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  • Converting keys of an array/object-tree to lowercase

    - by tstenner
    Im currently optimizing a PHP application and found one function being called around 10-20k times, so I'd thought I'd start optimization there. function keysToLower($obj) { if(!is_object($obj) && !is_array($obj)) return $obj; foreach($obj as $key=>$element) { $element=keysToLower($element); if(is_object($obj)) { $obj->{strtolower($key)}=$element; if(!ctype_lower($key)) unset($obj->{$key}); } else if(is_array($obj) && ctype_upper($key)) { $obj[strtolower($key)]=$element; unset($obj[$key]); } } return $obj; } Most of the time is spent in recursive calls (which are quite slow in PHP), but I don't see any way to convert it to a loop. What would you do?

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  • What is the most efficient approach to fetch category tree, products, brands, counts by subcategory

    - by alex227
    Symfony 1.4 + Doctrine 1.2. What is the best way to minimize the number of queries to retrieve products, subcategories of current category, product counts by subcategory and brand for the result set of the query below? Categories are a nested set. Here is my query: $q = Doctrine_Query::create() ->select('c.*, p.product,p.price, b.brand') ->from('Category c') ->leftJoin('c.Product p') ->leftJoin('p.Brand b') ->where ('c.root_id = ?', $this->category->getRootId()) ->andWhere('c.lft >= ?', $this->category->getLft()) ->andWhere('c.rgt <= ?', $this->category->getRgt()) ->setHydrationMode(Doctrine_Core::HYDRATE_ARRAY); $treeObject = Doctrine::getTable('Category')->getTree(); $treeObject->setBaseQuery($q); $this->treeObject = $treeObject; $treeObject->resetBaseQuery(); $this->products = $q->execute();

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  • How to hide some nodes in Richfaces Tree (do not render nodes by condition)?

    - by VestniK
    I have a tree of categories and courses in my SEAM application. Courses may be active and inactive. I want to be able to show only active or all courses in my tree. I've decided to always build complete tree in my PAGE scope component since building this tree is quite expensive operation. I have boolean flag courseActive in the data wrapped by TreeNode<T>. Now I can't find the way to show courses node only if this flag is true. The best result I've achieved with the following code: <h:outputLabel for="showInactiveCheckbox" value="show all courses: "/> <h:selectBooleanCheckbox id="showInactiveCheckbox" value="#{categoryTreeEditorModel.showAllCoursesInTree}"> <a4j:support event="onchange" reRender="categoryTree"/> </h:selectBooleanCheckbox> <rich:tree id="categoryTree" value="#{categoryTree}" var="item" switchType="ajax" ajaxSubmitSelection="true" reRender="categoryTree,controls" adviseNodeOpened="#{categoryTreeActions.adviseRootOpened}" nodeSelectListener="#{categoryTreeActions.processSelection}" nodeFace="#{item.typeName}"> <rich:treeNode type="Category" icon="..." iconLeaf="..."> <h:outputText value="#{item.title}"/> </rich:treeNode> <rich:treeNode type="Course" icon="..." iconLeaf="..." rendered="#{item.courseActive or categoryTreeEditorModel.showAllCoursesInTree}"> <h:outputText rendered="#{item.courseActive}" value="#{item.title}"/> <h:outputText rendered="#{not item.courseActive}" value="#{item.title}" style="color:#{a4jSkin.inactiveTextColor}"/> </rich:treeNode> </rich:tree> the only problem is if some node is not listed in any rich:treeNode it just still shown with title obtained by Object.toString() method insted of being hidden. Does anybody know how to not show some nodes in the Richfases tree according to some condition?

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  • How hide some nodes in Richfaces Tree (do not render nodes by condition)?

    - by VestniK
    I have a tree of categories and courses in my SEAM application. Courses may be active and inactive. I want to be able to show only active or all courses in my tree. I've decided to always build complete tree in my PAGE scope component since building this tree is quite expensive operation. I have boolean flag courseActive in the data wrapped by TreeNode<T>. Now I can't find the way to show courses node only if this flag is true. The best result I've achieved with the following code: <h:outputLabel for="showInactiveCheckbox" value="show all courses: "/> <h:selectBooleanCheckbox id="showInactiveCheckbox" value="#{categoryTreeEditorModel.showAllCoursesInTree}"> <a4j:support event="onchange" reRender="categoryTree"/> </h:selectBooleanCheckbox> <rich:tree id="categoryTree" value="#{categoryTree}" var="item" switchType="ajax" ajaxSubmitSelection="true" reRender="categoryTree,controls" adviseNodeOpened="#{categoryTreeActions.adviseRootOpened}" nodeSelectListener="#{categoryTreeActions.processSelection}" nodeFace="#{item.typeName}"> <rich:treeNode type="Category" icon="..." iconLeaf="..."> <h:outputText value="#{item.title}"/> </rich:treeNode> <rich:treeNode type="Course" icon="..." iconLeaf="..." rendered="#{item.courseActive or categoryTreeEditorModel.showAllCoursesInTree}"> <h:outputText rendered="#{item.courseActive}" value="#{item.title}"/> <h:outputText rendered="#{not item.courseActive}" value="#{item.title}" style="color:#{a4jSkin.inactiveTextColor}"/> </rich:treeNode> </rich:tree> the only problem is if some node is not listed in any rich:treeNode it just still shown with title obtained by Object.toString() method insted of being hidden. Does anybody know how to not show some nodes in the Richfases tree according to some condition?

