Search Results

Search found 1449 results on 58 pages for 'coordinate geometry'.

Page 5/58 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • A Star Path finding endless loop

    - by PoeHaH
    I have implemented A* algorithm. Sometimes it works, sometimes it doesn't, and it goes through an endless loop. After days of debugging and googling, I hope you can come to the rescue. This is my code: The algorythm: public ArrayList<Coordinate> findClosestPathTo(Coordinate start, Coordinate goal) { ArrayList<Coordinate> closed = new ArrayList<Coordinate>(); ArrayList<Coordinate> open = new ArrayList<Coordinate>(); ArrayList<Coordinate> travelpath = new ArrayList<Coordinate>(); open.add(start); while(open.size()>0) { Coordinate current = searchCoordinateWithLowestF(open); if(current.equals(goal)) { return travelpath; } travelpath.add(current); open.remove(current); closed.add(current); ArrayList<Coordinate> neighbors = current.calculateCoordAdjacencies(true, rowbound, colbound); for(Coordinate n:neighbors) { if(closed.contains(n) || map.isWalkeable(n)) { continue; } int gScore = current.getGvalue() + 1; boolean gScoreIsBest = false; if(!open.contains(n)) { gScoreIsBest = true; n.setHvalue(manhattanHeuristic(n,goal)); open.add(n); } else { if(gScore<n.getGvalue()) { gScoreIsBest = true; } } if(gScoreIsBest) { n.setGvalue(gScore); n.setFvalue(n.getGvalue()+n.getHvalue()); } } } return null; } What I have found out is that it always fails whenever there's an obstacle in the path. If I'm running it on 'open terrain', it seems to work. It seems to be affected by this part: || map.isWalkeable(n) Though, the isWalkeable function seems to work fine. If additional code is needed, I will provide it. Your help is greatly appreciated, Thanks :)

    Read the article

  • How to get the coordinate of Gridlayout

    - by Jessy
    Hi, I set my JPanel to GridLayout (6,6), with dimension (600,600) Each cell of the grid will display one pictures with different widths and heights. The picture first add to a JLabel, and the JLabel then added to the cells. How can retrieved the coordinate of the pictures in the cells and not the coordinate of cells? So far the out give these coordinate which equal height and width even on screen the pictures showed in different sizes. e.g. java.awt.Rectangle[x=100,y=100,width=100,height=100] java.awt.Rectangle[x=200,y=100,width=100,height=100] java.awt.Rectangle[x=300,y=100,width=100,height=100] The reason why I used GridLayout instead of gridBagLayout is that, I want each pictures to have boundary. If I use GridBagLayout, the grid will expand according to the picture size. I want grid size to be in fix size. JPanel pDraw = new JPanel(new GridLayout(6,6)); pDraw.setPreferredSize(new Dimension(600,600)); for (int i =0; i<(6*6); i++) { //get random number for height and width of the image int x = rand.nextInt(40)+(50); int y = rand.nextInt(40)+(50); ImageIcon icon = createImageIcon("bird.jpg"); //rescale the image according to the size selected Image img = icon.getImage().getScaledInstance(x,y,img.SCALE_SMOOTH); icon.setImage(img ); JLabel label = new JLabel(icon); pDraw.add(label); } for(Component component:components) { //retrieve the coordinate System.out.println(component.getBounds()); }

    Read the article

  • What do ptLineDist and relativeCCW do?

    - by Fasih Khatib
    I saw these methods in the Line2D Java Docs but did not understand what they do? Javadoc for ptLineDist says: Returns the distance from a point to this line. The distance measured is the distance between the specified point and the closest point on the infinitely-extended line defined by this Line2D. If the specified point intersects the line, this method returns 0.0 Doc for relativeCCW says: Returns an indicator of where the specified point (PX, PY) lies with respect to the line segment from (X1, Y1) to (X2, Y2). The return value can be either 1, -1, or 0 and indicates in which direction the specified line must pivot around its first endpoint, (X1, Y1), in order to point at the specified point (PX, PY). A return value of 1 indicates that the line segment must turn in the direction that takes the positive X axis towards the negative Y axis. In the default coordinate system used by Java 2D, this direction is counterclockwise. A return value of -1 indicates that the line segment must turn in the direction that takes the positive X axis towards the positive Y axis. In the default coordinate system, this direction is clockwise. A return value of 0 indicates that the point lies exactly on the line segment. Note that an indicator value of 0 is rare and not useful for determining colinearity because of floating point rounding issues. If the point is colinear with the line segment, but not between the endpoints, then the value will be -1 if the point lies "beyond (X1, Y1)" or 1 if the point lies "beyond (X2, Y2)".

