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  • why java application not working after applying "web look and feel" theme?

    - by Vasu
    I have developed "Employee Management System" java project .For improving the ui appearance i have integrated "web look and feel" into my application.Theme is applied correctly. But here the problem arises: At first i have runned the java application without connecting to oracle data base,application have runned and worked perfectly. But when i connected the application to oracle database and runned again the application is taking more time to open and getting strucked. Code: For applying theme try { WebLookAndFeel.install(); }catch(Exception ex){ ex.printStackTrace(); } Code for Connecting DataBase: if (con == null) { File sd = new File(""); File in = new File(sd.getAbsolutePath() + File.separator + "conf.properties"); File dir = new File(sd.getAbsolutePath() + File.separator + "conf.properties"); if (!dir.exists()) { // dir.mkdir(); dir.createNewFile(); Properties pro = new Properties(); pro.load(new FileInputStream(in)); pro.setProperty("driverclass", "oracle.jdbc.driver.OracleDriver"); pro.setProperty("url", "jdbc:oracle:thin:@192.168.1.1:1521:main"); pro.setProperty("username", "gb16"); pro.setProperty("passwd", "gb16"); try { FileOutputStream out = new FileOutputStream(in); pro.store(out, "Human Management System initialization properties"); out.flush(); out.close();} catch(Exception e) { e.printStackTrace(); } } else { // System.out.println("Already exists "); } Properties pro = new Properties(); pro.load(new FileInputStream(in)); Class.forName(pro.getProperty("driverclass")); con = DriverManager.getConnection(pro.getProperty("url"), pro.getProperty("username"), pro.getProperty("passwd")); st = con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE); st = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_UPDATABLE); } else { return con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_UPDATABLE); } without the theme the application with connected to database working correctly. Please help me in solving this issue. Thanks in advance..

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  • Downloading multimedia content in java from php pages

    - by jmcejuela
    The url: http://www.teamliquid.net/replay/download.php?replay=1830 is a download link to a .rep file. My question is: how to download this content in java knowing the name of the original rep file in order to save it with a defined prefix, like path/_.rep //I was trying to run wget from java but I don't see how to get the original file's name.

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  • Rails routes matching query parameters

    - by Harry Wood
    Rails routes are great for matching RESTful style '/' separated bits of a URL, but can I match query parameters in a map.connect config. I want different controllers/actions to be invoked depending on the presence of a parameter after the '?'. I was trying something like this... map.connect "api/my/path?apple=:applecode", :controller = 'apples_controller', :action = 'my_action' map.connect "api/my/path?banana=:bananacode", :controller = 'bananas_controller', :action = 'my_action' For routing purposes I don't care about the value of the parameter, as long as it is available to the controller in the 'params' hash

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  • is it possible to change the query parameters in REST API from script editor in SOAPUI?

    - by user1518659
    i am doing load test on this REST API using SOAPUI. http://maps.googleapis.com/maps/api/geocode/xml?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false i ve successfully setup the testsuite and all. my doubt is is it possible to change the query parameters in the REST API url by passing values from the script editor(either javascript or groovy) for the test suite when i perform test? if so, how should i write the script? Hope I am clear with my ques.

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  • Get individual query parameters from Uri

    - by Ghostrider
    I have a uri string like: http://example.com/file?a=1&b=2&c=string%20param Is there an existing function that would convert query parameter string into a dictionary same way as ASP.NET Context.Request does it. I'm writing a console app and not a web-service so there is no Context.Request to parse the URL for me. I know that it's pretty easy to crack the query string myself but I'd rather use a FCL function is if exists.

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  • question on rss feed application

    - by molleman
    Hello Guys i just want to create a simple application that will allow a user to input a url to a rss feed and display the contents to a user. what would be a good java library to enable me to read rss feeds? cheers

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  • ASP.Net 4.0 Database Created Pages

    - by Tyler
    I want to create asp.net 4.0 dynamic pages loaded from my MS SQL server. Basically, its a list of locations with informations. For example: Location1 would have the page www.site.com/location/location1.aspx Location44 would have the page www.site.com/location/location44.aspx I dont even know where to start with this, url writting maybe?

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  • Simple Iphone XML Example

    - by dub
    Hi, I a bit overwhelmed with all of the sample code I've seen on the apple dev site. I'm looking for a simple example to show me how to load an xml file from a server into iphone. I would like to read url's from this xml file and load an image.

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  • TouchCode XML parsing error

    - by itsaboutcode
    Hi, I have a xml document which has only one element in the document, which is <error>error string<error> But when i try to parse it, it says this document has no element at all. In other words when i try to access the rootElement it says "null" CXMLDocument *rssParser = [[[CXMLDocument alloc] initWithContentsOfURL:url options:0 error:nil] autorelease]; NSLog(@"Root: %@",[[rssParser rootElement] name]); Please tell me what is wroing with this. Thanks

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  • XML parse file from HTTP

    - by Travis
    I have an XML file located at a location such as http://example.com/test.xml I'm trying to parse the XML file to use it in my program with xPath like this but it is not working. Document doc = builder.parse(new File(url)); How can I get the XML file?

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  • html.actionlink doesn't passing parameter to controller action

    - by FosterZ
    hi, m having problem in passing parameter to controller action, i have done the following Url.Action("SchoolDetails","School",new{id=item.SchoolId}) and my controller action follows public ActionResult SchoolDetails(string schoolId,_ASI_School schoolDetail) { schoolDetail = SchoolRepository.GetSchoolById(schoolId); return View(schoolDetail); } i dn't know why the schoolId above in action is getting null..

