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  • Unable to load detached NIB in View

    - by Sheehan Alam
    I have two NIB's ParentViewController.xib ChildViewController.xib ParentViewController.xib contains a UIView and a UIViewController. ChildViewController.xib contains a UIButton I want ChildViewController.xib to load in the ParentViewController.xib's UIView I have done the following: Created @property for UIView in ParentViewController Connected File's Owner to UIView in ParentViewController Set UIViewController in ParentViewController's NIB Name property to ChildViewController in Interface Builder Set ChildViewController view property to UIView in ParentViewController I was hoping this would load ChildViewController into my UIView in ParentViewController but no luck. I did get the following warning, which could be the culprit: 'View Controller (Child View)' has both its 'NIB Name' property set and its 'view' outlet connected. This configuration is not supported. I also have added additional code in ParentViewController's viewDidLoad(): - (void)viewDidLoad { [super viewDidLoad]; ChildViewController *childViewController = [[ChildViewController alloc]initWithNibName:@"ChildViewController" bundle:nil]; childViewController.view = self.myView; } Any thoughts on why ChildViewController does not load in the UIView of ParentViewController?

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  • Open working copy file from eclipse history view

    - by Wolfgang
    The history view of eclipse shows you a list of files changed in a certain revision. When you open the context menu on one of these you have the option 'Open' which opens a view of that file in that revision. How can I open the editor for the selected file, i.e. the file in the version of the working copy, right from the history view? Background is that I want to use the history view to find files that have been changed recently to do code reviewing. People commit via subversion and I use subclipse to connect eclipse to the subversion server. Today, I must use the 'Open resource'/'Open type' function and type the name of the file that I can read from the history view.

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  • Table View rotate, but not properly (shape change)

    - by Pencrace
    Hello everyone, Here is the thing. I have a ViewController which contain a view in full window. And the program run in landscape mode. I want to put an UITableView over the full screen view but only on right half part of the screen. So I add a UITableView in my view controller, I used the Interface Builder in order to set the Table View in the upper half of the screen so It will be on the right part in LandscapeLeft mode. I searched for on a lot of forum how to rotate my Table View. And so it does... except, It get stuck on the upper half of the landscape mode, it should stick on the right half. I'm not a iPhone coder since long, so I'm a bit confused on how to solve this problem. Do you have any idea on how to resize or make the TableView rotate properly. Thanks,

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  • UIViewController prevent view from unloading

    - by Ican Zilb
    When my iPhone app receives a Memory warning the views of UIViewControllers that are not currently visible get unloaded. In one particular controller unloading the view and the outlets is rather fatal. I'm looking for a way to prevent this view from being unloaded. I find this behavior rather stupid - I have a cache mechanism, so when a memory warning comes - I unload myself tons of data and I free enough memory, but I definitely need this view untouched. I see UIViewController has a method 'unloadViewIfReloadable', which gets called when the Memory Warning comes. Does anybody know how to tell Cocoa Touch that my view is not reloadable? Any other suggestions how to prevent my view from being unloaded on Memory Warning? Thanks in advance

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  • Iphone sdk - please help , 1 view takes me 45 minutes to do :(

    - by Dave
    Hey, I've been working on a Cook Book App but each view ( or recipie page) takes about 45 minutes to complete so as you can imagine its taking forever. The problem is that I have to manually: Set up a gradient image for the back ground (Somtimes I have to add a few image backgrounds to fit the view as I often use a scroll view, not sure how this could be automated?) Put an image behind the titles "Recipe name" , "Time needed" and an image to go behind the recipie instructions ( again I might need a few of these depending on how long the description is. Creating view controllers for main sections such as "Breakfast" and "Lunch" and then I need to manually create view controllers to go in these sections. Theres got to be a way to set up a template for this? Thanks for reading all of this.

