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  • ASP.NET - FileUpload with PostBack Trigger

    - by Echilon
    I have an UpdatePanel which has an upload control and a button to upload. The button is set as a trigger, but the event handler for the button fails to execute on the first PostBack. My ASPX code is: <asp:UpdatePanel ID="updPages" runat="server" UpdateMode="Conditional"> <ContentTemplate> <div class="tabs"> <ul> <li><asp:LinkButton ID="lnkContentsPages" runat="server" OnClick="updateContents" CommandArgument="pages">Pages</asp:LinkButton></li> <%-- these tabs change the ActiveViewIndex to show a different UserControl --%> <li><asp:LinkButton ID="lnkContentsImages" runat="server" OnClick="updateContents" CommandArgument="images">Images</asp:LinkButton></li> </ul> <div class="tabbedContent"> <asp:MultiView runat="server" ID="mltContentsInner" ActiveViewIndex="0"> <asp:View ID="viwContentsImages" runat="server"> // ajax usercontrol for a list of images - works fine with ajax <fieldset> <legend>Upload New</legend> <div class="formRow"> <asp:Label ID="lblFile" runat="server" Text="Filename" AssociatedControlID="uplFile" /> <asp:FileUpload ID="uplFile" runat="server" /> </div> <div class="formRow"> <asp:Label ID="lblImageDescription" runat="server" Text="Description" AssociatedControlID="txtImageDescription" /> <asp:TextBox runat="server" ID="txtImageDescription" /> </div> <asp:Button ID="btnUpload" runat="server" Text="Upload" CssClass="c3button btnUpload" CausesValidation="false" OnClick="btnUpload_Click" /> </fieldset> </asp:View> <asp:View ID="viwContentsPages" runat="server"> // ajax usercontrol - works fine with ajax </asp:View> </asp:MultiView> </div> </div> </ContentTemplate> <Triggers> <asp:PostBackTrigger ControlID="btnUpload" /> </Triggers> </asp:UpdatePanel> The button works without fail on the second and subsequent times, just not the first. Is there any reason for this?

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  • Basic File upload in GWT

    - by Maksim
    I'm trying to figure out how to upload one file using GWTs FileUpload widget. I'm using GWT and Google AppEngine with Java but I would like to upload file to my own Linux server. I have the following code already but now I can't figure out how to submit my file to the Google AppServer server and save it to another server: public class FileUploader{ private ControlPanel cp; private FormPanel form = new FormPanel(); private FileUpload fu = new FileUpload(); public FileUploader(ControlPanel cp) { this.cp = cp; this.cp.setPrimaryArea(getFileUploaderWidget()); } @SuppressWarnings("deprecation") public Widget getFileUploaderWidget() { form.setEncoding(FormPanel.ENCODING_MULTIPART); form.setMethod(FormPanel.METHOD_POST); // form.setAction(/* WHAT SHOULD I PUT HERE */); VerticalPanel holder = new VerticalPanel(); fu.setName("upload"); holder.add(fu); holder.add(new Button("Submit", new ClickHandler() { public void onClick(ClickEvent event) { GWT.log("You selected: " + fu.getFilename(), null); form.submit(); } })); form.addSubmitHandler(new FormPanel.SubmitHandler() { public void onSubmit(SubmitEvent event) { if (!"".equalsIgnoreCase(fu.getFilename())) { GWT.log("UPLOADING FILE????", null); // NOW WHAT???? } else{ event.cancel(); // cancel the event } } }); form.addSubmitCompleteHandler(new FormPanel.SubmitCompleteHandler() { public void onSubmitComplete(SubmitCompleteEvent event) { Window.alert(event.getResults()); } }); form.add(holder); return form; } } Now, what do I need to do next? What do i need to put in web.xml and how do I write my servlet so i can store file and return url of that object (if possible)

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  • FindControl in DataList Edit Mode

    - by Doug
    As a new .net/C# web begginner, I always get tripped up when I try to use FindControl. Blam -flat on my face. Here is my current FindControl problem: I have an .aspx page and Form, then ajax updatePanel, inside it there is my DataList (DataList1) that has an EditItemTemplate: that has the following: <EditItemTemplate> <asp:Label ID="thumbnailUploadLabel" runat="server" text="Upload a new thumbnail image:"/><br /> <asp:FileUpload ID="thumbnailImageUpload" runat="server" /> <asp:Button ID="thunbnailImageUploadButton" runat="server" Text="Upload Now" OnClick="thumbnailUpload"/><br /> </EditItemTemplate> In my C# code behind I have the OnClick code for the fileUpload object: protected void thumbnailUpload(object s, EventArgs e) { if (thumbnailImageUpload.HasFile) { //get name of the file & upload string imageName = thumbnailImageUpload.FileName; thumbnailImageUpload.SaveAs(MapPath("../../images/merch_sm/" + imageName)); //let'em know that it worked (or didn't) thumbnailUploadLabel.Text = "Image " + imageName + "has been uploaded."; } else { thumbnailUploadLabel.Text = "Please choose a thumbnail image to upload."; } So of course I'm getting "Object reference not set to an instance of an object" for the FileUpload and the Label. What is the correct syntax to find these controls, before dealing with them in the OnClick event? The only way Ive used FindControl is something like: label thumbnailUploadLabel = DataList1.FindControl("thumbnailUploadLabel") as Label; But of course this is throwing the "Object reference not set to an instance of an object" error. Any help is very much appreciated. (I've also seen the 'recursive' code out there that is supposed to make using FindControl easier. Ha! I'm so green at C# that I don't even know how to incorporate those into my project.) Thanks to all for taking a look at this.