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  • Podcast Show Notes: The Red Room Interview &ndash; Part 2

    - by Bob Rhubart
    Room bloggers Sean Boiling, Richard Ward, and Mervin Chaing bring their in-the-trenches perspective to the conversation once again in this week’s edition of the OTN ArchBeat Podcast. Listen. (Missed last week? No problemo: Listen to Part 1) In this segment the conversation turns to SOA governance and balancing the need for reuse against the need for speed.  It’s no mystery that many people react to the term “SOA Governance” in much the same way as they would to the sound of Darth Vader’s respirator. But Mervin explains how a simple change in terminology can go a long way toward lowering blood pressure. Those interested in connecting with Sean, Richard, or Mervin can do so via the links listed below: Sean Boiling - Sales Consulting Manager for Oracle Fusion Middleware LinkedIn | Twitter | Blog Richard Ward - SOA Channel Development Manager at Oracle LinkedIn | Blog Mervin Chiang - Consulting Principal at Leonardo Consulting LinkedIn | Twitter | Blog And you’ll find the complete list of the Red Room SOA Best Practice Posts in last week’s show notes. The third and final segment of the Red Room series runs next week.  I have enough material from the original interview for a fourth program,  but it’ll have to wait. Also, as mentioned last week, the podcast name change is now complete, from Arch2Arch, to ArchBeat. As WPBH-TV9 weatherman Phil Connors says, “Anything different is good.”   Technorati Tags: archbeat,podcast. arch2arch,soa,soa governance,oracle,otn Flickr Tags: archbeat,podcast. arch2arch,soa,soa governance,oracle,otn

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  • Podcast Show Notes: Red Room Interview &ndash; Part 3: Ninja BPM

    - by Bob Rhubart
    The third and final segment of my conversation with Red Room bloggers Sean Boiling, Richard Ward, and Mervin Chaing is now available. Listen to Part 1 Listen to Part 2 Listen to Part 3 As you’ll hear, this segment gets its title from another example of Mervin’s tactic for tweaking terminology to make it easier to sell stakeholders on certain SOA concepts. These are some very bright, very knowledgeable guys, so I encourage you to connect with them via the links below to pick their brains on any SOA or related issues that might have you reaching for the aspirin bottle. Sean Boiling - Sales Consulting Manager for Oracle Fusion Middleware LinkedIn | Twitter | Blog Richard Ward - SOA Channel Development Manager at Oracle LinkedIn | Blog Mervin Chiang - Consulting Principal at Leonardo Consulting LinkedIn | Twitter | Blog Once again, you’ll find the complete list of Red Room SOA Best Practice Posts in here. Up Next Next week’s program features another panel discussion recorded during a virtual min meet-up. The panel includes Oracle ACE Directors Mike van Alst (IT-Eye) and Jordan Braunstein (TUSC) along with The Definitive Guide to SOA: Oracle Service Bus author Jeff Davies. Stay tuned: RSS   Technorati Tags: oracle technology network,oracle,archbeat,podcast. arch2arch,soa,bpm del.icio.us Tags: oracle technology network,oracle,archbeat,podcast. arch2arch,soa,bpm

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  • Efficient representation of Hierarchies in Hibernate.

