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  • Why do my raytraced spheres have dark lines when lit with multiple light sources?

    - by Curyous
    I have a simple raytracer that only works back up to the first intersection. The scene looks OK with two different light sources, but when both lights are in the scene, there are dark shadows where the lit area from one ends, even if in the middle of a lit area from the other light source (particularly noticeable on the green ball). The transition from the 'area lit by both light sources' to the 'area lit by just one light source' seems to be slightly darker than the 'area lit by just one light source'. The code where I'm adding the lighting effects is: // trace lights for ( int l=0; l<primitives.count; l++) { Primitive* p = [primitives objectAtIndex:l]; if (p.light) { Sphere * lightSource = (Sphere *)p; // calculate diffuse shading Vector3 *light = [[Vector3 alloc] init]; light.x = lightSource.centre.x - intersectionPoint.x; light.y = lightSource.centre.y - intersectionPoint.y; light.z = lightSource.centre.z - intersectionPoint.z; [light normalize]; Vector3 * normal = [[primitiveThatWasHit getNormalAt:intersectionPoint] retain]; if (primitiveThatWasHit.material.diffuse > 0) { float illumination = DOT(normal, light); if (illumination > 0) { float diff = illumination * primitiveThatWasHit.material.diffuse; // add diffuse component to ray color colour.red += diff * primitiveThatWasHit.material.colour.red * lightSource.material.colour.red; colour.blue += diff * primitiveThatWasHit.material.colour.blue * lightSource.material.colour.blue; colour.green += diff * primitiveThatWasHit.material.colour.green * lightSource.material.colour.green; } } [normal release]; [light release]; } } How can I make it look right?

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  • Explain this C# code: byte* p = (byte*) (void*) Scan0;

    - by qulzam
    I found the code from the net in which i cant understand this line:- byte* p = (byte*)(void*)Scan0; There Scan0 is System.IntPtr. It is code of C#.Net. Plz Explain the above line. The complete code is given below. this is code to convert a image in grayscale. public static Image GrayScale(Bitmap b) { BitmapData bmData = b.LockBits(new Rectangle(0, 0, b.Width, b.Height), ImageLockMode.ReadWrite, PixelFormat.Format24bppRgb); int stride = bmData.Stride; System.IntPtr Scan0 = bmData.Scan0; unsafe { byte* p = (byte*)(void*)Scan0; int nOffset = stride - b.Width * 3; byte red, green, blue; for (int y = 0; y < b.Height; ++y) { for (int x = 0; x < b.Width; ++x) { blue = p[0]; green = p[1]; red = p[2]; p[0] = p[1] = p[2] = (byte)(.299 * red + .587 * green + .114 * blue); p += 3; } p += nOffset; } } b.UnlockBits(bmData); return (Image)b; } I understand all the code but only have the problem on this line. byte* p = (byte*)(void*)Scan0;

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  • Computing "average" of two colors

    - by Francisco P.
    This is only marginally programming related - has much more to do w/ colors and their representation. I am working on a very low level app. I have an array of bytes in memory. Those are characters. They were rendered with anti-aliasing: they have values from 0 to 255, 0 being fully transparent and 255 totally opaque (alpha, if you wish). I am having trouble conceiving an algorithm for the rendering of this font. I'm doing the following for each pixel: // intensity is the weight I talked about: 0 to 255 intensity = glyphs[text[i]][x + GLYPH_WIDTH*y]; if (intensity == 255) continue; // Don't draw it, fully transparent else if (intensity == 0) setPixel(x + xi, y + yi, color, base); // Fully opaque, can draw original color else { // Here's the tricky part // Get the pixel in the destination for averaging purposes pixel = getPixel(x + xi, y + yi, base); // transfer is an int for calculations transfer = (int) ((float)((float) (255.0 - (float) intensity/255.0) * (float) color.red + (float) pixel.red)/2); // This is my attempt at averaging newPixel.red = (Byte) transfer; transfer = (int) ((float)((float) (255.0 - (float) intensity/255.0) * (float) color.green + (float) pixel.green)/2); newPixel.green = (Byte) transfer; // transfer = (int) ((float) ((float) 255.0 - (float) intensity)/255.0 * (((float) color.blue) + (float) pixel.blue)/2); transfer = (int) ((float)((float) (255.0 - (float) intensity/255.0) * (float) color.blue + (float) pixel.blue)/2); newPixel.blue = (Byte) transfer; // Set the newpixel in the desired mem. position setPixel(x+xi, y+yi, newPixel, base); } The results, as you can see, are less than desirable. That is a very zoomed in image, at 1:1 scale it looks like the text has a green "aura". Any idea for how to properly compute this would be greatly appreciated. Thanks for your time!

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  • Fluently setting C# properties and chaining methods

    - by John Feminella
    I'm using .NET 3.5. We have some complex third-party classes which are automatically generated and out of my control, but which we must work with for testing purposes. I see my team doing a lot of deeply-nested property getting/setting in our test code, and it's getting pretty cumbersome. To remedy the problem, I'd like to make a fluent interface for setting properties on the various objects in the hierarchical tree. There are a large number of properties and classes in this third-party library, and it would be too tedious to map everything manually. My initial thought was to just use object initializers. Red, Blue, and Green are properties, and Mix() is a method that sets a fourth property Color to the closest RGB-safe color with that mixed color. Paints must be homogenized with Stir() before they can be used. Bucket b = new Bucket() { Paint = new Paint() { Red = 0.4; Blue = 0.2; Green = 0.1; } }; That works to initialize the Paint, but I need to chain Mix() and other methods to it. Next attempt: Create<Bucket>(Create<Paint>() .SetRed(0.4) .SetBlue(0.2) .SetGreen(0.1) .Mix().Stir() ) But that doesn't scale well, because I'd have to define a method for each property I want to set, and there are hundreds of different properties in all the classes. Also, C# doesn't have a way to dynamically define methods prior to C# 4, so I don't think I can hook into things to do this automatically in some way. Third attempt: Create<Bucket>(Create<Paint>().Set(p => { p.Red = 0.4; p.Blue = 0.2; p.Green = 0.1; }).Mix().Stir() ) That doesn't look too bad, and seems like it'd be feasible. Is this an advisable approach? Is it possible to write a Set method that works this way? Or should I be pursuing an alternate strategy?

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  • Parse string to create a list of element

    - by Nick
    I have a string like this: "\r color=\"red\" name=\"Jon\" \t\n depth=\"8.26\" " And I want to parse this string and create a std::list of this object: class data { std::string name; std::string value; }; Where for example: name = color value = red What is the fastest way? I can use boost. EDIT: This is what i've tried: vector<string> tokens; split(tokens, str, is_any_of(" \t\f\v\n\r")); if(tokens.size() > 1) { list<data> attr; for_each(tokens.begin(), tokens.end(), [&attr](const string& token) { if(token.empty() || !contains(token, "=")) return; vector<string> tokens; split(tokens, token, is_any_of("=")); erase_all(tokens[1], "\""); attr.push_back(data(tokens[0], tokens[1])); } ); } But it does not work if there are spaces inside " ": like color="red 1".

