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  • Display a tree dijit using zend framework

    - by churris43
    I am trying to display a tree of categories and subcategories by using dijits with zend framework. Haven't been able to find a good example. This is what I've got: Basically I got the following code as my action: class SubcategoriesController extends Zend_Controller_Action{ ..... public function loadtreeAction() { Zend_Dojo::enableView($this->view); Zend_Layout::getMvcInstance()->disableLayout(); //Creating a sample tree of categories and subcategories $a["cat1"]["id"] = "id1"; $a["cat1"]["name"] = "Category1"; $a["cat1"]["type"] = "category"; $subcat1 = array("id" => "Subcat1","name" => "Subcategory1" , "type" => "subcategory"); $subcat2 = array("id" => "Subcat12","name" => "Subcategory12" , "type" => "subcategory"); $a["cat1"]["children"] = array($subcat1,$subcat2); $treeObj = new Zend_Dojo_Data('id', $a); $treeObj->setLabel('name'); $this->view->tree = $treeObj->toJson(); } .... } And on my view: <?php $this->dojo()->requireModule('dojo.data.ItemFileReadStore'); $this->dojo()->requireModule('dijit.Tree'); $this->dojo()->requireModule('dojo.parser'); ?> <div dojoType="dojo.data.ItemFileReadStore" url="/Subcategories/loadtree" jsId="store"></div> <div dojoType="dijit.tree.ForestStoreModel" jsId="treeModel" store="store" rootId="root" rootLabel="List of Categories" childrenAttrs="children" query="{type:'category'}"></div> <div dojoType="dijit.Tree" model="treeModel" labelAttrs="ListOfCategories"></div> It doesn't even seem to try to load the tree at all. Any help is appreciated

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  • Reduced Tree View in NetBeans IDE 7.2

    - by Geertjan
    Right-click within the Projects window in NetBeans IDE 7.2 and from the "View Java Packages As" menu, you can now choose "Reduced Tree".I never really understood the difference between "Reduced Tree" and the already existing "Tree". But it makes sense when you see it. Here's Reduced Tree view: And here's Tree view, where you can see that the "actions" and "nodes" packages above each have their own top level package nodes, which takes up more space than the above: What's cool is that your selected package view is persisted across restarts of the IDE. To be complete, here's the List view, which is the third option you have in the "View Java Packages As" menu: Seems to me like the new Reduced Tree view combines the best of the Tree view with the best of the List view! Related issue: http://netbeans.org/bugzilla/show_bug.cgi?id=53192

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  • check if a tree is a binary search tree

    - by TimeToCodeTheRoad
    I have written the following code to check if a tree is a Binary search tree. Please help me check the code: Pair p{ boolean isTrue; int min; int max; } public boo lean isBst(BNode v){ return isBST1(v).isTrue; } public Pair isBST1(BNode v){ if(v==null) return new Pair(true, INTEGER.MIN,INTEGER.MAX); if(v.left==null && v.right==null) return new Pair(true, v.data, v.data); Pair pLeft=isBST1(v.left); Pair pRight=isBST1(v.right); boolean check=pLeft.max<v.data && v.data<= pRight.min; Pair p=new Pair(); p.isTrue=check&&pLeft.isTrue&&pRight.isTrue; p.min=pLeft.min; p.max=pRight.max; return p; } Note: This function checks if a tree is a binary search tree

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  • how does NTFS actually work with B-tree ?

    - by bakra
    To improve performance, NTFS directories use a special data management structure called a B-tree. "B-tree" concept here refers to a "tree of storage units" that hold the contents of an individual directory. What I don't understand is where on the disk is this tree stored? Its surely not created every-time we reboot...that would take lots of time. and since its a tree(dynamic Data structure) unlike arrays it will grow. so space needs to be allocated every-time it grows. so how is this "dynamic meta-data" stored ?