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  • FancyBox, Obtaining an ATTR of the item clicked

    - by nobosh
    I have the following lines of code: $("a.quickview").fancybox({ ajax : { type : "POST", data : 'itemID=' + $(this).attr("name") } }); Which is binding on: <a name="614" class="quickview" href="/URL/index.cfm">quick view</a> I want data to post as itemID=614, but $(this).attr("name") is coming back as undefined? What am I doing wrong? Thanks

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  • Redirect question using mod_rewrite (no extensions - root of site)

    - by alex
    Hi, I'm having a small problem with mod_rewrite I have the following in my .htacces: Options +FollowSymlinks RewriteEngine on RewriteRule ^(.+)\.htm$ index.php?name=$1 [NC] This is my index.php file: <?php echo $_GET['name]; ?> This works great for the following url: www.mySite.com/this is an example.htm this would display "this is an example" What i'm trying to do however, is get it to do the same, without the .htm extension: for example: www.mySite.com/this is an example Any ideas? (dont think it's relevant but i'm using xampp to test this)

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  • Zend and web hosting - subdirectory appearing as root

    - by Giuseppe
    I have learned how to create a simple website with the Zend Framework. Now suppose I want to put it on some web hosting server. In my ZF project, I have a folder named public, which I want to appear as the root of the URL. I want my site to be visible and accessible as http://www.mysite.com while being served from a page like /public/index.phtml or similar. How is this done?

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  • Drupal how to set session or cookie?

    - by Gobi
    Hi, i jus friend reference function so i pass the user id through url like below www.example.com?fid=22 i need to set this as a session or cookie which access to all modules in drupal 6. if i set session it return for tht particular module . set cookie is not workin at all. $user-new_property works only on particular page where set if i move to another page no new_property in $user variable object list . Thanxs in advance, Gobi

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  • Django | how to append form field to the urlconf

    - by MMRUser
    I want to pass a form's field value to the next page (template) after user submit the page, the field could be user name, consider the following setup def form_submit(request): if request.method == 'POST': form = UsersForm(request.POST) if form.is_valid(): cd = form.cleaned_data try: newUser = form.save() return HttpResponseRedirect('/mysite/nextpage/') except Exception, ex: return HttpResponse("Ane apoi %s" % str(ex)) else: return HttpResponse('Error') "nextpage" is the template that renders after user submit the form, so I want to know how to append the form's field (user name) to the url and get that value from the view in order to pass it to the next page.. thanks.

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  • IE is not firing ajax call in jquery

    - by VinTem
    I have this code that it is working on firefox and chrome, but in IE8/IE7 it's not working. The server is not been reached ever. $("#adicionarItem").click(function(){ $.ajax({ type: 'GET', url: $("#formAdicionaItem").attr("action"), data: $("#formAdicionaItem").serialize(), success: function(result){ //do something } } }); }); Does anyone has any idea what is wrong? Thanks

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  • will_paginate link to nested resources

    - by neotracker
    Hi, I'm using the will paginate gem from http://github.com/mislav/will_paginate Routes: map.resources :post do |post| post.resources :comments end Post Controller: @post = Post.first @comments = @post.comments.paginate :page => params[:page], :per_page => 10 My problem lies in the view: <%= will_paginate @comments %> This generates links like /post/1?page=1 What I need is /post/1/comments?page=1 Is there a way to just tell will_paginate what url helper to use? (like post_comments_path) Any ideas?

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  • AFNetworking PostPath php Parameters are null

    - by Alejandro Escobar
    I am trying to send a username and password from an iOS app using AFNetworking framework to a php script. The iOS app continues to receive status code 401 which I defined to be "not enough parameters". I have tried returning the "username" from the php script to the iOS app and receive . Based on what I've been investigating so far, it seems as though: 1) The php script is not decoding the POST parameters properly 2) The iOS app is not sending the POST parameters properly The following is the iOS function - (IBAction)startLoginProcess:(id)sender { NSString *usernameField = usernameTextField.text; NSString *passwordField = passwordTextField.text; NSDictionary *parameters = [NSDictionary dictionaryWithObjectsAndKeys:usernameField, @"username", passwordField, @"password", nil]; NSURL *url = [NSURL URLWithString:@"http://localhost/~alejandroe1790/edella_admin/"]; AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:url]; [httpClient defaultValueForHeader:@"Accept"]; [httpClient setParameterEncoding:AFJSONParameterEncoding]; [httpClient postPath:@"login.php" parameters:parameters success:^(AFHTTPRequestOperation *operation, id response) { NSLog(@"operation hasAcceptableStatusCode: %d", [operation.response statusCode]); } failure:^(AFHTTPRequestOperation *operation, NSError *error) { NSLog(@"Error with request"); NSLog(@"%@",[error localizedDescription]); }]; } The following is the php script function checkLogin() { // Check for required parameters if (isset($_POST["username"]) && isset($_POST["password"])) { //Put parameters into local variables $username = $_POST["username"]; $password = $_POST["password"]; $stmt = $this->db->prepare("SELECT Password FROM Admin WHERE Username=?"); $stmt->bind_param('s', $username); $stmt->execute(); $stmt->bind_result($resultpassword); while ($stmt->fetch()) { break; } $stmt->close(); // Username or password invalid if ($password == $resultpassword) { sendResponse(100, 'Login successful'); return true; } else { sendResponse(400, 'Invalid Username or Password'); return false; } } sendResponse(401, 'Not enough parameters'); return false; } I feel like I may be missing something. Any assistance would be great.

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