Search Results

Search found 31707 results on 1269 pages for 'php jedi'.

Page 537/1269 | < Previous Page | 533 534 535 536 537 538 539 540 541 542 543 544  | Next Page >

• Check if a variable is empty

  - by Thomas

  I have some user-submitted variables that I want to display in a different part of my site like this: <div class="pre_box">Term: </div> <div class="entry"><?php $key='term'; echo get_post_meta($post->ID, $key, true); ?></div> Occasionally, these variables might be empty in which case I don't want to display the label for the empty variable. In the example above I would want to hide the <div class="pre_box">Term: </div> part. Is there some simple way to check if a php variable like the one above is empty and prevent the label from being displayed?

  Read the article

• Regular Expression issue

  - by Christian Sciberras

  I have the following URL structure which I need to match to and get the particular id from: /group/subgroup/id-name In short, I need to translate a URL like the following: /Blue Products/Dark Blue/5-Blue_Jelly To: /?pagename=Blue Products&model=5 IMPORTANT: I don't need to match group, I already have group. Example code: <?php foreach($cats as $cat) $cmd->rewrite('/\/'.$cat.'\/unused\/(ID)-unused\//','/?pagename='.$cat.'&model=%ID%'); ?> Edit: This is the completed code: if($groups->count()){ $names=array(); foreach($groups->rows as $row) $names[]=preg_quote($row->group); $names=implode('|',$names); $regex='('.$names.')/([^/]+)/([0-9]{1,})-([^/]+)/?$'; CmsHost::cms()->rewrite_url($regex,'index.php?pagename=Products',true); }

  Read the article

• How to structure web application with part of it being secured (SSL)

  - by spirytus

  What is the common pattern to structure web application where part of it has to be secured. So lets say I have page_a and page_b which do not need to be secured, although should display login information (login fields or login details once user logged in). This web app. also would have secured pages (admin, checkout or similar) secure_page_c and secure_page_d. My questions are: What is the common folder structure for such assuming I code in php with no frameworks? Also how shall I deal with session variables in case user navigates lets say from secure_page_b to non secure page_a or vice versa? What else might be a problem and should be considered when coding that kind of app in php? Thank you all for any suggestions

  Read the article

• problem in showing utf8 letters in jquery

  - by Mac Taylor

  hey guys i made a jquery script similar to wordpress that can show slugged title from an input box while user is typing $(function() { $(".word").keyup(function() { var word= $(this).val(); var inputmirror = $('#plink'); inputmirror.val(word); $.post("slug.php"+"&title="+word, function(data){ $('#preshow').html(data).fadeIn("slow"); }); return false; }); }); and php file : $title = $_GET['title']; if (!empty($title)) { echo Slugit($title); } everything works fine unless when i enter arabic letters in input box it shows coded characters like this : http://mysite.info/this-is-arabic-%d8%a7%d9%84%d9%84%d9%87

  Read the article

• Turning a spreadsheet into array and loop and call a function

  - by Anders

  This is related to generate groups in BuddyPress. I have a spreadsheet with (in this case) a group name, group description and slug. I need to grab the information from the file, turn it into an array, then loop through it and call groups_create_group() every time. I can find that function in bp-groups.php (http://www.nomorepasting.com/getpaste.php?pasteid=35217). It tells me all the parameters you need to fill in. I'm quite new to this and looking for how I can do this. Do you know how I can grab this information and turn it into an array? An loop it through and call groups_create_group() every time?

  Read the article

• PHP 5.5 sort en Alpha1 et introduit les générateurs, le block Finally ainsi qu'une API de hachage des mots de passe

  PHP 5.5 sort en Alpha 1 et introduit les générateurs, le block Finally ainsi qu'une API de hachage des mots de passe Le cycle de publication de PHP 5.5.0 vient officiellement de débuter. Les développeurs de la plateforme Web ont publié la première version Alpha de PHP 5.5.0. PHP 5.5.0 apporte des nouvelles fonctionnalités majeures au langage, dont le support des générateurs. Les générateurs sont un moyen simple et puissant de créer des itérateurs. L'introduction des générateurs dans PHP va permettre aux développeurs d'implémenter des itérateurs sans avoir à écrire beaucoup de code décoratif. Le support des générateurs s'accompagne de l'introduction du nouveau mot c...

