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• Printing a dynamic sheet as one document

  - by Sux2Lose

  I have a spreadsheet structured as follows: Summary section at the top Detail section on the bottom Summary section summarizes the detail section which is filtered using auto filters There are ten products that all need to be printed individually, but I want the page footer to show the overall page position of all the print jobs and the total number of pages. That is probably not clear. So for example, if I print the two page Product A view it will print page 1 of 2 and 2 of 2. If I print the one page Product B it will show page 1 of 1. What I want is to print both and have Product A show Page 1 of 3, Page 2 of 3, and Product B be Page 3 of 3. Is there any way to accomplish this?

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• Convertion of tiff image in Python script - OCR using tesseract

  - by PYTHON TEAM

  I want to convert a tiff image file to text document. My code perfectly as I expected to convert tiff images with usual font but its not working for french script font . My tiff image file contains text. The font of text is in french script format.I here is my code import Image import subprocess import util import errors tesseract_exe_name = 'tesseract' # Name of executable to be called at command line scratch_image_name = "temp.bmp" # This file must be .bmp or other Tesseract-compatible format scratch_text_name_root = "temp" # Leave out the .txt extension cleanup_scratch_flag = True # Temporary files cleaned up after OCR operation def call_tesseract(input_filename, output_filename): """Calls external tesseract.exe on input file (restrictions on types), outputting output_filename+'txt'""" args = [tesseract_exe_name, input_filename, output_filename] proc = subprocess.Popen(args) retcode = proc.wait() if retcode!=0: errors.check_for_errors() def image_to_string(im, cleanup = cleanup_scratch_flag): """Converts im to file, applies tesseract, and fetches resulting text. If cleanup=True, delete scratch files after operation.""" try: util.image_to_scratch(im, scratch_image_name) call_tesseract(scratch_image_name, scratch_text_name_root) text = util.retrieve_text(scratch_text_name_root) finally: if cleanup: util.perform_cleanup(scratch_image_name, scratch_text_name_root) return text def image_file_to_string(filename, cleanup = cleanup_scratch_flag, graceful_errors=True): If cleanup=True, delete scratch files after operation.""" try: try: call_tesseract(filename, scratch_text_name_root) text = util.retrieve_text(scratch_text_name_root) except errors.Tesser_General_Exception: if graceful_errors: im = Image.open(filename) text = image_to_string(im, cleanup) else: raise finally: if cleanup: util.perform_cleanup(scratch_image_name, scratch_text_name_root) return text if __name__=='__main__': im = Image.open("/home/oomsys/phototest.tif") text = image_to_string(im) print text try: text = image_file_to_string('fnord.tif', graceful_errors=False) except errors.Tesser_General_Exception, value: print "fnord.tif is incompatible filetype. Try graceful_errors=True" print value text = image_file_to_string('fnord.tif', graceful_errors=True) print "fnord.tif contents:", text text = image_file_to_string('fonts_test.png', graceful_errors=True) print text

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• Code refactoring with Visual Studio 2010 Part-1

  - by Jalpesh P. Vadgama

  Visual studio 2010 is a Great IDE(Integrated Development Environment) and we all are using it in day by day for our coding purpose. There are many great features provided by Visual Studio 2010 and Today I am going to show one of great feature called for code refactoring. This feature is one of the most unappreciated features of Visual Studio 2010 as lots of people still not using that and doing stuff manfully. So to explain feature let’s create a simple console application which will print first name and last name like following. And following is code for that. using System; namespace CodeRefractoring { class Program { static void Main(string[] args) { string firstName = "Jalpesh"; string lastName = "Vadgama"; Console.WriteLine(string.Format("FirstName:{0}",firstName)); Console.WriteLine(string.Format("LastName:{0}", lastName)); Console.ReadLine(); } } } So as you can see this is a very basic console application and let’s run it to see output. So now lets explore our first feature called extract method in visual studio you can also do that via refractor menu like following. Just select the code for which you want to extract method and then click refractor menu and then click extract method. Now I am selecting three lines of code and clicking on refactor –> Extract Method just like following. Once you click menu a dialog box will appear like following. As you can I have highlighted two thing first is Method Name where I put Print as Method Name and another one Preview method signature where its smart enough to extract parameter also as We have just selected three lines with  console.writeline.  One you click ok it will extract the method and you code will be like this. using System; namespace CodeRefractoring { class Program { static void Main(string[] args) { string firstName = "Jalpesh"; string lastName = "Vadgama"; Print(firstName, lastName); } private static void Print(string firstName, string lastName) { Console.WriteLine(string.Format("FirstName:{0}", firstName)); Console.WriteLine(string.Format("LastName:{0}", lastName)); Console.ReadLine(); } } } So as you can see in above code its has created a static method called Print and also passed parameter for as firstname and lastname. Isn’t that great!!!. It has also created static print method as I am calling it from static void main.  Hope you liked it.. Stay tuned for more..Till that Happy programming.