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  • MVC: Upload image in partial view, routing problem

    - by D.J
    I am trying to upload images via a form which sits in partial view using MVC. View Code: <form action="/Item/ImageUpload" method="post" enctype="multipart/form-data"> <%= Html.TextBox("ItemId",Model.ItemId) %> <input type="file" name="file" id="file" /> <input type="submit" value="Add" /> </form> Action Code: public void ImageUpload(string ItemId, HttpPostedFileBase file) { // upload image // Add Image record to database // Associate Image record to Item record //Go back to existing view where the partial view sits RedirectToAction("Details/"+ItemId); } The Image is uploaded successful All the data manipulation are working as expected However instead of redirect to view "Item/Details/id", page went to "/Item/ImageUpload" I tried several different way of doing this including using jsonResultAction, but all failed in this same result. where did i do wrong, any ideas? thanks in advance

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  • Table View Page Control Code

    - by PerwyL
    Hi Everyone this is what i want to achieve 1) Have a page control that allows user to do a swipe to 6 different pages 2) each page is a table view controller 3) everything is done via code NOT IB The tutorials that are i find either use VIEW CONTROLLER or is done via IB. I am not very good with IB and prefer to have everything done via coding. I have a TableViewController.h and TableViewController.m When the user navigate to the TableViewController view, my application will display a table view (filled with some information), when the user swip to the next page, another page (table view) will appear with another set of information... I am very new to objective-c and iphone programing...can some one pls guide me on how to achieve the above or is there another way to doing things? oh yar....i have a tab bar controller as my root controller...and for one of the tab (tab A) i have a navigation controller and my TableViewControllers falls inside tab A. THANKS IN ADVANCE!!!

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  • View Window Not Opening in Interface Builder

    - by senfo
    When I double click the XIB file in Xcode, Interface Builder typically launches a few different windows, one of which is the View window. For some reason, however, the View window isn't opening for one of my XIB files. If I open any of the other XIB files, however, the View window does open. I'm not sure if there's a way to manually launch the View window (I looked through all of the menu items and couldn't find a way) or if I broke something in my XIB. Update: I created a connection from the app delegate to a navigation controller, which seemed to break something. When I cleared that connection, the View window came back.

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  • How to get url parameter value of current route in view in ASP .NET MVC

    - by Dima
    For example I am on page http://localhost:1338/category/category1?view=list&min-price=0&max-price=100 And in my view I want to render some form @using(Html.BeginForm("Action", "Controller", new RouteValueDictionary { { /*this is poblem place*/ } }, FormMethod.Get)) { <!--Render some controls--> <input type="submit" value="OK" /> } What I want is to get view parameter value from current page link to use it for constructing form get request. I tried @using(Html.BeginForm("Action", "Controller", new RouteValueDictionary { { "view", ViewContext.RouteData.Values["view"] } }, FormMethod.Get)) but it doesn't help.

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  • ASP.NET MVC: How to Display custom object properties in View page

    - by Shyju
    I am trying to add ASP.NET MVC features(Especially Routing) to my already existing ASP.NET Web application.I added a Controlled and View (an asp.net page) .Now i want to know how can i display the details of object of my custom class( Ex : User) in the view ? Can assign the object in ViewData collection and render it in the view ? Hows that ? I already have a Datalayer (in ADO.NET) which is running for the the current ASP.NET web app.So i want to use that. I tried this in my controller public ActionResult Index() { BusinessObject.User objUser = new BusinessObject.User(); objUser.EmailId = "[email protected]"; objUser.ProfileTitle = "Web developer with 6 yrs expereince"; ViewData["objUser"] = objUser; ViewData["Message"] = "This is ASP.NET MVC!"; return View(); } How can i use this in the view page to display the user details ? Thanks in advance

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  • Combine two views into one view

    - by Kevin
    I have two views that I would like to combine into one. The first view shows all items of X where company ID = Y. This is to give preferential sort to the client first, and then everyone else. So I created a second view, all items of X, where company ID != Y. I created it as an Attachment to attach to the first view, but I don't think I got the intended result. How can I combine these views so the first view results are listed first, and then the second view is too, using the same pager, filters, and arguments? Is there any way of achieving this without programming it?