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  • URL rewriting with mod_rewrite

    - by Steven
    The web server is Apache. I want to rewrite URL so a user won't know the actual directory. For example: The original URL: www.mydomainname.com/en/piecework/piecework.php?piecework_id=11 Expected URL: piecework.mydomainname.com/en/11 I added the following statements in .htaccess: RewriteCond %{HTTP_HOST} ^(?!www)([^.]+)\.mydomainname\.com$ [NC] RewriteRule ^(w+)/(\d+)$ /$1/%1/%1.php?%1_id=$2 [L] Of course I replaced mydomainname with my domain name. .htaccess is placed in the site root, but when I access piecework.mydomainname.com/en/11, I got "Object not found".(Of course I replaced mydomainname with my domain name.) I added the following statements in .htaccess: RewriteRule ^/(.*)/en/piecework/(.*)piecework_id=([0-9]+)(.*) piecework.mydomainname.com/en/$3 Of course I replaced mydomainname with my domain name. .htaccess is placed in the site root, but when I access piecework.mydomainname.com/en/11, I got "Object not found".(Of course I replaced mydomainname with my domain name.) What's wrong?

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  • ASP.Net URL rewriting and redirecting....

    - by DDiVita
    I am trying to wrap my head around a URL rewrtie / redirect project I need to work on. We currently have this url: www.domain.com/Details/Detail.aspx?param1=8&param2=12345 Here is what the rewritten URL will look like: www.domain.com/Param1/8/Param2/12345 I am using the ISAPI_Rewrite filter to allow for the "nice" url and make the page think it is still using the old url. That works fine. Now, I need to redirect users, if they use the old URL, to the new URL. I fgiure I would need to use a combination of the filter and an HTTPModule / Handler to perfomr the redirect. Any ideas?

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  • url rewriting index.php

    - by bean
    i have urls like http://mysite.com/index.php?p=resources http://mysite.com/index.php?p=resources&s=view&id=938 but i want urls like http://mysite.com/resources http://mysite.com/resources/view/938 instead of making hundreds of rewrite rules i wonder if it would be possible to just have one? Ive head this is possible by "getting the uri and splitting it into parts" and then just add a rewrite rule for index.php but how? could someone give an example or link a tutorial

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  • Asp.net url rewriting and domain redirection

    - by GregM
    I have a domain "test.com" and I want this domain to redirect to "mydomain.com/test". I'm with 1and1 for my domain test.com and with discountAsp for mydomain.com. In the control panel of 1and1 you can set a redirection from a domain to another domain, so everything is fine. But when i'm on the page mydomain.com/test I want my url to be rewritten as test.com Is this possible to do that with IIS or in my asp.page (would prefer in my page) I'm using iis7 Thanks

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  • ASP.NET, IIS 6 and url rewriting

    - by stighy
    Hi, i've bought a shared hosting on a windows hoster with IIS 6. I would like to know how to rewrite url. I can't modify anything on the server, the only thing i can do is to use ... my asp.net code ! some advice ? Thanks!

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  • Problem Rewriting URL's from HTTPS to HTTP using IIS7 URL Rewriter, when using Webforms ReturnURL=

    - by theminesgreg
    I took Jeff's Re-write rules from this post and the HTTP to HTTPS conversion works great. However, going back to HTTP is giving me problems because of the ReturnUrl= in the URL (I'm using webforms). Here's an example of the url: https://localhost/Login.aspx?ReturnUrl=%2f Here's the rewrite rule I'm using: <rule name="HTTPS to HTTP redirect for all other pages" stopProcessing="true"> <match url="^login\.aspx$" ignoreCase="true" negate="true" /> <conditions> <add input="{SERVER_PORT}" pattern="^443$" /> </conditions> <action type="Redirect" redirectType="Found" url="http://{HTTP_HOST}{REQUEST_URI}" /> </rule> Here's the resulting re-written URL: http://localhost/,/ Has anyone found a work around for this?

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  • rewriting single url help

    - by Rich
    Hi, I'm trying to rewrite the following url: index.php?route=checkout/cart to /cart using: RewriteRule ^index.php?route=checkout/cart$ /basket [L] However it doesn't seem to work. Anyone know what I'm doing wrong? Thanks

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  • Page not rewriting in ExpressionEngine

    - by Andrew
    I recently just launched an ExpressionEngine site and one of the last steps I take is removing index.php from the URL. In the case of this site, the default template group is called "site". Long story short, after removing index.php from the URL, all pages continue to work great with the exception of my contact page, which also lives in the "site" template group. Going to http://example.com/contact/ gives me a 404 while going to http://example.com/site/contact produces the desired result. In past ExpressionEngine site setups (including my own) this has never happened, so does anyone have thoughts on why this might not be working?

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  • ASP.NET MVC Url Masking/Rewriting

    - by Dan Appleyard
    Let us say I have a url of subdomain.domain.com. Is there a way in ASP.NET MVC to have a url of say otherdomain.com/gotothesubdomain that takes you to subdomain.domain.com? I know that a simple redirect could do it, but I want the url to stay as otherdomain.com/gotothesubdomain. Any advice would be greatly appreciated and thanks!

