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• I need help with some terminology

  - by Christine

  I'm not a programmer; I'm a freelance writer and researcher. I have a client who'd looking for stats on certain "threats" to the apps market. One of them is cowboy coding. (I know what that means; that's not my question.) Specifically, he wants to see numbers regarding how many apps have failed/crashed/removed because of errors made by, in essence, sloppy coding. (I'm not here to debate the merits of cowboy coding, and whether or not it is sloppy; work with me here.) I've used every possible search term/phrase I can think of, but I can't find any hard numbers, just anecdotal evidence. Have any of you seen any reports that have this kind of data?

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• Project Euler 5: (Iron)Python

  - by Ben Griswold

  In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 5.  As always, any feedback is welcome. # Euler 5 # http://projecteuler.net/index.php?section=problems&id=5 # 2520 is the smallest number that can be divided by each # of the numbers from 1 to 10 without any remainder. # What is the smallest positive number that is evenly # divisible by all of the numbers from 1 to 20? import time start = time.time() def gcd(a, b): while b: a, b = b, a % b return a def lcm(a, b): return a * b // gcd(a, b) print reduce(lcm, range(1, 20)) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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• Friendly URLs: is there a max length for search engines?

  - by Olivier Pons

  People from stackoverflow have been working closely with google team to help them make the panda algorithm more efficient, so I guess they've learned a lot from the google team. Thus they may have done very clever friendly URLs to maximize the page rank. I've seen from time to time very long URLs (can't find where) in stackoverflow, but after a certain "amount" of character there were only numbers, kind of "ok passed this length, SEOs will ignore this so let's put only numbers". I've done a huge work on my framework to make very friendly URLs, and my website can come up with URLs like: http://www.mysite.fr/recherche/region/provence-alpes-cote-d-azur/departement/bouches-du-rhone/categorie-de-metiers/paramedical/ It's very long and I'm wondering if the previous URL won't be mixed with, say, this one: http://www.mysite.fr/recherche/region/provence-alpes-cote-d-azur/departement/bouches-du-rhone/categorie-de-metiers/art/

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• Virtual PBX Goes International

  DIDs (local incoming phone numbers) available in 45+ countries overseas can save customers big bucks.

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• skips nines in counter object, AS3

  - by VideoDnd

  It's not that noticeable at first, but my counter skips over to zero and ignores the nines. How can I get my counter to not skip over the nines? my FLA import flash.display.Sprite; import flash.events.Event; import flash.utils.Timer; import flash.events.TimerEvent; var timer:Timer; var count:int = 0; var fcount:int = 0; var numbers:NumbersView; trace("-----new NumberDocument created"); timer = new Timer(10); timer.addEventListener(TimerEvent.TIMER, incrementCounter); timer.start(); numbers = new NumbersView(); addChild(numbers); addEventListener(Event.ENTER_FRAME, enterFrameHandler); //addEventListener(Event.ADDED_TO_STAGE, traceMeOut); function incrementCounter(event:TimerEvent) { count++; fcount=int(count*count/1000); } function formatCount(i:int):String { return ("000000000" + i).substr(-9, 9); } function enterFrameHandler(e:Event):void { numbers.setTime(formatCount(fcount)); } function traceMeOut() { trace("-----Im here on stage!"); } NumbersView.as //NumbersView.as - Your Document Class package { import flash.display.MovieClip; public class NumbersView extends MovieClip { private var _listItems:Array; private const numHeight:int = 120; public function NumbersView() { _listItems = new Array(); var item:NumberImage; for (var i:Number = 0; i < 9; i++) { item = new NumberImage(); addChild(item); item.x = i * item.width; _listItems.push(item); } setTime('123456789'); } public function setTime($number:String):void { var nums:Array = $number.split(""); trace(nums); for (var i:Number = 0; i < nums.length; i++) { _listItems[i].start( int(nums[i]) ); } } } } Variation of NumbersView.as with Tweener //...SNIPPET public function setTime($number:String):void { var nums:Array = $number.split(""); for (var i:Number = 0; i < nums.length; i++) { if (nums[i] == previousNums[i]) continue; Tweener.removeTweens(_listItems[i]); var nuNum:int = int(nums[i]); var nuY:int = nuNum == 0 ? 0 : (nuNum - 1) * -numHeight; trace("nuY = " + nuY); trace("cY = " + _listItems[i].y); Tweener.addTween(_listItems[i], { y:nuY, time:0 } ); } previousNums = nums; } Variation of NumbersView.as that doesn't skip 9, but resets from bottom every count //...SNIPPET public function setTime($number:String):void { var nums:Array = $number.split(""); for (var i:Number = 0; i < nums.length; i++) { if (nums[i] == previousNums[i]) continue; Tweener.removeTweens(_listItems[i]); var newY:int = int(nums[i]) * -numHeight; if (_listItems[i].y < 0) _listItems[i].y = numHeight; Tweener.addTween(_listItems[i], { y:newY, time:3 } ); } previousNums = nums; } PUBLIC CLASS extends MovieClip place 'NumbersView.as' in same directory CLASS Library/'right-click' Properties/Class:NumberImage SYMBOL number column 70x1080 numbers 70x120 TWEENER caurina folder in local directory