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  • Exception if there is IBOutlet in view controller created by initWithNibName

    - by Kail
    When I create a Navigation-based application, the second view controller is created with initWithNibName, if I add a label onto the second view and connect it with IBOutlet in the second view controller. After I navigate to the second view by clicking table cell, and then back to the root view, the application aborts - send message retainCount to a freed object. I know this is caused by the IBOutlet label, which is retained, set nil in viewDidUnload and dealloc in dealloc. But I don't know why, and if I wanna still use IBOutlet, what can I do? Not dealloc it in viewcontroller's dealloc? Anybody could help? Thank you.

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  • pyramid view redirection

    - by ascobol
    This question title may be slightly incorrect but I could not find a better one (yet). I'm trying to integrate Mozilla Persona (browserid) into a Pyramid application. The login process is: user can login on any page by clicking on the login button a popup then shows a login form when the users enters correct login/password, an ajax call is made by the popup to a pyramid view that checks users credentials, and calls pyramid remember function if the check succeeded the browserid javascript code then reloads the current page Now I want to handle the case of a new user subscribing to the web app and present a new view asking for a few more details (desired username, etc) Since the "remember" function is called by an ajax call from the popup, I cannot redirect the user the the "/newuser" page. So every view needs to redirect new users to the "/newuser" url whenever the remembered browserid has no corresponding user in the database. Is there a way to intercept user requests before calling a view to call the "new_user" view instead ? Or maybe my authentication approach is fundamentally incorrect and I should rely on another approach ?

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  • Random access view in boost::multi_array

    - by linai
    Here is a boost example: typedef boost::multi_array<double, 1> array_type; typedef array_type::index index; array_type A(boost::extents[100]); for(index i = 0; i != A.size(); ++i) { A[i] = (double)i; } // creating view array_type::index_gen indices; typedef boost::multi_array_types::index_range range; array_type::array_view<1>::type myview = A[ indices[range(0,50)] ]; What this code does is creating a subarray or view mapping onto the original array. This view is continuous and covers from 0th to 50th elements of an original array. What if I need to explicitly define elements I'd like to see in the view? How can I create a view with indices like [1, 5, 35, 23] ? Any ideas?

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  • iPhone switching views without first view being reset

    - by user298261
    Heya! I'm making a role-playing game, and I want to have a Map View and a Battle Screen. With the possibility of other screens as well. I thought the best way to achieve this was to use multiple NIB files. When I prototyped this by have one view that creates content, switches to the next view, and then back, the content on the original view was reset. How do I make it so that the first view doesn't reset the data each time it's loaded? Thanks!

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  • Reload table view in real time

    - by Lucas Vallim da Costa
    The app receives a UILocalNotification, but if the user is at the UITableViewController at the fire time, the table view (containing the scheduled notifications) does not reload. The user has to get out of that view and load the view again so that the cells are loaded and, as the notification was already fired, it will not be displayed on any cell of that table view. Problem is: If the user touches the specific tableView cell that contained the notification that just fired, the app crashes, cause the notification is not there anymore. I've implemented the - (void)reloadData in every place possible, and it still doesn't load in real time. What would be a better solution for this? Other detail, how can I push a specific view after the notification is displayed (when the user slides the app icon when the phone is locked)? Any help will be truly appreciated, since theres are the last details remaining to publish my first App.

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  • Identifying the view selected in a ContextMenu (Android)

    - by Casebash
    In Android, onContextItemSelected has a single MenuItem argument and so it isn't clear how to identify the view selected. MenuItem.getMenuInfo provides access to Contextmenu.ContextMenuInfo, but while both known subclasses provide access to the target view, there does not appear to be an accessor on the interface. One alternative is to save the View provided in onCreateContextMenu in a private class variable which relies on onCreateContextMenu not being called again in the activity before onContextItemSelected. Another is to use the id of the View for the itemId argument of ContextMenu.add. If we do this, we would then need to identify the option selected from the context menu by using its (possibly internationalised) title. What is the best method for identifying the View selected in onContextSelected?