  Read the article

• SQL Server instead of MYSQL in WAMP

  - by Vish

  Hi, We have an application which uses WAMP server. Now, there is a new requirement from a customer who wants to use MS SQL Server instead of MySQL. How easy is it to port to SQL Server from MySQL. Also it has to retain this configuration. Apache-PHP-SQL Server on windows. How can I connect from Apache to SQL Server. Hope PHP works well with SQL server. Please advise. Thanks, Vish

  Read the article

• Send JSON object via GET and POST without having to wrapping it in another object literal, and manag

  - by Kucebe

  My site does some short ajax call in JSON format, using jQuery. At client-side i'd like to send object just passing it in ajax function, without being forced to wrap it in an object literal like this: {'person' : person}. For the same reasons, at server-side i'd like to manage objects without the binding of $_GET['person'] or $_POST['person']. For example: var person = { 'name' : 'John', 'lastName' : 'Doe', 'age' : 32, 'married' : true } sendAjaxRequest(person); in php, using: $person = json_decode(file_get_contents("php://input")); i can get easily the object, but only with POST format, not in GET. Any suggestions?

  Read the article

• Default controller name is removed on browser refresh (CodeigniterPHP/Nginx issue?)

  - by tim peterson

  For all pages in my codeigniter app except my default controller, when I refresh the browser the url isn't affected as one would expect. However for my default controller, main.php, when when I refresh the browser at "http://localhost/main" or "http://mysite.com/main", the main part is stripped off the url. So the browser bar shows just "http://localhost" or "http://mysite.com". Totally lost on where to start with this but was just wondering if anyone has come across this before...? Here's what I think could be the relevant part of my nginx.conf (if Nginx is the problem). if ($request_uri ~* ^(/main(/index)?|/index(.php)?)/?$) { rewrite ^(.*)$ / permanent; }

  Read the article

• How to generate a .po file?

  - by tobefound

  On Windows using WAMPserver (Apache, MySql, Php) I have the following: //test.php if (!defined('LC_MESSAGES')) define('LC_MESSAGES', 6); $lang = "sv"; putenv("LANG=$lang"); setlocale(LC_ALL, $lang); $domain = "messages"; bindtextdomain($domain, "./locale"); textdomain($domain); echo _("This is a string"); It works fine, i.e. it outputs "This is a string" which means I have gettext correctly setup up. But HOW in the world do I create a .po-file? I downloaded POEdit but I can't see how to make this happen with that software. ANy help is greatly appreciated!

  Read the article

• Is it possible to disable the iPhone's automatic hyperlinks?

  - by mririgo

  We send out a notification email whenever we have "phishing" emails reported to us. In these emails, we include a copy-paste of the text inside the original phishing email as a sample of what is reported to us. Our code strips all hyperlinks out of the email via PHP, but still includes (in plain text) the link. When users receive this email in their client (Thunderbird, Outlook, Horde/IMP, etc), the hyperlink is removed. However, the iPhone likes to take web addresses in plain text and automatically turn them into hyperlinks. Is there any possible way to stop this action from happening via a HTML tag or by using PHP to replace certain parts of the hyperlink?

  Read the article

• put one image on the other one

  - by newprog

  Hello How can I put one image on the other one with php? Thank`s for help

  Read the article

• How do I alter the Epitwitter scripts to post to twitter from a web form?

  - by waterfallrain

  Hello, I am trying to update my twitter status with php and outh using the Epitwitter scripts. The following is the textarea of the web form I created to allow me to update twitter. <textarea name="updatestatus" cols="50" rows="4" id="updatestatus"> </textarea> Do I change this line in my confirm.php script from $status = 'Testing API'; To this $status=$_POST["updatestatus"]; I am wanting to know if I at least got that right so I can look at other possible problems with this form not being able to update twitter. As it stands now I am manually editing the status each time and it works that way perfectly but have not yet figured out how to get a webform to do this.

  Read the article

• Suggestions for performance improvement surrounding sending email notifications?

