Search Results

Search found 7452 results on 299 pages for 'closed'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 53/299 | < Previous Page | 49 50 51 52 53 54 55 56 57 58 59 60  | Next Page >

  • Relationship between databases [closed]

    - by user1525474
    Hi I am getting ready to create my first web aplication.I have some knowledge of databases but I have never used databases with relationship created beetween them and also I am not sure how to acces the data in the relationship.My experience is limited to basic CRUD applications and working on simple tables with no realtionship using PHP and MySql. For example I will be creating a login system and for each user I would like to create a profile page that store different data(name , address , profile image etc.).Some of the info will be the same in both tables so there is no point in creating the same table twice. What I would like is if anyone can tell of some tutorials so I can better understand the concept?

    Read the article

  • Why use other bases when programming [closed]

    - by JMD
    Possible Duplicate: Why use other number bases when programming My coworkers and I have been bending our minds to figuring out why anyone would go out of their way to program numbers in a base other than base 10. I suggested that perhaps you could optimize longer equations by putting the variables in the correct base you are working with (for instance, if you have only sets of 5 of something with no remainders you could use base 5), but I'm not sure if that's true. Any thoughts?

    Read the article

  • How To return md5 salted hash? [closed]

    - by user1790627
    Here is the function and this function returns value for sessionGuid. Example, User1 login and join chat then the value of User1 for sessionGuid is. 1 User2 value for sessionGuid is. 2 User3 . value .3 i want this function return md5 salted hash to avoid hacks. function get_current_online_session_login() { $oSrvSec = &App::getModuleService('Account', 'Security'); $login = $oSrvSec->getCurrentUserLogin(); $aReq = getRow(App::getT('online_session'), 'online_session_user = "' . $login . '"'); // return $aReq['online_session_login']; return $aReq['online_session_id']; }

    Read the article

  • Drawning with canvas - problem with sizing [closed]

    - by pioncz
    For example i made 2 canvas with size 500px x 500px and 100px x 100px to see how fillrect works and i found that canvas.fillrect doesnt takes px for arguments, and my question is: how to make pixels as arguments or how to count these arguments for pixels? This is example: <html xmlns="http://www.w3.org/1999/xhtml"> <head> <script type="text/javascript"> function draw() { var canvas = document.getElementById('myCanvas'); var ctx = canvas.getContext('2d'); ctx.fillStyle = '#00f'; ctx.fillRect (0, 0,100, 100); var canvas2 = document.getElementById('myCanvas2'); var ctx2 = canvas2.getContext('2d'); ctx2.fillStyle = '#0f0'; ctx2.fillRect (0, 0, 100, 100); } </script> </head> <body onLoad="draw();"> <canvas id="myCanvas" style="background:black;width:500px;height:500px;display:block;position:absolute;top:0px;left:0px;"> </canvas> <canvas id="myCanvas2" style="background:purple;width:100px;height:100px;display:block;position:absolute;top:0px;left:0px;"> </canvas> </body> </html>

    Read the article

  • Problem inserting in two different tables [closed]

    - by imvarunkmr
    I have written an insert statement which inserts a record into Table1. Table1 has a column "ID" which is an auto_increment(Identity) primary key. How can I fetch the newly generated "ID" and as I need to Insert this value as foreign key in Table2? Note : I have written INSERT statement in a stored procedure and I am calling this procedure using C# Alternative suggestions to link both tables are also welcomed :)

    Read the article

  • export google search results to excel [closed]

    - by Om23
    I want to make a program/script that will be able to take the data from the excel spreadsheet in column A (for example, "team 123") and search Google and take the first 3 results from Google and put the data into the excel spreadsheet. I don't have that much experience in programming. So what language should I use? I know I have to use REST in the Google custom search API- how would I incorporate this? This might have been done before but all I've been able to find is scripts on how to export all the search results or the number of search results, not the first 3 search results. Thanks. If you know better tags for this post please let me know.

    Read the article

  • how httpregistryfilter() in blackberry works?how to use [closed]

    - by Sowjanya
    i am trying to start my application using an url in my device browser. for this i used this: HttpFilterRegistry.registerFilter("www.atsas23.com","com.rim.samples.device.push"); Here this method will registry my application with www.atsas23.com and the second one will call the protocol class ,which is their in com.rim.samples.device.push. Now after doing ,still i am not getting .Means my app is not opening in browser.Can anybody tell why my application is not registering.what is going wrong.

