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  • How do I check on non-transparent pixels in a bitmapdata?

    - by Opoe
    I'm still working on my window cleaning game from one of my previous questions I marked a contribution as my answer, but after all this time I can't get it to work and I have to many questions about this so I decided to ask some more about it. As a sequel on my mentioned previous question, my question to you is: How can I check whether or not a bitmapData contains non transparent pixels? Subquestion: Is this possible when the masked image is a movieclip? Shouldn't I use graphics instead? Information I have: A dirtywindow movieclip on the bottom layer and a clean window movieclip on layer 2(mc1) on the layer above. To hide the top layer(the dirty window) I assign a mask to it. Code // this creates a mask that hides the movieclip on top var mask_mc:MovieClip = new MovieClip(); addChild(mask_mc) //assign the mask to the movieclip it should 'cover' mc1.mask = mask_mc; With a brush(cursor) the player wipes of the dirt ( actualy setting the fill from the mask to transparent so the clean window appears) //add event listeners for the 'brush' brush_mc.addEventListener(MouseEvent.MOUSE_DOWN,brushDown); brush_mc.addEventListener(MouseEvent.MOUSE_UP,brushUp); //function to drag the brush over the mask function brushDown(dragging:MouseEvent):void{ dragging.currentTarget.startDrag(); MovieClip(dragging.currentTarget).addEventListener(Event.ENTER_FRAME,erase) ; mask_mc.graphics.moveTo(brush_mc.x,brush_mc.y); } //function to stop dragging the brush over the mask function brushUp(dragging:MouseEvent):void{ dragging.currentTarget.stopDrag(); MovieClip(dragging.currentTarget).removeEventListener(Event.ENTER_FRAME,erase); } //fill the mask with transparant pixels so the movieclip turns visible function erase(e:Event):void{ with(mask_mc.graphics){ beginFill(0x000000); drawRect(brush_mc.x,brush_mc.y,brush_mc.width,brush_mc.height); endFill(); } }

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  • Creating practically solvable 15 puzzle inputs

    - by Ashwin
    I am now developing a 15 puzzle game. I know the method to detect unsolvable puzzles. But unlike 8-puzzle, solution for 15-puzzle takes quite long time for some input states and can be solved within 5 seconds some other set of input states. Now the problem is that I cannot give the user(the player), a problem for which the solution takes more than 10 seconds(if he/she chooses to see the solution). So what I want is that when I initially shuffle the puzzle, I want to only present those puzzles which can be solved within 10 seconds. There must be some way to determine the hardness of the puzzle. I tried searching the net but could not find it. Does anyone know a way of determining the hardness of a puzzle? NOTE : I am using A* algorithm to find out the solution on a computer with 3GB RAM and 2.27GHZ processor.

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  • How do I get the correct values from glReadPixels in OpenGL 3.0?

    - by NoobScratcher
    I'm currently trying to Implement mouse selection into my game editor and I ran into a little problem when I look at the values stored in &pixel[0],&pixel[1],&pixel[2],&pixel[3]; I get r: 0 g: 0 b: 0 a: 0 As you can see I'm not able to get the correct values from glReadPixels(); My 3D models are red colored using glColor3f(255,0,0); I was hoping someone could help me figure this out. Here is the source code: case WM_LBUTTONDOWN: { GetCursorPos(&pos); ScreenToClient(hwnd, &pos); GLenum err = glGetError(); while (glGetError() != GL_NO_ERROR) {cerr << err << endl;} glReadPixels(pos.x, SCREEN_HEIGHT - 1 - pos.y, 1, 1, GL_RGB, GL_UNSIGNED_BYTE, &pixel[0] ); cerr << "r: "<< (int)pixel[0] << endl; cerr << "g: "<< (int)pixel[1] << endl; cerr << "b: "<< (int)pixel[2] << endl; cerr << "a: "<< (int)pixel[3] << endl; cout << pos.x << endl; cout << pos.y << endl; } break; I use : WIN32 API OPENGL 3.0 C++

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  • what making a good soundtrack for social game

    - by Maged
    there are many successful social games in Facebook and other social sites like brain buddies, who has the biggest brain and word challenge.both of them have a great soundtrack while playing and in the beginning of the game . my question is how to find a good soundtrack or what's i should look for to find a good soundtrack like this that's help to attract the user specially for games that need concentration ?