    - by Alison G
    I'm having some trouble representing an object hierarchy in Hibernate. I've searched around, and haven't managed to find any examples doing this or similar - you have my apologies if this is a common question. I have two types which I'd like to persist using Hibernate: Groups and Items. * Groups are identified uniquely by a combination of their name and their parent. * The groups are arranged in a number of trees, such that every Group has zero or one parent Group. * Each Item can be a member of zero or more Groups. Ideally, I'd like a bi-directional relationship allowing me to get: * all Groups that an Item is a member of * all Items that are a member of a particular Group or its descendants. I also need to be able to traverse the Group tree from the top in order to display it on the UI. The basic object structure would ideally look like this: class Group { ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { ... } /** @return all direct children of this group */ Set<Group> getChildren() { ... } ... } class Item { ... /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { ... } ... } Originally, I had just made a simple bi-directional many-to-many relationship between Items and Groups, such that fetching all items in a group hierarchy required recursion down the tree, and fetching groups for an Item was a simple getter, i.e.: class Group { ... private Set<Item> items; private Set<Group> children; ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { Set<Item> allItems = new HashSet<Item>(); allItems.addAll(this.items); for(Group child : this.getChildren()) { allItems.addAll(child.getAllItems()); } return allItems; } /** @return all direct children of this group */ Set<Group> getChildren() { return this.children; } ... } class Item { ... private Set<Group> groups; /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { return this.groups; } ... } However, this resulted in multiple database requests to fetch the Items in a Group with many descendants, or for retrieving the entire Group tree to display in the UI. This seems very inefficient, especially with deeper, larger group trees. Is there a better or standard way of representing this relationship in Hibernate? Am I doing anything obviously wrong or stupid? My only other thought so far was this: Replace the group's id, parent and name fields with a unique "path" String which specifies the whole ancestry of a group, e.g.: /rootGroup /rootGroup/aChild /rootGroup/aChild/aGrandChild The join table between Groups and Items would then contain group_path and item_id. This immediately solves the two issues I was suffering previously: 1. The entire group hierarchy can be fetched from the database in a single query and reconstructed in-memory. 2. To retrieve all Items in a group or its descendants, we can select from group_item where group_path='N' or group_path like 'N/%' However, this seems to defeat the point of using Hibernate. All thoughts welcome!

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  • How can I create a new branch in git from an existing file tree?

    - by pkaeding
    I am looking to add an existing file tree to a git repository as a new branch (I can't just copy the existing tree into my git tree, since the existing tree is versioned under a different VCS, and I am trying to sync them up). Is this possible? EDIT: Would setting up a new git repository, that is connected to the existing remote repository, and then moving the resulting .git folder work? That seems really hackish, but if that's the way to do it...

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  • Auto-Suggest via &lsquo;Trie&rsquo; (Pre-fix Tree)