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• Juju bootstrap fails with "Temporary failure in name resolution" using Amazon AWS

  - by Will

  I have followed the instructions over at https://juju.ubuntu.com/docs/config-aws.html to try and setup myself with a juju environment. It all seemed to setup alright. SSH keys, Gererate config, repository, adding access id and secret keys to environments.yaml file. Although my key file from aws IAM management console was called credentials.csv rather than rootkey, I couldn't find that link described in the documentation. When I give the command juju bootstrap in the testing page. It fails giving me the error: juju bootstrap ERROR Get https://s3-us-west-1.amazonaws.com/juju-gobblygookmynukmbersinhere/provider-state: lookup s3-us-west-1.amazonaws.com: Temporary failure in name resolution (note I just replaced my numbers for this posting my actual terminal has my numbers in. This is my first attempt at any ec2 work so I have gone in and created new IAM profiles. What have I done wrong? Any help would be great. I think I'm in over my head!

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• Skype support and dead parrot sketches

  - by Greg Low

  We as an industry have a lot to answer for. One thing is the level of support provided for users. Here's the conversation I'm having with Skype right now. It feels like being in a Monty Python skit. I was really hoping that when Microsoft purchased Skype that things might improve. 8:33:44 PM greglowInitial Question/Comment: Subscriptions (Unlimited Country, Unlimited Europe, Unlimited Region, Unlimited World)8:33:44 PM SystemThank you for contacting Skype Customer Support!8:33:49 PM SystemDonna Faye has joined this session!8:33:50 PM SystemConnected with Donna Faye8:33:50 PM SystemThank you for contacting Skype Customer Support!8:33:54 PM SystemPlease hold for the next available Live Support Agent.8:33:59 PM Donna FayeHello! Welcome to Skype Live Support! My name is Donna L. How may I help you?8:34:09 PM greglowI've got a subscription (skypename greglow)8:34:21 PM greglowIt's set to auto-renew8:34:45 PM greglowWhy have I been getting messages about my Skype number expiring, if it's set to renew automatically8:34:54 PM greglowand has recently renewed automatically8:35:09 PM Donna FayeThank you for the information.8:35:29 PM Donna FayeTo better assist you may I know your Skype name, please?8:35:37 PM greglowgreglow8:35:44 PM Donna FayeThank you.8:36:14 PM Donna FayeI understand your concern that you receive an email notification stating that your calling subscription will about to expire. Am I right?8:36:43 PM greglowNo, I got an email telling me that one of my Skype numbers was going to expire8:37:08 PM greglowWhen I went to the website, it said it was part of the subscription and the subscription was set to auto-renew8:37:18 PM greglowThe subscription auto-renewed on Oct XXth8:37:24 PM greglowBut the number still expired8:37:43 PM greglowWhen I logged on today, it said that the number had expired and that I had 52 days left to reactivate it8:37:58 PM greglowI did that but am trying to understand why that happens at all8:38:36 PM greglowWhy do you expire numbers that are part of auto-renewing subscriptions?8:39:49 PM Donna FayeUpon checking your account, your calling subscription link to three Online Numbers.8:39:55 PM greglowcorrect8:40:10 PM greglowbut until an hour or so ago, one of them had expired. why?8:40:54 PM Donna FayeLet me explain to you that now Online Number are detach to a calling subscription unlike before it was attach to the calling subscription so therefore each Online Number will recur individually.8:41:29 PM Donna FayeUpon checking your account it shows that all your Online Number will expire on October XX, 20138:41:44 PM Donna FayeIf you don't want to be charged again for you can cancel it anytime.8:41:59 PM greglowI have set it to charge automatically8:42:06 PM greglowso why do the numbers expire?8:42:32 PM Donna FayeNo they are not expired they are all active.8:42:33 PM greglowif there is an automatic payment set up, why does anything expire?8:42:52 PM greglowyes, but one of them was expired, and I only fixed it a few hours ago8:43:07 PM greglowI'm trying to