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  • jquery selecting all elements except the last per group

    - by Anthony
    I have a table that looks like: <table> <tr> <td>one</td><td>two</td><td>three</td><td>last</td> </tr> <tr> <td>blue</td><td>red</td><td>green</td><td>last</td> </tr> <tr> <td>Monday</td><td>Tuesday</td><td>Wednesday</td><td>last</td> </tr> </table> What I want is a jquery selector that will choose all but the last td of each table row. I tried: $("tr td:not(:last)").css("background-color","red"); //changing color just as a test... But instead of all cells but the last on each row being changed, all cells but the very last one in the table are selected. Similarly, if I change it to: $("tr td:last").css("background-color","red"); the only one that changes is the very last cell. How do I choose the last (or not last) of each row?

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  • BeautifulSoup: just get inside of a tag, no matter how many enclosing tags there are

    - by AP257
    I'm trying to scrape all the inner html from the <p> elements in a web page using BeautifulSoup. There are internal tags, but I don't care, I just want to get the internal text. For example, for: <p>Red</p> <p><i>Blue</i></p> <p>Yellow</p> <p>Light <b>green</b></p> How can I extract: Red Blue Yellow Light green Neither .string nor .contents[0] does what I need. Nor does .extract(), because I don't want to have to specify the internal tags in advance - I want to deal with any that may occur. Is there a 'just get the visible HTML' type of method in BeautifulSoup? ----UPDATE------ On advice, trying: p_tags = page.findAll('p',text=True) for i, p_tag in enumerate(p_tags): print str(p_tag) But that doesn't help - it just prints out: Red <i>Blue</i> Yellow Light <b>green</b>

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  • Why aren't these Canvases rendering?

    - by bpapa
    I'm creating a web app that allows users to enter a number of colors, by specifying RGB values. Upon submission, the user will see a canvas with a solid rectangle drawn in the color chosen. On this page, I have 7 canvases. The first one draws just fine, but none of the rest show up. The browser is Safari. Here's the relevant code: First, the script element in the header, which defines the function I use to draw to the canvas. <script language="JavaScript" TYPE="text/javascript"><!-- function drawCanvas(canvasId, red, green, blue) { var theCanvas = document.getElementById("canvas" + canvasId); var context = theCanvas.getContext("2d"); context.clearRect(0,0,100,100); context.setFillColor(red,green,blue,1.0); context.fillRect(0,0,100,100); } // --> </script> Next, the HTML source, where I have my canvas tags and some embedded Javascript to call my drawCanvas function <canvas id="canvas0" width="100" height="100"> </canvas> <script language="JavaScript" TYPE="text/javascript"><!-- drawCanvas(0,250,0,0); // --> </script> . . //more source . <canvas id="canvas1" width="100" height="100"> </canvas> <script language="JavaScript" TYPE="text/javascript"><!-- drawCanvas(1,4,250,6); // --> </script> Also provided is a screenshot. As you can see, the "red" canvas comes up just fine, but the second one, which should be green, doesn't show up at all. Any ideas?

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  • text-transform cannot change/be overwritten? (css)

    - by Radek
    I am studying css and I do not understand why some OTHER text and line 2 has red underline effect on them. I thought I either changed it for class others or reset it to none for class line2 I tried `text-decoration:none' for both .line2 and .others and the text was still red underlined. <html> <head> <style type="text/css"> .line {color:red; text-transform:uppercase; text-decoration:underline;} .line2 {color:blue; text-transform:none;} .others {color:black; text-transform:lowercase; text-decoration:blink; font-weight:bold;} </style> </head> <body> <div class='line'> line 1 <div class='others'><BR>some OTHER text<BR></DIV> <div class='line2'> <BR>line 2 </div> </div> </body> </html>

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  • d3: Coloring Multiple Lines from Nested Data

    - by diet_coke
    I'm currently assembling some line graphs with circles at the datapoints from arrays of JSON objects formatted like so: var data = [{ "name": "metric1", "datapoints": [ [10.0, 1333519140], [48.0, 1333519200] ] }, { "name": "metric2", "datapoints": [ [48.0, 1333519200], [12.0, 1333519260] ] }] I want to have a color for each metric, so I'm trying to color them based on the index of the object within the array data. The code I have currently for just placing the circles looks like: // We bind an svg group to each metric. var metric_groups = this.vis.selectAll("g.metric_group") .data(data).enter() .append("g") .attr("class", "metric_group"); // Then bind a circle for each datapoint. var circles = metric_groups.selectAll("circle") .data(function(d) { return d.datapoints; }); circles.enter().append("circle") .attr("r", 3.5); Now if I change that last bit to something like: circles.enter().append("circle") .attr("r", 3.5); .style("fill", function(d,i) { return i%2 ? "red" : "blue"; } I get alternating red and blue circles, as could be expected. Taking some advice from Nested Selections : 'Nesting and Index', I tried: circles.enter().append("circle") .attr("r", 3.5); .style("fill", function(d,i,j) { return j%2 ? "red" : "blue"; } Which doesn't work (j is undefined), presumably because we are in the named property datapoints, rather than an array element. How might I go about doing the coloring that I want without changing my data structure? Thanks!

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  • Create a multicolor selectbox on Symfony2

    - by Ninsuo
    I try to create the following field : <select name="test"> <option value="1">a</option> <option value="2">b</option> <option value="3" style="font-weight: bold; color: red;">c</option> <option value="4">d</option> <option value="5">e</option> </select> This creates a 2-color selectbox : But in Symfony2, I do not know how to apply a class to a single option. If in my view I do : {{ form_widget(myForm.test, { 'attr': { 'class': 'red', } }) }} Or if in my form I do : $builder->add('test', 'choice', array( 'required' => true, 'choices' => array('a', 'b', 'c', 'd', 'e'), 'attr' => array('class' => 'red'), )); The attribute is stored into the <select> tag and apply to the whole selectable values. How do I apply a class to an <option> in Symfony2 ?

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  • opengl shader make color "disappear"

    - by JFoulkes
    hi, I'm new to opengl and shaders. I'm trying to do some augmented reality on the iphone and messing about with shaders to alter a feed from the camera. What I'm trying to achieve is the appearance that an object in a picture has disappeared by setting the color to match the surrounding colour. I have a yellow rectangle and in it is a small red circle. I want to give the impressed the red circle has disappeared by setting the colour to be yellow. It won't always be solid colours but I'm just trying to get the basics down first. Currently I have a simple shader which will make a red colour lighter but this isn't ideal because it doesn't get close to the surrounding colour and I want this to work for different coloured objects and different coloured surrounding. I'm not even 100% shaders are what I need to be looking at or even opengl. I'm using it because of the performance it gives on the iPhone. I'm basically asking if: Anyone has done or seen anything similar Am I barking up the wrong tree using opengl es and opengl sl? Is this even possible? Cheers.

