Search Results

Search found 19600 results on 784 pages for 'chris long'.

Page 52/784 | < Previous Page | 48 49 50 51 52 53 54 55 56 57 58 59  | Next Page >

  • Where can I find a legal "permission to work on open source" document?

    - by Nathan Long
    One of the things I really like about my current job is that we developers are encouraged to make open source contributions. However, this encouragement has always been verbal. I've read some horror stories about developers having their open-source work legally claimed by their employer. I'd be more comfortable if we had something in writing from my employer saying that contributions are allowed and not owned by the company. Understanding that you are not lawyers, does anyone know where to find a boilerplate document to this effect?

    Read the article

  • Proper policy for user setup

    - by Dave Long
    I am still fairly new to linux hosting and am currently working on some policies for our production ubuntu servers. The servers are public facing webservers with ssh access from the public network and database servers with ssh access from the internal private network. We are a small hosting company so in the past with windows servers we used one user account and one password that each of us used internally. Anyone outside of the company who needed to access the server for FTP or anything else had their own user account. Is that okay to do in the linux world, or would most people recommend using individual accounts for each person who needs to access the server?

    Read the article

  • how to fix it =.= "Third party sources disabled"

    - by Long Pham
    When i tried to upgrade to 13.10, it was appearing on the screen while preparing to update "Third party sources disabled Some third party entries in your sources.list were disabled. You can re-enable them after the upgrade with the 'software-properties' tool or your package manager." After that it was on: W:Failed to fetch bzip2:/var/lib/apt/lists/partial/archive.ubuntu.com_ubuntu_dists_saucy_universe_source_Sources Hash Sum mismatch , E:Some index files failed to download. They have been ignored, or old ones used instead.

    Read the article

  • How to view files from host? (running inside VMWare Fusion)

    - by Dave Long
    I have just finished moving my development server into a Ubuntu 10.04 Server VM in VMWare Fusion 3. I have all of my mysql and tomcat stuff running and am now trying to connect to my actual site files which are stored on my mac under /{User Root}/Workspace/ColdFusion/. I know that normally you should be able to setup a shared folder in VMWare and find it under /mnt/hgfs/{Share Name}, but I can't find it. I am not sure if I have to manually mount it or what.

    Read the article

  • Can I minify Javascript that requires copyright notice?

    - by Nathan Long
    I guess this is actually a legal question, but it relates to software. I'm about to include a JS plugin in a project. The comments include: Redistributions of source code must retain the above copyright notice, this list of conditions and the following disclaimer. * Redistributions in binary form must reproduce the above copyright notice, this list of conditions and the following disclaimer in the documentation and/or other materials provided with the distribution. Is using this in my web site "redistribution?" If I minify this to conserve bandwidth, I assume it will strip all comments. If the answer to #1 is yes, doesn't that imply I'm legally not allowed to minify it? (That would stink, since I was planning to auto-minify all JS as part of the deploy process.)

    Read the article

  • questions on a particular algorithm

    - by paul smith
    Upon searching for a fast primr algorithm, I stumbled upon this: public static boolean isP(long n) { if (n==2 || n==3) return true; if ((n&0x1)==0 || n%3==0 || n<2) return false; long root=(long)Math.sqrt(n)+1L; // we check just numbers of the form 6*k+1 and 6*k-1 for (long k=6;k<=root;k+=6) { if (n%(k-1)==0) return false; if (n%(k+1)==0) return false; } return true; } My questions are: Why is long being used everywhere instead of int? Because with a long type the argument could be much larger than Integer.MAX thus making the method more flexible? In the second 'if', is n&0x1 the same as n%2? If so why didn't the author just use n%2? To me it's more readable. The line that sets the 'root' variable, why add the 1L? What is the run-time complexity? Is it O(sqrt(n/6)) or O(sqrt(n)/6)? Or would we just say O(n)?

