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  • Sorting arrays in java

    - by user360706
    Write a static method in Java : public static void sortByFour (int[] arr) That receives as a paramater an array full of non-negative numbers (zero or positive) and sorts the array in the following way : In the beginning of the array all the numbers that devide by four without a remainder will appear. After them all the numbers in the array that devide by 4 with a remainder of 1 will appear. After them all the numbers in the array that devide by 4 with a remainder of 2 will appear. In the end of the array all the rest numbers (those who divide by 4 with the remainder 3) will appear. (The order of the numbers in each group doesn't matter) The method must be the most efficient it can. This is what I wrote but unfortunately it doesn't work well... :( public static void swap( int[] arr, int left, int right ) { int temp = arr[left]; arr[left] = arr[right]; arr[right] = temp; } public static void sortByFour( int[] arr ) { int left = 0; int right = ( arr.length - 1 ); int mid = ( arr.length / 2 ); while ( left < right ) { if ( ( arr[left] % 4 ) > ( arr[right] % 4 ) ) { swap( arr, left, right ); right--; } if ( ( arr[left] % 4 ) == ( arr[right] % 4 ) ) left++; else left++; } } Can someone please help me by fixing my code so that it will work well or rewriting it?

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  • Efficient Multiplication of Varying-Length #s [Conceptual]

    - by Milan Patel
    Write the pseudocode of an algorithm that takes in two arbitrary length numbers (provided as strings), and computes the product of these numbers. Use an efficient procedure for multiplication of large numbers of arbitrary length. Analyze the efficiency of your algorithm. I decided to take the (semi) easy way out and use the Russian Peasant Algorithm. It works like this: a * b = a/2 * 2b if a is even a * b = (a-1)/2 * 2b + a if a is odd My pseudocode is: rpa(x, y){ if x is 1 return y if x is even return rpa(x/2, 2y) if x is odd return rpa((x-1)/2, 2y) + y } I have 3 questions: Is this efficient for arbitrary length numbers? I implemented it in C and tried varying length numbers. The run-time in was near-instant in all cases so it's hard to tell empirically... Can I apply the Master's Theorem to understand the complexity...? a = # subproblems in recursion = 1 (max 1 recursive call across all states) n / b = size of each subproblem = n / 1 - b = 1 (problem doesn't change size...?) f(n^d) = work done outside recursive calls = 1 - d = 0 (the addition when a is odd) a = 1, b^d = 1, a = b^d - complexity is in n^d*log(n) = log(n) this makes sense logically since we are halving the problem at each step, right? What might my professor mean by providing arbitrary length numbers "as strings". Why do that? Many thanks in advance

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  • How do I split ONE array to two separate arrays based on magnitude size and a threshold?

    - by youhaveaBigego
    I have an array which has BIG numbers and small numbers in it. I got it from after running a log from WireShark. It is the total number of Bytes of TCP traffic. But Wireshark does not discriminate(it would actually try, and hence it will tell you the traffic stats of ALL types of traffic, but since This is how the Array look like : @Array=qw(10912980 10924534 10913356 10910304 10920426 10900658 10911266 10912088 10928972 10914718 10920770 10897774 10934258 10882186 10874126 8531 8217 3876 8147 8019 68157 3432 3350 3338 3280 3280 7845 7869 3072 3002 2828 8397 1328 1280 1240 1194 1193 1192 1194 6440 1148 1218 4236 1161 1100 1102 1148 1172 6305 1010 5437 3534 4623 4669 3617 4234 959 1121 1121 1075 3122 3076 1020 3030 628 2938 2938 1611 1611 1541 1541 1541 1541 1541 1541 1541 1541 1541 1541 1541 1541 583 370 178) When you look at these this array carefully, one thing is obvious to the human eye. There are really BIG numbers and small numbers. (Basically what I am saying is, there is the 1% class and low income class, no middle class). I want to split the array to two different arrays. That would require me to set a threshold. Array 1 should be ONLY the BIG numbers (10924534-10874126), and array 2 should be the smaller numbers (68157-178). Btw, the array is not sorted. User will NOT input the threshold, and hence should be determined smartly.

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  • How is an array stored in memory?

