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  • django/apache permissions problem

    - by Kevin
    I'm running a django project on Centos 5.4 and serving it with httpd/mod_wsgi. I can't figure out the correct permissions for /home/website/django_project so that I don't get a 403 error. In my httpd.conf the user and group to run httpd as is apache. The group django is set up with website and apache as members. The owner of /home/website and all subdirs is website:django, and the permissions are rwxrwx---. Right now the project works fine with the dev server, but if I try to view it through apache, I get a 403 error. chmod -R o+rx /home/website/django_project fixes the problem, but this obviously isn't a good solution. Thanks

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  • Looking for python lib to manage remote tasks

    - by Riz
    Hi, I have server with django on it, this server runs some manage.py commands and update database. Now I need to move some of this tasks to different servers. I don't want to allow remote db access and need some tool\lib to be able to start task on remote servers by main server's command and update tasks code/add new tasks. I have ssh access to every server, all servers run under debian and all code in python. I was thiking about creating my own xmpp based solution(server sends messages to slave servers with commands to execute, like "update task", "run task"), or maybe some low-level ssh based solution where main server logs to slave servers and executes bash commands. But I would be happy to hear any advices.

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  • Django logging in and out - doesn't work if prepend_www set

    - by ropz
    I'm a Django beginner. My site - let's call it abc.com - works fine, letting users log in and out (having originally registered via Django registratiaon). If it's relevant, my virtuahosts file has ServerName abc.com and ServerAlias www.abc.com directives. I don't want my visitors to sense that both abc.com and www.abc.com exist, and so discovered Django's prepend_www setting, which works as intended. In addition to working as intended, however, there's a side effect that disables logging in and out when visiting the www. variant of my site.

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  • TypeError while using django Form in editing an Entry

    - by damon
    I have an Entry model which can belong to a Category.I am providing a CategoryChoicesForm sothat the user can choose from various Categorys (from a dropdown list)when an Entry is created or edited. I am having trouble with the CategoryChoicesForm while editing the Entry.It throws a TypeError.. If somebody can make out what is happening..please advise me how to correct this. int() argument must be a string or a number, not 'QueryDict' /home/Django-1.4/django/db/models/fields/__init__.py in get_prep_value, line 537 ...views.py in edit_entry category_choices_form = CategoryChoicesForm(form_data) ... ...forms.py in __init__ self.fields['categoryoption'].queryset = Category.objects.filter(creator=self.creator) Here is the form class CategoryChoicesForm(forms.Form): categoryoption = forms.ModelChoiceField( queryset = Category.objects.none(), required=False,label='Category') def __init__(self, categorycreator,*args, **kwargs): super(CategoryChoicesForm, self).__init__(*args, **kwargs) self.creator=categorycreator self.fields['categoryoption'].queryset = Category.objects.filter(creator=self.creator) The edit_entry view is as follows @login_required @transaction.commit_on_success def edit_entry(request,id,template_name,page_title): form_data = get_form_data(request) entry = get_object_or_404(Entry,pk=id,author=request.user) ... category_choices_form = CategoryChoicesForm(form_data) ...

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  • How to solve 404 for static files with Django and Nginx?

    - by Lucio
    I setup a Trusty VM with Django + Nginx (other stuffs too). The server is working, I get the "Welcome to Django" page. But when I enter to servername/admin it loads the HTML page but fails to load the static content. And the admin page have this links to static content: <link rel="stylesheet" type="text/css" href="/static/admin/css/base.css" /> <link rel="stylesheet" type="text/css" href="/static/admin/css/login.css" /> Both of the CSS files give me 404, as the Nginx log shows: 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin HTTP/1.1" 301 5 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin/ HTTP/1.1" 200 833 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/base.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/login.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" I think that the error is on my nginx.conf file, but do not know how to solve it.