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• Issues printing through ssh tunnel and port forwarding

  - by simogasp

  I'm having some problems trying to print through a ssh tunnel. I'd like to print from my laptop to a network printer (Toshiba es453, for what matters) which is in a local network. I can reach the local network using a gateway. So far I did the following: ssh -N -L19100:<Printer_IP>:9100 <username>@<ssh_gateway> Basically i just mapped the port 19100 of my laptop directly to the input port of the printer, passing through the gateway. So far, so good. Then, i tried to install on my laptop a new printer with the GUI config tool of ubuntu, so that the new printer is on localhost at port 19100 (as APP Socket/HP Jet Direct) , then I provided the proper driver of the printer. In theory, once the tunnel is open I should be able to print from any program just selecting this printer. Of course, it does not work. :-) The document hangs in the queue with status Processing while in the shell where I set up the tunnel I get these errors on failing opening channels debug1: Local forwarding listening on ::1 port 19100. debug1: channel 0: new [port listener] debug1: Local forwarding listening on 127.0.0.1 port 19100. debug1: channel 1: new [port listener] debug1: Requesting [email protected] debug1: Entering interactive session. debug1: Connection to port 19100 forwarding to 195.220.21.227 port 9100 requested. debug1: channel 2: new [direct-tcpip] debug1: Connection to port 19100 forwarding to 195.220.21.227 port 9100 requested. debug1: channel 3: new [direct-tcpip] channel 2: open failed: connect failed: Connection timed out debug1: channel 2: free: direct-tcpip: listening port 19100 for 195.220.21.227 port 9100, connect from ::1 port 44434, nchannels 4 debug1: Connection to port 19100 forwarding to 195.220.21.227 port 9100 requested. debug1: channel 2: new [direct-tcpip] channel 3: open failed: connect failed: Connection timed out debug1: channel 3: free: direct-tcpip: listening port 19100 for 195.220.21.227 port 9100, connect from ::1 port 44443, nchannels 4 channel 2: open failed: connect failed: Connection timed out debug1: channel 2: free: direct-tcpip: listening port 19100 for 195.220.21.227 port 9100, connect from ::1 port 44493, nchannels 3 debug1: Connection to port 19100 forwarding to 195.220.21.227 port 9100 requested. debug1: channel 2: new [direct-tcpip] As a further debugging test I tried the following. From a machine inside the local network I did a telnet <IP_printer> 9100, got access, wrote some random thing, closed the connection and correctly I got a print of what I had written. So the port and the ip of the printer should be correct. I tried the same from my laptop with the tunnel opened, the telnet succeeded but, again, the printer didn't print anything, getting the usual channel x: open failed: errors. I'm not a great expert on the matter, I just thought that in theory it was possible to do something like that, but maybe there is something that I didn't consider or I did wrong. Any clue? Thanks! Simone [update] As further debugging test, I tried to replicate the procedure from a machine in the local network. From that machine, I did ssh -N -L19100:<IP_printer>:9100 <username>@<ssh_gateway> (note that now the machine, the gateway and the printer are in the same local network) then I tried again the telnet test with telnet localhost 19100, I got access and everything, but I didn't get the print but the usual error channel 2: open failed: connect failed: Connection timed out Maybe I am missing some other connection to be forwarded or maybe this is not allowed by the administrators. Of course, if I connect via ssh tunneling to the local machine from my laptop through the gateway, I can successfully print using the lpr command (from the local machine). But this is what I would like to avoid (yes, I'm lazy...:-), I would like to have a more 'elegant' and transparent way to do that.