    - by George
    In an interest to delve deeper into how memory is allocated and stored, I have written an application that can scan memory address space, find a value, and write out a new value. I developed a sample application with the end goal to be able to programatically locate my array, and overwrite it with a new sequence of numbers. In this situation, I created a single dimensional array, with 5 elements, e.g. int[] array = new int[] {8,7,6,5,4}; I ran my application and searched for a sequence of the five numbers above. I was looking for any value that fell between 4 and 8, for a total of 5 numbers in a row. Unforuntately, my the sequential numbers in my array matched hundreds of results, as the numbers 4 through 8, in no particular sequence happened to be next to each other, in memory, in many situations. Is there any way to distinguish that a set of numbers within memory, represents an array, not simply integers that are next to each other? Is there any way of knowing that if I find a certain value, that the matching values proceeding it are that of an array? I would assume that when I declare int[] array, its pointing at the first address of my array, which would provide some kind of meta-data to what existed in the array, e.g. 0x123456789 meta-data, 5 - 32 bit integers 0x123456789 + 32 "8" 0x123456789 + 64 "7" 0x123456789 + 96 "6" 0x123456789 + 128 "5" 0x123456789 + 160 "4" Am I way off base?

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  • Invitation: WebCenter Implementation Specialist Exam Preparation Webcasts

    - by rituchhibber
    Oracle Partner Network would like to invite you to Refresh Courses for WebCenter Content and WebCenter Portal, to help partners to prepare for the WebCenter Implementation Specialist EXAMS.This is a 3 hours intensive refresher partner-only training session, providing attendees with an overview of WebCenter Content and WebCenter Portal functions and related topics. After the refresher part you will be able to take the relevant Implementation Specialist EXAM depending on your personal focus. NOTE: This is only suitable for experienced WebCenter Content or WebCenter Portal practitioners Who should attend?Partner Consultants who want to become an Oracle WebCenter Content or a WebCenter Portal Certified Implementation Specialist or both, that will help them to differentiate themselves in front of customers and support their Companies to become Specialized. Webcast Details: Date Topic Speaker  Web Call Details  Intercall Details  December 14th WebCenter Content RefreshCourse Markus Neubauer, SilburyWebCenter Content Specialized Partner Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249533/1412 Date Topic Speaker Web Call Details Intercall Details January 10th                  WebCenter Portal    Refresh Course                   Yannick Ongena, InfoMentumWebCenter Portal Specialized Partner                     Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249375/1001 Date Topic Speaker Web Call Details Intercall Details February 22nd                WebCenter Content  RefreshCourse Markus Neubauer, SilburyWebCenter Content Specialized Partner    Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around13:30 Conference ID/Key: 9249541/2202 Date Topic Speaker Web Call Details Intercall Details  March 13th                WebCenter Portal   Refresh     Course      Yannick Ongena, InfoMentumWebCenter Portal Specialized Partner    Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249549/1303 Local dial-in numbers can be found here . Next Steps:After the Webcast you will receive the Training material and FREE Vouchers to book and take the: Oracle ECM 11g Certified Implementation Specialist EXAM Oracle WebCenter 11g Essentials EXAM Booking with Voucher can be done on www.pearsonvue.com. Note: FREE Vouchers will be send after attending the webcast.

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  • post row where radio button is checked

    - by ognjenb
    View: <form id="numbers-form" method="post" action="/Numbers/Numbers"> <table id="numbers"> <tr> <th> prvi_br </th> <th> drugi_br </th> <th> treci_br </th> </tr> <% int rb = 1; %> <% foreach (var item in Model) { %> <tr> <td> <%= Html.Encode(item.prvi_br) %> <input type="radio" name="<%= Html.Encode(rb) %>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.prvi_br) %>'/> </td> <td> <%= Html.Encode(item.drugi_br) %> <input type="radio" name="<%= Html.Encode(rb)%>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.drugi_br) %>'/> </td> <td> <%= Html.Encode(item.treci_br) %> <input type="radio" name="<%= Html.Encode(rb)%>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.treci_br) %>'/> </td> </tr> <% rb++; %> <% } %> </table> <p> <input type="submit" value="Save" /> </p> </form> Controller action: [HttpPost] public ActionResult Numbers(int[] rb) { brojevi br = new brojevi(); for (int i = 1; i <= rb.Length; i++) //in this line I have error:Object reference not set to an instance of an object. { br.prvi_br = i; br.drugi_br = i+1; br.treci_br = i+3; } numbers.AddTobrojevi(br); numbers.SaveChanges(); return View(); } I try to post data row in wich radio button is checked but failed, what is wrong??