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  • URL rewriting in Wordpress

    - by Ajith
    I want to rewrite my url in wordpress. How can i rewrite my url in wordpress. I am trying to create htaccess file like following <IfModule mod_rewrite.c> RewriteEngine On RewriteBase /shopboxtile/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^([0-9]+)$ http://localhost/shopboxtile/?productid=$1 </IfModule> I think it is not correct.please help me to correct it. My requirement is to convert url from http://localhost/shopboxtile/?productid=59961 to http://localhost/shopboxtile/59961

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  • Rewriting URL's in ASP.net (Simple question)

    - by Tom Gullen
    On my master page I have: <link rel="stylesheet" href="css/default.css" /> I also have a page "blog.aspx" in the root directory. I have the rule: <rewrite url="~/blog/blog.aspx" to="~/blog.aspx" /> My questions are: Am I meant to make all my links in my site point to blog/blog.aspx now instead of just blog.aspx where it is physically located How is best to cope with the paths of the stylesheets etc now being messed up because they are one dir up?

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  • Accessing selected node of richfaces tree from Javascript

    - by kazanaki
    Hello This should be a very simple question. I have a richfaces tree that is rendered using JSF. When the user clicks on a node I want a javascript function to run. Nothing more nothing less. No redirects, no re-submit, no-rerender, no Ajax. Just plain old Javascript. I have seen the onselected attribute of the tree and it indeed fires a Javascript method. But of course I want to know which node was clicked. Here is what I have so far <head> <script type="text/javascript"> function documentClicked(nodeRef) { alert("Node is "+nodeRef); } </script> </head> <rich:tree switchType="client" value="#{ajaxDocumentTree.rootNode}" var="document" onselected="documentClicked()" > <rich:treeNode iconLeaf="../images/tree/doc.gif" icon="../images/tree/doc.gif"> <h:outputText value="#{doc.friendlyName}" /> </rich:treeNode> But this does not work because nodeRef is undefined. I expected that the first argument of the callback would be the selected node but this is not the case. So the question is this: How do I fire a Javascript function with the selected node from a richfaces tree?

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  • JQGrid tree - passing additional parameters when tree is expanded

    - by PHP thinker
    I have a JQGRid tree. It loads data click by click, not all at once. Typically, JQGRid passes 4 standard tree parameters with each call - row (level, parent, is leaf, is expanded). How can I pass more parameters that I will take from the row being expanded? E.g. data from Name column should be passed in AJAX call too. There doesn't seem to be OnExpand event or similar.

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  • k-d tree implementation [closed]

    - by user466441
    when i run my code and debugged,i got this error - this 0x00093584 {_Myproxy=0x00000000 _Mynextiter=0x00000000 } std::_Iterator_base12 * const - _Myproxy 0x00000000 {_Mycont=??? _Myfirstiter=??? } std::_Container_proxy * _Mycont CXX0017: Error: symbol "" not found _Myfirstiter CXX0030: Error: expression cannot be evaluated + _Mynextiter 0x00000000 {_Myproxy=??? _Mynextiter=??? } std::_Iterator_base12 * but i dont know what does it means,code is this #include<iostream> #include<vector> #include<algorithm> using namespace std; struct point { float x,y; }; vector<point>pointleft(4); vector<point>pointright(4); //we are going to implement two comparison function for x and y coordinates,we need it in calculation of median (we should sort vector //by x or y according to depth informaton,is depth even or odd. bool sortby_X(point &a,point &b) { return a.x<b.x; } bool sortby_Y(point &a,point &b) { return a.y<b.y; } //so i am going to implement to median finding algorithm,one for finding median by x and another find median by y point medianx(vector<point>points) { point temp; sort(points.begin(),points.end(),sortby_X); temp=points[(points.size()/2)]; return temp; } point mediany(vector<point>points) { point temp; sort(points.begin(),points.end(),sortby_Y); temp=points[(points.size()/2)]; return temp; } //now construct basic tree structure struct Tree { float x,y; Tree(point a) { x=a.x; y=a.y; } Tree *left; Tree *right; }; Tree * build_kd( Tree *root,vector<point>points,int depth) { point temp; if(points.size()==1)// that point is as a leaf { if(root==NULL) root=new Tree(points[0]); return root; } if(depth%2==0) { temp=medianx(points); root=new Tree(temp); for(int i=0;i<points.size();i++) { if (points[i].x<temp.x) pointleft[i]=points[i]; else pointright[i]=points[i]; } } else { temp=mediany(points); root=new Tree(temp); for(int i=0;i<points.size();i++) { if(points[i].y<temp.y) pointleft[i]=points[i]; else pointright[i]=points[i]; } } return build_kd(root->left,pointleft,depth+1); return build_kd(root->right,pointright,depth+1); } void print(Tree *root) { while(root!=NULL) { cout<<root->x<<" " <<root->y; print(root->left); print(root->right); } } int main() { int depth=0; Tree *root=NULL; vector<point>points(4); float x,y; int n=4; for(int i=0;i<n;i++) { cin>>x>>y; points[i].x=x; points[i].y=y; } root=build_kd(root,points,depth); print(root); return 0; } i am trying ti implement in c++ this pseudo code tuple function build_kd_tree(int depth, set points): if points contains only one point: return that point as a leaf. if depth is even: Calculate the median x-value. Create a set of points (pointsLeft) that have x-values less than the median. Create a set of points (pointsRight) that have x-values greater than or equal to the median. else: Calculate the median y-value. Create a set of points (pointsLeft) that have y-values less than the median. Create a set of points (pointsRight) that have y-values greater than or equal to the median. treeLeft = build_kd_tree(depth + 1, pointsLeft) treeRight = build_kd_tree(depth + 1, pointsRight) return(median, treeLeft, treeRight) please help me what this error means?