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  • Flickering when accessing texture by offset

    - by TravisG
    I have this simple compute shader that basically just takes the input from one image and writes it to another. Both images are 128/128/128 in size and glDispatchCompute is called with (128/8,128/8,128/8). The source images are cleared to 0 before this compute shader is executed, so no undefined values should be floating around in there. (I have the appropriate memory barrier on the C++ side set before the 3D texture is accessed). This version works fine: #version 430 layout (location = 0, rgba16f) uniform image3D ping; layout (location = 1, rgba16f) uniform image3D pong; layout (local_size_x = 8, local_size_y = 8, local_size_z = 8) in; void main() { ivec3 sampleCoord = gl_GlobalInvocationID.xyz; imageStore(pong, imageLoad(ping,sampleCoord)); } Reading values from pong shows that it's just a copy, as intended. However, when I load data from ping with an offset: #version 430 layout (location = 0, rgba16f) uniform image3D ping; layout (location = 1, rgba16f) uniform image3D pong; layout (local_size_x = 8, local_size_y = 8, local_size_z = 8) in; void main() { ivec3 sampleCoord = gl_GlobalInvocationID.xyz; imageStore(pong, imageLoad(ping,sampleCoord+ivec3(1,0,0))); } The data that is written to pong seems to depend on the order of execution of the threads within the work groups, which makes no sense to me. When reading from the pong texture, visible flickering occurs in some spots on the texture. What am I doing wrong here?

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  • Bouncing off a circular Boundary with multiple balls?

    - by Anarkie
    I am making a game like this : Yellow Smiley has to escape from red smileys, when yellow smiley hits the boundary game is over, when red smileys hit the boundary they should bounce back with the same angle they came, like shown below: Every 10 seconds a new red smiley comes in the big circle, when red smiley hits yellow, game is over, speed and starting angle of red smileys should be random. I control the yellow smiley with arrow keys. The biggest problem I have reflecting the red smileys from the boundary with the angle they came. I don't know how I can give a starting angle to a red smiley and bouncing it with the angle it came. I would be glad for any tips! My js source code : var canvas = document.getElementById("mycanvas"); var ctx = canvas.getContext("2d"); // Object containing some global Smiley properties. var SmileyApp = { radius: 15, xspeed: 0, yspeed: 0, xpos:200, // x-position of smiley ypos: 200 // y-position of smiley }; var SmileyRed = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 65 // y-position of smiley }; var SmileyReds = new Array(); for (var i=0; i<5; i++){ SmileyReds[i] = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 67 // y-position of smiley }; SmileyReds[i].xspeed = Math.floor((Math.random()*50)+1); SmileyReds[i].yspeed = Math.floor((Math.random()*50)+1); } function drawBigCircle() { var centerX = canvas.width / 2; var centerY = canvas.height / 2; var radiusBig = 300; ctx.beginPath(); ctx.arc(centerX, centerY, radiusBig, 0, 2 * Math.PI, false); // context.fillStyle = 'green'; // context.fill(); ctx.lineWidth = 5; // context.strokeStyle = '#003300'; // green ctx.stroke(); } function lineDistance( positionx, positiony ) { var xs = 0; var ys = 0; xs = positionx - 350; xs = xs * xs; ys = positiony - 350; ys = ys * ys; return Math.sqrt( xs + ys ); } function drawSmiley(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.7*r, y); ctx.arc(x,y,0.7*r, 0, Math.PI, false); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } function drawSmileyRed(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; //yellow ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.4*r, y+10); ctx.arc(x,y+10,0.4*r, 0, Math.PI, true); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } // --- Animation of smiley moving with constant speed and bounce back at edges of canvas --- var tprev = 0; // this is used to calculate the time step between two successive calls of run function run(t) { requestAnimationFrame(run); if (t === undefined) { t=0; } var h = t - tprev; // time step tprev = t; SmileyApp.xpos += SmileyApp.xspeed * h/1000; // update position according to constant speed SmileyApp.ypos += SmileyApp.yspeed * h/1000; // update position according to constant speed for (var i=0; i<SmileyReds.length; i++){ SmileyReds[i].xpos += SmileyReds[i].xspeed * h/1000; // update position according to constant speed SmileyReds[i].ypos += SmileyReds[i].yspeed * h/1000; // update position according to constant speed } // change speed direction if smiley hits canvas edges if (lineDistance(SmileyApp.xpos, SmileyApp.ypos) + SmileyApp.radius > 300) { alert("Game Over"); } // redraw smiley at new position ctx.clearRect(0,0,canvas.height, canvas.width); drawBigCircle(); drawSmiley(SmileyApp.xpos, SmileyApp.ypos, SmileyApp.radius); for (var i=0; i<SmileyReds.length; i++){ drawSmileyRed(SmileyReds[i].xpos, SmileyReds[i].ypos, SmileyReds[i].radius); } } // uncomment these two lines to get every going // SmileyApp.speed = 100; run(); // --- Control smiley motion with left/right arrow keys function arrowkeyCB(event) { event.preventDefault(); if (event.keyCode === 37) { // left arrow SmileyApp.xspeed = -100; SmileyApp.yspeed = 0; } else if (event.keyCode === 39) { // right arrow SmileyApp.xspeed = 100; SmileyApp.yspeed = 0; } else if (event.keyCode === 38) { // up arrow SmileyApp.yspeed = -100; SmileyApp.xspeed = 0; } else if (event.keyCode === 40) { // right arrow SmileyApp.yspeed = 100; SmileyApp.xspeed = 0; } } document.addEventListener('keydown', arrowkeyCB, true); JSFiddle : http://jsfiddle.net/gj4Q7/