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  • DexFile.class error in eclipse

    - by ninjasense
    I get this weird error everytime I debug in eclipse. It just seemed to appear one day and I was wondering if anyone else was running int the same problem. It does not affect my app in anyway visibly and does not cause a crash but it is an annoyance while debugging. Here is the full error: // Compiled from DexFile.java (version 1.5 : 49.0, super bit) public final class dalvik.system.DexFile { // Method descriptor #8 (Ljava/io/File;)V // Stack: 3, Locals: 2 public DexFile(java.io.File file) throws java.io.IOException; 0 aload_0 [this] 1 invokespecial java.lang.Object() [1] 4 new java.lang.RuntimeException [2] 7 dup 8 ldc <String "Stub!"> [3] 10 invokespecial java.lang.RuntimeException(java.lang.String) [4] 13 athrow Line numbers: [pc: 0, line: 4] Local variable table: [pc: 0, pc: 14] local: this index: 0 type: dalvik.system.DexFile [pc: 0, pc: 14] local: file index: 1 type: java.io.File // Method descriptor #18 (Ljava/lang/String;)V // Stack: 3, Locals: 2 public DexFile(java.lang.String fileName) throws java.io.IOException; 0 aload_0 [this] 1 invokespecial java.lang.Object() [1] 4 new java.lang.RuntimeException [2] 7 dup 8 ldc <String "Stub!"> [3] 10 invokespecial java.lang.RuntimeException(java.lang.String) [4] 13 athrow Line numbers: [pc: 0, line: 5] Local variable table: [pc: 0, pc: 14] local: this index: 0 type: dalvik.system.DexFile [pc: 0, pc: 14] local: fileName index: 1 type: java.lang.String // Method descriptor #22 (Ljava/lang/String;Ljava/lang/String;I)Ldalvik/system/DexFile; // Stack: 3, Locals: 3 public static dalvik.system.DexFile loadDex(java.lang.String sourcePathName, java.lang.String outputPathName, int flags) throws java.io.IOException; 0 new java.lang.RuntimeException [2] 3 dup 4 ldc <String "Stub!"> [3] 6 invokespecial java.lang.RuntimeException(java.lang.String) [4] 9 athrow Line numbers: [pc: 0, line: 6] Local variable table: [pc: 0, pc: 10] local: sourcePathName index: 0 type: java.lang.String [pc: 0, pc: 10] local: outputPathName index: 1 type: java.lang.String [pc: 0, pc: 10] local: flags index: 2 type: int // Method descriptor #28 ()Ljava/lang/String; // Stack: 3, Locals: 1 public java.lang.String getName(); 0 new java.lang.RuntimeException [2] 3 dup 4 ldc <String "Stub!"> [3] 6 invokespecial java.lang.RuntimeException(java.lang.String) [4] 9 athrow Line numbers: [pc: 0, line: 7] Local variable table: [pc: 0, pc: 10] local: this index: 0 type: dalvik.system.DexFile // Method descriptor #30 ()V // Stack: 3, Locals: 1 public void close() throws java.io.IOException; 0 new java.lang.RuntimeException [2] 3 dup 4 ldc <String "Stub!"> [3] 6 invokespecial java.lang.RuntimeException(java.lang.String) [4] 9 athrow Line numbers: [pc: 0, line: 8] Local variable table: [pc: 0, pc: 10] local: this index: 0 type: dalvik.system.DexFile // Method descriptor #32 (Ljava/lang/String;Ljava/lang/ClassLoader;)Ljava/lang/Class; // Stack: 3, Locals: 3 public java.lang.Class loadClass(java.lang.String name, java.lang.ClassLoader loader); 0 new java.lang.RuntimeException [2] 3 dup 4 ldc <String "Stub!"> [3] 6 invokespecial java.lang.RuntimeException(java.lang.String) [4] 9 athrow Line numbers: [pc: 0, line: 9] Local variable table: [pc: 0, pc: 10] local: this index: 0 type: dalvik.system.DexFile [pc: 0, pc: 10] local: name index: 1 type: java.lang.String [pc: 0, pc: 10] local: loader index: 2 type: java.lang.ClassLoader // Method descriptor #37 ()Ljava/util/Enumeration; // Signature: ()Ljava/util/Enumeration<Ljava/lang/String;>; // Stack: 3, Locals: 1 public java.util.Enumeration entries(); 0 new java.lang.RuntimeException [2] 3 dup 4 ldc <String "Stub!"> [3] 6 invokespecial java.lang.RuntimeException(java.lang.String) [4] 9 athrow Line numbers: [pc: 0, line: 10] Local variable table: [pc: 0, pc: 10] local: this index: 0 type: dalvik.system.DexFile // Method descriptor #30 ()V // Stack: 3, Locals: 1 protected void finalize() throws java.io.IOException; 0 new java.lang.RuntimeException [2] 3 dup 4 ldc <String "Stub!"> [3] 6 invokespecial java.lang.RuntimeException(java.lang.String) [4] 9 athrow Line numbers: [pc: 0, line: 11] Local variable table: [pc: 0, pc: 10] local: this index: 0 type: dalvik.system.DexFile // Method descriptor #42 (Ljava/lang/String;)Z public static native boolean isDexOptNeeded(java.lang.String arg0) throws java.io.FileNotFoundException, java.io.IOException; } Thanks

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  • compile Boost as static Universal binary lib