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  • Navigation problem with view controllers.

    - by abdulsamad
    Hi All I have some problem with the my view controllers. When i have about 50 or more records in one of my table view which is below in the stack of view controllers and if i tap the back button quickly the navigation bar on the tap changes but the view does't change. For example: if i have the search controller below in the stack and detail controller up in the stack in this case on tapping the back button quickly the navigation bar comes to the search but the view controller remains on detail page. can any one can give me cause or solution of this problem. your help will be highly appreciated.

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  • didSelectRowAtIndexPath being called after viewDidLoad of the called view

    - by Serguei Fedorov
    I am trying to pass variables over to the new view. I have the following code: appDelegate *dataCenter = (AppDelegate*)[[UIApplication sharedApplication] delegate]; dataCenter.myVariable = [array objectAtIndex:indexPath.row]; in the didSelectRowAtIndexPath of the calling view. However, the issue that I have is that this variable is empty in the vewDidLoad function of the next view, simply because it fired off BEFORE the didSelectRowAtIndexPath of the calling view. I am using storyboard to link the views together. Both are UITableView. If I hit back and then reselect the table element it is then set, granted that by the time I hit back and then selected again, the variable got set. Is there any way to for the order of execution? I really don't want to do UI view switching on the back end. Any help is greatly appreciated!

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  • updating the values in detail view from another view....

    - by praseed
    Hi friends, i am building one app almost similar to contact management system...in which i have a detail view .. on pressing one of the table cells, a new view will be shown were the user can enter the new values and on pressing the save button the values will be updated in the database. On going back to the detail view the user should be able to see the updated values in the table cells.. or how can i update the values in detail view from another view...? i came to know that this can be acheived through Appdelegate objects ... but i couldnt understand wat is it or how it is done.... may be bcuz i am new to iPhone apps development... Pls can anyone explain me the process..

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  • What is a good way for a custom accessory view in a UITableViewCell to message the table view contro

    - by Alex Gosselin
    Hi Everyone, I am working on adding a custom accessory view, (a button) to a UITableViewCell, and I need it to tell the table view when it is touched, but I can't figure out how to communicate to the table view what button was pressed. Ideally I'd like to somehow call a function like this: [controller tableView:view didSelectCustomButtonAtIndexPath:indexPath usingCell:self]; when my custom view button is pressed. Sorry if this is a bit vague, I'm not really sure how to explain this well. I am basically looking for how to mimic the implementation for tableView:didSelectRowAtIndexPath: without having to subclass UITableViewCell. Thanks for any help.

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  • ASP.NET MVC 3: Layouts and Sections with Razor