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  • How do I draw anti-aliased holes in a bitmap

    - by gyozo kudor
    I have an artillery game (hobby-learning project) and when the projectile hits it leaves a hole in the ground. I want this hole to have antialiased edges. I'm using System.Drawing for this. I've tried with clipping paths, and drawing with a transparent color using gfx.CompositingMode = CompositingMode.SourceCopy, but it gives me the same result. If I draw a circle with a solid color it works fine, but I need a hole, a circle with 0 alpha values. I have enabled these but they work only with solid colors: gfx.CompositingQuality = CompositingQuality.HighQuality; gfx.InterpolationMode = InterpolationMode.HighQualityBicubic; gfx.SmoothingMode = SmoothingMode.AntiAlias; In the two pictures consider black as being transparent. This is what I have (zoomed in): And what I need is something like this (made with photoshop): This will be just a visual effect, in code for collision detection I still treat everything with alpha 128 as solid. Edit: I'm usink OpenTK for this game. But for this question I think it doesn't really matter probably it is gdi+ related.

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  • Split vector vs matrix notation for transformation

    - by seahorse
    Some rendering engines like Ogre prefer to use a individual vector based notation for transformations like the following Split vector notation: Net Transformation is represented by Scale vector = sx, sy, sz Transformation vector = tx, ty, tz Rotation Quaternion Vector = w,x,y,z Matrix notation: There are other engines which simply use a net combined transformation matrix. What are the advantages of the first notation over the second? Also for animation interpolation does it work in the first notation that we interpolate across the individual components and use the interpolated parts to get the net transformation? Is this another advantage?

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  • Android Live Testing

    - by Matthew Dockerty
    I am making a game for android and in it I am using sensors which are not available in the emulator. At the moment I am connecting my device and transferring the apk, then installing to test but that is a pain to do, and I have gotten to the stage where I need to start logging values for debugging. I have gone into the run configs of my app and set it to prompt me to pick a device, but my device is never in the list when it is connected to my PC and I try to run it. How am I supposed to set it up to work properly? Thanks for the help.