    - by Albert
    I want to have a static Universal binary lib of Boost. (Preferable the latest stable version, that is 1.43.0, or newer.) I found many Google hits with similar problems and possible solutions. However, most of them seems outdated. Also none of them really worked. Right now, I am trying sudo ./bjam --toolset=darwin --link=static --threading=multi \ --architecture=combined --address-model=32_64 \ --macosx-version=10.4 --macosx-version-min=10.4 \ install That compiles and install fine. However, the produced binaries seems broken. az@ip245 47 (openlierox) %file /usr/local/lib/libboost_signals.a /usr/local/lib/libboost_signals.a: current ar archive random library az@ip245 49 (openlierox) %lipo -info /usr/local/lib/libboost_signals.a input file /usr/local/lib/libboost_signals.a is not a fat file Non-fat file: /usr/local/lib/libboost_signals.a is architecture: x86_64 az@ip245 48 (openlierox) %otool -hv /usr/local/lib/libboost_signals.a Archive : /usr/local/lib/libboost_signals.a /usr/local/lib/libboost_signals.a(trackable.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1536 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(connection.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1776 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(named_slot_map.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1856 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(signal_base.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1776 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(slot.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1616 SUBSECTIONS_VIA_SYMBOLS Any suggestion how to get that correct?

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  • What is the best algorithm for this array-comparison problem?

    - by mark
    What is the most efficient for speed algorithm to solve the following problem? Given 6 arrays, D1,D2,D3,D4,D5 and D6 each containing 6 numbers like: D1[0] = number D2[0] = number ...... D6[0] = number D1[1] = another number D2[1] = another number .... ..... .... ...... .... D1[5] = yet another number .... ...... .... Given a second array ST1, containing 1 number: ST1[0] = 6 Given a third array ans, containing 6 numbers: ans[0] = 3, ans[1] = 4, ans[2] = 5, ......ans[5] = 8 Using as index for the arrays D1,D2,D3,D4,D5 and D6, the number that goes from 0, to the number stored in ST1[0] minus one, in this example 6, so from 0 to 6-1, compare each res array against each D array My algorithm so far is: I tried to keep everything unlooped as much as possible. EML := ST1[0] //number contained in ST1[0] EML1 := 0 //start index for the arrays D While EML1 < EML if D1[ELM1] = ans[0] goto two if D2[ELM1] = ans[0] goto two if D3[ELM1] = ans[0] goto two if D4[ELM1] = ans[0] goto two if D5[ELM1] = ans[0] goto two if D6[ELM1] = ans[0] goto two ELM1 = ELM1 + 1 return 0 //If the ans[0] number is not found in either D1[0-6], D2[0-6].... D6[0-6] return 0 which will then exclude ans[0-6] numbers two: EML1 := 0 start index for arrays Ds While EML1 < EML if D1[ELM1] = ans[1] goto three if D2[ELM1] = ans[1] goto three if D3[ELM1] = ans[1] goto three if D4[ELM1] = ans[1] goto three if D5[ELM1] = ans[1] goto three if D6[ELM1] = ans[1] goto three ELM1 = ELM1 + 1 return 0 //If the ans[1] number is not found in either D1[0-6], D2[0-6].... D6[0-6] return 0 which will then exclude ans[0-6] numbers three: EML1 := 0 start index for arrays Ds While EML1 < EML if D1[ELM1] = ans[2] goto four if D2[ELM1] = ans[2] goto four if D3[ELM1] = ans[2] goto four if D4[ELM1] = ans[2] goto four if D5[ELM1] = ans[2] goto four if D6[ELM1] = ans[2] goto four ELM1 = ELM1 + 1 return 0 //If the ans[2] number is not found in either D1[0-6], D2[0-6].... D6[0-6] return 0 which will then exclude ans[0-6] numbers four: EML1 := 0 start index for arrays Ds While EML1 < EML if D1[ELM1] = ans[3] goto five if D2[ELM1] = ans[3] goto five if D3[ELM1] = ans[3] goto five if D4[ELM1] = ans[3] goto five if D5[ELM1] = ans[3] goto five if D6[ELM1] = ans[3] goto five ELM1 = ELM1 + 1 return 0 //If the ans[3] number is not found in either D1[0-6], D2[0-6].... D6[0-6] return 0 which will then exclude ans[0-6] numbers five: EML1 := 0 start index for arrays Ds While EML1 < EML if D1[ELM1] = ans[4] goto six if D2[ELM1] = ans[4] goto six if D3[ELM1] = ans[4] goto six if D4[ELM1] = ans[4] goto six if D5[ELM1] = ans[4] goto six if D6[ELM1] = ans[4] goto six ELM1 = ELM1 + 1 return 0 //If the ans[4] number is not found in either D1[0-6], D2[0-6].... D6[0-6] return 0 which will then exclude ans[0-6] numbers six: EML1 := 0 start index for arrays Ds While EML1 < EML if D1[ELM1] = ans[5] return 1 ////If the ans[1] number is not found in either D1[0-6]..... if D2[ELM1] = ans[5] return 1 which will then include ans[0-6] numbers return 1 if D3[ELM1] = ans[5] return 1 if D4[ELM1] = ans[5] return 1 if D5[ELM1] = ans[5] return 1 if D6[ELM1] = ans[5] return 1 ELM1 = ELM1 + 1 return 0 As language of choice, it would be pure c

