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  • Java language convention; getters/setters

    - by Skogen
    Public class Example { private int number; public Example(int number){ this.number = number; } public int getNumber(){ return number; } public void setNumber(int number){ this.number = number; } public static void main(String[] args){ Example e = new Example(5); What is preffered when accessing a variable within its own class; "e.number" or "e.getNumber()" ?

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  • What does /*!*/ mean in C#?

    - by Tristan
    I'm new to C# and am reading code with /*!*/ in what seem like strange places. For instance class methods defined as: protected override OptionsParser/*!*/ CreateOptionsParser() protected override void ParseHostOptions(string/*!*/[]/*!*/ args) Unfortunately /*!*/ is not googleable. What does it mean?

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  • Java: initialization problem, cannot print "assigned" values from arrayList

    - by HH
    $ javac ArrayListTest.java $ java ArrayListTest $ cat ArrayListTest.java import java.io.*; import java.util.*; public class ArrayListTest{ public static void main(String[] args) { try { String hello ="oeoaseu oeu hsoae sthoaust hoaeut hoasntu"; ArrayList<String> appendMe = null; for(String s : hello.split(" ")) appendMe.add(s+" "); for(String s : appendMe) System.out.println(s); //WHY DOES IT NOT PRINT? }catch(Exception e){ } } }

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  • Where should I initialize variables for an OO Recursive Descent Parse Tree?

    - by Vasto
    I'd like to preface this by stating that this is for a class, so please don't solve this for me. One of my labs for my cse class is creating an interpreter for a BNF that was provided. I understand most of the concepts, but I'm trying to build up my tree and I'm unsure where to initialize values. I've tried in both the constructor, and in the methods but Eclipse's debugger still only shows the left branch, even though it runs through completely. Here is my main procedure so you can get an idea of how I'm calling the methods. public class Parser { public static void main(String[] args) throws IOException { FileTokenizer instance = FileTokenizer.Instance(); FileTokenizer.main(args); Prog prog = new Prog(); prog.ParseProg(); prog.PrintProg(); prog.ExecProg(); } Now here is My Prog class: public class Prog { private DeclSeq ds; private StmtSeq ss; Prog() { ds = new DeclSeq(); ss = new StmtSeq(); } public void ParseProg() { FileTokenizer instance = FileTokenizer.Instance(); instance.skipToken(); //Skips program (1) // ds = new DeclSeq(); ds.ParseDS(); instance.skipToken(); //Skips begin (2) // ss = new StmtSeq(); ss.ParseSS(); instance.skipToken(); } I've tried having Prog() { ds = null; ss = null; } public void ParseProg() { FileTokenizer instance = FileTokenizer.Instance(); instance.skipToken(); //Skips program (1) ds = new DeclSeq(); ds.ParseDS(); ... But it gave me the same error. I need the parse tree built up so I can do a pretty print and an execute command, but like I said, I only get the left branch. Any help would be appreciated. Explanations why are even more so appreciated. Thank you, Vasto

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  • Assembly Load and loading the "sub-modules" dependencies - "cannot fild the file specified"

    - by Ted
    There are several questions out there that ask the same question. However the answers they received I cannot understand, so here goes: Similar questions: http://stackoverflow.com/questions/1874277/dynamically-load-assembly-and-manually-force-path-to-get-referenced-assemblies ; http://stackoverflow.com/questions/22012/loading-assemblies-and-its-dependencies-closed The question in short: I need to figure out how dependencies, ie References in my modules can be loaded dynamically. Right now I am getting "The system cannot find the file specified" on Assemblies referenced in my so called modules. I cannot really get how to use the AssemblyResolve event... The longer version I have one application, MODULECONTROLLER, that loads separate modules. These "separate modules" are located in well-known subdirectories, like appBinDir\Modules\Module1 appBinDir\Modules\Module2 Each directory contains all the DLLs that exists in the bin-directory of those projects after a build. So the MODULECONTROLLER loads all the DLLs contained in those folders using this code: byte[] bytes = File.ReadAllBytes(dllFileFullPath); Assembly assembly = null; assembly = Assembly.Load(bytes); I am, as you can see, loading the byte[]-array (so I dont lock the DLL-files). Now, in for example MODULE1, I have a static reference called MyGreatXmlProtocol. The MyGreatXmlProtocol.dll then also exists in the directory appBinDir\Modules\Module1 and is loaded using the above code When code in the MODULE1 tries to use this MyGreatXmlProtocol, I get: Could not load file or assembly 'MyGreatXmlProtocol, Version=1.0.3797.26527, Culture=neutral, PublicKeyToken=null' or one of its dependencies. The system cannot find the file specified. So, in a post (like this one) they say that To my understanding reflection will load the main assembly and then search the GAC for the referenced assemblies, if it cannot find it there, you can then incorparate an assemblyResolve event: First; is it really needed to use the AssemblyResolve-event to make this work? Shouldnt my different MODULEs themself load their DLLs, as they are statically referenced? Second; if AssemblyResolve is the way to go - how do I use it? I have attached a handler to the Event but I never get anything on MyGreatXmlProctol... === EDIT === CODE regarding the AssemblyResolve-event handler: public GUI() { InitializeComponent(); AppDomain.CurrentDomain.AssemblyResolve += new ResolveEventHandler(CurrentDomain_AssemblyResolve); ... } // Assembly CurrentDomain_AssemblyResolve(object sender, ResolveEventArgs args) { Console.WriteLine(args.Name); return null; } Hope I wasnt too fuzzy =) Thx