    Read the article

  • Link-building tips? [closed]

    - by RD01
    Possible Duplicate: What is a good way to get many inbound links to your site? I'm probably taking a huge chance here, but I've become a bit desperate. We've paid many a dollar to companies to help push up our page rank, but with no results. I myself have tried everything. Page Rank got up to 5, and now it seems to have gone down to 4. Any advice, even if you point me to an AFFORDABLE and RELIABLE company, I would really appreciate it?

    Read the article

  • Arrays and For Loop [closed]

    - by java
    I wrote this code: import java.io.*; public class dictionary { public static void main(String args[]) { String[] MyArrayE=new String[5]; String[] MyArrayS=new String[5]; String[] MyArrayA=new String[5]; MyArrayE[0]="Language"; MyArrayE[1]="Computer"; MyArrayE[2]="Engineer"; MyArrayE[3]="Home"; MyArrayE[4]="Table"; MyArrayS[0]="Lingua"; MyArrayS[1]="Computador"; MyArrayS[2]="Ing."; MyArrayS[3]="Casa"; MyArrayS[4]="Mesa"; System.out.println("Please enter a word"); BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String word= null; try { word= br.readLine(); } catch (IOException e) { System.out.println("Error!"); System.exit(1); } System.out.println("Your word is " + word); for(int i=0; i<MyArrayA.length; i++) { if(word.equals(MyArrayS[i])) { System.out.println(MyArrayE[i]); } } } } My Question: What about if the user inputs a word not in MyArrayS, I want to check that and print a statement like "Word does not exist". I think that it might look like: if(word!=MyArrayS) { System.out.println("Word does not exist"); }

    Read the article

  • Timer_EntityBody, Timer_ConnectionIdle and Connection Closed Unexpectly

    - by ihsany
    We have a windows application, it connects to a web service (XML web service hosted on a Windows 2008 Server IIS 7.5, no antivirus) and fetches some data to the client. But sometimes (around 5%-10% of the requests), it gives an error when trying to connect web service. Here is the client application error log; Exception:System.Net.WebException: The underlying connection was closed: The connection was closed unexpectedly. at System.Web.Services.Protocols.WebClientAsyncResult.WaitForResponse() at System.Web.Services.Protocols.WebClientProtocol.EndSend(IAsyncResult asyncResult, Object& internalAsyncState, Stream& responseStream) at System.Web.Services.Protocols.SoapHttpClientProtocol.EndInvoke(IAsyncResult asyncResult) at APPClient.APPFPService.WEBService.EndAddMoney(IAsyncResult asyncResult) at APPClient.BLL.ServiceAgent.AddMoneyCallback(IAsyncResult ar) From other hand, on the web server, i checked HTTP error logs and i see a long file like this; 2014-06-05 14:02:04 65.82.178.73 53798 SERVER.IP.ADDRESS 80 - - - - - Timer_ConnectionIdle - 2014-06-05 14:07:24 76.109.81.223 58985 SERVER.IP.ADDRESS 80 - - - - - Timer_ConnectionIdle - 2014-06-05 14:07:39 76.109.81.223 2803 SERVER.IP.ADDRESS 80 - - - - - Timer_ConnectionIdle - 2014-06-05 14:08:59 76.109.81.223 52656 SERVER.IP.ADDRESS 80 - - - - - Timer_ConnectionIdle - 2014-06-05 14:09:05 65.82.178.73 53904 SERVER.IP.ADDRESS 80 HTTP/1.1 POST /webservice/webservice.asmx - 2 Timer_EntityBody SYPService 2014-06-05 14:10:55 50.186.180.191 50648 SERVER.IP.ADDRESS 80 - - - - - Timer_ConnectionIdle - Here is a similar situation but it did not help me. UPDATE: When i checked the IIS logs, i see some issues like these; cs-method cs-uri-stem sc-status sc-win32-status time-taken cs-version POST /webservice/webservice.asmx 400 64 46 HTTP/1.1 POST /webservice/webservice.asmx 400 64 134675 HTTP/1.1 POST /webservice/webservice.asmx 400 64 37549 HTTP/1.1 POST /webservice/webservice.asmx 400 64 109 HTTP/1.1 POST /webservice/webservice.asmx 400 64 31 HTTP/1.1 POST /webservice/webservice.asmx 400 64 0 HTTP/1.1 POST /webservice/webservice.asmx 400 64 15 HTTP/1.1 sc-win32-status 64 : The specified network name is no longer available. sc-status 400 : Bad request Also some requests takes around 130 seconds, but some of less than 1 second. This is a windows application which connects to a web service for process some data. There is not a query takes around 130 seconds on the database.