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  • C# image drawing colours are incorrect

    - by Jon Tackabury
    I have a source bitmap that is 1x1 and I am trying to take that image and draw it to a new bitmap. The source bitmap is all red, but for some reason the new bitmap ends up with a gradient (see image). Using the code below, shouldn't the new bitmap be completely red? Where is it getting the white/alpha from? private void DrawImage() { Bitmap bmpSOURCE = new Bitmap(1, 1, PixelFormat.Format32bppArgb); using (Graphics g = Graphics.FromImage(bmpSOURCE)) { g.Clear(Color.Red); } Bitmap bmpTest = new Bitmap(300, 100, PixelFormat.Format32bppArgb); using (Graphics g = Graphics.FromImage(bmpTest)) { g.CompositingMode = CompositingMode.SourceCopy; g.CompositingQuality = CompositingQuality.AssumeLinear; g.InterpolationMode = InterpolationMode.HighQualityBicubic; g.PageUnit = GraphicsUnit.Pixel; g.PixelOffsetMode = PixelOffsetMode.None; g.SmoothingMode = SmoothingMode.None; Rectangle rectDest = new Rectangle(0, 0, bmpTest.Width, bmpTest.Height); Rectangle rectSource = new Rectangle(0, 0, 1, 1); g.DrawImage(bmpSOURCE, rectDest, rectSource, GraphicsUnit.Pixel); } pictureBox1.Image = bmpTest; }

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  • How to start animation when I'm pressing on item of ListView?

    - by Ares
    I want to implement next functional: When I'm tapping on ListView's item, it's turning into red color. If I release it has to reverse color back. I made transition drawable and set it as item's background. I tried to implement SimpleGestureListener and started animation on onDown and reversed it on onSingleTapUp events, but it doesn't give me any results (works fine, but items don't turn into red). If I return super.onDown (not true), the onLongPress raise every time(even I manage to release it). @Override public boolean onDown(MotionEvent e) { if(_currentRow.getTag()!=null) if(_currentRow.getTag().toString().equals("anim")) _currentRow.setBackgroundDrawable(context.getResources() .getDrawable(R.xml.listviewitem_yellow_red)); _drawable = (TransitionDrawable) _currentRow.getBackground(); _drawable.startTransition(500); return true; //super.onDown(e); // IF I UNCOMMENT IT TURNS INTO RED, BUT TRIGGERED onLongClick event!!! } @Override public boolean onSingleTapUp(MotionEvent e) { if(_drawable!=null){ _drawable.reverseTransition(500); } return super.onSingleTapUp(e); } @Override public void onLongPress(MotionEvent e) { if(getLongClickListener()!=null) getLongClickListener().onLongClick(_currentRow, _object); super.onLongPress(e); } If someone knows how to solve this problem, please help me.

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  • Create Clone Without Effecting Results of Original Object

    - by user1655096
    I have a function that when selecting an option, returns results. I want to be able to clone that function and have the ability to return another set of results, without adding the new results to the original object. // shows / hides results based on selection $(".categories-select").live("change" ,function(){ if($(this).val() == 'red'){ $('.red').removeClass('hide'); // toggles red results, sub menus $(this).parent('.controls').find('.sub').removeClass('hide'); } if($(this).val() == 'blue'){ $('.blue').removeClass('hide'); $(this).parent('.controls').find('.sub').addClass('hide'); } if($(this).val() == 'purple'){ $('.purple').removeClass('hide'); $(this).parent('.controls').find('.sub').addClass('hide'); } if($(this).val() == 'orange'){ $('.orange').removeClass('hide'); $(this).parent('.controls').find('.sub').addClass('hide'); } }); // Duplicates category select menu $(".add-color").find(function(){ $(".color-category").clone().removeClass('color-category').appendTo("#we-want-to").find('.sub,').addClass('hide') ; }); $(".add-color-alternate").click(function(){ $(".color-category-alternate").clone().removeClass('color-category-alternate').appendTo("#we-want-to").find('.sub, .results-table').addClass('hide'); });

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  • Windows 7 Mobile ListBox uncustomizable?

    - by Roy
    I've just recently started development using Visual Studio 2010 Express for Windows Phone and I put in a ListBox. I can't seem to manipulate the formatting. No matter what I do, the background is black/gray, the selected items have a blue border, and there is padding between the items in the listbox (i'm using images). Here is my code: Xaml: <Grid x:Name="ContentGrid" Grid.Row="1"> <Grid Name="gallery"> <Grid.RowDefinitions> <RowDefinition Height="370" /> <RowDefinition Height="150" /> </Grid.RowDefinitions> <Border BorderBrush="Red" Width="450" CornerRadius="4" BorderThickness="2" Background="Red" Margin="10,30,20,10" Padding="6,6,6,6"> <Image Grid.Row="0" Grid.Column="0" Height="360" x:Name="imgPreview"/> </Border> <ListBox x:Name="lbScrollGallery" Grid.Row="1" Grid.Column="0" Padding="0" VerticalAlignment="Top" Width="450" SelectionChanged="ScrollerSelectionChanged" d:LayoutOverrides="HorizontalAlignment" ScrollViewer.HorizontalScrollBarVisibility="Hidden"> <ListBox.ItemsPanel> <ItemsPanelTemplate> <StackPanel Orientation="Horizontal"/> </ItemsPanelTemplate> </ListBox.ItemsPanel> <ListBox.ItemTemplate> <DataTemplate> <Image Width="100" Height="100" Stretch="Fill" Name="imgSource" VerticalAlignment="Center" Source="{Binding Path=Url}" /> </DataTemplate> </ListBox.ItemTemplate> </ListBox> </Grid> </Grid> Is there some way I can customize the listbox? Like change the background to red or make the padding between different items 0?

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  • finding links that are hyper-links in jQuery

    - by Jacob Lowe
    Im trying to take a link either when clicked or hover over be able to grab the attribute href and tell if its a hyper-link or not. Also i want it to be able to tell me if its a hyper-link to my own site. Plus various other filters. The main purpose for this is so that when a internal link is clicked it will tell ajax to grab the content, alot of my links are generated (via wordpress)so I can't modify them too much. Another purpose for this is so i can also make all external links open on a new window. I have a solution that works on a simple test page but when i put into a working page it breaks. I know i am probably making this harder then it should be. Here is my code $(function(){ $('a').live('click', function(){ var x = $(this).attr('href'); $(this).parent('div').append('<div id="test">' + x +'</div>'); $('#test:contains("http")').css('color', 'red'); $('#test:contains("sitename")').css('color', 'black'); $('#test:contains("admin")').css('color', 'red'); if($('#test').css('color') == 'red'){ alert('external link'); $('#test').remove(); return true; }else{ alert('external link'); $('#test').remove(); return false; } }); }); thanks for you help

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  • Detect mouseover and show tooltip text for dots on an HTML Canvas

