx($langid); print ld_html::ld_create_cmb_html($cmbName, '#__ldcoi_subjects','id', 'subject_name', " WHERE id_language={$langid} ORDER BY subject_name" ); } There is a class wich is called ld_html wich has an funnction in it that creates a combobox. ld_html::ld_create_cmb_html() It gets an table name, id field, namefield and optional an where clause. It all works fine if there is just one combobox thats needs updating. It give a problem when there are two. Thanks for the help !

    Read the article

  • How can I use the Boost Graph Library to lay out verticies?

    - by Mike
    I'm trying to lay out vertices using the Boost Graph Library. However, I'm running into some compilation issues which I'm unsure about. Am I using the BGL in an improper manner? My code is: PositionVec position_vec(2); PositionMap position(position_vec.begin(), get(vertex_index, g)); int iterations = 100; double width = 100.0; double height = 100.0; minstd_rand gen; rectangle_topology<> topology(gen, 0, 0, 100, 100); fruchterman_reingold_force_directed_layout(g, position, topology); //Compile fails on this line The diagnostics produced by clang++(I've also tried GCC) are: In file included from test.cpp:2: /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:95:3: error: no member named 'dimensions' in 'boost::simple_point<double>' BOOST_STATIC_ASSERT (Point::dimensions == 2); ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ In file included from test.cpp:2: In file included from /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:13: In file included from /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/graph_traits.hpp:15: In file included from /Volumes/Data/mike/Downloads/boost_1_43_0/boost/tuple/tuple.hpp:24: /Volumes/Data/mike/Downloads/boost_1_43_0/boost/static_assert.hpp:118:49: note: instantiated from: sizeof(::boost::STATIC_ASSERTION_FAILURE< BOOST_STATIC_ASSERT_BOOL_CAST( B ) >)>\ ^ In file included from test.cpp:2: /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:95:3: note: instantiated from: BOOST_STATIC_ASSERT (Point::dimensions == 2); ^ ~~~~~~~ /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:95:31: note: instantiated from: BOOST_STATIC_ASSERT (Point::dimensions == 2); ~~~~~~~^ /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:417:19: note: in instantiation of template class 'boost::grid_force_pairs<boost::rectangle_topology<boost::random::linear_congruential<int, 48271, 0, 2147483647, 399268537> >, boost::iterator_property_map<__gnu_cxx::__normal_iterator<boost::simple_point<double> *, std::vector<boost::simple_point<double>, std::allocator<boost::simple_point<double> > > >, boost::vec_adj_list_vertex_id_map<boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, unsigned long>, boost::simple_point<double>, boost::simple_point<double> &> >' requested here make_grid_force_pairs(topology, position, g)), ^ /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:431:3: note: in instantiation of function template specialization 'boost::fruchterman_reingold_force_directed_layout<boost::rectangle_topology<boost::random::linear_congruential<int, 48271, 0, 2147483647, 399268537> >, boost::adjacency_list<boost::listS, boost::vecS, boost::undirectedS, boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, boost::no_property, boost::no_property, boost::listS>, boost::iterator_property_map<__gnu_cxx::__normal_iterator<boost::simple_point<double> *, std::vector<boost::simple_point<double>, std::allocator<boost::simple_point<double> > > >, boost::vec_adj_list_vertex_id_map<boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, unsigned long>, boost::simple_point<double>, boost::simple_point<double> &>, boost::square_distance_attractive_force, boost::attractive_force_t, boost::no_property>' requested here fruchterman_reingold_force_directed_layout ^ test.cpp:48:3: note: in instantiation of function template specialization 'boost::fruchterman_reingold_force_directed_layout<boost::rectangle_topology<boost::random::linear_congruential<int, 48271, 0, 2147483647, 399268537> >, boost::adjacency_list<boost::listS, boost::vecS, boost::undirectedS, boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, boost::no_property, boost::no_property, boost::listS>, boost::iterator_property_map<__gnu_cxx::__normal_iterator<boost::simple_point<double> *, std::vector<boost::simple_point<double>, std::allocator<boost::simple_point<double> > > >, boost::vec_adj_list_vertex_id_map<boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, unsigned long>, boost::simple_point<double>, boost::simple_point<double> &> >' requested here fruchterman_reingold_force_directed_layout(g, position, topology); ^ 1 error generated.