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• Bash Script help required

  - by Sunil J

  I am trying to get this bash script that i found on a forum to work. Copied it to text editor. Saved it as script.sh chmod 700 and tried to run it. rootdir="/usr/share/malware" day=`date +%Y%m%d` url=`echo "wget -qO - http://lists.clean-mx.com/pipermail/viruswatch/$day/thread.html |\ awk '/\[Virus/'|tail -n 1|sed 's:\": :g' |\ awk '{print \"http://lists.clean-mx.com/pipermail/viruswatch/$day/\"$3}'"|sh` filename=`wget -qO - http://lists.clean-mx.com/pipermail/viruswatch/$day/thread.html |\ awk '/\[Virus/'|tail -n 1|sed 's:": :g' |awk '{print $3}'` links -dump $url$filename | awk '/Up/'|grep "TR\|exe" | awk '{print $2,$8,$10,$11,$12"\n"}' > $rootdir/>$filename dirname=`wget -qO - http://lists.clean-mx.com/pipermail/viruswatch/$day/thread.html |\ awk '/\[Virus/'|tail -n 1|sed 's:": :g' |awk '{print $3}'|sed 's:.html::g'` rm -rf $rootdir/$dirname mkdir $rootdir/$dirname cd $rootdir grep "exe$" $filename |awk '{print "wget \""$5"\""}' | sh ls *.exe | xargs md5 >> checksums mv *.exe $dirname rm -r $rootdir/*exe* mv checksums $rootdir/$dirname mv $filename $rootdir/$dirname I get the following message.. script.sh: line 11: /usr/share/malware/: Is a directory script.sh: line 11: links: command not found

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• Wise settings for Git

  - by Marko Apfel

  These settings reflecting my Git-environment. It a result of reading and trying several ideas of input from others. Must-Haves Aliases [alias] ci = commit st = status co = checkout oneline = log --pretty=oneline br = branch la = log --pretty=\"format:%ad %h (%an): %s\" --date=short df = diff dc = diff --cached lg = log -p lol = log --graph --decorate --pretty=oneline --abbrev-commit lola = log --graph --decorate --pretty=oneline --abbrev-commit --all ls = ls-files ign = ls-files -o -i --exclude-standard Colors [color] ui = auto [color "branch"] current = yellow reverse local = yellow remote = green [color "diff"] meta = yellow bold frag = magenta bold old = red bold new = green bold whitespace = red reverse [color "status"] added = green changed = red untracked = cyan Core [core] autocrlf = true excludesfile = c:/Users/<user>/.gitignore editor = 'C:/Program Files (x86)/Notepad++/notepad++.exe' -multiInst -notabbar -nosession –noPlugin Nice to have Merge and Diff [merge] tool = kdiff3 [mergetool "kdiff3"] path = c:/Program Files (x86)/KDiff3/kdiff3.exe [mergetool "p4merge"] path = c:/Program Files (x86)/Perforce Merge/p4merge.exe cmd = p4merge \"$BASE\" \"$LOCAL\" \"$REMOTE\" \"$MERGED\" keepTemporaries = false trustExitCode = false keepBackup = false [diff] guitool = kdiff3 [difftool "kdiff3"] path = c:/Program Files (x86)/KDiff3/kdiff3.exe [difftool "p4merge"] path = C:/Users/<user>/My Applications/Perforce Merge/p4merge.exe cmd = \"p4merge.exe $LOCAL $REMOTE\" .

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• Printing background colours in Chrome

  - by Mick

  Hi, I'm trying to print a php generated document in Chrome. On the browser it looks fine, but my printer will not print any coloured backgrounds. I know that IE has an option to print background but Chrome does not. As the end user will print this off, I do not want to find alternatives like a screen grab or save file etc. I want to find a real solution to this. Here is the page i want to print, for information Can anyone offer a suggestion please?

