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  • Very simple mod_rewrite questions

    - by Camran
    1- Does mod_rewrite means that if I make this url: domain.com/ad.php?id=8498292 INTO domain.com/8498292 that all links on my website will have to be changed to the later above? example the link: domain.com/ad.php?id=8498292 wont work now, unless I replace it with domain.com/8498292 ? Or will the server know that they are the same still? 2- Will the rewritten link appear rewritten in the browsers adress bars also, so if I enter domain.com/ad.php?id=8498292 it will actually appear as domain.com/8498292 in the adress bar itself? 3- Will images and all other related links and material on the page whose link is rewritten remain intact? ie will pictures and links still work FROM that page which are relative? Thanks

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  • Program using read() entering into an infinite loop

    - by Soham
    1oid ReadBinary(char *infile,HXmap* AssetMap) { int fd; size_t bytes_read, bytes_expected = 100000000*sizeof(char); char *data; if ((fd = open(infile,O_RDONLY)) < 0) err(EX_NOINPUT, "%s", infile); if ((data = malloc(bytes_expected)) == NULL) err(EX_OSERR, "data malloc"); bytes_read = read(fd, data, bytes_expected); if (bytes_read != bytes_expected) printf("Read only %d of %d bytes %d\n", \ bytes_read, bytes_expected,EX_DATAERR); /* ... operate on data ... */ printf("\n"); int i=0; int counter=0; char ch=data[0]; char message[512]; Message* newMessage; while(i!=bytes_read) { while(ch!='\n') { message[counter]=ch; i++; counter++; ch =data[i]; } message[counter]='\n'; message[counter+1]='\0'; //--------------------------------------------------- newMessage = (Message*)parser(message); MessageProcess(newMessage,AssetMap); //-------------------------------------------------- //printf("idNUM %e\n",newMessage->idNum); free(newMessage); i++; counter=0; ch =data[i]; } free(data); } Here, I have allocated 100MB of data with malloc, and passed a file big enough(not 500MB) size of 926KB about. When I pass small files, it reads and exits like a charm, but when I pass a big enough file, the program executes till some point after which it just hangs. I suspect it either entered an infinite loop, or there is memory leak. EDIT For better understanding I stripped away all unnecessary function calls, and checked what happens, when given a large file as input. I have attached the modified code void ReadBinary(char *infile,HXmap* AssetMap) { int fd; size_t bytes_read, bytes_expected = 500000000*sizeof(char); char *data; if ((fd = open(infile,O_RDONLY)) < 0) err(EX_NOINPUT, "%s", infile); if ((data = malloc(bytes_expected)) == NULL) err(EX_OSERR, "data malloc"); bytes_read = read(fd, data, bytes_expected); if (bytes_read != bytes_expected) printf("Read only %d of %d bytes %d\n", \ bytes_read, bytes_expected,EX_DATAERR); /* ... operate on data ... */ printf("\n"); int i=0; int counter=0; char ch=data[0]; char message[512]; while(i<=bytes_read) { while(ch!='\n') { message[counter]=ch; i++; counter++; ch =data[i]; } message[counter]='\n'; message[counter+1]='\0'; i++; printf("idNUM \n"); counter=0; ch =data[i]; } free(data); } What looks like is, it prints a whole lot of idNUM's and then poof segmentation fault I think this is an interesting behaviour, and to me it looks like there is some problem with memory FURTHER EDIT I changed back the i!=bytes_read it gives no segmentation fault. When I check for i<=bytes_read it blows past the limits in the innerloop.(courtesy gdb)

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  • Problem Making C++ script

    - by Abs
    Hello all, I am not sure if I can post this sort of question (apologies in advance) but I am trying to build something from this blog post. # mkdir wkthumb # cat > wkthumb.cpp # qmake -project # qmake && make # ./wkthumb I have no experience with this, but I download all the files needed in the directory wkthumb using git. I have gone inside this directory and tried to execute cat > wkthumb.cpp - this just hangs for me. In addition, I thought cat was supposed to be used like this: cat file1.txt file2.txt > file3.txt? The above is blank with the first arguments? I am using Fedora Core 10.

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  • Is git revert broken?

    - by sabgenton
    The following pastebin is a repo with one file with one, two, three, four, five typed on each line. Each line was commited separately into git: http://pastebin.ca/raw/2136179 I then tried to delete the line two with the command git revert <commmit which creates two> And get: error: could not revert b4e0a66... second hint: after resolving the conflicts, mark the corrected paths hint: with 'git add <paths>' or 'git rm <paths>' hint: and commit the result with 'git commit' There should be no conflict for something this simple? Or am I doing it wrong/got the wrong command? The merge details don't seem to make sense either: one <<<<<<< HEAD two three four five ======= >>>>>>> parent of b4e0a66... second Isn't that saying delete everything but one? I was expecting only two to be affected... git 1.7.10

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  • How to get line count from variable (from MYSQL query)?

