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  • One-line expression to map dictionary to another

    - by No Such IP
    I have dictionary like d = {'user_id':1, 'user':'user1', 'group_id':3, 'group_name':'ordinary users'} and "mapping" dictionary like: m = {'user_id':'uid', 'group_id':'gid', 'group_name':'group'} All i want to "replace" keys in first dictionary with keys from second (e.g. replace 'user_id' with 'uid', etc.) I know that keys are immutable and i know how to do it with 'if/else' statement. But maybe there is way to do it in one line expression?

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  • Declaring models elsewhere than in "models.py" AND dynamically

    - by sebpiq
    Hi ! I have an application that splits models into different files. Actually the folder looks like : >myapp __init__.py models.py >hooks ... ... myapp don't care about what's in the hooks, folder, except that there are models, and that they have to be declared somehow. So, I put this in myapp.__init__.py : from django.conf import settings for hook in settings.HOOKS : try : __import__(hook) except ImportError as e : print "Got import err !", e #where settings.HOOKS = ("myapp.hooks.a_super_hook1", ...) The problem is that it doesn't work when I run syncdb(and throws some strange "Got import err !"... strange considering that it's related to another module of my program that I don't even import anywhere :/ ) ! So I tried successively : 1) for hook in settings.HOOKS : try : exec ("from %s import *" % hook) - doesn't work either : syncdb doesn't install the models in hooks 2) from myapp.hooks.a_super_hook1 import * - This works 3) exec("from myapp.hooks.a_super_hook1 import *") - This works to So I checked that in the test 1), the statement executed is the same than in tests 2) and 3), and it is exactly the same ... Any idea ???

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  • Implementing a server side push for a small number of clients

    - by Helper Method
    For an web application I am working on I have the following requirements: Clients need to be able to log in via a web brower. After logging in, they will be able to change configurations (normal request/response) will be able to receive alarms sent by the server (a server side push) Now, the question is how to implement the alarms. I first thought of using some long polling approach (Comet), but as the amount of clients will definitely belimited to 5-10, I'm now thinking to go with a simpler approach. What are the options I have? Would it be okay to just let the clients poll the server? Important aspects are: Alarms should be delivered in (nearly) real-time. Alarms must not get lost (a lost alarm could cause harm to real people).

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  • Selenium selected option in dropdown not displayed correctly

    - by luckyfool
    I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

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  • Strange (atleast for me) behavior in Django template

    - by lud0h
    The following code snippet in a Django template (v 1.1) doesn't work. {{ item.vendors.all.0 }} == returns "Test" but the following code snippet, doesn't hide the paragraph! {% ifnotequal item.vendors.all.0 "Test" %} <p class="view_vendor">Vendor(s): {{item.vendors.all.0}} </p><br /> {% endifnotequal %} Any tips on what's wrong? Thanks.

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  • How to merge or copy anonymous session data into user data when user logs in?

    - by benhoyt
    This is a general question, or perhaps a request for pointers to other open source projects to look at: I'm wondering how people merge an anonymous user's session data into the authenticated user data when a user logs in. For example, someone is browsing around your websites saving various items as favourites. He's not logged in, so they're saved to an anonymous user's data. Then he logs in, and we need to merge all that data into their (possibly existing) user data. Is this done different ways in an ad-hoc fashion for different applications? Or are there some best practices or other projects people can direct me to?

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  • Django model class and custom property

    - by dArignac
    Howdy - today a weird problem occured to me: I have a modle class in Django and added a custom property to it that shall not be saved into the database and therefore is not represent in the models structure: class Category(models.Model): groups = models.ManyToManyField(Group) title = defaultdict() Now, when I'm within the shell or writing a test and I do the following: c1 = Category.objects.create() c1.title['de'] = 'german title' print c1.title['de'] # prints "german title" c2 = Category.objects.create() print c2.title['de'] # prints "german title" <-- WTF? It seems that 'title' is kind of global. If I change title to a simple string it works as expected, so it has to do something with the dict? I also tried setting title as a property: title = property(_title) But that did not work, too. So, how can I solve this? Thank you in advance! enter code here

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  • Yet another list comprehension question

    - by relima
    I had this: if Setting["Language"] == "en": f.m_radioBox3.SetSelection(0) elif Setting["Language"] == "pt": f.m_radioBox3.SetSelection(1) elif Setting["Language"] == "fr": f.m_radioBox3.SetSelection(2) elif Setting["Language"] == "es": f.m_radioBox3.SetSelection(3) Then I did this: Linguas = ["en","pt","fr","es"] a = 0 for i in Linguas: if i == Setting["Language"]: f.m_radioBox3.SetSelection(a) a += 1 Is it possible to further simplify this and make it into a one-liner?