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• Result class dependency

  - by Stefano Borini

  I have an object containing the results of a computation. This computation is performed in a function which accepts an input object and returns the result object. The result object has a print method. This print method must print out the results, but in order to perform this operation I need the original input object. I cannot pass the input object at printing because it would violate the signature of the print function. One solution I am using right now is to have the result object hold a pointer to the original input object, but I don't like this dependency between the two, because the input object is mutable. How would you design for such case ?

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• Will the Canon Pixma MX882 Wireless Multifunction Printer allow you to keep printing once one ink cartridge has run out?

  - by braveterry

  My wife's Epson Workforce 600 has died, and I'm thinking of replacing it with a Canon Pixma MX882 printer/scanner/copier/fax. One of the most annoying things about the Epson is that once it has decided that one of the ink cartridges is empty, it will not let you print anything until the empty cartridge is replaced. I have a Canon IP1800 that will let you print until a cartridge actually runs out of ink, and even when a cartridge is depleted, I can continue to print using the other colors. (The driver allows you to print using only the color cartridges or using only the black cartridge.) Questions: Will the Canon Pixma MX882 allow me to print until the ink runs out or will it declare the cartridge empty while ink is still left? Will the Canon Pixma MX882 allow me to keep printing even after one of the cartridges has been used up?

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• Perl syntax error [closed]

  - by Linny

  I am a beginner taking a Perl programming course. We are trying to write a basic program for counting nucleotides in a DNA string. I'm getting syntax errors on the lines that have a single bracket on lines 28 & 70 and don't know why. It also reads that I have compilation errors. I have no idea where to start figuring that out. # The purpose of this program is to count the number of nucleotides in a strand. Each protein is counted separately # print "/n NOTE: Nucleotide counting /n"; # use strict; # enforce variable declarations use warnings; # enable compiler warnings # Display number of A,a,T,t,G,g,C,c, nucleotides in a word or sequence of letters. # my ($base) = ''; # an extracted letter from a string my ($nuceotide_count) = 0 ; # the current position within the word my ($position) = 0 ; # number of vowels in user-supplied word my ($word) = ''; # word to be processed my ($A_count) = 0 ; # of A nucleotides in the user-supplied sequence my ($a_count) = 0 ; # of A nucleotides in the user-supplied sequence my ($C_count) = 0 ; # of C nucleotides in the user-supplied sequence my ($c_count) = 0 ; # of C nucleotides in the user-supplied sequence my ($G_count) = 0 ; # of G nucleotides in the user-supplied sequence my ($g_count) = 0 ; # of G nucleotides in the user-supplied sequence my ($T_count) = 0 ; # of T nucleotides in the user-supplied sequence my ($t_count) = 0 ; # of T nucleotides in the user-supplied sequence word = (STDIN) for ($position = 0);($position if (($base eq 'a') or ($base eq 'A')) { ++$A_count; } # end if ++$position; if (($base eq 'T') or ($base eq 't')) { ++$T_count; } end if ++$position; if (($base eq 'G') or ($base eq 'g')) { ++$G_count; } # end if ++$position; if (($base eq 'C') or ($base eq 'c')) { ++$C_count; } # end if ++$position; } # end for # Display final results. # print " \n The number of A or a neucleotides is: $A_count"; print " \n The number of T or t neucleotides is: $T_count"; print " \n The number of G or g neucleotides is: $G_count"; print " \n The number of C or c neucleotides is: $C_count"; print " \n\n Program completed successfully. \n" ; exit ;

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• Printing to a printer connected to a wireless router

  - by mspencer

  I have a Netgear WNDR4500 wireless router which allows me to print wirelessly to a printer connected to it via a USB cable. However, the software used to print to it only works for Windows and OS X. I've seen the question Printing to a printer attached to a network USB hub, and tried the instructions it gave using my router's IP address, but when I print a test page it says copying data then says printer is in use. In the printer queue window it says not connected. How can I print to the printer using Ubuntu? Thanks.