understand why it expired8:44:54 PM Donna FayeThe email you got just notify you that you should have good enough funding source of your calling subscription and Online Number in order for this to recur.8:45:12 PM greglowAgreed. I did that but the number still expired. Why?8:45:38 PM Donna FayeHowever do not worry on this hence all Online Number are active and not expired.8:45:41 PM greglowWhen I logged on today it said that the number had expired and that I had 52 days left to reactivate it. Why did that happen?8:46:14 PM Donna FayeMay I know the Online Number you are pertaining, please?The number that had expired was (07) XXXX XXXX (Australia)8:49:19 PM Donna FayeOkay, do not worry on this Online Number because this will expire on October XX, 2013.8:49:38 PM Donna FayeThank you for all the information.8:49:46 PM greglowI understand that it won't expire now until next year. I'm trying to understand why it stopped working this time8:49:51 PM greglowso I can avoid that next time8:50:39 PM Donna FayeWhat do yo stop working, you mean that Online Number is unable to be reach out?8:50:59 PM Donna Faye*what do you mean by stop working8:51:18 PM greglowThe Skype number +61 7 XXXX XXXX stopped working because it expired8:51:32 PM Donna FayeNo, this into expired.8:51:34 PM greglowI'm trying to understand why it expired8:51:50 PM greglowSorry I don't follow "this into expired"8:52:39 PM Donna FayeLet me inform you that this Online Number is not expired.8:52:54 PM Donna FayePlease disregard the notification you see on your Skype account.8:53:02 PM greglowSorry, this is getting very frustrating. I already told you I fixed it today. I want to know why it happened.8:53:20 PM Donna FayeHence I can rest assured you that this is active until October XX, 2013.8:53:21 PM greglowSo I can avoid it happening again, on this account, or on our other accounts8:53:34 PM greglowCan I speak to someone who really understands this please?Donna FayeSkype send a notification to Skype users for their Skype product in order for them to be aware the expiration of your product however your Online Number still active on your account hence when your calling subscription Unlimited World recur your Online Number also recur. 8:57:59 PM Donna Faye I do apologize for this matter, please allow me to resolve this issue for you. 9:02:48 PM greglow My question is still the same: if it's set to auto-pay, why did it expire? 9:03:50 PM greglow Why did it stop working? Why did I have to "reactivate" it? 9:04:08 PM greglow Why didn't it just keep working if it's set to auto-pay? 9:04:30 PM greglow This isn't a difficult concept 9:04:34 PM Donna Faye Let me clarify to you that this is not the really expired what is emphasizing on this is when you don't have good enough funding source when you calling subscription recur the Online Number will possibly expired but seem that you have a good funding source then this will continue until 2013. 9:05:10 PM greglow When I logged on today, it was not working, and your website said it had expired and that I had 52 days left to reactivate it 9:05:17 PM greglow Why?and so on, and so on, and so on.... 

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• Annual Review: what hard data should a developer bring?

  - by sunpech

  Many companies have annual reviews for their employees. I've heard that it's generally a good idea to muster up some hard data to analyze and bring to the review. The better the data, the better the chances to help support a promotion or raise. What I mean by hard data, are tangible numbers-- something that can be measured and/or calculated. Obviously data that a developer would have access to. Something intangible would be how beautiful the code a developer has written. I think this would be very hard to measure, nor would upper management care for it. My question is: For a software developer, what kind of hard data should be analyzed and brought to a review to help highlight good work that was done? An example I've been given in the past: The support tickets produced by each project a developer was involved in. Are the numbers low? Are the rate per month getting lower? Etc.

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• How to avoid flickering in jquery?

