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  • Errors in c++ faq lite?

    - by Gianluca
    Hello, I'm reading questions and answers around here for a few days. I have seen the c++ faq lite at Parashift has been mentioned many times. Personally I have always considered it to be a good reference, not my favourite one but certainly useful. Here I have seen somebody advising it, but many others commenting against it instead. Somebody mentioned it's full of mistakes. Could you please point out which are the major errors in there, if any?

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  • Need help in Hashtable implementation

    - by rafael
    Hi all, i'm quite a beginner in C# , i tried to write a program that extract words from an entered string, the user has to enter a minimum length for the word to filter the words output ... my code doesn't look good or intuitive, i used two arrays countStr to store words , countArr to store word length corresponding to each word .. but the problem is i need to use hashtables instead of those two arrays , because both of their sizes are depending on the string length that the user enter , i think that's not too safe for the memory or something ? here's my humble code , again i'm trying to replace those two arrays with one hashtable , how can this be done ? using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Collections; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { int i = 0 ; int j = 0; string myString = ""; int counter = 0; int detCounter = 0; myString = Console.ReadLine(); string[] countStr = new string[myString.Length]; int[] countArr = new int[myString.Length]; Console.Write("Enter minimum word length:"); detCounter = int.Parse(Console.ReadLine()); for (i = 0; i < myString.Length; i++) { if (myString[i] != ' ') { counter++; countStr[j] += myString[i]; } else { countArr[j] = counter; counter = 0; j++; } } if (i == myString.Length) { countArr[j] = counter; } for (i = 0; i < myString.Length ; i++) { if (detCounter <= countArr[i]) { Console.WriteLine(countStr[i]); } } Console.ReadLine(); } } }

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  • Generating a python file

    - by fema
    Hi! I'm havin issues with python (imo python itself is an issue). I have a txt file, it contains a custom language and I have to translate it to a working python code. The input: import sys n = int(sys.argv[1]) ;;print "Beginning of the program!" LOOP i in range(1,n) {print "The number:";;print i} BRANCH n < 5 {print n ;;print "less than 5"} The wanted output looks exactly like this: import sys n = int(sys.argv[1]) print "Beginning of the program!" for i in range(1,n) : print "The number:" print i if n < 5 : print n print "less than 5" The name of the input file is read from parameter. The out file is out.py. In case of a wrong parameter, it gives an error message. The ;; means a new line. When I tried to do it, I made an array, I read all the lines into it, split by " ". Then I wanted to strip it from the marks I don't need. I made 2 loops, one for the lines, one for the words. So then I started to replace the things. Everything went fine until it came to the } mark. It finds it, but it can not replace or strip it. I have no more idea what to do. Could someone help me, please? Thanks in advance!

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  • display flex xml with dash

    - by user217582
    In Flex, how do I display "midi-channel" to s:Label? I tried songTitle.text = mainXML.child("movement-title").text(); it worked but unsure how to display for midi-channel part. <score-partwise> <movement-title>zsdf</movement-title> <part-list> <score-part id="P1"> <part-name>Piano</part-name> <score-instrument id="P1-I1"> <instrument-name>Acoustic Grand Piano</instrument-name> </score-instrument> <midi-instrument id="P1-I1"> <midi-channel>1</midi-channel> <midi-program>1</midi-program> </midi-instrument> </score-part> </part-list>

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  • What version of mongodb was full $text query operator introduced?

    - by Marc Maxson
    Stupid question, right? But the official docs for 'text index' say: http://docs.mongodb.org/manual/core/index-text/ Text Indexes New in version 2.4. To perform queries that access the text index, use the $text query operator. Whereas if you click on the help for searching the index you created with the $text operator, it reads: http://docs.mongodb.org/manual/reference/operator/query/text/#op._S_text $text New in version 2.6. Seems to be 2.4 but still having problems wiht it.

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  • SQL: Is there a more efficient way to calculate elapsed hours, minutes, seconds?