    - by Strenium
    Auto-Suggest (Auto-Complete) “thing” has been around for a few years. Here’s my little snippet on the subject. For one of my projects, I had to deal with a non-trivial set of items to be pulled via auto-suggest used by multiple concurrent users. Simple, dumb iteration through a list in local cache or back-end access didn’t quite cut it. Enter a nifty little structure, perfectly suited for storing and matching verbal data: “Trie” (http://tinyurl.com/db56g) also known as a Pre-fix Tree: “Unlike a binary search tree, no node in the tree stores the key associated with that node; instead, its position in the tree defines the key with which it is associated. All the descendants of a node have a common prefix of the string associated with that node, and the root is associated with the empty string. Values are normally not associated with every node, only with leaves and some inner nodes that correspond to keys of interest.” This is a very scalable, performing structure. Though, as usual, something ‘fast’ comes at a cost of ‘size’; fortunately RAM is more plentiful today so I can live with that. I won’t bore you with the detailed algorithmic performance here - Google can do a better job of such. So, here’s C# implementation of all this. Let’s start with individual node: Trie Node /// <summary> /// Contains datum of a single trie node. /// </summary> public class AutoSuggestTrieNode {     public char Value { get; set; }       /// <summary>     /// Gets a value indicating whether this instance is leaf node.     /// </summary>     /// <value>     ///     <c>true</c> if this instance is leaf node; otherwise, a prefix node <c>false</c>.     /// </value>     public bool IsLeafNode { get; private set; }       public List<AutoSuggestTrieNode> DescendantNodes { get; private set; }         /// <summary>     /// Initializes a new instance of the <see cref="AutoSuggestTrieNode"/> class.     /// </summary>     /// <param name="value">The phonetic value.</param>     /// <param name="isLeafNode">if set to <c>true</c> [is leaf node].</param>     public AutoSuggestTrieNode(char value = ' ', bool isLeafNode = false)     {         Value = value;         IsLeafNode = isLeafNode;           DescendantNodes = new List<AutoSuggestTrieNode>();     }       /// <summary>     /// Gets the descendants of the pre-fix node, if any.     /// </summary>     /// <param name="descendantValue">The descendant value.</param>     /// <returns></returns>     public AutoSuggestTrieNode GetDescendant(char descendantValue)     {         return DescendantNodes.FirstOrDefault(descendant => descendant.Value == descendantValue);     } }   Quite self-explanatory, imho. A node is either a “Pre-fix” or a “Leaf” node. “Leaf” contains the full “word”, while the “Pre-fix” nodes act as indices used for matching the results.   Ok, now the Trie: Trie Structure /// <summary> /// Contains structure and functionality of an AutoSuggest Trie (Pre-fix Tree) /// </summary> public class AutoSuggestTrie {     private readonly AutoSuggestTrieNode _root = new AutoSuggestTrieNode();       /// <summary>     /// Adds the word to the trie by breaking it up to pre-fix nodes + leaf node.     /// </summary>     /// <param name="word">Phonetic value.</param>     public void AddWord(string word)     {         var currentNode = _root;         word = word.Trim().ToLower();           for (int i = 0; i < word.Length; i++)         {             var child = currentNode.GetDescendant(word[i]);               if (child == null) /* this character hasn't yet been indexed in the trie */             {                 var newNode = new AutoSuggestTrieNode(word[i], word.Count() - 1 == i);                   currentNode.DescendantNodes.Add(newNode);                 currentNode = newNode;             }             else                 currentNode = child; /* this character is already indexed, move down the trie */         }     }         /// <summary>     /// Gets the suggested matches.     /// </summary>     /// <param name="word">The phonetic search value.</param>     /// <returns></returns>     public List<string> GetSuggestedMatches(string word)     {         var currentNode = _root;         word = word.Trim().ToLower();           var indexedNodesValues = new StringBuilder();         var resultBag = new ConcurrentBag<string>();           for (int i = 0; i < word.Trim().Length; i++)  /* traverse the trie collecting closest indexed parent (parent can't be leaf, obviously) */         {             var child = currentNode.GetDescendant(word[i]);               if (child == null || word.Count() - 1 == i)                 break; /* done looking, the rest of the characters aren't indexed in the trie */               indexedNodesValues.Append(word[i]);             currentNode = child;         }           Action<AutoSuggestTrieNode, string> collectAllMatches = null;         collectAllMatches = (node, aggregatedValue) => /* traverse the trie collecting matching leafNodes (i.e. "full words") */             {                 if (node.IsLeafNode) /* full word */                     resultBag.Add(aggregatedValue); /* thread-safe write */                   Parallel.ForEach(node.DescendantNodes, descendandNode => /* asynchronous recursive traversal */                 {                     collectAllMatches(descendandNode, String.Format("{0}{1}", aggregatedValue, descendandNode.Value));                 });             };           collectAllMatches(currentNode, indexedNodesValues.ToString());           return resultBag.OrderBy(o => o).ToList();     }         /// <summary>     /// Gets the total words (leafs) in the trie. Recursive traversal.     /// </summary>     public int TotalWords     {         get         {             int runningCount = 0;               Action<AutoSuggestTrieNode> traverseAllDecendants = null;             traverseAllDecendants = n => { runningCount += n.DescendantNodes.Count(o => o.IsLeafNode); n.DescendantNodes.ForEach(traverseAllDecendants); };             traverseAllDecendants(this._root);               return runningCount;         }     } }   Matching operations and Inserts involve traversing the nodes before the right “spot” is found. Inserts need be synchronous since ordering of data matters here. However, matching can be done in parallel traversal using recursion (line 64). Here’s sample usage:   [TestMethod] public void AutoSuggestTest() {     var autoSuggestCache = new AutoSuggestTrie();       var testInput = @"Lorem ipsum dolor sit amet, consectetur adipiscing elit. Integer nec odio. Praesent libero.                 Sed cursus ante dapibus diam. Sed nisi. Nulla quis sem at nibh elementum imperdiet. Duis sagittis ipsum. Praesent mauris.                 Fusce nec tellus sed augue semper porta. Mauris massa. Vestibulum lacinia arcu eget nulla. Class aptent taciti sociosqu ad                 litora torquent per conubia nostra, per inceptos himenaeos. Curabitur sodales ligula in libero. Sed dignissim lacinia nunc.                 Curabitur tortor. Pellentesque nibh. Aenean quam. In scelerisque sem at dolor. Maecenas mattis. Sed convallis tristique sem.                 Proin ut ligula vel nunc egestas porttitor. Morbi lectus risus, iaculis vel, suscipit quis, luctus non, massa. Fusce ac                 turpis quis ligula lacinia aliquet. Mauris ipsum. Nulla metus metus, ullamcorper vel, tincidunt sed, euismod in, nibh. Quisque                 volutpat condimentum velit. Class aptent taciti sociosqu ad litora torquent per conubia nostra, per inceptos himenaeos. Nam                 nec ante. Sed lacinia, urna non tincidunt mattis, tortor neque adipiscing diam, a cursus ipsum ante quis turpis. Nulla                 facilisi. Ut fringilla. Suspendisse potenti. Nunc feugiat mi a tellus consequat imperdiet. Vestibulum sapien. Proin quam. Etiam                 ultrices. Suspendisse in justo eu magna luctus suscipit. Sed lectus. Integer euismod lacus luctus magna. Quisque cursus, metus                 vitae pharetra auctor, sem massa mattis sem, at interdum magna augue eget diam. Vestibulum ante ipsum primis in faucibus orci                 luctus et ultrices posuere cubilia Curae; Morbi lacinia molestie dui. Praesent blandit dolor. Sed non quam. In vel mi sit amet                 augue congue elementum. Morbi in ipsum sit amet pede facilisis laoreet. Donec lacus nunc, viverra nec.";       testInput.Split(' ').ToList().ForEach(word => autoSuggestCache.AddWord(word));       var testMatches = autoSuggestCache.GetSuggestedMatches("le"); }   ..and the result: That’s it!