    Read the article

  • Projecting a 3D point to 2D screen coordinate OpenTK

    - by sinsro
    Using Monotouch and OpenTK I am trying to get the screen coordinate of one 3D point. I have my world view projection matrix set up, and OpenGL makes sense of it and projects my 3D model perfectly, but how to use the same matrix to project just one point from 2D to 3D? I thought I could simply use: Vector3.Transform(ref input3Dpos, ref matWorldViewProjection, out projected2Dpos); Then have the projected screen coordinate in projected2DPos. But the resulting Vector4 does not seem to represent the proper projected screen coordinate. And I do not know how to calculate it from there on.

    Read the article

  • How to download Miles Reid's Algebraic Geometry video on Windows and view it offline

    - by Tiez Ered
    I would really like to augment my knowledge of Algebraic Geometry from the lectures by Miles Reid which can be found here. However, since I do not have fast Internet all the time, I am searching ways to download these lectures and view them offline. This question was asked here but the answer is for Linux platform and I think this is the appropriate forum to ask for help. Can you please help me download? Thanks a lot.

    Read the article

  • Software to draw 3D geometry

    - by ilovekonoka
    Does anyone know any software that can draw 3D geometry like figures usually seen in computer graphics papers and articles(example: http://www.iquilezles.org/www/articles/sphereao/sphereao.htm)? I know it can be done in Inskcape or Illustrator but I'm not sure they're the only choices.

    Read the article

  • Software to draw 3D geometry

    - by ilovekonoka
    Does anyone know any software that can draw 3D geometry like figures usually seen in computer graphics papers and articles(example: http://www.iquilezles.org/www/articles/sphereao/sphereao.htm)? I know it can be done in Inskcape or Illustrator but I'm not sure they're the only choices.

    Read the article

  • Merge Replication with Geometry data type

    - by Puneet Jain
    The Merge Agent failed because the schema of the article at the Publisher does not match the schema of the article at the Subscriber. This can occur when there are pending DDL changes waiting to be applied at the Subscriber. Restart the Merge Agent to apply the DDL changes and synchronize the subscription. (Source: MSSQL_REPL, Error number: MSSQL_REPL-2147199398) Error converting data type varchar to geometry. (Source: MSSQLServer, Error number: 8114) Get help: http://help/8114

    Read the article

  • photoshop - How to show the cursor coordinate in selection and dropper

    - by q0987
    I am using Adobe Photoshop CS4 to edit a picture. The problems I have are that I don't know where I can see the mouse cursor coordinate while I move my mouse. Q1 For example, in Paint.Net, whenever I move mouse cursor, I can immediately see the feedback from bottom-right corner (x, y), how can I see such info in photoshop while I use eyedropper function? Q2 For example, when in crop mode, I drag-drop a rectangle but I cannot see the size of the created region of interest? Thank you

    Read the article

  • Merging photo textures - (from calibrated cameras) - projected onto geometry

    - by freakTheMighty
    I am looking for papers/algorithms for merging projected textures onto geometry. To be more specific, given a set of fully calibrated cameras/photographs and geometry, how can we define a metric for choosing which photograph should be used to texture a given patch of the geometry. I can think of a few attributes one may seek minimize including the angle between the surface normal and the camera, the distance of the camera from the surface, as well as minimizing some parameterization of sharpness. The question is how do these things get combined and are there well established existing solutions?

    Read the article

  • Why does DirectX use a left-handed coordinate system?

    - by greyfade
    I considered posting on Stack Overflow, but the question strikes me as being far too subjective since I can't think of a reasonable technical explanation for Microsoft's choice in this matter. But this question has bugged me for so long and the issue keeps coming up in one of my projects, and I have never actually seen an attempt at explaining this: OpenGL uses a right-handed coordinate system, where the +Z part of the world coordinate system extends toward the viewer. DirectX uses a left-handed system where the +Z part of the world coordinate extends into the screen, away from the viewer. I never used the Glide API, so I don't know how it worked, but from what I can gather, it uses a left-handed system as well. Is there a technical reason for this? And if not, is there some conceptual advantage to a particular handedness of a coordinate system? Why would one choose one over the other?

    Read the article

  • How to generate normal coordinate?

    - by rbchr
    Hi! I'm developping an game using the API opengl es 2.0. I need to know how to generate the normal coordinate because i need them to developp the lighting. I'm wondering if there is a software or an algorithm that generate normal coordinate. Great thanks!