    - by hamlin11
    I'm using Computed Columns to provide me with the following information: Hours, Minutes, and Seconds between a Start DateTime and Finish DateTime (Where Minutes and Seconds are between 0 and 59 and Hours can be any value 0 or greater) Computed Column for Seconds: datediff(second,[Start],[Finish]) % 60 Computed Column for Minutes: floor(datediff(second,[Start],[Finish]) / 60.0) % 60 Computed Column for Hours: floor(datediff(second,[Start],[Finish]) / 3600.0) Here's the table for reference Note: I'm also calculating TotalElapsedSeconds, TotalElapsedMinutes, and TotalElapsedHours in other computed columns, but those are easy. I just feel like I might be missing out on a nice built in function in SQL.

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  • string in c++,question

    - by user189364
    Hi, I created a program in C++ that remove commas (') from a given integer. i.e. 2,00,00 would return 20000. I am not using any new space. Here is the program i created void removeCommas(string& str1,int len) { int j=0; for(int i=0;i<len;i++) { if(str1[i] == ',') continue; else { str1[j] =str1[i]; j++; } } str1[j] = '\0'; } void main() { string str1; getline(cin,str1); int i = str1.length(); removeCommas(str1,i); cout<<"the new string "<<str1<<endl; } Here is the result i get : Input : 2,000,00 String length =8 Output = 200000 0 Length = 8 My question is that why does it show the length has 8 in output and shows the rest of string when i did put a null character. It should show output as 200000 and length has 6.

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  • JsonIgnore attributes not working in ASP.NET?

    - by Geoffrey
    I've got an object in my project with circular references. I've put [JsonIgnore] above the field like so: [JsonIgnore] public virtual Foobar ChildObject { get; set; } I'm still getting circular reference errors when I serialize the object. The only fields that do not have JsonIgnore are string fields and should not cause this. Is there something else I need to do to get JsonIgnore to work? Thanks!

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  • Attempt to create nested for loops generating missing arguments error

    - by JerryK
    Am attempting to teach myself to program using Tcl. (I want to become more familiar with the language to understand someone else's code - SCID chess) The task i've set myself to motivate my learing of Tcl is to solve the 8 queens problem. My approach to creating a program is to sucessively 'prototype' a solution. So. I'm up to nesting a for loop holding the q pos on row 2 inside the for loop holding the q pos on row 1 Here is my code set allowd 1 set notallowd 0 for {set r1p 1} {$r1p <= 8} {incr r1p } { puts "1st row q placed at $r1p" ;# re-initialize r2 'free for q placemnt' array after every change of r1 q pos: for {set i 1 } {$i <= 8} {incr i} { set r2($i) $allowd } for { set r2($r1p) $notallowd ; set r2([eval $r1p-1]) $notallowd ; set r2([eval $r1p+1]) $notallowd ; set r2p 1} {$r2p <= 8} { incr r2p ;# end of 'next' arg of r2 forloop } ;# commnd arg of r2 forloop placed below: {puts "2nd row q placed at $r2p" } } My problem is that when i run the code the interpreter is aborting with the fatal error: "wrong #args should be for start test next command. I've gone over my code a few times and can't see that i've missed any of the for loop arguments.

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  • when to make a method static

    - by Don
    Hi, I'd like to know how people decide whether to define a method as static. I'm aware that a method can only be defined as static if it doesn't require access to instance fields. So lets say we have a method that does not access instance fields, do you always define such a method as static, or only if you need to call it statically (without a reference to an instance). Perhaps another way of asking the same question, is whether you use static or non-static as the default? Thanks, Don

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  • C# Dictionary<> and mutable keys

    - by Pierreten
    I was told that one of the many reasons strings were made immutable in the C# spec was to avoid the issue of HashTables having keys changed when references to the string keys altered their content. The Dictionary< type allows reference types to be used as a key. How does the dictionary avoid the issue of altered keys that lead to "misplaced" values? Is there a memberwise clone made of an object when used as a key?

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  • web services & php

    - by pareja
    Hi... I need help because I don't know about web services using php somebody help me I need to create a web services with php and I need some any reference (free) Thanks for your help

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  • Can the size of a structure change after compiled?