    Read the article

  • Apache2 configuration error: "<VirtualHost> was not closed" error.

    - by Chris
    So I've already checked through my config file and I really can't see an instance where any tag hasn't been properly closed...but I keep getting this configuration error...Would you mind taking a look through the error and the config file below? Any assistance would be greatly appreciated. FYI, I've already googled the life out of the error and looked through the log extensively, I really can't find anything. Error: apache2: Syntax error on line 236 of /etc/apache2/apache2.conf: syntax error on line 1 of /etc/apache2/sites-enabled/000-default: /etc/apache2/sites-enabled/000-default:1: was not closed. Line 236 of apache2.conf: Include the virtual host configurations: Include /etc/apache2/sites-enabled/ Contents of 000-default: <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /var/www <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost> <VirtualHost *:443> SetEnvIf Request_URI "^/u" dontlog ErrorLog /var/log/apache2/error.log Loglevel warn SSLEngine On SSLCertificateFile /etc/apache2/ssl/apache.pem ProxyRequests Off <Proxy *> AuthUserFile /srv/ajaxterm/.htpasswd AuthName EnterPassword AuthType Basic require valid-user Order Deny,allow Allow from all </Proxy> ProxyPass / http://localhost:8022/ ProxyPassReverse / http://localhost:8022/ </VirtualHost>

    Read the article

  • eXist-db: can't start webstart client on a closed port, reverse proxied via apache

    - by rvdb
    I am configuring an Apache HTTP server so it reverse proxies requests starting with /app/ to an eXist-db instance running in a Tomcat server, on port 8082. This port has been closed in the firewall and is inaccessible to the outer world. Following the eXist documentation, I have following rules in place in my httpd.conf file: ProxyPass /apps/ http://localhost:8082/ ProxyPassReverse /apps/ http://localhost:8082/ ProxyPassReverseCookiePath /apps/ / All goes well for requests to e.g. 'http://mydomain/apps/exist/index.xml'. Yet, the webstart client (accessible at 'http://localhost:8082/exist/webstart/exist.jnlp' on the web server) doesn't work behind the proxy. While 'http://mydomain/apps/exist/webstart/exist.jnlp' does generate a valid exist.jnlp file, that file can't be executed. The reason seems quite obvious: apparently, the eXist-db instance generating the exist.jnlp file only sees the proxied request as: 'http://localhost:8082/exist/webstart/exist.jnlp'. Yet, since the exist.jnlp file is executed on the client, that reference is meaningless (unless the client computer happens to have an eXist-db instance running on that port). Executing the exist.jnlp file hence fails with a 'connection refused' error. Yet, there's no problem at all connecting a local eXist-db Java client to the proxied eXist instance with the URL xmldb:exist://mydomain/apps/exist/xmlrpc. The problem lies in generating the webstart exist.jnlp file, which seems to need access to a publicly accessible URL. However, opening port 8082 and replacing the Proxy references to 'http://localhost:8082' with 'http://mydomain:8082' IMO rather destroys the point of reverse proxying. Do others have had success reverse proxying eXist-db on a closed port behind Apache? Are there perhaps some Proxy configuration settings I have overlooked (I'm no expert at all) that can make eXist see the original request instead of the proxied one? Kind regards, Ron