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  • A question about GC

    - by chun
    This is a quesiton taken from a java exam, How many objects are eligible for gabage collection at #1 ? public class Main { Integer x = 32768; public static void main(String[] args) { Main m = new Main(); m = null; // #1 } } I thought it just collect Integer x, does GC even collect the Main object m?

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  • Exception when access inner class reflectively

    - by MikeJiang
    Hi Folk, Here is a sample java program. I wonder why the two approaches reslut different stories. Is it a bug or kind of bitter java feature? And I run the sample upon java 1.5 package test; public class TestOut{ public static void main(String[] args){ new TestIn();//it works Class.forName("test.TestOut$TestIn").newInstance();// throw IllegalAccessException } private static class TestIn{} }

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  • How can I connect to MSMQ over a workgroup?

    - by cyclotis04
    I'm writing a simple console client-server app using MSMQ. I'm attempting to run it over the workgroup we have set up. They run just fine when run on the same computer, but I can't get them to connect over the network. I've tried adding Direct=, OS:, and a bunch of combinations of other prefaces, but I'm running out of ideas, and obviously don't know the right way to do it. My queue's don't have GUIDs, which is also slightly confusing. Whenever I attempt to connect to a remote machine, I get an invalid queue name message. What do I have to do to make this work? Server: class Program { static string _queue = @"\Private$\qim"; static MessageQueue _mq; static readonly object _mqLock = new object(); static void Main(string[] args) { _queue = Dns.GetHostName() + _queue; lock (_mqLock) { if (!MessageQueue.Exists(_queue)) _mq = MessageQueue.Create(_queue); else _mq = new MessageQueue(_queue); } Console.Write("Starting server at {0}:\n\n", _mq.Path); _mq.Formatter = new BinaryMessageFormatter(); _mq.BeginReceive(new TimeSpan(0, 1, 0), new object(), OnReceive); while (Console.ReadKey().Key != ConsoleKey.Escape) { } _mq.Close(); } static void OnReceive(IAsyncResult result) { Message msg; lock (_mqLock) { try { msg = _mq.EndReceive(result); Console.Write(msg.Body); } catch (Exception ex) { Console.Write("\n" + ex.Message + "\n"); } } _mq.BeginReceive(new TimeSpan(0, 1, 0), new object(), OnReceive); } } Client: class Program { static MessageQueue _mq; static void Main(string[] args) { string queue; while (_mq == null) { Console.Write("Enter the queue name:\n"); queue = Console.ReadLine(); //queue += @"\Private$\qim"; try { if (MessageQueue.Exists(queue)) _mq = new MessageQueue(queue); } catch (Exception ex) { Console.Write("\n" + ex.Message + "\n"); _mq = null; } } Console.Write("Connected. Begin typing.\n\n"); _mq.Formatter = new BinaryMessageFormatter(); ConsoleKeyInfo key = new ConsoleKeyInfo(); while (key.Key != ConsoleKey.Escape) { key = Console.ReadKey(); _mq.Send(key.KeyChar.ToString()); } } }

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  • Why do sockets not die when server dies? Why does a socket die when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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  • Jumping into argv?