    Read the article

  • Debugging OpenOffice crashes

    - by JD Long
    This is partly an OpenOffice question and partly a Ubuntu question. I'm running OpenOffice 3.2.0 and Ubuntu 10.04. I get frequent crashes of OO, especially the Calc app, although I get crashes in the word processor as well. They are very abrupt and accompanies by no warning or error message. I'm just typing away and then the app is gone. Sometimes I even end up thinking I'm typing in OO and discover that OO has crashed and I'm typing in whatever application was under OO. However, I can't reproduce these crashes on demand. They seem random. I can open the same file and do the same exact thing but it does not crash. In Ubuntu how do I trace, track, or diagnose these types of crashes? Is there software I can invoke to help diagnose? Can I start OO from a command prompt with debugging of some sort enabled? Note: if someone could add the tag OpenOffice, I would appreciate it

    Read the article

  • How do I know if I'm getting the most out of my video card?

    - by b.long
    My computer at home is a bit lacking, so I want to make sure I'm getting the most out of it while I can. Generally speaking, here are the specs: 4GB Memory AMD Athlon(tm) 64 X2 Dual Core Processor 5200+ × 2 64-bit Ubuntu The terminal shows me the following: me@home:~$ uname -a Linux home 3.0.0-17-generic #30-Ubuntu SMP Thu Mar 8 20:45:39 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux me@home:~$ lspci | grep VGA 01:00.0 VGA compatible controller: ATI Technologies Inc RV380 [Radeon X600 (PCIE)] me@home:~$ sudo lshw -C video *-display:0 description: VGA compatible controller product: RV380 [Radeon X600 (PCIE)] vendor: ATI Technologies Inc physical id: 0 bus info: pci@0000:01:00.0 version: 00 width: 32 bits clock: 33MHz capabilities: pm pciexpress msi vga_controller bus_master cap_list rom configuration: driver=radeon latency=0 resources: irq:44 memory:e0000000-efffffff ioport:ac00(size=256) memory:fdef0000-fdefffff memory:fdec0000-fdedffff *-display:1 UNCLAIMED description: Display controller product: RV380 [Radeon X600] vendor: ATI Technologies Inc physical id: 0.1 bus info: pci@0000:01:00.1 version: 00 width: 32 bits clock: 33MHz capabilities: pm pciexpress bus_master cap_list configuration: latency=0 resources: memory:fdee0000-fdeeffff me@home:~$ lspci -nn | grep VGA 01:00.0 VGA compatible controller [0300]: ATI Technologies Inc RV380 [Radeon X600 (PCIE)] [1002:5b62] The additional drivers menu in System Settings shows me nothing useful and my attempt at installing ATI's Catalyst Control center (drivers that came with the video card) failed. I believe the latest version of Ubuntu at the time was 9.x. What should I do? Install an old version of Ubuntu 9? Use some alternative driver? UPDATE: I might try my hand at a bit from this answer next: "Installing Catalyst Manually (from AMD/ATI's site)" . From a terminal, fgl_glxgears returns *"fgl_glxgears: command not found"*. Any thoughts?

    Read the article

  • Installing 10.04 server on HP xw9400 Workstation with RAID 5

    - by Dave Long
    I have a workstation that was given to me that is a friggen powerhouse, so I figured I would set it up as my development and demo server. This is my first experience installing Ubuntu onto a RAID array and so far it has not been a fun one. I have been following the Advanced Installation guide for installing Ubuntu 10.04 server, and it says that there will be an option on the Partition Disks screen to manually create the partitions, but the only options I have are: Configure iSCSI volumes Undo changes to partitions Finish partitioning and write changes to disk Just before I got to that screen I got a message that said: One or more drives containing Serial ATA RAID configurations have been found. Do you wish to activate these RAID devices? It doesn't matter whether I answer yes or no to that, I still get the same Partition Disks screen. When I try to select Finish partitioning and write changes to disk I just get the No root file system error. Has anyone else experienced this, and how do I get past it? Can I not run Ubuntu on this machine?