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• Indefinite loops where the first time is different

  - by George T

  This isn't a serious problem or anything someone has asked me to do, just a seemingly simple thing that I came up with as a mental exercise but has stumped me and which I feel that I should know the answer to already. There may be a duplicate but I didn't manage to find one. Suppose that someone asked you to write a piece of code that asks the user to enter a number and, every time the number they entered is not zero, says "Error" and asks again. When they enter zero it stops. In other words, the code keeps asking for a number and repeats until zero is entered. In each iteration except the first one it also prints "Error". The simplest way I can think of to do that would be something like the folloing pseudocode: int number = 0; do { if(number != 0) { print("Error"); } print("Enter number"); number = getInput(); }while(number != 0); While that does what it's supposed to, I personally don't like that there's repeating code (you test number != 0 twice) -something that should generally be avoided. One way to avoid this would be something like this: int number = 0; while(true) { print("Enter number"); number = getInput(); if(number == 0) { break; } else { print("Error"); } } But what I don't like in this one is "while(true)", another thing to avoid. The only other way I can think of includes one more thing to avoid: labels and gotos: int number = 0; goto question; error: print("Error"); question: print("Enter number"); number = getInput(); if(number != 0) { goto error; } Another solution would be to have an extra variable to test whether you should say "Error" or not but this is wasted memory. Is there a way to do this without doing something that's generally thought of as a bad practice (repeating code, a theoretically endless loop or the use of goto)? I understand that something like this would never be complex enough that the first way would be a problem (you'd generally call a function to validate input) but I'm curious to know if there's a way I haven't thought of.

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• Debian: Firefox or Iceweasel default printer for POS station

  - by Bubnoff

  Context Using Debian 6.04 "Squeeze" as POS station. There are two printers installed: Network printer and a receipt printer It absolutely must be able to print by default to the receipt printer on a certain website though the system default is a network printer. In Debian ...it doesn't. Problem I've set up XP, 7, Ubuntu and even Mac OSX this way, so I'm no stranger to setting Firefox up this way ...same Iceweasel/Firefox settings ...complete fail. Always uses system default no matter what the settings, or, which printer you print from. To get this to work on other systems you do this: Print a page in Firefox using desired printer. Ensure print.save_settings is true. Firefox remembers last printer used Set print.always_print_silent = true The end. This works on every OS I've set up ....except Firefox and Iceweasel in Debian. My only recourse seems to be to set the receipt printer as default or go back to bloaty Ubuntu/Mint ...etc.

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• My Brother printer doesn't accept quality settings anymore - what can I do?

  - by rearlight

  I have a Brother MFC-465CN network printer. It uses the brother-cups-wrapper-bh7 and brother-lpr-drivers-bh7drivers. Now, when I print (which works perfectly fine) I try to print in "fast normal" settings to save some ink. I use LibreOffice and Ubuntus default PDF-viewer to print and set the settings in the print dialog manually. "Fast normal" is the default printing setting (in the Ubuntu GUI printing config). But the printer always prints in "normal" or even "fine" quality settings which takes forever and uses much more ink. So, what can I do about that? Thanks for your help in advance!

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• PDF export printing in Internet Explorer [closed]

