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Search found 184 results on 8 pages for 'charat'.

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  • Write a program that allows the user to enter a string and then prints the letters of the String sep

    - by WM
    The output is always a String, for example H,E,L,L,O,. How could I limit the commas? I want the commas only between letters, for example H,E,L,L,O. import java.util.Scanner; import java.lang.String; public class forLoop { public static void main(String[] args) { Scanner Scan = new Scanner(System.in); System.out.print("Enter a string: "); String Str1 = Scan.next(); String newString=""; String Str2 =""; for (int i=0; i < Str1.length(); i++) { newString = Str1.charAt(i) + ","; Str2 = Str2 + newString; } System.out.print(Str2); } }

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  • Searching through Collections in Java

    - by Click Upvote
    I have a java properties file containing a key/value pair of country names and codes. I will load the contents of this file into a Collection like List or HashMap. Then, I want users to be able to search for a country, e.g if they type 'Aus' in a textbox and click submit, then I want to search through the collection I have, containing a key/value pair of country codes/names (e.g AUS=Australia), and return those countries which are found matching. Is there any more efficient way of doing this, other than looping through the elements of the collection and using charAt()?

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  • Write a file in UTF-8 using FileWriter (Java)?

    - by user1280970
    I have the following code however, I want it to write as a UTF-8 file to handle foreign characters. Is there a way of doing this, is there some need to have a parameter? I would really appreciate your help with this. Thanks. try { BufferedReader reader = new BufferedReader(new FileReader("C:/Users/Jess/My Documents/actresses.list")); writer = new BufferedWriter(new FileWriter("C:/Users/Jess/My Documents/actressesFormatted.csv")); while( (line = reader.readLine()) != null) { //If the line starts with a tab then we just want to add a movie //using the current actor's name. if(line.length() == 0) continue; else if(line.charAt(0) == '\t') { readMovieLine2(0, line, surname.toString(), forename.toString()); } //Else we've reached a new actor else { readActorName(line); } } } catch (IOException e) { e.printStackTrace(); } }

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  • How to save Chinese Characters to file with java ?

    - by Frank
    I use the following code to save Chinese characters into a .txt file, but when I opened it with wordpad, I can't read it. StringBuffer Shanghai_StrBuf=new StringBuffer("\u4E0A\u6D77"); boolean Append=true; FileOutputStream fos; fos=new FileOutputStream(FileName,Append); for (int i=0;i<Shanghai_StrBuf.length();i++) fos.write(Shanghai_StrBuf.charAt(i)); fos.close(); What can I do ? I know if I cut and paste Chinese characters into a wordpad I can save it into a .txt file. How to do that with java ?

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  • Why Doesn't This Java Code Skip Lines with #?

    - by Nathan
    I'm trying to allow an external .txt file that is read by a Java script be able to have some comments in the beginning of the file so others can easily edit it and add more to it. But if the file contains # (the sign designated for a line that is a comment) it just returns the error that there is a "Format Error in file" (the IOException - so it is getting past that first "IF"...) Can someone help? Here's the portion of the code that deals with commenting lines out of the .txt file being called earlier in the script: while ((line = br.readLine()) != null) { line = line.trim(); if (line.length() < 1 || line.charAt(0) == '#') { // ignore comments continue; } final String[] parts = line.split("="); if (parts.length != 2) { throw new IOException("Format error in file " + JLanguageTool.getDataBroker().getFromRulesDirAsUrl(getFileName()) + ", line: " + line); }

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  • Cookie value to define style on page load

    - by zac
    I am using the scripts from here http://www.quirksmode.org/js/cookies.html and have successfully created a cookie.. but am having trouble doing anything with it. I would like to have a style defined if a cookie is present. The function for the readCookie is function readCookie(name) { var nameEQ = name + "="; var ca = document.cookie.split(';'); for(var i=0;i < ca.length;i++) { var c = ca[i]; while (c.charAt(0)==' ') c = c.substring(1,c.length); if (c.indexOf(nameEQ) == 0) return c.substring(nameEQ.length,c.length); } return null; } I am trying to use it on page load with something like this window.onload=function(){ var x = readCookie('myCookieValue'); if (x) { document.getElementById('div').innerHTML = "<style type=\"text/css\">.form {display:none}</style>"; } } What would be the correct way of writing this?