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  • Can I use CodeSynthesis XSD (C++/Tree mapping) together with a GPLv3-licensed library?

    - by Erik Sjölund
    Is it possible to write an open source project that uses generated code from CodeSynthesis XSD (C++/Tree) and then link it to a third-party library that is licensed under the GPL version 3? Some background information: CodeSynthesis XSD is licensed under the GPL version 2 but with an extra FLOSS exception (http://www.codesynthesis.com/projects/xsd/FLOSSE). C++ source code generated from CodeSynthesis XSD (C++/Tree) needs to be linked against Xerces (http://xerces.apache.org/xerces-c/) that is licensed under the Apache License 2.0. Update I posted a similar question on the xsd-users mailing list two years ago but I didn't fully understand the answers. In that email thread, I wrote: I think it is the GPL version 3 software that doesn't allow itself be linked to software that can't be "relicensed" to GPL version 3 ( for instance GPL version 2 software ). That would also include XSD as the FLOSS exception doesn't give permission to "relicense" XSD to GPL version 3.

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  • Black screen while booting, after installing installing AMD Catalyst™ 12.8 Proprietary Linux x86 Display Driver on HP pavilion dm4

    - by Megharaj
    HP Pavilion dm4 with configuration as shown below cpu intel Core i5 2.26 GHz RAM 4.0 GB Graphics processor 512MB ATI Mobility Radeon(TM) HD 5450 switchable graphics [HDMI, VGA]. I installed ubuntu 10.04 ( without AMD graphics driver) it was working fine, but when I installed AMD graphics drivers AMD Catalyst™ 12.8 Proprietary Linux x86 Display Driver, than the problem started from then When I boot I was get black screen. Than I thought to upgrade from ubuntu 10.04 to 12.04 using the bootable pen drive but was getting black screen than read on some forums that was because of the switchable graphics, than upgraded ubuntu 12.04 by setting to "nomodeset". It was working, again thought to install graphics driver AMD Catalyst™ 12.8 Proprietary Linux x86 Display Driver, again after installing this, when I boot I am getting blank scree . Can anyone help me to inatall ubuntu 12.04 along with AMD Catalyst™ 12.8 Proprietary Linux x86 Display Driver. Any help is highly appreciated.

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  • Ubuntu 13.04 boot into black screen, even after installing nvidia drivers, fail at: "Starting Reload cups, upon starting avahi-daemon..."

    - by Elad92
    I got a new machine with i7 4770k and gefore gtx660. I installed windows and then installed Ubuntu 13.04. In the installation everything went well, after the installation I again boot from the USB and choose try ubuntu, and installed boot-repair because windows automatically boot with no option for ubuntu. After I repaired the boot, I restarted and got into grub, when I chose Ubuntu I got message saying I'm running on low graphics mode and when I pressed ok the screen turned off. I couldn't do anything so I restarted and after reading this post: My computer boots to a black screen, what options do I have to fix it? I got into recovery, selected dpkg and repaired packages. Then I rebooted, and tried to press 'e' and change quiet splash to no splash and nomodeset but unfortunately both of them didn't work, and not the screen didn't get turned off, but I just saw a blank screen. So I rebooted again, entered the recovery, and this time I went to the root shell, and tried to install nvidia drivers from this guide here: http://www.howopensource.com/2012/10/install-nvidia-geforce-driver-in-ubuntu-12-10-12-04-using-ppa/ I rebooted and got the same black screen again (the screen didn't go off, just saw a blank screen). In the grub I see that the kernel is 3.8.0-25. I also checked that the usb files are not corrupted using the check CD from the ubuntu installation screen. I'm really frustrated, I don't know what else can I do. (If someone also knows how can I connect to wifi using the root shell it will be very appreciated, because when I choose the 'enable networking' it again booting me to a black screen. Thanks Edit After digging more, I again boot with nomodeset and saw where is it failing, this is the lines I saw: * Starting Reload cups, upon starting avahi-daemon to make sure remote queues are populated [OK] * Starting Reload cups, upon starting avahi-daemon to make sure remote queues are populated [fail] I searched for it in google and this is the closest result I got: http://ubuntuforums.org/showthread.php?t=2144261 i didn't find any way to solve it in the internet, from what I understand this is a problem with 13.04. If someone knows how to fix it I will be very grateful. Thanks Edit 2 - 23.6.13 As Mitch suggested, I disabled the avahi-daemon, and when I boot in nomodeset I get the following error: What else can be the problem?

