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  • rsyslog - regex trouble

    - by benmccann
    I'm trying to setup the logentries service. If a log entry has a token in it then I would like to send it to api.logentries.com:10000. The token is a guid in the format aaaaaaaa-bbbb-cccc-dddd-eeeeeeeeeeee. Right now I'm doing: # If there's a logentries token then send it directly to logentries :msg, regex, ".*[a-z0-9]{8}-[a-z0-9]{4}-[a-z0-9]{4}-[a-z0-9]{4}-[a-z0-9]{12}.*" & @@api.logentries.com:10000 I checked the rsyslog debug logs and my regex is not matching, but I can't figure out why or how to fix it: 5245.961161378:7fb79b514700: Filter: check for property 'msg' (value ' fb1c507f-2ede-4d7f-a140-2bd8d56e133 - application - [play-akka.actor.default-dispatcher-1] - Found user: 4fb11ea5e4b00a1aeebe2800') regex '.*[a-z0-9]{8}-[a-z0-9]{4}-[a-z0-9]{4}-[a-z0-9]{4}-[a-z0-9]{12}.*': FALSE

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  • Word mergefield wildcard not correctly matching

    - by aZn137
    Hello, Below is my mergefield code: { IF { MERGEFIELD Subs_State } = "GA" "blah blah" "{ IF { MERGEFIELD CEOrgStates } = "GA" "blah blah" ""} "} I'm pulling records from a MS Access db. My goal is to check whether a record has Subs_State field matching "GA", or the CEOrgStates has the word "GA" (some records have stuff like "|FL|CA|GA|CT|KY|" (no quotes)). When I merged the docs, Word doesnt seem to be able to match with the wildcards: If I use and compare "*GA" (fields ending with GA), it works; however, the double wildcards "*GA*" dont seem to work at all. Here are the things I’ve tried: Have data in lowercase, then compare with lowercase Have data in lowercase, convert to and then compare with uppercase Do the opposite of the above 2 with uppercase data Use “*GA*” and “*ga*” (no pipe) Use different delimiters Nothing seems to work with the double wildcard matching. What am I doing wrong? Thanks!

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  • Quick Replace in Visual Studio 2010 fails to use Tagged Expression n

    - by slomojo
    I'm trying to do some basic regex Quick Replace operations in Visual Studio 2010, but when I use regex grouping I don't get Tagged Expressions (ie. \1 \2 etc.) returning their values, instead they are blank. For example: Text int a = int.Parse("10"); int b = int.Parse("20"); int c = int.Parse("30"); Search Pattern (regex enabled) int\.Parse\("([0-9]*)"\); Replace \1; Replaced Text int a = ; int b = ; int c = ;

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  • Regex query: how can I search PDFs for a phrase where words in that phrase appear on more than one l

    - by Alison
    I am trying to set up an index page for the weekly magazine I work on. It is to show readers the names of companies mentioned in that weeks' issue, plus the page numbers they are appear on. I want to search all the PDF files for the week, where one PDF = one magazine page (originally made in Adobe InDesign CS3 and Adobe InCopy CS3). I have set up a list of companies I want to search for and, using PowerGREP and using delimited regular expressions, I am able to find most page numbers where a company is mentioned. However, where a company name contains two or more words, the search I am running will not pick up instances where the name appears over more than one line. For example, when looking for "CB Richard Ellis" and "Cushman & Wakefield", I got no result when the text appeared like this: DTZ beat BNP PRE, CB [line break here] Richard Ellis and Cushman & [line break here] Wakefield to secure the contract. [line end here] Could someone advise me on how to write a regular expression that will ignore white space between words and ignore line endings OR one that will look for the words including all types of white space (ie uneven spaces between words; spaces at the end of lines or line endings; and tabs (I am guessing that this info is imbedded somehow in PDF files). Here is a sample of the set of terms I have asked PowerGREP to search for: \bCB Richard Ellis\b \bCB Richard Ellis Hotels\b \bCentaur Services\b \bChapman Herbert\b \bCharities Property Fund\b \bChetwoods Architects\b \bChurch Commissioners\b \bClive Emson\b \bClothworkers’ Company\b \bColliers CRE\b \bCombined English Stores Group\b \bCommercial Estates Group\b \bConnells\b \bCooke & Powell\b \bCordea Savills\b \bCrown Estate\b \bCushman & Wakefield\b \bCWM Retail Property Advisors\b [Note that there is a delimited hard return between each \b at the end of each phrase and beginnong of the next phrase.] By the way, I am a production journalist and not usually involved in finding IT-type solutions and am finding it difficult to get to grips with the technical language on the PowerGREP site. Thanks for assistance Alison