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  • Extjs: Tree, Selecting node after creating the tree

    - by Natkeeran
    I have a simple TreePanel. I would like to select a particular node upon loading it. The nodes are from a remote file (json). The tree is loading as expected. However, the node is not being selected. Firebug shows node as undefined. This perhaps because of the async property. But, I an unable to configure this other wise, or specify the node be selected. Any suggestions welcomed, and thank you. LeftMenuTree = new Ext.tree.TreePanel({ renderTo: 'TreeMenu', collapsible: false, height: 450, border: false, userArrows: true, animate: true, autoScroll: true, id: 'testtest', dataUrl: fileName, root: { nodeType: 'async', iconCls:'home-icon', expanded:true, text: rootText }, listeners: { "click": { fn: onPoseClick, scope: this } }, "afterrender": { fn: setNode, scope: this } }); function setNode(){ alert (SelectedNode); if (SelectedNode == "Orders"){ var treepanel = Ext.getCmp('testtest'); var node = treepanel.getNodeById("PendingItems"); node.select(); } }

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  • SVN project folder tree structure vs production folder tree structure

    - by Marco Demaio
    While developing a PHP+JS web application we always try to separate big blocks of code into small modules/components, in order to make these last ones as much reusable as possible in other applications. Let's say we now have: the EcommerceApp (an ecommerce main application) a Server-file-mgr component (a component to view/manage file on server) a Mylib (a library of useful functions) a MailistApp (another main application to handle mail lists) ... EcommerceApp needs both Server-file-mgr component and Mylib to work Server-file-mgr needs Mylib to work MaillistApp needs both Server-file-mgr component and Mylib to work too. My idea is to simply structure the SVN project folder tree putting everything at the same level: trunk/EcommerceApp trunk/Server-file-mgr trunk/Mylib trunk/MaillistApp But in real life to make these apps to work the folder tree structure must be the following: EcommerceApp |_ Mylib |_ Server-file-mgr MaillistApp |_ Mylib |_ Server-file-mgr I mean Mylib and Server-file-mgr needs to be inside the EcommerceApp/MaillistApp folder. How would you then structure the SVN folder, as I did or in a different/better/smarter way???

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  • Insert element into a tree from a list in Standard ML

    - by vichet
    I have just started to learn SML on my own and get stuck with a question from the tutorial. Let say I have: tree data type datatype node of (tree*int*tree) | null insert function fun insert (newItem, null) = node (null, newItem, null) | insert (newItem, node (left, oldItem, right)) = if (newItem <= oldItem) then node (insert(newItem,left),oldItem, right) else node (left, oldItem, insert(newItem, right) an integer list val intList = [19,23,21,100,2]; my question is how can I add write a function to loop through each element in the list and add to a tree? Your answer is really appreciated.

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