    - by carl asquith
    Ive recently created a "map" although not very sophisticated (im working on it) it has the basic function and is generally heading in the right direction. If you look at it you can see a tiny red dots and on those tiny red dots i want to mouseover it and see text basically but ive had a bit of trouble getting the code right. http://hummingbird2.x10.mx/website%20creation/mainpage.htm This is all the code so far. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN""http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Oynx Warrior</title> <link rel="stylesheet" type="text/css" href="mystyle.css" /> </head> <body> <h1>Oynx Warrior</h1> <canvas id="myCanvas" width="500" height="500" style="border:1px solid #c3c3c3;"> Your browser does not support the canvas element. </canvas> <script type="text/javascript"> var c=document.getElementById("myCanvas"); var cxt=c.getContext("2d"); cxt.fillStyle="#red"; cxt.beginPath(); cxt.arc(50,50,1,0,Math.PI*2,true); cxt.closePath(); cxt.fill(); </script> </body> </html>

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  • TextColor not showing when row backgroundcolor set

    - by RuAware
    if my row is colored red the text wont set to green and bold italic. When debugging I can see it telling the TextView to set each textViews setting. Thanks TableRow row = new TableRow(getContext()); row.setLayoutParams(new TableRow.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT)); String[] items = list.get(l).split(":"); for(int i=0; i < items.length; i++){ //see if i need to colour row if(items[i].startsWith("colorme_") == true) { if (items[i].substring(8).equals("red") == true) { row.setBackgroundColor(Color.RED); } } else { //create a temp textview then add to row TextView tempTV = new TextView(getContext()); tempTV.setText(items[i].toString()); //test against correct answers and colour text view green if correct if (correctAnswers != null && correctAnswers.size() > i) { if (correctAnswers.get(i).equals(items[i].toString()) == true) { tempTV.setTextColor(Color.GREEN); tempTV.setTypeface(null, Typeface.BOLD_ITALIC); } } row.addView(tempTV,lpTextView); } } //add the row tempTable.addView(row);

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  • Alternate colors on click with jQuery

    - by Jace Cotton
    I'm sure there is a simple solution to this, and I'm sure this is a duplicate question, though I have been unable to solve my solution particularly because I don't really know how to phrase it in order to search for other questions/solutions, so I'm coming here hoping for some help. Basically, I have spans with classes that assigns a background-color property, and inside those spans are words. I have three of these spans, and each time a user clicks on a span I want the class to change (thus changing the background color and inner text). HTML: <span class="alternate"> <span class="blue showing">Lorem</span> <span class="green">Ipsum</span> <span class="red">Dolor</span> </span> CSS: .alternate span { display : none } .alternate .showing { display : inline } .blue { background : blue } .green { background : green } .red { background : red } jQuery: $(".alternate span").each(function() { $(this).on("click", function() { $(this).removeClass("showing"); $(this).next().addClass("showing"); }); }); This solution works great using $.next until I get to the third click, whereafter .showing is removed, and is not added since there are no more $.next options. How do I, after getting to the last-child, add .showing to the first-child and then start over? I have tried various options including if($(".alternate span:last-child").hasClass("showing")) { etc. etc. }, and I attempted to use an array and for loop though I failed to make it work. Newb question, I know, but I can't seem to solve this so as a last resort I'm coming here.

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  • Is there a concise way to map a string to an enum in Objective-C?

    - by zekel
    I have a string I want to parse and return an equivalent enum. I need to use the enum type elsewhere, and I think I like how I'm defining the class. The problem is that I don't know a good way to check the string against the enum values without being redundant about the order of the enums. typedef enum { ZZColorRed, ZZColorGreen, ZZColorBlue, } ZZColorType; - (ZZColorType)parseColor:(NSString *)inputString { // inputString will be @"red", @"green", or @"blue" (trust me) // how can I turn that into ZZColorRed, etc. without // redefining their order like this? NSArray *colors = [NSArray arrayWithObjects:@"red", @"green", @"blue", nil]; return [colors indexOfObject:inputString]; } In Python, I'd probably do something like the following, although to be honest I'm not in love with that either. ## maps url text -> constant string RED_CONSTANT = 1 BLUE_CONSTANT = 2 GREEN_CONSTANT = 3 TYPES = { 'red': RED_CONSTANT, 'green': GREEN_CONSTANT, 'blue': BLUE_CONSTANT, } def parseColor(inputString): return TYPES.get(inputString) ps. I know there are color constants in Cocoa, this is just an example.

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  • Why is this ajax call being made even though it shouldn't be

    - by user2921557
    i have this validation script im working on but cant see why im having an issue. You can see that i have a check = false / true, check before it runs the ajax call. However, even if a field is empty and check is set to false, it is still running the call. so: // JavaScript - Update Password AJAX $(document).ready(function () { // When the form is submitted $('.updatepasswordform').submit(function () { var check = true; // Get the values var password1 = $("input[name=password1]").val(); var password2 = $("input[name=password2]").val(); var newpassword = $("input[name=newpassword]").val(); /* Password Validation */ // If fields are empty if (password1 === '') { check = false; $("input[name=password1]").css('border', 'solid 2px red'); } // If fields are empty if (password2 === '') { check = false; $("input[name=password2]").css('border', 'solid 2px red'); } // If fields are empty if (newpassword === '') { check = false; $("input[name=newpassword]").css('border', 'solid 2px red'); } if (check = true) { $.ajax({ type: "POST", url: "process/updatepassword.php", data: $(".updatepasswordform").serialize(), dataType: "json", success: function (response) { /* Checks for database validation, removed for space saving */ } }); } return false; }); });

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  • How Expedia Made My New Bride Cry