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  • JavaFX: File upload to REST service / servlet fails because of missing boundary

    - by spa
    I'm trying to upload a file using JavaFX using the HttpRequest. For this purpose I have written the following function. function uploadFile(inputFile : File) : Void { // check file if (inputFile == null or not(inputFile.exists()) or inputFile.isDirectory()) { return; } def httpRequest : HttpRequest = HttpRequest { location: urlConverter.encodeURL("{serverUrl}"); source: new FileInputStream(inputFile) method: HttpRequest.POST headers: [ HttpHeader { name: HttpHeader.CONTENT_TYPE value: "multipart/form-data" } ] } httpRequest.start(); } On the server side, I am trying to handle the incoming data using the Apache Commons FileUpload API using a Jersey REST service. The code used to do this is a simple copy of the FileUpload tutorial on the Apache homepage. @Path("Upload") public class UploadService { public static final String RC_OK = "OK"; public static final String RC_ERROR = "ERROR"; @POST @Produces("text/plain") public String handleFileUpload(@Context HttpServletRequest request) { if (!ServletFileUpload.isMultipartContent(request)) { return RC_ERROR; } FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List<FileItem> items = null; try { items = upload.parseRequest(request); } catch (FileUploadException e) { e.printStackTrace(); return RC_ERROR; } ... } } However, I get a exception at items = upload.parseRequest(request);: org.apache.commons.fileupload.FileUploadException: the request was rejected because no multipart boundary was found I guess I have to add a manual boundary info to the InputStream. Is there any easy solution to do this? Or are there even other solutions?

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  • java.lang.ClassNotFoundException: org.apache.commons.logging.LogFactory

    - by Sanjeev
    I am using My-eclipse and doing a struts project there is no syntax error but on starting tomcat server the following error appear in console. java.lang.ClassNotFoundException: org.apache.commons.logging.LogFactory and javax.servlet.UnavailableException: Parsing error processing resource path jndi:/localhost/strutspro/WEB-INF/struts-config.xml any idea whats the problem.

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  • Page appears indexed in Google but not findable for any search terms?

    - by Jeff Atwood
    (Note that I am going to use screenshots here because I suspect writing about this will change the behavior over time.) If you do a Google search for uiviewcontroller best practices either with or without the quotes, you end up with results like this: Note that none of these pages resolve to the actual Stack Overflow question containing those words in the title. They resolve to either a) sites that are mirroring our creative commons data and correctly pointing back to the source question without nofollow, as properly specified by our attribution requirements or b) our own internal links to the question, but not the actual question itself. The actual page with the title ... Custom UIView and UIViewController best practices? ... does exist at this URL ... http://stackoverflow.com/questions/3300183/custom-uiview-and-uiviewcontroller-best-practices ... and apparently it is present in Google's index! But why does it not appear when we search for uiviewcontroller best practices ? We know that Google contains this page in its index Our search terms match the title of the question Stack Overflow has much higher pagerank than the other sites that are mirroring this question under Creative Commons I don't get it. What are we doing wrong here?

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  • Software licensing template that gives room for restricting usage to certain industries/uses of software/source

    - by BSara
    *Why this question is not a duplicate of the questions specified as such: I did not ask if there was a license that restricted specific uses and I did not ask if I could rewrite every line of any open source project. I asked very specifically: "Does there exist X? If not, can I Y with Z?". As far as I can tell, the two questions that were specified as duplicates do not answer my specific question. Please remove the duplicate status placed on the question. I'm developing some software that I would like to be "semi" open source. I would like to allow for anyone to use my software/source unless they are using the software/source for certain purposes. For example, I don't want to allow usage of the software/source if it is being used to create, distribute, view or otherwise support pornography, illegal purposes, etc. I'm no lawyer and couldn't ever hope to write a license myself nor do I have to time to figure how to best do this. My question is this: Does there exist a freely available license or a template for a license that I can use to license my software under they conditions explained above just like one can use the Creative Commons licenses? If not, am I allowed to just alter one of Creative Commons licenses to meet my needs?