    Read the article

  • This Year's SQL Christmas Card

    - by Mike C
    This year's Christmas Card is similar to last year's. I used the geometry data type again for a spatial data design. Just download the attachment, unzip the .SQL script and run it in SSMS. Then look at the Spatial Data preview tab for the result. Also don't forget to visit http://www.noradsanta.org/ if your kids want to track Santa. Merry Christmas, Happy Holidays and have a great new year!...(read more)

    Read the article

  • Need a list of all countries in the world, with a longitude and latitude coordinate

    - by ptrn
    I need a list of all the countries in the world, with one lat/long coordinate for the country. I had a look at GeoNames, but all I can seem to find are lists that have the countries as well as cities in the same list. I guess I can just parse it and filter out the countries, but I was hoping to avoid that. Basically, what I need; Country name - Lat/long coordinate (some sort of center of the country) It doesn't need to say anything about continent, but I wouldn't mind if it did. _L

    Read the article

  • C++ library for Coordinate Transformation Matrices (CTM)?

    - by BastiBense
    I'm looking for a C++ library which allows for easy integration of Coordinate Transformation Matrices (CTM) in my application. You might know CTMs from PDF or PostScript. For one project we are using C++/Qt4 as a framework, which offers a QTransform class, which provides methods like .translate(double x, double y) or .rotate(double degrees). After doing some transformations, it would allow me to get all 6 CTM values, which I could feed into a PDF library or use a transformation matrix in export files. Qt's API also allows for arbitrary mapping of polygons (QPolygon), rectangles (QRect) and other primitive data structures into transformed coordinate systems. So basically I'm looking for something similar to what Qt provides, but without the need of using Qt. I know I could do the matrix multiplications myself, but I'm not really interested in doing so, as I'm very sure that someone already solved this problem, so please no links to books or other guides on how to multiply matrices. Thanks!

    Read the article

  • How to know the Geometry coordinates for google Maps

    - by Sam
    I found a sample script on Google Code about : Google Maps Javascript API V3 Overlays - http://code.google.com/apis/maps/documentation/javascript/overlays.html#OverlaysOverview And I want to apply this code to other countries (France, spain...) but I don't know where/how to find the Geometry code like in this script (see commented line) Here is the code: var australia = new google.maps.LatLng(-25, 133); map = new google.maps.Map(document.getElementById('map_canvas'), { center: australia, zoom: 4, mapTypeId: google.maps.MapTypeId.ROADMAP }); layer = new google.maps.FusionTablesLayer({ query: { select: 'geometry', from: '815230' // This one }, styles: [{ polygonOptions: { fillColor: "#00FF00", fillOpacity: 0.3 } }, { where: "birds > 300", polygonOptions: { fillColor: "#0000FF" } }, { where: "population > 5", polygonOptions: { fillOpacity: 1.0 } }] }); layer.setMap(map); P.S. I tried to change the google.maps.LatLng(-25, 133) to France Lat&Long but this is used only to center the map on that position. Thank you for your help

    Read the article

  • Arbitrary Rotation about a Sphere

    - by Der
    I'm coding a mechanic which allows a user to move around the surface of a sphere. The position on the sphere is currently stored as theta and phi, where theta is the angle between the z-axis and the xz projection of the current position (i.e. rotation about the y axis), and phi is the angle from the y-axis to the position. I explained that poorly, but it is essentially theta = yaw, phi = pitch Vector3 position = new Vector3(0,0,1); position.X = (float)Math.Sin(phi) * (float)Math.Sin(theta); position.Y = (float)Math.Sin(phi) * (float)Math.Cos(theta); position.Z = (float)Math.Cos(phi); position *= r; I believe this is accurate, however I could be wrong. I need to be able to move in an arbitrary pseudo two dimensional direction around the surface of a sphere at the origin of world space with radius r. For example, holding W should move around the sphere in an upwards direction relative to the orientation of the player. I believe I should be using a Quaternion to represent the position/orientation on the sphere, but I can't think of the correct way of doing it. Spherical geometry is not my strong suit. Essentially, I need to fill the following block: public void Move(Direction dir) { switch (dir) { case Direction.Left: // update quaternion to rotate left break; case Direction.Right: // update quaternion to rotate right break; case Direction.Up: // update quaternion to rotate upward break; case Direction.Down: // update quaternion to rotate downward break; } }

