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  • Can't iterate over nestled dict in django

    - by fredrik
    Hi, Im trying to iterate over a nestled dict list. The first level works fine. But the second level is treated like a string not dict. In my template I have this: {% for product in Products %} <li> <p>{{ product }}</p> {% for partType in product.parts %} <p>{{ partType }}</p> {% for part in partType %} <p>{{ part }}</p> {% endfor %} {% endfor %} </li> {% endfor %} It's the {{ part }} that just list 1 char at the time based on partType. And it seams that it's treated like a string. I can however via dot notation reach all dict but not with a for loop. The current output looks like this: Color C o l o r Style S ..... The Products object looks like this in the log: [{'product': <models.Products.Product object at 0x1076ac9d0>, 'parts': {u'Color': {'default': u'Red', 'optional': [u'Red', u'Blue']}, u'Style': {'default': u'Nice', 'optional': [u'Nice']}, u'Size': {'default': u'8', 'optional': [u'8', u'8.5']}}}] What I trying to do is to pair together a dict/list for a product from a number of different SQL queries. The web handler looks like this: typeData = Products.ProductPartTypes.all() productData = Products.Product.all() langCode = 'en' productList = [] for product in productData: typeDict = {} productDict = {} for type in typeData: typeDict[type.typeId] = { 'default' : '', 'optional' : [] } productDict['product'] = product productDict['parts'] = typeDict defaultPartsData = Products.ProductParts.gql('WHERE __key__ IN :key', key = product.defaultParts) optionalPartsData = Products.ProductParts.gql('WHERE __key__ IN :key', key = product.optionalParts) for defaultPart in defaultPartsData: label = Products.ProductPartLabels.gql('WHERE __key__ IN :key AND partLangCode = :langCode', key = defaultPart.partLabelList, langCode = langCode).get() productDict['parts'][defaultPart.type.typeId]['default'] = label.partLangLabel for optionalPart in optionalPartsData: label = Products.ProductPartLabels.gql('WHERE __key__ IN :key AND partLangCode = :langCode', key = optionalPart.partLabelList, langCode = langCode).get() productDict['parts'][optionalPart.type.typeId]['optional'].append(label.partLangLabel) productList.append(productDict) logging.info(productList) templateData = { 'Languages' : Settings.Languges.all().order('langCode'), 'ProductPartTypes' : typeData, 'Products' : productList } I've tried making the dict in a number of different ways. Like first making a list, then a dict, used tulpes anything I could think of. Any help is welcome! Bouns: If someone have an other approach to the SQL quires, that is more then welcome. I feel that it kinda stupid to run that amount of quires. What is happening that each product part has a different label base on langCode. ..fredrik

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  • I'm getting the following error ''expected an indented block'' Where is the failing code?

    - by user1833814
    import math def area(base, height): '''(number,number) -> number Return the area of a wirh given base and height. >>>area(10,40) 200.0 ''' return base * height / 2 def perimeter(side1, side2, side3): '''(number,number,number) -> number Return the perimeter of the triangle with sides of length side1,side2 and side3. >>>perimeter(3,4,5) 12 >>>perimeter(10.5,6,9.3) 25.8 ''' return (side1 + side2 + side3) def semiperimeter(side1, side2, side3): return perimeter(side1, side2, side3) / 2 def area_hero(side1, side2, side3): semi = semiperimeter(side1, side2, side3) area = math.sqrt((semi * (semi - side1) * (semi - side2) * (semi - side3)) return area

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  • Py GTK Drawing area and Rich Text Editor

    - by crashekar
    I would like to include a rich text editor in a pygtk drawing area for an application i am developing. The editor ( a small resizable widget ) should be able to move around the drawing area like a rectangle. I am not sure how to start as I am pretty new to PyGTK. thank you !

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  • how to fetch more than 1000 entities NON keybased?

    - by user291071
    If I should be approaching this problem through a different method, please suggest so. I am creating an item based collaborative filter. I populate the db with the LinkRating2 class and for each link there are more than a 1000 users that I need to call and collect their ratings to perform calculations which I then use to create another table. So I need to call more than 1000 entities for a given link. For instance lets say there are over a 1000 users rated 'link1' there will be over a 1000 instances of this class for the given link property that I need to call. How would I complete this example? class LinkRating2(db.Model): user = db.StringProperty() link = db.StringProperty() rating2 = db.FloatProperty() query =LinkRating2.all() link1 = 'link string name' a = query.filter('link = ', link1) aa = a.fetch(1000)##how would i get more than 1000 for a given link1 as shown? ##keybased over 1000 in other post example i need method for a subset though not key class MyModel(db.Expando): @classmethod def count_all(cls): """ Count *all* of the rows (without maxing out at 1000) """ count = 0 query = cls.all().order('__key__') while count % 1000 == 0: current_count = query.count() if current_count == 0: break count += current_count if current_count == 1000: last_key = query.fetch(1, 999)[0].key() query = query.filter('__key__ > ', last_key) return count