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  • Slick2d Spritesheet showing whole image

    - by BotskoNet
    I'm trying to show a single subimage from a sprite sheet. Using slick2d SpriteSheet class, all it's doing is showing me the entire image, but scaled down to fit the cell dimensions. The image is 96x192 and should have cells of 32x32. The code: SpriteSheet spriteSheet = new SpriteSheet("images/"+file, 32, 32 ); System.out.println("Horiz Count: " + spriteSheet.getHorizontalCount()); System.out.println("Vert Count: " + spriteSheet.getVerticalCount()); System.out.println("Height: " + spriteSheet.getHeight()); System.out.println("Width: " + spriteSheet.getWidth()); System.out.println("Texture Width: " + spriteSheet.getTextureWidth()); System.out.println("Texture Height: " + spriteSheet.getTextureHeight()); Prints: Horiz Count: 3 Vert Count: 6 Height: 192 Width: 96 Texture Width: 0.75 Texture Height: 0.75 Not sure what the texture dimensions refer to, but the rest is entirely accurate. However, when I draw the icon, the entire sprite image shows scaled down to 32x32: Image image = spriteSheet.getSprite(1, 0); // a test image.bind(); GL11.glEnable(GL11.GL_BLEND); GL11.glBlendFunc(GL11.GL_SRC_ALPHA, GL11.GL_ONE_MINUS_SRC_ALPHA); GL11.glBegin(GL11.GL_QUADS); GL11.glTexCoord2f(0,0); GL11.glVertex2f(x,y); GL11.glTexCoord2f(1,0); GL11.glVertex2f(x+image.getWidth(),y); GL11.glTexCoord2f(1,1); GL11.glVertex2f(x+image.getWidth(),y+image.getHeight()); GL11.glTexCoord2f(0,1); GL11.glVertex2f(x,y+image.getHeight()); GL11.glEnd(); GL11.glDisable(GL11.GL_BLEND);

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  • Html 5 ping pong game side collision problem

    - by Gurjit
    I am making a simple ping pong game where I am facing a side collision problem means when the ball collides with the either side of the paddle . Although I have written code for making it works but something is failing....I want plz someone to give suggestions and tell how to avoid it. Means while trying to hit the ball with side face of the paddle poses a problem.!! Here is the main part of the code causing problem function checkCollision(){ ///// This is collision detection for the upper part ///// if( cy + radius >= paddleTop && cx + radius > paddleLeft && cy + radius >= paddleTop + 5 && cx - radius <= paddleLeft + paddleWidth ) { dy = -dy; ++hits; /// On collision we are increasing the Score playSound(); } else if( cy + radius >= paddleTop && cy + radius <= paddleTop + paddleHeight && cx + radius >= paddleLeft && cy - radius <= paddleLeft - (radius + 1) ) { dx = -dx; } } here is working fiddle for it :- http://jsfiddle.net/gurjitmehta/orzpzf69/

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  • Is there any advantage in using DX10/11 for a 2D game?

    - by David Gouveia
    I'm not entirely familiar with the feature set introduced by DX10/11 class hardware. I'm vaguely familiar with the new stages added to the programmable graphics pipeline, such as the geometry shader, the compute shader, and the new tesselation stages. I don't see how any of these make much of a difference for a 2D game though. Is there any compelling reason to make the switch to DX10/11 (or the OpenGL equivalents) for a 2D game, or would it be wiser to stick with DX9 considering that that a significant share of the market still runs on older technologies (e.g. the February 2012 Steam surveys lists around 17% of users as still using Windows XP)?

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  • How can I save state from script in a multithreaded engine?