    Read the article

  • SNMP closed state in CentOS

    - by anksoWX
    I'm having a problem here, I've added to my IPtables rules this: -A INPUT -p tcp -m state --state NEW -m tcp --dport 161 -j ACCEPT -A INPUT -p udp -m state --state NEW -m udp --dport 161 -j ACCEPT but when I scan with nmap or any other tool it says this: Not shown: 998 filtered ports PORT STATE SERVICE 22/tcp open ssh 161/tcp closed snmp also when I am doing: netstat -apn | grep snmpd tcp 0 0 127.0.0.1:199 0.0.0.0:* LISTEN 3669/snmpd<br> udp 0 0 0.0.0.0:161 0.0.0.0:* 3669/snmpd<br> unix 2 [ ] DGRAM 226186 3669/snmpd Also: service iptables status Table: filter Chain INPUT (policy ACCEPT) num target prot opt source destination 1 ACCEPT all -- 0.0.0.0/0 0.0.0.0/0 state RELATED,ESTABLISHED 2 ACCEPT icmp -- 0.0.0.0/0 0.0.0.0/0 3 ACCEPT all -- 0.0.0.0/0 0.0.0.0/0 4 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:161 5 ACCEPT udp -- 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:161 6 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:22 7 REJECT all -- 0.0.0.0/0 0.0.0.0/0 reject-with icmp-host-prohibited Chain FORWARD (policy ACCEPT) num target prot opt source destination 1 REJECT all -- 0.0.0.0/0 0.0.0.0/0 reject-with icmp-host-prohibited Chain OUTPUT (policy ACCEPT) num target prot opt source destination Any idea what's going on? There is no UDP in closed/open state. what do I have to do?

    Read the article

  • ssh - "Connection closed by xxx.xxx.xxx.xxx" - using password

    - by Michael B
    I attempted to create an new user account that I wish to use to log in using ssh. I did this (in CentOs): /usr/sbin/adduser -d /home/testaccount -s /bin/bash user passwd testaccount This is the error I receive when trying to log in via ssh: ~/.ssh$ ssh -v [email protected] OpenSSH_5.1p1 Debian-5ubuntu1, OpenSSL 0.9.8g 19 Oct 2007 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to xxx.xxx.xxx [xxx.xxx.xxx.xxx] port 22. debug1: Connection established. debug1: identity file /home/user/.ssh/identity type -1 debug1: identity file /home/user/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file /home/user/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_4.3 debug1: match: OpenSSH_4.3 pat OpenSSH_4* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.1p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-cbc hmac-md5 none debug1: kex: client->server aes128-cbc hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'xxx.xxx.xxx.xxx' is known and matches the RSA host key. debug1: Found key in /home/user/.ssh/known_hosts:8 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Next authentication method: gssapi-with-mic debug1: Unspecified GSS failure. Minor code may provide more information No credentials cache found debug1: Unspecified GSS failure. Minor code may provide more information No credentials cache found debug1: Unspecified GSS failure. Minor code may provide more information debug1: Next authentication method: publickey debug1: Offering public key: /home/user/.ssh/id_rsa debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Trying private key: /home/user/.ssh/identity debug1: Trying private key: /home/user/.ssh/id_dsa debug1: Next authentication method: password testaccount@xxx's password: Connection closed by xxx.xxx.xxx.xxx The "connection closed" message appeared immediately after entering the password (if I enter the wrong password it waits and then prompts for another password) I am able to log in from the same computer using other accounts that had been setup previously. When logged into the remote machine I am able to do 'su testaccount' Thanks for your time.