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  • Groovy GDK equivalent of Apache Commons StringUtils.capitalize(str) or Perl's ucfirst(str)

    - by knorv
    Yes/no-question: Is there a Groovy GDK function to capitalize the first character of a string? I'm looking for a Groovy equivalent of Perl's ucfirst(..) or Apache Commons StringUtils.capitalize(str) (the latter capitalizes the first letter of all words in the input string). I'm currently coding this by hand using .. str = str[0].toUpperCase() + str[1 .. str.size() - 1] .. which works, but I assume there is a more Groovy way to do it. I'd imagine ucfirst(..) being a more common operation than say center(..) which is a standard method in the Groovy GDK (see http://groovy.codehaus.org/groovy-jdk/java/lang/String.html).

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  • Download file using java apache commons?

    - by Kyle
    How can I use the library to download a file and print out bytes saved? I tried using import static org.apache.commons.io.FileUtils.copyURLToFile; public static void Download() { URL dl = null; File fl = null; try { fl = new File(System.getProperty("user.home").replace("\\", "/") + "/Desktop/Screenshots.zip"); dl = new URL("http://ds-forums.com/kyle-tests/uploads/Screenshots.zip"); copyURLToFile(dl, fl); } catch (Exception e) { System.out.println(e); } } but I cannot display bytes or a progress bar. Which method should I use?

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  • apache commons http client efficiency

    - by wo_shi_ni_ba_ba
    I use apache commons http client to send data via post every second, is there a way to make the following code more efficient? I know http is stateless, but is there anything I can do to improve since the base url is always the same in this case(only the parameter value change. private void sendData(String s){ try { HttpClient client = getHttpClient(); HttpPost method = new HttpPost("http://192.168.1.100:8080/myapp"); System.err.println("send to server "+s); List formparams = new ArrayList(); formparams.add(new BasicNameValuePair("packet", s)); UrlEncodedFormEntity entity = new UrlEncodedFormEntity(formparams, "UTF-8"); method.setEntity(entity); HttpResponse resp=client.execute(method); String res = EntityUtils.toString(resp.getEntity()); System.out.println(res); } catch (Exception e) { e.printStackTrace(); } } private HttpClient getHttpClient() { if(httpClient==null){ httpClient = new DefaultHttpClient(); } return httpClient; }

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  • Why can't upload three files with FileUpload ?

    - by Valter Henrique
    Hi everyone, i'm trying to upload three images to my server, is working, but upload always the last file selected by the user, not the three selected. Here's my code: protected void doPost(HttpServletRequest request, HttpServletResponse response){ boolean multipart = ServletFileUpload.isMultipartContent(request); if (multipart) { DiskFileItemFactory fileItemFactory = new DiskFileItemFactory(); fileItemFactory.setSizeThreshold(5 * 1024 * 1024); //5 MB fileItemFactory.setRepository(tmpDir); ServletFileUpload uploadHandler = new ServletFileUpload(fileItemFactory); try { List items = uploadHandler.parseRequest(request); Iterator itr = items.iterator(); while (itr.hasNext()) { FileItem item = (FileItem) itr.next(); File file = new File(dir, generateNewName()); item.write(file); } } catch (FileUploadException ex) { } catch (Exception ex) { } } } -- UPDATE: <html> <head> <title>Upload</title> </head> <body> <form action="Upload" method="post" enctype="multipart/form-data"> <input type="file" name="file1" /> <br /> <input type="file" name="file2" /> <br /> <input type="file" name="file3" /> <br /> <input type="submit" value="Enviar" /> </form> </body> </html> Best regards, Valter Henrique.

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  • How to change fileupload name

    - by Domnic
    im using following code to upload protected void UploadButton_Click(object sender, EventArgs e) { if(FileUploadControl.HasFile) { try { string filename = Path.GetFileName(FileUploadControl.FileName); FileUploadControl.SaveAs(Server.MapPath("~/") + filename); StatusLabel.Text = "Upload status: File uploaded!"; } catch(Exception ex) { StatusLabel.Text = "Upload status: The file could not be uploaded. The following error occured: " + ex.Message; } } } i want to cahnge upload file name...i have to assign file name for every uploaded file how?

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  • The SaveAs method is configured to require a rooted path, and the path <blah> is not rooted.