  - by jcmoney

  It takes around a couple of seconds for my app to execute the code to send an email right now on a test server with nothing much else running. Not sure if this is typical/expected. I'm also using the php framework Kohana's email helper and not php's mail directly out of convenience if that matters. Is it always just better to schedule a cron job to send emails every 5 min or so? Or should I be able to send emails immediately and I'm just not doing something right? What the script does is insert a row into the db and notifies the relevant group that the row was created. The groups are usually < 20 people so I just do a loop calling Kohana's email helper each time for each member of the group.

  Read the article

• Lazy loading? Better avoiding it?

  - by Charlie Pigarelli

  I just read about this design pattern: Lazy Load. And, since in the application i'm working on i have all the classes in one folder, i was wondering if this pattern could just make me avoiding the include() function for every class. I mean: It's nice to know that if i forgot to include a class, PHP, before falling into an error, trough an __autoload() function try to get it. But is it fine enough to just don't care about including classes and let PHP do it by your own every time? Or we should write __autoload() just in case it is needed?

  Read the article

• After tar extract, Changing Permissions

  - by Moe

  Just a Question Regarding unix and PHP today. What I am doing on my PHP is using the Unix system to untar a tarred file. exec("tar -xzf foo.tar.gz"); Generally everything works fine until I run into this particular foo.tar.gz, which has a file system as follows: Applications/ Library/ Systems/ After running the tar command, it seems that the file permissions get changed to 644 (instead of 755). This causes Permission denied (errno 13) and therefore disabling most of my code. (I'm guessing from lack of privileges) Any way I can stop this tar command completely ruining my permissions? Thanks. Oh and this seems to only happen when I have a foo.tar.gz file that Has this particular file system. Anything else and I'm good.

  Read the article

• Basic javascript function

  - by McDan Garrett

  I have this function working <script type="text/javascript"> $(window).scroll(function() { if ($(window).scrollTop() == $(document).height() - $(window).height()) { $('div#loadmoreajaxloader').show(); $.ajax({ url: "loadmore.php?wall=<?php echo $wall; ?>&lastid=" + $(".postitem:last").attr("id"), success: function(html) { if (html) { $("#postswrapper").append(html); $('div#loadmoreajaxloader').hide(); } else { $('div#loadmoreajaxloader').html('<center><font color="white">No more posts to show.</font></center>'); } } }); } }); </script> But I need to have the same stuff happening (on IOS Devices), but instead of it happening when the browser reaches the loadmoreajaxeloader div, I simply need it to happen on an onclick event on a link. Thanks heaps. Tried to add code but didn't format so here it is http://pastebin.com/p2VUqZff

  Read the article

• How can I generate XML application configuration using Zend_Tool?

