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  • A regex to match a substring that isn't followed by a certain other substring.

    - by Rayne
    I need a regex that will match blahfooblah but not blahfoobarblah I want it to match only foo and everything around foo, as long as it isn't followed by bar. I tried using this: foo.*(?<!bar) which is fairly close, but it matches blahfoobarblah. The negative look behind needs to match baranything and not just bar. The specific language I'm using is Clojure which uses Java regexes under the hood.

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  • regex. How can I match the value between '+' and ':' ?

    - by martin
    I have this string: sometext +[value]:- I would like to match the value(1-3 numerical characters) (with regex, javascript) sometext may contain a +sign if i'm unlucky so I don't wanna end up with matching some +text +value:- I sat up last night banging my head against this, so I would be really glad if someone could help me.

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  • How do you code up a pattern matching block in scala?

    - by egervari
    How do you code a function that takes in a block of code that contains case statements? For instance, in my block of code, I don't want to code a match or a default case... looking something like this myApi { case Whatever() => // code for case 1 case SomethingElse() => // code for case 2 } And inside of my myApi(), it'll actually do the matches. Help?

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  • How do you code up a pattern matching code block in scala?

    - by egervari
    How do you code a function that takes in a block of code as a parameter that contains case statements? For instance, in my block of code, I don't want to do a match or a default case explicitly. I am looking something like this myApi { case Whatever() => // code for case 1 case SomethingElse() => // code for case 2 } And inside of my myApi(), it'll actually execute the code block and do the matches. Help?

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  • How would I order a table by the number of matching params in the where clause of an sql statement?

    - by Eitan
    I'm writing sql to search a database by a number of parameters. How would I go about ordering the result set by the items that match the most parameters in the where clause. For example: SELECT * FROM users WHERE username = 'eitan' OR email = '[email protected]' OR company = 'eitan' Username | email | company 1) eitan | [email protected] | blah 2) eitan | [email protected] | eitan 3) eitan | [email protected] | blah should be ordered like: 2, 3, 1. Thanks. (ps the query isn't that easy, has a lot of joins and a lot of OR's in the WHERE) Eitan

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  • Which substring of the string1 matches with the string2.

    - by Harikrishna
    There are two strings. String str1="Order Number Order Time Trade Number"; String str2="Order Tm"; Then I want to know that str2 matches with which substring in the str1. string regex = Regex.Escape(str2.Replace(@"\ ", @"\s*"); bool isColumnNameMatched = Regex.IsMatch(str1, regex, RegexOptions.IgnoreCase); I am using regex because "Order Tm" will also matches "Order Time".It gives bool value that matches occurred or not. Like str2="Order Tm" then it should return like in the str1,Order Time is the substring where matches is occurred.

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  • Save File Contents to Variable in Python3.3 [migrated]

    - by Neo_Programmer
    I have a Python3.3 script that seems to not work. The script will search for an XML pattern and then print the results to the screen. I am using Ubuntu 12.10 (AMD64) and python3.3. I prefer to use regex with XML, so please disregard this unconventional form of programming. #!/usr/bin/python3.3 import io, re openfile = open('./temp/xaiml/temp_db1.xaiml', 'r') TEMPDB = openfile.read() OUTPUT = print(''.join(re.findall('<cgy><prn>.*_.*<\/prn>.*<\/cgy>', TEMPDB, flags=re.I)))

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  • Javascript regex returning true.. then false.. then true.. etc

    - by betamax
    I have a strange problem with the validation I am writing on a form. It is a 'Check Username' button next to an input. The input default value is the username for example 'betamax'. When I press 'Check Username' it passes the regex and sends the username to the server. The server behaves as expected and returns '2' to tell the javascript that they are submitting their own username. Then, when I click the button again, the regex fails. Nothing is sent to the server obviously because the regex has failed. If I press the button again, the regex passes and then the username is sent to the server. I literally cannot figure out what would be making it do this! It makes no sense to me! This is my code: $j("#username-search").click(checkUserName); function checkUserName() { var userName = $j("#username").val(); var invalidUserMsg = 'Invalid username (a-zA-Z0-9 _ - and not - or _ at beginning or end of string)'; var filter = /^[^-_]([a-z0-9-_]{4,20})[^-_]$/gi; if (filter.test(userName)) { console.log("Pass") $j.post( "/account/profile/username_check/", { q: userName }, function(data){ if(data == 0) { $j("#username-search-results").html("Error searching for username. Try again?"); } else if(data == 5) { $j("#username-search-results").html(invalidUserMsg); } else if(data == 4) { $j("#username-search-results").html("Username too short or too long."); } else if(data == 2) { $j("#username-search-results").html("This is already your username."); } else if(data == 3) { $j("#username-search-results").html("This username is taken."); } else if(data == 1){ $j("#username-search-results").html("This username is available!"); } }); } else { console.log("fail") $j("#username-search-results").html(invalidUserMsg); } return false; } The HTML: <input name="username" id="username" value="{{ user.username }}" /> <input type="button" value="Is it taken?" id="username-search"> <span id="username-search-results"></span>