    - by ScottGu
    This is another in a series of posts I’m doing that cover some of the new ASP.NET MVC 3 features: Introducing Razor (July 2nd) New @model keyword in Razor (Oct 19th) Layouts with Razor (Oct 22nd) Server-Side Comments with Razor (Nov 12th) Razor’s @: and <text> syntax (Dec 15th) Implicit and Explicit code nuggets with Razor (Dec 16th) Layouts and Sections with Razor (Today) In today’s post I’m going to go into more details about how Layout pages work with Razor.  In particular, I’m going to cover how you can have multiple, non-contiguous, replaceable “sections” within a layout file – and enable views based on layouts to optionally “fill in” these different sections at runtime.  The Razor syntax for doing this is clean and concise. I’ll also show how you can dynamically check at runtime whether a particular layout section has been defined, and how you can provide alternate content (or even an alternate layout) in the event that a section isn’t specified within a view template.  This provides a powerful and easy way to customize the UI of your site and make it clean and DRY from an implementation perspective. What are Layouts? You typically want to maintain a consistent look and feel across all of the pages within your web-site/application.  ASP.NET 2.0 introduced the concept of “master pages” which helps enable this when using .aspx based pages or templates.  Razor also supports this concept with a feature called “layouts” – which allow you to define a common site template, and then inherit its look and feel across all the views/pages on your site. I previously discussed the basics of how layout files work with Razor in my ASP.NET MVC 3: Layouts with Razor blog post.  Today’s post will go deeper and discuss how you can define multiple, non-contiguous, replaceable regions within a layout file that you can then optionally “fill in” at runtime. Site Layout Scenario Let’s look at how we can implement a common site layout scenario with ASP.NET MVC 3 and Razor.  Specifically, we’ll implement some site UI where we have a common header and footer on all of our pages.  We’ll also add a “sidebar” section to the right of our common site layout.  On some pages we’ll customize the SideBar to contain content specific to the page it is included on: And on other pages (that do not have custom sidebar content) we will fall back and provide some “default content” to the sidebar: We’ll use ASP.NET MVC 3 and Razor to enable this customization in a nice, clean way.  Below are some step-by-step tutorial instructions on how to build the above site with ASP.NET MVC 3 and Razor. Part 1: Create a New Project with a Layout for the “Body” section We’ll begin by using the “File->New Project” menu command within Visual Studio to create a new ASP.NET MVC 3 Project.  We’ll create the new project using the “Empty” template option: This will create a new project that has no default controllers in it: Creating a HomeController We will then right-click on the “Controllers” folder of our newly created project and choose the “Add->Controller” context menu command.  This will bring up the “Add Controller” dialog: We’ll name the new controller we create “HomeController”.  When we click the “Add” button Visual Studio will add a HomeController class to our project with a default “Index” action method that returns a view: We won’t need to write any Controller logic to implement this sample – so we’ll leave the default code as-is.  Creating a View Template Our next step will be to implement the view template associated with the HomeController’s Index action method.  To implement the view template, we will right-click within the “HomeController.Index()” method and select the “Add View” command to create a view template for our home page: This will bring up the “Add View” dialog within Visual Studio.  We do not need to change any of the default settings within the above dialog (the name of the template was auto-populated to Index because we invoked the “Add View” context menu command within the Index method).  When we click the “Add” Button within the dialog, a Razor-based “Index.cshtml” view template will be added to the \Views\Home\ folder within our project.  Let’s add some simple default static content to it: Notice above how we don’t have an <html> or <body> section defined within our view template.  This is because we are going to rely on a layout template to supply these elements and use it to define the common site layout and structure for our site (ensuring that it is consistent across all pages and URLs within the site).  Customizing our Layout File Let’s open and customize the default “_Layout.cshtml” file that was automatically added to the \Views\Shared folder when we created our new project: The default layout file (shown above) is pretty basic and simply outputs a title (if specified in either the Controller or the View template) and adds links to a stylesheet and jQuery.  The call to “RenderBody()” indicates where the main body content of our Index.cshtml file will merged into the output sent back to the browser. Let’s modify the Layout template to add a common header, footer and sidebar to the site: We’ll then edit the “Site.css” file within the \Content folder of our project and add 4 CSS rules to it: And now when we run the project and browse to the home “/” URL of our project we’ll see a page like below: Notice how the content of the HomeController’s Index view template and the site’s Shared Layout template have been merged together into a single HTML response.  Below is what the HTML sent back from the server looks like: Part 2: Adding a “SideBar” Section Our site so far has a layout template that has only one “section” in it – what we call the main “body” section of the response.  Razor also supports the ability to add additional "named sections” to layout templates as well.  These sections can be defined anywhere in the layout file (including within the <head> section of the HTML), and allow you to output dynamic content to multiple, non-contiguous, regions of the final response. Defining the “SideBar” section in our Layout Let’s update our Layout template to define an additional “SideBar” section of content that will be rendered within the <div id=”sidebar”> region of our HTML.  We can do this by calling the RenderSection(string sectionName, bool required) helper method within our Layout.cshtml file like below:   The first parameter to the “RenderSection()” helper method specifies the name of the section we want to render at that location in the layout template.  