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  • Android:Playing bigger size audio wav sound file produces crash

    - by user187532
    Hi Android experts, I am trying to play the bigger size audio wav file(which is 20 mb) using the following code(AudioTrack) on my Android 1.6 HTC device which basically has less memory. But i found device crash as soon as it executes reading, writing and play. But the same code works fine and plays the lesser size audio wav files(10kb, 20 kb files etc) very well. P.S: I should play PCM(.wav) buffer sound, the reason behind why i use AudioTrack here. Though my device has lesser memory, how would i read bigger audio files bytes by bytes and play the sound to avoid crashing due to memory constraints. private void AudioTrackPlayPCM() throws IOException { String filePath = "/sdcard/myWav.wav"; // 8 kb file byte[] byteData = null; File file = null; file = new File(filePath); byteData = new byte[(int) file.length()]; FileInputStream in = null; try { in = new FileInputStream( file ); in.read( byteData ); in.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } int intSize = android.media.AudioTrack.getMinBufferSize(8000, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_8BIT); AudioTrack at = new AudioTrack(AudioManager.STREAM_MUSIC, 8000, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_8BIT, intSize, AudioTrack.MODE_STREAM); at.play(); at.write(byteData, 0, byteData.length); at.stop(); at.release(); } Could someone guide me please to play the AudioTrack code for bigger size wav files?

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  • Calling webservice via server causes java.net.MalformedURLException: no protocol

    - by Thomas
    I am writing a web-service, which parses an xml file. In the client, I read the whole content of the xml into a String then I give it to the web-service. If I run my web-service with main as a Java-Application (for tests) there is no problem, no error messages. However when I try to call it via the server, I get the following error: java.net.MalformedURLException: no protocol I use the same xml file, the same code (without main), and I just cannot figure out, what the cause of the error can be. here is my code: DOMParser parser=new DOMParser(); try { parser.setFeature("http://xml.org/sax/features/validation", true); parser.setFeature("http://apache.org/xml/features/validation/schema",true); parser.setFeature("http://apache.org/xml/features/validation/dynamic",true); parser.setErrorHandler(new myErrorHandler()); parser.parse(new InputSource(new StringReader(xmlFile))); document=parser.getDocument(); xmlFile is constructed in the client so: String myFile ="C:/test.xml"; File file=new File(myFile); String myString=""; FileInputStream fis=new FileInputStream(file); BufferedInputStream bis=new BufferedInputStream(fis); DataInputStream dis=new DataInputStream(bis); while (dis.available()!=0) { myString=myString+dis.readLine(); } fis.close(); bis.close(); dis.close(); Any suggestions will be appreciated!

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  • how to convert bitmap into byte array in android

    - by satyamurthy
    hi all i am new in android i am implementing image retrieve in sdcard in image convert into bitmap and in bitmap convert in to byte array please forward some solution of this code public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); ImageView image = (ImageView) findViewById(R.id.picview); EditText value=(EditText)findViewById(R.id.EditText01); FileInputStream in; BufferedInputStream buf; try { in = new FileInputStream("/sdcard/pictures/1.jpg"); buf = new BufferedInputStream(in,1070); System.out.println("1.................."+buf); byte[] bMapArray= new byte[buf.available()]; buf.read(bMapArray); Bitmap bMap = BitmapFactory.decodeByteArray(bMapArray, 0, bMapArray.length); for (int i = 0; i < bMapArray.length; i++) { System.out.print("bytearray"+bMapArray[i]); } image.setImageBitmap(bMap); value.setText(bMapArray.toString()); if (in != null) { in.close(); } if (buf != null) { buf.close(); } } catch (Exception e) { Log.e("Error reading file", e.toString()); } } } solution is 04-12 16:41:16.168: INFO/System.out(728): 4......................[B@435a2908 this is the result for byte array not display total byte array this array size is 1034 please forward some solution

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  • Unable to upload large files on FTP using Apache commons-net-3.1

    - by Nitin
    I am trying to upload the one large file ( more than 8 MB) using storeFile(remote, local) method of FTPClient but it results false.It get uploaded with some extra bytes.Following is the code with Output: public class Main { public static void main(String[] args) { FTPClient client = new FTPClient(); FileInputStream fis = null; try { client.connect("208.106.181.143"); client.setFileTransferMode(client.BINARY_FILE_TYPE); client.login("abc", "java"); int reply = client.getReplyCode(); System.out.println("Received Reply from FTP Connection:" + reply); if(FTPReply.isPositiveCompletion(reply)){ System.out.println("Connected Success"); } client.changeWorkingDirectory("/"+"Everbest"+"/"); client.makeDirectory("ETPSupplyChain5.3-EvbstSP3"); client.changeWorkingDirectory("/"+"Everbest"+"/"+"ETPSupplyChain5.3-EvbstSP3"+"/"); FTPFile[] names = client.listFiles(); String filename = "E:\\Nitin\\D-Drive\\Installer.rar"; fis = new FileInputStream(filename); boolean result = client.storeFile("Installer.rar", fis); int replyAfterupload = client.getReplyCode(); System.out.println("Received Reply from FTP Connection replyAfterupload:" + replyAfterupload); System.out.println("result:"+result); for (FTPFile name : names) { System.out.println("Name = " + name); } client.logout(); fis.close(); client.disconnect(); } catch (SocketException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } o/p: Received Reply from FTP Connection:230 Connected Success 32 /Everbest/ETPSupplyChain5.3-EvbstSP3 Received Reply from FTP Connection replyAfterupload:150 result:false

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  • Java Scanner won't follow file

    - by Steve Renyolds
    Trying to tail / parse some log files. Entries start with a date then can span many lines. This works, but does not ever see new entries to file. File inputFile = new File("C:/test.txt"); InputStream is = new FileInputStream(inputFile); InputStream bis = new BufferedInputStream(is); //bis.skip(inputFile.length()); Scanner src = new Scanner(bis); src.useDelimiter("\n2010-05-01 "); while (true) { while(src.hasNext()){ System.out.println("[ " + src.next() + " ]"); } } Doesn't seem like Scanner's next() or hasNext() detects new entries to file. Any idea how else I can implement, basically, a tail -f with custom delimiter. ok - using Kelly's advise i'm checking & refreshing the scanner, this works. Thank you !! if anyone has improvement suggestions plz do! File inputFile = new File("C:/test.txt"); InputStream is = new FileInputStream(inputFile); InputStream bis = new BufferedInputStream(is); //bis.skip(inputFile.length()); Scanner src = new Scanner(bis); src.useDelimiter("\n2010-05-01 "); while (true) { while(src.hasNext()){ System.out.println("[ " + src.next() + " ]"); } Thread.sleep(50); if(bis.available() > 0){ src = new Scanner(bis); src.useDelimiter("\n2010-05-01 "); } }

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  • Capture data read from file into string stream Java

    - by halluc1nati0n
    I'm coming from a C++ background, so be kind on my n00bish queries... I'd like to read data from an input file and store it in a stringstream. I can accomplish this in an easy way in C++ using stringstreams. I'm a bit lost trying to do the same in Java. Following is a crude code/way I've developed where I'm storing the data read line-by-line in a string array. I need to use a string stream to capture my data into (rather than use a string array).. Any help? char dataCharArray[] = new char[2]; int marker=0; String inputLine; String temp_to_write_data[] = new String[100]; // Now, read from output_x into stringstream FileInputStream fstream = new FileInputStream("output_" + dataCharArray[0]); // Convert our input stream to a BufferedReader BufferedReader in = new BufferedReader (new InputStreamReader(fstream)); // Continue to read lines while there are still some left to read while ((inputLine = in.readLine()) != null ) { // Print file line to screen // System.out.println (inputLine); temp_to_write_data[marker] = inputLine; marker++; }

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  • How to set DocFlavor for printservice in Java for WIndows.

    - by om
    Hello, I have written code to run the printer programatically in Java.I have to set the value of docflavor to print the .txt file.When I set it for INPUT_STREAM.TEXT_PLAIN_UTF_8 and run my program on Linux , it prints the text file.but when i run the same code for windows.It can't print the text file.It only prints the jpeg format file.I am using HP Deskjet F735 printer for this. Following is my code . DocFlavor docflavor = DocFlavor.INPUT_STREAM.TEXT_PLAIN_UTF_8; PrintRequestAttributeSet attr_set = new HashPrintRequestAttributeSet(); attr_set.add(new Copies(2)); PrintService[] service = PrintServiceLookup.lookupPrintServices(docflavor, attr_set); if (service.length==0) { JOptionPane.showMessageDialog(null, "No Printer Selected"); } else if (service.length > 0) { System.out.println("Selected printer is " + service[0].getName()); DocPrintJob pj = service[0].createPrintJob(); { PrintService ps = pj.getPrintService(); FileInputStream fis = null; try { File file = new File("/home/ignu/Desktop/newfile"); fis = new FileInputStream(file); Doc doc = new SimpleDoc(fis, docflavor, null); pj.print(doc, attr_set);

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  • To have efficient many-to-many relation in Java

    - by Masi
    How can you make the efficient many-to-many -relation from fileID to Words and from word to fileIDs without database -tools like Postgres in Java? I have the following classes. The relation from fileID to words is cheap, but not the reverse, since I need three for -loops for it. My solution is not apparently efficient. Other options may be to create an extra class that have word as an ID with the ArrayList of fileIDs. Reply to JacobM's answer The relevant part of MyFile's constructors is: /** * Synopsis of data in wordToWordConutInFile.txt: * fileID|wordID|wordCount * * Synopsis of the data in the file wordToWordID.txt: * word|wordID **/ /** * Getting words by getting first wordIDs from wordToWordCountInFile.txt and then words in wordToWordID.txt. */ InputStream in2 = new FileInputStream("/home/dev/wordToWordCountInFile.txt"); BufferedReader fi2 = new BufferedReader(new InputStreamReader(in2)); ArrayList<Integer> wordIDs = new ArrayList<Integer>(); String line = null; while ((line = fi2.readLine()) != null) { if ((new Integer(line.split("|")[0]) == currentFileID)) { wordIDs.add(new Integer(line.split("|")[6])); } } in2.close(); // Getting now the words by wordIDs. InputStream in3 = new FileInputStream("/home/dev/wordToWordID.txt"); BufferedReader fi3 = new BufferedReader(new InputStreamReader(in3)); line = null; while ((line = fi3.readLine()) != null) { for (Integer wordID : wordIDs) { if (wordID == (new Integer(line.split("|")[1]))) { this.words.add(new Word(new String(line.split("|")[0]), fileID)); break; } } } in3.close(); this.words.addAll(words); The constructor of Word is at the paste.

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  • Traceroute comparison and statistics

    - by ben-casey
    I have a number of traceroutes that i need to compare against each other but i dont know the best way to do it, ive been told that hash maps are a good technique but i dont know how to implement them on my code. so far i have: FileInputStream fstream = new FileInputStream("traceroute.log"); // Get the object of DataInputStream DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String strLine; // reads lines in while ((strLine = br.readLine()) != null) { System.out.println(strLine); } and the output looks like this: Wed Mar 31 01:00:03 BST 2010 traceroute to www.bbc.co.uk (212.58.251.195), 30 hops max, 40 byte packets 1 139.222.0.1 (139.222.0.1) 0.873 ms 1.074 ms 1.162 ms 2 core-from-cmp.uea.ac.uk (10.0.0.1) 0.312 ms 0.350 ms 0.463 ms 3 ueaha1btm-from-uea1 (172.16.0.34) 0.791 ms 0.772 ms 1.238 ms 4 bound-from-ueahatop.uea.ac.uk (193.62.92.71) 5.094 ms 4.451 ms 4.441 ms 5 gi0-3.norw-rbr1.eastnet.ja.net (193.60.0.21) 4.426 ms 5.014 ms 4.389 ms 6 gi3-0-2.chel-rbr1.eastnet.ja.net (193.63.107.114) 6.055 ms 6.039 ms * 7 lond-sbr1.ja.net (146.97.40.45) 6.994 ms 7.493 ms 7.457 ms 8 so-6-0-0.lond-sbr4.ja.net (146.97.33.154) 8.206 ms 8.187 ms 8.234 ms 9 po1.lond-ban4.ja.net (146.97.35.110) 8.673 ms 6.294 ms 7.668 ms 10 bbc.lond-sbr4.ja.net (193.62.157.178) 6.303 ms 8.118 ms 8.107 ms 11 212.58.238.153 (212.58.238.153) 6.245 ms 8.066 ms 6.541 ms 12 212.58.239.62 (212.58.239.62) 7.023 ms 8.419 ms 7.068 ms what i need to do is compare this trace against another one just like it and look for the changes and time differences etc, then print a stats page.

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  • How can i zip files in Java and not include files paths

    - by Ignacio
    For example, i want to zip a file stored in /Users/me/Desktop/image.jpg I maded this method: public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){ // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // VER SI HAY QUE CREAR EL ROOT PATH boolean result = (new File(destinationDir)).mkdirs(); String zipFullFilename = destinationDir + "/" + zipFilename ; System.out.println(result); // Create the ZIP file ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename)); // Compress the files for (String filename: sourcesFilenames) { FileInputStream in = new FileInputStream(filename); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filename)); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); return true; } catch (IOException e) { return false; } } But when i extract the file, the unzipped files have the full path. I don't want the full path of each file in the zip i only want the filename. How can i made this?

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  • sharing message object between web applications

    - by jezhilvalan
    I need to share java mail message objects between two web applications(A and B). WebApplication A obtains the message and write it to the outputStream for(int i=0;i<messagesArr.length;i++){ uid = pop3FolderObj.getUID(messagesArr[i]); //storing messages with uid names inorder to maintain uniqueness File f = new File("F:/PersistedMessagesFolder" + uid); FileOutputStream fos = new FileOutputStream(f); messagesArr[i].writeTo(fos); fos.flush(); fos.close(); } Is FileOutputStream the best output stream for persisting message objects? Is it possible to use ObjectOutputStream for message object persistence? WebApplication B reads the message object via InputStream FileInputStream fis = new FileInputStream("F:/MessagesPersistedFolder"+uid); MimeMessage mm = new MimeMessage(sessionObj,fis); What if the mail message object which is already written via WebApplication A is not a MimeMessage? How can I read non-mime messages using input stream? MimeMessage constructor mandates sessionObj as the first parameter? How can I obtain this sessionObj in WebApplicationB? Do I have to again establish store connection with the same emailid,emailpassword,popserver and port(already used in WebApplication A) with the email server inorder to obtain this session object? Even if obtained, will this session object remains the same as that of the session object which is priorly obtained in WebApplicationA? Since I am using uids to name Message objects (inorder to maintain uniqueness of file names) how can I share these uids between WebApplication A and WebApplication B? WebApplication B needs the uid inorder to access the specific file which is present in "F:/MessagesPersistedFolder" Please help me in resolving the aforeseen issues.

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  • Variable reference problem when loading an object from a file in Java

    - by Snail
    I have a problem with the reference of a variable when loading a saved serialized object from a data file. All the variables referencing to the same object doesn't seem to update on the change. I've made a code snipped below that illustrates the problem. Tournament test1 = new Tournament(); Tournament test2 = test1; try { FileInputStream fis = new FileInputStream("test.out"); ObjectInputStream in = new ObjectInputStream(fis); test1 = (Tournament) in.readObject(); in.close(); } catch (IOException ex){ Logger.getLogger(Frame.class.getName()).log(Level.SEVERE, null, ex); } catch (ClassNotFoundException ex){ Logger.getLogger(Frame.class.getName()).log(Level.SEVERE, null, ex); } System.out.println("test1: " + test1); System.out.println("test2: " + test2); After this code is ran test1 and test2 doesn't reference to the same object anymore. To my knowledge they should do that since in the declaration of test2 makes it a reference to test1. When test1 is updated test2 should reflect the change and return the new object when called in the code. Am I missing something essential here or have I been misstaught about how the variable references in Java works?

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  • Java try finally variations

    - by Petr Gladkikh
    This question nags me for a while but I did not found complete answer to it yet (e.g. this one is for C# http://stackoverflow.com/questions/463029/initializing-disposable-resources-outside-or-inside-try-finally). Consider two following Java code fragments: Closeable in = new FileInputStream("data.txt"); try { doSomething(in); } finally { in.close(); } and second variation Closeable in = null; try { in = new FileInputStream("data.txt"); doSomething(in); } finally { if (null != in) in.close(); } The part that worries me is that the thread might be somewhat interrupted between the moment resource is acquired (e.g. file is opened) but resulting value is not assigned to respective local variable. Is there any other scenarios the thread might be interrupted in the point above other than: InterruptedException (e.g. via Thread#interrupt()) or OutOfMemoryError exception is thrown JVM exits (e.g. via kill, System.exit()) Hardware fail (or bug in JVM for complete list :) I have read that second approach is somewhat more "idiomatic" but IMO in the scenario above there's no difference and in all other scenarios they are equal. So the question: What are the differences between the two? Which should I prefer if I do concerned about freeing resources (especially in heavily multi-threading applications)? Why? I would appreciate if anyone points me to parts of Java/JVM specs that support the answers.

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  • FTPing a file to Mainframe using Java, Apache Common Net

    - by SKR
    I'm am trying to upload a file into mainframe server using FTP. My code is below FTPClient client = new FTPClient(); InputStream in = null; FileInputStream fis = null; try{ client.connect("10.10.23.23"); client.login("user1", "pass123"); client.setFileType(FTPClient.BINARY_FILE_TYPE); int reply ; reply = client.getReplyCode(); System.out.println("Reply Code:"+reply); if(FTPReply.isPositiveCompletion(reply)){ System.out.println("Positive reply"); String filename ="D:\\FILE.txt"; in = new FileInputStream(filename); client.storeFile("FILE.TXT", in); client.logout(); fis.close(); }else{ System.out.println("Negative reply"); } }catch(final Throwable t){ t.printStackTrace(); } The code gets struck in client.storeFile("FILE.TXT", in); I am unable to debug. Please suggest ways / solutions.

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  • KeyStore, HttpClient, and HTTPS: Can someone explain this code to me?

    - by stormin986
    I'm trying to understand what's going on in this code. KeyStore trustStore = KeyStore.getInstance(KeyStore.getDefaultType()); FileInputStream instream = new FileInputStream(new File("my.keystore")); try { trustStore.load(instream, "nopassword".toCharArray()); } finally { instream.close(); } SSLSocketFactory socketFactory = new SSLSocketFactory(trustStore); Scheme sch = new Scheme("https", socketFactory, 443); httpclient.getConnectionManager().getSchemeRegistry().register(sch); My Questions: trustStore.load(instream, "nopassword".toCharArray()); is doing what exactly? From reading the documentation load() will load KeyStore data from an input stream (which is just an empty file we just created), using some arbitrary "nopassword". Why not just load it with null as the InputStream parameter and an empty string as the password field? And then what is happening when this empty KeyStore is being passed to the SSLSocketFactory constructor? What's the result of such an operation? Or -- is this simply an example where in a real application you would have to actually put a reference to an existing keystore file / password?

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  • What is the proper way to code a read-while loop in Scala?

    - by ARKBAN
    What is the "proper" of writing the standard read-while loop in Scala? By proper I mean written in a Scala-like way as opposed to a Java-like way. Here is the code I have in Java: MessageDigest md = MessageDigest.getInstance( "MD5" ); InputStream input = new FileInputStream( "file" ); byte[] buffer = new byte[1024]; int readLen; while( ( readLen = input.read( buffer ) ) != -1 ) md.update( buffer, 0, readLen ); return md.digest(); Here is the code I have in Scala: val md = MessageDigest.getInstance( hashInfo.algorithm ) val input = new FileInputStream( "file" ) val buffer = new Array[ Byte ]( 1024 ) var readLen = 0 while( readLen != -1 ) { readLen = input.read( buffer ) if( readLen != -1 ) md.update( buffer, 0, readLen ) } md.digest The Scala code is correct and works, but feels very un-Scala-ish. For one it is a literal translation of the Java code, taking advantage of none of the advantages of Scala. Further it is actually longer than the Java code! I really feel like I'm missing something, but I can't figure out what. I'm fairly new to Scala, and so I'm asking the question to avoid falling into the pitfall of writing Java-style code in Scala. I'm more interested in the Scala way to solve this kind of problem than in any specific helper method that might be provided by the Scala API to hash a file. (I apologize in advance for my ad hoc Scala adjectives throughout this question.)

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  • how to send image to remote server using webservices in android only save to byte array

    - by satyamurthy
    get image from sdcard and store that image to remote server. i am getting the image from sdcard and i converterd that image to bytearray by using bitmap .but what's the problem if i oberver byte array it is showing some different values it is not matching with .net image byte array conversion. can u pl help if you have any solution it is very urgent to me following is the code i am using can u pl suggest me FileInputStream fin = new FileInputStream(new File("/sdcard/pictures/1.jpg")); BufferedInputStream bis = new BufferedInputStream(fin,3000); byte[] data = new byte[bis.available()]; bis.read(data, 0, data.length); byte[] data1=new byte[data.length]; for (int i = 0; i < data.length; i++) { System.out.print(data[i]); data1[i]=data[i]; } System.out.println("5..................."+data1); Bitmap bitmap = BitmapFactory.decodeByteArray(data1,0,data1.length); System.out.println("6..................."+data1.length); Log.v("hgfjohfjghjdfhgj",""+bitmap); if(bitmap!=null) image.setImageBitmap(bitmap); else Log.e("Bitmap "," Not Created");

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  • how to read xml properties value?

    - by bala
    I have xml file in sdcard(xxx.file) how to read all the xml tag properties values starting point to end point and prints that value please help me I am not familiar in xml pullparser please help me... This is my xml file code: <?xml version="1.0"?> <layout schemaVersion="1" width="800" height="450" bgcolor="#000000"> <region id="47ff29524ce1b" width="800" height="450" top="0" left="0" userId="1"> <media id="9" type="image" duration="30" lkid="4" userId="1" schemaVersion="1"> <options><uri>9.png</uri></options> <raw/> </media></region></layout> java code: public class MainActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); try{ XmlPullParserFactory factory = XmlPullParserFactory.newInstance(); factory.setNamespaceAware(true); XmlPullParser parser = factory.newPullParser(); File file = new File(Environment.getExternalStorageDirectory()+ "/xxx.xml"); FileInputStream fis = new FileInputStream(file); parser.setInput(new InputStreamReader(fis)); }catch(XmlPullParserException e){ e.printStackTrace(); }catch(FileNotFoundException e){ e.printStackTrace(); } } }

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  • How to prevent the other threads from accessing a method when one thread is accessing a method?

    - by geeta
    I want to search for a string in 10 files and write the matching lines to a single file. I wrote the matching lines from each file to 10 output files(o/p file1,o/p file2...) and then copied those to a single file using 10 threads. But the output single file has mixed output(one line from o/p file1,another line from o/p file 2 etc...) because its accessed simultaneously by many threads. If I wait for all threads to complete and then write the single file it will be much slower. I want the output file to be written by one thread at a time. What should i do? My source code:(only writing to single file method) public void WriteSingle(File output_file,File final_output) throws IOException { synchronized(output_file){ System.out.println("Writing Single file"); FileOutputStream fo = new FileOutputStream(final_output,true); FileChannel fi = fo.getChannel(); FileInputStream fs = new FileInputStream(output_file); FileChannel fc = fs.getChannel(); int maxCount = (64 * 1024 * 1024) - (32 * 1024); long size = fc.size(); long position = 0; while (position < size) { position += fc.transferTo(position, maxCount, fi); } } }

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  • Why the HelloWorld of opennlp library works fine on Java but doesn't work with Jruby?

    - by 0x90
    I am getting this error: SyntaxError: hello.rb:13: syntax error, unexpected tIDENTIFIER public HelloWorld( InputStream data ) throws IOException { The HelloWorld.rb is: require "java" import java.io.FileInputStream; import java.io.InputStream; import java.io.IOException; import opennlp.tools.postag.POSModel; import opennlp.tools.postag.POSTaggerME; public class HelloWorld { private POSModel model; public HelloWorld( InputStream data ) throws IOException { setModel( new POSModel( data ) ); } public void run( String sentence ) { POSTaggerME tagger = new POSTaggerME( getModel() ); String[] words = sentence.split( "\\s+" ); String[] tags = tagger.tag( words ); double[] probs = tagger.probs(); for( int i = 0; i < tags.length; i++ ) { System.out.println( words[i] + " => " + tags[i] + " @ " + probs[i] ); } } private void setModel( POSModel model ) { this.model = model; } private POSModel getModel() { return this.model; } public static void main( String args[] ) throws IOException { if( args.length < 2 ) { System.out.println( "HelloWord <file> \"sentence to tag\"" ); return; } InputStream is = new FileInputStream( args[0] ); HelloWorld hw = new HelloWorld( is ); is.close(); hw.run( args[1] ); } } when running ruby HelloWorld.rb "I am trying to make it work" when I run the HelloWorld.java "I am trying to make it work" it works perfectly, of course the .java doesn't contain the require java statement. EDIT: I followed the following steps. The output for jruby -v : jruby 1.6.7.2 (ruby-1.8.7-p357) (2012-05-01 26e08ba) (Java HotSpot(TM) 64-Bit Server VM 1.6.0_35) [darwin-x86_64-java]

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  • In Android GUI flickers when reading the properties file

    - by ManojValiveti
    Hi, I am getting the GUI flicker when reading a file properties and accordingly enabling/disabling checkbox and List value in listbox. when i remove this file reading code the GUI doesnt have flicker. I am reading the properties before creating the Preferences in OnCreate(). Attached the file write code below for reference.Please let us know is there any other way to read and update the preference staus. private void SetExtendConf(String key, String strValue) { mProperties = new Properties(); try { File file = new File(FILE_EXT); if(!file.exists()) file.createNewFile(); file.setWritable(true,false); FileInputStream fis = new FileInputStream(file); mProperties.load(fis); fis.close(); FileOutputStream stream = new FileOutputStream(file); Log.d(TAG, "Setting Values " + key + ":"+ strValue); mProperties.setProperty(key, strValue); mProperties.store(stream,"ext.conf"); stream.close(); } catch (IOException e) { Log.d(TAG, "Could not open properties file: " + GPS_FILE_EXT); } } -Manoj

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  • how to send image to remote server using web services in android

    - by Aswan
    get image from sdcard and store that image to remote server. i am getting the image from sdcard and i converterd that image to bytearray by using bitmap .but what's the problem if i oberver byte array it is showing some different values it is not matching with .net image byte array conversion. can u pl help if you have any solution it is very urgent to me following is the code i am using can u pl suggest me FileInputStream fin = new FileInputStream(new File("/sdcard/pictures/1.jpg")); BufferedInputStream bis = new BufferedInputStream(fin,3000); byte[] data = new byte[bis.available()]; bis.read(data, 0, data.length); byte[] data1=new byte[data.length]; for (int i = 0; i < data.length; i++) { System.out.print(data[i]); data1[i]=data[i]; } System.out.println("5..................."+data1); Bitmap bitmap = BitmapFactory.decodeByteArray(data1,0,data1.length); System.out.println("6..................."+data1.length); Log.v("hgfjohfjghjdfhgj",""+bitmap); if(bitmap!=null) image.setImageBitmap(bitmap); else Log.e("Bitmap "," Not Created");

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  • download large files using servlet

    - by niks
    I am using Apache Tomcat Server 6 and Java 1.6 and am trying to write large mp3 files to the ServletOutputStream for a user to download. Files are ranging from a 50-750MB at the moment. The smaller files aren't causing too much of a problem but with the larger files it and getting socket exception broken pipe. File fileMp3 = new File(objDownloadSong.getStrSongFolder() + "/" + strSongIdName); FileInputStream fis = new FileInputStream(fileMp3); response.setContentType("audio/mpeg"); response.setHeader("Content-Disposition", "attachment; filename=\"" + strSongName + ".mp3\";"); response.setContentLength((int) fileMp3.length()); OutputStream os = response.getOutputStream(); try { int byteRead = 0; while ((byteRead = fis.read()) != -1) { os.write(byteRead); } os.flush(); } catch (Exception excp) { downloadComplete = "-1"; excp.printStackTrace(); } finally { os.close(); fis.close(); }

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  • When Creating a Reference for an Object Where from where that class is Loaded?

    - by asela38
    When doing some sample codings with Java I came crosss ClassCast Exception, from where I cast the object to StaticClass. Can any explaing the what has happened here. public void test5() throws Exception { System.out.println(StaticClass.obj); Object newInstance = ClassLoader.getSystemClassLoader().loadClass("com.StaticClass").newInstance(); System.out.println(newInstance.getClass().getDeclaredField("obj").get(newInstance)); Object newInstance2 = new ILoader().loadClass("com//StaticClass.class").newInstance(); System.out.println(newInstance2.getClass().getDeclaredField("obj").get(newInstance2)); StaticClass s = (StaticClass)newInstance2; System.out.println(s.obj); System.out.println(newInstance.getClass().getClassLoader()); System.out.println(newInstance2.getClass().getClassLoader()); } package com; public class StaticClass { public static final Object obj = new Object(); } package com; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; public class ILoader extends ClassLoader { public ILoader() { super(null); } @Override protected Class<?> findClass(String name) throws ClassNotFoundException { File file = new File(name); byte[] bytes = new byte[(int)file.length()]; try { new FileInputStream(file).read(bytes); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return super.defineClass("com.StaticClass",bytes, 0, bytes.length); } } output which was given by last sysout's when the casting part of the code not existed is as belows. sun.misc.Launcher$AppClassLoader@133056f com.ILoader@1ac3c08

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  • Java File Handling, what did I do wrong?

    - by Urda
    Wrote up a basic file handler for a Java Homework assignment, and when I got the assignment back I had some notes about failing to catch a few instances: Buffer from file could have been null. File was not found File stream wasn't closed Here is the block of code that is used for opening a file: /** * Create a Filestream, Buffer, and a String to store the Buffer. */ FileInputStream fin = null; BufferedReader buffRead = null; String loadedString = null; /** Try to open the file from user input */ try { fin = new FileInputStream(programPath + fileToParse); buffRead = new BufferedReader(new InputStreamReader(fin)); loadedString = buffRead.readLine(); fin.close(); } /** Catch the error if we can't open the file */ catch(IOException e) { System.err.println("CRITICAL: Unable to open text file!"); System.err.println("Exiting!"); System.exit(-1); } The one comment I had from him was that fin.close(); needed to be in a finally block, which I did not have at all. But I thought that the way I have created the try/catch it would have prevented an issue with the file not opening. Let me be clear on a few things: This is not for a current assignment (not trying to get someone to do my own work), I have already created my project and have been graded on it. I did not fully understand my Professor's reasoning myself. Finally, I do not have a lot of Java experience, so I was a little confused why my catch wasn't good enough.

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