    Read the article

  • Lost connectivity after configuring multiple network adapters on separate networks

    - by Dave Long
    I am trying to setup an Ubuntu hosting server, currently just for development, and the server has two NICs, each sitting on a different network. eth0 is on 192.168.200.* and eth1 is on 192.168.101.* and each one has a static IP. eth0 is the public facing NIC card and eth1 is strictly for internal access to the server. I initially only setup eth0 and added the eth1 card when I needed it. eth0 was working find until I added eth1, now, can't get any connectivity on eth0 unless I pull eth1 out of the box. The configuration on each system is as follows: auto eth0 iface eth0 inet static address 192.168.200.94 netmask 255.255.255.0 network 192.168.200.0 broadcast 192.168.200.255 gateway 192.168.200.253 auto eth1 iface eth1 inet static address 192.168.101.64 netmask 255.255.255.0 network 192.168.101.0 broadcast 192.168.101.255 gateway 192.168.101.254 Again eth0 worked fine until I added eth1. I have seen this happen with Windows servers if you have a Default Gateway setup for both NICs, but I am not sure if this works the same on Ubuntu. My resolv.conf file looks like so: nameserver 192.168.101.59 nameserver 192.168.101.58 domain domain.local search domain.local Per request here is the Routing table 192.168.101.0 * 255.255.255.0 U 0 0 0 eth1 192.168.200.0 * 255.255.255.0 U 0 0 0 eth0 default 192.168.101.254 0.0.0.0 UG 100 0 0 eth1 default 192.168.200.253 0.0.0.0 UG 100 0 0 eth0

    Read the article

  • Call DB Stored Procedure using @NamedStoredProcedureQuery Injection

    - by anwilson
    Oracle Database Stored Procedure can be called from EJB business layer to perform complex DB specific operations. This approach will avoid overhead from frequent network hits which could impact end-user result. DB Stored Procedure can be invoked from EJB Session Bean business logic using org.eclipse.persistence.queries.StoredProcedureCall API. Using this approach requires more coding to handle the Session and Arguments of the Stored Procedure, thereby increasing effort on maintenance. EJB 3.0 introduces @NamedStoredProcedureQuery Injection to call Database Stored Procedure as NamedQueries. This blog will take you through the steps to call Oracle Database Stored Procedure using @NamedStoredProcedureQuery.EMP_SAL_INCREMENT procedure available in HR schema will be used in this sample.Create Entity from EMPLOYEES table.Add @NamedStoredProcedureQuery above @NamedQueries to Employees.java with definition as given below - @NamedStoredProcedureQuery(name="Employees.increaseEmpSal", procedureName = "EMP_SAL_INCREMENT", resultClass=void.class, resultSetMapping = "", returnsResultSet = false, parameters = { @StoredProcedureParameter(name = "EMP_ID", queryParameter = "EMPID"), @StoredProcedureParameter(name = "SAL_INCR", queryParameter = "SALINCR")} ) Observe how Stored Procedure's arguments are handled easily in  @NamedStoredProcedureQuery using @StoredProcedureParameter.Expose Entity Bean by creating a Session Facade.Business method need to be added to Session Bean to access the Stored Procedure exposed as NamedQuery. public void salaryRaise(Long empId, Long salIncrease) throws Exception { try{ Query query = em.createNamedQuery("Employees.increaseEmpSal"); query.setParameter("EMPID", empId); query.setParameter("SALINCR", salIncrease); query.executeUpdate(); } catch(Exception ex){ throw ex; } } Expose business method through Session Bean Remote Interface. void salaryRaise(Long empId, Long salIncrease) throws Exception; Session Bean Client is required to invoke the method exposed through remote interface.Call exposed method in Session Bean Client main method. final Context context = getInitialContext(); SessionEJB sessionEJB = (SessionEJB)context.lookup("Your-JNDI-lookup"); sessionEJB.salaryRaise(new Long(200), new Long(1000)); Deploy Session BeanRun Session Bean Client.Salary of Employee with Id 200 will be increased by 1000.

    Read the article

  • Disable automatic starting of sshd?