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  • Regex for [a-zA-Z0-9\-] with dashes allowed in between but not at the start or end

    - by orokusaki
    I'm using Python and I'm not trying to extract the value, but rather test to make sure it fits the pattern. allowed values: spam123-spam-eggs-eggs1 spam123-eggs123 spam 123 eggs123 I just can't have a dash at the starting or the end. There is a question on here that works in the opposite direction by getting the string value after the fact, but I simply need to test for the value so that I can disallow it. Also, it can be a maximum of 25 chars long, but a minimum of 4 chars long. Here's what I've come up with after some experimentation with lookbehind, etc: # Nothing here

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  • C# Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    Hello guys, I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program: http://img43.imageshack.us/img43/2118/11618743.jpg

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  • Using regex to extract variables from a plain-text form letter?

    - by Yaaqov
    Hi - I'm looking for a good example of using Regular Expressions in PHP to "reverse engineer" a form letter (with a known format, of course) that has been pasted into a multiline textbox and sent to a script for processing. So, for example, let's assume this is the original plain-text input (taken from a USDA press release): WASHINGTON, April 5, 2010 - North American Bison Co-Op, a New Rockford, N.D., establishment is recalling approximately 25,000 pounds of whole beef heads containing tongues that may not have had the tonsils completely removed, which is not compliant with regulations that require the removal of tonsils from cattle of all ages, the U.S. Department of Agriculture's Food Safety and Inspection Service (FSIS) announced today. For clarity, the fields that are variables are highlighted below: [pr_city=]WASHINGTON, [pr_date=]April 5, 2010 - [corp_name=]North American Bison Co-Op, a [corp_city=]New Rockford, [corp_state=]N.D., establishment is recalling approximately [amount=]25,000 pounds of [product=]whole beef heads containing tongues that may not have had the tonsils completely removed, which is not compliant with regulations that require [reason=]the removal of tonsils from cattle of all ages, the U.S. Department of Agriculture's Food Safety and Inspection Service (FSIS) announced today. How could I efficiently extract the contents of the pr_city pr_date corp_name corp_city corp_state amount product reason fields from my example? Any help would be appreciated, thanks.

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  • Regex for retrieving the parameter of the css url function...

    - by Kieron
    Hi, I'm trying to get the url portion of the following string: url(images/ui-bg_highlight-soft_75_cccccc_1x100.png) So the required part if images/ui-bg_highlight-soft_75_cccccc_1x100.png. Currently I've got this: url\((?<url>.*)\) But it seems to be choking on the following example: url(images/ui-bg_flat_0_aaaaaa_40x100.png) 50% 50% repeat-x; opacity: .30;filter:Alpha(Opacity=30) Which results in images/ui-bg_flat_0_aaaaaa_40x100.png) 50% 50% repeat-x; opacity: .30;filter:Alpha(Opacity=30... I'd like to make sure that it supports as many variations as possible (additional whitespace etc). Thanks! Kieron

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  • What is wrong with this really really simple RegEx expression?

    - by Pure.Krome
    Hi folks, this one is really easy. I'm trying to create a Regular Expression that will result in a Successful Match when against the following text /default.aspx? So i tried the following... ^/default.aspx$ and it's failing to match it. Can someone help, please? (i'm guessing i'm screwing up becuase of the \ and the ? in the input expression).

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  • Regex to identify rows that do not contain exact number of occurences of quotemark character using Notepad++

    - by SamAspin
    I would like to be able to jump to rows that dont contain 6 quotemarks in a quoted-CSV file as it feels like a good way to identify broken rows. I think using a regular expression with Notepad++'s find features would be a sensible approach but I'm not sure how to pick the rows up. 6 quotemarks (") would suggest a complete row so I want to skip to any row that does not contain 6. Here is some sample data to play with, in this example its the 4th line I'd like to jump to "sam","mark","dave" "sam","mark","dave" "sam","mark","dave" "sam","mark"," dave" "sam","mark","dave" "sam","mark","dave"

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  • How to regex match a string of alnums and hyphens, but which doesn't begin or end with a hyphen?