    Read the article

  • Make a Crystal Report with data fetched from two differents tables

    - by Selom
    Hi, Im using vb.net and I need to fetch data from two different tables and display it in form of report. These are the schemas and data of my two tables: CREATE TABLE personal_details (staff_ID integer PRIMARY KEY, title varchar(10), fn varchar(250), ln varchar(250), mn varchar(250), dob varchar(50), hometown varchar(250), securityno varchar(50), phone varchar(15), phone2 varchar(15), phone3 varchar(15), email varchar(250), address varchar(300), confirmation varchar(50), retirement varchar(50), designation varchar(250), region varchar(250)); INSERT INTO personal_details VALUES(1,'Mr.','Selom','AMOUZOU','Kokou','Sunday, March 28, 2010','Ho',7736,'024-747-4883','277-383-8383','027-838-3837','[email protected]','Lapaz Kum Hotel','Sunday, March 28, 2010','Sunday, March 28, 2010','Designeur','Brong Ahafo'); CREATE TABLE training( training_ID integer primary key NOT NULL, staff_ID varchar(100), training_level varchar (60), school_name varchar(100), start_date varchar(100), end_date varchar(100)); INSERT INTO training VALUES(1,1,'Primary School','New School','Feb 1955','May 1973'); INSERT INTO training VALUES(2,1,'Middle/JSS','Ipmc','Feb 1955','May 1973'); Im trying to fetch and display data from the tables above the following way: Dim rpt As New CrystalReport1() Dim da As New SQLiteDataAdapter Dim ds As New presbydbDataSet ds.EnforceConstraints = False If conn.State = ConnectionState.Closed Then conn.Open() End If Dim cmd As New SQLiteCommand("SELECT p.fn, t.training_level FROM personal_details p INNER JOIN training t ON p.staff_ID = t.staff_ID", conn) cmd.ExecuteNonQuery() da.SelectCommand = cmd da.Fill(ds) rpt.SetDataSource(ds) CrystalReportViewer1.ReportSource = rpt conn.Close() My problem is that nothing displays on the report unless I take off either the training fields or the personal_details fields from the report. Need your help. Thanks

    Read the article

  • Variable number of two-dimensional arrays into one big array

    - by qlb
    I have a variable number of two-dimensional arrays. The first dimension is variable, the second dimension is constant. i.e.: Object[][] array0 = { {"tim", "sanchez", 34, 175.5, "bla", "blub", "[email protected]"}, {"alice", "smith", 42, 160.0, "la", "bub", "[email protected]"}, ... }; Object[][] array1 = { {"john", "sdfs", 34, 15.5, "a", "bl", "[email protected]"}, {"joe", "smith", 42, 16.0, "a", "bub", "[email protected]"}, ... }; ... Object[][] arrayi = ... I'm generating these arrays with a for-loop: for (int i = 0; i < filter.length; i++) { MyClass c = new MyClass(filter[i]); //data = c.getData(); } Where "filter" is another array which is filled with information that tells "MyClass" how to fill the arrays. "getData()" gives back one of the i number of arrays. Now I just need to have everything in one big two dimensional array. i.e.: Object[][] arrayComplete = { {"tim", "sanchez", 34, 175.5, "bla", "blub", "[email protected]"}, {"alice", "smith", 42, 160.0, "la", "bub", "[email protected]"}, ... {"john", "sdfs", 34, 15.5, "a", "bl", "[email protected]"}, {"joe", "smith", 42, 16.0, "a", "bub", "[email protected]"}, ... ... }; In the end, I need a 2D array to feed my Swing TableModel. Any idea on how to accomplish this? It's blowing my mind right now.

    Read the article

  • c# Most efficient way to combine two objects

    - by Dested
    I have two objects that can be represented as an int, float, bool, or string. I need to perform an addition on these two objects with the results being the same thing c# would produce as a result. For instance 1+"Foo" would equal the string "1Foo", 2+2.5 would equal the float 5.5, and 3+3 would equal the int 6 . Currently I am using the code below but it seems like incredible overkill. Can anyone simplify or point me to some way to do this efficiently? private object Combine(object o, object o1) { float left = 0; float right = 0; bool isInt = false; string l = null; string r = null; if (o is int) { left = (int)o; isInt = true; } else if (o is float) { left = (float)o; } else if (o is bool) { l = o.ToString(); } else { l = (string)o; } if (o1 is int) { right = (int)o1; } else if (o is float) { right = (float)o1; isInt = false; } else if (o1 is bool) { r = o1.ToString(); isInt = false; } else { r = (string)o1; isInt = false; } object rr; if (l == null) { if (r == null) { rr = left + right; } else { rr = left + r; } } else { if (r == null) { rr = l + right; } else { rr = l + r; } } if (isInt) { return Convert.ToInt32(rr); } return rr; }