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  • Get first character of each word and its position in a sentence/paragraph

    - by Radhika
    I am trying to create a map by taking the first character of each word and it's position in a sentence/paragraph. I am using regex pattern to achieve this. Regex is a costly operation. Are there are any ways to achieve this? Regex way: public static void getFirstChar(String paragraph) { Pattern pattern = Pattern.compile("(?<=\\b)[a-zA-Z]"); Map newMap = new HashMap(); Matcher fit = pattern.matcher(paragraph); while (fit.find()) { newMap.put((fit.group().toString().charAt(0)), fit.start()); } }

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  • why am i getting a null pointer when converting string to int array?

    - by Sackling
    My main method: public static void main(String[] args) { Scanner input = new Scanner(System.in); String string1; string1 = input.next(); LargeInteger firstInt = new LargeInteger(string1); System.out.printf("First integer: %s \n", firstInt.display()); } LargeInteger class: public class LargeInteger { private int[] intArray; //convert the strings to array public LargeInteger(String s) { for (int i = 0; i < s.length(); i++) { intArray[i] = Character.digit(s.charAt(i), 10); // in base 10 } } //display the strings public String display() { String result = ""; for (int i = 0; i < intArray.length; i++) { result += intArray[i]; } return result.toString(); } }

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  • Java multidimensional array and scanner novice Q

    - by Max
    I'm new to Java and trying to in essence implement a grid with a character, and if the user inputs 'w' 'a' 's' or 'd' the character moves up/down/left/right within the plane. I created a multidimensional array sized 10x10 public static String[][] grid = new String[10][10]; And then just used a for loop to print "*"s in a 10x10 grid, except for grid[a][b] which is equal to character "A" i.e. my thing to be moved around. That seemed to work alright, then I needed to detect the 'wasd' input from the user so I set up a: Scanner in = new Scanner (System.in); while (in.hasNext()) And I had then: String s = in.next(); char ch = s.charAt(0); switch (ch) but I couldn't make this work, and it wasn't because I didn't complete the "switch" statement, I did, I just see it void copying and pasting the entire thing. I'm sure its incredibly easy slight thing I am missing, can you please point it out for me?

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  • Postfix evaluation in C

    - by Andrewziac
    I’m taking a course in C and we have to make a program for the classic Postfix evaluation problem. Now, I’ve already completed this problem in java, so I know that we have to use a stack to push the numbers into, then pop them when we get an operator, I think I’m fine with all of that stuff. The problem I have been having is scanning the postfix expression in C. In java it was easier because you could use charAt and you could use the parseInt command. However, I’m not aware of any similar commands in C. So could anyone explain a method to read each value from a string in the form: 4 9 * 0 - = Where the equals is the signal of the end of the input. Any help would be greatly appreciated and thank you in advance :)

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  • When parsing XML with jquery, how can we pass the current node from within each() to another functio

    - by Johusa
    Say we have an XML document with many book nodes... When parsing XML with jquery, how can i pass the current node from each() iteration to another function that will do some stuff until something is reached and then go back to the previous function (passing along the current node from this function back to the first function)? Here something more descriptive (this is just an example out of my head, not accurate): function MyParser(x1,x2,dom) { // if i am called by anotherFunction(thisNode) proceed from the passed node dom.find('book').each(function() { var Letter = thisNode.find(author).charAt(0); if(x1 == Letter) { // print everything till the next letter (x2) anotherFunction(thisNode) } } } function anotherFunction(x2,thisNode) { //continue parsing here until you reached x2 //when x2 is reached, return to previous function passing again the current node }

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  • Java spliting strings

    - by N0b
    Hi I've got a Java problem. I'm trying split a string when ever a " " occurs, for example the sentence test abc. Then move the first letter in each word from first to last. I got the moving the letter to work on the original string using String text = JOptionPane.showInputDialog(null,"Skriv in en normal text:"); char firstLetter = text.charAt(0); normal = text.substring(1,text.length()+0) + firstLetter; So my question is how would I split the string then start moving the letters around in each part of the cut string? Thanks in advance

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  • Text + randomchar dosn't work [JavaScript]

    - by user558773
    <script> function makeid() { var text = "var text = document.write(lastNumber);"; var possible = "*+-/"; for( var i=0; i < 1; i++ ) document.write(lastNumber + possible.charAt(Math.floor(Math.random() * possible.length)); return text; } document.write(makeid(1))</script> How do i make this to type for ex: 23* 45- 13/ and so on. What is wrong? It just show me 2 numbers and no char after.