    - by jth
    Hi, I`am experimenting with shellcode and stumbled upon the nop-slide technique. I wrote a little tool that takes buffer-size as a parameter and constructs a buffer like this: [ NOP | SC | RET ], with NOP taking half of the buffer, followed by the shellcode and the rest filled with the (guessed) return address. Its very similar to the tool aleph1 described in his famous paper. My vulnerable test-app is the same as in his paper: int main(int argc, char **argv) { char little_array[512]; if(argc>1) strcpy(little_array,argv[1]); return 0; } I tested it and well, it works: jth@insecure:~/no_nx_no_aslr$ ./victim $(./exploit 604 0) $ exit But honestly, I have no idea why. Okay, the saved eip was overwritten as intended, but instead of jumping somewhere into the buffer, it jumped into argv, I think. gdb showed up the following addresses before strcpy() was called: (gdb) i f Stack level 0, frame at 0xbffff1f0: eip = 0x80483ed in main (victim.c:7); saved eip 0x154b56 source language c. Arglist at 0xbffff1e8, args: argc=2, argv=0xbffff294 Locals at 0xbffff1e8, Previous frame's sp is 0xbffff1f0 Saved registers: ebp at 0xbffff1e8, eip at 0xbffff1ec Address of little_array: (gdb) print &little_array[0] $1 = 0xbfffefe8 "\020" After strcpy(): (gdb) i f Stack level 0, frame at 0xbffff1f0: eip = 0x804840d in main (victim.c:10); saved eip 0xbffff458 source language c. Arglist at 0xbffff1e8, args: argc=-1073744808, argv=0xbffff458 Locals at 0xbffff1e8, Previous frame's sp is 0xbffff1f0 Saved registers: ebp at 0xbffff1e8, eip at 0xbffff1ec So, what happened here? I used a 604 byte buffer to overflow little_array, so he certainly overwrote saved ebp, saved eip and argc and also argv with the guessed address 0xbffff458. Then, after returning, EIP pointed at 0xbffff458. But little_buffer resides at 0xbfffefe8, that`s a difference of 1136 byte, so he certainly isn't executing little_array. I followed execution with the stepi command and well, at 0xbffff458 and onwards, he executes NOPs and reaches the shellcode. I'am not quite sure why this is happening. First of all, am I correct that he executes my shellcode in argv, not little_array? And where does the loader(?) place argv onto the stack? I thought it follows immediately after argc, but between argc and 0xbffff458, there is a gap of 620 bytes. How is it possible that he successfully "lands" in the NOP-Pad at Address 0xbffff458, which is way above the saved eip at 0xbffff1ec? Can someone clarify this? I have actually no idea why this is working. My test-machine is an Ubuntu 9.10 32-Bit Machine without ASLR. victim has an executable stack, set with execstack -s. Thanks in advance.

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  • How to get the path of a shortcut (NOT target path) in .net?

    - by okkko
    Hello world! I have an .exe application written in vb.net. When I make shortcuts to the application, say on desktop (or anywhere else) and then click on them I want to programatically get the path to that shortcut, ie. C:/Users/xxx/Desktop/shortcut.lnk. I want this so I can store the pairs shortcuts : (program + different cmd args).

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  • Dispatcher.CurrentDispatcher?

    - by Mark
    If I do this... public PriorityQueue(Dispatcher dispatcher = null) { this.dispatcher = dispatcher ?? Dispatcher.CurrentDispatcher; } And then use it in a ViewModel (without passing any args) that is created through the XAML, this.dispatcher will point to the UI thread right?

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  • jQuery UI dialog + WebKit + HTML response with script