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  • Word VBA - Find text between delimiters and convert to lower case

    - by jJack
    I would like to find text which is between the < and characters, and then turn any found text into "normal" case, where first letter of word is capitalized. Here is what I have thus far: Function findTextBetweenCarots() As String Dim strText As String With Selection .Find.Text = "<" ' what about <[^0-9]+> ? .Find.Forward = True .Find.Wrap = wdFindContinue End With Selection.Find.Execute ' Application.Selection. ' how do I get the text between the other ">"? findCarotSymb = Application.Selection.Text End Function Or, is there a better way of doing this? I also approached the problem using the VBScript Regex 5.5 library, which worked on simple documents, but not on certain documents with complex tables. For example, trying to just bold the text (for simplicity): Sub BoldUpperCaseWords() Dim regEx, Match, Matches Dim rngRange As Range Set regEx = New RegExp regEx.Pattern = "<[^0-9]+>" regEx.IgnoreCase = False regEx.Global = True Set Matches = regEx.Execute(ActiveDocument.Range.Text) For Each Match In Matches ActiveDocument.Range(Match.FirstIndex, Match.FirstIndex + Len(Match.Value)).Bold = True Next End Sub would not work in a document with tables. In fact, it would not even bold the correct text (the text between the <. This leads me to believe I have a broader issue here that I am missing. Here is what a sample doc looks like. Notice the wrong text is bold:

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  • Python: Convert format string to regular expression

    - by miracle2k
    The users of my app can configure the layout of certain files via a format string. For example, the config value the user specifies might be: layout = '%(group)s/foo-%(locale)s/file.txt' I now need to find all such files that already exist. This seems easy enough using the glob module: glob_pattern = layout % {'group': '*', 'locale': '*'} glob.glob(glob_pattern) However, now comes the hard part: Given the list of glob results, I need to get all those filename-parts that matched a given placeholder, for example all the different "locale" values. I thought I would generate a regular expression for the format string that I could then match against the list of glob results (or then possibly skipping glob and doing all the matching myself). But I can't find a nice way to create the regex with both the proper group captures, and escaping the rest of the input. For example, this might give me a regex that matches the locales: regex = layout % {'group': '.*', 'locale': (.*)} But to be sure the regex is valid, I need to pass it through re.escape(), which then also escapes the regex syntax I have just inserted. Calling re.escape() first ruins the format string. I know there's fnmatch.translate(), which would even give me a regex - but not one that returns the proper groups. Is there a good way to do this, without a hack like replacing the placeholders with a regex-safe unique value etc.? Is there possibly some way (a third party library perhaps?) that allows dissecting a format string in a more flexible way, for example splitting the string at the placeholder locations?

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  • regular expression for emails NOT ending with replace script

    - by corroded
    I'm currently modifying my regex for this: http://stackoverflow.com/questions/2782031/extracting-email-addresses-in-an-html-block-in-ruby-rails basically, im making another obfuscator that uses ROT13 by parsing a block of text for all links that contain a mailto referrer(using hpricot). One use case this doesn't catch is that if the user just typed in an email address(without turning it into a link via tinymce) So here's the basic flow of my method: 1. parse a block of text for all tags with href="mailto:..." 2. replace each tag with a javascript function that changes this into ROT13 (using this script: http://unixmonkey.net/?p=20) 3. once all links are obfuscated, pass the resulting block of text into another function that parses for all emails(this one has an email regex that reverses the email address and then adds a span to that email - to reverse it back) step 3 is supposed to clean the block of text for remaining emails that AREN'T in a href tags(meaning it wasn't parsed by hpricot). Problem with this is that the emails that were converted to ROT13 are still found by my regex. What i want to catch are just emails that WEREN'T CONVERTED to ROT13. How do i do this? well all emails the WERE CONVERTED have a trailing "'.replace" in them. meaning, i need to get all emails WITHOUT that string. so far i have this regex: /\b([A-Z0-9._%+-]+@[A-Z0-9.-]+.[A-Z]{2,4}('.replace))\b/i but this gets all the emails with the trailing '.replace i want to get the opposite and I'm currently stumped with this. any help from regex gurus out there? MORE INFO: Here's the regex + the block of text im parsing: http://www.rubular.com/r/NqXIHrNqjI as you can see, the first two 'email addresses' are already obfuscated using ROT13. I need a regex that gets the emails [email protected] and [email protected]

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  • What is a Perl regex for finding the first non-consecutively-repeating character in a string.