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  • Good Form for Random Number Generator?

    - by JackCJR
    I wanted to get a few opinions on doing a random number generator. I read through a couple different ways to do it and this is the way that I created after doing a little reading. Is it acceptable form? Any foreseeable issues? function master(){ function generate(){ var pickFrom= "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"; var j = pickFrom.length; var i = Math.floor(Math.random()*j+1); //Generates a random number var code = pickFrom.charAt(i) //Picks a number based on what number was picked. document.write(code) } x = 1; while(x){ generate(); x--; } } master();

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  • Converting Java code block to Objective-C

    - by user1123688
    I am trying to convert my Android app to iOS. This will be my first iOS app. I can't seem to translate this code properly. If someone wouldn't mind showing me how its done, that would be greatly appreciated. //scrambBase20 is a Byte array String descramble(String input){ char[] ret; ret = input.toCharArray(); int offset = -scrambBase20.length; for(int i=0;i<input.length();i++){ if(i%scrambBase20.length==0) offset+=scrambBase20.length; ret[scrambBase20[i%scrambBase20.length]+offset]=(char) ((byte) (input.charAt(i))^0x45); } String realRet = ""; for (char x : ret){ realRet+=x; } realRet = realRet.trim(); return realRet; }

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  • Do I have to write my own IsNumeric function?

    - by cf_PhillipSenn
    I found this function: function IsNumeric(sText) { var ValidChars = "0123456789."; var IsNumber=true; var Char; for (i = 0; i < sText.length && IsNumber == true; i++) { Char = sText.charAt(i); if (ValidChars.indexOf(Char) == -1){ IsNumber = false; } } return IsNumber; }; Q: Isn't there a built-in JavaScript function for isNumeric? Something like val()?

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  • Validate if aTextBox Value Start with a Specific Letter

    - by Vincent Maverick Durano
    In case you will be working on a page that needs to validate the first character of the TextBox entered by a user then here are two options that you can use: Option 1: Using an array   1: <asp:Content ID="Content1" ContentPlaceHolderID="HeadContent" runat="server"> 2: <script type="text/javascript"> 3: function CheckFirstChar(o) { 4: var arr = ['A', 'B', 'C', 'D']; 5: if (o.value.length > 0) { 6: for (var i = 0; i < arr.length; i++) { 7: if (o.value.charAt(0) == arr[i]) { 8: alert('Valid'); 9: return true; 10: } 11: else { 12: alert('InValid'); 13: return false; 14: } 15: } 16: } 17: } 18: </script> 19: </asp:Content> 20: <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> 21: <asp:TextBox ID="TextBox1" runat="server" onblur="return CheckFirstChar(this);"></asp:TextBox> 22: </asp:Content>   The example above uses an array of string for storing the list of  characters that a TextBox value should start with. We then iterate to the array and compare the first character of TextBox value to see if it matches any characters from the array. Option 2: Using Regular Expression (Preferred way)   1: <asp:Content ID="Content1" ContentPlaceHolderID="HeadContent" runat="server"> 2: <script type="text/javascript"> 3: function CheckFirstChar(o) { 4: pattern = /^(A|B|C|D)/; 5: if (!pattern.test(o.value)) { 6: alert('InValid'); 7: return false; 8: } else { 9: alert('Valid'); 10: return true; 11: } 12: } 13: </script> 14: </asp:Content> 15: <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> 16: <asp:TextBox ID="TextBox1" runat="server" onblur="return CheckFirstChar(this);"></asp:TextBox> 17: </asp:Content>   The example above uses regular expression with the pattern  /^(A|B|C|D)/. This will check if the TextBox value starts with A,B,C or D. Please note that it's case sensitive. If you want to allow lower case then you can alter the patter to this /^(A|B|C|D)/i. The i in the last part will cause a case-insensitive search.   That's it! I hope someone find this post useful!