  - by Pandiya Chendur

  I am using jquery with asp.net webforms..... I am using asp.net pagemethods and jquery.... I am emptying a div on click of anchor tags and filling it with new content.... What happens is my div flickers when my new data is loaded to it... How to avoid this in jquery? Can i use any effect for this.... <script type="text/javascript"> $(document).ready(function() { getRecordspage(1, 5); $("a.page-numbers").click(function() { $("#ResultsDiv").empty(); getRecordspage($(this).text(), 5) }); }); </script> and my page, <body> <form id="form1" runat="server"> <div id="ResultsDiv"> </div> <div class="pager"> <a ID="lnkbtn0" class="page-numbers" href="javascript:void(0);">1</a> <a ID="lnkbtn1" class="page-numbers" href="javascript:void(0);">2</a> <a ID="lnkbtn2" class="page-numbers" href="javascript:void(0);">3</a> <a ID="lnkbtn3" class="page-numbers" href="javascript:void(0);">4</a> </div> </form> </body> and my getRecordspage() function is function getRecordspage(curPage, pagSize) { $.ajax({ type: "POST", url: "Default.aspx/GetRecords", data: "{'currentPage':" + curPage + ",'pagesize':" + pagSize + "}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(jsonObj) { var strarr = jsonObj.d.split('##'); var jsob = jQuery.parseJSON(strarr[0]); $.each(jsob.Table, function(i, employee) { $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').appendTo('#ResultsDiv'); }); $(".resultsdiv:even").addClass("resultseven"); $(".resultsdiv").hover(function() { $(this).addClass("resultshover"); }, function() { $(this).removeClass("resultshover"); }); } }); }

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• Windows Phone 7 Development Updates &ndash; March 8th 2011

  - by Nikita Polyakov

  Here are the latest update from the Windows Phone 7 Developer Worlds that went live this month. Here are some of the latest numbers: Windows Phone Marketplace currently offers more than 9,000 quality apps and games and enjoys a base of over 32,000 registered developers, delivering an average of 100 new apps every day. There have been over 1 million downloads of the developers tools for Windows Phone 7. Trial version help you sell more Trials result in higher sales by the numbers: Users like trials  - paid apps with trial functionality are downloaded 70 times more than paid apps that don’t Nearly 1 out of 10 trial apps downloaded convert to a purchase and generate 10 times more revenue on average than paid apps that don’t include trial functionality. Trial downloads convert to paid downloads quickly. More than half of trial downloads that convert to a sale do so within the 1st 24 hours of trial download, and mostly within 2 hours of trial download. Microsoft Ad Control is gaining traction By the numbers - ad supported Windows Phone 7 apps are: Roughly ¼ of all registered U.S. WP7 developers have downloaded the free Ad SDK for Silverlight and XNA Of ad funded apps, over 95 percent use the free Microsoft Advertising Ad Control Monthly impressions from our Ad Exchange has continued to grow by double digits – impressions increased by 376 percent since January Ad Control, the first wave of “How Do I” videos are now available on MSDN: Create an Ad in a Windows Phone 7 XNA Game App Register Ad-Enabled Windows Phone 7 Apps Measure Ad Performance of Windows Phone 7 Apps Boarder International App submission for Free Apps through Yalla Apps As of today you can start submitting your free applications in developer markets that are currently not covered by Microsoft. To submit your Free application if you DO NOT belong to one of the Marketplace supported countries, go to: Yalla Apps Marketplace Policy Updates: Free App Marketplace Submission upped to 100 and other news Microsoft has been revisiting a few of our Marketplace policies based on feedback from developers to reduce friction and cost, word for word: 1. We have raised the limit on the number of certifications that can be performed for FREE apps at no cost to the registered developer from five to 100. This was a common request from developers which we are glad to implement after building alternate methods to ensure that users can find and download high quality apps. 2. We have converted policy 5.6 - related to the inclusion of contact information for support - from a mandatory to an optional policy. This is still a strongly recommended best practice, but we recognized and responded to developer feedback that this policy was creating excessive drag on the certification process for developers without commensurate user benefit for all apps. 3. We also understand the desire for clarification with regard to our policy on applications distributed under open source licenses.  The Marketplace Application Provider Agreement (APA) already permits applications under the BSD, MIT, Apache Software License 2.0 and Microsoft Public License.  We plan to update the APA shortly to clarify that we also permit applications under the Eclipse Public License, the Mozilla Public License and other, similar licenses and we continue to explore the possibility of accommodating additional OSS licenses. Enjoy and happy coding! Official Blog Post for reference.