    - by Mint
    My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"` $testMYSQL now contains: test test test Then I do: TEST=$(echo $testMYSQL | wc -l) echo "$TEST" I would of thought that would work, but it doesn't, it returns 1 But if I put this into $testMYSQL: "test\ntest\ntest" it will say 3… Whats going on here? does MYSQL not use new lines? PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

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  • Memory Regions displayed in SMAPS output with no permissions

    - by crissangel
    If I see the output of cat /proc//smaps, I find that there are some memory regions with which no read/write/execute permissions have been associated. Also these region are mapped to inode number 0. I wanted to know how does a region end up in such a state? Is it some sort of memory leak? Can these regions be ever used again by the process?

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  • task_current redundant field

    - by user341940
    Hi, I'm writing a kernel module that reads from a /proc file. When someone writes into the /proc file the reader will read it, but if it reads again while there is no "new" write, it should be blocked. In order to remember if we already read, i need to keep a map of the latest buffer that process read. To avoid that, I was told that there might be some redundant field inside the current- (task_struct struct) that i can use to my benefits in order to save some states on the current process. How can I find such fields ? and how can i avoid them being overwritten ? I read somewhere that i can use the offset field inside the struct in order to save my information there and i need to block lseek operations so that field will stay untouched. How can I do so ? and where is that offset field, i can't find it inside the task_Struct. Thanks and I need to save for each process some information in order to map it against other information. I can write a ma

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  • What scripts should not be ported from bash to python?

    - by Jack
    I decided to rewrite all our Bash scripts in Python (there are not so many of them) as my first Python project. The reason for it is that although being quite fluent in Bash I feel it's somewhat archaic language and since our system is in the first stages of its developments I think switching to Python now will be the right thing to do. Are there scripts that should always be written in Bash? For example, we have an init.d daemon script - is it OK to use Python for it? We run CentOS. Thanks.

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  • Why thread specific data is required in pthread ?

    - by user504542
    Hi As i know, all the threads share memory location. For example a global variable changes in one thread will reflect in another thread. Since each thread has its own stack, the local variables that are created inside the thread is unique. In this case, why do we need to go for thread specific data mechanism?. Can't it be achieved by auto storage varibles inside the thread function ? Kindly clarify!!!. BR Rj

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  • Synchronization between user space process and interupt context code

    - by user1748950
    Recently I attended couple of interviews. Out of all kernel questions which were asked, thr is one specific question which I couldnt find convincing answer of. How will you use different synchronization techniques while sharing data between user space process and interrupt context function? My convincing answer was: In interrupt context code: 1. do *spin_lock_irqsave* 2. access data buffer which is shared between user space app and kernel 3. do *spin_lock_irqrestore* Then this was not convincing answer. Do I have to do irqsave and irqrestore in all the instances of data access? Regards, Yogi

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  • How to fill a structure when a pointer to it, is passed as an argument to a function

    - by Ram
    I have a function: func (struct passwd* pw) { struct passwd* temp; struct passwd* save; temp = getpwnam("someuser"); /* since getpwnam returns a pointer to a static * data buffer, I am copying the returned struct * to a local struct. */ if(temp) { save = malloc(sizeof *save); if (save) { memcpy(save, temp, sizeof(struct passwd)); /* Here, I have to update passed pw* with this save struct. */ *pw = *save; /* (~ memcpy) */ } } } The function which calls func(pw) is able to get the updated information. But is it fine to use it as above. The statement *pw = *save is not a deep copy. I do not want to copy each and every member of structure one by one like pw-pw_shell = strdup(save-pw_shell) etc. Is there any better way to do it? Thanks.

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  • Use sudo su - <username> to access the <username's> account but sudo su - shouldn't be possible with a sudo user

    - by Winnie
    There is a requirement I got. My sudo users (for which their entry in sudoers file) should be able to access other user's account say Oracle using following command: sudo su - Oracle The above should work with giving current users password. But if the same user is firing the following command, sudo su - it shouldn't work and thus root access shouldnt be given to current user. I am not using su because because i dont want current user to know the credentials of other user(root,Oracle etc.). Can anyone please help me . Its urgent...

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  • find string from the file in somewhere

    - by lightmanhk
    I want to find a string from some file in subdirectory. Like we are in bundle/. and in bundle/ there are multiple subdirectories and multiple txt files I want to do something like find . -type f -exec grep "\<F8\>" {} \; want to get the file where it contain string < F8 this command does work, find the string, but never return filename I hope anyone can give me a better solution to this, like display filename along with the line containing that string

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  • Is this time related process accounting stats gathering appropriate?