    - by Peter Ren
    We are building a multithreaded game engine and we've encountered some problems as described below. The engine have 3 threads in total: script, render, and audio. Each frame, we update these 3 threads simultaneously. As these threads updating themselves, they produce some tasks and put them into a public storage area. As all the threads finish their update, each thread go and copy the tasks for themselves one by one. After all the threads finish their task copying, we make the threads process those tasks and update these threads simultaneously as described before. So this is the general idea of the task schedule part of our engine. Ok, well, all the task schedule part work well, but here's the problem: For the simplest, I'll take Camera as an example: local oldPos = camera:getPosition() -- ( 0, 0, 0 ) camera:setPosition( 1, 1, 1 ) -- Won't work now, cuz the render thread will process the task at the beginning of the next frame local newPos = camera:getPosition() -- Still ( 0, 0, 0 ) So that's the problem: If you intend to change a property of an object in another thread, you have to wait until that thread process this property-changing message. As a result, what you get from the object is still the information in the last frame. So, is there a way to solve this problem? Or are we build the task schedule part in a wrong way? Thanks for your answers :)

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  • Improving Click and Drag with C++

    - by Josh
    I'm currently using SFML 2.0 to develop a game in C++. I have a game sprite class that has a click and drag method. The method works, but there is a slight problem. If the mouse moves too fast, the object the user selected can't keep up and is left behind in the spot where the mouse left its bounds. I will share the class definition and the given function implementation. Definition: class codePeg { protected: FloatRect bounds; CircleShape circle; int xPos, yPos, xDiff, yDiff, once; int xBase, yBase; Vector2i mousePos; Vector2f circlePos; public: void init(RenderWindow& Window); void draw(RenderWindow& Window); void drag(RenderWindow& Window); void setPegPosition(int x, int y); void setPegColor(Color pegColor); void mouseOver(RenderWindow& Window); friend int isPegSelected(void); }; Implementation of the "drag" function: void codePeg::drag(RenderWindow& Window) { mousePos = Mouse::getPosition(Window); circlePos = circle.getPosition(); if(Mouse::isButtonPressed(Mouse::Left)) { if(mousePos.x > xPos && mousePos.y > yPos && mousePos.x - bounds.width < xPos && mousePos.y - bounds.height < yPos) { if(once) { xDiff = mousePos.x - circlePos.x; yDiff = mousePos.y - circlePos.y; once = 0; } xPos = mousePos.x - xDiff; yPos = mousePos.y - yDiff; circle.setPosition(xPos, yPos); } } else { once = 1; xPos = xBase; yPos = yBase; xDiff = 0; yDiff = 0; circle.setPosition(xBase, yBase); } Window.draw(circle); } Like I said, the function works, but to me, the code is very ugly and I think it could be improved and could be more efficient. The only thing I can think of as to why the object cannot keep up with the mouse is that there are too many function calls and/or checks. The user does not really have to mouse the mouse "fast" for it to happen, I would say at an average pace the object is left behind. How can I improve the code so that the object remains with the mouse when it is selected? Any help improving this code or giving advice is greatly appreciated.

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  • How would I achieve diablo like 2D isometric projection?

    - by Darestium
    Good day, I am in the process of coming up with an idea for a game, and I would like it to be isometric like Diablo. The problem is I have no idea how it achieves the effect of height like in the following screenshot (on the columns): http://upload.wikimedia.org/wikipedia/en/thumb/2/20/Diabloscreen.jpg/350px-Diabloscreen.jpg but whatever the case, I'm sure it is going to be harder to achieve then creating a traditional isometric game, but any ideas regarding the topic would be greatly appreciated.

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  • Can SpriteBatch be used to fill a polygon with a texture?

    - by can poyrazoglu
    I basically need to fill a texture into a polygon using the SpriteBatch. I've done some research but couldn't find anything useful except polygon triangulation method, which works well only with convex polygons (without diving into super math which is definitely not something I'm pretty good at). Are there any solutions for filling in a polygon in a basic way? I of course need something dynamic (I'll have a map editor that you can define polygons, and the game will render them (and collision detection will also use them but that's off topic), basically I can't accept solutions like "pre-calculated" bitmaps or anything like that. I need to draw a polygon with the segments provided, to the screen, using the SpriteBatch.