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• Acting as though the laptop Fn key is pressed

  - by Matt

  I have a Fujitsu laptop and all was working fine until I ended teamviewer. On the keyboard it has a numberpad on some of the letters which you press the Fn button to use. The system is acting like I have the Fn key pressed and I get numbers shown when it should be letters. If I press the Fn key the numbers go to letters. The Fn key is not stuck down. Is there a way to reset keyboard settings or a known fix. The operating system is Ubuntu 11.04 Natty.

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• How do you achieve a numeric versioning scheme with Git?

  - by Erlend

  My organization is considering moving from SVN to Git. One argument against moving is as follows: How do we do versioning? We have an SDK distribution based on the NetBeans Platform. As the svn revisions are simple numbers we can use them to extend the version numbers of our plugins and SDK builds. How do we handle this when we move to Git? Possible solutions: Using the build number from hudson (Problem: you have to check hudson to correlate that to an actual git version) Manually upping the version for nightly and stable (Problem: Learning curve, human error) If someone else has encountered a similar problem and solved it, we'd love to hear how.

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• Detect duplicate in a subset from a set of elements

  - by Abhinav Shrivastava

  I have a set of numbers say : 1 1 2 8 5 6 6 7 8 8 4 2... I want to detect the duplicate element in subsets(of given size say k) of the above numbers... For example : Consider the increasing subsets(for example consider k=3) Subset 1 :{1,1,2} Subset 2 :{1,2,8} Subset 3 :{2,8,5} Subset 4 :{8,5,6} Subset 5 :{5,6,6} Subset 6 :{6,6,7} .... .... So my algorithm should detect that subset 1,5,6 contains duplicates.. My approach : 1)Copy the 1st k elements to a temporary array(vector) 2) using #include file in C++ STL...using unique() I would determine if there's any change in size of vector.. Any other clue how to approach this problem..

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• How much to pay for artwork in an indie game?

  - by f20k

  I am an indie developer and I need some detailed artwork. How much is reasonable to pay an artist for say 20 character designs? I know it depends on the artist's skills, etc, but I am wondering what to expect so that I can budget it. Edit: Let's say cartoon-ish art (Example - not necessarily in that level of detail but that kind of cartoony-art style). No 3-d modelling - The art will be used as still images in game and for promotional reasons. I'd provide a base sprite design for them to expand on and detail. Also, some numbers would be nice - I like numbers. Even a range is helpful. Like: expect to spend $x2 ~ $x1 for top-notch and $y2 ~ $y1 for decent quality. I understand I can ask at some indie-help site but, if an artist says something like $1000 for 20 designs, I wouldn't have any idea if it's reasonable / good deal / bad idea etc.

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• How to make bash script run with a latency (i.e. wait 1 sec at each iterations)?

  - by user2413

  I have this bash script; for (( i = 1 ; i <= 160 ; i++ )); do qsub myccomputations"${i}".pbs done Basically, I would prefer if there was a 1 second delay between each iteration. The reason is that at each iterations, it sends the program file mycomputation"${i}$.pbs to a core node for solving. Solving in this instance involves the use of pseudo random numbers. I suspect the RNG I use (R's) uses CPU time as seed because as things are now I get repeating pseudo random numbers (at the rate of approx 1 out of 100). So how to you ask bash to for (( i = 1 ; i <= 160 ; i++ )); do wait 1 sec qsub myccomputations"${i}".pbs done

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• Concept behind SHA-1 Checksum

  - by Vishwas Gagrani

  What's the basis behind SHA-1 or SHA-2 or other Checksum algorithms? I read about it here http://en.wikipedia.org/wiki/SHA-1#Data_Integrity But I am still wondering about an answer in a layman's language. Can I understand it as a very, very compressed code that can be translated back into original data? Let's say, I have a letter written in notepad. Then the whole of my 1 A4 page size data can be converted into something like this "9b90417b6a186b6f314f0b679f439c89a3b0cdf5". So whenever I want my original data back, I can convert this back into original data? I am very sure that I am wrong here, because it is weird how data that itself contains combination of letters and numbers can be represented by smaller set of letters and numbers. Illogical! Then, what's the basic?