    - by Ceko Cakata
    Based on sys/acct.h (V1, not V3) I need to gather some user usage statistics based on a parser that parser the acct file line by line. The parser will run and parse the entire file every N seconds and I need to gather user statistics accumulated since the last run (N seconds back). I'm not sure what will be the most appropriate way to do it based on the info provided by sys/acct.h. Maybe something like this: if ((ac_btime + ac_etime) < (current_time - N)) { gather; } Also comp_t is said to be "floating-point value consisting of a 3-bit, base-8 exponent, and a 13-bit mantissa", but I think u_int16_t is just a unsigned short int. Should I be converting it to long it with the provided formula or not?

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  • sed: group capturing

    - by Michael
    Is there any way to tell sed to output only captured groups? for example given by input: This is a sample 123 text and some 987 numbers and pattern /([\d]+)/ I could get only 123 and 987 output in the way formatted by back references perhaps?

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  • Testing shared memory ,strange thing happen

    - by barfatchen
    I have 2 program compiled in 4.1.2 running in RedHat 5.5 , It is a simple job to test shared memory , shmem1.c like following : #define STATE_FILE "/program.shared" #define NAMESIZE 1024 #define MAXNAMES 100 typedef struct { char name[MAXNAMES][NAMESIZE]; int heartbeat ; int iFlag ; } SHARED_VAR; int main (void) { int first = 0; int shm_fd; static SHARED_VAR *conf; if((shm_fd = shm_open(STATE_FILE, (O_CREAT | O_EXCL | O_RDWR), (S_IREAD | S_IWRITE))) > 0 ) { first = 1; /* We are the first instance */ } else if((shm_fd = shm_open(STATE_FILE, (O_CREAT | O_RDWR), (S_IREAD | S_IWRITE))) < 0) { printf("Could not create shm object. %s\n", strerror(errno)); return errno; } if((conf = mmap(0, sizeof(SHARED_VAR), (PROT_READ | PROT_WRITE), MAP_SHARED, shm_fd, 0)) == MAP_FAILED) { return errno; } if(first) { for(idx=0;idx< 1000000000;idx++) { conf->heartbeat = conf->heartbeat + 1 ; } } printf("conf->heartbeat=(%d)\n",conf->heartbeat) ; close(shm_fd); shm_unlink(STATE_FILE); exit(0); }//main And shmem2.c like following : #define STATE_FILE "/program.shared" #define NAMESIZE 1024 #define MAXNAMES 100 typedef struct { char name[MAXNAMES][NAMESIZE]; int heartbeat ; int iFlag ; } SHARED_VAR; int main (void) { int first = 0; int shm_fd; static SHARED_VAR *conf; if((shm_fd = shm_open(STATE_FILE, (O_RDWR), (S_IREAD | S_IWRITE))) < 0) { printf("Could not create shm object. %s\n", strerror(errno)); return errno; } ftruncate(shm_fd, sizeof(SHARED_VAR)); if((conf = mmap(0, sizeof(SHARED_VAR), (PROT_READ | PROT_WRITE), MAP_SHARED, shm_fd, 0)) == MAP_FAILED) { return errno; } int idx ; for(idx=0;idx< 1000000000;idx++) { conf->heartbeat = conf->heartbeat + 1 ; } printf("conf->heartbeat=(%d)\n",conf->heartbeat) ; close(shm_fd); exit(0); } After compiled : gcc shmem1.c -lpthread -lrt -o shmem1.exe gcc shmem2.c -lpthread -lrt -o shmem2.exe And Run both program almost at the same time with 2 terminal : [test]$ ./shmem1.exe First creation of the shm. Setting up default values conf->heartbeat=(840825951) [test]$ ./shmem2.exe conf->heartbeat=(1215083817) I feel confused !! since shmem1.c is a loop 1,000,000,000 times , how can it be possible to have a answer like 840,825,951 ? I run shmem1.exe and shmem2.exe this way,most of the results are conf-heartbeat will larger than 1,000,000,000 , but seldom and randomly , I will see result conf-heartbeat will lesser than 1,000,000,000 , either in shmem1.exe or shmem2.exe !! if run shmem1.exe only , it is always print 1,000,000,000 , my question is , what is the reason cause conf-heartbeat=(840825951) in shmem1.exe ? Update: Although not sure , but I think I figure it out what is going on , If shmem1.exe run 10 times for example , then conf-heartbeat = 10 , in this time shmem1.exe take a rest and then back , shmem1.exe read from shared memory and conf-heartbeat = 8 , so shmem1.exe will continue from 8 , why conf-heartbeat = 8 ? I think it is because shmem2.exe update the shared memory data to 8 , shmem1.exe did not write 10 back to shared memory before it took a rest ....that is just my theory... i don't know how to prove it !!

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