    Read the article

  • Tomcat JNDI Connection Pool docs - Random Connection Closed Exceptions

    - by Andy Faibishenko
    I found this in the Tomcat documentation here What I don't understand is why they close all the JDBC objects twice - once in the try{} block and once in the finally{} block. Why not just close them once in the finally{} clause? This is the relevant docs: Random Connection Closed Exceptions These can occur when one request gets a db connection from the connection pool and closes it twice. When using a connection pool, closing the connection just returns it to the pool for reuse by another request, it doesn't close the connection. And Tomcat uses multiple threads to handle concurrent requests. Here is an example of the sequence of events which could cause this error in Tomcat: Request 1 running in Thread 1 gets a db connection. Request 1 closes the db connection. The JVM switches the running thread to Thread 2 Request 2 running in Thread 2 gets a db connection (the same db connection just closed by Request 1). The JVM switches the running thread back to Thread 1 Request 1 closes the db connection a second time in a finally block. The JVM switches the running thread back to Thread 2 Request 2 Thread 2 tries to use the db connection but fails because Request 1 closed it. Here is an example of properly written code to use a db connection obtained from a connection pool: Connection conn = null; Statement stmt = null; // Or PreparedStatement if needed ResultSet rs = null; try { conn = ... get connection from connection pool ... stmt = conn.createStatement("select ..."); rs = stmt.executeQuery(); ... iterate through the result set ... rs.close(); rs = null; stmt.close(); stmt = null; conn.close(); // Return to connection pool conn = null; // Make sure we don't close it twice } catch (SQLException e) { ... deal with errors ... } finally { // Always make sure result sets and statements are closed, // and the connection is returned to the pool if (rs != null) { try { rs.close(); } catch (SQLException e) { ; } rs = null; } if (stmt != null) { try { stmt.close(); } catch (SQLException e) { ; } stmt = null; } if (conn != null) { try { conn.close(); } catch (SQLException e) { ; } conn = null; } }

    Read the article

  • Why do some questions get closed for no reason? [closed]

    - by IVlad
    Recently there was a question asking about generating all subsets of a set using a stack and a queue, which was closed (and now deleted it seems) as not a real question for no good reason, since it didn't fit into any of these conditions: It's difficult to tell what is being asked here. No, it was clear what was being asked. This question is ambiguous, vague, incomplete, or rhetorical and cannot be reasonably answered in its current form. Not ambiguous, not vague, not incomplete, definitely not rhetorical and could easily be answered if one knew the solution. Now, the exact same thing has happened with this question: http://stackoverflow.com/questions/2791982/a-shortest-path-problem-with-superheroes-and-intergalactic-journeys/2793746#2793746 I am interested in hearing a logical argument for why that question is either ambiguous, vague, incomplete, rhetorical or cannot reasonably be answered in its current form. It seems that (the same bunch of) people like to close questions that they think are homework questions, especially when they think people want to be served the solution on a platter, which is also not the case: Any suggestions or ideas of how this problem might be solved would be most welcomed. Most of the time the people asking these questions are very reasonable and appreciate even the most vague idea, yet their question is closed. Let's go further and assume that it IS a homework problem. So what? When I registered here I didn't see any rule that said not to post homework problems, nor do I see such a rule now. What is wrong with posting homework problems that makes people hunt them down with a passion to close them without even reading the entire question body? This site is full of questions asked by people who get paid to know the things they are asking, yet their questions are considered fine. How is solving someone's homework problem worse? In some places (like where I live), computer science is a mandatory high school subject, and not everyone is interested in it. How is helping at least those people worse than doing someone's JOB? Not answering homework questions is fine and it's everyone's choice, but I consider closing them to be an act of power abuse, selfishness, and an insult to the fellow community members who are also interested in a solution or want feedback on their proposed solution. So my questions are: - Why do questions like the above get closed for reasons that do not apply? Why do you close them? Why don't you? - Why doesn't a vote to reopen a question reopen it automatically? Needing 5 votes for a reopen takes too long, and it's not fair because one reopen vote basically cancels out a close vote, making it 4 close votes (or 5 to 1, which is the same as only 4 people wanting to close the question), which isn't enough to close the question. I think a question should only be closed when CloseVotes - ReopenVotes >= 5. I'm hoping this will stay up, but I realize it probably won't. In either case, I think this is worth saying and discussing, since it IS community-related.

    Read the article

  • How to Check if an iFrame is closed?

    - by jl
    Hi, I would like to know is there any way that check if an iframe is closed by user? For example, when I click a link to open up a new _blank browser with the content contained within a iframe. Upon closing the iframe, how can I check if the iframe has been closed? Thank you.

    Read the article

  • Detect non-closed connections to SQL

    - by JoeJoe
    I've inherited a very large project in ASP.net, SQL 2005 and have found where some SQL connections are not closed - which is bad. Without going thru every line of code, is there a way to detect if connections are not being closed? Performance counter? as a follow up - how does SQL reclaim unclosed connections. I'm using non-pooled connectionstring.