    Read the article

  • SQL Joining Two or More from Table B with Common Data in Table A

    - by Matthew Frederick
    The real-world situation is a series of events that each have two or more participants (like sports teams, though there can be more than two in an event), only one of which is the host of the event. There is an Event db table for each unique event and a Participant db table with unique participants. They are joined together using a Matchup table. They look like this: Event EventID (PK) (other event data like the date, etc.) Participant ParticipantID (PK) Name Matchup EventID (FK to Event table) ParicipantID (FK to Participant) Host (1 or 0, only 1 host = 1 per EventID) What I'd like to get as a result is something like this: EventID ParticipantID where host = 1 Participant.Name where host = 1 ParticipantID where host = 0 Participant.Name where host = 0 ParticipantID where host = 0 Participant.Name where host = 0 ... Where one event has 2 participants and another has 3 participants, for example, the third participant column data would be null or otherwise noticeable, something like (PID = ParticipantID): EventID PID-1(host) Name-1 (host) PID-2 Name-2 PID-3 Name-3 ------- ----------- ------------- ----- ------ ----- ------ 1 7 Lions 8 Tigers 12 Bears 2 11 Dogs 9 Cats NULL NULL I suspect the answer is reasonably straightforward but for some reason I'm not wrapping my head around it. Alternately it's very difficult. :) I'm using MYSQL 5 if that affects the available SQL.

    Read the article

  • CSS layout - Aligning two divs side by side

    - by Ronnie
    Hello, I have a small problem. I am trying to align two divs side by side using CSS, however, I would like the center div to be positioned horizontally central in the page, I achieved this by using: #page-wrap { margin 0 auto; } Thats worked fine. The second div I would like positioned to the left side of the central page wrap but I can't manage to do this using floats although I'm sure it is possible. Maybe its best to show the example of what I am describing: I would like to push the red div up alongside the white div. Here is my current CSS concerning these two divs, sidebar being the red div and page-wrap being the white div: #sidebar { width: 200px; height: 400px; background: red; float: left; } #page-wrap { margin: 0 auto; width: 600px; background: #ffffff; height: 400px; } Any help would be appreciated.

    Read the article

  • Retrive data from two tables in asp.net mvc using ADO.Net Entity Framework

    - by user192972
    Please read my question carefully and reply me. I have two tables as table1 and table2. In table1 i have columns as AddressID(Primary Key),Address1,Address2,City In table2 i have columns as ContactID(Primary Key),AddressID(Foriegn Key),Last Name,First Name. By using join operation i can retrive data from both the tables. I created a Model in my MVC Application.I can see both the tables in enitity editor. In the ViewData folder of my solution explorer i created two class as ContactViewData.cs and SLXRepository.cs In the ContactViewData.cs i have following code public IEnumerable<CONTACT> contacts { get; set; } In the SLXRepository.cs i have following code public IEnumerable<CONTACT> GetContacts() { var contact = ( from c in context.CONTACT join a in context.ADDRESS on c.ADDRESSID equals a.ADDRESSID select new { a.ADDRESS1, a.ADDRESS2, a.CITY, c.FIRSTNAME, c.LASTNAME } ); return contact; } I am getting the error in return type Cannot implicitly convert type 'System.Linq.IQueryable' to 'System.Collections.Generic.IEnumerable'. An explicit conversion exists (are you missing a cast?)

    Read the article

  • Two PickerViews in save View issue?