    - by Anthony Koval'
    Once again I am faced with a great problem! :) So, here is the stuff: on the client side, I have a link. By clicking on it, jQuery makes a request to the server, gets response as HTML content, then popups UI dialog with that content. Here is the code of the request-function: function preview(){ $.ajax({ url: "/api/builder/", type: "post", //dataType: "html", data: {"script_tpl": $("#widget_code").text(), "widgets": $.toJSON(mwidgets), "widx": "0"}, success: function(data){ //console.log(data) $("#previewArea").dialog({ bgiframe: true, autoOpen: false, height: 600, width: 600, modal: true, buttons: { "Cancel": function() { $(this).dialog('destroy'); } } }); //console.log(data.toString()); $('#previewArea').attr("innerHTML", data.toString()); $("#previewArea").dialog("open"); }, error: function(){ console.log("shit happens"); } }) } The response (data) is: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <script type="text/javascript">var smakly_widget_sid = 0 ,widgets = [{"cols": "2","rows": "2","div_id": "smakly_widget","wid": "0","smakly_style": "small_image",}, ] </script> <script type="text/javascript" src="/media/js/smak/smakme.js"></script> </head> <body> preview <div id="smakly_widget" style="width:560px;height:550px"> </div> </body> </html> As you see, there is a script to load: smakme.js, somehow it doesn't execute in WebKit-based browsers (I tried in Safari and Chrome), but in Firefox, Internet Explorer and Opera it works as expected! Here is that script: String.prototype.format = function(){ var pattern = /\{\d+\}/g; var args = arguments; return this.replace(pattern, function(capture){ return args[capture.match(/\d+/)]; }); } var turl = "/widget" var widgetCtrl = new(function(){ this.render_widget = function (w, content){ $("#" + w.div_id).append(content); } this.build_widgets = function(){ for (var widx in widgets){ var w = widgets[widx], iurl = '{0}?sid={1}&wid={2}&w={3}&h={4}&referer=http://ya.ru&thrash={5}'.format( turl, smakly_widget_sid, w.wid, w.cols, w.rows, Math.floor(Math.random()*1000).toString()), content = $('<iframe src="{0}" width="100%" height="100%"></iframe>'.format(iurl)); this.render_widget(w, content); } } }) $(document).ready(function(){ widgetCtrl.build_widgets(); }) Is that some security issue, or anything else?

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  • Regex to match javadoc style comments

    - by Anant
    I have files having content like /** * Some Content * @param .. * @author .. * */ function a_sample_function ( $args = '' ) { I need to extract the text Some Content @param .. @author .. given a function name a_sample_function ( the * can be removed by a gsub later I believe) I'm writing this in ruby.

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  • due at midnight - program compiles but has logic error(s)

    - by Leslie Laraia
    not sure why this program isn't working. it compiles, but doesn't provide the expected output. the input file is basically just this: Smith 80000 Jones 100000 Scott 75000 Washington 110000 Duffy 125000 Jacobs 67000 Here is the program: import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; /** * * @author Leslie */ public class Election { /** * @param args the command line arguments */ public static void main(String[] args) throws FileNotFoundException { // TODO code application logic here File inputFile = new File("C:\\Users\\Leslie\\Desktop\\votes.txt"); Scanner in = new Scanner(inputFile); int x = 0; String line = ""; Scanner lineScanner = new Scanner(line); line = in.nextLine(); while (in.hasNextLine()) { line = in.nextLine(); x++; } String[] senatorName = new String[x]; int[] votenumber = new int[x]; double[] votepercent = new double[x]; System.out.printf("%44s", "Election Results for State Senator"); System.out.println(); System.out.printf("%-22s", "Candidate"); //Prints the column headings to the screen System.out.printf("%22s", "Votes Received"); System.out.printf("%22s", "%of Total Votes"); int i; for(i=0; i<x; i++) { while(in.hasNextLine()) { line = in.nextLine(); String candidateName = lineScanner.next(); String candidate = candidateName.trim(); senatorName[i] = candidate; int votevalue = lineScanner.nextInt(); votenumber[i] = votevalue; } } votepercent = percentages(votenumber, x); for (i = 0; i < x; i++) { System.out.println(); System.out.printf("%-22s", senatorName[i]); System.out.printf("%22d", votenumber[i]); System.out.printf("%22.2f", votepercent[i]); System.out.println(); } } public static double [] percentages(int[] votenumber, int z) { double [] percentage = new double [z]; double total = 0; for (double element : votenumber) { total = total + element; } for(int i=0; i < votenumber.length; i++) { int y = votenumber[i]; percentage[i] = (y/total) * 100; } return percentage; } }

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  • Help me with this java program