    - by Lance Robinson
    Tweet this? Email Expedia and ask them to give me and my new wife our honeymoon? When Expedia followed up their failure with our honeymoon trip with a complete and total lack of acknowledgement of any responsibility for the problem and endless loops of explaining the issue over and over again - I swore that they would make it right. When they brought my new bride to tears, I got an immediate and endless supply of motivation. I hope you will help me make them make it right by posting our story on Twitter, Facebook, your blog, on Expedia itself, and when talking to your friends in person about their own travel plans.   If you are considering using them now for an important trip - reconsider. Short summary: We arrived early for a flight - but Expedia had made a mistake with the data they supplied to JetBlue and Emirates, which resulted in us not being able to check in (one leg of our trip was missing)!  At the time of this post, three people (myself, my wife, and an exceptionally patient JetBlue employee named Mary) each spent hours on the phone with Expedia.  I myself spent right at 3 hours (according to iPhone records), Lauren spent an hour and a half or so, and poor Mary was probably on the phone for a good 3.5 hours.  This is after 5 hours total at the airport.  If you add up our phone time, that is nearly 8 hours of phone time over a 5 hour period with little or no help, stall tactics (?), run-around, denial, shifting of blame, and holding. Details below (times are approximate): First, my wife and I were married yesterday - June 18th, the 3 year anniversary of our first date. She is awesome. She is the nicest person I have ever known, a ton of fun, absolutely beautiful in every way. Ok enough mushy - here are the dirty details. 2:30 AM - Early Check-in Attempt - we attempted to check-in for our flight online. Some sort of technology error on website, instructed to checkin at desk. 4:30 AM - Arrive at airport. Try to check-in at kiosk, get the same error. We got to the JetBlue desk at RDU International Airport, where Mary helped us. Mary discovered that the Expedia provided itinerary does not match the Expedia provided tickets. We are informed that when that happens American, JetBlue, and others that use the same software cannot check you in for the flight because. Why? Because the itinerary was missing a leg of our flight! Basically we were not shown in the system as definitely being able to make it home. Mary called Expedia and was put on hold by their automated system. 4:55 AM - Mary, myself, and my brand new bride all waited for about 25 minutes when finally I decided I would make a call myself on my iPhone while Mary was on the airport phone. In their automated system, I chose "make a new reservation", thinking they might answer a little more quickly than "customer service". Not surprisingly I was connected to an Expedia person within 1 minute. They informed me that they would have to forward me to a customer service specialist. I explained to them that we were already on hold for that and had been for nearly half an hour, that we were going on our honeymoon and that our flight would be leaving soon - could they please help us. "Yes, I will help you". I hand the phone to JetBlue Mary who explains the situation 3 or 4 times. Obviously I couldn't hear both ends of the conversation at this point, but the Expedia person explained what the problem was by stating exactly what Mary had just spent 15 minutes explaining. Mary calmly confirms that this is the problem, and asks Expedia to re-issue the itinerary. Expedia tells Mary that they'll have to transfer her to customer service. Mary asks for someone specific so that we get an answer this time, and goes on hold. Mary get's connected, explains the situation, and then Mary's connection gets terminated. 5:10 AM - Mary calls back to the Expedia automated system again, and we wait for about 5 minutes on hold this time before I pick up my iPhone and call Expedia again myself. Again I go to sales, a person picks up the phone in less than a minute. I explain the situation and let them know that we are now very close to missing our flight for our honeymoon, could they please help us. "Yes, I will help you". Again I give the phone to Mary who provides them with a call back number in case we get disconnected again and explains the situation again. More back and forth with Expedia doing nothing but repeating the same questions, Mary answering the questions with the same information she provided in the original explanation, and Expedia simply restating the problem. Mary again asks them to re-issue the itinerary, and explains that doing so will fix the problem. Expedia again repeats the problem instead of fixing it, and Mary's connection gets terminated. 5:20 AM - Mary again calls back to Expedia. My beautiful bride also calls on her own phone. At this point she is struggling to hold back her tears, stumbling through an explanation of all that has happened and that we are about to miss our flight. Please help us. "Yes, I will help". My beautiful bride's connection gets terminated. Ok, maybe this disconnection isn't an accident. We've now been disconnected 3 times on two different phones. 5:45 AM - I walk away and pleadingly beg a person to help me. They "escalate" the issue to "Rosy" (sp?) at Expedia. I go through the whole song and dance again with Rosy, who gives me the same treatment Mary was given. Rosy blames JetBlue for now having the correct data. Meanwhile Mary is on the phone with Emirates Air (the airline for the second leg of our trip), who agrees with JetBlue that Expedia's data isn't up to date. We are informed by two airport employees that issues like this with Expedia are not uncommon, and that the fix is simple. On the phone iwth Rosy, I ask her to re-issue the itinerary because we are about to miss our flight. She again explains the problem to me. At this point, I am standing at the window, pleading with Rosy to help us get to our honeymoon, watching our airplane. Then our airplane leaves without us. 6:03 AM - At this point we have missed our flight. Re-issuing the itinerary is no longer a solution. I ask Rosy to start from the beginning and work us up a new trip. She says that she cannot do that. She says that she needs to talk to JetBlue and Emirates and find out why we cannot check-in for our flight. I remind Rosy that our flight has already left - I just watched it taxi away - it no longer matters why (not to mention the fact that we already knew why, and have known why since 4:30 AM), and have known the solution since 4:30 AM. Rosy, can you please book a new trip? Yes, but it will cost $400. Excuse me? Now you can, but it will cost ME to fix your mistake? Rosy says that she can escalate the situation to her supervisor but that will take 1.5 hours. 6:15 AM - I told Rosy that if they had re-issued the itinerary as JetBlue asked (at 4:30 AM), my new wife and I might be on the airplane now instead of dealing with this on the phone and missing the beginning (and how much more?) of our honeymoon. Rosy said that it was not necessary to re-issue the itinerary. Out of curiosity, i asked Rosy if there was some financial burden on them to re-issue the itinerary. "No", said Rosy. I asked her if it was a large time burden on Expedia to re-issue the itinerary. "No", said Rosy. I directly asked Rosy: Why wouldn't Expedia have re-issued the itinerary when JetBlue asked? No answer. I asked Rosy: If you had re-issued the itinerary at 4:30, isn't it possible that I would be on that flight right now? She actually surprised me by answering "Yes" to that question. So I pointed out that it followed that Expedia was responsible for the fact that we missed out flight, and she immediately went into more about how the problem was with JetBlue - but now it was ALSO an Emirates Air problem as well. I tell Rosy to go ahead and escalate the issue again, and please call me back in that 1.5 hours (which how is about 1 hour and 10 minutes away). 6:30 AM - I start tweeting my frustration with iPhone. It's now pretty much impossible for us to make it to The Maldives by 3pm, which is the time at which we would need to arrive in order to be allowed service to the actual island where we are staying. Expedia has now given me the run-around for 2 hours, caused me to miss my flight, and worst of all caused my amazing new wife Lauren to miss our honeymoon. You think I was mad? No. Furious. Its ok to make mistakes - but to refuse to fix them and to ruin our honeymoon? No, not ok, Expedia. I swore right then that Expedia would make this right. 7:45 AM - JetBlue mary is still talking her tail off to other people in JetBlue and Emirates Air. Mary works it out so that if Expedia simply books a new trip, JetBlue and Emirates will both waive all the fees. Now we just have to convince Expedia to fix their mistake and get us on our way! Around this time Expedia Rosy calls me back! I inform her of the excellent work of JetBlue Mary - that JetBlue and Emirates both will waive the fees so Expedia can fix their mistake and get us going on our way. She says that she sees documentation of this in her system and that she needs to put me on hold "for 1 to 10 minutes" to talk to Emirates Air (why I'm not exactly sure). I say ok. 8:45 AM - After an hour on hold, Rosy comes on the line and asks me to hold more. I ask her to call me back. 9:35 AM - I put down the iPhone Twitter app and picks up the laptop. You think I made some noise with my iPhone? Heh 11:25 AM - Expedia follows me and sends a canned "We're sorry, DM us the details".  If you look at their Twitter feed, 16 out of the most recent 20 tweets are exactly the same canned response.  The other 4?  Ads.  Um - #MultiFAIL? To Expedia:  You now have had (as explained above) 8 hours of 3 different people explaining our situation, you know the email address of our Expedia account, you know my web blog, you know my Twitter address, you know my phone number.  You also know how upset you have made both me and my new bride by treating us with such a ... non caring, scripted, uncooperative, argumentative, and possibly even deceitful manner.  In the wise words of the great Kenan Thompson of SNL: "FIX IT!".  And no, I'm NOT going away until you make this right. Period. 11:45 AM - Expedia corporate office called.  The woman I spoke to was very nice and apologetic.  She listened to me tell the story again, she says she understands the problem and she is going to work to resolve it.  I don't have any details on what exactly that resolution might me, she said she will call me back in 20 minutes.  She found out about the problem via Twitter.  Thank you Twitter, and all of you who helped.  Hopefully social media will win my wife and I our honeymoon, and hopefully Expedia will encourage their customer service teams treat their customers properly. 12:22 PM - Spoke to Fran again from Expedia corporate office.  She has a flight for us tonight.  She is booking it now.  We will arrive at our honeymoon destination of beautiful Veligandu Island Resort only 1 day late.  She cannot confirm today, but she expects that Expedia will pay for the lost honeymoon night.  Thank you everyone for your help.  I will reflect more on this whole situation and confirm its resolution after our flight is 100% confirmed.  For now, I'm going to take a breather and go kiss my wonderful wife! 1:50 PM - Have not yet received the promised phone call.  We did receive an email with a new itinerary for a flight but the booking is not for specific seats, so there is no guarantee that my wife and I will be able to sit together.  With the original booking I carefully selected our seats for every segment of our trip.  I decided to call into the phone number that Fran from the Expedia corporate office gave me.  Its automated voice system identified itself as "Tier 3 Support".  I am currently still on hold with them, I have not gotten through to a human yet. 1:55 PM - Fran from Expedia called me back.  She confirmed us as booked.  She called the airlines to confirm.  Unfortunately, Expedia was unwilling or unable to allow us any type of seat selection.  It is possible that i won't get to sit next to the woman I married less than a day ago on our 40 total hours of flight time (there and back).  In addition, our seats could be the worst seats on the planes, with no reclining seat back or right next to the restroom.  Despite this fact (which in my opinion is huge), the horrible inconvenience, the hours at the airport, and the negative Internet publicity that Expedia is receiving, Expedia declined to offer us any kind of upgrade or to mark us as SFU (suitable for upgrade).  Since they didn't offer - I asked, and was rejected.  I am grateful to finally be heading in the right direction, but not only did Expedia horribly botch this job from the very beginning, they followed that botch job with near zero customer service, followed by a verbally apologetic but otherwise half-hearted resolution.  If this works out favorably for us, great.  If not - I'm not done making noise, Expedia.  You owe us, and I expect you to make it right.  You haven't quite done that yet. Thanks - Thank you to Twitter.  Thanks to all those who sympathize with us and helped us get the attention of Expedia, since three people (one of them an airline employee) using Expedia's normal channels of communication for many hours didn't help.  Thanks especially to my PowerShell and Sharepoint friends, my local friends, and those connectors who encouraged me and spread my story. 5:15 PM - Love Wins - After all this, Lauren and I are exhausted.  We both took a short nap, and when we woke up we talked about the last 24 hours.  It was a big, amazing, story-filled 24 hours.  I said that Expedia won, but Lauren said no.  She pointed out how lucky we are.  We are in love and married.  We have wonderful family and friends.  We are both hard-working successful people who love what they do.  We get to go to an amazing exotic destination for our honeymoon like Veligandu in The Maldives...  That's a lot of good.  Expedia didn't win.  This was (is) a big loss for Expedia.  It is a public blemish for all to see.  But Lauren and I did win, big time.  Expedia may not have made things right - but things are right for us.  Post in progress... I will relay any further comments (or lack of) from Expedia soon, as well as an update on confirmation of their repayment of our lost resort room rates.  I'll also post a picture of us on our honeymoon as soon as I can!