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  • How to discriminate from two nodes with identical frequencies in a Huffman's tree?

    - by Omega
    Still on my quest to compress/decompress files with a Java implementation of Huffman's coding (http://en.wikipedia.org/wiki/Huffman_coding) for a school assignment. From the Wikipedia page, I quote: Create a leaf node for each symbol and add it to the priority queue. While there is more than one node in the queue: Remove the two nodes of highest priority (lowest probability) from the queue Create a new internal node with these two nodes as children and with probability equal to the sum of the two nodes' probabilities. Add the new node to the queue. The remaining node is the root node and the tree is complete. Now, emphasis: Remove the two nodes of highest priority (lowest probability) from the queue Create a new internal node with these two nodes as children and with probability equal to the sum of the two nodes' probabilities. So I have to take two nodes with the lowest frequency. What if there are multiple nodes with the same low frequency? How do I discriminate which one to use? The reason I ask this is because Wikipedia has this image: And I wanted to see if my Huffman's tree was the same. I created a file with the following content: aaaaeeee nnttmmiihhssfffouxprl And this was the result: Doesn't look so bad. But there clearly are some differences when multiple nodes have the same frequency. My questions are the following: What is Wikipedia's image doing to discriminate the nodes with the same frequency? Is my tree wrong? (Is Wikipedia's image method the one and only answer?) I guess there is one specific and strict way to do this, because for our school assignment, files that have been compressed by my program should be able to be decompressed by other classmate's programs - so there must be a "standard" or "unique" way to do it. But I'm a bit lost with that. My code is rather straightforward. It literally just follows Wikipedia's listed steps. The way my code extracts the two nodes with the lowest frequency from the queue is to iterate all nodes and if the current node has a lower frequency than any of the two "smallest" known nodes so far, then it replaces the highest one. Just like that.

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  • Is there a keyboard shortcut to toggle Tree view / Places View?

    - by zinzolin
    I find both the Tree view and the Places view useful. Changing from one view to the other is not fast because one have to go into the appearance menu. It's even slower with Oneiric because this menu can now be far away. (Before Unity, I always had the tree view on and I used my bookmarks directly from the Places menu. That was fine) Is there a keyboard shortcut to toggle from one view to the other? Or is it possible to create one oneself? Thanks a lot the help !

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  • Example usage of a custom delegate in c#

    - by Freakishly
    Hi, I found this question on SO about a tree implementation in C#. I have no idea about delegates and I was wondering how the following code could be used to implement a tree. Also, what would be the most efficient way to keep a track of parent nodes? delegate void TreeVisitor<T>(T nodeData); class NTree<T> { T data; LinkedList<NTree<T>> children; public NTree(T data) { this.data = data; children = new LinkedList<NTree<T>>(); } public void addChild(T data) { children.AddFirst(new NTree<T>(data)); } public NTree<T> getChild(int i) { foreach (NTree<T> n in children) if (--i == 0) return n; return null; } public void traverse(NTree<T> node, TreeVisitor<T> visitor) { visitor(node.data); foreach (NTree<T> kid in node.children) traverse(kid, visitor); } }

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  • Deeply nested subqueries for traversing trees in MySQL

    - by nickf
    I have a table in my database where I store a tree structure using the hybrid Nested Set (MPTT) model (the one which has lft and rght values) and the Adjacency List model (storing parent_id on each node). my_table (id, parent_id, lft, rght, alias) This question doesn't relate to any of the MPTT aspects of the tree but I thought I'd leave it in in case anyone had a good idea about how to leverage that. I want to convert a path of aliases to a specific node. For example: "users.admins.nickf" would find the node with alias "nickf" which is a child of one with alias "admins" which is a child of "users" which is at the root. There is a unique index on (parent_id, alias). I started out by writing the function so it would split the path to its parts, then query the database one by one: SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users';-- 1 SELECT `id` FROM `my_table` WHERE `parent_id` = 1 AND `alias` = 'admins'; -- 8 SELECT `id` FROM `my_table` WHERE `parent_id` = 8 AND `alias` = 'nickf'; -- 37 But then I realised I could do it with a single query, using a variable amount of nesting: SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users' ) AND `alias` = 'admins' ) AND `alias` = 'nickf'; Since the number of sub-queries is dependent on the number of steps in the path, am I going to run into issues with having too many subqueries? (If there even is such a thing) Are there any better/smarter ways to perform this query?