    - by aser
    The question : Input file: customer’s account number, account balance at beginning of month, transaction type (withdrawal, deposit, interest), transaction amount Output: account number, beginning balance, ending balance, total interest paid, total amount deposited, number of deposits, total amount withdrawn, number of withdrawals package sentinel; import java.io.*; import java.util.*; public class Ex7 { /** * @param args the command line arguments */ public static void main(String[] args) throws FileNotFoundException { int AccountNum; double BeginningBalance; double TransactionAmount; int TransactionType; double AmountDeposited=0; int NumberOfDeposits=0; double InterestPaid=0.0; double AmountWithdrawn=0.0; int NumberOfWithdrawals=0; boolean found= false; Scanner inFile = new Scanner(new FileReader("Account.in")); PrintWriter outFile = new PrintWriter("Account.out"); AccountNum = inFile.nextInt(); BeginningBalance= inFile.nextDouble(); while (inFile.hasNext()) { TransactionAmount=inFile.nextDouble(); TransactionType=inFile.nextInt(); outFile.printf("Account Number: %d%n", AccountNum); outFile.printf("Beginning Balance: $%.2f %n",BeginningBalance); outFile.printf("Ending Balance: $%.2f %n",BeginningBalance); outFile.println(); switch (TransactionType) { case '1': // case 1 if we have a Deposite BeginningBalance = BeginningBalance + TransactionAmount; AmountDeposited = AmountDeposited + TransactionAmount; NumberOfDeposits++; outFile.printf("Amount Deposited: $%.2f %n",AmountDeposited); outFile.printf("Number of Deposits: %d%n",NumberOfDeposits); outFile.println(); break; case '2':// case 2 if we have an Interest BeginningBalance = BeginningBalance + TransactionAmount; InterestPaid = InterestPaid + TransactionAmount; outFile.printf("Interest Paid: $%.2f %n",InterestPaid); outFile.println(); break; case '3':// case 3 if we have a Withdraw BeginningBalance = BeginningBalance - TransactionAmount; AmountWithdrawn = AmountWithdrawn + TransactionAmount; NumberOfWithdrawals++; outFile.printf("Amount Withdrawn: $%.2f %n",AmountWithdrawn); outFile.printf("Number of Withdrawals: %d%n",NumberOfWithdrawals); outFile.println(); break; default: System.out.println("Invalid transaction Tybe: " + TransactionType + TransactionAmount); } } inFile.close(); outFile.close(); } } But is gives me this : Exception in thread "main" java.util.InputMismatchException at java.util.Scanner.throwFor(Scanner.java:840) at java.util.Scanner.next(Scanner.java:1461) at java.util.Scanner.nextInt(Scanner.java:2091) at java.util.Scanner.nextInt(Scanner.java:2050) at sentinel.Ex7.main(Ex7.java:36) Java Result: 1

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  • How do I use multiple arguments from an array to construct an execl() call in C?

    - by chucknelson
    I have a string array in C named args[] - now how can I use this list of arguments to construct a proper call to execl()? So if the array contains: {"/bin/ls","ls","-a","-l"} ...how can I eventually construct an execl() call that is: execl("/bin/ls","ls","-a","-l",NULL); I must be thinking about this wrong, as I can't find anything online, just talk about defining functions that can take a variable number of arguments.

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  • Question about multiple 'catch'

    - by chun
    Can anyone tell me why the output of this class is 'xa'? why the other exception won't be caught? public class Tree { public static void main(String... args){ try { throw new NullPointerException(new Exception().toString()); } catch (NullPointerException e) { System.out.print("x"); } catch (RuntimeException e) { System.out.print("y"); } catch (Exception e) { System.out.print("z"); } finally{System.out.println("a");} } }

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  • A question taken from Java exam

    - by chun
    public static void main(String[] args) { int [][]shatner = new int[1][1]; int []rat = new int[4]; shatner[0] = rat; System.out.println(shatner[0][3]); } surprised, The answer is 0, Java doesn't check this kind of indexOutOfBound error?

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  • tcl_findLibrary doesn't work.

    - by user437815
    I'm trying to run freshly compiled program, written with Tcl&Tk. When running it I get an error: felix@Astroserver:~/?????????/Simon$ sudo ./simon1 invalid command name "tcl_findLibrary" I'm running Ubuntu 11.04, I have installed Tcl&Tk (cause I was able to succesfully build the program). If I'm running wish: *% tcl_findLibrary wrong # args: should be "tcl_findLibrary basename version patch initScript enVarName varName"* Could anyone help?

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  • jQuery attr command

    - by senzacionale
    I want to add a value to the onchange event, but the JS code has errors $(args).attr('onChange', 'setTimeout('__doPostBack(\'ctl00$cpBody$txtDate\',\'\')', 0)'); anyone see error?

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  • Why sockets does not die when server dies? Why socket dies when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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