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  • Excel: Conditional Formatting (Highlighting) Values Based on Another Worksheet

    - by ScottSEA
    I have a workbook that has two worksheets. The first worksheet is simply a list of the first 78,498 prime numbers in a single column, A1-A78498. The second worksheet has a grid of numbers from 1 to n. The goal is to highlight the cells with prime numbers in the grid by referencing the prime number values in the other worksheet. Is this possible, and if so, how? edit I have named the column with my prime numbers "PRIMES1T". I would like the formula to work for the entire worksheet, regardless of size, but my excel-fu is extremely weak. If at all possible, I would like to be able to enter the formula in the dialog box for conditional formatting (as below): I have tried =NOT(ISNA(MATCH(A:Z,PRIMES1T,0) (only A-Z, but have to start somewhere) with no luck.

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  • Anything wrong with this function for comparing floats?

    - by Michael Borgwardt
    When my Floating-Point Guide was yesterday published on slashdot, I got a lot of flak for my suggested comparison function, which was indeed inadequate. So I finally did the sensible thing and wrote a test suite to see whether I could get them all to pass. Here is my result so far. And I wonder if this is really as good as one can get with a generic (i.e. not application specific) float comparison function, or whether I still missed some edge cases. import static org.junit.Assert.assertFalse; import static org.junit.Assert.assertTrue; import org.junit.Test; public class NearlyEqualsTest { public static boolean nearlyEqual(float a, float b) { final float epsilon = 0.000001f; final float absA = Math.abs(a); final float absB = Math.abs(b); final float diff = Math.abs(a-b); if (a*b==0) { // a or b or both are zero // relative error is not meaningful here return diff < Float.MIN_VALUE / epsilon; } else { // use relative error return diff / (absA+absB) < epsilon; } } /** Regular large numbers - generally not problematic */ @Test public void big() { assertTrue(nearlyEqual(1000000f, 1000001f)); assertTrue(nearlyEqual(1000001f, 1000000f)); assertFalse(nearlyEqual(10000f, 10001f)); assertFalse(nearlyEqual(10001f, 10000f)); } /** Negative large numbers */ @Test public void bigNeg() { assertTrue(nearlyEqual(-1000000f, -1000001f)); assertTrue(nearlyEqual(-1000001f, -1000000f)); assertFalse(nearlyEqual(-10000f, -10001f)); assertFalse(nearlyEqual(-10001f, -10000f)); } /** Numbers around 1 */ @Test public void mid() { assertTrue(nearlyEqual(1.0000001f, 1.0000002f)); assertTrue(nearlyEqual(1.0000002f, 1.0000001f)); assertFalse(nearlyEqual(1.0002f, 1.0001f)); assertFalse(nearlyEqual(1.0001f, 1.0002f)); } /** Numbers around -1 */ @Test public void midNeg() { assertTrue(nearlyEqual(-1.000001f, -1.000002f)); assertTrue(nearlyEqual(-1.000002f, -1.000001f)); assertFalse(nearlyEqual(-1.0001f, -1.0002f)); assertFalse(nearlyEqual(-1.0002f, -1.0001f)); } /** Numbers between 1 and 0 */ @Test public void small() { assertTrue(nearlyEqual(0.000000001000001f, 0.000000001000002f)); assertTrue(nearlyEqual(0.000000001000002f, 0.000000001000001f)); assertFalse(nearlyEqual(0.000000000001002f, 0.000000000001001f)); assertFalse(nearlyEqual(0.000000000001001f, 0.000000000001002f)); } /** Numbers between -1 and 0 */ @Test public void smallNeg() { assertTrue(nearlyEqual(-0.000000001000001f, -0.000000001000002f)); assertTrue(nearlyEqual(-0.000000001000002f, -0.000000001000001f)); assertFalse(nearlyEqual(-0.000000000001002f, -0.000000000001001f)); assertFalse(nearlyEqual(-0.000000000001001f, -0.000000000001002f)); } /** Comparisons involving zero */ @Test public void zero() { assertTrue(nearlyEqual(0.0f, 0.0f)); assertFalse(nearlyEqual(0.00000001f, 0.0f)); assertFalse(nearlyEqual(0.0f, 0.00000001f)); } /** Comparisons of numbers on opposite sides of 0 */ @Test public void opposite() { assertFalse(nearlyEqual(1.000000001f, -1.0f)); assertFalse(nearlyEqual(-1.0f, 1.000000001f)); assertFalse(nearlyEqual(-1.000000001f, 1.0f)); assertFalse(nearlyEqual(1.0f, -1.000000001f)); assertTrue(nearlyEqual(10000f*Float.MIN_VALUE, -10000f*Float.MIN_VALUE)); } /** * The really tricky part - comparisons of numbers * very close to zero. */ @Test public void ulp() { assertTrue(nearlyEqual(Float.MIN_VALUE, -Float.MIN_VALUE)); assertTrue(nearlyEqual(-Float.MIN_VALUE, Float.MIN_VALUE)); assertTrue(nearlyEqual(Float.MIN_VALUE, 0)); assertTrue(nearlyEqual(0, Float.MIN_VALUE)); assertTrue(nearlyEqual(-Float.MIN_VALUE, 0)); assertTrue(nearlyEqual(0, -Float.MIN_VALUE)); assertFalse(nearlyEqual(0.000000001f, -Float.MIN_VALUE)); assertFalse(nearlyEqual(0.000000001f, Float.MIN_VALUE)); assertFalse(nearlyEqual(Float.MIN_VALUE, 0.000000001f)); assertFalse(nearlyEqual(-Float.MIN_VALUE, 0.000000001f)); assertFalse(nearlyEqual(1e20f*Float.MIN_VALUE, 0.0f)); assertFalse(nearlyEqual(0.0f, 1e20f*Float.MIN_VALUE)); assertFalse(nearlyEqual(1e20f*Float.MIN_VALUE, -1e20f*Float.MIN_VALUE)); } }