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  • How to make players be creative in a game, if the game cannot evaluate it?

    - by Mensonge
    I am working on a prototype game with several funny/visual effects that the player can trigger. The player can be quite creative in the way to use or combine these effects but it seems impossible to make detect/evaluate this creativity by the computer. So, from a game design perspective, I wonder what could be the features to drive the players to be creative (experiment various combinations). For the moment i think about "Draw something" where the result is evaluated by other players. I think about levels designed by "Little Big Planet" players but this aspect is out of the core game. I think also about "Minecraft" but I do not understand really how this game encourages the people to be creative (except of the open world). Please tell me if you have any ideas, articles or references that could help me coping with this problem.

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  • View matrix question (rotate by 180 degrees)

    - by King Snail
    I am using a third party rendering API on top of OpenGL code and I cannot get my matrices correct. The API states this: We're right handed by default, and we treat y as up by convention. Since IwGx's coordinate system has (0,0) as the top left, you typically need a 180 degree rotation around Z in your view matrix. I think the viewer does this by default. In my OpenGL app I have access to the view and projection matrices separately. How can I convert them to fit the criteria used by my third party rendering API? I don't understand what they mean to rotate 180 degrees around Z, is that in the view matrix itself or something in the camera before making the view matrix. Any code would be helpful, thanks.

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  • Rotate canvas along its center based on user touch - Android

    - by Ganapathy
    I want to rotate the canvas circularly on its center axis based on user touch. i want to rotate based on center but its rotating based on top left corner . so i am able to see only 1/4 for rotation of image. any idea.. Like a old phone dialer . I have tried like as follows onDraw(Canvas canvas){ canvas.save(); // do my rotation canvas.rotate(rotation,0,0); canvas.drawBitmap( ((BitmapDrawable)d).getBitmap(),0,0,p ); canvas.restore(); } @Override public boolean onTouchEvent(MotionEvent e) { float x = e.getX(); float y = e.getY(); updateRotation(x,y); mPreviousX = x; mPreviousY = y; invalidate(); } private void updateRotation(float x, float y) { double r = Math.atan2(x - centerX, centerY - y); rotation = (int) Math.toDegrees(r); }

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  • How do I properly use multithreading with Nvidia PhysX?

    - by xcrypt
    I'm having a multithreading problem with Nvidia PhysX. the SDK requires that you call Simulate() (starts computing new physics positions within a new thread) and FetchResults() (waits 'till the physics computations are done). Inbetween Simulate() and FetchResults() you may not "compute new physics". It is proposed (in a sample) that we create a game loop as such: Logic (you may calculate physics here and other stuff) Render + Simulate() at start of Render call and FetchResults at end of Render() call However, this has given me various little errors that stack up: since you actually render the scene that was computed in the previous iteration in the game loop. Does anyone have a solution to this?

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  • XNA 4.0 SpriteFont not displaying all Characters

    - by Iain Brown
    Am looking for a little help and trying to use SpriteFont in my XNA 4.0 game but the problem is am displaying to string "This is a test" but all that's displayed on the screen is "This is st" so the "a te" are missing from the screen. The space is there for the characters but the letters are not. The code am using is: spriteBatch.Begin(SpriteSortMode.BackToFront, BlendState.AlphaBlend); spriteBatch.DrawString(font,"this is a test",new Vector2(692,372),Color.White); spriteBatch.Draw(texture,new Rectangle(0,0,100,100),Color.White); spriteBatch.End(); Any help with this would be great!