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  • calculix data visualizor using QT

    - by Ann
    include "final1.h" include "ui_final1.h" include include include ifndef GL_MULTISAMPLE define GL_MULTISAMPLE 0x809D endif define numred 100 define numgrn 10 define numblu 6 final1::final1(QWidget *parent) : QGLWidget(parent) { setFormat(QGLFormat(QGL::SampleBuffers)); rotationX = -38.0; rotationY = -58.0; rotationZ = 0.0; scaling = .05; // glPolygonMode(GL_FRONT_AND_BACK,GL_FILL); //createGradient(); createGLObject(); } final1::~final1() { makeCurrent(); glDeleteLists(glObject, 1); } void final1::paintEvent(QPaintEvent * /* event */) { QPainter painter(this); draw(); } void final1::mousePressEvent(QMouseEvent *event) { lastPos = event-pos(); } void final1::mouseMoveEvent(QMouseEvent *event) { GLfloat dx = GLfloat(event-x() - lastPos.x()) / width(); GLfloat dy = GLfloat(event-y() - lastPos.y()) / height(); if (event->buttons() & Qt::LeftButton) { rotationX += 180 * dy; rotationY += 180 * dx; update(); } else if (event->buttons() & Qt::RightButton) { rotationX += 180 * dy; rotationZ += 180 * dx; update(); } lastPos = event->pos(); } void final1::createGLObject() { makeCurrent(); GLfloat f1[150],f2[150],f3[150],length=0; qreal size=2; int k=1,a,b,c,d,e,f,g,h,element_node_no=0; GLfloat x,y,z; QString str1,str2,str3,str4,str5,str6,str7,str8; int red,green,blue,index=1,displacement; int LUT[1000][3]; for(red=100;red glShadeModel(GL_SMOOTH); glObject = glGenLists(1); glNewList(glObject, GL_COMPILE); // qglColor(QColor(255, 239, 191)); glLineWidth(1.0); QLinearGradient linearGradient(0, 0, 100, 100); linearGradient.setColorAt(0.0, Qt::red); linearGradient.setColorAt(0.2, Qt::green); linearGradient.setColorAt(1.0, Qt::black); //renderArea->setBrush(linearGradient); //glColor3f(1,0,0);pow((f1[e]-f1[a]),2) QFile file("/home/41407/input1.txt"); if (!file.open(QIODevice::ReadOnly | QIODevice::Text)) return; QTextStream in(&file); while (!in.atEnd()) { QString line = in.readLine(); if(k<=125) { str1= line.section(',', 1, 1); str2=line.section(',', 2, 2); str3=line.section(',', 3, 3); x=str1.toFloat(); y=str2.toFloat(); z=str3.toFloat(); f1[k]=x; f2[k]=y; f3[k]=z; /* glBegin(GL_TRIANGLES); // glColor3f(LUT[k][0],LUT[k][1],LUT[k][2]); //QColorAt();//setPointSize(size); glVertex3f(x,y,z); glEnd();*/ } else if(k>125) { element_node_no=0; qCount(line.begin(),line.end(),',',element_node_no); // printf("\n%d",element_node_no); str1= line.section(',', 1, 1); str2=line.section(',', 2, 2); str3=line.section(',', 3, 3); str4= line.section(',', 4, 4); str5=line.section(',', 5, 5); str6=line.section(',', 6, 6); str7= line.section(',', 7, 7); str8=line.section(',', 8, 8); a=str1.toInt(); b=str2.toInt(); c=str3.toInt(); d=str4.toInt(); e=str5.toInt(); f=str6.toInt(); g=str7.toInt(); h=str8.toInt(); glBegin(GL_POLYGON); glPolygonMode(GL_FRONT_AND_BACK,GL_FILL); //brush.setColor(Qt::black);//setColor(QColor::black()); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); // pmp.setBrush(gradient); glVertex3f(f1[a],f2[a] ,f3[a]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[b],f2[b] ,f3[b]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[c],f2[c] ,f3[c]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[d],f2[d] ,f3[d]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[a],f2[a] ,f3[a]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); //glEnd(); //glBegin(GL_LINE_LOOP); glVertex3f(f1[e],f2[e] ,f3[e]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[f],f2[f] ,f3[f]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[g],f2[g], f3[g]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[h],f2[h], f3[h]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[d],f2[d] ,f3[d]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[a],f2[a] ,f3[a]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glEnd(); glBegin(GL_POLYGON); //glVertex3f(f1[a],f2[a] ,f3[a]); glVertex3f(f1[e],f2[e] ,f3[e]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[h],f2[h], f3[h]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); //glVertex3f(f1[d],f2[d] ,f3[d]); glVertex3f(f1[g],f2[g], f3[g]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[c],f2[c] ,f3[c]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[f],f2[f] ,f3[f]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glVertex3f(f1[b],f2[b] ,f3[b]); glColor3f(LUT[k][0],LUT[k][1],LUT[k++][2]); glEnd(); /*length=sqrt(pow((f1[e]-f1[a]),2)+pow((f2[e]-f2[a]),2)+pow((f3[e]-f3[a]),2)); printf("\n%d",length);*/ } k++; } glEndList(); file.close(); k=1; QFile file1("/home/41407/op.txt"); if (!file1.open(QIODevice::ReadOnly | QIODevice::Text)) return; QTextStream in1(&file1); k=1; while (!in1.atEnd()) { QString line = in1.readLine(); // if(k<=125) { str1= line.section(' ', 1, 1); x=str1.toFloat(); str2=line.section(' ', 2, 2); y=str2.toFloat(); str3=line.section(' ', 3, 3); z=str3.toFloat(); displacement=sqrt(pow( (x-f1[k]),2)+pow((y-f2[k]),2)+pow((z-f3[k]),2)); //printf("\n %d : %d",k,displacement); glBegin(GL_POLYGON); //glColor3f(LUT[displacement][0],LUT[displacement][1],LUT[displacement][2]); glVertex3f(f1[k],f2[k],f3[k]); glEnd(); a1[k]=x+f1[k]; a2[k]=y+f2[k]; a3[k]=z+f3[k]; //printf("\nc: %f %f %f",x,y,z); //printf("\nf: %f %f %f",f1[k],f2[k],f3[k]); //printf("\na: %f %f %f",a1[k],a2[k],a3[k]); } k++; glEndList(); } } void final1::draw() { glPushAttrib(GL_ALL_ATTRIB_BITS); glMatrixMode(GL_PROJECTION); glPushMatrix(); glLoadIdentity(); GLfloat