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  • StringBuffer behavior in LWJGL

    - by Michael Oberlin
    Okay, I've been programming in Java for about ten years, but am entirely new to LWJGL. I have a specific problem whilst attempting to create a text console. I have built a class meant to abstract input polling to it, which (in theory) captures key presses from the Keyboard object and appends them to a StringBuilder/StringBuffer, then retrieves the completed string after receiving the ENTER key. The problem is, after I trigger the String return (currently with ESCAPE), and attempt to print it to System.out, I consistently get a blank line. I can get an appropriate string length, and I can even sample a single character out of it and get complete accuracy, but it never prints the actual string. I could swear that LWJGL slipped some kind of thread-safety trick in while I wasn't looking. Here's my code: static volatile StringBuffer command = new StringBuffer(); @Override public void chain(InputPoller poller) { this.chain = poller; } @Override public synchronized void poll() { //basic testing for modifier keys, to be used later on boolean shift = false, alt = false, control = false, superkey = false; if(Keyboard.isKeyDown(Keyboard.KEY_LSHIFT) || Keyboard.isKeyDown(Keyboard.KEY_RSHIFT)) shift = true; if(Keyboard.isKeyDown(Keyboard.KEY_LMENU) || Keyboard.isKeyDown(Keyboard.KEY_RMENU)) alt = true; if(Keyboard.isKeyDown(Keyboard.KEY_LCONTROL) || Keyboard.isKeyDown(Keyboard.KEY_RCONTROL)) control = true; if(Keyboard.isKeyDown(Keyboard.KEY_LMETA) || Keyboard.isKeyDown(Keyboard.KEY_RMETA)) superkey = true; while(Keyboard.next()) if(Keyboard.getEventKeyState()) { command.append(Keyboard.getEventCharacter()); } if (Framework.isConsoleEnabled() && Keyboard.isKeyDown(Keyboard.KEY_ESCAPE)) { System.out.println("Escape down"); System.out.println(command.length() + " characters polled"); //works System.out.println(command.toString().length()); //works System.out.println(command.toString().charAt(4)); //works System.out.println(command.toString().toCharArray()); //blank line! System.out.println(command.toString()); //blank line! Framework.disableConsole(); } //TODO: Add command construction and console management after that } } Maybe the answer's obvious and I'm just feeling tired, but I need to walk away from this for a while. If anyone sees the issue, please let me know. This machine is running the latest release of Java 7 on Ubuntu 12.04, Mate desktop environment. Many thanks.

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  • Probelm with String.split() in java

    - by Matt
    What I am trying to do is read a .java file, and pick out all of the identifiers and store them in a list. My problem is with the .split() method. If you run this code the way it is, you will get ArrayOutOfBounds, but if you change the delimiter from "." to anything else, the code works. But I need to lines parsed by "." so is there another way I could accomplish this? import java.io.BufferedReader; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.*; public class MyHash { private static String[] reserved = new String[100]; private static List list = new LinkedList(); private static List list2 = new LinkedList(); public static void main (String args[]){ Hashtable hashtable = new Hashtable(997); makeReserved(); readFile(); String line; ListIterator itr = list.listIterator(); int listIndex = 0; while (listIndex < list.size()) { if (itr.hasNext()){ line = itr.next().toString(); //PROBLEM IS HERE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! String[] words = line.split("."); //CHANGE THIS AND IT WILL WORK System.out.println(words[0]); //TESTING TO SEE IF IT WORKED } listIndex++; } } public static void readFile() { String text; String[] words; BufferedReader in = null; try { in = new BufferedReader(new FileReader("MyHash.java")); //NAME OF INPUT FILE } catch (FileNotFoundException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } try { while ((text = in.readLine()) != null){ text = text.trim(); words = text.split("\\s+"); for (int i = 0; i < words.length; i++){ list.add(words[i]); } for (int j = 0; j < reserved.length; j++){ if (list.contains(reserved[j])){ list.remove(reserved[j]); } } } } catch (IOException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } try { in.close(); } catch (IOException ex) { Logger.getLogger(MyHash.class.getName()).log(Level.SEVERE, null, ex); } } public static int keyIt (int x) { int key = x % 997; return key; } public static int horner (String word){ int length = word.length(); char[] letters = new char[length]; for (int i = 0; i < length; i++){ letters[i]=word.charAt(i); } char[] alphabet = new char[26]; String abc = "abcdefghijklmnopqrstuvwxyz"; for (int i = 0; i < 26; i++){ alphabet[i]=abc.charAt(i); } int[] numbers = new int[length]; int place = 0; for (int i = 0; i < length; i++){ for (int j = 0; j < 26; j++){ if (alphabet[j]==letters[i]){ numbers[place]=j+1; place++; } } } int hornered = numbers[0] * 32; for (int i = 1; i < numbers.length; i++){ hornered += numbers[i]; if (i == numbers.length -1){ return hornered; } hornered = hornered % 997; hornered *= 32; } return hornered; } public static String[] makeReserved (){ reserved[0] = "abstract"; reserved[1] = "assert"; reserved[2] = "boolean"; reserved[3] = "break"; reserved[4] = "byte"; reserved[5] = "case"; reserved[6] = "catch"; reserved[7] = "char"; reserved[8] = "class"; reserved[9] = "const"; reserved[10] = "continue"; reserved[11] = "default"; reserved[12] = "do"; reserved[13] = "double"; reserved[14] = "else"; reserved[15] = "enum"; reserved[16] = "extends"; reserved[17] = "false"; reserved[18] = "final"; reserved[19] = "finally"; reserved[20] = "float"; reserved[21] = "for"; reserved[22] = "goto"; reserved[23] = "if"; reserved[24] = "implements"; reserved[25] = "import"; reserved[26] = "instanceof"; reserved[27] = "int"; reserved[28] = "interface"; reserved[29] = "long"; reserved[30] = "native"; reserved[31] = "new"; reserved[32] = "null"; reserved[33] = "package"; reserved[34] = "private"; reserved[35] = "protected"; reserved[36] = "public"; reserved[37] = "return"; reserved[38] = "short"; reserved[39] = "static"; reserved[40] = "strictfp"; reserved[41] = "super"; reserved[42] = "switch"; reserved[43] = "synchronize"; reserved[44] = "this"; reserved[45] = "throw"; reserved[46] = "throws"; reserved[47] = "trasient"; reserved[48] = "true"; reserved[49] = "try"; reserved[50] = "void"; reserved[51] = "volatile"; reserved[52] = "while"; reserved[53] = "="; reserved[54] = "=="; reserved[55] = "!="; reserved[56] = "+"; reserved[57] = "-"; reserved[58] = "*"; reserved[59] = "/"; reserved[60] = "{"; reserved[61] = "}"; return reserved; } }