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  • Group Matchmaking

    - by Simon Kérouack
    Consider different groups(1 or more players) queuing together, we want to make 2 opposing teams containing each the same amount of players while keeping the groups together. At the same time we want to make both teams' average ranking as close as possible. Now also consider we have as a working set the subset of groups currently queuing within a given ranking range. For an example, let's say we have the following groups, ordered by queuing time: Id, playerCount, totalRank, avgRank 0, 3, 126, 42 1, 2, 60, 30 2, 1, 25, 25 3, 2, 80, 40 4, 1, 40, 40 5, 1, 20, 20 6, 3, 150, 50 for this specific subset, the expected output should ideally be: team1: 0, 1 (total: 186) team2: 2, 5, 6 (total: 195) up to now the solution I have been using is to balance out each team by making each team pick the group with highest ranking within the subset turn by turn. The team who picks is the one with the currently lowest average rank unless one is already full. If one team is already full the other team tries to complete itself with groups that would make the rank gap as small as possible. This solution turns out to have issues with frequent edge cases and I'm looking for a better solution, or some fine-tuning that could be made. In most cases, players seems to want teams of 5 people and queue in group of 2. Our average subset when 2 teams of 5 are chosen is made of about 14 players if that may be of any help.

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  • Translate extrinsic rotations to intrinsic rotations ( Euler angles )

    - by MineMan287
    The problem I have is very frustrating: I am using the Jitter Physics library which gives Quaternion rotations, you can extract the extrinsic rotations but I need intrinsic rotations to rotate in OpenTK (There are other reasons as well so I don't want to make OpenTK use a Matrix) GL.Rotate(xr, 1, 0, 0) GL.Rotate(yr, 0, 1, 0) GL.Rotate(zr, 0, 0, 1) EDIT : Response to the first answer Like This? GL.Rotate(zr, 0, 0, 1) GL.Rotate(yr, 0, 1, 0) GL.Rotate(xr, 1, 0, 0) Or This? GL.Rotate(xr, 1, 0, 0) GL.Rotate(yr, 0, 1, 0) GL.Rotate(zr, 0, 0, 1) GL.Rotate(zr, 0, 0, 1) GL.Rotate(yr, 0, 1, 0) GL.Rotate(xr, 1, 0, 0) GL.Rotate(xr, 1, 0, 0) GL.Rotate(yr, 0, 1, 0) GL.Rotate(zr, 0, 0, 1) I'm confused, please give an example

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  • library for octree or kdtree

    - by Will
    Are there any robust performant libraries for indexing objects? It would need frustum culling and visiting objects hit by a ray as well as neighbourhood searches. I can find lots of articles showing the math for the component parts, often as algebra rather than simple C, but nothing that puts it all together (apart from perhaps Ogre, which has rather more involved and isn't so stand-alone). Surely hobby game makers don't all have to make their own octrees? (Python or C/C++ w/bindings preferred)

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  • How to determine the end of list has been reached?

    - by Sweta Dwivedi
    I'm trying to animate my object according to a set of recorded values from kinect skeleton stream by saving the (x,y,z) stream from the skeletal data into a list and then set my objects x and y position from the x,y of the list. However, once the list end has been reached it starts to animate again from the start. I don't want that - I just want the model position to keep going in the positive X direction. Is there any way I can check if end of the list has been reached and to just update the model position in x direction? Or is there any other way to continue moving my sprite once the points in the list are over... i dont want it to start animating all the way again.. protected override void Update(GameTime gameTime) { //position += spriteSpeed * (float)gameTime.ElapsedGameTime.TotalSeconds; //// TODO: Add your update logic here using (StreamReader r = new StreamReader(f)) { string line; Viewport view = graphics.GraphicsDevice.Viewport; int maxWidth = view.Width; int maxHeight = view.Height; while((line = r.ReadLine()) != null) { string[] temp = line.Split(','); int x = (int) Math.Floor(((float.Parse(temp[0]) * 0.5f) + 0.5f) * maxWidth); int y = (int) Math.Floor(((float.Parse(temp[1]) * -0.5f) + 0.5f) * maxHeight); motion_2.Add(new Point(x, y)); } } position.X = motion_2[i].X; position.Y = motion_2[i].Y; i++; a_butterfly_up.Update(gameTime); a_butterfly_side.Update(gameTime); G_vidPlayer.Play(mossV); base.Update(gameTime); }

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