    Read the article

  • Apache2 configuration error: "<VirtualHost> was not closed" error

    - by Chris
    So I've already checked through my config file and I really can't see an instance where any tag hasn't been properly closed...but I keep getting this configuration error...Would you mind taking a look through the error and the config file below? Any assistance would be greatly appreciated. FYI, I've already googled the life out of the error and looked through the log extensively, I really can't find anything. Error: apache2: Syntax error on line 236 of /etc/apache2/apache2.conf: syntax error on line 1 of /etc/apache2/sites-enabled/000-default: /etc/apache2/sites-enabled/000-default:1: was not closed. Line 236 of apache2.conf: # Include the virtual host configurations: Include /etc/apache2/sites-enabled/ Contents of 000-default: <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /var/www <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost> <VirtualHost *:443> SetEnvIf Request_URI "^/u" dontlog ErrorLog /var/log/apache2/error.log Loglevel warn SSLEngine On SSLCertificateFile /etc/apache2/ssl/apache.pem ProxyRequests Off <Proxy *> AuthUserFile /srv/ajaxterm/.htpasswd AuthName EnterPassword AuthType Basic require valid-user Order Deny,allow Allow from all </Proxy> ProxyPass / http://localhost:8022/ ProxyPassReverse / http://localhost:8022/ </VirtualHost> UPDATE I had a load of other issues with my install so I wound up just wiping it and reinstalling. If I run into the same problem, I'll repost. Everyone, thanks for your help/suggestions.

    Read the article

  • NHibernate, and odd "Session is Closed!" errors

    - by Sekhat
    Note: Now that I've typed this out, I have to apologize for the super long question, however, I think all the code and information presented here is in some way relevant. Okay, I'm getting odd "Session Is Closed" errors, at random points in my ASP.NET webforms application. Today, however, it's finally happening in the same place over and over again. I am near certain that nothing is disposing or closing the session in my code, as the bits of code that use are well contained away from all other code as you'll see below. I'm also using ninject as my IOC, which may / may not be important. Okay, so, First my SessionFactoryProvider and SessionProvider classes: SessionFactoryProvider public class SessionFactoryProvider : IDisposable { ISessionFactory sessionFactory; public ISessionFactory GetSessionFactory() { if (sessionFactory == null) sessionFactory = Fluently.Configure() .Database( MsSqlConfiguration.MsSql2005.ConnectionString(p => p.FromConnectionStringWithKey("QoiSqlConnection"))) .Mappings(m => m.FluentMappings.AddFromAssemblyOf<JobMapping>()) .BuildSessionFactory(); return sessionFactory; } public void Dispose() { if (sessionFactory != null) sessionFactory.Dispose(); } } SessionProvider public class SessionProvider : IDisposable { ISessionFactory sessionFactory; ISession session; public SessionProvider(SessionFactoryProvider sessionFactoryProvider) { this.sessionFactory = sessionFactoryProvider.GetSessionFactory(); } public ISession GetCurrentSession() { if (session == null) session = sessionFactory.OpenSession(); return session; } public void Dispose() { if (session != null) { session.Dispose(); } } } These two classes are wired up with Ninject as so: NHibernateModule public class NHibernateModule : StandardModule { public override void Load() { Bind<SessionFactoryProvider>().ToSelf().Using<SingletonBehavior>(); Bind<SessionProvider>().ToSelf().Using<OnePerRequestBehavior>(); } } and as far as I can tell work as expected. Now my BaseDao<T> class: BaseDao public class BaseDao<T> : IDao<T> where T : EntityBase { private SessionProvider sessionManager; protected ISession session { get { return sessionManager.GetCurrentSession(); } } public BaseDao(SessionProvider sessionManager) { this.sessionManager = sessionManager; } public T GetBy(int id) { return session.Get<T>(id); } public void Save(T item) { using (var transaction = session.BeginTransaction()) { session.SaveOrUpdate(item); transaction.Commit(); } } public void Delete(T item) { using (var transaction = session.BeginTransaction()) { session.Delete(item); transaction.Commit(); } } public IList<T> GetAll() { return session.CreateCriteria<T>().List<T>(); } public IQueryable<T> Query() { return session.Linq<T>(); } } Which is bound in Ninject like so: DaoModule public class DaoModule : StandardModule { public override void Load() { Bind(typeof(IDao<>)).To(typeof(BaseDao<>)) .Using<OnePerRequestBehavior>(); } } Now the web request that is causing this is when I'm saving an object, it didn't occur till I made some model changes today, however the changes to my model has not changed the data access code in anyway. Though it changed a few NHibernate mappings (I can post these too if anyone is interested) From as far as I can tell, BaseDao<SomeClass>.Get is called then BaseDao<SomeOtherClass>.Get is called then BaseDao<TypeImTryingToSave>.Save is called. it's the third call at the line in Save() using (var transaction = session.BeginTransaction()) that fails with "Session is Closed!" or rather the exception: Session is closed! Object name: 'ISession'. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.ObjectDisposedException: Session is closed! Object name: 'ISession'. And indeed following through on the Debugger shows the third time the session is requested from the SessionProvider it is indeed closed and not connected. I have verified that Dispose on my SessionFactoryProvider and on my SessionProvider are called at the end of the request and not before the Save call is made on my Dao. So now I'm a little stuck. A few things pop to mind. Am I doing anything obviously wrong? Does NHibernate ever close sessions without me asking to? Any workarounds or ideas on what I might do? Thanks in advance