    - by NextRev
    I'm trying to have 2 pickerviews in the same view. It works except for two things. If one pickerview has more rows than the other the app crashes when picking an item from the pickerview with more items. Also I created an NSLog for the pickerviews and the console shows that I'm picking two items at once when in fact i'm only dealing with one pickerview. I know it sounds a bit confusing but I'm including all the code. Thank you in advance. list and list2 are NSMutableArrays list has 4 items list2 has 5 items There error: * Terminating app due to uncaught exception 'NSRangeException', reason: '* -[NSCFArray objectAtIndex:]: index (4) beyond bounds (4)' -(NSInteger)numberOfComponentsInPickerView:(UIPickerView *)thePickerView{ if([thePickerView isEqual:pickerView1 ]){ return 1; } else if([thePickerView isEqual:pickerView2]){ return 1; } else{ return 0; } } -(NSInteger)pickerView:(UIPickerView *)thePickerView numberOfRowsInComponent:(NSInteger)component{ if([thePickerView isEqual:pickerView1 ]){ return [list count]; } else if([thePickerView isEqual:pickerView2]){ return [list2 count]; } else{ return 0; } } -(NSString *)pickerView:(UIPickerView *)thePickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component{ if([thePickerView isEqual:pickerView1 ]){ return [list objectAtIndex:row]; } else if([thePickerView isEqual:pickerView2]){ return [list2 objectAtIndex:row]; } else{ return 0; } } - (void)pickerView:(UIPickerView *)thePickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component { NSLog(@"Selected item %@. Index of selected item:%i", [list objectAtIndex:row], row); NSLog(@"Selected item %@. Index of selected item:%i", [list2 objectAtIndex:row], row); NSLog(@"Selected item %@. Index of selected item:%i", [list3 objectAtIndex:row], row); if([thePickerView isEqual:pickerView1 ]){ //Do Something } else if([thePickerView isEqual:pickerView2 ]){ //Do Something } else if([thePickerView isEqual:pickerView3 ]){ //Do Something } }

    Read the article

  • Algorithm to find the percentage of how much two texts are identical

    - by qster
    What algorithm would you suggest to identify how much from 0 to 1 (float) two texts are identical? Note that I don't mean similar (ie, they say the same thing but in a different way), I mean exact same words, but one of the two texts could have extra words or words slightly different or extra new lines and stuff like that. A good example of the algorithm I want is the one google uses to identify duplicate content in websites (X search results very similar to the ones shown have been omitted, click here to see them). The reason I need it is because my website has the ability for users to post comments; similar but different pages currently have their own comments, so many users ended up copy&pasting their comments on all the similar pages. Now I want to merge them (all similar pages will "share" the comments, and if you post it on page A it will appear on similar page B), and I would like to programatically erase all those copy&pasted comments from the same user. I have quite a few million comments but speed shouldn't be an issue since this is a one time thing that will run in the background. The programming language doesn't really matter (as long as it can interface to a MySQL database), but I was thinking of doing it in C++.

    Read the article

  • jQuery: Using autocomplete to add values to two fields instead of one

    - by rayne
    I want to use the autocomplete plugin for jQuery to populate not one, but two fields when selecting one of the autocomplete values - the name of a band is entered in the #band input field, but the band url (if exists) should also automatically be added to the #url input field when selecting the band name. Right now I simply have an un-pretty list in an external php file from which the autocompleter takes it's values: $bands_sql = "SELECT bands.name, bands.url FROM bands ORDER BY name"; $bands_result = mysql_query($bands_sql) or print (mysql_error()); while ($bands_row = mysql_fetch_array($bands_result)) { $band_name = $bands_row['name']; $band_url = $bands_row['url']; echo $band_name."\n"; #needs to be replaced with an array that holds name and url } My autocomplete function looks very basic atm, but as I'm an absolute beginner when it comes to jQuery (and also clueless when it comes to PHP arrays), I have no idea how to tell it to populate two fields and not one. $(document).ready(function() { $("#band").autocomplete('/autocomplete-bands.php'); }); Is that even possible?!