    - by b.long
    Simple question here; what's the correct way to stop the sshd service from starting when the OS boots ? I'm not sure if this answer is correct, so I'm hoping some guru(s) can help me out! What I'd like is a configuration that (after boot) allows me to start the service using sudo service ssh start when necessary. Version info: me@home:~$ ssh -V OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 me@home:~$ lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 12.04.1 LTS Release: 12.04 Codename: precise

    Read the article

  • Files in /home deleted

    - by long-time user....2006
    In the most specific, unemotional terms: Reinstalled os, using 11.10(1 month after release to skip initial issues that usually crop up). Configured system to my specifications(just ways of organizing config files, etc). Log out Log back in after after an hour or so...to find my home directory obliterated and just a few skeleton files existing. think oh well, try again (this has happened before with an install for reasons I've never been able to pinpoint, usually around install time with some sort of update but its never been a major recurring issue) same thing happens I thought something was awry, so I reinstalled again (another 20 minutes, meh) Set up system, arranged home directory a bit differently thinking maybe I tread on something I shouldn't have. log out, come back --- the same thing. Most of the directories I added were deleted (e.g. .xmonad which links to xmonad.hs in my portable config directory) tl;dr every change I make in my home directory gets deleted. The emotional part: UNACCEPTABLE. I need to configure my system the way I want, not get punched in the face everytime I make a change. I'll willingly fill in details as needed, this was just a start to see if anyone can help, I've found no trace of this issue in a search.

    Read the article

  • C# HttpListener without using netsh to register a URI

    - by Chris T
    My application uses a small webserver to server up some files and have a web interface for administration remotely. Right now the user has to use netsh to register the URI like so netsh http add urlacl url=http://+:1233/ user=Chris-PC\Chris Which is no fun for the average user. I'd like the program to be able to listen on any port specified by the user from my program without the end-user needing to using command prompt. Is there anyway to accomplish this short of just using Process.Start and running command prompt myself?

    Read the article

  • how do i load a csv file in rails from a migrate usiing load data local infile ?

    - by Chris Drappier
    Hi All, I have my csv file in my public folder, and i'm trying to load it from a migration, but I get a file not found error using this script : ActiveRecord::Base.connection.execute( "load data local infile '#{RAILS_ROOT}/public/muds_variables.csv' into table muds_variables " + "fields terminated by ',' " + "lines terminated by '\n' " + "(variable_name, definition)") I've checked and re-checked the file path, and that's definitely where it lives, I've also tried it just using the file name without any of the path, and a few other combos, but I can't make it work :(. can anyone help me out with this? here's the error : Mysql::Error: File '/home/chris/rails_projects/muds/public/muds_variables.csv' not found (Errcode: 2): load data local infile '/home/chris/rails_projects/muds/public/muds_variables.csv' into table muds_variables fields terminated by ',' lines terminated by ' ' (variable_name, definition) -C

    Read the article

  • Regex Problem in PHP

    - by Chris
    I'm attempting to utilize the following Regex pattern: $regex = '/Name: [a-zA-Z ]*] [0-9]/'; When testing it in Rubular, it works fine, but when using PHP the expression never returns true, even when it should. Incidentally, if I remove the "[0-9]" part, it works fine. Is there some difference in PHP's regex syntax that I'm overlooking? Edit: I'm looking for the characters "Name:" then a name containing any number of letters or spaces, then a "]", then a space, then a single number. So "Name: Chris] 5" would return true and "Name: Chris] [lorem ipsum]" should return false. I also tried escaping the second bracket "\[" but this did not fix the problem.

    Read the article

  • How to get items that are and are not in a list

    - by Chris
    I have an IEnumerable, listOfOnes, and an IEnumerable, listOfTwos. Assuming that I can compare objects of V against objects of T, I'd like to find which items are in listOfOnes but, not in listOfTwos. And vice versa. ex: var listOfOnes = new List<One> { new One { name = "chris", type = "user" }, new One { name = "foo", type = "group" }, new One { name = "john", type = "user" }, }; var listOfTwos = new[] { new Two { name = "chris", type = "user" }, new Two { name = "john", type = "user" }, new Two { name = "the Steves", type = "group" } }; var notInTwos; //= listOfOnes.FindDifferences(listOfTwos); //find all objects not in listOfTwos. Should find 'foo'. var notInOnes; //= listOfTwos.FindDifferences(listOfOnes) //find all objects not in listOfOnes. Should find 'the Steves'.

    Read the article

  • "is not abstact and does not override abstract method."