    - by DVK
    Your task, should you choose to accept it, is to write a Perl regular expression that for a given string, will return the first occurence of a character that is not consecutively duplicated. In other words, both preceded AND succeeded by characters different from itself (or start/end of string respectively). Example: IN: aabbcdecc OUT: c Please note that "not consecutively duplicated" does not mean "anywhere in the string". NOTE: it must be a pure regex expression. E.g. the solution that obviously comes to mind (clone the string, delete all the duplicates, and print the first remaining character) does not count, although it solves the problem. The question is inspired by my somewhat off-topic answer to this: http://stackoverflow.com/questions/2548606/perl-function-to-find-first-non-repeating-character-in-a-string

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  • A regex to match a comma that isn't surrounded by quotes.

    - by Rayne
    I'm using Clojure, so this is in the context of Java regexes. Here is an example string: "{:a "ab,cd, efg", :b "ab,def, egf,", :c "Conjecture"}" The important bits are the commas after each string. I'd like to be able to replace them with newline characters with Java's replaceAll method. A regex that will match any comma that is not surrounded by quotes will do. If I'm not coming across well, please ask and I'll be happily to clarify anything. edit: sorry for the confusion in the title. I haven't been awake very long. String: {:a "ab, cd efg",} <-- In this example, the comma at the end would be matched, but the ones inside the quote would not.

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  • How can I capture multiple matches from the same Perl regex?

    - by Sho Minamimoto
    I'm trying to parse a single string and get multiple chunks of data out from the same string with the same regex conditions. I'm parsing a single HTML doc that is static (For an undisclosed reason, I can't use an HTML parser to do the job.) I have an expression that looks like: $string =~ /\<img\ssrc\="(.*)"/; and I want to get the value of $1. However, in the one string, there are many img tags like this, so I need something like an array returned (@1?) is this possible?

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  • How to add title of link as a alt of img. using regex and in dreamweaver?

    - by jitendra
    How to add title of link as a alt of img. using regex and in dreamweaver. I have to do in a large document. and in multiple files Before <a title="Whatever is written here" href="#" target="_blank"> <img width="14" height="14" src="#" /></a> after <a title="Whatever is written here" href="#" target="_blank"> <img width="14" height="14" src="#" alt="Whatever is written here" /></a>

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  • How can I match end-of-line multiple times in a regex without interpolation?

    - by harschware
    Hi, if I have a input with new lines in it like: [INFO] xyz [INFO] How can I pull out the xyz part? I tried a pattern like /^\[INFO\]$(.*?)$\[INFO\]/ms, but perl gives me: Use of uninitialized value $\ in regexp compilation at scripts\t.pl line 6. I've been trying things to get interpolation to stop like using qr// but alas, no love. EDIT: The key is that the end-of-line anchor is a dollar sign but at times it may be necessary to intersperse the end-of-line anchor through the pattern. If the pattern is interpolating then you might get problems such as uninitialized $\. For instance an acceptable solution here is /^\[INFO\]\s*^(.*?)\s*^\[INFO\]/ms but that does not solve the crux of the first problem. I've changed the anchors to be ^ so there is no interpolation going on, and with this input I'm free to do that. But what about when I really do want to reference EOL with $ in my pattern? How do I get the regex to compile?

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  • What would be the PHP equivalent of this Perl regex?

    - by Jamie
    What would be the PHP equivalent of this Perl regex? if (/^([a-z0-9-]+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)$/ and $1 ne "global" and $1 ne "") { print " <tr>\n"; print " <td>$1</td>\n"; print " <td>$2</td>\n"; print " <td>$3</td>\n"; print " <td>$4</td>\n"; print " <td>$5</td>\n"; print " <td>$6</td>\n"; print " <td>$7</td>\n"; print " <td>$8</td>\n"; print " </tr>\n"; }

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  • How can match end-of-line multiple times in a regex without interpolation?

    - by harschware
    Hi, if I have a input with new lines in it like: [INFO] xyz [INFO] How can I pull out the xyz part? I tried a pattern like /^\[INFO\]$(.*?)$\[INFO\]/ms, but perl gives me: Use of uninitialized value $\ in regexp compilation at scripts\t.pl line 6. I've been trying things to get interpolation to stop like using qr// but alas, no love. EDIT: The key is that the end-of-line anchor is a dollar sign but at times it may be necessary to intersperse the end-of-line anchor through the pattern. If the pattern is interpolating then you might get problems such as uninitialized $\. For instance an acceptable solution here is /^\[INFO\]\s*^(.*?)\s*^\[INFO\]/ms but that does not solve the crux of the first problem. I've changed the anchors to be ^ so there is no interpolation going on, and with this input I'm free to do that. But what about when I really do want to reference EOL with $ in my pattern? How do I get the regex to compile?

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