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  • Trouble getting SSL to work with django + nginx + wsgi

    - by Kevin
    I've followed a couple of examples for Django + nginx + wsgi + ssl, but I can't get them to work. I simply get an error in my browser than I can't connect. I'm running two websites off the host. The config files are identical except for the ip addresses, server names, and directories. When neither use SSL, they work fine. When I try to listen on 443 with one of them, I can't connect to either. My config files are below, and any suggestions would be appreciated. server{ listen xxx.xxx.xxx.xxx:80; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } server{ listen xxx.xxx.xxx.xxx:443; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; ssl on; ssl_certificate sub.domain.com.crt; ssl_certificate_key sub.domain.com.key; ssl_prefer_server_ciphers on; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-Forwarded-Protocol https; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } <VirtualHost *:8080> ServerName xxx.xxx.xxx.xxx ServerAlias xxx.xxx.xxx.xxx LogLevel warn ErrorLog /home/django/logs/apache_customerdb_error.log CustomLog /home/django/logs/apache_customerdb_access.log combined WSGIScriptAlias / /home/django/customerdb/apache/django.wsgi WSGIDaemonProcess customerdb_wsgi processes=4 threads=5 WSGIProcessGroup customerdb_wsgi SetEnvIf X-Forwarded-Protocol "^https$" HTTPS=on </VirtualHost> UDPATE: the existence of two sites (on separate IPs) on the host is the issue. if i delete the other site, the setting above mostly work. doing so also brings up another issue: chrome doesn't accept the site as secure saying that some content is not encrypted.

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  • You Don’t Need to Install a Task Manager: How to Manage Running Apps on Android

    - by Chris Hoffman
    Google Play is full of task managers for Android. These utilities can show you apps running in the background, kill running apps, and otherwise manage your apps — but you don’t need to install any third-party software to do this. We’ll show you how to quickly and easily kill and manage your running apps using only the software included with your Android phone. Third-party task managers are unnecessary and many include harmful features, like task killers.    

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  • Manage Your Favorite Social Accounts in Chrome and Iron with Seesmic

    - by Asian Angel
    Are you looking for a way to manage your Twitter, Facebook, Google Buzz, LinkedIn, and Foursquare accounts all in one place? Using the Seesmic Web App for Chrome and Iron you can access your favorite accounts and manage them in a single, simple-to-use interface. A feature that we loved from the start was the ability to access Twitter without creating a special Seesmic account. And in these days of multiple accounts who needs another one to complicate things up? All that you need to do is to sign in with your user name/e-mail along with your password. You do have to authorize access for Seesmic to connect with your account but the whole process (login & authorization) is handled in a single window instance. Now on to a quick look at some of the UI features… The sidebar allows you to add additional columns to the main interface, set your favorite location for Trends, and tie in additional social services as desired. You can also access additional options and controls in the upper right corner. When you are ready to start tweeting click in the blank at the top and enter your text, etc. in the convenient drop-down window that appears. Another nice perk is the ability to switch to a black and grey theme if the white is too bright for your needs. The Seesmic web app provides a simple-to-use, highly efficient way to manage your Twitter account and other favorite social services in a single tab interface. Seesmic [Chrome Web Store] Latest Features How-To Geek ETC Should You Delete Windows 7 Service Pack Backup Files to Save Space? What Can Super Mario Teach Us About Graphics Technology? Windows 7 Service Pack 1 is Released: But Should You Install It? How To Make Hundreds of Complex Photo Edits in Seconds With Photoshop Actions How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) Manage Your Favorite Social Accounts in Chrome and Iron with Seesmic E.T. II – Extinction [Fake Movie Sequel Video] Remastered King’s Quest Games Offer Classic Gaming on Modern Machines Compare Your Internet Cost and Speed to Global Averages [Infographic] Orbital Battle for Terra Wallpaper WizMouse Enables Mouse Over Scrolling on Any Window

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  • How to serve static files for multiple Django projects via nginx to same domain