    - by Chris Bolton
    So I'm pretty new to android development and have been trying to piece together some code bits. Here's what I have so far: package com.teslaprime.prirt; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.ArrayAdapter; import android.widget.Button; import android.widget.EditText; import android.widget.ListView; import android.widget.AdapterView.OnItemClickListener; import java.util.ArrayList; import java.util.List; public class TaskList extends Activity { List<Task> model = new ArrayList<Task>(); ArrayAdapter<Task> adapter = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Button add = (Button) findViewById(R.id.add); add.setOnClickListener(onAdd); ListView list = (ListView) findViewById(R.id.tasks); adapter = new ArrayAdapter<Task>(this,android.R.layout.simple_list_item_1,model); list.setAdapter(adapter); list.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(View v, int position, long id) { adapter.remove(position); } });} private View.OnClickListener onAdd = new View.OnClickListener() { public void onClick(View v) { Task task = new Task(); EditText name = (EditText) findViewById(R.id.taskEntry); task.name = name.getText().toString(); adapter.add(task); } }; } and here are the errors I'm getting: compile: [javac] /opt/android-sdk/tools/ant/main_rules.xml:384: warning: 'includeantruntime' was not set, defaulting to build.sysclasspath=last; set to false for repeatable builds [javac] Compiling 2 source files to /home/chris-kun/code/priRT/bin/classes [javac] /home/chris-kun/code/priRT/src/com/teslaprime/prirt/TaskList.java:30: <anonymous com.teslaprime.prirt.TaskList$1> is not abstract and does not override abstract method onItemClick(android.widget.AdapterView<?>,android.view.View,int,long) in android.widget.AdapterView.OnItemClickListener [javac] list.setOnItemClickListener(new OnItemClickListener() { [javac] ^ [javac] /home/chris-kun/code/priRT/src/com/teslaprime/prirt/TaskList.java:32: remove(com.teslaprime.prirt.Task) in android.widget.ArrayAdapter<com.teslaprime.prirt.Task> cannot be applied to (int) [javac] adapter.remove(position); [javac] ^ [javac] 2 errors BUILD FAILED /opt/android-sdk/tools/ant/main_rules.xml:384: Compile failed; see the compiler error output for details. Total time: 2 seconds any ideas?

    Read the article

  • Factor Clojure code setting many different fields in a Java object

    - by chris
    How do I factor code setting many different fields in a Java object? I would like to factor (set! (. employee name) "Chris") (set! (. employee age) 100) (set! (. employee salary) 5000) to (doseq [field '((name "Chris") (age 100) (salary 5000))] (set! (. employee (first field)) (second field))) However this won't work because the period is a macro, and tries to evaluate (first field) literally. By the way, I understand that setting fields is not good practice. I need to inter-operate with legacy code.

    Read the article

  • HTG Explains: Are You Using IPv6 Yet? Should You Even Care?

