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  • Optimal way to store and pass a date to Javascript

    - by user1493115
    I need to store a date-time value in MySQL and subsequently display it on a webpage. Due to its flexibility I usually chose to store a Unix timestamp in the database and convert it with PHP's date() to the desired format. This time however I would like to use MySQL's datetime field (mostly due to 2038) and apply the browser's timezone (hence I cannot simply format it on the server and pass the string to the client). I thought of storing the date as UTC datetime in the database and send it as well-defined format to the client, where it will be further processed. Here I would like to avoid a Unix timestamp but everything else might add additional overhead in processing. Is there any best practice as far as date processing is concerned in a MySQL, PHP, JQuery environment? Thanks.

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  • Seeking assistance with Escaping Data for MySQL queries

    - by JM4
    Please don't send me a link to php.net referencing mysql_real_escape_string as the only response. I have read through the page and while I understand the general concepts, I am having some trouble based on how my INSERT statement is currently built. Today, I am using the following: $sql = "INSERT INTO tablename VALUES ('', '$_SESSION['Member1FirstName'], '$_SESSION['Member1LastName'], '$_SESSION['Member1ID'], '$_SESSION['Member2FirstName'], '$_SESSION['Member2LastName'], '$_SESSION['Member2ID'] .... and the list goes on for 20+ members with some other values entered. It seems most people in the examples already have all their data stored in an array. On my site, I accept form inputs, action="" is set to self, php validation takes place and if validation passes, data is stored into SESSION variables on page 2 then redirected to the next page in the process (page 3) (approximately 8-10 pages in the whole process). thanks!

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  • Is there any way to use imagegrabwindow() with Firefox or Chrome?

    - by patternsofchaos
    I'm trying to generate website thumbnails programatically in PHP. To do this, I'm using imagegrabwindow() with a COM object: $browser = new COM("InternetExplorer.Application"); $handle = $browser->HWND; $browser->Visible = true; $browser->Navigate($pre.$URL); while ($browser->Busy) { com_message_pump(4000); } $img = imagegrabwindow($handle); What I'm wondering is if there is any way to do the same thing with Firefox or Chrome? Can I invoke either of them with PHP COM?

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  • How do I make a URL text a link?

    - by jpjp
    Say on Facebook or Twitter, when I type "www.google.com" and submit it, it becomes a link. How do I code this in PHP? Do I use regular expressions to get where the www starts and the .com ends? Is this how they do it? <?PHP //some regular expression to get www and .com part $link="<a href='$url'>$url</a>"; echo $link; ?> How do I write a regular expression to get the "www" and ".com" part? And for twitter's @obama, obama would become a link to obama's site. What regular expression do they use to get the text after the @ and before the space?

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  • Add a custom class name to Wordpress body tag?

    - by Scott B
    I'd like to place a directive in my theme's functions.php file which appends a classname to the wordpress body tag. Is there a built-in API method for this? For example, my body tag code is... <body <?php if(function_exists("body_class") && !is_404()){body_class();} else echo 'class="page default"'?>> And it results in the following being written to the body tag (depending on the context in which the page is presented (page, post, logged-in, etc) <body class="home blog logged-in"> Depending on the child theme I'm using at the time, I want it to be... <body class="home blog logged-in mychildthemename">

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  • Problem with onsubmit ID

    - by Liso22
    I need an onsubmit to return false if what's written on the first field is a certain PHP value however the field has a strange id format and I'm not quite sure how to add it in the onsubmit. This is the form, I didn't add the element ID to it: <form class="questionform" name="questionform-0" id="questionform-0" onsubmit="if (document.getElementById('').value == '<?php echo $casi; ?>') return false;" > <textarea class="question-box" style="width:97%;" cols="20" rows="4" id="question-box-' . $questionformid . '" name="title" type="text" maxlength="80" size="28" value=""></textarea> I tried many times but couldn't add it. How should I do it? Thanks

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  • CakePHP accessing other controllers

    - by James
    CakePHP Newbie :) I am having trouble accessing another controller and passing that data to a view in one of my controllers: In controllers/landings_controller.php: var $uses = 'User'; function home() { $userdata = $this->User->read(); $this->set(compact('userdata')); } In views/landings/home.ctp: <?php echo $this->userdata; ?> When accessing /landings/home I get the following error: Notice (8): Undefined property: View::$userdata [APP/views/landings/home.ctp, line 38] I don't know what I am doing wrong. Any help? Thanks!