    Read the article

  • "Walking" along a rotating surface in LimeJS

    - by Dave Lancea
    I'm trying to have a character walk along a plank (a long, thin rectangle) that works like a seesaw, being rotated around a central point by box2d physics (falling objects). I want the left and right arrow keys to move the player up and down the plank, regardless of it's slope, and I don't want to use real physics for the player movement. My idea for achieving this was to compute the coordinate based on the rotation of the plank and the current location "up" or "down" the board. My math is derived from here: http://math.stackexchange.com/questions/143932/calculate-point-given-x-y-angle-and-distance Here's the code I have so far: movement = 0; if(keys[37]){ // Left movement = -3; } if(keys[39]){ // Right movement = 3; } // this.plank is a LimeJS sprite. // getRotation() Should return an angle in degrees var rotation = this.plank.getRotation(); // this.current_plank_location is initialized as 0 this.current_plank_location += movement; var x_difference = this.current_plank_location * Math.cos(rotation); var y_difference = this.current_plank_location * Math.sin(rotation); this.setPosition(seesaw.PLANK_CENTER_X + x_difference, seesaw.PLANK_CENTER_Y + y_difference); This code causes the player to swing around in a circle when they are out of the center of the plank given a slight change in rotation of the plank. Any ideas on how I can get the player position to follow the board position?

    Read the article

  • a flexible data structure for geometries

    - by AkiRoss
    What data structure would you use to represent meshes that are to be altered (e.g. adding or removing new faces, vertices and edges), and that have to be "studied" in different ways (e.g. finding all the triangles intersecting a certain ray, or finding all the triangles "visible" from a given point in the space)? I need to consider multiple aspects of the mesh: their geometry, their topology and spatial information. The meshes are rather big, say 500k triangles, so I am going to use the GPU when computations are heavy. I tried using arrays with vertices and arrays with indices, but I do not love adding and removing vertices from them. Also, using arrays totally ignore spatial and topological information, which I may need studying the mesh. So, I thought about using custom double-linked list data structures, but I believe doing so will require me to copy the data to array buffers before going on the GPU. I also thought about using BST, but not sure it fits. Any help is appreciated. If I have been too fuzzy and you require other information feel free to ask.

    Read the article

  • How to transform coordinate from WGS84 to a coordinate in a projection in PROJ.4?

    - by Sanoj
    I have a GPS-coordinate in WGS84 that I would like to transform to a map-projection coordinate in SWEREF99 TM using PROJ.4 in Java or proj4js in JavaScript. Its hard to find documentation for PROJ.4 and how to us it. If you have a good link, please post it as a comment. The PROJ.4 parameters for SWEREF99 TM is +proj=utm +zone=33 +ellps=GRS80 +towgs84=0,0,0,0,0,0,0 +units=m +no_defs I have tried to use a PROJ.4 Java library and tried this code and values: String[] proj4_w = new String[] { "+proj=utm", "+zone=33", "+ellps=GRS80", "+towgs84=0,0,0,0,0,0,0", "+units=m", "+no_defs" }; Projection proj = ProjectionFactory.fromPROJ4Specification(proj4_w); Point2D.Double testLatLng = new Point2D.Double(55.0000, 12.7500); Point2D.Double testProjec = proj.transform(testLatLng, new Point2D.Double()); This give me the point Point2D.Double[5197915.86288144, 1822635.9083898761] but I should be N: 6097106.672, E: 356083.438 What am I doing wrong? and what method and parameters should I use instead? The correct values is taken from Lantmäteriet. I am not sure if proj.transform(testLatLng, new Point2D.Double()); is the right method to use.

    Read the article

  • Calculating bounding box a certain distance away from a lat/long coordinate in Java

    - by Bryce Thomas
    Given a coordinate (lat, long), I am trying to calculate a square bounding box that is a given distance (e.g. 50km) away from the coordinate. So as input I have lat, long and distance and as output I would like two coordinates; one being the south-west (bottom-left) corner and one being the north-east (top-right) corner. I have seen a couple of answers on here that try to address this question in Python, but I am looking for a Java implementation in particular. Just to be clear, I intend on using the algorithm on Earth only and so I don't need to accommodate a variable radius. It doesn't have to be hugely accurate (+/-20% is fine) and it'll only be used to calculate bounding boxes over small distances (no more than 150km). So I'm happy to sacrifice some accuracy for an efficient algorithm. Any help is much appreciated. Edit: I should have been clearer, I really am after a square, not a circle. I understand that the distance between the center of a square and various points along the square's perimeter is not a constant value like it is with a circle. I guess what I mean is a square where if you draw a line from the center to any one of the four points on the perimeter that results in a line perpendicular to a side of the perimeter, then those 4 lines have the same length.

    Read the article

  • php PHPExcel split Excel cell coordinate

    - by Shiro
    currently, I used PHPExcel to import excel file, there is a function $cell-getCoordinate(); I would like to ask any solution for split the cell coordinate alphabet and integer? e.g A1, A2, I need to know currently which row, and until which column. I do some research about split, but not luck for it. Any idea?

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >