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  • -moz CSS properties and browser support

    - by twodayslate
    As of right now I believe only Firefox support -moz-border-radius property. I am surprised that twitter uses it. Are any other browsers planning on supporting this or does CSS3 have something like this in the works? edit:// also found -webkit-border-top-left-radius and then the CSS3 version So when is CSS3 coming out?

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  • How does java.util.Collections.contains() perform faster than a linear search?

    - by The111
    I've been fooling around with a bunch of different ways of searching collections, collections of collections, etc. Doing lots of stupid little tests to verify my understanding. Here is one which boggles me (source code further below). In short, I am generating N random integers and adding them to a list. The list is NOT sorted. I then use Collections.contains() to look for a value in the list. I intentionally look for a value that I know won't be there, because I want to ensure that the entire list space is probed. I time this search. I then do another linear search manually, iterating through each element of the list and checking if it matches my target. I also time this search. On average, the second search takes 33% longer than the first one. By my logic, the first search must also be linear, because the list is unsorted. The only possibility I could think of (which I immediately discard) is that Java is making a sorted copy of my list just for the search, but (1) I did not authorize that usage of memory space and (2) I would think that would result in MUCH more significant time savings with such a large N. So if both searches are linear, they should both take the same amount of time. Somehow the Collections class has optimized this search, but I can't figure out how. So... what am I missing? import java.util.*; public class ListSearch { public static void main(String[] args) { int N = 10000000; // number of ints to add to the list int high = 100; // upper limit for random int generation List<Integer> ints; int target = -1; // target will not be found, forces search of entire list space long start; long end; ints = new ArrayList<Integer>(); start = System.currentTimeMillis(); System.out.print("Generating new list... "); for (int i = 0; i < N; i++) { ints.add(((int) (Math.random() * high)) + 1); } end = System.currentTimeMillis(); System.out.println("took " + (end-start) + "ms."); start = System.currentTimeMillis(); System.out.print("Searching list for target (method 1)... "); if (ints.contains(target)) { // nothing } end = System.currentTimeMillis(); System.out.println(" Took " + (end-start) + "ms."); System.out.println(); ints = new ArrayList<Integer>(); start = System.currentTimeMillis(); System.out.print("Generating new list... "); for (int i = 0; i < N; i++) { ints.add(((int) (Math.random() * high)) + 1); } end = System.currentTimeMillis(); System.out.println("took " + (end-start) + "ms."); start = System.currentTimeMillis(); System.out.print("Searching list for target (method 2)... "); for (Integer i : ints) { // nothing } end = System.currentTimeMillis(); System.out.println(" Took " + (end-start) + "ms."); } }

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  • 2D Car Simulation with Throttle Linear Physics

    - by James
    I'm trying to make a simulation game for an automatic cruise control system. The system simulates a car on varying inclinations and throttle speeds. I've coded up to the car physics but these do note make sense. The dynamics of the simulation are specified as follows: a = V' - V T = (k1)V + ?(k2) + ma V' = (1 - (k1 / m) V) + T - ( k2 / m) * ? Where T = throttle position k1 = viscous friction V = speed V' = next speed ? = angle of incline k2 = m g sin ? a = acceleration m = mass Notice that the angle of incline in the equation is not chopped up by sin or cos. Even the equation for acceleration isn't right. Can anyone correct them or am I misinterpreting the physics?

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  • Linear search vs Octree (Frustum cull)

    - by Dave
    I am wondering whether I should look into implementing an octree of some kind. I have a very simple game which consists of a 3d plane for the floor. There are multiple objects scattered around on the ground, each one has an aabb in world space. Currently I just do a loop through the list of all these objects and check if its bounding box intersects with the frustum, it works great but I am wondering if if it would be a good investment in an octree. I only have max 512 of these objects on the map and they all contain bounding boxes. I am not sure if an octree would make it faster since I have so little objects in the scene.

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  • How to create a vertical gradient in flex

    - by Zeeshan Rang
    How to create vertical gradient in flex. What i currently have is a horizontal color gradient. And its working fine. But I am unable to figure out how should I make it vertical (which ofcourse is the requirement) I use styleName = "chatWindowLeftGradient" <mx:VBox id="chatTabBarVBox" height="100%" styleName="chatWindowLeftGradient"> </mx:VBox> And the style sheet looks like this: <mx:Style> .chatWindowLeftGradient{ backgroundImage: ClassReference("custom.GradientBackground"); backgroundSize: "100%"; fillColors: #6db263, #a4d9a1; fillAlphas: 1, 1; } </mx:Style> This give a gradient from top to bottom. How i can make from left to right?? Regards Zeeshan

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  • Issue when I'm trying to draw gradient in swift

    - by bagusflyer
    I got an error when I was trying to draw gradient in Swift code: GradientView.swift:31:40: Could not find an overload for '__conversion' that accepts the supplied arguments Here is my code: let context : CGContextRef = UIGraphicsGetCurrentContext() let locations :CGFloat[] = [ 0.0, 0.25, 0.5, 0.75 ] let colors = [UIColor.redColor().CGColor,UIColor.greenColor().CGColor,UIColor.blueColor().CGColor, UIColor.yellowColor().CGColor] let colorspace : CGColorSpaceRef = CGColorSpaceCreateDeviceRGB() let gradient : CGGradientRef = CGGradientCreateWithColors(colorspace, colors, locations) //CGGradientCreateWithColors(colorspace,colors,locations) let startPoint : CGPoint = CGPointMake(0, 0) let endPoint : CGPoint = CGPointMake(500,500) CGContextDrawLinearGradient(context, gradient,startPoint, endPoint, 0); The problem is the CGGradientCreateWithColors takes CFArray not a normal Swift Array. I have no idea how to convert CFArray to Array and can't find anything in Apple's document. Any idea? Thanks

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  • CSS Square Div with an Inward Oval Shape

    - by user2813099
    I am trying to create a div in css with an inward oval shape to it like this. At the moment, I have a shape that is outward instead of inward (JS Fiddle Link). .shape { float: left; width: 100px; height: 50px; border: none; background: #CC0000; border-radius: 0 90px 0 0; -moz-border-radius: 0 90px 0 0; -webkit-border-radius: 0 90px 0 0; background-image: -webkit-gradient( linear, left top, right bottom, color-stop(0, #520C0C), color-stop(1, #CC0000) ); background-image: -o-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: -moz-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: -webkit-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: -ms-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: linear-gradient(to right bottom, #520C0C 0%, #CC0000 100%); } Any ideas on how to go about this?

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  • How do I create a gradient button on an iPhone?

    - by jkp
    How can I create a button that looks like the one found in the screenshot below on an iPhone with the 3.0 SDK? It's a button that shows when connecting to a host iTunes library from the iTunes remote. Is it a case of writing a custom control or is this a stock style?

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  • Integer Linear Programming Java: Multiple Open Source and Commercial tools are available. Which one

    - by Sandeep Jindal
    Hi, I need to use Integer Linear Programming API/Tool for my application. Though my application is in Java but I don’t mind calling an EXE (Tool) from Java providing input using file (MPS, etc). My search analysis is as follows: There are multiple Open Source and Commercial tools available to solve ILP Following I found and think are useful for my needs. 1. Gnu LP Kit(GLPK): I think this is the oldest and probably most stable and efficient 2. IP_Solve: Has good reviews about it. 3. JavaILP: Found this, but not much reviews about it 4. Apache Common-Math: Supports LP but not ILP, so ruled out. 5. Coin-OR Can you please suggest which one shall be the best in terms of stability, efficiency, acceptance, etc Regards Sandeep Jindal

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  • R: ggplot2, how to get the parameters from a plotted linear model smoother?

    - by John
    I have a data.frame with 3 time series in it, shown below. When I plot them with a smoother time series, I want to be able to get the parameters of the linear model that I plot, but I can't see how to do that? > data day od series_id 1 1 0.10 A1 2 3 1.00 A1 3 5 0.50 A1 4 7 0.70 A1 5 1 1.70 B1 6 3 1.60 B1 7 5 1.75 B1 8 7 1.70 B1 9 1 2.10 C1 10 3 2.30 C1 11 5 2.50 C1 12 7 2.70 C1 data = data.frame (day = c(1,3,5,7,1,3,5,7,1,3,5,7), od = c(0.1,1.0,0.5,0.7 ,1.7,1.6,1.75,1.7 ,2.1,2.3,2.5,2.7), series_id = c("A1", "A1", "A1","A1", "B1", "B1","B1", "B1", "C1","C1", "C1", "C1")) r <- ggplot(data = data, aes(x = day, y = od)) r + stat_smooth(aes(group = series_id, color = series_id),method="lm")

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  • linear algebra libraries for clusters

    - by Abruzzo Forte e Gentile
    Hi all I need to develop applications doing linear algebra + eigenvalue + linear equation solutions over a cluster of pcs ( I have a lot of machines available ). I discovered Scalapack libraries but they seem to me developed long time ago. Do you know if these are other libs available that I should learn doing math & linear algebra in a cluster? My language is C++ and off course I am newbie to this topic. Kind Regards to everybody AFG

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  • Jquery gradient behavior applies to all but first URL

    - by Dustin
    I've got a page that shows my photography portfolio. I'm trying to do a jquery gradient on the text, and it's working on all but the first link. Here's the html: <h1><a href="portfolio/engagements"><span></span>engagements</a> | </h1><br> <h1><a href="portfolio/weddings"><span></span>weddings</a> | </h1> <br> <h1><a href="portfolio/bridals"><span></span>bridals</a> | </h1> <br> <h1><a href="portfolio/families"><span></span>families</a> | </h1> <br> <h1><a href="portfolio/seniors"><span></span>seniors</a> </h1> <br> And here's the jquery call: $(".jquery h1").prepend("<span></span>"); And here's the css for it: .gradient4 span { background: url(images/gradient-dark.png) repeat-x; position: absolute; bottom: -0.1em; display: inline; width: 100%; height: 29px; } The problem I'm having is that all urls but the first link (currently 'engagements'), have the gradient effect. Any ideas why the first link isn't working?

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  • CSS repeat pattern with linear gradient

    - by luca
    I'm on my first approach with photoshop patterns.I'm buildin a webpage where I want to use my pattern to give a nice effect to my webpage background. The pattern I found is 120x120 px If I was done here I should use this css: background-imag:url(mypattern.jpg); background-repeat:repeat; But Im not done.Id like to *add to my page's background a linear gradient(dir=top/down col=light-blue/green) with the pattern fill layer on top of it, with blending mode=darken *. This is the final effect: I come to the point. QUESTION: Combining linear vertical-gradient effect and my 120x120 pattern is it possible to find a pattern that I could use to repeat itself endlessly both vertical and horizontal??which is a common solution in this case? Hope It's clear thanks Luca

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  • How to gradient fill a button's background?

    - by Samuh
    I have to create a colored button with gradient fill(starting from the middle of the button along Y axis). If I set the background property of the button to the color I want, I lose the rounded look and feel of a button and also the gradient fill(It looks like a TextView with a background). Also, I want this color to change when the user depresses the button. Can i specify this via selector XMLs(Color State Lists)? Any tutorials or links that can help me here is appreciated. Thanks.

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  • Nested Linear layout only shows first view after being set from gone to visible in Android

    - by Adam
    Hi guys, I am developing an Android app but I'm still pretty new. I want to have a button, and when you push that button, a few TextViews and Buttons will appear. So I have a main linear layout, and then another linear layout nested inside containing the things I want hidden. I have the nested linear layout set to android:visibility="gone". The problem I am having is that it only shows the first item inside the hidden linear layout instead of all of them. The way I try to make it appear is vgAddView = (ViewGroup)findViewById(R.id.add_details); btnAche.setOnClickListener(new OnClickListener(){ public void onClick(View v){ vgAddView.setVisibility(0); } }); My XML file is this <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" > <Button android:text="@string/but_stomach_ache" android:id="@+id/but_stomach_ache" android:layout_width="fill_parent" android:layout_height="wrap_content"> </Button> <Button android:text="@string/but_food" android:id="@+id/but_food" android:layout_width="fill_parent" android:layout_height="wrap_content"> </Button> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:id="@+id/add_details" android:visibility="gone"> <TextView android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="@string/when_happen"> </TextView> <Button android:text="@string/happen_now" android:id="@+id/happen_now" android:layout_width="fill_parent" android:layout_height="wrap_content"> </Button> </LinearLayout> </LinearLayout>

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  • Excel 2007: plot data points not on an axis/ force linear x-incrementation without altering integrity of non-linear data

    - by Ennapode
    In Excel, how does one go about plotting points that don't have an x component that is an x-axis label? For example, in my graph, the x-components are derived from the cosine function and aren't linear, but Excel is displaying them as if .0016 to .0062 to .0135 is an equal incrementation. How would I change this so that the x-axis has an even incrementation without altering the integrity of the points themselves? In other words, how do I plot a point with an x component independent from the x-axis label?