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  • "C variable type sizes are machine dependent." Is it really true? signed & unsigned numbers ;

    - by claws
    Hello, I've been told that C types are machine dependent. Today I wanted to verify it. void legacyTypes() { /* character types */ char k_char = 'a'; //Signedness --> signed & unsigned signed char k_char_s = 'a'; unsigned char k_char_u = 'a'; /* integer types */ int k_int = 1; /* Same as "signed int" */ //Signedness --> signed & unsigned signed int k_int_s = -2; unsigned int k_int_u = 3; //Size --> short, _____, long, long long short int k_s_int = 4; long int k_l_int = 5; long long int k_ll_int = 6; /* real number types */ float k_float = 7; double k_double = 8; } I compiled it on a 32-Bit machine using minGW C compiler _legacyTypes: pushl %ebp movl %esp, %ebp subl $48, %esp movb $97, -1(%ebp) # char movb $97, -2(%ebp) # signed char movb $97, -3(%ebp) # unsigned char movl $1, -8(%ebp) # int movl $-2, -12(%ebp)# signed int movl $3, -16(%ebp) # unsigned int movw $4, -18(%ebp) # short int movl $5, -24(%ebp) # long int movl $6, -32(%ebp) # long long int movl $0, -28(%ebp) movl $0x40e00000, %eax movl %eax, -36(%ebp) fldl LC2 fstpl -48(%ebp) leave ret I compiled the same code on 64-Bit processor (Intel Core 2 Duo) on GCC (linux) legacyTypes: .LFB2: .cfi_startproc pushq %rbp .cfi_def_cfa_offset 16 movq %rsp, %rbp .cfi_offset 6, -16 .cfi_def_cfa_register 6 movb $97, -1(%rbp) # char movb $97, -2(%rbp) # signed char movb $97, -3(%rbp) # unsigned char movl $1, -12(%rbp) # int movl $-2, -16(%rbp)# signed int movl $3, -20(%rbp) # unsigned int movw $4, -6(%rbp) # short int movq $5, -32(%rbp) # long int movq $6, -40(%rbp) # long long int movl $0x40e00000, %eax movl %eax, -24(%rbp) movabsq $4620693217682128896, %rax movq %rax, -48(%rbp) leave ret Observations char, signed char, unsigned char, int, unsigned int, signed int, short int, unsigned short int, signed short int all occupy same no. of bytes on both 32-Bit & 64-Bit Processor. The only change is in long int & long long int both of these occupy 32-bit on 32-bit machine & 64-bit on 64-bit machine. And also the pointers, which take 32-bit on 32-bit CPU & 64-bit on 64-bit CPU. Questions: I cannot say, what the books say is wrong. But I'm missing something here. What exactly does "Variable types are machine dependent mean?" As you can see, There is no difference between instructions for unsigned & signed numbers. Then how come the range of numbers that can be addressed using both is different? I was reading http://stackoverflow.com/questions/2511246/how-to-maintain-fixed-size-of-c-variable-types-over-different-machines I didn't get the purpose of the question or their answers. What maintaining fixed size? They all are the same. I didn't understand how those answers are going to ensure the same size.