x = 3.0 * GLfloat(width()) / height(); glOrtho(-x, +x, -3.0, +3.0, 4.0, 15.0); glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadIdentity(); glTranslatef(0.0, 0.0, -10.0); glScalef(scaling, scaling, scaling); glRotatef(rotationX, 1.0, 0.0, 0.0); glRotatef(rotationY, 0.0, 1.0, 0.0); glRotatef(rotationZ, 0.0, 0.0, 1.0); glEnable(GL_MULTISAMPLE); glCallList(glObject); glMatrixMode(GL_MODELVIEW); glPopMatrix(); glMatrixMode(GL_PROJECTION); glPopMatrix(); glPopAttrib(); } /*uint final1::colorAt(int x) { generateShade(); QPolygonF pts = m_hoverPoints->points(); for (int i=1; i < pts.size(); ++i) { if (pts.at(i-1).x() <= x && pts.at(i).x() >= x) { QLineF l(pts.at(i-1), pts.at(i)); l.setLength(l.length() * ((x - l.x1()) / l.dx())); return m_shade.pixel(qRound(qMin(l.x2(), (qreal(m_shade.width() - 1)))), qRound(qMin(l.y2(), qreal(m_shade.height() - 1)))); } } return 0;*/ //final1:: //} /*void final1::createGLObject() { makeCurrent(); //QPainter painter; QPixmap pm(20, 20); QPainter pmp(&pm); pmp.fillRect(0, 0, 10, 10, Qt::blue); pmp.fillRect(10, 10, 10, 10, Qt::lightGray); pmp.fillRect(0, 10, 10, 10, Qt::darkGray); pmp.fillRect(10, 0, 10, 10, Qt::darkGray); pmp.end(); QPalette pal = palette(); pal.setBrush(backgroundRole(), QBrush(pm)); //setAutoFillBackground(true); setPalette(pal); //GLfloat f1[150],f2[150],f3[150],a1[150],a2[150],a3[150]; int k=1,a,b,c,d,e,f,g,h; //int p=0; GLfloat x,y,z; int displacement; QString str1,str2,str3,str4,str5,str6,str7,str8; int red,green,blue,index=1; int LUT[8000][3]; for(red=0;red //glShadeModel(GL_LINE); glObject = glGenLists(1); glNewList(glObject, GL_COMPILE); //qglColor(QColor(120,255,210)); glLineWidth(1.0); //glColor3f(1,0,0); QFile file("/home/41407/input.txt"); if (!file.open(QIODevice::ReadOnly | QIODevice::Text)) return; QTextStream in(&file); while (!in.atEnd()) { //glColor3f(LUT[k][0],LUT[k][1],LUT[k][2]); QString line = in.readLine(); if(k<=125) { //printf("\nline :%c",line); str1= line.section(',', 1, 1); str2=line.section(',', 2, 2); str3=line.section(',', 3, 3); x=str1.toFloat(); y=str2.toFloat(); z=str3.toFloat(); f1[k]=x; f2[k]=y; f3[k]=z; //printf("\nf: %f %f %f",f1[k],f2[k],f3[k]); } else if(k125) //for(p=0;p<6;p++) { //glColor3f(LUT[k][0],LUT[k][1],LUT[k][2]); update(); str1= line.section(',', 1, 1); str2=line.section(',', 2, 2); str3=line.section(',', 3, 3); str4= line.section(',', 4, 4); str5=line.section(',', 5, 5); str6=line.section(',', 6, 6); str7= line.section(',', 7, 7); str8=line.section(',', 8, 8); a=str1.toInt(); b=str2.toInt(); c=str3.toInt(); d=str4.toInt(); e=str5.toInt(); f=str6.toInt(); g=str7.toInt(); h=str8.toInt(); //for (p = 0; p < 6; p++) { // glBegin(GL_LINE_WIDTH); //glColor3f(LUT[126][0],LUT[126][1],LUT[126][2]); //update(); //glNormal3fv(&n[p][0]); //glVertex3f(f1[i],f2[i],f3[i]); glVertex3fv(&v[faces[i][1]][0]); glVertex3fv(&v[faces[i][2]][0]); glVertex3fv(&v[faces[i][3]][0]); //glEnd(); //} glBegin(GL_LINE_LOOP); //glColor3f(p*20,p*20,p); glColor3f(1,0,0); glVertex3f(f1[a],f2[a] ,f3[a]); //painter.fillRect(QRectF(f1[a],f2[a] ,f3[a], 2), Qt::magenta); glVertex3f(f1[b],f2[b] ,f3[b]); glVertex3f(f1[c],f2[c] ,f3[c]); glVertex3f(f1[d],f2[d] ,f3[d]); glVertex3f(f1[a],f2[a] ,f3[a]); glVertex3f(f1[e],f2[e] ,f3[e]); glVertex3f(f1[f],f2[f] ,f3[f]); glVertex3f(f1[g],f2[g], f3[g]); glVertex3f(f1[h],f2[h], f3[h]); glVertex3f(f1[d],f2[d] ,f3[d]); glVertex3f(f1[a],f2[a] ,f3[a]); //glColor3f(1,0,0); //QLinearGradient ( f1[a], f2[a], f1[b], f2[b] ); glEnd(); glBegin(GL_LINES); //glNormal3fv(&n[p][0]); //glColor3f(LUT[k][0],LUT[k][1],LUT[k][2]); glVertex3f(f1[e],f2[e] ,f3[e]); glVertex3f(f1[h],f2[h], f3[h]); glVertex3f(f1[g],f2[g], f3[g]); glVertex3f(f1[c],f2[c] ,f3[c]); glVertex3f(f1[f],f2[f] ,f3[f]); glVertex3f(f1[b],f2[b] ,f3[b]); glEnd(); } } k++; } glEndList(); qglColor(QColor(239, 255, 191)); glLineWidth(1.0); glColor3f(0,1,0); k=1; QFile file1("/home/41407/op.txt"); if (!file1.open(QIODevice::ReadOnly | QIODevice::Text)) return; QTextStream in1(&file1); k=1; while (!in1.atEnd()) { QString line = in1.readLine(); // if(k<=125) { str1= line.section(' ', 1, 1); x=str1.toFloat(); str2=line.section(' ', 2, 2); y=str2.toFloat(); str3=line.section(' ', 3, 3); z=str3.toFloat(); displacement=sqrt(pow( (x-f1[k]),2)+pow((y-f2[k]),2)+pow((z-f3[k]),2)); printf("\n %d : %d",k,displacement); glBegin(GL_POINT); glColor3f(LUT[displacement][0],LUT[displacement][1],LUT[displacement][2]); glVertex3f(x,y,z); glLoadIdentity(); glEnd(); a1[k]=x+f1[k]; a2[k]=y+f2[k]; a3[k]=z+f3[k]; //printf("\nc: %f %f %f",x,y,z); //printf("\nf: %f %f %f",f1[k],f2[k],f3[k]); //printf("\na: %f %f %f",a1[k],a2[k],a3[k]); } k++; glEndList(); } }*/ /*void final1::draw() { glPushAttrib(GL_ALL_ATTRIB_BITS); glMatrixMode(GL_PROJECTION); glPushMatrix(); glLoadIdentity(); GLfloat x = 3.0 * GLfloat(width()) / height(); glOrtho(-x, +x, -3.0, +3.0, 4.0, 15.0); glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadIdentity(); glTranslatef(0.0, 0.0, -10.0); glScalef(scaling, scaling, scaling); glRotatef(rotationX, 1.0, 0.0, 0.0); glRotatef(rotationY, 0.0, 1.0, 0.0); glRotatef(rotationZ, 0.0, 0.0, 1.0); glEnable(GL_MULTISAMPLE); glCallList(glObject); glMatrixMode(GL_MODELVIEW); glPopMatrix(); glMatrixMode(GL_PROJECTION); glPopMatrix(); glPopAttrib(); }*/ I need to change the color of a portion of beam where pressure is applied.But I am not able to color the front end back phase.