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • How can I store and access SQLite databases from a central location?

    - by Brian Ramsay
    I have installed SQLite on my UNIX system, and am planning on accessing it from PHP. However, the database is created in the directory I initialize it in, and if a script runs in a different directory a new database is created in the same directory. Is there an option for SQLite (or the PHP wrappers) to create the databases in one location, and have those databases accessible just by name outside of that directory? Ideally, I'd like to be able to do something like $db=new SQLiteDatabase("db.test"); in any directory and have it reference the same database, if that makes sense.

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  • My rewrite rule is not working

    - by DijkeMark
    I need to make a rewrite rule for a page, but it does not work. I do have mod_rewrite for apache enabled This is my .htacces file: <IfModule mod_rewrite.c> RewriteEngine on RewriteRule ^gameofthrones/(full|house|characters)\.(all|Stark|Lannister)\.(html|xml|json)$ index.php?output=$3&house=$2&info=$1 </IfModule> But when I enter this url: localhost/school/str-webservices/eindopdracht/index.php?output=html&house=all&info=full It stays that way, but it should be something like: localhost/school/str-webservices/eindopdracht/gameofthrones/full/all/html What am I doing wrong? Thanks in advance, Mark

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  • array_count_values for javascript instead

    - by user626342
    Hi, I have the following php-script, now I need to do the same thing in javascript. Is there a funcion in javascript that works similar to the php function, I have been searching for days but cannot find anything similar? What I want to do is to count the number of times a certain word is beeing used in an array. $interfaceA = array($interfaceA_1,$interfaceA_2,$interfaceA_3,$interfaceA_4,$interfaceA_5,$interfaceA_6,$interfaceA_7,$interfaceA_8); $interfaceA_array=array_count_values($interfaceA); $knappsatsA = $interfaceA_array[gui_knappsats]; $touchpanelA = $interfaceA_array[gui_touchpanel]; Many thanks linda

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  • How to handle un-assigned records

    - by Mico
    I have this PHP page where the user can select and un-select items. The interface looks like this: Now I'm using these code, when the user hit the save changes button: foreach( $value as $al_id ){ //al_id is actually location id //check if a record exists //if location were assigned and leave it as is $assigned_count = $this->AssignedLoc->checkIfAssigned( $tab_user_id, $al_id ); if( $assigned_count == 0 ){ //else if not, insert this new record $this->insertAssigned( $tab_user_id, $company_id, $al_id ); } } Now my question is, how do I delete the un assigned locations? For example in the screenshot above, there are 4 assigned locations, if I'm gonna remove (or unassign) "Mercury Morong" and "GP Hagonoy" from the assigned locations, only two must remain. What are the possible solutions using PHP? Thanks for any help!

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  • which one consume less resources? opening text file or make an sql query,both a thousand times ?

    - by imin
    hi I've a php website which displays recipes www.trymasak.my, to be exact. The recipes being displayed at the index page is updated about once a day. To get the latest recipes, I just use a mysql query which is something like "select recipe_name, page_views, image from table order by last_updated". So if I got 10000 visitors a day, obviously the query would be made 10000 times a day. A friend told me a better way (in terms of reducing server load) is when I update the recipes, I just put in the latest recipe details (names,images etc) into a text file, and make my page instead of querying a same query for 10,000 times, just get the data from the text file. Is his suggestion really better? If yes, which is the best php command should I use to open, read and close the text file? thanks

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  • 1054 - Unknown column 'apa_calda' in 'where clause'

    - by sebastian
    Hi, I keep getting this error in mysql. Here is the query: SELECT user_id FROM detalii_contor WHERE tip_contor=apa_calda i want to use this query in a php file but it doesn't give any result. so i tried to write it in the sql command prompt. here is what i tried in the php file: $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='".$contor."'"; $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='$contor'"; even without "" or without '' i wanted to get $contor from a form, i also tried with $_POST['util'] and {$_POST['util']} i've also tried to set $contor the value i need, but no result. please help. thanks, Sebastian

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  • 'An error occurred. Please try later' message on Facebook authentication dialog

    - by Eugene Zhuang
    I am a newbie who is trying to create a Facebook app using PHP and Facebook's PHP SDK. The app is hosted on Heroku, and the sample app that they provided is working fine. However, I am now trying to get the sample app to work on Apache 2.2, and I have encountered a lot of problems along the way. Well, straight to the point, my latest problem will be trying to do Facebook login on localhost, but the 'An error occurred. Please try later' appears on the popup dialog. This does not happen on Heroku. Will someone please enlighten me on if there's any steps that I can take to overcome this error? I don't think it got to do with any coding error since I am just following the provided sample app. Thanks!