    - by Sarah Altiva
    Hi, suppose you have the following structure: #include <windows.h> // BOOL is here. #include <stdio.h> typedef struct { BOOL someBool; char someCharArray[100]; int someIntValue; BOOL moreBools, anotherOne, yetAgain; char someOthercharArray[23]; int otherInt; } Test; int main(void) { printf("Structure size: %d, BOOL size: %d.\n", sizeof(Test), sizeof(BOOL)); } When I compile this piece of code in my machine (32-bit OS) the output is the following: Structure size: 148, BOOL size: 4. I would like to know if, once compiled, these values may change depending on the machine which runs the program. E.g.: if I ran this program in a 64-bit machine, would the output be the same? Or once it's compiled it'll always be the same? Thank you very much, and forgive me if the answer to this question is obvious...

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  • Finding the digit root of a number

    - by Jessica M.
    Study question is to find the digit root of a already provided number. The teacher provides us with the number 2638. In order to find the digit root you have to add each digit separately 2 + 6 + 3 + 8 = 19. Then you take the result 19 and add those two digits together 1 + 9 = 10. Do the same thing again 1 + 0 = 1. The digit root is 1. My first step was to use the variable total to add up the number 2638 to find the total of 19. Then I tried to use the second while loop to separate the two digits by using the % I have to try and solve the problem by using basic integer arithmetic (+, -, *, /). 1.Is it necessary and or possible to solve the problem using nested while loops? 2.Is my math correct? 3. As I wrote it here it does not run in Eclipse. Am I using the while loops correctly? import acm.program.*; public class Ch4Q7 extends ConsoleProgram { public void run(){ println("This program attempts to find the digit root of your number: "); int n = readInt("Please enter your number: "); int total = 0; int root = total; while (n > 0 ){ total = total + (n %10); n = (n / 10); } while ( total > 0 ){ root = total; total = ((total % 10) + total / 10); } println("your root should be " + root); } }

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  • Can't get the new 2009 XAML primitives working, why?

    - by Will
    What I'd like to use: 2009 XAML primitives How it would be nice to use them: <sapv:ExpressionTextBox xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" ExpressionType="x:String" /> What actually happens: "Type reference cannot find the public type named String" The examples I see don't have updated namespaces. I tried 2009 and 2010, but to no avail. This is in VS 2010 RTM. What am I doing wrong?

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  • Which Java Service or Daemon framework would you recommend?

    - by blwy10
    I have encountered many different ways to turn a Java program into a Windows Service or a *nix daemon, such as Java Service Wrapper, Apache Commons Daemon, and so on. Barring licensing concerns (such as JSW's GPL or pay dual-license), and more advanced features, which one would you recommend? All I intend to do is convert a simple Java program into a service; I don't need anything fancy, just something that runs as a service or a daemon, so I can start it or stop it in the service manager, or it runs for the lifetime of my *nix uptime. EDIT: I've decided to make this community wiki. I didn't start this question with an intention to find an answer for a problem I really had. I was just doing some reading and researching and chanced upon this question, so I was looking for recommendations and the like. Sorry for not doing this sooner or doing this at first. I didn't know what community wiki was for when I first started, and I completely forgot about this question until now. Many thanks for the answers!

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  • Android layouts within layouts, with separate classes handling their input?

    - by Demonofloom
    Hey all, I have created a program in Java that uses Jpanels within Jpanels. One example of this is having a side view containing buttons that change the main view when pressed. The main view also has buttons that can be used to alter itself. I am trying to re-create this on the android. I have my layout set up from an xml, with a side panel containing buttons and the main view. There is another xml that contains what I want in the main view. Now I am struggling to get this separate xml to be displayed in the main view and can’t figure out how I would get the class to handle its own input. I don’t want to paste the code into the main.xml as I want to keep things object orientated and each view needs some custom elements such as different textviews. An example of what I am trying to convert for the android is below:- //The ViewInt class has its own layout ViewInt tempView = new ViewInt(i, mFloorNo); //The viewInt class is then added to the main window. mainWindowPanel.add(tempView); This small bit of code would create a view, add it to the main view and then any input in the main window is handled by that class, but at the same time any input not in this main window is handled by another class (probably the root class). Any help is greatly appreciated, thanks. To clarify: The program has a side panel layout, containing buttons. And a main view layout that is empty. I am trying to set a .xml layout to this main view layout, and have it so that if any buttons are pressed in that main view then a class for that layout will handle it.

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