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  • Anatomy of a serialization killer

    - by Brian Donahue
    As I had mentioned last month, I have been working on a project to create an easy-to-use managed debugger. It's still an internal tool that we use at Red Gate as part of product support to analyze application errors on customer's computers, and as such, should be easy to use and not require installation. Since the project has got rather large and important, I had decided to use SmartAssembly to protect all of my hard work. This was trivial for the most part, but the loading and saving of results was broken by SA after using the obfuscation, rendering the loading and saving of XML results basically useless, although the merging and error reporting was an absolute godsend and definitely worth the price of admission. (Well, I get my Red Gate licenses for free, but you know what I mean!)My initial reaction was to simply exclude the serializable results class and all of its' members from obfuscation, and that was just dandy, but a few weeks on I decided to look into exactly why serialization had broken and change the code to work with SA so I could write any new code to be compatible with SmartAssembly and save me some additional testing and changes to the SA project.In simple terms, SA does all that it can to prevent serialization problems, for instance, it will not obfuscate public members of a DLL and it will exclude any types with the Serializable attribute from obfuscation. This prevents public members and properties from being made private and having the name changed. If the serialization is done inside the executable, however, public members have the access changed to private and are renamed. That was my first problem, because my types were in the executable assembly and implemented ISerializable, but did not have the Serializable attribute set on them!public class RedFlagResults : ISerializable        {        }The second problem caused by the pruning feature. Although RedFlagResults had public members, they were not truly properties, and used the GetObjectData() method of ISerializable to serialize the members. For that reason, SA could not exclude these members from pruning and further broke the serialization. public class RedFlagResults : ISerializable        {                public List<RedFlag.Exception> Exceptions;                 #region ISerializable Members                 public void GetObjectData(SerializationInfo info, StreamingContext context)                {                                info.AddValue("Exceptions", Exceptions);                }                 #endregionSo to fix this, it was necessary to make Exceptions a proper property by implementing get and set on it. Also, I added the Serializable attribute so that I don't have to exclude the class from obfuscation in the SA project any more. The DoNotPrune attribute means I do not need to exclude the class from pruning.[Serializable, SmartAssembly.Attributes.DoNotPrune]        public class RedFlagResults        {                public List<RedFlag.Exception> Exceptions {get;set;}        }Similarly, the Exception class gets the Serializable and DoNotPrune attributes applied so all of its' properties are excluded from obfuscation.Now my project has some protection from prying eyes by scrambling up the code so it's harder to reverse-engineer, without breaking anything. SmartAssembly has also provided the benefit of merging so that the end-user doesn't need to extract all of the DLL files needed by RedFlag into a directory, and can be run directly from the .zip archive. When an error occurs (hey, I'm only human!), an exception report can be sent to me so I can see what went wrong without having to, er, debug the debugger.

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