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  • Running multipul lines through a server.

    - by Kevin Roberson
    I am looking to buy numbers in bulk on DIDx.net. After I purchase the numbers in a particular area code, I want to forward those numbers to other numbers that are outside of that area code. This way it will be seen as a local call versus long distance. I have the customers but I don't have the system I need. I have read about Asterisk, VOIP, SIP, and BYOH. But I have no clue what will be the best system for me. Does anyone have any idea what my next step should be when it comes to hardware and software? Or what type of operating system I should use? I basically want to set up a system like GoogleVoice & Phonebooth.

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  • linux shell utils: convert a list of hex to list of decimals

    - by osgx
    Hello How can I convert a file with a lot hex numbers into the decimal? Example: file1 0x59999 0x5acdc 0xffeff I want to start $ cat file1 | util | cat file2 and get file2 with smth like 1021489 1249230 3458080 (numbers in example output are random, as I cant convert so long hex to dec) Upd: perl : perl -pe '$_=hex;$_.="\n"'. Can anybody do it better? The real task is a sorting of hex numbers.

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  • Running multipul lines through a server.

    - by Kevin Roberson
    I am looking to buy numbers in bulk on DIDx.net. After I purchase the numbers in a particular area code, I want to forward those numbers to other numbers that are outside of that area code. This way it will be seen as a local call versus long distance. I have the customers but I don't have the system I need. I have read about Asterisk, VOIP, SIP, and BYOH. But I have no clue what will be the best system for me. Does anyone have any idea what my next step should be when it comes to hardware and software? Or what type of operating system I should use? I basically want to set up a system like GoogleVoice & Phonebooth.

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  • Running multiple lines through a server.

    - by Kevin Roberson
    I am looking to buy numbers in bulk on DIDx.net. After I purchase the numbers in a particular area code, I want to forward those numbers to other numbers that are outside of that area code. This way it will be seen as a local call versus long distance. I have the customers but I don't have the system I need. I have read about Asterisk, VOIP, SIP, and BYOH. But I have no clue what will be the best system for me. Does anyone have any idea what my next step should be when it comes to hardware and software? Or what type of operating system I should use? I basically want to set up a system like GoogleVoice & Phonebooth.

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  • Data-only static libraries with GCC

    - by regularfry
    How can I make static libraries with only binary data, that is without any object code, and make that data available to a C program? Here's the build process and simplified code I'm trying to make work: ./datafile: abcdefghij Makefile: libdatafile.a: ar [magic] datafile main: libdatafile.a gcc main.c libdatafile.a -o main main.c: #define TEXTPTR [more magic] int main(){ char mystring[11]; memset(mystring, '\0', 11); memcpy(TEXTPTR, mystring, 10); puts(mystring); puts(mystring); return 0; } The output I'm expecting from running main is, of course: abcdefghijabcdefghij My question is: what should [magic] and [more magic] be?

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  • displaying python's autodoc to the user (python 3.3)

    - by Plotinus
    I'm writing a simple command line math game, and I'm using python's autodoc for my math algorithms to help me remember, for example, what a proth number is while i'm writing the algorithm, but later on I'll want to tell that information to the user as well, so they'll know what the answer was. So, for example I have: def is_proth(): """Proth numbers and numbers that fit the formula k×2^n + 1, where k are odd positive integers, and 2^n > k.""" [snip] return proths and then I tried to make a dictionary, like so: definitions = {"proths" : help(is_proth)} But it doesn't work. It prints this when I start the program, one for each item in the dictionary, and then it errors out on one of them that returns a set. And anyway, I don't want it displayed to the user until after they've played the game. Help on function is_proth in module __main__: is_proth() Proth numbers and numbers that fit the formula k×2^n + 1, where k are odd positive integers, and 2^n > k. (END) I understand the purpose of autodoc is more for helping programmers who are calling a function than for generating userdoc, but it seems inefficient to have to type out the definition of what a proth number is twice, once in a comment to help me remember what an algorithm does and then once to tell the user the answer to the game they were playing after they've won or lost.