The second parameter is optional, and allows us to define whether the section we are rendering is required or not.  If a section is “required”, then Razor will throw an error at runtime if that section is not implemented within a view template that is based on the layout file (which can make it easier to track down content errors).  If a section is not required, then its presence within a view template is optional, and the above RenderSection() code will render nothing at runtime if it isn’t defined. Now that we’ve made the above change to our layout file, let’s hit refresh in our browser and see what our Home page now looks like: Notice how we currently have no content within our SideBar <div> – that is because the Index.cshtml view template doesn’t implement our new “SideBar” section yet. Implementing the “SideBar” Section in our View Template Let’s change our home-page so that it has a SideBar section that outputs some custom content.  We can do that by opening up the Index.cshtml view template, and by adding a new “SiderBar” section to it.  We’ll do this using Razor’s @section SectionName { } syntax: We could have put our SideBar @section declaration anywhere within the view template.  I think it looks cleaner when defined at the top or bottom of the file – but that is simply personal preference.  You can include any content or code you want within @section declarations.  Notice above how I have a C# code nugget that outputs the current time at the bottom of the SideBar section.  I could have also written code that used ASP.NET MVC’s HTML/AJAX helper methods and/or accessed any strongly-typed model objects passed to the Index.cshtml view template. Now that we’ve made the above template changes, when we hit refresh in our browser again we’ll see that our SideBar content – that is specific to the Home Page of our site – is now included in the page response sent back from the server: The SideBar section content has been merged into the proper location of the HTML response : Part 3: Conditionally Detecting if a Layout Section Has Been Implemented Razor provides the ability for you to conditionally check (from within a layout file) whether a section has been defined within a view template, and enables you to output an alternative response in the event that the section has not been defined.  This provides a convenient way to specify default UI for optional layout sections.  Let’s modify our Layout file to take advantage of this capability.  Below we are conditionally checking whether the “SideBar” section has been defined without the view template being rendered (using the IsSectionDefined() method), and if so we render the section.  If the section has not been defined, then we now instead render some default content for the SideBar:  Note: You want to make sure you prefix calls to the RenderSection() helper method with a @ character – which will tell Razor to execute the HelperResult it returns and merge in the section content in the appropriate place of the output.  Notice how we wrote @RenderSection(“SideBar”) above instead of just RenderSection(“SideBar”).  Otherwise you’ll get an error. Above we are simply rendering an inline static string (<p>Default SideBar Content</p>) if the section is not defined.  A real-world site would more likely refactor this default content to be stored within a separate partial template (which we’d render using the Html.RenderPartial() helper method within the else block) or alternatively use the Html.Action() helper method within the else block to encapsulate both the logic and rendering of the default sidebar. When we hit refresh on our home-page, we will still see the same custom SideBar content we had before.  This is because we implemented the SideBar section within our Index.cshtml view template (and so our Layout rendered it): Let’s now implement a “/Home/About” URL for our site by adding a new “About” action method to our HomeController: The About() action method above simply renders a view back to the client when invoked.  We can implement the corresponding view template for this action by right-clicking within the “About()” method and using the “Add View” menu command (like before) to create a new About.cshtml view template.  We’ll implement the About.cshtml view template like below. Notice that we are not defining a “SideBar” section within it: When we browse the /Home/About URL we’ll see the content we supplied above in the main body section of our response, and the default SideBar content will rendered: The layout file determined at runtime that a custom SideBar section wasn’t present in the About.cshtml view template, and instead rendered the default sidebar content. One Last Tweak… Let’s suppose that at a later point we decide that instead of rendering default side-bar content, we just want to hide the side-bar entirely from pages that don’t have any custom sidebar content defined.  We could implement this change simply by making a small modification to our layout so that the sidebar content (and its surrounding HTML chrome) is only rendered if the SideBar section is defined.  The code to do this is below: Razor is flexible enough so that we can make changes like this and not have to modify any of our view templates (nor make change any Controller logic changes) to accommodate this.  We can instead make just this one modification to our Layout file and the rest happens cleanly.  This type of flexibility makes Razor incredibly powerful and productive. Summary Razor’s layout capability enables you to define a common site template, and then inherit its look and feel across all the views/pages on your site. Razor enables you to define multiple, non-contiguous, “sections” within layout templates that can be “filled-in” by view templates.  The @section {} syntax for doing this is clean and concise.  Razor also supports the ability to dynamically check at runtime whether a particular section has been defined, and to provide alternate content (or even an alternate layout) in the event that it isn’t specified.  This provides a powerful and easy way to customize the UI of your site - and make it clean and DRY from an implementation perspective. Hope this helps, Scott P.S. In addition to blogging, I am also now using Twitter for quick updates and to share links. Follow me at: twitter.com/scottgu