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  • Filtering with joined tables

    - by viraptor
    I'm trying to get some query performance improved, but the generated query does not look the way I expect it to. The results are retrieved using: query = session.query(SomeModel). options(joinedload_all('foo.bar')). options(joinedload_all('foo.baz')). options(joinedload('quux.other')) What I want to do is filter on the table joined via 'first', but this way doesn't work: query = query.filter(FooModel.address == '1.2.3.4') It results in a clause like this attached to the query: WHERE foos.address = '1.2.3.4' Which doesn't do the filtering in a proper way, since the generated joins attach tables foos_1 and foos_2. If I try that query manually but change the filtering clause to: WHERE foos_1.address = '1.2.3.4' AND foos_2.address = '1.2.3.4' It works fine. The question is of course - how can I achieve this with sqlalchemy itself?

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  • Is it okay to rollback code if your client refuses to pay you?

    - by JustinY
    A friend of mine did some contracting work to add localization support to an existing mobile app. He was not contracted to add any other features or fix any already existing bugs. He has finished his work, but the client refuses to pay him because of an already existing bug that he hasn't fixed. The only card my friend has left is to rollback the server code to the state it was before he began working, which will probably break the mobile app and hopefully force the client's hand. Is this legal? Is there a better way to handle the situation?

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  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

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  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

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  • why my code show messy code ..

    - by zjm1126
    class sss(webapp.RequestHandler): def get(self): url = "http://www.google.com/" result = urlfetch.fetch(url) if result.status_code == 200: self.response.out.write(result.content) and this view show : when i change code to this: if result.status_code == 200: self.response.out.write(result.content.decode('utf-8').encode('gb2312')) it show : so ,what i should do ? thanks

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  • Wait until a webpage finished loading to load the next one in a list

    - by envy
    Hi! I'm using PyQT webView to visit some webpages I have stored on a dictionary the code is something like this: def loadLink(self, url): manager = QNetworkAccessManager() request = QNetworkRequest(QUrl(url)) self.ui.webView.load(QUrl(visitar)) def readUnreadLinks(self): print "Links to read: " + str(len(self.unreadLinks)) for link in self.unreadLinks: print "link-> " + str(link) self.loadLink(link) the problem is it doesn't wait until finished loading the web page and starts loading the next one. I want to load a webpage, wait until it finished loading and then load the next one. Thanks, this is driving me crazy :)

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  • OpToSoapDomComv.TRefCache.FNodes contains references to non-existing XMLNodes

    - by Bascy
    In our D2007 application we are using a Webservice, accessed with a THTTPRIO object. When the TDatamodule containing the THTTPRIO object is Destroyed an access violation occurs. This AV is raised when the TSoapDOMConvert is freed, which in turn executes: TRefCache(RefMap[0].Instance).Free calling destructor TRefCache.Destroy; begin FHREFs.Free; FMHREFs.Free; FNodes := nil; //Causes AV end; FNodes is a TInterfaceList containing one reference to IXMLNodes, but the object seems to have been freed before all this. Does anyone know this problem? How to solve it?

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  • Appengine backreferences - need composite index?

    - by davezor
    I have a query that is very recently starting to throw: "The built-in indices are not efficient enough for this query and your data. Please add a composite index for this query." I checked the line on which this exception is being thrown, and the problem query is this one: count = self.vote_set.filter("direction =", 1).count() This is literally a one-filter operation using appengine's built-in backreferences. I have no idea how to optimize this query...anyone have any suggestions? I tried to add this index: - kind: Vote properties: - name: direction direction: desc - kind: Vote properties: - name: direction And I got a message (obviously) saying this was an unnecessary index. Thanks for your help in advance.

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