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  • How to get child nodes after store load

    - by Azincourt
    Version: ExtJs 4.1 To change the child items I use this function: TreeStore (Ext.data.TreeStore) storeId : 'treeStore', ... constructor: function( oConfig ) { ... this.on( 'expand', function( oObj ) { oObj.eachChild(function(oNode) { switch(oNode.data.type) { case "report": oNode.set('icon', strIconReport); break; case "view": oNode.set('icon', strIconView); break; } }); }); Reload After removing or adding items in the tree, I reload the tree somewhere else with: var oStore = Ext.getStore('treeStore'); oStore.load({ node : oNode, params : { newpath : oNode.data.path, overwrite : true } }); Although it is the same store treeStore, after loading and expanding to the correct path, the icons are not changed since the .on( 'expand') function is not called. Why? Question How can I change the icons of this newly loaded store before it expands to the node path? What I tried Before calling .load() I tried to edit the children with oNode.eachChild(function(oChild) {} but no success.

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  • SQL Server Developer Tools &ndash; Codename Juneau vs. Red-Gate SQL Source Control

    - by Ajarn Mark Caldwell
    So how do the new SQL Server Developer Tools (previously code-named Juneau) stack up against SQL Source Control?  Read on to find out. At the PASS Community Summit a couple of weeks ago, it was announced that the previously code-named Juneau software would be released under the name of SQL Server Developer Tools with the release of SQL Server 2012.  This replacement for Database Projects in Visual Studio (also known in a former life as Data Dude) has some great new features.  I won’t attempt to describe them all here, but I will applaud Microsoft for making major improvements.  One of my favorite changes is the way database elements are broken down.  Previously every little thing was in its own file.  For example, indexes were each in their own file.  I always hated that.  Now, SSDT uses a pattern similar to Red-Gate’s and puts the indexes and keys into the same file as the overall table definition. Of course there are really cool features to keep your database model in sync with the actual source scripts, and the rename refactoring feature is now touted as being more than just a search and replace, but rather a “semantic-aware” search and replace.  Funny, it reminds me of SQL Prompt’s Smart Rename feature.  But I’m not writing this just to criticize Microsoft and argue that they are late to the party with this feature set.  Instead, I do see it as a viable alternative for folks who want all of their source code to be version controlled, but there are a couple of key trade-offs that you need to know about when you choose which tool set to use. First, the basics Both tool sets integrate with a wide variety of source control systems including the most popular: Subversion, GIT, Vault, and Team Foundation Server.  Both tools have integrated functionality to produce objects to upgrade your target database when you are ready (DACPACs in SSDT, integration with SQL Compare for SQL Source Control).  If you regularly live in Visual Studio or the Business Intelligence Development Studio (BIDS) then SSDT will likely be comfortable for you.  Like BIDS, SSDT is a Visual Studio Project Type that comes with SQL Server, and if you don’t already have Visual Studio installed, it will install the shell for you.  If you already have Visual Studio 2010 installed, then it will just add this as an available project type.  On the other hand, if you regularly live in SQL Server Management Studio (SSMS) then you will really enjoy the SQL Source Control integration from within SSMS.  Both tool sets store their database model in script files.  In SSDT, these are on your file system like other source files; in SQL Source Control, these are stored in the folder structure in your source control system, and you can always GET them to your file system if you want to browse them directly. For me, the key differentiating factors are 1) a single, unified check-in, and 2) migration scripts.  How you value those two features will likely make your decision for you. Unified Check-In If you do a continuous-integration (CI) style of development that triggers an automated build with unit testing on every check-in of source code, and you use Visual Studio for the rest of your development, then you will want to really consider SSDT.  Because it is just another project in Visual Studio, it can be added to your existing Solution, and you can then do a complete, or unified single check-in of all changes whether they are application or database changes.  This is simply not possible with SQL Source Control because it is in a different development tool (SSMS instead of Visual Studio) and there is no way to do one unified check-in between the two.  You CAN do really fast back-to-back check-ins, but there is the possibility that the automated build that is triggered from the first check-in will cause your unit tests to fail and the CI tool to report that you broke the build.  Of course, the automated build that is triggered from the second check-in which contains the “other half” of your changes should pass and so the amount of time that the build was broken may be very, very short, but if that is very, very important to you, then SQL Source Control just won’t work; you’ll have to use SSDT. Refactoring and Migrations If you work on a mature system, or on a not-so-mature but also not-so-well-designed system, where you want to refactor the database schema as you go along, but you can’t have data suddenly disappearing from your target system, then you’ll probably want to go with SQL Source Control.  As I wrote previously, there are a number of changes which you can make to your database that the comparison tools (both from Microsoft and Red Gate) simply cannot handle without the possibility (or probability) of data loss.  Currently, SSDT only offers you the ability to inject PRE and POST custom deployment scripts.  There is no way to insert your own script in the middle to override the default behavior of the tool.  In version 3.0 of SQL Source Control (Early Access version now available) you have that ability to create your own custom migration script to take the place of the commands that the tool would have done, and ensure the preservation of your data.  Or, even if the default tool behavior would have worked, but you simply know a better way then you can take control and do things your way instead of theirs. You Decide In the environment I work in, our automated builds are not triggered off of check-ins, but off of the clock (currently once per night) and so there is no point at which the automated build and unit tests will be triggered without having both sides of the development effort already checked-in.  Therefore having a unified check-in, while handy, is not critical for us.  As for migration scripts, these are critically important to us.  We do a lot of new development on systems that have already been in production for years, and it is not uncommon for us to need to do a refactoring of the database.  Because of the maturity of the existing system, that often involves data migrations or other additional SQL tasks that the comparison tools just can’t detect on their own.  Therefore, the ability to create a custom migration script to override the tool’s default behavior is very important to us.  And so, you can see why we will continue to use Red Gate SQL Source Control for the foreseeable future.