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  • Single Table Per Class Hierarchy with an abstract superclass using Hibernate Annotations

    - by Andy Hull
    I have a simple class hierarchy, similar to the following: @Entity @Table(name="animal") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="animal_type", discriminatorType=DiscriminatorType.STRING) public abstract class Animal { } @Entity @DiscriminatorValue("cat") public class Cat extends Animal { } @Entity @DiscriminatorValue("dog") public class Dog extends Animal { } When I query "from Animal" I get this exception: "org.hibernate.InstantiationException: Cannot instantiate abstract class or interface: Animal" If I make Animal concrete, and add a dummy discriminator... such as @DiscriminatorValue("animal")... my query returns my cats and dogs as instances of Animals. I remember this being trivial with HBM based mappings but I think I'm missing something when using annotations. Can anyone help? Thanks!

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  • NHibernate HiLo - new column per entity and HiLo catches

    - by Gareth
    Im currently using the hilo id generator for my classes but have just been using the minimal of settings eg <class name="ClassA" <id name="Id" column="id" unsaved-value="0" <generator class="hilo" / </id ... But should I really be specifying a new column for NHibernate to use foreach entity and providing it with a max lo? <class name="ClassA" <id name="Id" column="id" unsaved-value="0" <generator class="hilo" <param name="table"hibernate_unique_key</param <param name="column"classA_nexthi</param <param name="max_lo"20</param </generator </id ... <class name="ClassB" <id name="Id" column="id" unsaved-value="0" <generator class="hilo" <param name="table"hibernate_unique_key</param <param name="column"classB_nexthi</param <param name="max_lo"20</param </generator </id ... Also I've noticed that when I do the above the SchemaExport will not create all the columns - only classB_nexthi, is there something else im doing wrong. Thanks

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  • Combobox with collection view itemssource does not update selection box item on changes to the Model

    - by Vinit Sankhe
    Hello, Sorry for the earlier lengthy post. Here is my concise (!) description. I bind a collection view to a combobox as a itemsSource and also bind its selectedvalue with a property from my view model. I must keep IsSynchronizedWithCurrentItem="False". I change the source list ofr the view and then refresh the view. The changed (added, removed, edited) items appear correctly in the item list of the combo. But problem is with the selected item. When I change its property which is also the displaymember path of the combo, the changed property value does not reflect back on the selecton box of the combo. If you open the combo dropdown it appears correctly on the item list but not on the selection box. Now if I change the combobox tag to Listbox in my XAML (keeping all attributes as it is) then when selected item's displaymember property value is updated, the changes reflect back on the selected item of the list box . Why this issue? Just FYI: My View Model has properties EmployeeCollectionView and SelectedEmployeeId which are bound to combo as ItemsSource and SelectedValue resp. This VM implements the INotifyPropertyChanged interface. My core employee class (list of which is the source for the EmployeeCollectionView) is simply a Model class without INotifyPropertyChanged. DisplayMemberPath is "Name" property of employee Model class. I change this by some means and expect the combo selection box to update the value. I tried refreshing ther SelectedEmployeeId by setting it 0 (where it correctly selects the dummy "-- Select All --" employee entry from itemsSource) and old selected value back. But no use. The old value takes me back to the old label. Items collection has latest entry though. When I make combobox's IsEditable=True before the view's refresh and after refresh I make IsEditable=False then the things work out correctly! But this is a patch and is unnecessary. Thx Vinit Sankhe

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