    Read the article

  • Rails 3 : create two dimensional hash and add values from a loop

    - by John
    I have two models : class Project < ActiveRecord::Base has_many :ticket attr_accessible .... end class Ticket < ActiveRecord::Base belongs_to :project attr_accessible done_date, description, .... end In my ProjectsController I would like to create a two dimensional hash to get in one variable for one project all tickets that are done (with done_date as key and description as value). For example i would like a hash like this : What i'm looking for : @tickets_of_project = ["done_date_1" => ["a", "b", "c"], "done_date_2" => ["d", "e"]] And what i'm currently trying (in ProjectsController) ... def show # Get current project @project = Project.find(params[:id]) # Get all dones tickets for a project, order by done_date @tickets = Ticket.where(:project_id => params[:id]).where("done_date IS NOT NULL").order(:done_date) # Create a new hash @tickets_of_project = Hash.new {} # Make a loop on all tickets, and want to complete my hash @tickets.each do |ticket| # TO DO #HOW TO PUT ticket.value IN "tickets_of_project" WITH KEY = ticket.done_date ??** end end I don't know if i'm in a right way or not (maybe use .map instead of make a where query), but how can I complete and put values in hash by checking index if already exist or not ? Thanx :)

    Read the article

  • Obj-C: ++variable is increasing by two instead of one

    - by Eli Garfinkel
    I am writing a program that asks users yes/no questions to help them decide how to vote in an election. I have a variable representing the question number called questionnumber. Each time I go through the switch-break loop, I add 1 to the questionnumber variable so that the next question will be displayed. This works fine for the first two questions. But then it skips the third question and moves on to the fourth. When I have more questions in the list, it skips every other question. Somewhere, for some reasons, the questionnumber variable is increasing when I don't want it to. Please look at the code below and tell me what I'm doing wrong. Thank you! Eli import "MainView.h" import @implementation MainView @synthesize Question; @synthesize mispar; int conservative = 0; int liberal = 0; int questionnumber = 1; (IBAction)agreebutton:(id)sender { ++liberal; } (IBAction)disagreebutton:(id)sender { ++conservative; } (IBAction)nextbutton:(id)sender { ++questionnumber; switch (questionnumber) { case 2: Question.text = @"Congress should pass a law that would ban Americans from earning more than one hundred million dollars in any given year."; break; case 3: Question.text = @"It is not fair to admit people to a university or employ them on the basis of merit alone. Factors such as race, gender, class, and sexual orientation must also be considered."; break; case 4: Question.text = @"There are two Americas - one for the rich and one for the poor."; break; case 5: Question.text = @"Top quality health care should be free for all."; break; default: break; } } @end

    Read the article

  • randomized quicksort: probability of two elements comparison?

    - by bantu
    I am reading "Probability and Computing" by M.Mitzenmacher, E.Upfal and I have problems understanding how the probability of comparison of two elements is calculated. Input: the list (y1,y2,...,YN) of numbers. We are looking for pivot element. Question: what is probability that two elements yi and yj (ji) will be compared? Answer (from book): yi and yj will be compared if either yi or yj will be selected as pivot in first draw from sequence (yi,yi+1,...,yj-1,yj). So the probablity is: 2/(y-i+1). The problem for me is initial claim: for example, picking up yi in the first draw from the whole list will cause the comparison with yj (and vice-versa) and the probability is 2/n. So, rather the "reverse" claim is true -- none of the (yi+1,...,yj-1) elements can be selected beforeyi or yj, but the "pool" size is not fixed (in first draw it is n for sure, but on the second it is smaller). Could someone please explain this, how the authors come up with such simplified conclusion? Thank you in advance

    Read the article

  • Most efficient way to combine two objects in C#

    - by Dested
    I have two objects that can be represented as an int, float, bool, or string. I need to perform an addition on these two objects with the results being the same thing c# would produce as a result. For instance 1+"Foo" would equal the string "1Foo", 2+2.5 would equal the float 5.5, and 3+3 would equal the int 6 . Currently I am using the code below but it seems like incredible overkill. Can anyone simplify or point me to some way to do this efficiently? private object Combine(object o, object o1) { float left = 0; float right = 0; bool isInt = false; string l = null; string r = null; if (o is int) { left = (int)o; isInt = true; } else if (o is float) { left = (float)o; } else if (o is bool) { l = o.ToString(); } else { l = (string)o; } if (o1 is int) { right = (int)o1; } else if (o is float) { right = (float)o1; isInt = false; } else if (o1 is bool) { r = o1.ToString(); isInt = false; } else { r = (string)o1; isInt = false; } object rr; if (l == null) { if (r == null) { rr = left + right; } else { rr = left + r; } } else { if (r == null) { rr = l + right; } else { rr = l + r; } } if (isInt) { return Convert.ToInt32(rr); } return rr; }

    Read the article

< Previous Page | 45 46 47 48 49 50 51 52 53 54 55 56  | Next Page >