    Read the article

  • ssh tunnel error "ssh_exchange_identification: Connection closed by remote host"

    - by Jacob Ewing
    I'm trying to use an ssh tunnel from my office machine to my home machine, and get an error when I try to use it. What I'm doing is starting one shell like so: ssh -gL 12345:my.home.domain:22 my.home.domain This is giving me a proper shell, no problem. What I normally do then is ssh to my home machine through this office machine, like so: ssh -p 12345 127.0.0.1 This has always worked for me, until last week, when I set up a new system on my home machine (switching from Ubuntu to Debian). Now I get an error. I can still open up my initial ssh connection, but when I try to use that tunnel, I get (on the office machine) this error: ssh_exchange_identification: Connection closed by remote host Also, when that happens, the open shell that I have the tunnelling set up through gets this line spat out at it: channel 3: open failed: connect failed: Connection timed out At which point, I'm at a loss. If any more info is needed, I'll be happy to post it. ============= further to that ============== After fiddling around further, I've found that I'm getting a different response from the server (my home machine that is) when I try to telnet in on the various ports. If I try: telnet my.home.domain 22 I get this back: Trying <my ip address>... Connected to <my domain>. Escape character is '^]'. SSH-2.0-OpenSSH_5.5p1 Debian-6+squeeze2 Which is what I would expect. After setting up the tunnel though, and then telnetting to that, I see this response: Trying 127.0.0.1... Connected to 127.0.0.1. Escape character is '^]'. ============== and further still ================== As per kbulgrien's suggestion, here is the output from the client machine with the -v option: ssh -vp 24600 127.0.0.1 OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to 127.0.0.1 [127.0.0.1] port 24600. debug1: Connection established. debug1: identity file /home/jacob/.ssh/id_rsa type -1 debug1: identity file /home/jacob/.ssh/id_rsa-cert type -1 debug1: identity file /home/jacob/.ssh/id_dsa type -1 debug1: identity file /home/jacob/.ssh/id_dsa-cert type -1 debug1: identity file /home/jacob/.ssh/id_ecdsa type -1 debug1: identity file /home/jacob/.ssh/id_ecdsa-cert type -1 ssh_exchange_identification: Connection closed by remote host

    Read the article

  • TightVNC and Vista yields "VNC server closed connection"

    - by Earlz
    I have forwarded the port 5900 for TightVNC. I have TightVNC 2.0 Beta4 installed on my Windows Vista machine. I then try to connect from an Arch Linux box: [earlz@earlzarch ~]$ vncviewer somehost::5900 Connected to RFB server, using protocol version 3.8 Performing standard VNC authentication Password: Authentication successful vncviewer: VNC server closed connection [earlz@earlzarch ~]$ vncviewer --help TightVNC Viewer version 1.3.10 What is wrong here? I thought that TightVNC 2.0 fixed the Vista bug with VNC servers? Is there any additional configuration I needed?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 49 50 51 52 53 54 55 56 57 58 59 60  | Next Page >