    - by Shahar Evron
    I have some code validating a string of 1 to 32 characters, which may contain only alpha-numerics and hyphens ('-') but may not begin or end with a hyphen. I'm using PCRE regular expressions & PHP (albeit the PHP part is not really important in this case). Right now the pseudo-code looks like this: if (match("/^[\p{L}0-9][\p{L}0-9-]{0,31}$/u", string) and not match("/-$/", string)) print "success!" That is, I'm checking first that the string is of right contents, doesn't being with a '-' and is of the right length, and then I'm running another test to see that it doesn't end with a '-'. Any suggestions on merging this into a single PCRE regular expression? I've tried using look-ahead / look-behind assertions but couldn't get it to work.

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  • How to do regex HTML tag replace in MS SQL?

    - by timmerk
    I have a table in SQL Server 2005 with hundreds of rows with HTML content. Some of the content has HTML like: <span class=heading-2>Directions</span> where "Directions" changes depending on page name. I need to change all the <span class=heading-2> and </span> tags to <h2> and </h2> tags. I wrote this query to do content changes in the past, but it doesn't work for my current problem because of the ending HTML tag: Update ContentManager Set ContentManager.Content = replace(Cast(ContentManager.Content AS NVARCHAR(Max)), 'old text', 'new text') Does anyone know how I could accomplish the span to h2 replacing purely in T-SQL? Everything I found showed I would have to do CLR integration. Thanks!

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  • Best way to get back to using the power of lxml after having to use a regex to find something in an

    - by PyNEwbie
    I am trying to rip some text out of a large number of html documents (numbers in the hundreds of thousands). The documents are really forms but they are prepared by a very large group of different organizations so there is significant variation in how they create the document. For example, the documents are divided into chapters. I might want to extract the contents of Chapter 5 from every document so I can analyze the content of the chapter. Initially I thought this would be easy but it turns out that the authors might use a set of non-nested tables throughout the document to hold the content so that Chapter n could be displayed using td tags inside a table. Or they might use other elements such as p tags H tags, div tags or any other block level element. After trying repeatedly to use lxml to help me identify the beginning and end of each chapter I have determined that it is a lot cleaner to use a regular expression because in every case, no matter what the enclosing html element is the chapter label is always in the form of >Chapter # It is a little more complicated in that there might be some white space or non-breaking space represented in different ways (  or   or just spaces). Nonetheless it was trivial to write a regular expression to identify the beginning of each section. (The beginning of one section is the end of the previous section.) But now I want to use lxml to get the text out. My thought is that I have really no choice but to walk along my string to find the close tag for the element that encloses the text I am using to find the relevant section. That is here is one example where the element holding the Chapter name is a div <div style="DISPLAY: block; MARGIN-LEFT: 0pt; TEXT-INDENT: 0pt; MARGIN-RIGHT: 0pt" align="left"><font style="DISPLAY: inline; FONT-WEIGHT: bold; FONT-SIZE: 10pt; FONT-FAMILY: Times New Roman">Chapter 1.&#160;&#160;&#160;Our Beginnings.</font></div> So I am imagining that I would begin at the location where I found the match for chapter 1 and set up a regular expressions to find the next </div|</td|</p|</h1 . . . So at this point I have identified the type of element holding my chapter heading I can use the same logic to find all of the text that is within that element that is set up a regular expression to help me mark from >Chapter 1.&#160;&#160;&#160;Our Beginnings.< So I have identified where my Chapter 1 begins I can do the same for chapter 2 (which is where Chapter 1 ends) Now I am imagining that I am going to snip the document beginning at the opening of the element that I identified as the element the indicates where chapter 1 begins and ending just before the opening of the element that I identified as the element that indicates where Chapter 2 begins. The string that I have identified will then be fed to lxml to use its power to get the content. I am going to all of this trouble because I have read over and over - never use a regular expression to extract content from html documents and I have not hit on a way to be as accurate with lxml to identify the starting and ending locations for the text I want to extract. For example, I can never be certain that the subtitle of Chapter 1 is Our Beginnings it could be Our Red Canary. Let me say that I spent two solid days trying with lxml to be confident that I had the beginning and ending elements and I could only be accurate <60% of the time but a very short regular expression has given me better than 95% success. I have a tendency to make things more complicated than necessary so I am wondering if anyone has seen or solved a similar problems and if they had an approach (not the details mind you) that they would like to offer.

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  • How can I match at the beginning of any line, including the first, with a Perl regex?