    - by Jen
    OK I've seen a few people with this issue - but I'm already using a file path, not a relative path. My code works fine on my PC, but when another developer goes to upload an image they get this error. I thought it was a security permission thing on the folder - but the system account has full access to the folder (though I get confused about how to test which account the application is running under). Also usually running locally doesn't often give you too many security issues :) A code snippet: Guid fileIdentifier = Guid.NewGuid(); CurrentUserInfo currentUser = CMSContext.CurrentUser; string identifier = currentUser.UserName.Replace(" ", "") + "_" + fileIdentifier.ToString(); string fileName1 = System.IO.Path.GetFileName(fileUpload.PostedFile.FileName); string Name = System.IO.Path.GetFileNameWithoutExtension(fileName1); string renamedFile = fileName1.Replace(Name, identifier); string path = ConfigurationManager.AppSettings["MemberPhotoRepository"]; String filenameToWriteTo = path + currentUser.UserName.Replace(" ", "") + fileName1; fileUpload.PostedFile.SaveAs(filenameToWriteTo); Where my config settings value is: Again this works fine on my PC! (And I checked the other person has the folder on their PC). Any suggestions would be appreciated - thanks :)

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  • How to limit an upload speed in java servlet?

    - by den-javamaniac
    Hi. I'm working on an app (based on Spring as DI and MVC framework) that has a file upload function which is currently implemented using Spring Multipart Upload (which in it's turn utilizes commons fileupload libs). So what I'm looking for is a way to lower the upload bandwidth consumption. How can I accomplish that?

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  • How to enable attachment using Apache File upload

    - by Stardust
    I am using Apache commons File upload API to Store the file from JSP to servlets in temp directory, but I don't know what should I do next to send the email as an attachment using javamail API. How can I retrieve those files which is written in temp directory using Apache Fileupload API to send them as attachment to mail Server. How will writing those files either to memory or disk will help me?

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  • File Upload in asp.net

    - by vaibhav
    I am using FileUpload control to facilitate Image file upload on my website. I want to restrict a user to upload only Image file. I am using if (fupFirmLogo.PostedFile.ContentType == "image/Jpeg") { } to check if the file is a image or not. I want to allow all image extensions like PNG, GiF, Jpeg, tif , BMP etc. How should I do it.

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  • ASP.Net File Upload Network Issue

    - by John Delate
    I have tried both the .net FileUpload control and the ajax Asyncfileuploadcontrol to upload a file less than 500kb. It seems that when I tried to go through my wireless router (att.bellsouth) that the uploads always fail, however when I plug my droid into my laptop and use my pda connection it works perfectly fine. I'm wondering if the network connection from my house to my server could be causing this issue, and if anyone had any solutions to this problem. Tomorrow I'm going to try and upload from other networks and pray it works.

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  • Multiple File Selection For Uploading in ASP.NET

    - by IrfanRaza
    Hi Friends, There are several resources available on net to upload multiple files, but using multiple FileUpload controls. What I need to have multiple file selection dialog box so that user can select multiple files at one shot and then all files should be uploaded on one click. Anyone of you have any idea? Thanks in advance.

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  • org.apache.commons.httpclient.HttpClient stuck on request

    - by Roman
    Hi All I have that code : while(!lastPage && currentPage < maxPageSize){ StringBuilder request = new StringBuilder("http://catalog.bizrate.com/services/catalog/v1/us/" + " some more ..."); currentPage++; HttpClient client = new HttpClient(new MultiThreadedHttpConnectionManager()); client.getHttpConnectionManager().getParams().setConnectionTimeout(15000); GetMethod get = new GetMethod(request.toString()); HostConfiguration configuration = new HostConfiguration(); int iGetResultCode = client.executeMethod(configuration, get); if (iGetResultCode != HttpStatus.SC_OK) { System.err.println("Method failed: " + get.getStatusLine()); return; } XMLStreamReader reader = XMLInputFactory.newInstance().createXMLStreamReader(get.getResponseBodyAsStream()); while (reader.hasNext()) { int type = reader.next(); // some more xml parsing ... } reader.close(); get.releaseConnection(); } Somehow the code gets suck from time to time on line : executing request. I cant find the configuration for a request time out (not the connection timeout) , can someone help me maybe , or is there something that I am doing basely wrong ? The client I am using.

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  • Creative Commons Attribution-Share Alike 3.0: Commercial Use?

    - by Jorre
    On the following URL are some icons I'd like to use in a website for a client. This would be commercial work. The site says "free for public use", what is public use and can I use them in commercial works? http://somerandomdude.com/projects/iconic I checked the license at: http://creativecommons.org/licenses/by-sa/3.0/us/ and there it says "free cultural works". Can anyone clear this up?

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  • java.lang.ClassNotFoundException using google commons

    - by pie154
    I have two classes inside a package. Both call a method from another class, one works perfectly fine and the other gives the error java.lang.ClassNotFoundException and the error java.lang.NoClassDefFoundError: com/google/common/base/Predicate The class path should be the same for both as they are in he same package so I can't figure out why one has access to the class and the other doesn't? thanks in advance for any help given.

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