    - by thanley
    I am trying to setup my nginx conf so that I can serve the relevant files for my multiple Django projects. Ultimately I want each app to be available at www.example.com/app1, www.example.com/app2 etc. They all serve static files from a 'static-files' directory located in their respective project root. The project structure: Home Ubuntu Web www.example.com ref logs app app1 app1 static bower_components templatetags app1_project templates static-files app2 app2 static templates templatetags app2_project static-files app3 tests templates static-files static app3_project app3 venv When I use the conf below, there are no problems for serving the static-files for the app that I designate in the /static/ location. I can also access the different apps found at their locations. However, I cannot figure out how to serve all of the static files for all the apps at the same time. I have looked into using the 'try_files' command for the static location, but cannot figure out how to see if it is working or not. Nginx Conf - Only serving static files for one app: server { listen 80; server_name example.com; server_name www.example.com; access_log /home/ubuntu/web/www.example.com/logs/access.log; error_log /home/ubuntu/web/www.example.com/logs/error.log; root /home/ubuntu/web/www.example.com/; location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; } location /media/ { alias /home/ubuntu/web/www.example.com/media/; } location /app1/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app1; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app1.sock; } location /app2/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app2; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app2.sock; } location /app3/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app3; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app3.sock; } # what to serve if upstream is not available or crashes error_page 400 /static/400.html; error_page 403 /static/403.html; error_page 404 /static/404.html; error_page 500 502 503 504 /static/500.html; # Compression gzip on; gzip_http_version 1.0; gzip_comp_level 5; gzip_proxied any; gzip_min_length 1100; gzip_buffers 16 8k; gzip_types text/plain text/css application/x-javascript text/xml application/xml application/xml+rss text/javascript; # Some version of IE 6 don't handle compression well on some mime-types, # so just disable for them gzip_disable "MSIE [1-6].(?!.*SV1)"; # Set a vary header so downstream proxies don't send cached gzipped # content to IE6 gzip_vary on; } Essentially I want to have something like (I know this won't work) location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; alias /home/ubuntu/web/www.example.com/app/app2/static-files/; alias /home/ubuntu/web/www.example.com/app/app3/static-files/; } or (where it can serve the static files based on the uri) location /static/ { try_files $uri $uri/ =404; } So basically, if I use try_files like above, is the problem in my project directory structure? Or am I totally off base on this and I need to put each app in a subdomain instead of going this route? Thanks for any suggestions TLDR: I want to go to: www.example.com/APP_NAME_HERE And have nginx serve the static location: /home/ubuntu/web/www.example.com/app/APP_NAME_HERE/static-files/;

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  • Looking for a good example usage of get_or _create in Django views and raising a Form error

    - by Rik Wade
    I am looking for a good example of how to achieve the following: I would like to use get_or_create to check whether an object already exists in my database. If it does not, then it will be created. If it does exist, then I will not create the new object, but need to raise a form error to inform the user that they need to enter different data (for example, a different username). The view contains: p, created = Person.objects.get_or_create( email = registration_form.cleaned_data['email'], defaults = { 'creationDate': datetime.datetime.now(), 'dateOfBirth': datetime.date(1970,1,1) }) So 'p' will contain the existing Person if it exists, or the new Person if not. I would like to act on the boolean value in 'created' in order to skip over saving the Person and re-display the registration_form and raise an appropriate form validation error. The alternative I'm considering is doing a check in a custom Form validation method to see whether a Person exists with the data in the provided 'email' field, and just raising a validation error.

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  • Django QuerySet API: How do I join iexact and icontains?

    - by Zeynel
    Hello, I have this join: lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) This is the site If you try Last Name: Abbas and First Name: Amr it tells you that amr abbas has 1 schoolmates. But if you try First name only it says that there are no lawyers in the database called amr (obviously there is). If I change (last__iexact=last_name) to (last__icontains=last_name) then leaving Last Name blank works fine and amr is found. But with last__icontains=last_name if you search for "collin" you also get "collins" and "collingwood" which is not what I want. Do you know how I can use iexact and also have it ignored if it is blank? Thanks This is the view function: def search_form(request): if request.method == 'POST': search_form = SearchForm(request.POST) if search_form.is_valid(): last_name = search_form.cleaned_data['last_name'] first_name = search_form.cleaned_data['first_name'] lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) if len(lawyers)==0: form = SearchForm() return render_to_response('not_in_database.html', {'last': last_name, 'first': first_name, 'form': form}) if len(lawyers)>1: form = SearchForm(initial={'last_name': last_name}) return render_to_response('more_than_1_match.html', {'lawyers': lawyers, 'last': last_name, 'first': first_name, 'form': form}) q_school = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('school', flat=True) q_year = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('year_graduated', flat=True) lawyers1 = Lawyer.objects.filter(school__iexact=q_school[0]).filter(year_graduated__icontains=q_year[0]).exclude(last__icontains=last_name) form = SearchForm() return render_to_response('search_results.html', {'lawyers': lawyers1, 'last': last_name, 'first': first_name, 'form': form}) else: form = SearchForm() return render_to_response('search_form.html', {'form': form, })