  - by user619804

  protected static byte[] exportReportToPdf(JasperPrint jasperPrint) throws JRException { JRPdfExporter exporter = new JRPdfExporter(); ByteArrayOutputStream baos = new ByteArrayOutputStream(); exporter.setParameter(JRExporterParameter.JASPER_PRINT, jasperPrint); exporter.setParameter(JRExporterParameter.OUTPUT_STREAM, baos); exporter.setParameter(JRPdfExporterParameter.PDF_JAVASCRIPT, "this.print({bUI: true,bSilent: false,bShrinkToFit: true});"); exporter.exportReport(); return baos.toByteArray(); } We are using code like this to export a PDF document from a Jasper application. The line exporter.setParameter(JRPdfExporterParameter.PDF_JAVASCRIPT, "this.print({bUI: true,bSilent: false,bShrinkToFit: true});"); adds JavaScript to send the PDF document directly to the printer. The expected behavior is that a print dialog will come up with a preview of the PDF document. This works fine most of the time - except I am having problems about one out of every 5-6 times in Internet Explorer 8 and Firefox. What happens is - the print preview dialog with the PDF document does not appear or it appears with a blank document in the preview window. -I've tried a number of different JavaScripts (different params to this.print() via exporter.setParameter -I've tried setting different response headers such as response.setContentType("application/pdf"); response.setHeader("Content-disposition","inline; filename=\"" + reportName + "\""); response.setContentLength(baos.size()); these did not seem to help This seems to be an IE and FF issue. Has anyone ever dealt with this problem? I need to get it to work across all browsers 100% of the time. Perhaps a different approach to accomplish the goal of sending the PDF document export directly to the printer? or a third party library that will work across browsers?

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• Network printer problem with 12.04

  - by G. He

  I had an HP LaserJet 3030 printer connected to an Ubuntu box. It worked fine with 11.10. I was able to print from Ubuntu as well as from Windows and Mac from the home network. About a month or so ago, I upgraded 11.10 to 12.04, then things started to falling apart. My Windows 7 laptop couldn't print to the printer any more. Today, I installed many updates on 12.04, hoping that would fix the printing problem. Unfortunately, it made the situation much worse. Now not only my Windows 7 laptop won't print, my XP desktop won't print either. Every time I print something from the Windows computer, the Ubuntu box logs an error message in /var/log/samba/log.'machineName' as: _spoolss_OpenPrinterEx: Cannot open a printer handle for printer \\server. It is interesting that it uses the server name as the printer, not the \\server\xyzprinter as the printer name. Anyone had a similar problem? Anyway to work around the problem?

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• Very basic beginner Ruby question to do with elsif and ranges [migrated]

  - by MattKneale

  I've been trying to get to grasps with Ruby (for all of an hour) and this is my first language. I've got the following code: var_comparison = 5 print "Please enter a number: " my_num = Integer(gets.chomp) if my_num > var_comparison print "You picked a number greater than 5!" elsif my_num < var_comparison print "You picked a number less than 5!" elsif my_num > 99 print "Your number is too large, man." else print "You picked the number 5!" end Clearly the interpreter has no way of distinguishing between accepting the rule 5 or 99. How do I make it so that any number between 6-99 returns "You picked a number greater than 5!", but a number 100 or greater returns "Your number is too large, man!"? Do I need to specifically state a range somehow? How would I best do that? Would it by the normal range methods e.g. if my_num 6..99 or if my_num.between(6..99) ?

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• Printing Multiple Pages in GDI+

  In this article you will learn how to print Multiple Pages in GDI+

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• Map rendering Libgdx Java

  - by user3165683

  Ok, so I am trying to create a 2D non-movable random tiled map. This is what I have so far: private void generateTile(){ System.out.print("tiletry1"); while(loadedTiles != 8100){ System.out.print("tiletry"); Texture currentTile = null; int tileX = 0; int tileY = 0; if (tileX == 120); tileY = 16; tileX = 0; game.batch.begin(); switch(MathUtils.random(2)){ case 0: //game.batch.draw(tile1, tileX, tileY); System.out.print("tile1"); currentTile = tile1; break; case 1: //game.batch.draw(tile2, tileX, tileY); System.out.print("tile2"); currentTile = tile2; break; case 2: //game.batch.draw(tile3, tileX, tileY); System.out.print("tile3"); currentTile = tile3; break; } tileX+=16; loadedTiles ++; game.batch.draw(currentTile, tileX, tileY); game.batch.end(); } } However, I can't see any of the tiles and the screen just looks green. This method is above my render method which I have: camera.update(); batch.setProjectionMatrix(camera.combined); Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT); game.batch.begin(); //other render stuff Why am I not able to see the tiles?