  - by wimvds

  When creating a new project using zf create project myproject it will create a default project layout with an application.ini in the configs folder. Where can I change these default settings so that it generates (and uses) an XML file (application.xml)? I've looked at the documentation for Zend_Tool (http://framework.zend.com/manual/en/zend.tool.html), but there seems to be no information on how to do this. And suppose you'd like to use a different default folder layout (ie. use htdocs instead of public as your document root), is there a way to specify this as well? Any pointers to relevant information (btw I've looked at the Quickstart, nothing relevant is mentioned there unless I'm overlooking it)? edit I already tried creating a profile (stored in .zf/project/profiles), and used that to create a project (using zf create project myproject myprofile) but that doesn't change anything, even though the .zfproject.xml file in the root of the new project does contain the <applicationConfigFile type="xml"/> setting... The new project contains this (as you can see, it's just the default settings, only the type of applicationConfigFile has been changed) : <?xml version="1.0"?> <projectProfile type="default" version="1.10"> <projectDirectory> <projectProfileFile filesystemName=".zfproject.xml"/> <applicationDirectory classNamePrefix="Application_"> <apisDirectory enabled="false"/> <configsDirectory> <applicationConfigFile type="xml"/> </configsDirectory> <controllersDirectory> <controllerFile controllerName="Index"> <actionMethod actionName="index"/> </controllerFile> <controllerFile controllerName="Error"/> </controllersDirectory> <formsDirectory enabled="false"/> <layoutsDirectory enabled="false"/> <modelsDirectory/> <modulesDirectory enabled="false"/> <viewsDirectory> <viewScriptsDirectory> <viewControllerScriptsDirectory forControllerName="Index"> <viewScriptFile forActionName="index"/> </viewControllerScriptsDirectory> <viewControllerScriptsDirectory forControllerName="Error"> <viewScriptFile forActionName="error"/> </viewControllerScriptsDirectory> </viewScriptsDirectory> <viewHelpersDirectory/> <viewFiltersDirectory enabled="false"/> </viewsDirectory> <bootstrapFile filesystemName="Bootstrap.php"/> </applicationDirectory> <dataDirectory enabled="false"> <cacheDirectory enabled="false"/> <searchIndexesDirectory enabled="false"/> <localesDirectory enabled="false"/> <logsDirectory enabled="false"/> <sessionsDirectory enabled="false"/> <uploadsDirectory enabled="false"/> </dataDirectory> <docsDirectory> <file filesystemName="README.txt"/> </docsDirectory> <libraryDirectory> <zfStandardLibraryDirectory enabled="false"/> </libraryDirectory> <publicDirectory> <publicStylesheetsDirectory enabled="false"/> <publicScriptsDirectory enabled="false"/> <publicImagesDirectory enabled="false"/> <publicIndexFile filesystemName="index.php"/> <htaccessFile filesystemName=".htaccess"/> </publicDirectory> <projectProvidersDirectory enabled="false"/> <temporaryDirectory enabled="false"/> <testsDirectory> <testPHPUnitConfigFile filesystemName="phpunit.xml"/> <testApplicationDirectory> <testApplicationBootstrapFile filesystemName="bootstrap.php"/> </testApplicationDirectory> <testLibraryDirectory> <testLibraryBootstrapFile filesystemName="bootstrap.php"/> </testLibraryDirectory> </testsDirectory> </projectDirectory> </projectProfile>

  Read the article

• Is this safe on a production server?

  - by Camran

  I have a database application (or search engine) which is called Solr. I connect to it via port 8983. I do this from php code, so I add and remove records from it via php. On my server I have a firewall. I have set this firewall to only allow connections to and from this port (8983) from the ip adress of my own server. In other words, only allow servers IP to access this port. Is that safe? Or am I thinking all wrong here? Will others be able to "simulate" my ip adress and act as the server? This is because otherwise others may add/remove records as they want from their own ip adresses... Thanks

  Read the article

• Open page in Joomla

  - by dutt

  I'm using Jumi to echo php code and then showing that in a Joomla Article, and everythings working fine. Now I want to do this: The output is basically a list from a database like this: Name Price Type A 1 T1 B 2 T2 In this list I want to include links to only show items of the same type, so "T1" would like to a page only showing things of type T1. So I thought I would do this by making a new page that takes a type and then get all the items of that type from the database. Without Joomla this wouldv'e been a piece of cake, with Joomla I'm not quite sure where to begin. How should the a href=... tags in the html code printed by my php script look? Is my basic structure still correct, and if so, how do I make Joomla open the new page in the normal frame and not replace the whole Joomla page. some kind of target-frame attribute?

  Read the article

• JavaScript: If clause partially executed !!!

  - by arwa

  Hi everyone My problem is that when the condition is true it will close the window but not execute the php part ! here goes my code.. function onClose() { var r=confirm("Is the meeting Over!"); if (r==true) { window.close(); } else { } } </blink> this is the php part.. $sql="UPDATE previousmeetings SET Live='0' WHERE MeetingID='34'"; //$meeting_id $sql2="UPDATE previousmeetings SET Live='1' WHERE MeetingID='34'";

  Read the article

• mysql_real_escape_string and search data in mySql DB

  - by ryrysz

  I have problem with php function : mysql_real_escape_string My test string: @,&!#$%^*()_+' "\/ I add this data to mySql database, like that (in short): $str = mysql_real_escape_string($str); $sql = "INSERT INTO table(company) VALUES('".$str. "')"; In DB is stored as: @,&!#$%^*()_+\' \"\\/ But problem is with find this data by SELECT statement. I want find, company where name is like ' " My SELECT's: SELECT company FROM table WHERE company LIKE '%\' "%'; SELECT company FROM table WHERE company LIKE '%\\' \\"%'; ; not working. This works: SELECT `company` FROM `table` WHERE `company` LIKE '%\\\' \\\\"%'; and SELECT `company` FROM `table` WHERE `company` LIKE '%\\\\\\\' \\\\\\\"%' But I dont know why this work :(. My questions are: why must add so many slashes ? how I can make correct query in PHP: $query = '\' "'; '%'.mysql_real_escape_string($query).'%' result is : '%\' \"%' '%'.mysql_real_escape_string(mysql_real_escape_string($query)).'%' result is : '%\\\' \\\"%' '%'.mysql_real_escape_string(mysql_real_escape_string(mysql_real_escape_string($query))).'%' result is : '%\\\\\\\' \\\\\\\"%' Only last one works good.