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)? EDIT: OK, it seems that the file has BOM information (3 chars) at the beginning and that's what's messing me up. Any way to get ^ to match anyway? EDIT: So in the end it works (as long as there's no BOM), but now it seems that the Perl documentation is wrong, since it says "after any newline"

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  • Help with Perl Regex Recursive Replace One Liner? Replace MySQL comments '--' with '#'

    - by NJTechie
    I have various SQL files with '--' comments and we migrated to the latest version of MySQL and it hates these comments. I want to replace -- with #. I am looking for a recursive, inplace replace one-liner. This is what I have : perl -p -i -e 's/--/# /g' `fgrep -- -- * ` A sample .sql file : use myDB; --did you get an error I get the following error : Unrecognized switch: --did (-h will show valid options). p.s : fgrep skipping 2 dashes was just discussed here if you are interested. Any help is appreciated.

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  • How to validate a domain name using Regex & Php?

    - by David
    Hi, I want a solution to validate only domain names not full urls, The following example is what i'm looking for: domain.com -> true domain.net/org/biz... -> true domain.co.uk -> true sub.domain.com -> true domain.com/folder -> false domµ*$ain.com -> false Thank you

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  • Can I improve this regex check for valid domain names?

    - by Josh
    So, I have been working on this domain name regular expression. So far, it seems to pick up domain names with SLDs and TLDs (with the optional ccTLD), but there is duplication of the TLD listing. Can this be refactored any further? params[:domain_name].downcase.strip.match(/^[a-z0-9\-]{2,63} \.((a[cdefgilmnoqrstuwxz]|aero|arpa)|(b[abdefghijmnorstvwyz]|biz)| (c[acdfghiklmnorsuvxyz]|cat|com|coop)|d[ejkmoz]|(e[ceghrstu]|edu)|f[ijkmor]| (g[abdefghilmnpqrstuwy]|gov)|h[kmnrtu]|(i[delmnoqrst]|info|int)| (j[emop]|jobs)|k[eghimnprwyz]|l[abcikrstuvy]| (m[acdghklmnopqrstuvwxyz]|me|mil|mobi|museum)|(n[acefgilopruz]|name|net)|(om|org)| (p[aefghklmnrstwy]|pro)|qa|r[eouw]|s[abcdeghijklmnortvyz]| (t[cdfghjklmnoprtvwz]|travel)|u[agkmsyz]|v[aceginu]|w[fs]|y[etu]|z[amw]) (\.((a[cdefgilmnoqrstuwxz]|aero|arpa)|(b[abdefghijmnorstvwyz]|biz)| (c[acdfghiklmnorsuvxyz]|cat|com|coop)|d[ejkmoz]|(e[ceghrstu]|edu)|f[ijkmor]| (g[abdefghilmnpqrstuwy]|gov)|h[kmnrtu]|(i[delmnoqrst]|info|int)| (j[emop]|jobs)|k[eghimnprwyz]|l[abcikrstuvy]| m[acdghklmnopqrstuvwxyz]|mil|mobi|museum)| (n[acefgilopruz]|name|net)|(om|org)| (p[aefghklmnrstwy]|pro)|qa|r[eouw]|s[abcdeghijklmnortvyz]| (t[cdfghjklmnoprtvwz]|travel)|u[agkmsyz]|v[aceginu]|w[fs]|y[etu]|z[amw]))?$/)

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  • .NET Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program:

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  • How to extract part of the path and the ending file name with Regex?

    - by brasofilo
    I need to build an associative array with the plugin name and the language file it uses in the following sequence: /whatever/path/length/public_html/wp-content/plugins/adminimize/languages/adminimize-en_US.mo /whatever/path/length/public_html/wp-content/plugins/audio-tube/lang/atp-en_US.mo /whatever/path/length/public_html/wp-content/languages/en_US.mo /whatever/path/length/public_html/wp-content/themes/twentyeleven/languages/en_US.mo Those are the language files WordPress is loading. They are all inside /wp-content/, but with variable server paths. I'm looking only for those inside the plugins folder, grab the plugin folder name and the filename. Hipothetical case in PHP, where reg_extract_* functions are the parts I'm missing: $plugins = array(); foreach( $big_array as $item ) { $folder = reg_extract_folder( $item ); if( 'plugin' == $folder ) { // "folder-name-after-plugins-folder" $plugin_name = reg_extract_pname( $item ); // "ending-mo-file.mo" $file_name = reg_extract_fname( $item ); $plugins[] = array( 'name' => $plugin_name, 'file' => $file_name ); } } [update] Ok, so I was missing quite a basic function, pathinfo... :/ No problem to detect if /plugins/ is contained in the array. But what about the plugin folder name?

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