    - by Chris Hoffman
    IPv6 is extremely important for the long-term health of the Internet. But is your Internet service provider providing IPv6 connectivity yet? Does your home network support it? Should you even care if you’re using IPv6 yet? Switching from IPv4 to IPv6 will give the Internet a much larger pool of IP addresses. It should also allow every device to have its own public IP address, rather than be hidden behind a NAT router. IPv6 is Important Long-Term IPv6 is very important for the long-term health of the Internet. There are only about 3.7 billion public IPv4 addresses. This may sound like a lot, but it isn’t even one IP address for each person on the planet. Considering people have more and more Internet-connected devices — everything from light bulbs to thermostats are starting to become network-connected — the lack of IP addresses is already proving to be a serious problem. This may not affect those of us in well-off developed countries just yet, but developing countries are already running out of IPv4 addresses. So, if you work at an Internet service provider, manage Internet-connected servers, or develop software or hardware — yes, you should care about IPv6! You should be deploying it and ensuring your software and hardware works properly with it. It’s important to prepare for the future before the current IPv4 situation becomes completely unworkable. But, if you’re just typical user or even a typical geek with a home Internet connection and a home network, should you really care about your home network just yet? Probably not. What You Need to Use IPv6 To use IPv6, you’ll need three things: An IPv6-Compatible Operating System: Your operating system’s software must be capable of using IPv6. All modern desktop operating systems should be compatible — Windows Vista and newer versions of Windows, as well as modern versions of Mac OS X and Linux. Windows XP doesn’t have IPv6 support installed by default, but you shouldn’t be using Windows XP anymore, anyway. A Router With IPv6 Support: Many — maybe even most — consumer routers in the wild don’t support IPv6. Check your router’s specifications details to see if it supports IPv6 if you’re curious. If you’re going to buy a new router, you’ll probably want to get one with IPv6 support to future-proof yourself. If you don’t have an IPv6-enabled router yet, you don’t need to buy a new one just to get it. An ISP With IPv6 Enabled:  Your Internet service provider must also have IPv6 set up on their end. Even if you have modern software and hardware on your end, your ISP has to provide an IPv6 connection for you to use it. IPv6 is rolling out steadily, but slowly — there’s a good chance your ISP hasn’t enabled it for you yet. How to Tell If You’re Using IPv6 The easiest way to tell if you have IPv6 connectivity is to visit a website like testmyipv6.com. This website allows you to connect to it in different ways — click the links near the top to see if you can connect to the website via different types of connections. If you can’t connect via IPv6, it’s either because your operating system is too old (unlikely), your router doesn’t support IPv6 (very possible), or because your ISP hasn’t enabled it for you yet (very likely). Now What? If you can connect to the test website above via IPv6, congratulations! Everything is working as it should. Your ISP is doing a good job of rolling out IPv6 rather than dragging its feet. There’s a good chance you won’t have IPv6 working properly, however. So what should you do about this — should you head to Amazon and buy a new IPv6-enabled router or switch to an ISP that offers IPv6? Should you use a “tunnel broker,” as the test site recommends, to tunnel into IPv6 via your IPv4 connection? Well, probably not. Typical users shouldn’t have to worry about this yet. Connecting to the Internet via IPv6 shouldn’t be perceptibly faster, for example. It’s important for operating system vendors, hardware companies, and Internet service providers to prepare for the future and get IPv6 working, but you don’t need to worry about this on your home network. IPv6 is all about future-proofing. You shouldn’t be racing to implement this at home yet or worrying about it too much — but, when you need to buy a new router, try to buy one that supports IPv6. Image Credit: Adobe of Chaos on Flickr, hisperati on Flickr, Vox Efx on Flickr     

    Read the article

  • Creating an Objective-C++ Static Library in Xcode

    - by helixed
    So I've developed an engine for the iPhone with which I'd like to build a couple different games. Rather than copy and paste the files for the engine inside of each game's project directory, I'd a way to link to the engine from each game, so if I need to make a change to it I only have to do so once. After reeding around a little bit, it seems like static libraries are the best way to do this on the iPhone. I created a new project called Skeleton and copied all of my engine files over to it. I used this guide to create a static library, and I imported the library into a project called Chooser. However, when I tried to compile the project, Xcode started complaining about some C++ data structures I included in a file called ControlScene.mm. Here's my build errors: "operator delete(void*)", referenced from: -[ControlScene dealloc] in libSkeleton.a(ControlScene.o) -[ControlScene init] in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t>::deallocate(operation_t*, unsigned long)in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t*>::deallocate(operation_t**, unsigned long)in libSkeleton.a(ControlScene.o) "operator new(unsigned long)", referenced from: -[ControlScene init] in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t*>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) "std::__throw_bad_alloc()", referenced from: __gnu_cxx::new_allocator<operation_t*>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) "___cxa_rethrow", referenced from: std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_create_nodes(operation_t**, operation_t**)in libSkeleton.a(ControlScene.o) std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_initialize_map(unsigned long)in libSkeleton.a(ControlScene.o) "___cxa_end_catch", referenced from: std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_create_nodes(operation_t**, operation_t**)in libSkeleton.a(ControlScene.o) std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_initialize_map(unsigned long)in libSkeleton.a(ControlScene.o) "___gxx_personality_v0", referenced from: ___gxx_personality_v0$non_lazy_ptr in libSkeleton.a(ControlScene.o) ___gxx_personality_v0$non_lazy_ptr in libSkeleton.a(MenuLayer.o) "___cxa_begin_catch", referenced from: std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_create_nodes(operation_t**, operation_t**)in libSkeleton.a(ControlScene.o) std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_initialize_map(unsigned long)in libSkeleton.a(ControlScene.o) ld: symbol(s) not found collect2: ld returned 1 exit status If anybody could offer some insight as to why these problems are occuring, I'd appreciate it. Thanks, helixed