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  • FREE! SQL Scripts Manager – a Christmas gift from Red Gate

    Red Gate has released SQL Scripts Manager, a free tool containing over 25 scripts written by SQL Server experts, to help you automate common troubleshooting, diagnostic, and maintenance tasks. Join SQL Backup’s 35,000+ customers to compress and strengthen your backups "SQL Backup will be a REAL boost to any DBA lucky enough to use it." Jonathan Allen. Download a free trial now.

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  • What's happening in Red Gate's .NET Developer Tools division?

    .NET 4.0, Silverlight 4, F# decompilation in .NET Reflector, our crazy shipping schedule, and some prize draw winners. Yes, with a list of topics that broad, it can only be another update on what's happening in Red Gate's .NET Developer Tools division....Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • SSTP BPDU with bad TLV and macflap -- info please

    - by Adeodatus
    Hi All, I'm slowly locking down the network I've inherited and mac-flapping has been a problem in the past with customers doing all kinds of crazy things. Thats changing but I am now encountering this error: Dec 30 18:31:31 10.50.1.50 1565: 001567: Dec 30 18:31:30: %SW_MATM-4-MACFLAP_NOTIF: Host xxxx.xxxx.f681 in vlan 1 is flapping between port Gi0/5 and port Gi0/48 Dec 30 18:43:28 10.50.1.50 1566: 001568: Dec 30 18:43:26: %SPANTREE-2-RECV_BAD_TLV: Received SSTP BPDU with bad TLV on GigabitEthernet0/5 VLAN1. Dec 30 18:48:18 10.50.1.50 1567: 001569: .Dec 30 18:48:17: %SPANTREE-2-RECV_BAD_TLV: Received SSTP BPDU with bad TLV on GigabitEthernet0/5 VLAN1. unfortunately, that mac address is the mac of our core router, the only link to the internet, on port gi0/48 On the other end of gi0/5, I have about 50 bridged customer machines connected through a series of managed and unmanaged L2 switches. Yes, on VLAN1 too ... like I said, working on changing this slowly. In the mean time, it has me quite baffled on how to deal with this and track down the customer or switch that is the problem. What else could be going on with these messages ... the bad TLV is a new one for me. Any ideas? Thank you and Happy New Year to you all!!

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  • Confirm that two filesystems are identical, ignoring special files

    - by endolith
    /media/A and /media/B should be identical, but I want to confirm before deleting one. Duplicate file finders don't work, because they'll find two copies of the same file within B, for instance. I only want to confirm that every file in one is identical to the other. diff -qr /media/A/ /media/B/ seems to work, but the output is cluttered with garbage like diff: /media/A//etc/alternatives/ControlPanel: No such file or directory and File /media/A//dev/tty8 is a character special file while file /media/B//dev/tty8 is a character special file I can suppress the former with 2> /dev/null, but I don't know about the latter. rsync -avn /media/A/ /media/B/ also produces a bunch of clutter, like "skipping non-regular file". How can I compare the two trees and just make sure that all the real files exist in both and are identical?

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