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  • Finding a Eulerian Tour

    - by user590903
    I am trying to solve a problem on Udacity described as follows: # Find Eulerian Tour # # Write a function that takes in a graph # represented as a list of tuples # and return a list of nodes that # you would follow on an Eulerian Tour # # For example, if the input graph was # [(1, 2), (2, 3), (3, 1)] # A possible Eulerian tour would be [1, 2, 3, 1] I came up with the following solution, which, while not as elegant as some of the recursive algorithms, does seem to work within my test case. def find_eulerian_tour(graph): tour = [] start_vertex = graph[0][0] tour.append(start_vertex) while len(graph) > 0: current_vertex = tour[len(tour) - 1] for edge in graph: if current_vertex in edge: if edge[0] == current_vertex: current_vertex = edge[1] else: current_vertex = edge[0] graph.remove(edge) tour.append(current_vertex) break return tour graph = [(1, 2), (2, 3), (3, 1)] print find_eulerian_tour(graph) >> [1, 2, 3, 1] However, when submitting this, I get rejected by the grader. I am doing something wrong? I can't see any errors.

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  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

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  • What is the most suitable for writing a high speed server C, C++ or C# ?

    - by wniroshan
    I'm goint to write a server which does lots of image processing. Server-end processsing is expected to be very tedious. Server will maily have mobile phones as its clients. I am really concerend about speed and effciency. Security is pretty important too. Server will be running on a windows platform. Can anyone tell me what should I use as the language C, C++ or C#? or at least what are the ares that I should be looking at when selecting one of them Thank you.

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  • Clear sqlalchemy reflection cache

    - by OrganicPanda
    Hi all, I'm using sqlalchemy's reflection tools to get a Table object. I do this because these tables are dynamic and tables/columns can change. Here's the code I'm using: def getTableByReflection(self, tableName, metadata, engine): return Table(tableName, metadata, autoload = True, autoload_with = engine) The problem is that when the above code is run twice it seems to return the same results regardless of whether or not the columns have changed. I have tried refreshing using the mysession.refresh(mytable) but that fails because the table is not attached to any metadata - which makes sense but then why am I seeing cached results? Is there any way to tell the metadata/engine/session to forget about this table and let me load it cleanly?

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  • django file serving issues

    - by tipu
    I have in my url patterns, urlpatterns += patterns('', (r'^(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/home/tipu/Dropbox/dev/workspace/search/images'}) In my template when I do <link rel="stylesheet" type="text/css" href="{{ MEDIA_URL }}style.css" /> It serves the css just fine. But the file logo.png, that's in the same directory as style.css, doesn't show when I do this: <img src = "{{ MEDIA_URL }}logo.png" id = "logo" /> Any idea why?

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  • Most secure way to generate a random session ID for a cookie?

    - by ensnare
    I'm writing my own sessions controller that issues a unique id to a user once logged in, and then verifies and authenticates that unique id at every page load. What is the most secure way to generate such an id? Should the unique id be completely random? Is there any downside to including the user id as part of the unique id?

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  • how to change headers data

    - by Moayyad Yaghi
    hello i have the following class class AssetTableModel(QtCore.QAbstractTableModel): def init(self,filename=''): super(AssetTableModel,self).init() self.fileName=filename self.dirty = False self.assets = [] self.setHeaderData(0,QtCore.Qt.Horizontal,QtCore.QVariant('moayyad'),QtCore.Qt.EditRole) and i need to change the headers of the columns or the rows ,i used ( self.setHeaderdata()) but its not working ,i have a table that consistes of 2 columns and 2 rows only. is there any other function that changes headers ??. please help thanx in adnvance

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  • How to join list of strings?

    - by satsurae
    Hi all, This is probably seriously easy to solve for most of you but I cannot solve this simply putting str() around it can I? I would like to convert this list: ['A','B','C'] into 'A B C'. Thanks in advance!!

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  • Reordering fields in Django model

    - by Alex Lebedev
    I want to add few fields to every model in my django application. This time it's created_at, updated_at and notes. Duplicating code for every of 20+ models seems dumb. So, I decided to use abstract base class which would add these fields. The problem is that fields inherited from abstract base class come first in the field list in admin. Declaring field order for every ModelAdmin class is not an option, it's even more duplicate code than with manual field declaration. In my final solution, I modified model constructor to reorder fields in _meta before creating new instance: class MyModel(models.Model): # Service fields notes = my_fields.NotesField() created_at = models.DateTimeField(auto_now_add=True) updated_at = models.DateTimeField(auto_now=True) class Meta: abstract = True last_fields = ("notes", "created_at", "updated_at") def __init__(self, *args, **kwargs): new_order = [f.name for f in self._meta.fields] for field in self.last_fields: new_order.remove(field) new_order.append(field) self._meta._field_name_cache.sort(key=lambda x: new_order.index(x.name)) super(TwangooModel, self).__init__(*args, **kwargs) class ModelA(MyModel): field1 = models.CharField() field2 = models.CharField() #etc ... It works as intended, but I'm wondering, is there a better way to acheive my goal?