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  • Why do I get garbage output when printing an int[]?

    - by Kat
    My program is suppose to count the occurrence of each character in a file ignoring upper and lower case. The method I wrote is: public int[] getCharTimes(File textFile) throws FileNotFoundException { Scanner inFile = new Scanner(textFile); int[] lower = new int[26]; char current; int other = 0; while(inFile.hasNext()){ String line = inFile.nextLine(); String line2 = line.toLowerCase(); for (int ch = 0; ch < line2.length(); ch++) { current = line2.charAt(ch); if(current >= 'a' && current <= 'z') lower[current-'a']++; else other++; } } return lower; } And is printed out using: for(int letter = 0; letter < 26; letter++) { System.out.print((char) (letter + 'a')); System.out.println(": " + ts.getCharTimes(file)); } Where ts is a TextStatistic object created earlier in my main method. However when I run my program, instead of printing out the number of how often the character occurs it prints: a: [I@f84386 b: [I@1194a4e c: [I@15d56d5 d: [I@efd552 e: [I@19dfbff f: [I@10b4b2f And I don't know what I'm doing wrong.

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  • jquery tab switching links so they jump to top of page?

    - by Evan
    I was given some great help by redsquare to get this far to change jquery tabs from links within the content, but I have one more issue that I'm looking for support on... When a user clicks a link to switch to a different tab from within the content, can i get the page to jump to the top of the page? Within my demo link, scroll to the bottom of the page to click the links and they switch tabs just perfectly, which you can confirm if you scroll up. So, I'm looking for the switch to also jump the user to the top of the page, so the user doesn't have to "scroll" to the top of the page to begin reading new content. Here's my demo: http://jsbin.com/etoku3/11 Existing code: <script type="text/javascript"> $(document).ready(function() { var $tabs = $("#container-1").tabs(); var changeTab = function(ev){ ev.preventDefault(); var tabIndex = this.hash.charAt(this.hash.length-1) -1; $tabs.tabs('select', tabIndex); }; $('a.tablink').click(changeTab); }); </script> Thank you so much! Evan

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  • Objective-C : Fowler–Noll–Vo (FNV) Hash implementation

    - by Dough
    Hi ! I have a HTTP connector in my iPhone project and queries must have a parameter set from the username using the Fowler–Noll–Vo (FNV) Hash. I have a Java implementation working at this time, this is the code : long fnv_prime = 0x811C9DC5; long hash = 0; for(int i = 0; i < str.length(); i++) { hash *= fnv_prime; hash ^= str.charAt(i); } Now on the iPhone side, I did this : int64_t fnv_prime = 0x811C9DC5; int64_T hash = 0; for (int i=0; i < [myString length]; i++) { hash *= fnv_prime; hash ^= [myString characterAtIndex:i]; } This script doesn't give me the same result has the Java one. In first loop, I get this : hash = 0 hash = 100 (first letter is "d") hash = 1865261300 (for hash = 100 and fnv_prime = -2128831035 like in Java) Do someone see something I'm missing ? Thanks in advance for the help !