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  • Is there a Django template tag that lets me set a context variable?

    - by hekevintran
    I want to be able to set variables in a template to string values. I wrote a tag, but it doesn't seem to change the context. The intended use is: {% define my_var as "a string" %} class DefineNode(Node): def __init__(self, value, variable_name, nodelist): self.value = value self.variable_name = variable_name self.nodelist = nodelist def __repr__(self): return "<DefineNode>" def render(self, context): context[self.variable_name] = self.value return '' @register.tag def define(parser, token): bits = list(token.split_contents()) if len(bits) != 4: raise TemplateSyntaxError("%r expected format is 'value as variable'" % bits[0]) if bits[1][0] in ('"', "'") and bits[1][-1] == bits[1][0]: value = bits[1][1:-1] nodelist = parser.parse(('enddefine',)) parser.delete_first_token() return DefineNode(value, bits[3], nodelist) I

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  • Display a boolean model field in a django form as a radio button rather than the default Checkbox.

    - by Lakshman Prasad
    This is how I went about, to display a Boolean model field in the form as Radio buttons Yes and No. choices = ( (1,'Yes'), (0,'No'), ) class EmailEditForm(forms.ModelForm): #Display radio buttons instead of checkboxes to_send_form = forms.ChoiceField(choices=choices,widget=forms.RadioSelect) class Meta: model = EmailParticipant fields = ('to_send_email','to_send_form') def clean(self): """ A workaround as the cleaned_data seems to contain u'1' and u'0'. There may be a better way. """ self.cleaned_data['to_send_form'] = int(self.cleaned_data['to_send_form']) return self.cleaned_data As you can see in the code above, I need a clean method that converts input string to an integer, which may be unnecessary. Is there a better and/or djangoic way to do this. If so, how? And no, using BooleanField seems to cause a lot more problems. Using that seemed obvious to me; but it isn't. Why is it so.

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  • Django: How can I delete a formset entry if one of it's data is blank?

    - by mkret
    Hi, I have the following scenario: I have a form with data that does not need translation and a formset with a textfield that should be translated into an undefined amount of languages. Both parts are bound to a model. Each translated text is kept in a model with a foreign key that binds it to the untranslatable data. Something like: class Person(models.Model): name = models.CharField(max_length=60) birth_date = models.DateField() class PersonBio(models.Model): person = models.ForeignKey(Person) locale = models.CharField(max_length=10) bio = models.TextField() Each form in the formset has 2 fields: A textfield (with the translated text) A locale field (with the language into which the text was translated) I've got it working with no problems until I tryed to change it's normal behaviour. I wanted to eliminate the need for the DELETE field by deleting an instance of the translated text if the textfield was left blank. I've googled quite a lot now and read the whole documentation for forms, formsets and model validation but had no luck. To be honest, I couldn't even think of a solution. Where should I implement this? On a Form clean() method? On the view? Somewhere in the Fieldset? Fieldset's save() method, maybe? I'll keep trying to find a way to do that, but any help/tip/clue is appreciated. Thanks in advance.

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  • Sorting and indexing into a list in a Django template?