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  • Is it okay to rollback code if your client refuses to pay you?

    - by JustinY
    A friend of mine did some contracting work to add localization support to an existing mobile app. He was not contracted to add any other features or fix any already existing bugs. He has finished his work, but the client refuses to pay him because of an already existing bug that he hasn't fixed. The only card my friend has left is to rollback the server code to the state it was before he began working, which will probably break the mobile app and hopefully force the client's hand. Is this legal? Is there a better way to handle the situation?

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  • Django template context not working with imported class

    - by Andy Hume
    I'm using Django's templating on appengine, and am having a problem whereby a class I'm importing from another package is not correctly being made available to the template context. Broadly speaking, this is the code. The prop1 is not available in the template in the first example below, but is in the second. MyClass is identical in both cases. This does not work: from module import MyClass context = MyClass() self.response.out.write(template.render(path, context)) This does: class MyClass(object): def __init__(self): self.prop1 = "prop1" context = MyClass() self.response.out.write(template.render(path, context)) If I log the context in the above code I get: <module.MyClass object at 0x107b1e450> when it's imported, and: <__main__.MyClass object at 0x103759390> when it's defined in the same file. Any clues as to what might cause this kind of behaviour?

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  • better for-loop syntax for detecting empty sequences?

    - by Dmitry Beransky
    Hi, Is there a better way to write the following: row_counter = 0 for item in iterable_sequence: # do stuff with the item counter += 1 if not row_counter: # handle the empty-sequence-case Please keep in mind that I can't use len(iterable_sequence) because 1) not all sequences have known lengths; 2) in some cases calling len() may trigger loading of the sequence's items into memory (as the case would be with sql query results). The reason I ask is that I'm simply curious if there is a way to make above more concise and idiomatic. What I'm looking for is along the lines of: for item in sequence: #process item *else*: #handle the empty sequence case (assuming "else" here worked only on empty sequences, which I know it doesn't)

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  • Programmatic binding of accelerators in wxPython

    - by Inductiveload
    I am trying to programmatically create and bind a table of accelerators in wxPython in a loop so that I don't need to worry about getting and assigning new IDs to each accelerators (and with a view to inhaling the handler list from some external resource, rather than hard-coding them). I also pass in some arguments to the handler via a lambda since a lot of my handlers will be the same but with different parameters (move, zoom, etc). The class is subclassed from wx.Frame and setup_accelerators() is called during initialisation. def setup_accelerators(self): bindings = [ (wx.ACCEL_CTRL, wx.WXK_UP, self.on_move, 'up'), (wx.ACCEL_CTRL, wx.WXK_DOWN, self.on_move, 'down'), (wx.ACCEL_CTRL, wx.WXK_LEFT, self.on_move, 'left'), (wx.ACCEL_CTRL, wx.WXK_RIGHT, self.on_move, 'right'), ] accelEntries = [] for binding in bindings: eventId = wx.NewId() accelEntries.append( (binding[0], binding[1], eventId) ) self.Bind(wx.EVT_MENU, lambda event: binding[2](event, binding[3]), id=eventId) accelTable = wx.AcceleratorTable(accelEntries) self.SetAcceleratorTable(accelTable) def on_move(self, e, direction): print direction However, this appears to bind all the accelerators to the last entry, so that Ctrl+Up prints "right", as do all the other three. How to correctly bind multiple handlers in this way?

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  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

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  • Calculating the null space of a matrix

    - by Ainsworth
    I'm attempting to solve a set of equations of the form Ax = 0. A is known 6x6 matrix and I've written the below code using SVD to get the vector x which works to a certain extent. The answer is approximately correct but not good enough to be useful to me, how can I improve the precision of the calculation? Lowering eps below 1.e-4 causes the function to fail. from numpy.linalg import * from numpy import * A = matrix([[0.624010149127497 ,0.020915658603923 ,0.838082638087629 ,62.0778180312547 ,-0.336 ,0], [0.669649399820597 ,0.344105317421833 ,0.0543868015800246 ,49.0194290212841 ,-0.267 ,0], [0.473153758252885 ,0.366893577716959 ,0.924972565581684 ,186.071352614705 ,-1 ,0], [0.0759305208803158 ,0.356365401030535 ,0.126682113674883 ,175.292109352674 ,0 ,-5.201], [0.91160934274653 ,0.32447818779582 ,0.741382053883291 ,0.11536775372698 ,0 ,-0.034], [0.480860406786873 ,0.903499596111067 ,0.542581424762866 ,32.782593418975 ,0 ,-1]]) def null(A, eps=1e-3): u,s,vh = svd(A,full_matrices=1,compute_uv=1) null_space = compress(s <= eps, vh, axis=0) return null_space.T NS = null(A) print "Null space equals ",NS,"\n" print dot(A,NS)

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  • make a tree based on the key of each element in list.