    Read the article

  • Adding a valuetype to IDL, compile and it fails with "No factory found"

    - by jim
    I can't figure out why the client keeps complaining about the not finding the factory method. I've tried the IDL with and without the "factory" keyword and that didn't change the behavior. The SDMGeoVT IDL matches other objects used (which run successfully). The SDMGeoVT classes generated match other generated classes in regards to inheritance and methods. The IDL is as follows; The idlj compiler runs w/o error. I implement the function on the server and I see the server code run and serialize the object over the wire (the server code runs fine). The client bombs with the following stack trace (the first couple of lines is from the jacORB library). I've created a small app just to compile and test the code (ArrayClient & ArrayServer). The base app (from the jacORB demo) works fine. I've tried using the base class OFBaseVT and a single object (SDMGeoVT vs the list return) and have the same issue. 2010-05-27 15:37:11.813 FINE read GIOP message of size 100 from ClientGIOPConnection to 127.0.0.1:47030 (1e4853f) 2010-05-27 15:37:11.813 FINE read GIOP message of size 100 from ClientGIOPConnection to 127.0.0.1:47030 (1e4853f) org.omg.CORBA.MARSHAL: No factory found for: IDL:pl/SDMGeoVT:1.0 at org.jacorb.orb.CDRInputStream.read_untyped_value(CDRInputStream.java:2906) at org.jacorb.orb.CDRInputStream.read_typed_value(CDRInputStream.java:3082) at org.jacorb.orb.CDRInputStream.read_value(CDRInputStream.java:2679) at com.helloworld.pl.SDMGeoVTHelper.read(SDMGeoVTHelper.java:106) at com.helloworld.pl.SDMGeoVTListHelper.read(SDMGeoVTListHelper.java:51) at com.helloworld.pl._PLManagerIFStub.getSDMGeos(_PLManagerIFStub.java:28) at com.helloworld.ArrayClient.<init>(ArrayClient.java:40) at com.helloworld.ArrayClient.main(ArrayClient.java:125) valuetype SDMGeoVT : common::OFBaseVT{ private string sdmName; private string zip; private string atz; private long long primaryDeptId; private string deptName; factory instance(in string name,in string ZIP,in string ATZ,in long long primaryDeptId,in string deptName,in string name); string getZIP(); void setZIP(in string ZIP); string getATZ(); void setATZ(in string ATZ); long long getPrimaryDeptId(); void setPrimaryDeptId(in long long primaryDeptId); string getDeptName(); void setDeptName(in string deptName); }; typedef sequence<SDMGeoVT> SDMGeoVTList; interface PLManagerIF : PublicManagerIF { pl::SDMGeoVTList getSDMGeos(in framework::ITransactionHandle tHandle, in long long productionLocationId); };

    Read the article

  • How to return a single variable from a CUDA kernel function?

    - by Pooya
    I have a CUDA search function which calculate one single variable. How can I return it back. global void G_SearchByNameID(node* Node, long nodeCount, long start,char* dest, long answer){ answer = 2; } cudaMemcpy(h_answer, d_answer, sizeof(long), cudaMemcpyDeviceToHost); cudaFree(d_answer); for both of these lines I get this error: error: argument of type "long" is incompatible with parameter of type "const void *"

    Read the article

  • Call/Ret in x86 assembly embedded in C++

    - by SP658
    This is probably trivial, but for some reason I can't it to work. Its supposed to be a simple function that changes the last byte of a dword to 'AA' (10101010), but nothing happens when I call the function. It just returns my original dword __declspec(naked) long function(unsigned long inputDWord, unsigned long *outputDWord) { _asm{ mov ebx, dword ptr[esp+4] push ebx call SET_AA pop ebx mov eax, dword ptr[esp+8] mov dword ptr[eax], ebx } } __declspec(naked) unsigned long SET_AA( unsigned long inputDWord ) { __asm{ mov eax, [esp+4] mov al, 0xAA ret } }

    Read the article

< Previous Page | 48 49 50 51 52 53 54 55 56 57 58 59  | Next Page >