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• Printing Multiple Pages in GDI+

  In this article you will learn how to print Multiple Pages in GDI+

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• Roll Your Own MsgBox

  How to create a custom message box from first principles, including system sounds and print capability

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• Generate random number histogram using java

  - by Chewart

  Histogram -------------------------------------------------------- 1 ****(4) 2 ******(6) 3 ***********(11) 4 *****************(17) 5 **************************(26) 6 *************************(25) 7 *******(7) 8 ***(3) 9 (0) 10 *(1) -------------------------------------------------------- basically above is what my prgram needs to do.. im missing something somewhere any help would be great :) import java.util.Random; public class Histogram { /*This is a program to generate random number histogram between 1 and 100 and generate a table */ public static void main(String args[]) { int [] randarray = new int [80]; Random random = new Random(); System.out.println("Histogram"); System.out.println("---------"); int i ; for ( i = 0; i<randarray.length;i++) { int temp = random.nextInt(100); //random numbers up to number value 100 randarray[i] = temp; } int [] histo = new int [10]; for ( i = 0; i<10; i++) { /* %03d\t, this generates the random numbers to three decimal places so the numbers are generated with a full number or number with 00's or one 0*/ if (randarray[i] <= 10) { histo[i] = histo[i] + 1; //System.out.println("*"); } else if ( randarray[i] <= 20){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 30){ histo[i] = histo[i] + 1; } else if ( randarray[i] <= 40){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 50){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=60){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=70){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=80){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=90){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=100){ histo[i] = histo[i] + 1; } switch (randarray[i]) { case 1: System.out.print("0-10 | "); break; case 2: System.out.print("11-20 | "); break; case 3: System.out.print("21-30 | "); break; case 4: System.out.print("31-40 | "); break; case 5: System.out.print("41-50 | "); break; case 6: System.out.print("51-60 | "); break; case 7: System.out.print("61-70 | "); break; case 8: System.out.print("71-80 | "); break; case 9: System.out.print("81-90 | "); break; case 10: System.out.print("91-100 | "); } for (int i = 0; i < 80; i++) { randomNumber = random.nextInt(100) index = (randomNumber - 1) / 2; histo[index]++; } } } }

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• find substring and indices in mips

  - by ccc

  im trying find out substring and first occurrence indices. but something wrong. im comparing each element of pattern array and each element of string array until pointer reach to '\0'. and if any characater found it keep in temp array. and increasing pointers +1. whats the problem. algorithm is totaly wrong ? #Note: $v0 is a symbolic name used by the assember for $2. # $a0 is a symbolic name used by the assember for $4. .data prompt_str: .asciiz "Please type a text string: " prompt_ptr: .asciiz "Please type a pattern string: " print_yes: .asciiz "Yes, there is a match." print_no: .asciiz "No, there is no match." text_str: .asciiz "Text string : " pattern_str: .asciiz "Pattern string : " print_out: .asciiz "Output to be produced :" print_dash: .asciiz "----------------------" print_index: .asciiz "Starting index :" print_msg : .asciiz "Length of longest partial match = " nl: .asciiz "\n" str : .space 81 ptr : .space 81 tmp : .space 81 .text main: la $a0, prompt_str li $v0, 4 #print_string command. syscall la $a0,str #read string li $a1,81 li $v0,8 syscall la $t0,str #move string to $t0 la $a0,prompt_ptr li $v0,4 #print pattern command syscall la $a0,ptr #read pattern li $a1,81 li $v0,8 syscall la $t1,ptr #move pattern to $t1 la $t5,tmp #move temp to $t5 lb $t2,0($t0) #pointer first element array of string lb $t3,0($t1) #pointer first element array of pattern lb $t6,0($t5) #pointer first element array of temp loop : beq $t3,$0,end_loop beq $t2,$t3,match addiu $t0,$t0,1 j loop match : move $t6,$t2 addiu $t5,$t5,1 addiu $t0,$t0,1 addiu $t1,$t1,1 j print_match print_match : la $a0,text_str #print string li $v0,4 syscall move $a0,$t0 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,pattern_str #print pattern string li $v0,4 syscall move $a0,$t1 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,print_out #print output line and newline character li $v0,4 syscall la $a0,nl li $v0,4 syscall la $a0,print_dash li $v0,4 syscall la $a0,print_yes li $v0,4 syscall la $a0,print_index #print starting index li $v0,4 syscall li $v0,10 syscall end_loop : li $v0,10 syscall