  Read the article

• Google Maps API - Marker not showing

  - by popnbrown

  I'm trying to add markers for every single row from a table, that sits on the page. The page is http://www.sravanks.com/first/2013ftcmap.php This is the JS code that's loading the markers: $(document).ready(function() { var mapOptions = { center: new google.maps.LatLng(39.740, -89.503), zoom: 7 }; var map = new google.maps.Map(document.getElementById("map-canvas"), mapOptions); var infowindow = new google.maps.InfoWindow(); /* City Markers */ var cityCircle = new Array(); var i = 0; $.each($('.events tr'), function(index, value) { var name = $(this).find('td:first()').html(); var address = $(this).find('.address').html(); var linkUrl = "http://www.sravanks.com/first/geocode.php?address=" + address; $.ajax({ url: linkUrl }).done(function(data){ var json = $.parseJSON(data.substring(0, data.length-1)); lat = json.results[0].geometry.location.lat; lng = json.results[0].geometry.location.lng; var latlng = new google.maps.LatLng(lat, lng); var marker = new google.maps.Marker({ position: latlng, map: map, icon: 'map-pointer-medium.gif' }); google.maps.event.addListener(marker, 'click', function() { infowindow.setContent(name); infowindow.open(map, marker); cityCircle[i] = new google.maps.Circle({strokeColor: '#00FF00', strokeOpacity: 0.8, strokeWeight: 2, fillColor: '#00FF00', fillOpacity: 0.35, map: map, center: latlng, radius: 144841}); i++; }); }); }); /*Team Markers*/ var markers = {}; var teamName, teamNumber, lat, lng, content; $.each($('.list tr'), function(index, value) { teamName = $(this).find('td.name').html(); teamNumber = $(this).find('td.number').html(); markers[teamNumber] = {}; lat = parseFloat($(this).find('td.lat').html()); lng = parseFloat($(this).find('td.lng').html()); content = "Name: " + teamName + "<br />Number: " + teamNumber; markers[teamNumber]['latlng'] = new google.maps.LatLng(lat, lng); markers[teamNumber]['marker'] = new google.maps.Marker({ position: markers[teamNumber]['latlng'], map: map }); google.maps.event.addListener(markers[teamNumber]['marker'], 'click', function() { infowindow.setContent(content); infowindow.open(map, markers[teamNumber]['marker']); }); }); google.maps.event.addListener(infowindow, 'closeclick', function() { for(var i=0;i<cityCircle.length;i++){ cityCircle[i].setMap(null); } }); }); I've got no errors, but the Team Markers do not show up. The strange thing is that the City Markers do show up. Some more info, the City Markers ajax call is just to a proxy that calls the google geocoding api. Again the link's at http://www.sravanks.com/first/2013ftcmap.php

  Read the article

• What are the possible reasons for App::import() not working?

  - by Julien Poulin

  I'm trying to implement a simple way to manage static pages in CakePhp, as described in this article. The problem I'm facing is that App::import() doesn't seem to import the required class in the routes.php file. The code is the following: App::import('Core','ClassRegistry'); $page = new StaticPage(); $slugs = $page->find('list', array( 'fields' => array('StaticPage.slug'), 'order' => 'StaticPage.slug DESC' )); I'm getting the error: Fatal error: Class 'StaticPage' not found in ... I just started CakePhp a few weeks ago and I guess I'm missing a simple thing here... I'm using CakePhp 1.3 and Php 5.2.42.

  Read the article

• Cannot output json from MySQL - getting null value

  - by sky

  I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script>

  Read the article

< Previous Page | 533 534 535 536 537 538 539 540 541 542 543 544  | Next Page >