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• How to get distance from point to line with distinction between side of line?

  - by tesselode

  I'm making a 2d racing game. I'm taking the nice standard approach of having a set of points defining the center of the track and detecting whether the car is off the track by detecting its distance from the nearest point. The nicest way I've found of doing this is using the formula: d = |Am + Bn + C| / sqrt(A^2 + B^2) Unfortunately, to have proper collision resolution, I need to know which side of the line the car is hitting, but I can't do that with this formula because it only returns positive numbers. So my question is: is there a formula that will give me positive or negative numbers based on which side of the line the point is on? Can I just get rid of the absolute value in the formula or do I need to do something else?

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• booth multiplication algorithm

  - by grassPro

  Is booth algorithm for multiplication only for multiplying 2 negative numbers (-3 * -4) or one positive and one negative number (-3 * 4) ? Whenever i multiply 2 positive numbers using booth algorithm i get a wrong result. example : 5 * 4 A = 101 000 0 // binary of 5 is 101 S = 011 000 0 // 2's complement of 5 is 011 P = 000 100 0 // binary of 4 is 100 x = 3 y = 3 m = 5 -m = 2's complement of m r = 4 After right shift of P by 1 bit 0 000 100 After right shift of P by 1 bit 0 000 010 P+S = 011 001 0 After right shift by 1 bit 0 011 001 Discarding the LSB 001100 But that comes out to be the binary of 12 . It should have been 20(010100)

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• Java chunk negative number problem

  - by user1990950

  I've got a tile based map, which is divided in chunks. I got a method, which puts tiles in this map and with positive numbers it's working. But when using negative numbers it wont work. This is my setTile method: public static void setTile(int x, int y, Tile tile) { int chunkX = x / Chunk.CHUNK_SIZE, chunkY = y / Chunk.CHUNK_SIZE; IntPair intPair = new IntPair(chunkX, chunkY); world.put(intPair, new Chunk(chunkX, chunkY)); world.get(intPair).setTile(x - chunkX * Chunk.CHUNK_SIZE, y - chunkY * Chunk.CHUNK_SIZE, tile); } This is the setTile method in the chunk class (CHUNK_SIZE is a constant with the value 64): public void setTile(int x, int y, Tile t) { if (x >= 0 && x < CHUNK_SIZE && y >= 0 && y < CHUNK_SIZE) tiles[x][y] = t; } What's wrong with my code?

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• Sortie de Safari 4.0.5 la mise à jour corrige quelques bugs et améliore le stabilité du navigateur

  Apple propose ce soir une mise à jour pour son navigateur web Safari, pour Mac (Snow Leopard, Leopard et Tiger) et Windows. Elle apporte quelques changements : amélioration de la performance pour Top Sites ; amélioration de la stabilité pour les modules additionnels de tierce partie ; amélioration de la stabilité pour les sites web contenant des formulaires en ligne et des graphiques Scalable Vector ; une réponse au problème empêchant Safari de modifier les réglages sur certains routeurs Linksys ; une réponse au problème empêchant certains utilisateurs d'iWork.com de publier des commentaires sur les documents. Mise à jour disponible via le menu Pomme ou sur le site d'

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• Where can I find statistics / figures on how long testing should / could take?

  - by NoCarrier

  I'm trying to convince management that testing/QA takes considerably longer than non-developers think. Some smaller shops don't have budgets for testers and phbs automatically assume the developer will spend a few minutes after every build "testing" and deliver a perfectly functional system. Can someone point me to some numbers? e.g. Testing should be XX% of your total man hour count , etc etc? Or perhaps some real world experience? My goal is to have some numbers that are grounded in real life so I can make time/effort allocation justifications for "proper" testing when preparing estimates and timelines for applications. Maybe not full blown 100% TDD, but pragmatically close to it. I apologize if I seem vague.

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• Partitioning set into subsets with respect to equality of sum among subsets

  - by Al.Net

  let say i have {3, 1, 1, 2, 2, 1,5,2,7} set of numbers, I need to split the numbers such that sum of subset1 should be equal to sum of subset2 {3,2,7} {1,1,2,1,5,2}. First we should identify whether we can split number(one way might be dividable by 2 without any remainder) and if we can, we should write our algorithm two create s1 and s2 out of s. How to proceed with this approach? I read partition problem in wiki and even in some articles but i am not able to get anything. Can someone help me to find the right algorithm and its explanation in simple English?