    - by cocobear
    >>> s [{'000000': [['apple', 'pear']]}, {'100000': ['good', 'bad']}, {'200000': ['yeah', 'ogg']}, {'300000': [['foo', 'foo']]}, {'310000': [['#'], ['#']]}, {'320000': ['$', ['1']]}, {'321000': [['abc', 'abc']]}, {'322000': [['#'], ['#']]}, {'400000': [['yeah', 'baby']]}] >>> for i in s: ... print i ... {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} i want to make a tree based on the key of each element in list. result in logic will be: {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} perhaps a nested list can implement this or I need a tree type?

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  • Django. default=datetime.now() problem

    - by Shamanu4
    Hello. I've such db model: from datetime import datetime class TermPayment(models.Model): dev_session = models.ForeignKey(DeviceSession, related_name='payments') user_session = models.ForeignKey(UserSession, related_name='payment') date = models.DateTimeField(default=datetime.now(),blank=True) sum = models.FloatField(default=0) cnt = models.IntegerField(default=0) class Meta: db_table = 'term_payments' ordering = ['-date'] and here new instance is added: # ... tp = TermPayment() tp.dev_session = self.conn.session # device session hash tp.user_session = self.session # user session hash tp.sum = sum tp.cnt = cnt tp.save() But i've a problem: all records in database have the same value in date field - the date of the first payment. After server restart - one record have new date and others have the same as first after restart. It's look like some data cache is using but I can't found where. database: mysql 5.1.25 django v1.1.1

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  • reading specific lines from a file

    - by MacUsers
    What's the best way of reading only the specific lines (based on matching text) from a file? This is what I'm doing now: match_txt = "lhcb" for inFile in os.listdir('.'): readFile = open(inFile, 'r') lines = readFile.readlines() readFile.close() for line in lines: if line.find(match_txt)==0: #< do stuff here > i.e. I'm reading the lines, only with "lhcb" in it, from all the files in the present directory one by one. Is it the best way of doing that? Can it be done without loading the whole file in the memory in the first place?

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  • How do I do a semijoin using SQLAlchemy?

    - by Jason Baker
    http://en.wikipedia.org/wiki/Relational_algebra#Semijoin Let's say that I have two tables: A and B. I want to make a query that would work similarly to the following SQL statement using the SQLAlchemy orm: SELECT A.* FROM A, B WHERE A.id = B.id AND B.type = 'some type'; The thing is that I'm trying to separate out A and B's logic into different places. So I'd like to make two queries that I can define in separate places: one where A uses B as a subquery, but only returns rows from A. I'm sure this is fairly easy to do, but an example would be nice if someone could show me.

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  • Flask Admin didn't show all fields

    - by twoface88
    I have model like this: class User(db.Model): __tablename__ = 'users' __table_args__ = {'mysql_engine' : 'InnoDB', 'mysql_charset' : 'utf8'} id = db.Column(db.Integer, primary_key=True) username = db.Column(db.String(80), unique=True) email = db.Column(db.String(120), unique=True) _password = db.Column('password', db.String(80)) def __init__(self, username = None, email = None, password = None): self.username = username self.email = email self._set_password(password) def _set_password(self, password): self._password = generate_password_hash(password) def _get_password(self): return self._password def check_password(self, password): return check_password_hash(self._password, password) password = db.synonym("_password", descriptor=property(_get_password, _set_password)) def __repr__(self): return '<User %r>' % self.username I have ModelView: class UserAdmin(sqlamodel.ModelView): searchable_columns = ('username', 'email') excluded_list_columns = ['password'] list_columns = ('username', 'email') form_columns = ('username', 'email', 'password') But no matter what i do, flask admin didn't show password field when i'm editing user info. Is there any way ? Even just to edit hash code. UPDATE: https://github.com/mrjoes/flask-admin/issues/78

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  • Appengine Model SelfReferenceProperty and parent child relationship

    - by GeekTantra
    I have a scenario in which I need a self reference property as follow: class Post(db.Model): creator = db.UserProperty() post_title = db.StringProperty(required=True) post_status = db.StringProperty(required=True, choices=['draft', 'published']) post_parent = db.SelfReferenceProperty() Now, I want ensure that an entity shouldn't be its own parent and a child of an entity cannot be its parent. How can I ensure this kind of a relationship in the PostForm model form and the Post model.

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