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  • Apache crashes after installing mysqli

    - by Marco P.
    System: Apache 2.2 running on Windows 2008 Server with PHP 5.2.17 VC6 Thread-Safe as a Module and MySQL 5.5.17 - all working fine. After installing mysqli using the php package, Apache won't start anymore. There is no error message in the log. What I have tried: Make sure Windows PATH points to libmysql.dll: Yes, done. Make sure extension_dir points to the right point: Yes. Other extensions load fine. Try without mysqli: Yes, Apache loads fine then. Try without mysql: Yes, does not help. Test mysql itself: Restarts server! Overwrite libmysql: Yes, does not help. It seems to me that there is some general problem with MySql, but the DB server seems to be running fine. I'm really out of ideas of things I could try, so I'm desperate for any hints or tricks.

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  • Placing .htaccess file in var/www folder messes my website up...

    - by Camran
    I am playing with mod_rewrite now, and have successfully enabled it. However, I need to put a htaccess file inside var/www/ in order to achieve what I want, which is to rename Urls simply... When I place it my website becomes very strange and nothing basically works... Is there any code I need to put into the htaccess file in order for things to act normally? Here is the htaccess file I have so far: Options +FollowSymLinks Options +Indexes RewriteEngine On RewriteCond %{REQUEST_URI} !^/ad\.php RewriteRule ^(.*)$ ad.php?ad_id=$1 [L] My DocumentRoot is also set to var/www/ and my entire website root is there... (index.html etc etc)... What am I missing about the htaccess? If you need more input let me know...

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  • Need help with regular expressions - URL redirection

    - by paperless
    Hello everyone. I'm trying to redirect an easy to remember url to a php file but I'm having some trouble with the regex. Here's what I have at the moment: RewriteRule ^tcb/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,}) /tcb/lerbd.php?autocarro=$1&tipo=$2&dsd=$3 It is working but only if I supply all 3 arguments. I want the last two arguments to be optional so it either works with only the first or all three. I'm hoping you can help me with this. Thank you very much.

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  • How is this problem usually solved without using sever-side scripting?

    - by cyggi
    Simple problem I have so far always solved via PHP: You have a site with header, menu, footer and content field. Header, menu and footer are usually the same for each page. How do you, without PHP or any other server-side language, have the header, menu and footer data exist only in one file? So that for example you don't have ten sites (like home.html, products.html, about.html, ..) all having a copy of the static header and menu in their html files. Now if you want to change the header you have to change ten files. I hope I made my question clear enough, if not please leave a comment :)

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  • Getting Null value with JSON from MySQL, how to retrive data from MySQL to JSON correctly?

    - by sky
    I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script> This is the table: message Try iPhone post! Welcome to Yo~ :) ??!

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  • woocommerce show attribute description when selecting a variable

    - by user2916995
    I'm trying to figure out a way to display custom text based on the users selection of the variable product. The attribute is 'pricing' and the tag is deposit - which I've added a text description to when adding the attribute. So I'm trying to make this text appear when the user selects 'deposit' But the code I'm using in 'content-single-product.php' is displaying the text all the time no matter what variable is selected or not. <?php $my_taxonomy = 'pa_pricing'; $terms = wp_get_post_terms( $post->ID, $my_taxonomy ); echo term_description($terms[0]->term_id, $my_taxonomy); ?> I only want the text to be displayed after the user has selected pricing 'deposit' Can someone help me with this?

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  • Uploading files wont work on production server

    - by Camran
    I have a php script which uploads images to a temporary folder on the server. This works on my local computer with the local (virtual) server. (wampserver). However, on the production server (linux) I cant get it working. Everything is loading as it should, except for that the file doesn't show up on the server. My Q is, is there anything I should think about when moving to a production server with uploading images or files? I have set permissions on the folder where the images are supposed to go to 777 and also the php-code which uploads them to 777. Thanks

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