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  • user input question

    - by jdbeverly87
    My program checks to test if a word or phrase is a palindrome (reads the same both backward and forward, ex "racecar"). The issue I'm having is after someone enters in "racecar" getting it to actually test. In the below code, I marked where if I type in "racecar" and run, Java returns the correct answer so I know I'm right there. But what am I missing as far as entering it into the console. I think my code is ok, but maybe I have something missing or in the wrong spot? Not really looking for a new answer unless I'm missing something, but if possible perhaps a pro at this moving my code to the correct area bc I'm stuck! `import java.util.*; public class Palindrome { public static void main(String[] args) { String myInput; Scanner in = new Scanner(System.in); System.out.println("Enter a word or phrase: "); **//this asks user for input but doesn't check for whether or not it is a palindrome** myInput = in.nextLine(); in.close(); System.out.println("You entered: " + myInput); } { String s="racecar"; **//I can type a word here and it works but I need** int i; **//I need it to work where I ask for the input** int n=s.length(); String str=""; for(i=n-1;i>=0;i--) str=str+s.charAt(i); if(str.equals(s)) System.out.println(s+ " is a palindrome"); else System.out.println(s+ " is not a palindrome"); } }` I'm new at programming so I'm hoping what I got is ok. I know the palindrome test works I'm just needing helping having it test thru where I'm entering it into the console. Thanks

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  • Flex textarea control not updating properly.

    - by ielashi
    I am writing a flex application that involves modifying a textarea very frequently. I have encountered issues with the textarea sometimes not displaying my modifications. The following actionscript code illustrates my problem: <?xml version="1.0" encoding="utf-8"?> <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" minWidth="955" minHeight="600"> <mx:TextArea x="82" y="36" width="354" height="291" id="textArea" creationComplete="initApp()"/> <mx:Script> <![CDATA[ private var testSentence:String = "The big brown fox jumps over the lazy dog."; private var testCounter:int = 0; private function initApp():void { var timer:Timer = new Timer(10); timer.addEventListener(TimerEvent.TIMER, playSentence); timer.start(); } private function playSentence(event:TimerEvent):void { textArea.editable = false; if (testCounter == testSentence.length) { testCounter = 0; textArea.text += "\n"; } else { textArea.text += testSentence.charAt(testCounter++); } textArea.editable = true; } ]]> </mx:Script> </mx:Application> When you run the above code in a flex project, it should repeatedly print, character by character, the sentence "The big brown fox jumps over the lazy dog.". But, if you are typing into the textarea at the same time, you will notice the text the timer prints is distorted. I am really curious as to why this happens. The single-threaded nature of flex and disabling user input for the textarea when I make modifications should prevent this from happening, but for some reason this doesn't seem to be working. I must note too that, when running the timer at larger intervals (around 100ms) it seems to work perfectly, so I am tempted to think it's some kind of synchronization issue in the internals of the flex framework. Any ideas on what could be causing the problem?

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  • Sort ArrayList alphabetically

    - by relyt
    I'm trying to find all permutations of a string and sort them alphabetically. This is what I have so far: public class permutations { public static void main(String args[]) { Scanner s = new Scanner(System.in); System.out.print("Enter String: "); String chars = s.next(); findPerms("", chars); } public static void findPerms(String mystr, String chars) { List<String> permsList = new ArrayList<String>(); if (chars.length() <= 1) permsList.add(mystr + chars); //System.out.print(mystr + chars + " "); else for (int i = 0; i < chars.length(); i++) { String newString = chars.substring(0, i) + chars.substring(i + 1); findPerms(mystr + chars.charAt(i), newString); } Collections.sort(permsList); for(int i=0; i<permsList.size(); i++) { System.out.print(permsList.get(i) + " "); } } } IF I enter a string "toys" I get: toys tosy tyos tyso tsoy tsyo otys otsy oyts oyst osty osyt ytos ytso yots yost ysto ysot stoy styo soty soyt syto syot What am I doing wrong. How can I get them in alphabetical order? Thanks!

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