    - by slypete
    How can you perform complex sorting on an object before passing it to the template? For example, here is my view: @login_required def overview(request): physicians = PhysicianGroup.objects.get(pk=physician_group).physicians for physician in physicians.all(): physician.service_patients.order_by('bed__room__unit', 'bed__room__order', 'bed__order') return render_to_response('hospitalists/overview.html', RequestContext(request, {'physicians': physicians,})) The physicians object is not ordered correctly in the template. Why not? Additionally, how do you index into a list inside the template? For example, (this doesn't work): {% for note_type in note_types %} <div><h3>{{ note_type }}</h3> {% for notes in note_sets.index(parent.forloop.counter0) %} #only want to display the notes of this note_type! {% for note in notes %} <p>{{ note }}</p> {% endfor %} {% endfor %} </div> {% endfor %}

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  • Can I filter a django model with a python list?

    - by Rhubarb
    Say I have a model object 'Person' defined, which has a field called 'Name'. And I have a list of people: l = ['Bob','Dave','Jane'] I would like to return a list of all Person records where the first name is not in the list of names defined in l. What is the most pythonic way of doing this?

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  • How do I memoize expensive calculations on Django model objects?

    - by David Eyk
    I have several TextField columns on my UserProfile object which contain JSON objects. I've also defined a setter/getter property for each column which encapsulates the logic for serializing and deserializing the JSON into python datastructures. The nature of this data ensures that it will be accessed many times by view and template logic within a single Request. To save on deserialization costs, I would like to memoize the python datastructures on read, invalidating on direct write to the property or save signal from the model object. Where/How do I store the memo? I'm nervous about using instance variables, as I don't understand the magic behind how any particular UserProfile is instantiated by a query. Is __init__ safe to use, or do I need to check the existence of the memo attribute via hasattr() at each read? Here's an example of my current implementation: class UserProfile(Model): text_json = models.TextField(default=text_defaults) @property def text(self): if not hasattr(self, "text_memo"): self.text_memo = None self.text_memo = self.text_memo or simplejson.loads(self.text_json) return self.text_memo @text.setter def text(self, value=None): self.text_memo = None self.text_json = simplejson.dumps(value)

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  • How do I flag only one of the formsets in django admin ?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). My first solution was to override the validation of the formset but did understand how to do this. (is_correct is displayed as checkbox, and I'd display an error that only one is_correct should be selected.)

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  • How do I modify the HttpResponse object in django ?

    - by Rohit
    I need the html returned using render_to_response to be escaped. I am unable to find any suitable documentation. Can someone point in some direction ? the code is : return render_to_response(template_name, {return render_to_response(template_name, { 'form': form, redirect_field_name: redirect_to, 'site': current_site, 'site_name': current_site.name, }, context_instance=RequestContext(request)) Here I need the response html text to be escaped. I way I know is reading template file in string and escaping it with re.escape() and then rendering it. whats a cleaner and simpler way to do that ??

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  • Django, Redirecting staff from login to the admin site.

    - by Francisco Gomez
    So my site basically has 2 kinds of ways to login, one of them is for the common users, who get the regular screen that asks them for username and password, the other way its for staff. The staff login should redirect them to the admin site after logging in, but for some reason the redirect doesnt happen, it stays on the same login page. I use this condition on the login view. if user is not None and user.is_active and user.is_staff: auth.login(request,user) return HttpResponseRedirect("/admin/") The admin site its up and running in my url configuration and everything, but i dont know if this is the correct way to redirect to the admin site already on session. Thanks, any help would be appreciated.

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  • Django: How to iterate over formsets and access cleaned data?

    - by Mark
    What if I want to do something with my formset other than immediately saving it? How can I do this? for form in vehicles_formset.forms: listing.id = None listing.vehicle_year = form.cleaned_data['year'] listing.vehicle_make = form.cleaned_data['make'] listing.vehicle_model = form.cleaned_data['model'] listing.vin = form.cleaned_data['vin'] listing.vehicle_runs = form.cleaned_data['runs'] listing.vehicle_convertible = form.cleaned_data['convertible'] listing.vehicle_modified = form.cleaned_data['modified'] listing.save() (Thus creating multiple listings) Apparently cleaned_data does not exist. There's a bunch of stuff in the data dict like form-0-year but it's pretty useless to me like that.

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  • How to preprocess a Django model field value before return?

    - by Satoru.Logic
    Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

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