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• Why is n given the initial value of 1 in this loop?

  - by notypist

  From Kochan's "Programming in C": Input: printf ("TABLE OF TRIANGULAR NUMBERS\n\n"); printf (" n Sum from 1 to n\n"); printf ("--- ---------------\n"); triangularNumber = 0; for(n=1; n<=10; ++n){ triangularNumber += n; ? printf (" %i", n); } Output (only partly pasted): TABLE OF TRIANGULAR NUMBERS n = 1 Sum from 1 to n = 1 n = 2 Sum from 1 to n = 2 Question: I understand the purpose of this, but here's what I can't get my head around: If within the loop we assign an initial value of "1" to "n", then we check if n<=10, and if that's true (which it should be with the initial value), we then add "1" to n. Shouldn't (and I know it shouldn't, just don't understand why) the initial value displayed in our table be n=2 ? Thanks in advance for your patience and effort!

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• Whats the problem with reporting ?

  - by simonsabin

  Its the reports.   Take this for example, it is a report generated during a demo of Report Builder 3.0 by someone in MS marketing. She says things like “..and you can see easily how my divisions are doing”. No you can’t you’ve just got a bunch of numbers. This is really the issue with reporting systems and especially with Microsoft reporting. The problem is that people think generating a report is about getting lists of numbers onto a page. Reporting services is great at doing that and its very...(read more)

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• bulls and cows game -- programming algorithm(python)

  - by IcyFlame

  This is a simulation of the game Cows and Bulls with three digit numbers I am trying to get the number of cows and bulls between two numbers. One of which is generated by the computer and the other is guessed by the user. I have parsed the two numbers I have so that now I have two lists with three elements each and each element is one of the digits in the number. So: 237 will give the list [2,3,7]. And I make sure that the relative indices are maintained.the general pattern is:(hundreds, tens, units). And these two lists are stored in the two lists: machine and person. ALGORITHM 1 So, I wrote the following code, The most intuitive algorithm: cows and bulls are initialized to 0 before the start of this loop. for x in person: if x in machine: if machine.index(x) == person.index(x): bulls += 1 print x,' in correct place' else: print x,' in wrong place' cows += 1 And I started testing this with different type of numbers guessed by the computer. Quite randomly, I decided on 277. And I guessed 447. Here, I got the first clue that this algorithm may not work. I got 1 cow and 0 bulls. Whereas I should have got 1 bull and 1 cow. This is a table of outputs with the first algorithm: Guess Output Expected Output 447 0 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 0 cows 2 bulls, 0 cows 777 0 bulls, 3 cows 2 bulls, 0 cows So obviously this algorithm was not working when there are repeated digits in the number randomly selected by the computer. I tried to understand why these errors are taking place, But I could not. I have tried a lot but I just could not see any mistake in the algorithm(probably because I wrote it!) ALGORITHM 2 On thinking about this for a few days I tried this: cows and bulls are initialized to 0 before the start of this loop. for x in range(3): for y in range(3): if x == y and machine[x] == person[y]: bulls += 1 if not (x == y) and machine[x] == person[y]: cows += 1 I was more hopeful about this one. But when I tested this, this is what I got: Guess Output Expected Output 447 1 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 2 cows 2 bulls, 0 cows 777 2 bulls, 4 cows 2 bulls, 0 cows The mistake I am making is quite clear here, I understood that the numbers were being counted again and again. i.e.: 277 versus 477 When you count for bulls then the 2 bulls come up and thats alright. But when you count for cows: the 7 in 277 at units place is matched with the 7 in 477 in tens place and thus a cow is generated. the 7 in 277 at tens place is matched with the 7 in 477 in units place and thus a cow is generated.' Here the matching is exactly right as I have written the code as per that. But this is not what I want. And I have no idea whatsoever on what to do after this. Furthermore... I would like to stress that both the algorithms work perfectly, if there are no repeated digits in the number selected by the computer. Please help me with this issue. P.S.: I have been thinking about this for over a week, But I could not post a question earlier as my account was blocked(from asking questions) because I asked a foolish question. And did not delete it even though I got 2 downvotes immediately after posting the question.

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