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  • Thoughts about alternatives to barplot-with-error-bars

    - by gd047
    I was thinking of an alternative to the barplot-with-error-bars plot. To get an idea by example, I roughly 'sketched' what I mean using the following code library(plotrix) plot(0:12,type="n",axes=FALSE) gradient.rect(1,0,3,8,col=smoothColors("red",38,"red"),border=NA,gradient="y") gradient.rect(4,0,6,6,col=smoothColors("blue",38,"blue"),border=NA,gradient="y") lines(c(2,2),c(5.5,10.5)) lines(c(2-.5,2+.5),c(10.5,10.5)) lines(c(2-.5,2+.5),c(5.5,5.5)) lines(c(5,5),c(4.5,7.5)) lines(c(5-.5,5+.5),c(7.5,7.5)) lines(c(5-.5,5+.5),c(4.5,4.5)) gradient.rect(7,8,9,10.5,col=smoothColors("red",100,"white"),border=NA,gradient="y") gradient.rect(7,5.5,9,8,col=smoothColors("white",100,"red"),border=NA,gradient="y") lines(c(7,9),c(8,8),lwd=3) gradient.rect(10,6,12,7.5,col=smoothColors("blue",100,"white"),border=NA,gradient="y") gradient.rect(10,4.5,12,6,col=smoothColors("white",100,"blue"),border=NA,gradient="y") lines(c(10,12),c(6,6),lwd=3) The idea was to use bars like the ones in the second pair, instead of those in the first. However, there is something that I would like to change in the colors. Instead of a linear gradient fill, I would like to adjust the color intensity in accordance with the values of the pdf of the mean estimator. Do you think it is possible? A slightly different idea (where gradient fill isn't an issue) was to use one (or 2 back-to-back) bell curve(s) filled with (solid) color, instead of a rectangle. See for example the shape that corresponds to the letter F here. In that case the bell-curve(s) should (ideally) be drawn using something like plot(x, dnorm(x, mean = my.mean, sd = std.error.of.the.mean)) I have no idea though, of a way to draw rotated (and filled with color) bell curves. Of course, all of the above may be freely judged as midnight springtime dreams :-)

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  • Color picker does not give gradient appearance

    - by ykaratoprak
    i added below codes. But it generates to me 16 color. but i need 16 color between "red" and "khaki". i don't need gradient flow. My colors look like gradient flow. My colors must not closer to each other. Because i will use this codes return values in chart columns. they are too near each other. static class Program { [STAThread] static void Main() { Form form = new Form(); Color start = Color.Red, end = Color.Khaki; for (int i = 0; i < 16; i++) { int r = Interpolate(start.R, end.R, 15, i), g = Interpolate(start.G, end.G, 15, i), b = Interpolate(start.B, end.B, 15, i); Button button = new Button(); button.Dock = DockStyle.Top; button.BackColor = Color.FromArgb(r, g, b); form.Controls.Add(button); button.BringToFront(); } Application.Run(form); } static int Interpolate(int start, int end, int steps, int count) { float s = start, e = end, final = s + (((e - s) / steps) * count); return (int)final; } }

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  • Gradient fills only half the cell

    - by Gopal
    Hi, How do I get the IE gradient function here in this code sample to completely fill the table cell? With the code given below, I could only get it to cover the upper half of the cell. <HTML> <HEAD> <style> <!--table .cl1 { font-family:Comic Sans MS; font-size:11.0pt; color:#800000; border-left:1.5pt solid #000000; border-top:1.5pt solid #000000; border-right:1.5pt solid #000000; border-bottom:1.5pt solid #000000; background-color:#ffffff; filter: progid:DXImageTransform.Microsoft.Gradient(GradientType=1, StartColorStr='#ffffff', EndColorStr='#99cc00') progid:DXImageTransform.Microsoft.dropshadow(Color='#660000', Positive='true', OffX=0, OffY=0); } --> </style></HEAD> <BODY> <table x:str cellspacing=0 style='table-layout:fixed; border-left:1.0pt solid; border-top:1.0pt solid; border-right:1.0pt solid; border-bottom:1.0pt solid; border-left-color:#c0c0c0; border-top-color:#c0c0c0; border-right-color:#c0c0c0; border-bottom-color:#c0c0c0; '> <col style='width:67pt;'> <tr style='height:28.00pt'> <td class=cl1 style='width:67pt;'>Cell Text</td> </tr> </BODY> </HTML>

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