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• Make Python Socket Server More Efficient

  - by BenMills

  I have very little experience working with sockets and multithreaded programming so to learn more I decided to see if I could hack together a little python socket server to power a chat room. I ended up getting it working pretty well but then I noticed my server's CPU usage spiked up over 100% when I had it running in the background. Here is my code in full: http://gist.github.com/332132 I know this is a pretty open ended question so besides just helping with my code are there any good articles I could read that could help me learn more about this? My full code: import select import socket import sys import threading from daemon import Daemon class Server: def __init__(self): self.host = '' self.port = 9998 self.backlog = 5 self.size = 1024 self.server = None self.threads = [] self.send_count = 0 def open_socket(self): try: self.server = socket.socket(socket.AF_INET6, socket.SOCK_STREAM) self.server.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) self.server.bind((self.host,self.port)) self.server.listen(5) print "Server Started..." except socket.error, (value,message): if self.server: self.server.close() print "Could not open socket: " + message sys.exit(1) def remove_thread(self, t): t.join() def send_to_children(self, msg): self.send_count = 0 for t in self.threads: t.send_msg(msg) print 'Sent to '+str(self.send_count)+" of "+str(len(self.threads)) def run(self): self.open_socket() input = [self.server,sys.stdin] running = 1 while running: inputready,outputready,exceptready = select.select(input,[],[]) for s in inputready: if s == self.server: # handle the server socket c = Client(self.server.accept(), self) c.start() self.threads.append(c) print "Num of clients: "+str(len(self.threads)) self.server.close() for c in self.threads: c.join() class Client(threading.Thread): def __init__(self,(client,address), server): threading.Thread.__init__(self) self.client = client self.address = address self.size = 1024 self.server = server self.running = True def send_msg(self, msg): if self.running: self.client.send(msg) self.server.send_count += 1 def run(self): while self.running: data = self.client.recv(self.size) if data: print data self.server.send_to_children(data) else: self.running = False self.server.threads.remove(self) self.client.close() """ Run Server """ class DaemonServer(Daemon): def run(self): s = Server() s.run() if __name__ == "__main__": d = DaemonServer('/var/servers/fserver.pid') if len(sys.argv) == 2: if 'start' == sys.argv[1]: d.start() elif 'stop' == sys.argv[1]: d.stop() elif 'restart' == sys.argv[1]: d.restart() else: print "Unknown command" sys.exit(2) sys.exit(0) else: print "usage: %s start|stop|restart" % sys.argv[0] sys.exit(2)

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• Simple way to decrease values without making a new attribute?

  - by Jam

  I'm making a program where you're firing a 'blaster', and I have 5 ammo. I'm blasting an alien who has 5 health. At the end I instantiate the player and make him blast 6 times to check that the program works correctly. But the way I've done it makes it so that the amount won't decrease. Is there an easy fix to this, or do I just have to make a new attribute for ammo and health? Here's what I have: class Player(object): """ A player in a shooter game. """ def blast(self, enemy, ammo=5): if ammo>=1: ammo-=1 print "You have blasted the alien." print "You have", ammo, "ammunition left." enemy.die(5) else: print "You are out of ammunition!" class Alien(object): """ An alien in a shooter game. """ def die(self, health=5): if health>=1: health-=1 print "The alien is wounded. He now has", health, "health left." elif health==0: health-=1 print "The alien gasps and says, 'Oh, this is it. This is the big one. \n" \ "Yes, it's getting dark now. Tell my 1.6 million larvae that I loved them... \n" \ "Good-bye, cruel universe.'" else: print "The alien's corpse sits up momentarily and says, 'No need to blast me, I'm dead already!" # main print "\t\tDeath of an Alien\n" hero = Player() invader = Alien() hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) raw_input("\n\nPress the enter key to exit.")

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