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  • Using Take and skip keyword to filter records in LINQ

    - by vik20000in
    In LINQ we can use the take keyword to filter out the number of records that we want to retrieve from the query. Let’s say we want to retrieve only the first 5 records for the list or array then we can use the following query     int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };     var first3Numbers = numbers.Take(3); The TAKE keyword can also be easily applied to list of object in the following way. var first3WAOrders = (         from cust in customers         from order in cust.Orders         select cust ) .Take(3); [Note in the query above we are using the order clause so that the data is first ordered based on the orders field and then the first 3 records are taken. In both the above example we have been able to filter out data based on the number of records we want to fetch. But in both the cases we were fetching the records from the very beginning. But there can be some requirements whereby we want to fetch the records after skipping some of the records like in paging. For this purpose LINQ has provided us with the skip method which skips the number of records passed as parameter in the result set. int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 }; var allButFirst4Numbers = numbers.Skip(4); The SKIP keyword can also be easily applied to list of object in the following way. var first3WAOrders = (         from cust in customers         from order in cust.Orders         select cust ).Skip(3);  Vikram

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  • TakeWhile and SkipWhile method in LINQ

    - by vik20000in
     In my last post I talked about how to use the take and the Skip keyword to filter out the number of records that we are fetching. But there is only problem with the take and skip statement. The problem lies in the dependency where by the number of records to be fetched has to be passed to it. Many a times the number of records to be fetched is also based on the query itself. For example if we want to continue fetching records till a certain condition is met on the record set. Let’s say we want to fetch records from the array of number till we get 7. For this kind of query LINQ has exposed the TakeWhile Method.     int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };     var firstNumbersLessThan6 = numbers.TakeWhile(n => n < 7);   In the same way we can also use the SkipWhile statement. The skip while statement will skip all the records that do not match certain condition provided. In the example below we are skiping all those number which are not divisible by 3. Remember we could have done this with where clause also, but SkipWhile method can be useful in many other situation and hence the example and the keyword.     int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };     var allButFirst3Numbers = numbers.SkipWhile(n => n % 3 != 0); Vikram

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  • CodeGolf : Find the Unique Paths

    - by st0le
    Here's a pretty simple idea, in this pastebin I've posted some pair of numbers. These represent Nodes of a unidirected connected graph. The input to stdin will be of the form, (they'll be numbers, i'll be using an example here) c d q r a b d e p q so x y means x is connected to y (not viceversa) There are 2 paths in that example. a->b->c->d->e and p->q->r. You need to print all the unique paths from that graph The output should be of the format a->b->c->d->e p->q->r Notes You can assume the numbers are chosen such that one path doesn't intersect the other (one node belongs to one path) The pairs are in random order. They are more than 1 paths, they can be of different lengths. All numbers are less than 1000. If you need more details, please leave a comment. I'll amend as required. Shameless-Plug For those who enjoy Codegolf, please Commit at Area51 for its very own site:) (for those who don't enjoy it, please support it as well, so we'll stay out of your way...)

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  • [LINQ] Master&ndash;Detail Same Record (I)

    - by JTorrecilla
    PROBLEM Firstly, I am working on a project based on LINQ, EF, and C# with VS2010. The following Table shows what I have and what I want to show. Header C1 C2 C3 1 P1 01/01/2011 2 P2 01/02/2011 Details 1 1 D1 2 1 D2 3 1 D3 4 2 D1 5 2 D4 Expected Results 1 P1 01/01/2011 D1, D2, D3 2 P2 01/02/2011 D1,D4   IDEAS At the begin I got 3 possible ways: - Doing inside the DB:  It could be achieved from DB with a CURSOR in a Stored Procedure. - Doing from .NET with LOOPS. - Doing with LINQ (I love it!!) FIRST APROX Example with a simple CLASS with a LIST: With and Employee Class that acts as Header Table: 1: public class Employee 2: { 3: public Employee () { } 4: public Int32 ID { get; set; } 5: public String FirstName{ get; set; } 6: public String LastName{ get; set; } 7: public List<string> Numbers{ get; set; } // Acts as Details Table 8: } We can show all numbers contained by Employee: 1: List<Employee > listado = new List<Employee >(); 2: //Fill Listado 3: var query= from Employee em in listado 4: let Nums= string.Join(";", em.Numbers) 5: select new { 6: em.Name, 7: Nums 8: }; The “LET” operator allows us to host the results of “Join” of the Numbers List of the Employee Class. A little example. ASAP I will post the second part to achieve the same with Entity Framework. Best Regards

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  • How to use Secure Erase and is it on the install CD?

    - by Mikey
    Supposedly there is some built in hard drive magic called "Secure Erase" which is wildly faster and more secure than "dd if=/dev/zero..." I am most excited about the speed increase. There seems to be a GUI for it as part of Parted Magic: http://www.ocztechnologyforum.com/forum/showthread.php?81321-Secure-Erase-With-bootable-CD-USB-Linux..-Point-and-Click-Method Is there something like this for Ubuntu? Better yet, is there a way to actually issue this command "manually" like with smartctl or something?

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